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  • Form validation

    - by kielie
    Hi guys, I need to create a form that has many of the same fields, that have to be inserted into a database, but the problem I have is that if a user only fills in one or two of the rows, the form will still submit the blank data of the empty fields along with the one or two fields the user has filled in. How can I check for the rows that have not been filled in and leave them out of the query? or check for those that have been filled in and add them to the query. . . The thank_you.php file will capture the $_POST variables and add them to the database. <form method="post" action="thank_you.php"> Name: <input type="text" size="28" name="name1" /> E-mail: <input type="text" size="28" name="email1" /> <br /> Name: <input type="text" size="28" name="name2" /> E-mail: <input type="text" size="28" name="email2" /> <br /> Name: <input type="text" size="28" name="name3" /> E-mail: <input type="text" size="28" name="email3" /> <br /> Name: <input type="text" size="28" name="name4" /> E-mail: <input type="text" size="28" name="email4" /> <input type="image" src="images/btn_s.jpg" /> </form> I am assuming that I could use javascript or jQuery to accomplish this, how would I go about doing this? Thanx in advance for the help.

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  • Best practices for withstanding launch day traffic burst

    - by Sam McAfee
    We are working on a website for a client that (for once) is expected to get a fair amount of traffic on day one. There are press releases, people are blogging about it, etc. I am a little concerned that we're going to fall flat on our face on day one. What are the main things you would look at to ensure (in advance without real traffic data) that you can stay standing after a big launch. Details: This is a L/A/M/PHP stack, using an internally developed MVC framework. This is currently being launched on one server, with Apache and MySQL both on it, but we can break that up if need be. We are already installing memcached and doing as much PHP-level caching as we can think of. Some of the pages are rather query intensive, and we are using Smarty as our template engine. Keep in mind there is no time to change any of these major aspects--this is the just the setup. What sorts of things should we watch out for?

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  • Combining Data from two MySQL tables.

    - by Nick
    I'm trying to combine data from two tables in MySQL with PHP. I want to select all the data (id, title, post_by, content and created_at) from the "posts" table. Then I would like to select the comment_id COUNT from the "comments" table IF the comment_id equals the posts id. Finally, I would like to echo/print something on this order: <? echo $row->title; ?> Posted by <? echo $row->post_by; ?> on <? echo $row->created_at; ?> CST <? echo $row->content; ?> <? echo $row->comment_id; ?> comments | <a href="comment.php?id=<? echo $row->id; ?>">view/post comments</a> I'm uncertain as to how to "combine" the data from two tables. I have tried numerous things and have spent several evenings and have had no luck. Any help would be greatly appreciated!

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  • Get part of array string

    - by user1560295
    Hello my output PHP code is : Array ( [country] => BG - Bulgaria ) ... and he comes from here : <?php $ip = $_SERVER['REMOTE_ADDR']; print_r(geoCheckIP($ip)); //Array ( [domain] => dslb-094-219-040-096.pools.arcor-ip.net [country] => DE - Germany [state] => Hessen [town] => Erzhausen ) //Get an array with geoip-infodata function geoCheckIP($ip) { //check, if the provided ip is valid if(!filter_var($ip, FILTER_VALIDATE_IP)) { throw new InvalidArgumentException("IP is not valid"); } //contact ip-server $response=@file_get_contents('http://www.netip.de/search?query='.$ip); if (empty($response)) { throw new InvalidArgumentException("Error contacting Geo-IP-Server"); } //Array containing all regex-patterns necessary to extract ip-geoinfo from page $patterns=array(); $patterns["country"] = '#Country: (.*?)&nbsp;#i'; //Array where results will be stored $ipInfo=array(); //check response from ipserver for above patterns foreach ($patterns as $key => $pattern) { //store the result in array $ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : ''; } return $ipInfo; } ?> How can I get ONLY the name of the Country like in my case "Bulgaria"? I think it will happen with preg_replace or substr but i dont know what is the better solution now.

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  • explode is not working to split string

    - by pmms
    we unable to split the string following code.please Help us. <?php $i=0; $myFile = "testFile.txt"; $fh = fopen($myFile, 'a') or die("can't open file"); $stringData = "no\t"; fwrite($fh, $stringData); $stringData = "username \t"; fwrite($fh, $stringData); $stringData ="password \t"; fwrite ($fh,$stringData); $newline ="\r\n"; fwrite ($fh,$newline); $stringData1 = "1\t"; fwrite($fh, $stringData1); $stringData1 = "srinivas \t"; fwrite($fh, $stringData1); $stringData1 ="malayappa \t"; fwrite ($fh,$stringData1); fclose($fh); ?> $fh = fopen("testFile.txt", "r"); $ while (!feof($fh)) { $line = fgets($fh); echo $line; } fclose($fh); $Beatles = array('pmm','malayappa','sreenivas','PHP'); for($i=0;$i<count($Beatles);$i++) { if($i==2) { echo $Beatles[$i-1]; echo $Beatles[$i-2]; } } $pass_ar=array(); $fh = fopen("testFile.txt", "r"); while (!feof($fh)) { $line = fgets($fh); echo $line; $t1=explode(" ",$line); print_r($t1); array_push($pass_ar,t1); } fclose($fh); Thanks & Regards pmms

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  • Illegal offset type error when => value is omitted

    - by thomas
    Line 3 of the code below fails if I omit the => $v portion. I get the following error: Warning: Illegal offset type in /home/site/page.php on line 404 When the [$k] in line 5 is changed to ['$k'], i receive the following error. Notice: Undefined index: $k in /home/site/page.php on line 404 When it is like below with the the full $k => $v everything works though. I don't even use $v. Why do I need it in the foreach loop to make it work then? <? if ( $arr[ 'status'][ 'chain'] ) { foreach ( $arr[ 'status'][ 'chain'] as $k => $v) { ?> <tr> <td class="line_item_data status_td"> <?= $ arr[ 'status'][ 'chain'][$k][ 'message'] ?> </td> <td align="center"> <img src="images/green_check.gif" width="20" /> </td> </tr> <? } } ?> I did see this answer, but don't know that it really applies. Thanks so much!

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  • Using a join with three tables when a field might be null

    - by John
    Hello, The code below works great. It combines data from two MySQL tables. I would like to modify it by pulling in some data from a third MySQL table called "comment." In the HTML table below, "title" is a field in the MySQL table "submission." Every "title" has a corresponding "submissionid" field. The field "submissionid" is also found in the "comment" MySQL table. In the HTML table below, I would like "countComments" to equal the number of times a field called "commentid" appears in the MySQL table "comment" for any given "submissionid," where the "submissionid" is the same in both the "submission" and "comment" tables, and where the "submissionid" corresponds to the "title" being used. Here's the catch: if there is no row in the MySQL table "comment" that corresponds with the "submissionid" being used for "table", I would like "countComments" to equal to zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Sonata Media Bundle sortBy created_at

    - by tony908
    I use SonataMediaBundle and i would like sort Gallery by created_at field. In repository class i have (without orderBy working good!): $qb = $this->createQueryBuilder('m') ->orderBy('j.expires_at', 'DESC'); $query = $qb->getQuery(); return $query->getResult(); and this throw error: An exception has been thrown during the rendering of a template ("[Semantical Error] line 0, col 80 near 'created_at D': Error: Class Application\Sonata\MediaBundle\Entity\Gallery has no field or association named created_at") so i add this field to Gallery class: /** * @var \DateTime */ private $created_at; /** * Set created_at * * @param \DateTime $createdAt * @return Slider */ public function setCreatedAt($createdAt) { $this->created_at = $createdAt; return $this; } /** * Get created_at * * @return \DateTime */ public function getCreatedAt() { return $this->created_at; } but now i have error: FatalErrorException: Compile Error: Declaration of Application\Sonata\MediaBundle\Entity\Gallery::setCreatedAt() must be compatible with Sonata\MediaBundle\Model\GalleryInterface::setCreatedAt(DateTime $createdAt = NULL) in /home/tony/www/test/Application/Sonata/MediaBundle/Entity/Gallery.php line 32 GalleryInterface: https://github.com/sonata-project/SonataMediaBundle/blob/master/Model/GalleryInterface.php So... how can i use sortBy in my example?

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  • Codeigniter return config file as array with autoload enabled

    - by Fverswijver
    So I'm using CodeIgniter to build a website and I've made it so that all my specific settings are stored in a config file that's automatically loaded. I've also built a page that loads the settings file, makes a nice little table and allows me to edit everything from that page, afterwards it saves the entire page again (I know I could've done the same with a database but I want to try it this way). My problem is that I can't seem to use this bit when autoloading of my config file is enabled, but when I disable autoloading I can't seem to manually load it, it never finds my variables. So what I'm doing here is just taking all values from the config file and putting them in a single array so I can pass this array onto my settings administration page (edit/show all settings). $this->config->load('site_settings', TRUE); $data['settings'] = $this->config->item('site_settings'); ... $this->load->view('template', $data); config/site_settings.php <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); $config['header_img'] = './img/header/'; $config['copyright_text'] = 'Copyright Instituto Kabu'; $config['copyright_font'] = './system/fonts/motoroil.ttf'; $config['copyright_font_color'] = 'ffffff'; $config['copyright_font_size'] = '32';

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  • file cretaed using exec could not be accessed immediately after creation?

    - by Holicreature
    HI I'm using exec in php to execute a command and it will create a .png file in a temp folder.. After creating that i'm trying to open that file and read contents and process them,, but i end up file could not read error.. I think the time taken by the exec to execute and create a file is the cause for the issue.. but i dont know how to fix it? i tried sleep() but it makes my script to run slow <?php error_reporting(E_ALL); extension_loaded('ffmpeg') or die('Error in loading ffmpeg'); //db connection codes $max_width = 120; $max_height = 72; $path ="/path/"; $qry="select id, input_file, output_file from videos where thumbnail='' or thumbnail is null;"; $res=mysql_query($qry); $cnt = 1; while($row = mysql_fetch_array($res,MYSQL_ASSOC)) { $outfile = $row[output_file]; $imgname = $cnt.".png"; $srcfile = "/path/".$outfile; echo "####$srcfile####"; exec("ffmpeg -i ".$srcfile." -r 1 -ss 00:00:05 -f image2 -s 120x72 ".$path.$imgname); $nname = "./temp/".$imgname; echo "nname===== $nname"; $fileo = fopen($nname,"rb"); if($fileo) { $imgData = addslashes(file_get_contents($nname)); .. ... .... } else echo "Could not open<br><br>"; $cnt = $cnt + 1: } ?>

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  • Appending Comment Number Anchors to Comments

    - by John
    Hello, I am using a PHP file called comments.php that has a query that enters values into a mySQL table called "comment." As the query does this, it auto-generates a field called "commentid", which is set to auto_increment in MySQL. The file also contains a loop what echoes out all comments for a given submission. It all works fine and dandy, but I want to simultaneously pull this "commentid" and turn it into a hashtag / anchor that when appended to the end of the URL makes that comment at the top of the user's browser. Someone said on another question that in order to do this one thing I should do is create an anchor on the row where the comment is being printed out. How can I do this? Thanks in advance, John The query that inserts comments into the MySQL table "comment": $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); The fields in the table "comment": commentid loginid submissionid comment datecommented The row in a loop where the comments are echoed out: echo '<td rowspan="3" class="commentname1">'.stripslashes($row["comment"]).'</td>';

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  • Send file FTP over SSL with custom port number

    - by JM4
    I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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  • Getting list of Facebook friends with latest API

    - by Eric
    I'm using the most recent version of the Facebook SDK (which lets to connect to something called the 'graph API' though I'm not sure). I've adapted Facebook's example code to let me connect to Facebook and that works... but I can't get a list of my friends. $friends = $facebook->api('friends.get'); This produces the error message: "Fatal error: Uncaught OAuthException: (#803) Some of the aliases you requested do not exist: friends.get thrown in /mycode/facebook.php on line 543" No clue why that is or what that means. Can someone tell me the right syntax (for the latest Facebook API) to get a list of friends? (I tried "$friends = $facebook-api-friends_get();" and get a different error, "Fatal error: Call to a member function friends_get() on a non-object in /mycode/example.php on line 129".) I can confirm that BEFORE this point in my code, things are fine: I'm connected to Facebook with a valid session and I can get my info and dump it to the screen just... i.e. this code executes perfectly before the failed friends.get call: $session = $facebook->getSession(); if ($session) { $uid = $facebook->getUser(); $me = $facebook->api('/me'); } print_r($me);

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  • If statement doesn't work? do download without filed name and email

    - by user1833871
    I've created some if / else statements to get a download when a user hit click jf he fields name and email but doesn"t work for my site http://my-easy-woodworking-projects.com because it is do download without field name and email contact.php is <?php $field_name = $_POST['cf_name']; $field_email = $_POST['cf_email']; $field_message = $_POST['cf_message']; $mail_to = '[email protected]'; $subject = 'Message from a site visitor '.$field_name; $body_message = 'From: '.$field_name."\n"; $body_message .= 'E-mail: '.$field_email."\n"; $body_message .= 'Message: '.$field_message; $headers = 'From: '.$field_email."\r\n"; $headers .= 'Reply-To: '.$field_email."\r\n"; $mail_status = mail($mail_to, $subject, $body_message, $headers); if ($mail_status) { echo <script>\n" echo "var str = \"download\"; \n"" echo "document.write(str.link("http://www.myshedplans.com/12BY8SHED.pdf"));\n" echo "</script>\n" } echo else { echo <script language="javascript" type="text/javascript"> echo // Print a message echo alert('Message failed. Please, send an email to [email protected]'); echo // Redirect to some page of the site. You can also specify full URL, e.g. http://template-help.com window.location = 'contact_page.html'; echo </script> }?>

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  • i read that for RESTful websites. it is not good to use $_SESSION. Why is it not good? how then do i

    - by keisimone
    I read that it is not good to use $_SESSION. http://www.recessframework.org/page/towards-restful-php-5-basic-tips I am creating a WEBSITE, not web service in PHP. and i am trying to make it more RESTful. at least in spirit. right now i am rewriting all the action to use Form tags POST and add in a hidden value called _method which would be "delete" for deleting action and "put" for updating action. however, i am not sure why it is recommended NOT to use $_SESSION. i would like to know why and what can i do to improve. To allow easy authorization checking, what i did was to after logging in the user, the username is stored in the $_SESSION. Everytime the user navigates to a page, the page would check if the username is stored inside $_SESSION and then based on the $_SESSION retrieves all the info including privileges from the database and then evaluates the authorization to access the page based on the info retrieved. Is the way I am implementing bad? not RESTful? how do i improve performance and security? Thank you.

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  • Error loading il8n console in CakePHP 1.3

    - by inkedmn
    I'm trying to generate the .po files for the site I'm working with. When I run this command from within the console directory: Warning: strtotime(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Los_Angeles' for 'PDT/-7.0/DST' instead in /Users/bkelly/Development/[redacted]/www/trunk/about/trunk/cake/libs/cache.php on line 570 Warning: strtotime(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Los_Angeles' for 'PDT/-7.0/DST' instead in /Users/bkelly/Development/[redacted]/www/trunk/about/trunk/cake/libs/cache.php on line 570 Error: Class Il8nShell could not be loaded. This also happens if I issue ./cake il8n help . The bake console seems to load fine (no errors, takes me to the expected menu). I'm running CakePHP 1.3.0 under Mac OSX 10.6 (using MAMP). Cake appears to be functioning normally otherwise. Thanks!

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  • How do I use curl to display a table on a page?

    - by user272899
    I want to use curl to retrieve a table from an external page. So far my code retrieves all data from the page. I have read that using preg_match or preg_replace is the way to go about it. This is my code so far: <?php $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL,"http://www.megaupload.com/?d=XE30L1GA&w=631&h=392"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1=curl_exec($ch) or die(curl_error()); echo "<font color=black face=verdana size=3>".$data1."</font>"; echo curl_error($ch); curl_close($ch); ?> This is the data I want to retrieve from the page: <FORM method="POST" id="captchaform"> <INPUT type="hidden" name="captchacode" value="1a589e0a53c54f937eb8"> <INPUT type="hidden" name="megavar" value="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"> <TR> <TD>Enter this </TD> <TD width="100" align="center" height="40"><img src="http://wwwq32.megaupload.com/gencap.php?23243f17c2404dd4.gif" border="0" alt=""></TD> <TD> here:</TD> <TD><input type="text" name="captcha" id="captchafield" maxlength="4" style="border:solid 1px; border-color:#C4C4C4; background-color:#F9F9F9; width:50px; height:25px;"></TD> </TR> </FORM>

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • How do I make a HTTP POST request to an url from within a c++ dll?

    - by tjorriemorrie
    Hi, there's an open-source application I need to use. It allows you to use a custom dll. Unfortunately, I can't code c++; i don't like it; it don't want to learn it. I do know PHP very well however, thus you can see that I'll rather do my logic within a PHP application. Thus I'm thinking about posting the data from c++/dll to a url on my localhost. (i have my local server set up, that's not the problem). I need to post a large amount of variables (thus a POST and not GET request required). The return value will only be one (int)variable, either 0, 1 or 2. So I need a c++ function that: 1) will post variables to an url. 2) Wait for, and receive the answer. The data type can be in xml, soap, json, whatever, doesn't matter. Is there anyone that can write a little c++ http function for me? pretty please? ;)

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  • How to add an array value to the middle of an associative array?

    - by Citizen
    Lets say I have this array: $array = array('a'=>1,'z'=>2,'d'=>4); Later in the script, I want to add the value 'c'=>3 before 'z'. How can I do this? EDIT: Yes, the order is important. When I run a foreach() through the array, I do NOT want this newly added value added to the end of the array. I am getting this array from a mysql_fetch_assoc() EDIT 2: The keys I used above are placeholders. Using ksort() will not achieve what I want. EDIT 3: http://www.php.net/manual/en/function.array-splice.php#88896 accomplishes what I'm looking for but I'm looking for something simpler. EDIT 4: Thanks for the downvotes. I gave feedback to your answers and you couldn't help, so you downvoted and requested to close the question because you didn't know the answer. Thanks. EDIT 5: Take a sample db table with about 30 columns. I get this data using mysql_fetch_assoc(). In this new array, after column 'pizza' and 'drink', I want to add a new column 'full_dinner' that combines the values of 'pizza' and 'drink' so that when I run a foreach() on the said array, 'full_dinner' comes directly after 'drink'

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • Generated images fail to load in browser

    - by notJim
    I've got a page on a webapp that has about 13 images that are generated by my application, which is written in the Kohana PHP framework. The images are actually graphs. They are cached so they are only generated once, but the first time the user visits the page, and the images all have to be generated, about half of the images don't load in the browser. Once the page has been requested once and images are cached, they all load successfully. Doing some ad-hoc testing, if I load an individual image in the browser, it takes from 450-700 ms to load with an empty cache (I checked this using Google Chrome's resource tracking feature). For reference, it takes around 90-150 ms to load a cached image. Even if the image cache is empty, I have the data and some of the application's startup tasks cached, so that after the first request, none of that data needs to be fetched. My questions are: Why are the images failing to load? It seems like the browser just decides not to download the image after a certain point, rather than waiting for them all to finish loading. What can I do to get them to load the first time, with an empty cache? Obviously one option is to decrease the load times, and I could figure out how to do that by profiling the app, but are there other options? As I mentioned, the app is in the Kohana PHP framework, and it's running on Apache. As an aside, I've solved this problem for now by fetching the page as soon as the data is available (it comes from a batch process), so that the images are always cached by the time the user sees them. That feels like a kludgey solution to me, though, and I'm curious about what's actually going on.

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  • What's causing this permission's error and how can I work around it?

    - by Scott B
    Warning: move_uploaded_file(/home/site/public_html/wp-content/themes/mytheme/upgrader.zip) [function.move-uploaded-file]: failed to open stream: Permission denied in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phptempfile' to '/home/site/public_html/wp-content/themes/mytheme/upgrader.zip' in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 There was a problem. Sorry! Code is below for that line... // permission settings for newly created folders $chmod = 0755; // Ensures that the correct file was chosen $accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/s-compressed'); foreach($accepted_types as $mime_type) { if($mime_type == $type) { $okay = true; break; } } $okay = strtolower($name[1]) == 'zip' ? true: false; if(!$okay) { die("This upgrader requires a zip file. Please make sure your file is a valid zip file with a .zip extension"); } //mkdir($target); $saved_file_location = $target . $filename; //Next line is 79 if(move_uploaded_file($source, $saved_file_location)) { openZip($saved_file_location); } else { die("There was a problem. Sorry!"); }

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  • Need help with jQuery/AJAX call in Safari/Mac

    - by protohominid
    I've got something that works perfectly in FF and MSIE but it's not working properly in Safari. It's a form with selects that get updated via AJAX/jQuery from a MySQL DB. In Safari, when you select the first item, it correctly loads the options for the next select menu; however, when you choose one of those (which loads new options in a subsequent select menu), the whole form resets and is broken from that point on. Does anyone know of a Safari bug that would cause this? Here's the JS: $(document).ready(function(){ $("#searchForm select").change(updateSearchForm); }); function updateSearchForm() { $.ajax({ url: '/elements/search_form.php?ajax=true', data: $('#searchForm').serialize(), error:function(xhr,err){ alert("readyState: "+xhr.readyState+"\nstatus: "+xhr.status); alert("responseText: "+xhr.responseText); }, success: function(data) { $("#searchForm").html(data); $("#searchForm select").change(updateSearchForm); } }); } I can post the relevant PHP/HTML for the form, but it's lengthy. I'm relatively new to JS so I'm not sure where to start debugging this... TIA

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  • How can I debug PEAR auth?

    - by croceldon
    I have a directory on my site that I've implemented PEAR's Auth to run my authentication. It is working great. However, I've tried to make a copy of my site (it's going to be translated to a different language), and on this new site, the Auth process doesn't seem to be working correctly. I can login properly, but every time I try to go to a different page in the same directory, and use Auth to authorize, it forces me to login again. Here's my logic: $auth_options = array( 'dsn' => mysql://user:password@server/db', 'table' => 'users', 'usernamecol' => 'username', 'passwordcol' => 'password', 'db_fields' => '*' ); $auth = new Auth("DB", $auth_options, "login_function"); $auth->setFailedLoginCallback('bad_login'); $auth->start(); if (!$auth->checkAuth()) { die('cannot succeed in checkAuth') exit; } else { include("nocache.php"); } This is part of a file that's included in every php page I that I desire to require authentication. I can login properly once, but whenever I then try to go to a different page that requires authentication, it makes me login again (and I see the 'cannot succeed' die message at the bottom of the page). Again, this solution works fine on my original site, I copied all the files, and only changed the db server/password - it still doesn't work. And I'm using the same webhost for both. What am I doing wrong here? Or how can I debug this further?

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