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• Custom dynamic listview in wpf for showing combobox ?

  - by Indigo Praveen

  Hi All, I want to create an application in WPF in which I have to create a gridview kind of control and in that I'll have two columns, first column is fixed but in the second column I have to create comboboxes at runtime. For example if I have a setting like <key="Level" Value="1,2,3,4,5"/> then the first column will have Level and the second column will have a combobox with values 1,2,3,4,5. Can anyone please suggest me the right WPF control to use in this scenario and how it can be done ?

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• expand a varchar column very slowly , why?

  - by francs

  Hi We need to modify a column of a big product table , usually normall ddl statments will be excutely fast ,but the above ddl statmens takes about 10 minnutes?I wonder know the reason! I just want to expand a varchar column?The following is the detailsl --table size wapreader_log= select pg_size_pretty(pg_relation_size('log_foot_mark')); pg_size_pretty ---------------- 5441 MB (1 row) --table ddl wapreader_log= \d log_foot_mark Table "wapreader_log.log_foot_mark" Column | Type | Modifiers -------------+-----------------------------+----------- id | integer | not null create_time | timestamp without time zone | sky_id | integer | url | character varying(1000) | refer_url | character varying(1000) | source | character varying(64) | users | character varying(64) | userm | character varying(64) | usert | character varying(64) | ip | character varying(32) | module | character varying(64) | resource_id | character varying(100) | user_agent | character varying(128) | Indexes: "pk_log_footmark" PRIMARY KEY, btree (id) --alter column wapreader_log= \timing Timing is on. wapreader_log= ALTER TABLE wapreader_log.log_foot_mark ALTER column user_agent TYPE character varying(256); ALTER TABLE Time: 603504.835 ms

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• Left Join not returning all rows

  - by DisgruntledGoat

  I have this query in MySQL: SELECT pr.*, pr7.value AS `room_price_high` FROM `jos_hp_properties` pr LEFT OUTER JOIN `jos_hp_properties2` pr7 ON pr7.property=pr.id WHERE pr7.field=23 The jos_hp_properties table has 27 rows but the query only returns one. Based on this question I think it may be because of the WHERE clause. The jos_hp_properties2 table has fields id, property, field, value, where field is a foreign key to a third table (which I don't need to get data from). Is there a way to select all the rows from the first table, including the value from table #2 where the field is 23 (or NULL if there is no field 23)?

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• Trying to catch integrity error with sqlaclhemey

  - by Lostsoul

  I'm having problems with trying to catch a error. I'm using pyramid/sqlalchemy and made a sign up form with email as the primary key. The problem is when a duplicate email is entered it raises a IntegrityError, so I'm trying to catch that error and provide a message but no matter what I do I can't catch it(the error keeps appearing). try: new_user = Users(email, firstname, lastname, password) DBSession.add(new_user) return HTTPFound(location = request.route_url('new')) except IntegrityError: message1 = "Yikes! Your email already exists in our system. Did you forget your password?" I get the same message when I tried except exc.SQLAlchemyError (although I want to catch specific errors and not a blanket catch all). Is there something wrong with my python syntax? or is there something I need to do special in sqlalchemy to catch it?

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• how to demonstrate thet a protocol is certain with those specifications.

  - by kawtousse

  Hi every one, we have 4 persons A, B, C and D witch want to know the averge of their salary SA SB SC SD but no one wants that the others know his salary. For that they use this protocol: 1.A-B: [N+SA ]KB 2.B-C:[N+SA+SB]KC 3.C-D:[N+SA+SB+SC]KD 4.D-A:[N+SA+SB+SC+SD]KA where the notation [m]KY represents the message x crypted xith the public key of y Is this protocol certain. can we trust it. want you please give me justification. thanks for help.

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• Is there a way to automate MS Office applications without license?

  - by james-h-l

  I am currently writing an application that will perform automation in Excel. I have MS Office (2007) installed on my work computer and the application is working fine referencing the the Microsoft Excel 12.0 Object Lirary. The target machine has the Office installed but not registered. It is one of those preinstalled editions. Attempting to run the application on the target machine I get an error saying Office is not installed? I'm assuming then you have to have a registed Office to use the object libraries? Is there anyway around this as I do not have a Office license key lying around and its quite expensive?

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• How do i style a JSON feed in my view?

  - by stephenmurdoch

  My rails app gets the following JSON feed from mixcloud and sticks the results into my index page At the moment when I do this, the entire contents of my feed are displayed unformatted in one big blob of scary looking text (without the curly JSON brackets) I only want to display specific values from the feed in the view. From the feed in question lets say for simplicity that I just wanted to display all values with a key of "url" In case I'm doing something wrong here's my code: # podcast controller def index # I'm using a class method to get the feed @feed = Podcast.feed end # podcast model def self.feed feed = JSON.parse(open("http://api.mixcloud.com/alivefrommaryhill/feed").read) end # index.html.haml .feed = @feed I can't figure out how to style the results and display only certain items from the feed. Is my approach wrong?

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• Rails - Active Record :conditions overrides :select

  - by Nick

  I have a fairly large model and I want to retrieve only a select set of fields for each record in order to keep the JSON string I am building small. Using :select with find works great but my key goal is to use conditional logic with an associated model. Is the only way to do this really with a lamda in a named scope? I'm dreading that perhaps unnecessarily but I'd like to understand if there is a way to make the :select work with a condition. This works: @sites = Site.find :all, :select => 'id,foo,bar' When I try this: @sites = Site.find :all, :select => 'id,foo,bar', :include => [:relatedmodel], :conditions => ["relatedmodel.type in (?)", params[:filters]] The condition works but each record includes all of the Site attributes which makes my JSON string way way too large. Thanks for any pointers!

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• Table-per-type inheritance insert problem

  - by gzak

  I followed this article on making a table-per-type inheritance model for my entities, but I get the following error when I try to add an instance of a subclass to the database. Here is how I create the subtype: var cust = db.Users.CreateObject<Customer>(); // Customer inherits User db.Users.AddObject(cust); db.SaveChanges(); I get the following error when I make that last call: "A value shared across entities or associations is generated in more than one location. Check that mapping does not split an EntityKey to multiple store-generated columns." With the following inner exception: "An item with the same key has already been added." Any ideas on what I could be missing?

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• Table rows with identifying parameter in each row SQL SERVER 2008 into single row

  - by LiverpoolsNumber9

  Sorry - my question title is probably as inept at my attempt to do this. I have the following (well, similar) in a table in a CMS pageID key value 201 title Page 201's title 201 description This is 201 201 author Dave 301 title Page 301's title 301 description This is 301 301 author Bob As you've probably guessed, what I need is a query that will produce: pageID title description author 201 Page 201's title This is page 201 Dave 301 Page 301's title This is page 301 Bob If anybody could help, i'd be eternally grateful - I know this is "please send me the code" but I'm absolutely stuck. Thanks in advance.

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• Git using wrong email address when talking to Heroku

  - by David

  git clone [email protected]:myapp.git Results in a "myoldemailaddress not authorized to access myapp" myoldemailaddress was an email address I was using on an old heroku account, but it seems to be stuck using it, I can use my new one. I've removed the .heroku directory, and regenerated it, it has the correct user name and password, I can see my apps listed I've uploaded my key (I've regenerated my several times now) ssh-keygen -t rsa -C mynewaddress I uninstalled and reinstalled heroku on a different user in the same machine it works just fine. Something about my account has my old address, but I can't figure out where.

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• How to generate graphs and statistics from SQLAlchemy tables [Python]?

  - by Az

  Hi all, After running a bunch of simulations I'm going to be outputting the results into a table created using SQLAlchemy. I plan to use this data to generatw statistics - mean and variance being key. These, in turn, will be used to generate some graphs - histograms/line graphs, pie-charts and box-and-whisker plots specifically. I'm aware of the Python graphing libraries like matplotlib. The thing is, I'm not sure how to have this integrate with the information contained within the database tables. Any suggestions on how to make these two play with each other? The main problem is that I'm not sure how to supply the information as "data sets" to the graphing library. Thanks in advance.

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• How to specify a different column for a @Inheritance JPA annotation

  - by Cue

  @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Foo @Entity @Inheritance(strategy = InheritanceType.JOINED) public class BarFoo extends Foo mysql> desc foo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ mysql> desc barfoo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | | foo_id | int | | bar_id | int | +---------------+-------------+ mysql> desc bar; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ Is it possible to specify column barfo.foo_id as the joined column? Are you allowed to specify barfoo.id as BarFoo's @Id since you are overriding the getter/seeter of class Foo? I understand the schematics behind this relationship (or at least I think I do) and I'm ok with them. The reason I want an explicit id field for BarFoo is exactly because I want to avoid using a joined key (foo _id, bar _id) when querying for BarFoo(s) or when used in a "stronger" constraint. (as Ruben put it)

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• Jquery Ajax Returned Array - how to handle in Javascript

  - by user232840

  Hi there, If someone could assist me please. I'm doing a jquery Ajax post, for some reason the Json object isn't working so just returning a php array instead $.post ( "classes/RegisterUser.php", $("#frmRegistration").serialize(), function(data) { alert(data); } ); The data is returned to Javascript 100% as array ( [key]=>value [Name] => SomeOneName [Surname] => SomeOneSurName ) How would i go about getting the value of Surname in Javascript? Thanks for your assistance? Regards

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• KeyDown event is not firing second time.

  - by stackuser1

  In my masterpage, i'm having one textbox for searching purpose. if we press enterkey it is redirecting to some otherpage. But it is happening only one time. next time when i enter some text and press enter key, it is not going to the Keydown event handler. Code: javascript Code: function SearchQuestionsAndDisplay(txt, event) { if (event.keyCode == 13) { document.location = "BrowserAddOn.aspx?SearchString=" + escape(txt.value); } return false; } Text Box: onkeyup = "return SearchQuestionsAndDisplay(this,event)" CssClass="searchtxtbox" / Please suggest me what i need to do. pl let me know if there is anything missing in my code.

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• Mysql table data problem?

  - by DaTeNtImE

  I'm new to mysql and was wondering how can I add the users birthdate in the following HTML format to the MYSQL table data listed below? How would the structure look like for example email VARCHAR(80) NOT NULL,? Here is the HTML code below. <li><label>Date of Birth: </label> <label for="month">Month: </label> <select name="month" id="month"> <option value="January">January</option> <option value="February">February</option> <option value="March">March</option> <option value="April">April</option> <option value="May">May</option> <option value="June">June</option> <option value="July">July</option> <option value="August">August</option> <option value="September">September</option> <option value="October">October</option> <option value="November">November</option> <option value="December">December</option> </select> <label for="day">Day: </label> <select id="day" name="day"> <option value="0" selected="selected">Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <label for="year">Year: </label><input type="text" name="year" id="year" /></li> Here is the MySQL table data. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, first_name VARCHAR(20) NOT NULL, last_name VARCHAR(40) NOT NULL, email VARCHAR(80) NOT NULL, pass CHAR(40) NOT NULL, user_level TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, active CHAR(32), registration_date DATETIME NOT NULL, PRIMARY KEY (user_id), UNIQUE KEY (email), INDEX login (email, pass) );

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• Software protection

  - by anfono

  I want to protect my software from being used without permission. I will provide it for free to the parties I authorize to use it. Anyone knows a good protection scheme against having it copied and run by unauthorized parties ? So far, I thought about introducing a key validation mechanism: periodically, the user needs to send me (web site query) a code based on which I generate a new code that app validates against. There is an initial code, and so I can track users... Thoughts ? Later edit: I changed the licensing part to avoid unfocused discussion.

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• Django User "per project" group assignation

  - by Ben G

  Hi, Here's my problem : my site has users, which can create projects, and access other user's projects. Each project can assign different rights to users. So, i could have Project A : user "John" is in group "manager" , and Project "B" user "John" is in group "worker". How could I use the Django User authentication model to do that ? From a SQL point a view, what i would like is to be able to add "project_id" in the primary key for the "auth_user_groups" table. I don't think profile is of any help here. Any advice ? UPDATE : "worker" and "manager" are just two examples of the permission group (or "roles") that my application defines. There will be more in the future. Eg : i will probably also have "admin", "reporting", etc...

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• Sorting NSTableColumn contents

  - by Yahoo

  Hey, I have a problem with sorting NSTableColumn contents. In my NSTableView there are three columns: File, Size, Path. The contents are stored in NSMutableArray. Each object in this array is a NSDictionary containing three keys: file, size and path - value for each is a NSString. In Interface Builder, in each Table Column's attributes I can choose sorting options: Selector: IB entered "compare:" which I think is ok, because I compare NSStrings. Sort Key - and that's the problem I think - I don't know what to enter here. Any clues? If you've got questions about my code, please ask.

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• Boost multiindex complex struct

  - by StrifeLow

  In boost multiindex example complex_structs, it use one key in the car_manufacturer struct for car_table. If car_manufacturer have been modify to have 2 ID struct car_manufacturer { std::string name; int cm_code; car_manufacturer(const std::string& name_, const int& cm_code_):name(name_), cm_code(cm_code_){} }; What will be the key_from_key struct looks like? Have try to add another KeyExtractor or use composite index inside key_from_key, but still cannot compile. Please help on this. Thanks.

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• Full-Text Search in SQL Server Express Won't Recognize Latest IFilters

  - by Brandon King

  I'm having difficulty getting full-text search working in SQL Server 2008 Express with Advanced Services. I have a table loaded with .DOCX files as varbinary(MAX) data that I want to use for a full-text catalog, but it doesn't seem to recognize the .DOCX format. Here are the steps that I've taken... Installed the latest Filter Pack 2.0 Exec sp_fulltext_service 'load_os_resources', 1 Exec sys.sp_help_fulltext_system_components 'all' (NOTE: .DOCX is not shown as a filter) Building the full-text catalog fails to identify any key words I initially thought there might be a conflict between x86 SQL Express and x64 Filter Pack on my Windows 7 machine, but I just tried it with everything x86 in a Windows XP virtual machine and got the same result.

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• Hibernate: how to maintain insertion order

  - by jwaddell

  I have a list of entities where creation order is important, but they do not contain a timestamp to use for sorting. Entities are added to the end of the list as they are created so they will be ordered correctly in the list itself. After persisting the list using Hibernate the entities appear in the database table in the order that they were created. However when retrieving the list using a new Hibernate session the list is now in reverse order of insertion/creation. Is this expected behaviour? Is there any way to retrieve the list in the same order as it appears in the table? The primary key is a UUID, and the list of entities should always have been created on the same IP address and JVM. This mean sorting by UUID is a possibility but I'd rather not make assumptions. Another possibility is if the list is guaranteed to always come out in reverse order I could always just work through it backwards.

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• MySQL get row closest to NOW()

  - by Christopher McCann

  I have a table with User data such as name, address etc and another table which has a paragraph of text about the user. The reason that they are separate is because we need to record all the old about data. So if the user changes their paragraph - the old one should still be stored. Each bit of about data has a primary key aboutMeID. What I want to do is have a join that pulls their name, address etc and the latest bit of aboutMe data from the other table. I am not sure though how I can order the join to only get the latest about me data. Can someone help?

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• SQL Query in NHibernate diction

  - by Jan-Frederik Carl

  I have a SQL Query which works in SQL Management Studio: Select Id From table t Where t.Date= (Select Max(Date) From ( Select * From table where ReferenceId = xy) u) Reason is, from all entries with a certain foreign key, I want to receive the one with the highest date. I tried to reform this Query for use in NHibernate, and I got IQuery query = session.CreateQuery(String.Format( @"Select t.Id From table t Where t.Date = (Select Max(Date) From (Select * From table t where t.ReferenceItem.Id = " + item.ReferenceItem.Id + ")u)")); I get the error message: "In expected" How do I have to form the NHibernate query? What does the "In" mean?

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• Magento connect stuck while installing

  - by itsandy

  Hi Everyone, I am facing this problem while installing extensions, themes basically anything from magento connect. When I enter the extension key and click install It just gets stuck and even when it says done and I try and go back on admin page it says "There are PEAR processes running. If you will close the window or navigate away from the page, installation will be interrupted. " Has anyone faced this problem. I am working on ubuntu 9.1 and having magento 1.4. Any help would be highly appreciated. Cheers

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