Search Results

Search found 29638 results on 1186 pages for 'phone number'.

Page 578/1186 | < Previous Page | 574 575 576 577 578 579 580 581 582 583 584 585  | Next Page >

  • A leader election algorithm for an oriented hypercube

    - by mick
    I'm stuck with some problem where I have to design a leader election algorithm for an oriented hypercube. This should be done by using a tournament with a number of rounds equal to the dimension D of the hypercube. In each stage d, with 1 <= d < D two candidate leaders of neighbouring d-dimensional hypercubes should compete to become the single candidate leader of the (d+1)-dimensional hypercube that is the union of their respective hypercubes.

    Read the article

  • Why does one loop take longer to detect a shared memory update than another loop?

    - by Joseph Garvin
    I've written a 'server' program that writes to shared memory, and a client program that reads from the memory. The server has different 'channels' that it can be writing to, which are just different linked lists that it's appending items too. The client is interested in some of the linked lists, and wants to read every node that's added to those lists as it comes in, with the minimum latency possible. I have 2 approaches for the client: For each linked list, the client keeps a 'bookmark' pointer to keep its place within the linked list. It round robins the linked lists, iterating through all of them over and over (it loops forever), moving each bookmark one node forward each time if it can. Whether it can is determined by the value of a 'next' member of the node. If it's non-null, then jumping to the next node is safe (the server switches it from null to non-null atomically). This approach works OK, but if there are a lot of lists to iterate over, and only a few of them are receiving updates, the latency gets bad. The server gives each list a unique ID. Each time the server appends an item to a list, it also appends the ID number of the list to a master 'update list'. The client only keeps one bookmark, a bookmark into the update list. It endlessly checks if the bookmark's next pointer is non-null ( while(node->next_ == NULL) {} ), if so moves ahead, reads the ID given, and then processes the new node on the linked list that has that ID. This, in theory, should handle large numbers of lists much better, because the client doesn't have to iterate over all of them each time. When I benchmarked the latency of both approaches (using gettimeofday), to my surprise #2 was terrible. The first approach, for a small number of linked lists, would often be under 20us of latency. The second approach would have small spats of low latencies but often be between 4,000-7,000us! Through inserting gettimeofday's here and there, I've determined that all of the added latency in approach #2 is spent in the loop repeatedly checking if the next pointer is non-null. This is puzzling to me; it's as if the change in one process is taking longer to 'publish' to the second process with the second approach. I assume there's some sort of cache interaction going on I don't understand. What's going on?

    Read the article

  • getelementbyid does not work in firefox

    - by gaurab
    hi, this below mentioned code works perfect in internet explorer but not in firefox... i get an error in line in firefox: document.getElementById("supplier_no").value= values_array[0]; that getElementById returns null. how to solve the problem? var winName; //variable for the popup window var g_return_destination = null ; //variable to track where the data gets sent back to. // Set the value in the original pages text box. function f_set_home_value( as_Value ) { if (document.getElementById(g_return_destination[0]).name == "netbank_supplier_name_info" ) { //clear the old values for (selnum = 1; selnum <= 5; selnum++) { document.getElementById("expense_account"+selnum).value = ""; document.getElementById("expense_account_name"+selnum).value = ""; document.getElementById("expense_vat_flag"+selnum).value = "off"; document.getElementById("expense_vat_flag"+selnum).checked = ""; document.getElementById("expense_vat_amount"+selnum).value = ""; document.getElementById("expense_vat_code"+selnum).value = ""; document.getElementById("expense_period"+selnum).value = ""; document.getElementById("expense_date"+selnum).value = ""; if (selnum!=1) {//these are sometimes defaulted in, and in any case you will always have line1 document.getElementById("expense_more_dept"+selnum).value = ""; document.getElementById("expense_more_prj"+selnum).value = ""; document.getElementById("expense_more_subj"+selnum).value = ""; } document.getElementById("expense_amount"+selnum).value = ""; } var values_array = as_Value[0].split("!"); document.getElementById("supplier_no").value= values_array[0]; document.getElementById("supplier_bankAccount_no").value= values_array[1]; str = values_array[2] ; str = str.split(";sp;").join(" "); document.getElementById("default_expense_account").value= str; document.getElementById("expense_account1").value= str; document.getElementById("expense_more_sok1").disabled= false; str = values_array[3] ; str = str.split(";sp;").join(" "); document.getElementById("payment_term").value= str; strPeriod = calcPeriod(str,document.getElementById("due_date").value); document.getElementById("expense_period1").value = (strPeriod); strExpenseDate = calcExpenseDate(str,document.getElementById("due_date").value); document.getElementById("expense_date1").value = (strExpenseDate); str = values_array[4] ; str = str.split(";sp;").join(" "); document.getElementById("expense_account_name1").value= str; str = values_array[5] ; str = str.split(";sp;").join(" "); document.getElementById("expense_vat_code1").value= str; if (str == 0) { document.getElementById("expense_vat_flag1").checked= ''; document.getElementById("expense_vat_flag1").disabled= true; }else{ document.getElementById("expense_vat_flag1").checked= 'yes'; document.getElementById("expense_vat_flag1").value= 'on'; document.getElementById("expense_vat_flag1").disabled= false; } str = values_array[6] ; str = str.split(";sp;").join(" "); document.getElementById("supplier_name").value= str; var str = values_array[7]; str = str.split(";sp;").join(" "); str = str.split("&cr;").join("\r"); document.getElementById("netbank_supplier_name_info").value= str; strx = justNumberNF(document.getElementById("amount").value); document.all["expense_vat_amount1"].value = NetbankToDollarsAndCents(strx * (24/124)) ; document.getElementById("amount").value=NetbankToDollarsAndCents(strx); document.getElementById("expense_amount1").value = document.getElementById("amount").value; document.getElementById("expense_amount2").value = ''; document.getElementById("expense_account2").value= ''; //document.getElementById("expense_vat_flag2").value= ''; document.getElementById("expense_vat_amount2").value= ''; document.getElementById("expense_amount3").value = ''; document.getElementById("expense_account3").value= ''; //.getElementById("expense_vat_flag3").value= ''; document.getElementById("expense_vat_amount3").value= ''; document.getElementById("expense_amount4").value = ''; document.getElementById("expense_account4").value= ''; //document.getElementById("expense_vat_flag4").value= ''; document.getElementById("expense_vat_amount4").value= ''; document.getElementById("expense_amount5").value = ''; document.getElementById("expense_account5").value= ''; //document.getElementById("expense_vat_flag5").value= ''; document.getElementById("expense_vat_amount5").value= ''; str = values_array[8] ; str = str.split(";sp;").join(" "); if (str=="2"){ document.frmName.ButtonSelPeriodisering1.disabled=false; document.frmName.ButtonSelPeriodisering1.click(); } winName.close(); } } //Pass Data Back to original window function f_popup_return(as_Value) { var l_return = new Array(1); l_return[0] = as_Value; f_set_home_value(l_return); } function justNumberNF(val){ val = (val==null) ? 0 : val; // check if a number, otherwise try taking out non-number characters. if (isNaN(val)) { var newVal = parseFloat(val.replace(/[^\d\.\-]/g, '.')); // check if still not a number. Might be undefined, '', etc., so just replace with 0. return (isNaN(newVal) ? 0 : newVal); } // return 0 in place of infinite numbers. else if (!isFinite(val)) { return 0; } return val; }; function NetbankToDollarsAndCents(n) { var s = "" + Math.round(n * 100) / 100 ; var i = s.indexOf('.') ; if (i < 0) {return s + ",00" } ; var t = s.substring(0, i + 1) + s.substring(i + 1, i + 3) ; if (i + 2 == s.length) {t += "0"} ; return t.replace('.',',') ; }

    Read the article

  • Avoid trailing zeroes in printf()

    - by Gorpik
    I keep stumbling on the format specifiers for the printf() family of functions. What I want is to be able to print a double (or float) with a maximum given number of digits after the decimal point. If I use: printf("%1.3f", 359.01335); printf("%1.3f", 359.00999); I get 359.013 359.010 Instead of the desired 359.013 359.01 Can anybody help me?

    Read the article

  • How to extract the word and line wrapping information from JTextArea for text with given font

    - by Gábor Lipták
    I have to convert styled text to wrapped simple text (for SVG word wrapping). I cannot beleive that the word wrapping information (how many lines are there, where are the line breaks) cannot be extracted from the JTextArea. So I created a small frame program: package bla; import java.awt.BorderLayout; import java.awt.Color; import java.awt.Font; import java.awt.Frame; import java.awt.event.WindowAdapter; import java.awt.event.WindowEvent; import java.util.ArrayList; import java.util.List; import javax.swing.JTextArea; public class Example1 extends WindowAdapter { private static String content = "01234567890123456789\n" + "0123456 0123456 01234567 01234567"; JTextArea text; public Example1() { Frame f = new Frame("TextArea Example"); f.setLayout(new BorderLayout()); Font font = new Font("Serif", Font.ITALIC, 20); text = new JTextArea(); text.setFont(font); text.setForeground(Color.blue); text.setLineWrap(true); text.setWrapStyleWord(true); f.add(text, BorderLayout.CENTER); text.setText(content); // Listen for the user to click the frame's close box f.addWindowListener(this); f.setSize(100, 511); f.show(); } public static List<String> getLines( JTextArea text ) { //WHAT SHOULD I WRITE HERE return new ArrayList<String>(); } public void windowClosing(WindowEvent evt) { List<String> lines = getLines(text); System.out.println( "Number of lines:" + lines.size()); for (String line : lines) { System.out.println( line ); } System.exit(0); } public static void main(String[] args) { Example1 instance = new Example1(); } } If you run it you will see this: And what I expect as output: Number of lines:6 0123456789 0123456789 0123456 0123456 01234567 01234567 What should I write in place of the comment?

    Read the article

  • Selecting a user-defined scalar function that takes as a parameter another field

    - by ghills
    I have a table a with a list of id's, and a user-defined function foo(id) that takes the id and returns a VARCHAR(20). What I am trying to do is: SELECT id, foo(id) AS 'text field' FROM a However, instead of calling the function for each ID number, like I desired, the text comes back the same for every row. I have tested the foo() function manually with the returned ID's and it does not have that problem, so I realize I must not understand something about the evaluation of the query.

    Read the article

  • How can I run .aggregate() on a field introduced using .extra(select={...}) in a Django Query?

    - by Jake
    I'm trying to get the count of the number of times a player played each week like this: player.game_objects.extra(select={'week': 'WEEK(`games_game`.`date`)'}).aggregate(count=Count('week')) But Django complains that FieldError: Cannot resolve keyword 'week' into field. Choices are: <lists model fields> I can do it in raw SQL like this SELECT WEEK(date) as week, COUNT(WEEK(date)) as count FROM games_game WHERE player_id = 3 GROUP BY week Is there a good way to do this without executing raw SQL in Django?

    Read the article

  • barcode in PDF to Code39 conversion in C#?

    - by acadia
    Hello, I have a PDF file which contains just 1 Page. I have a barcode at the end of the page. How do I extract the barcode number from the PDF in C# I have seen a post to convert barcode Image to Code 39 but how do we do it from PDF, Please help http://stackoverflow.com/questions/204008/barcode-image-to-code39-conversion-in-c#204084 Thanks

    Read the article

  • assign subset of parent table to objects in R

    - by Brandon
    Hello, I would like to iterate through a table and break it into relvant parts based on the number of visits. I have tried several things but cannot seem to get it to work. I have included the code. for(i in 1:6){ paste("testing.visit",i,"\n",sep="") <- subset(testing,visit_no==2) } But I get the following error. Error in paste("testing.visit", i, "\n", sep = "") <- subset(testing, : target of assignment expands to non-language object Thank you, Brandon

    Read the article

  • Calculate # of Rowspans and Colspans based on keys in a Multi-Array

    - by sologhost
    Ok, I have these 2 types of layouts, basically, it can be any layout really. I have decided to use tables for this, since using div tags cause undesirable results in some possible layout types. Here are 2 pics that describe the returned results of row and column: This would return the $layout array like so: $layout[0][0] $layout[0][1] $layout[1][1] In this layout type: $layout[1][0] is NOT SET, or doesn't exist. Row 1, Column 0 doesn't exist in here. So how can we use this to help us determine the rowspans...? Ok, this layout type would now return the following: $layout[0][0] $layout[0][1] $layout[1][0] $layout[2][0] $layout[2][1] $layout[3][1] Again, there are some that are NOT SET in here: $layout[1][1] $layout[3][0] Ok, I have an array called $layout that does a foreach on the row and column, but it doesn't grab the rows and columns that are NOT SET. So I created a for loop (with the correct counts of how many rows there are and how many columns there are). Here's what I got so far: // $not_set = array(); for($x = 0; $x < $cols; $x++) { $f = 0; for($p = 0; $p < $rows; $p++) { // $f = count($layout[$p]); if(!isset($layout[$p][$x])) { $f++; // It could be a rowspan or a Colspan... // We need to figure out which 1 it is! /* $not_set[] = array( 'row' => $p, 'column' => $x, ); */ } // if ($rows - count($layout[$p])) } } Ok, the $layout array has 2 keys. The first 1 is [ row ] and the 2nd key is [ column ]. Now looping through them all and determining whether it's NOT SET, tells me that either a rowspan or a colspan needs to be put into something somewhere. I'm completely lost here. Basically, I would like to have an array returned here, something like this: $spans['row'][ row # ][ column # ] = Number of rowspans for that <td> element. $spans['column'][ row # ][ column # ] = Number of colspans for that <td> element. It's either going to need a colspan or a rowspan, it will definitely never need both for the same element. Am I going about this whole thing the wrong way? Any help at all would be greatly appreciated!! I've been driving myself crazy with this for days! Pllleaase...

    Read the article

  • "RFC 2833 RTP Event" Consecutive Events and the E "End" Bit

    - by brian_d
    Hello, I can send out a RFC 2833 dtmf event as outlined at http://www.ietf.org/rfc/rfc2833.txt When I do set the E "End" bit, but leave it as 0, I get the following behaviour: If for example keys 7874556332111111145855885#3 were pressed, then ALL events would be sent and show up in a program like wireshark, however only 87456321458585#3 would sound. So the first key (which I figure could be a separate issue) and any repeats of an event (ie 11111) are failing to sound. In section 3.9, figure 2 of the above linked document, they give a 911 example. Here all but the last event have the E bit set. When I set the bit for all numbers, I never get an event to sound. I have thought of a couple possible thing but do not know if they are the reason: 1) figure 2 shows payload types of 96 and 97 sent. I have not nor know how to exactly. In section 3.8, codes 96 and 97 are described as "the dynamic payload types 96 and 97 have been assigned for the redundancy mechanism and the telephone event payload respectively" 2) In section 3.5, "E:", "A sender MAY delay setting the end bit until retransmitting the last packet for a tone, rather than on its first transmission" Does anyone have an idea of how to actually do this? I have also fiddled around with timestamp intervals and the RTP marker. Any help is greatly appreciated. Here is a sample wireshark event capture of the relevant areas: 6590 31.159045000 xx.x.x.xxx --.--.---.-- RTP EVENT Payload type=RTP Event, DTMF Pound # (end) Real-Time Transport Protocol Stream setup by SDP (frame 6225) Setup frame: 6225 Setup Method: SDP 10.. .... = Version: RFC 1889 Version (2) ..0. .... = Padding: False ...0 .... = Extension: False .... 0000 = Contributing source identifiers count: 0 0... .... = Marker: False Payload type: telephone-event (101) Sequence number: 0 Extended sequence number: 65536 Timestamp: 0 Synchronization Source identifier: 0x15f27104 (368210180) RFC 2833 RTP Event Event ID: DTMF Pound # (11) 1... .... = End of Event: True .0.. .... = Reserved: False ..00 0000 = Volume: 0 Event Duration: 2048

    Read the article

  • Usage of open source libraries in high governance and risk-averse large organizations (banks, financ

    - by bart
    Does anyone have any good stories of these kinds of organizations being open to using open source dependencies (and also tools). Many staff I've encountered have little or no exposure to open source/systems and open source is treated with great suspicion. Some reasons given for this are lack of support and robustness, which is ironic given the number of end-of-life unsupported vendor products that are in production. I'm also interested in any success stories where you've seen open source go into orgs like this and have a real benefit!

    Read the article

  • How to create a "Clustergram" plot ? (in R)

    - by Tal Galili
    Hi all, I came across this interesting website, with an idea of a way to visualize a clustering algorithm called "Clustergram": I am not sure how useful this really is, but in order to play with it I would like to reproduce it with R, but am not sure how to go about doing it. How would you create a line for each item so it would stay consistent throughout the different number of clusters? Here is an example code/data to play with for potential answer: hc <- hclust(dist(USArrests), "ave") plot(hc)

    Read the article

  • Setting a custom XOM EntityResolver

    - by Stefan Kendall
    I need to not validate against a doctype, so I'd like to set a custom EntityResolver that accepts everything. I'm getting data back from tagsoup, so I know my data is well-formed and correct. Furthermore, I need to rapidly hit a number of documents, so when I do this with the default EntityResolver, I get 503 from w3.org. How, then, can I use a XOM builder with a custom entity resolver?

    Read the article

  • Go — variadic parameter functions weirdness

    - by ivanzoid
    I'm trying to write simple fmt.Printf wrapper which takes variable number of arguments, here is the code: func Die(format string, args ...interface{}) { str := fmt.Sprintf(format, args) fmt.Fprintf(os.Stderr, "%v\n", str) os.Exit(1) } But when I'm calling it: Die("foo") I get: foo%!(EXTRA []interface {}=[]) Can't figure why I'm getting this text after the "foo" & what is the correct way to create wrappers around fmt.Fprintf?

    Read the article

  • Bitwise Operations -- Arithmetic Operations..

    - by RBA
    Hi, Can you please explain the below lines, with some good examples. A left arithmetic shift by n is equivalent to multiplying by 2n (provided the value does not overflow), while a right arithmetic shift by n of a two's complement value is equivalent to dividing by 2n(2 to the power n) and rounding toward negative infinity. If the binary number is treated as ones' complement, then the same right-shift operation results in division by 2n and rounding toward zero. Thankx..

    Read the article

  • Opening HTML Table in Excel - numbers are getting changed

    - by nickfranceschina
    so I have this HTML table with a bunch of big numbers in it that I want to open in Excel 2007... you can follow along at home: <table> <tr> <td>this is a big number</td> </tr><tr> <td>1111111</td> </tr><tr> <td>2335322864</td> </tr><tr> <td>23353228641</td> </tr><tr> <td>233532286418</td> </tr><tr> <td>2335322864187</td> </tr><tr> <td>23353228641877</td> </tr><tr> <td>233532286418777</td> </tr><tr> <td>2335322864187774</td> </tr><tr> <td>23353228641877745</td> </tr><tr> <td>233532286418777456</td> </tr><tr> <td>2335322864187774562</td> </tr><tr> <td>23353228641877745623</td> </tr><tr> <td>233532286418777456238</td> </tr> when I open this file in Excel it starts converting those numbers to scientific notation when they get over 10 digits in length... and in doing so, it starts changing the actual number and replaces least significant digits to zeros how can I tell Excel not to do this?

    Read the article

  • build notification in visual Studio 2008\2010 - WMI etc

    - by AWC
    I want to be notified when a build has been completed\failed in visual studio and I DO NOT want to use pre\post build steps, I want an external process or VS plugin that will count the number of builds. So is there anyway to achieve this using something like WMI or other such technology? I'm not interested in third party libaries, I want to write a plugin for visual studio.

    Read the article

  • Simple question on ASM 8086

    - by Tal
    Hello ,I'm studying ASM 8086 at high school and I have this question: For example I have this number ABCD(hex), how is it stored on the memory? Does the AB go for example to memory address 01 and the CD goes to address 02? Thank you :-)

    Read the article

  • What is your solution to the FizzBuzz problem?

    - by saniul
    See here Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz". Disclaimer: I do realize this is easy, and I understand the content of the Coding Horror post I just linked to

    Read the article

  • Visual Studio 2008 marks solution files as version 10.00

    - by bja
    Hi After trying out VS2010b2 also my VS2008 installation changes the versions of solution and project files to "Version 10.00". The MSBuild.exe on our CI Server does not support them. Is there a way to make VS2008 generate sln files with version number 9.00 again? I know, i can fix that manually. But each time I open a solution, the version gets changed back, which is annoying. Cheers, bja

    Read the article

< Previous Page | 574 575 576 577 578 579 580 581 582 583 584 585  | Next Page >