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  • Why is user asked to choose their workgroup?

    - by Clinton Blackmore
    We running Mac OS X Server 10.5.8 with Mac OS X 10.5.8 clients. Students use network logins to, well, log in. I've been asked to deny internet access to a specific user. I was told that a good way to do it is to create a user workgroup called "No Internet Access" and manage settings there. (Specifically, I told parental controls to allow access to no sites, and blacklisted all the installed web browsers). Now, when the user authenticates to log in, they are greeted with this dialog: Workgroups for <username> Grade 7 Students No Internet Access It is unlikely that the student would willing choose "No Internet Access" to be their base group. Looking in Workgroup Manager at the student's record, it shows their primary group ID is the grade 7 group, and "No Internet Access" is listed as another group they belong to. I looked at the managed preferences for all the computers pertaining to logins. They are set to their defaults. Specifically, the computer groups' preference for Logins - Access has the defaults: [unchecked] Ignore workgroup nesting [checked] Combine available workgroup settings Based on my reading of Tips and Tricks for Mac Administrators, this should be correct, the user should not be asked which group they belong to, and settings from all applicable groups should be applied. How can I achieve that result? Edit: I've decided to add some additional information from the Tips and Tricks for Mac Management White Paper (via Apple in Education, via the author's site). On page 21, it says: With Leopard MCX, workgroup preference settings are combined by default into a single set of values. This means that instead of having to choose between the Math, Science, or Language Arts workgroups when logging in, a user can just authenticate and be taken directly to the desktop. All the settings for each of those workgroups are composited together, providing you with all the Dock items and a composite of all the other settings. On page 40, an example is given in which settings are combined from different 'domains', one computer group, two (user) workgroups, and one individual user's settings. [When johnd logs into a leopard client,] the items staged in the Dock from left to right are: computer group, first workgroup alphabetically, second workgroup, user. Items within the workgroup are staged alphabetically. Nowhere is there an indication that groups are nested; indeed, I can see no sensible (non-flat) heirarchy for groups like Math, Science, and Language Arts. I strongly believe that there is a way to apply settings from two unrelated user workgroups such that a user of OS X 10.5.x or newer does not need to choose their workgroup. This is what I seek to achieve.

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  • Apache Simple Configuration Issue: Setting up per-user directory permission denied problem

    - by Huckphin
    Hello. I am just getting Apache 2.2 running on Fedora 13 Beta 64-bit. I am running into issues setting my per-user directory. The goal is to make localhost/~user map to /home/~user/public_html. I think that I have the permissions right because I have 755 to /home/~user, and I have 755 to /home/~user/public_html/ and I have 777 for all contents inside of /home/~user/public_html/ recursively set. My mod_userdir configuration looks like this: <IfModule mod_userdir.c> # # UserDir is disabled by default since it can confirm the presence # of a username on the system (depending on home directory # permissions). # UserDir disabled root UserDir enabled huckphin # # To enable requests to /~user/ to serve the user's public_html # directory, remove the "UserDir disabled" line above, and uncomment # the following line instead: # UserDir public_html The error that I am seeing in the error log is this: [Sat May 15 09:54:29 2010] [error] [client 127.0.0.1] (13)Permission denied: access to /~huckphin/index.html denied When I login as the apache user, I know that /~huckphin does not exist, and this is not what I want. I want it to be accessing ~huckphin, not /~huckphin. What do I need to change on my configuration for this to work? [Added after comments] Hi Andol, thank you for your suggestions. So, first off, you said that you assume that I have the userdir module enabled, but I am not sure what that means exactly. That could be part of the problem. I do have the Module loaded, using the LoadModule directive. I have this: LoadModule userdir_module modules/mod_userdir.so I also did a find on where mod_userdir is, and I found it located here: [huckphin@crhyner-workbox]/% find / . -name '*mod_userdir.so*' 2> /dev/null /usr/lib64/lighttpd/mod_userdir.so /usr/lib64/httpd/modules/mod_userdir.so Is there something else I need to enable? Also, my directory configuration was mentioned. I have uncommented the default configuration given. I have not looked into what all of the configurations mean, and this could probably explain the issue. Here is the Directory that I have for the user directories: <Directory "/home/*/public_html"> AllowOverride FileInfo AuthConfig Limit Options MultiViews Indexes SymLinksIfOwnerMatch IncludesNoExec <Limit GET POST OPTIONS> Order allow,deny Allow from all </Limit> <LimitExcept GET POST OPTIONS> Order deny,allow Deny from all </LimitExcept> </Directory>

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  • Experiencing the New Social Enterprise

    - by kellsey.ruppel(at)oracle.com
    Social media and networking tools, popularly known as Web 2.0 technologies, are rapidly transforming user expectations of enterprise systems. Many organizations are investing in these new tools to cultivate a modern user experience in an "Enterprise 2.0" environment that unlocks the full potential of traditional IT systems and fosters collaboration in key business processes. Is your organization a social enterprise? How are you using Web 2.0 and Enterprise 2.0 technologies? Read this white paper to learn how Oracle WebCenter Suite enables organizations to become social enterprises and is the modern user experience platform for the enterprise and the Web.

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  • Disallow root to su on a user which is not listed in /etc/passwd

    - by marc.riera
    Hello, on linux we autenticate users against AD. The AD users are not listed on /etc/passwd. We are about to deploy a NFS solution to mount some extra space for each group of users. If a user(A) with sudo su privileges goes to root, then he can impersonate user(B) just by su user(B) and going to the NFS. Is there any way to disallow root to su user if the user is not listed on /etc/passwd ? Thanks.

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  • How to work around the home directory changing to /root when using sudo?

    - by Nathanel Titane
    Hello everybody! With Natty coming out soon, I've been at work updating my deployment and self-config script to make my desktop on 11.04 run and look the way I want it to. One bummer is that dbus seems to have changed and does not permit, in the same manner Lucid and Maverick did, the authentication of the current user by terminal call using grep and cat. Ideally, to run the script, I would sudo -s and then launch it as # chmod +x install && ./install Instead of returning my user name.. it now returns root and applies changes to the root profile and aborts whenever paths do not correspond. Here is my script header: #!/bin/bash ON_USER=$(echo ~ | awk -F'/' '{ print $1 $2 $3 }' | sed 's/home//g') export $(grep -v "^#" ~/.dbus/session-bus/`cat /var/lib/dbus/machine-id`-0) if sudo -u $ON_USER test -z "$DBUS_SESSION_BUS_ADDRESS" ; then eval `sudo -u $ON_USER dbus-launch --sh-syntax --exit-with-session` fi RELEASE=$(lsb_release -cs) How could I make it return the actual user now that natty is coming? Thanks for the help

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  • Prevent one user from disconnecting an active remote desktop session

    - by Nick R
    I've got a server where a number of users are sharing user logins for a short period of time to prevent too many people from logging in at the same time. The users are connecting over remote desktop, but the problem is that when one user is busy doing something, another user logs in as the same user and disconnects the active session. Is there any way of preventing one user from logging in and disconnecting the same username who is already connected to somewhere else?

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  • GWT - occasional com.google.gwt.user.client.rpc.SerializationException

    - by user214984
    Hello we are haunted by occasional occurences of exceptions such as: com.google.gwt.user.client.rpc.SerializationException: Type 'xxx' was not assignable to 'com.google.gwt.user.client.rpc.IsSerializable' and did not have a custom field serializer.For security purposes, this type will not be serialized.: instance = xxx at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serialize(ServerSerializationStreamWriter.java:610) at com.google.gwt.user.client.rpc.impl.AbstractSerializationStreamWriter.writeObject(AbstractSerializationStreamWriter.java:129) at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter$ValueWriter$8.write(ServerSerializationStreamWriter.java:152) at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serializeValue(ServerSerializationStreamWriter.java:534) at com.google.gwt.user.server.rpc.RPC.encodeResponse(RPC.java:609) at com.google.gwt.user.server.rpc.RPC.encodeResponseForSuccess(RPC.java:467) at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:564) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:188) at de.softconex.travicemanager.server.TraviceManagerServiceImpl.processCall(TraviceManagerServiceImpl.java:615) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processPost(RemoteServiceServlet.java:224) at com.google.gwt.user.server.rpc.AbstractRemoteServiceServlet.doPost(AbstractRemoteServiceServlet.java:62) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.jboss.web.tomcat.filters.ReplyHeaderFilter.doFilter(ReplyHeaderFilter.java:96) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:230) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175) at org.jboss.web.tomcat.security.SecurityAssociationValve.invoke(SecurityAssociationValve.java:179) at org.jboss.web.tomcat.security.JaccContextValve.invoke(JaccContextValve.java:84) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.jboss.web.tomcat.service.jca.CachedConnectionValve.invoke(CachedConnectionValve.java:157) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:262) at org.apache.coyote.ajp.AjpAprProcessor.process(AjpAprProcessor.java:419) at org.apache.coyote.ajp.AjpAprProtocol$AjpConnectionHandler.process(AjpAprProtocol.java:378) at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1508) at java.lang.Thread.run(Thread.java:619) The application is normally running fine. The indicated class implements Serializable (the whole object graph). So far the only patterns / observations are: we seem to have the issue only when the application is used inside an iframe the problem seems to happen when a new version of the application has been deployed running firefox in privacy mode (disabling all caches etc.) doesn't fix the problem Any ideas? Holger

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  • Switching between iScroll and standard WebView Scrolling functionality

    - by Jonathan
    I'm using iScroll 4 for my rather heavy iPhone web/Phonegap app and trying to find a way to switch between iScrolls scrolling functionality and standard "native" webview scrolling, basically on click. Why I want this is described below. My app has several different subpages all in one file. Some subpages have input fields, some don't. As we all know, iScroll + input fields = you're out of luck. I've wrapped iScrolls wrapper div (and all its functionality) around the one sub page where scrolling is crucial, and where there are no input fields. The other sections, I've simply placed outside this div, which gives these no scrolling functionality at all. I've of course tried wrapping all inside the wrapper and enabling/disabling scroll (shown below) but that didn't work me at all: myScroll.disable() myScroll.enable() By placing some sub pages outside the main scrolling area / iscroll div, I've disabled both iScrolls and the standard webview scrolling (the latter - which i guess iScroll does) which leaves me with only basic basic scrolling, hence basically no scrolling at all. One can move around vertically, but once you let go of the screen with, the "scrolling" stops. Quite naturally but alas so nasty. Therefore, I'm searching for a way to enable standard webview scrolling on the sub pages placed outside of iScroll's wrapper div. I've tried different approaches such as the one above and by using: document.removeEventListener('touchmove', preventDefault, false); document.removeEventListener('touchmove', preventDefault, true); But with no success. Sorry for not providing you guys with any hard code or demos to test out for yourselves, it's simply too much code and it would be presented so out of its context, nobody would be able to debug it. So, is there a way n javascript to do this, switching between iScroll scrolling functionality and standard "native" webview scrolling? I would rather not rebuild the entire DOM framework so a solution like the one described above would be preferable.

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  • Best Practice for Shell Layout and Switching Views - Prism, SL4, On Demand Load Modules

    - by kmacmahon
    I am learning Prism, and I have a question on the best approach for the main Shell. Assuming the Shell has 2 regions: Toolbar, Main. The toolbar has 3 main buttons that each represent a different On Demand Load Module. Each of these modules currently register themselves as fitting in the Main Region. When I click one of the buttons I want to do the following: Notify any active view that its switching, with an option to cancel if there is a pending action still required. This might cascade to child views. If the action isn't cancelled then load the on demand module if it has not yet been loaded, else activate it within the region. Should these three modules all fit in the same Region or should my shell have 3 regions defined within content presenters? One of the areas I got stuck on was that when you register a view from the Module Initialize, it doesn't get added with a strongly typed name, so when I tried to determine if my view was already added to the region with GetView(viewname) it always returns null, so I end up adding another view to the region.

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  • Switching from Java to .NET from a career change point of view

    - by Joe
    Could anyone share with me their experience with switching from Java to .NET from a career point of view? I've been a Java developer for 12 years and am just getting tired of how fragmented the Java world has become. For my liking, there's just too many frameworks, tools, application servers, etc.. And it seems each new tool just adds complexity and time to even the simplest of projects. I'm not trying to start any wars - I'm just giving you the reason I ask the main question. I've read a few books on .NET and have done one WebForms job. I love the integrated environment and would like to hear how others transitioned from Java to .NET. What I mean by that is did you do it somehow as a contractor or did you join a company as a beginner .NET developer with much Java experience? Personally, I'm ready to take the leap if I can figure out how to not lose too much income in the process (Senior Java developer to beginner .NET developer). I would really appreciate hearing your stories.

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  • iPhone View Switching basics.

    - by Daniel Granger
    I am just trying to get my head around simple view switching for the iPhone and have created a simple app to try and help me understand it. I have included the code from my root controller used to switch the views. My app has a single toolbar with three buttons on it each linking to one view. Here is my code to do this but I think there most be a more efficient way to achieve this? Is there a way to find out / remove the current displayed view instead of having to do the if statements to see if either has a superclass? I know I could use a tab bar to create a similar effect but I am just using this method to help me practice a few of the techniques. -(IBAction)switchToDataInput:(id)sender{ if (self.dataInputVC.view.superview == nil) { if (dataInputVC == nil) { dataInputVC = [[DataInputViewController alloc] initWithNibName:@"DataInput" bundle:nil]; } if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:dataInputVC.view atIndex:0]; } } -(IBAction)switchToUIElements:(id)sender{ if (self.UIElementsVC.view.superview == nil) { if (UIElementsVC == nil) { UIElementsVC = [[UIElementsViewController alloc] initWithNibName:@"UIElements" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:UIElementsVC.view atIndex:0]; } } -(IBAction)switchToTotals:(id)sender{ if (self.totalsVC.view.superview == nil) { if (totalsVC == nil) { totalsVC = [[TotalsViewController alloc] initWithNibName:@"Totals" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } [self.view insertSubview:totalsVC.view atIndex:0]; } }

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  • Background color remaining when switching views

    - by Guy
    Hi Guys. I have a UIViewController named equationVC who's user interface is being programmatically created from another NSObject class called equationCon. Upon loading equationVC, a method called chooseInterface is called from the equationCon class. I have a global variable (globalVar) that points to a user defined string. chooseInterface finds a method in the equationCon class that matches the string globalVar points to. In this case, let's say that globalVar points to a string that is called "methodThatMatches." In methodThatMatches, another view controller needs to show the results of what methodThatMatches did. methodThatMatches creates a new equationVC that calls upon methodThatMatches2. As a test, each method changes the color of the background. When the application starts up, I get a purple background, but as soon as I hit backwards I get another purple screen, which should be yellow. I do not think that I am release the view properly. Can anyone help? -(void)chooseInterface { NSString* equationTemp = [globalVar stringByReplacingOccurrencesOfString:@" " withString:@""]; equationTemp = [equationTemp stringByReplacingOccurrencesOfString:@"'" withString:@""]; SEL equationName = NSSelectorFromString(equationTemp); NSLog(@"selector! %@",NSStringFromSelector(equationName)); if([self respondsToSelector:equationName]){ [self performSelector:equationName]; } } -(void)methodThatMatches{ self.equationVC.view.backgroundColor = [UIColor yellowColor]; [setGlobalVar:@"methodThatMatches2"]; EquationVC* temp = [[EquationVC alloc] init]; [[self.equationVC navigationController] pushViewController:temp animated:YES ]; [temp release]; } -(void)methodThatmatches2{ self.equationVC.view.backgroundColor = [UIColor purpleColor]; }

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  • Sharepoint user details not visible to other users

    - by richardoz
    I am managing a SharePoint site that uses Form Based Authentication. We have several generic lists, document libraries and active task lists that users can create update and delete. Users can use the people pickers to select/search for everyone. But the users cannot see other users names, email addresses etc. in display lists or the people pickers. If I log in as the site collection administrator, I can see everyones details. So I know the data is available. Updated details on this problem (non-administrators) SharePoint users cannot see other users information. Example: User A assigns a task to user B. User A creates a new task and uses the people picker to find user B. User B is only visible by the login name “bname” and any information about user B is not visible or searchable within the people picker. Once user B is assigned the task, user A no longer sees the name in the task list – even though user A created it. No modified by, created by, assigned to or owner field data is visible to non-administrator users. Facts: Extranet site is configured to use Forms Based Authentication. Intranet uses windows based authentication Users of both the intranet and extranet have the same problem All databases are local The site uses SSRS integration SharePoint WSS on Windows 2003 Std -- After activating the verbose logging it looks like SharePoint is definately asking SQL server for only the user info for the currently logged in user: SELECT TOP 6 /lots-of-columns/ FROM UserData INNER MERGE JOIN Docs AS t1 ON ( 1 = 1 AND UserData.[tp_RowOrdinal] = 0 AND t1.SiteId = UserData.tp_SiteId AND t1.SiteId = @L2 AND t1.DirName = UserData.tp_DirName AND t1.LeafName = UserData.tp_LeafName AND t1.Level = UserData.tp_Level AND t1.IsCurrentVersion = 1 AND (1 = 1) ) LEFT OUTER JOIN AllUserData AS t2 ON ( UserData.[tp_Author]=t2.[tp_ID] AND UserData.[tp_RowOrdinal] = 0 AND t2.[tp_RowOrdinal] = 0 AND ( (t2.tp_IsCurrent = 1) ) AND t2.[tp_CalculatedVersion] = 0 AND t2.[tp_DeleteTransactionId] = 0x AND t2.tp_ListId = @L3 AND UserData.tp_ListId = @L4 AND t2.[tp_Author]=162 /* this is the currently logged in user */ ) WHERE (UserData.tp_IsCurrent = 1) AND UserData.tp_SiteId=@L2 AND (UserData.tp_DirName=@DN) AND UserData.tp_RowOrdinal=0 AND ( ( (UserData.[datetime1] IS NULL ) OR (UserData.[datetime1] = @L5DTP) ) AND t1.SiteId=@L2 AND (t1.DirName=@DN) ) ORDER BY UserData.[tp_Modified] Desc, UserData.[tp_ID] Asc Again, any ideas would be appreciated.

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  • Switching to WPF, the best use of time at Visual Studio Launch 2010

    - by Stewbob
    Yes, this is a programming-related question, if a little indirectly (that's why I marked it Community Wiki right away). For better or worse, I am switching from Winforms to WPF in April. I am also going to be in attendance at the Visual Studio Launch in Las Vegas. I have a real need to get up to speed quickly in WPF, so my question is: What sessions are going to be the best use of my time? I've got some picked out already, but I'm looking for some more advice on how to wade through all the marketing fluff and get some real educational value out of these few days. I have not been to one of these events before, so I don't really know how much is marketing hype, and how much is solid content. A couple of the workshops look interesting (VPR02 and VPS02), but I don't know enough about the actual content of these to justify the extra expense right now. Any thoughts there would be appreciated. And yes, I do have WPF learning planned other than just these few days in Vegas, but since I'm going to be there anyway, I want to learn as much as I can in the time available.

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  • Switching languajes on a website with PHP

    - by jnkrois
    Hello everybody, I'm just looking for some advice. I'm creating a website that offers (at least) 2 languages. The way I'm setting it up is by using XML files for the language, PHP to retrieve the values in the XML nodes. Say you have any XML file, being loaded as follows: <?php $lang = "en"; $xmlFile = simplexml_load_file("$lang/main.xml"); ?> Once the file contents are available, I just output each node into an HTML tag like so: <li><?php echo $xmlFile->navigation->home; ?></li> which in turn is equal to : <li><a href="#">Home</a></li> as a nav bar link. Now, the way in which I'm switching languages is by changing the value of the "$lang" variable, through a "$_POST", like so: if(isset($_POST['es'])){ $lang = "es"; }elseif(isset($_POST['en'])){ $lang = "en"; } The value of the "$lang" variable is reset and the new file is loaded, loading as well all the new nodes from the new XML file, hence changing the language. I'm just wondering if there is another way to reset the "$lang" variable using something else, other than "$_POST" or "$_GET". I don't want to use query string either. I know I could use JavaScript or jQuery to achieve this, but I'd like to make the site not too dependable on JavaScript. I'd appreciate any ideas or advice. Thanks

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  • SQL problem - select accross multiple tables (user groups)

    - by morpheous
    I have a db schema which looks something like this: create table user (id int, name varchar(32)); create table group (id int, name varchar(32)); create table group_member (foobar_id int, user_id int, flag int); I want to write a query that allows me to so the following: Given a valid user id (UID), fetch the ids of all users that are in the same group as the specified user id (UID) AND have group_member.flag=3. Rather than just have the SQL. I want to learn how to think like a Db programmer. As a coder, SQL is my weakest link (since I am far more comfortable with imperative languages than declarative ones) - but I want to change that. Anyway here are the steps I have identified as necessary to break down the task. I would be grateful if some SQL guru can demonstrate the simple SQL statements - i.e. atomic SQL statements, one for each of the identified subtasks below, and then finally, how I can combine those statements to make the ONE statement that implements the required functionality. Here goes (assume specified user_id [UID] = 1): //Subtask #1. Fetch list of all groups of which I am a member Select group.id from user inner join group_member where user.id=group_member.user_id and user.id=1 //Subtask #2 Fetch a list of all members who are members of the groups I am a member of (i.e. groups in subtask #1) Not sure about this ... select user.id from user, group_member gm1, group_member gm2, ... [Stuck] //Subtask #3 Get list of users that satisfy criteria group_member.flag=3 Select user.id from user inner join group_member where user.id=group_member.user_id and user.id=1 and group_member.flag=3 Once I have the SQL for subtask2, I'd then like to see how the complete SQL statement is built from these subtasks (you dont have to use the SQL in the subtask, it just a way of explaining the steps involved - also, my SQL may be incorrect/inefficient, if so, please feel free to correct it, and point out what was wrong with it). Thanks

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  • Switching between 2 UINavigationControllers

    - by Smikey
    Hi all, I seem to have a problem switching between 2 UINavigationControllers, i.e. one which controls the main (selection) menu of my application, and the second which controls the main session (i.e. the user can't go back to the selection menu once they're started a new session). The first works just fine, but I get into trouble when trying to load the second. I have a class called GameViewController which contains the second UINavigationController instance. I set this up as usual, linking it as an IBOutlet to the delegate and setting up the NavController in the GameViewController.xib file with its 'Class' property pointing at GameScreenViewController (my main game screen), and its NIB Name property pointing to the GameScreenViewController nib file. I then create a new instance of GameViewController and load it. In IB, the navigation controller looks fine, with its View 'loaded from "GameScreenViewController"', however when the NavigationController is loaded in the game, it actually loads the GameViewController's UIWindow instance (just a blank window). I'm not sure how to make it load the Navigation Controller's view rather than its own window? Also, another quick question. When I load the second navigation controller from the first, which makes more sense to use: [self.view addSubview:gameViewController.view]; or [self presentModalViewController:gameViewController animated:YES]; Thanks for any help, much appreciated :D Michael

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  • Switching Between Cards in a CardLayout using getParent()

    - by plutoisaplanet
    Hey everyone, I am writing an application where I am using the CardLayout to swap between two panels that are placed right on top of one another. There's a JPanel called Top, and it's layout is the CardLayout. Inside this JPanel is a JPanel called CMatch. Whenever the user clicks the submit button in the CMatch panel, I want a new JPanel added to Top that is custom built based on what the user types in, and it will be shown instead of the original CMatch panel. All of this done using the CardLayout. These are all different classes in different files, however (the panel Top with CardLayout, the panel CMatch that is inside the Top panel, and the custom built panel). So i tried using the following to add the new panel to the Top panel and then have it shown: (this code takes place in the CMatch class): private void submitButtionActionPerformed(ActionEvent e) { CardLayout cl = (CardLayout)(this.getParent().getLayout()); cl.addLayoutComponent(new CChoice(), "college_choices"); cl.show(this.getParent(), "college_choices"); } However, this didn't work. So i was wondering, what am I doing wrong? Any advice is greatly appreciated, thanks!

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  • Fast modulo 3 or division algorithm?

    - by aaa
    Hello is there a fast algorithm, similar to power of 2, which can be used with 3, i.e. n%3. Perhaps something that uses the fact that if sum of digits is divisible by three, then the number is also divisible. This leads to a next question. What is the fast way to add digits in a number? I.e. 37 - 3 +7 - 10 I am looking for something that does not have conditionals as those tend to inhibit vectorization thanks

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  • Spatial Index for Rectangles With Fast Insert

    - by TheCloudlessSky
    Hello, I'm looking for a data structure that provides indexing for Rectangles. I need the insert algorithm to be as fast as possible since the rectangles will be moving around the screen (think of dragging a rectangle with your mouse to a new position). I've looked into R-Trees, R+Trees, kD-Trees, Quad-Trees and B-Trees but from my understanding insert's are usually slow. I'd prefer to have inserts at sub-linear time complexity so maybe someone can prove me wrong about either of the listed data structures. I should be able to query the data structure for what rectangles are at point(x, y) or what rectangles intersect rectangle(x, y, width, height). EDIT: The reason I want insert so fast is because if you think of a rectangle being moved around the screen, they're going to have to be removed and then re-inserted. Thanks!

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  • iPhone: fast hash function for storing web images (url) as files (hashed filenames)

    - by Stefan Klumpp
    What is a fast hash function available for the iPhone to hash web urls (images)? I'd like to store the cached web image as a file with a hash as the filename, because I suppose the raw web url could contain strange characters that could cause problems on the file system. The hash function doesn't need to be cryptographic, but it definitely needs to be fast. Example: Input: http://www.calumetphoto.com/files/iccprofiles/icc-test-image.jpg Output: 3573ed9c4d3a5b093355b2d8a1468509 This was done by using MD5(), but since I don't know much about that topic I don't know if it is overkill (- slow).

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  • How to allow multiple inputs from user using R?

    - by Juan
    For example, if I need that the user specifies the number of rows and columns of a matrix: PROMPT: Number of rows?: USER INPUT: [a number] I need that R 'waits' for the input. Then save [a number] into a variable v1. Next, PROMPT: Number of columns?: USER INPUT: [another number] Also save [another number] into a variable v2. At the end, I will have two variables (v1, v2) that will be used in the rest of the code. "readline" only works for one input at a time. I can't run the two lines together v1 <- readline("Number of rows?: ") v2 <- readline("Number of columns?: ") Any ideas or suggestions? Thank you in advance

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  • Hierarchical Data in MySQL is fast to retrieve?

    - by ajsie
    i've got a list of all countries - states - cities (- subcities/villages etc) in a XML file and to retrieve for example a state's all cities it's really quick with XML (using xml parser). i wonder, if i put all this information in mysql, is retrieving a state's all cities as fast as with XML? cause XML is designed to store hierarchical data while relational databases like mysql are not. the list contains like 500 000 entities. so i wonder if its as fast as XML using either of: Adjacency list model Nested Set model And which one should i use? Cause (theoretically) there could be unlimited levels under a state. And which is fastest for this huge dataset? Thanks!

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