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  • Creating C++ objects

    - by Phenom
    I noticed that there are two ways to create C++ objects: BTree *btree = new BTree; and BTree btree; From what I can tell, the only difference is in how class objects are accessed (. vs. - operator), and when the first way is used, private integers get initialized to 0. Which way is better, and what's the difference? How do you know when to use one or the other?

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  • Is there any syntax checker for knockout.js?

    - by YMC
    I like knockout.js, the only problem is Visual Studio knows nothing about this framework, so it does not prevent me from silly things like assigning some value to observable property with '=' operator which makes it regular property, and it's not easy to reveal at compile time and often at runtime even. I wonder is there any syntax checker/highlighter for Visual Studio 2010 that helps me prevent faults like this? What about VS 2011? It might be a great help for developers who are new to knockout. Thanks

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  • RowFilter including [ character in search string

    - by JeffC
    I fill a DataSet and allow the user to enter a search string. Instead of hitting the database again, I set the RowFilter to display the selected data. When the user enters a square bracket ( "[" ) I get an error "Error in Like Operator". I know there is a list of characters that need prefixed with "\" when they are used in a field name, but how do I prevent RowFilter from interpreting "[" as the beginning of a column name?

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  • Exception in MSAccess when adding datas with ' character

    - by Suryakavitha
    i am using windows forms application with MSAccess.... i got data from database table successfully but when i am trying to add data with (') character i got the exception that "OLEDB Exception: Syntax error(Missing Operator)inquery expression" ... Now how can i solve this problem? Plz tell me the solution of this problem.... all characters are accepted but apostrophe character only got error... Thanks in Advance

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  • Getting geospatial indexes to work in MongoDB 1.4.3

    - by Marcel J.
    I wanted to try geospatial indexes with MongoDB, but all I get is > db.map_nodes.find( { coodinate: { $near: [54, 10] } } ) error: { "$err" : "invalid operator: $near" } and > db.map_nodes.runCommand({geoNear:"coordinates", near:[50,50]}) { "errmsg" : "no such cmd", "bad cmd" : { "geoNear" : "coordinates", "near" : [ 50, 50 ] }, "ok" : 0 } I am using MongoDB 1.4.3. What am I doing wrong?

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  • How to change default conjunction with Lucene MultiFieldQueryParser

    - by Luke H
    I have some code using Lucene that leaves the default conjunction operator as OR, and I want to change it to AND. Some of the code just uses a plain QueryParser, and that's fine - I can just call setDefaultOperator on those instances. Unfortunately, in one place the code uses a MultiFieldQueryParser, and calls the static "parse" method (taking String, String[], BooleanClause.Occur[], Analyzer), so it seems that setDefaultOperator can't help, because it's an instance method. Is there a way to keep using the same parser but have the default conjunction changed?

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  • How could a quine in my programming language look?

    - by ads
    I have created a turing-complete programming language (already proven) so it must be possible to write a quine for it, right? But all quines I know store their source code in a string and then replace a special character in it using something like chr and ord. My language only has the following Basic arithmetics Int and string types Variables == operator Conditional gotos I have no idea how I could write a quine as I have no real string manipulation available, I can only output constant strings. Yet, it is 100% turing-complete.

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  • Problem of * in Command line argument

    - by Nithya
    Hi, This is simple question only... i did a program in java that accepts input via command line arguments. I get input of two numbers and operator in command line. multiplying two numbers, i have to give input as 5 3 *. But if i give like this, i cant get answer. Y its not accept * in cmd.... waiting for reply guys...

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  • ASP.Net check value with DBNULL

    - by c11ada
    hey all, i have the following code foreach (DataRowView dr in Data) { if (dr == System.DBNull.Value) { nedID = 1; } } but i get the following error Operator '==' cannot be applied to operands of type 'System.Data.DataRowView' and 'System.DBNull' please can some one advice me on how i can check if the value is null or DBNULL

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  • I'm capturing keys on my WinForm but I'm trying to see if the pressed key is a 'String' - getting an

    - by Sergio Tapia
    Here's my code: void gkh_KeyDown(object sender, KeyEventArgs e) { if (e.KeyCode == neededLetter as Keys) { if (neededLetter == "n") { neededLetter = "o"; } else if (neededLetter == "o") { neededLetter = "t"; } else if (neededLetter == "t") { neededLetter = "e"; } else if (neededLetter == "e") { this.Show(); } } else { neededLetter = "n"; } } I'm getting an error on the first If block: The as operator must be used with a reference type or nullable type

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  • Problem with LINQ Where Clause

    - by Krishma
    var results = from formNumber in context.DetailTM join c in context.ClaimPeriodTM on formNumber.ClaimPeriod equals c.Cid where formNumber.FormNumber.StartsWith(fNumber) && formNumber.RegistrationNumber != registrationNumber select new { RegNo = formNumber.RegistrationNumber, CP = c.ClaimPeriod, FormNo = formNumber.FormNumber }; The AND CLAUSE with .STARTSWITH Doesn't work. If I use == operator the query works fine. I tried adding brackets to the where clause but it didn't help. Any idea what is missing. Thank you in Advance.

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  • Strange declaration(templates). C++

    - by atch
    Hi, guys could anyone explain to my like to a not very inteligent child what is declared here: (this is taken from another post on this forum) template<typename C> static char (&f(ChT<int Fallback::*, &C::x>*))[1]; how I read it is: template of static function f called with (ChT*) but then I can't make sense why is there address of operator and why is there array? When explaining please picture not very inteligent child and then try to make it clear to it. Thanks for any help

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  • Uses of a C++ Arithmetic Promotion Header

    - by OlduvaiHand
    I've been playing around with a set of templates for determining the correct promotion type given two primitive types in C++. The idea is that if you define a custom numeric template, you could use these to determine the return type of, say, the operator+ function based on the class passed to the templates. For example: // Custom numeric class template <class T> struct Complex { Complex(T real, T imag) : r(real), i(imag) {} T r, i; // Other implementation stuff }; // Generic arithmetic promotion template template <class T, class U> struct ArithmeticPromotion { typedef typename X type; // I realize this is incorrect, but the point is it would // figure out what X would be via trait testing, etc }; // Specialization of arithmetic promotion template template <> class ArithmeticPromotion<long long, unsigned long> { typedef typename unsigned long long type; } // Arithmetic promotion template actually being used template <class T, class U> Complex<typename ArithmeticPromotion<T, U>::type> operator+ (Complex<T>& lhs, Complex<U>& rhs) { return Complex<typename ArithmeticPromotion<T, U>::type>(lhs.r + rhs.r, lhs.i + rhs.i); } If you use these promotion templates, you can more or less treat your user defined types as if they're primitives with the same promotion rules being applied to them. So, I guess the question I have is would this be something that could be useful? And if so, what sorts of common tasks would you want templated out for ease of use? I'm working on the assumption that just having the promotion templates alone would be insufficient for practical adoption. Incidentally, Boost has something similar in its math/tools/promotion header, but it's really more for getting values ready to be passed to the standard C math functions (that expect either 2 ints or 2 doubles) and bypasses all of the integral types. Is something that simple preferable to having complete control over how your objects are being converted? TL;DR: What sorts of helper templates would you expect to find in an arithmetic promotion header beyond the machinery that does the promotion itself?

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  • Different behavior of functors (copies, assignments) in VS2010 (compared with VS2005)

    - by Patrick
    When moving from VS2005 to VS2010 we noticed a performance decrease, which seemed to be caused by additional copies of a functor. The following code illustrates the problem. It is essential to have a map where the value itself is a set. On both the map and the set we defined a comparison functor (which is templated in the example). #include <iostream> #include <map> #include <set> class A { public: A(int i, char c) : m_i(i), m_c(c) { std::cout << "Construct object " << m_c << m_i << std::endl; } A(const A &a) : m_i(a.m_i), m_c(a.m_c) { std::cout << "Copy object " << m_c << m_i << std::endl; } ~A() { std::cout << "Destruct object " << m_c << m_i << std::endl; } void operator= (const A &a) { m_i = a.m_i; m_c = a.m_c; std::cout << "Assign object " << m_c << m_i << std::endl; } int m_i; char m_c; }; class B : public A { public: B(int i) : A(i, 'B') { } static const char s_c = 'B'; }; class C : public A { public: C(int i) : A(i, 'C') { } static const char s_c = 'C'; }; template <class X> class compareA { public: compareA() : m_i(999) { std::cout << "Construct functor " << X::s_c << m_i << std::endl; } compareA(const compareA &a) : m_i(a.m_i) { std::cout << "Copy functor " << X::s_c << m_i << std::endl; } ~compareA() { std::cout << "Destruct functor " << X::s_c << m_i << std::endl; } void operator= (const compareA &a) { m_i = a.m_i; std::cout << "Assign functor " << X::s_c << m_i << std::endl; } bool operator() (const X &x1, const X &x2) const { std::cout << "Comparing object " << x1.m_i << " with " << x2.m_i << std::endl; return x1.m_i < x2.m_i; } private: int m_i; }; typedef std::set<C, compareA<C> > SetTest; typedef std::map<B, SetTest, compareA<B> > MapTest; int main() { int i = 0; std::cout << "--- " << i++ << std::endl; MapTest mapTest; std::cout << "--- " << i++ << std::endl; SetTest &setTest = mapTest[0]; std::cout << "--- " << i++ << std::endl; } If I compile this code with VS2005 I get the following output: --- 0 Construct functor B999 Copy functor B999 Copy functor B999 Destruct functor B999 Destruct functor B999 --- 1 Construct object B0 Construct functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Destruct functor C999 Destruct object B0 Destruct functor C999 Destruct object B0 --- 2 If I compile this with VS2010, I get the following output: --- 0 Construct functor B999 Copy functor B999 Copy functor B999 Destruct functor B999 Destruct functor B999 --- 1 Construct object B0 Construct functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy functor C999 Assign functor C999 Assign functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy functor C999 Assign functor C999 Assign functor C999 Destruct functor C999 Destruct functor C999 Destruct object B0 Destruct functor C999 Destruct object B0 --- 2 The output for the first statement (constructing the map) is identical. The output for the second statement (creating the first element in the map and getting a reference to it), is much bigger in the VS2010 case: Copy constructor of functor: 10 times vs 8 times Assignment of functor: 2 times vs. 0 times Destructor of functor: 10 times vs 8 times My questions are: Why does the STL copy a functor? Isn't it enough to construct it once for every instantiation of the set? Why is the functor constructed more in the VS2010 case than in the VS2005 case? (didn't check VS2008) And why is it assigned two times in VS2010 and not in VS2005? Are there any tricks to avoid the copy of functors? I saw a similar question at http://stackoverflow.com/questions/2216041/prevent-unnecessary-copies-of-c-functor-objects but I'm not sure that's the same question. Thanks in advance, Patrick

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  • deleting an object

    - by Nima
    Hi, First, when you want to free the memory assigned to an object in C++, which one is preferred? Explicitly calling deconstructor or using delete? Object* object = new Object(...); ... delete object; OR object->~Object(); Second, does the delete operator call the deconstructor implicitly? Thanks,

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  • MSIL inspection

    - by Frank Schwieterman
    I have some MSIL in byte format (result of reflection's GetMethodBody()) that I'd like to analyze a bit. I'd like to find all classes created with the new operator in the MSIL. Any ideas on how to do that programmatically?

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  • Objective-C Decimal to Base 16 Hex conversion

    - by JustinXXVII
    Does anyone have a code snippet or a class that will take a long long and turn it into a 16 byte Hex string? I'm looking to turn data like this long long decimalRepresentation = 1719886131591410351; and turn it into this //Base 16 Hex Output: 17DE435307A07300 The %x operator doesn't want to work for me NSLog(@"Hex: %x",decimalRepresentation); //console : "Hex: 7a072af" As you can see that's not even close. Any help is truly appreciated!

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