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  • Daily/Weekly/Monthly Record Count Search via StoredProcedure

    - by user270960
    Using MS SQL Server.I have made a Stored Procedure naming "SP_Get_CallsLogged". I have a table named "TRN_Call", and it has one column named "CallTime" which is a DateTime. I have a web-page in my application where the User enters:- 1.StartDate (DateTime) 2.EndDate (DateTime) 3.Period(Daily/Weekly/Monthly) (varchar) (from DropDownList) I want to get the Record Count of those calls in my table *TRN_Call* on the basis of the specified Period(Daily/Weekly/Monthly) selected by user in the DropDownList. e.g. StartDate ='1/18/2010 11:10:46 AM' EndDate ='1/25/2010 01:10:46 AM' Period =Daily So the record count between these above mentioned dates(StartDate+EndDate) should come in a manner so that I can refer to those counts separately i.e. the following:- Date 1/18/2010 Records Found 5 Date 1/19/2010 Records Found 50 Date 1/20/2010 Records Found 15 Date 1/21/2010 Records Found 32 Date 1/22/2010 Records Found 12 Date 1/23/2010 Records Found 15 Date 1/24/2010 Records Found 17 Date 1/25/2010 Records Found 32 and send those Counts to the Web Application so that these counts could be listed then in the Crystal Reports.

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  • Fast word count function in Vim

    - by Greg Sexton
    I am trying to display a live word count in the vim statusline. I do this by setting my status line in my .vimrc and inserting a function into it. The idea of this function is to return the number of words in the current buffer. This number is then displayed on the status line. This should work nicely as the statusline is updated at just about every possible opportunity so the count will always remain 'live'. The problem is that the function I have currently defined is slow and so vim is obviously sluggish when it is used for all but the smallest files; due to this function being executed so frequently. In summary, does anyone have a clever trick for producing a function that is blazingly fast at calculating the number of words in the current buffer and returning the result?

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  • WCF high instance count: anyone knows negative sideffects?

    - by Alex
    Hi there! Did anyone experience or know of negative side effects from having a high service instance count like 60k? Aside from the memory consumption of course. I am planning to increase the threshold for the maximum allowed instance count in our production environments. I am basically sick of severe production incidents just because "something" forgot to close a proxy properly. I plan to go to something like 60k instances which will allow the service to survive using default session timeouts at a call rate average for our clients. Thanks, Alex

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  • IN R counting hierarchical data

    - by Alison
    I have a list of counties in each state that received nonattainment status in years 1995-2005. I want to know how many counties in each state each year that received this status. If my data is formatted like this, State1 Country1 YR1 Yr2 Yr3 Yr4... State1 Country2 YR1 Yr2 Yr3 Yr4 State2 County1 Yr1 Yr2..... Each year variable could have a 1 or a zero, since a county may gain or loose this status in a time period. I need to count each year how many counties in each state have nonattainment status (YRx=1), but can't think of how to do it.

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  • VB working with SQL DB - end of row count, keeps looping

    - by Tramd
    I'm adding to a combo box an ID and a name that i'm pulling from a database. My problem is that for some reason my loop doesnt end once it reaches the end of the records in the database table. Here's my code: For intcount = 0 To dtOrders.Rows.Count - 1 cmbSearch.Items.Add(dtOrders.Rows(intcount)("EmployeeID").ToString & " " & dtOrders.Rows(intcount)("EmployeeLastName").ToString & ", " & dtOrders.Rows(intcount)("EmployeeFirstName").ToString) Next Shouldnt the .rows.count - 1 stop it once it reaches the last record? It loops 4 times through.

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  • Count how many divs has a specific content?

    - by David
    I want to count how many divs with the class .tool that contain the following html by example : <b>Photoshop</b> <div class="tool"><b>After Effects</b></div> <div class="tool"><b>Photoshop</b></div> <div class="tool"><b>Illustrator</b></div> <div class="tool"><b>Photoshop</b></div> <div class="tool"><b>Photoshop</b></div> // This would return 3 How to do that using jQuery? i only can count all .tool divs? Thanks

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  • Facebook API returning wrong unread thread count

    - by houbysoft
    I'm trying to query the thread FQL table to get all unread messages, and also the count of unread items in the thread. This is how I query the table: SELECT thread_id,updated_time,snippet,snippet_author,unread FROM thread WHERE folder_id=0 AND unread!=0 From reading the doc to which I linked above, it seems to me that unread should include the count of unread messages in the thread. However, I just tested the above call and Facebook gives me back a value of unread=1, despite the thread in question having 4 unread items. This is how the thread looks on facebook.com (notice the (4), showing that unread should be 4): This is what the API returns to me, which is wrong (notice the "unread":1): { "data":[ { "name":"messages", "fql_result_set":[ { "thread_id":"BLAH BLAH BLAH", "updated_time":1333317140, "snippet":"BLAH BLAH BLAH", "snippet_author":BLAH, "unread":1 } ] } ] } Am I doing something wrong, or is this a bug?

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  • Lines-of-code counting for many C# solutions

    - by Eric
    I am currently researching a solution for counting lines of code in C#. I pretty much need a combination of the following two tools: http://richnewman.wordpress.com/2007/07/01/c-and-vbnet-line-count-utility/ http://www.locmetrics.com/index.html My problem is that I need to recursively scan a folder containing a lot of visual studio solutions. So can't really use the first tool without any major work on its code, as it's only able to scan a single solution at a time. But I also need to split the results for each solution, preferably even the contained projects. This disqualifies the second tool I found. I also found NDepend which suffers from the same problem. Do you know of any free tools that do what I need? I am unable to find anything suitable.

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  • What is a SQL statement that can tally up the counts even including the Zeros? (all in 1 statement)

    - by Jian Lin
    A SQL statement can give a list of the most popular gifts that are sent in a Social application, all the way to the ones that are sent 1, or 2 times, but it won't include the Zeros. I think the same goes for getting the list of the most popular Classes that students are registering for, when the registration process for all students is 10 days and now it is the 3rd day. Again, we get the count but the Zeros are not there. Is there a simple SQL statement that can show the whole list, including the zeros?

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  • Pig: Count number of keys in a map

    - by Donald Miner
    I'd like to count the number of keys in a map in Pig. I could write a UDF to do this, but I was hoping there would be an easier way. data = LOAD 'hbase://MARS1' USING org.apache.pig.backend.hadoop.hbase.HBaseStorage( 'A:*', '-loadKey true -caching=100000') AS (id:bytearray, A_map:map[]); In the code above, I want to basically build a histogram of id and how many items in column family A that key has. In hoping, I tried c = FOREACH data GENERATE id, COUNT(A_map); but that unsurprisingly didn't work. Or, perhaps someone can suggest a better way to do this entirely. If I can't figure this out soon I'll just write a Java MapReduce job or a Pig UDF.

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  • Convert Java program to C

    - by imicrothinking
    I need a bit of guidance with writing a C program...a bit of quick background as to my level, I've programmed in Java previously, but this is my first time programming in C, and we've been tasked to translate a word count program from Java to C that consists of the following: Read a file from memory Count the words in the file For each occurrence of a unique word, keep a word counter variable Print out the top ten most frequent words and their corresponding occurrences Here's the source program in Java: package lab0; import java.io.File; import java.io.FileReader; import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; public class WordCount { private ArrayList<WordCountNode> outputlist = null; public WordCount(){ this.outputlist = new ArrayList<WordCountNode>(); } /** * Read the file into memory. * * @param filename name of the file. * @return content of the file. * @throws Exception if the file is too large or other file related exception. */ public char[] readFile(String filename) throws Exception{ char [] result = null; File file = new File(filename); long size = file.length(); if (size > Integer.MAX_VALUE){ throw new Exception("File is too large"); } result = new char[(int)size]; FileReader reader = new FileReader(file); int len, offset = 0, size2read = (int)size; while(size2read > 0){ len = reader.read(result, offset, size2read); if(len == -1) break; size2read -= len; offset += len; } return result; } /** * Make article word by word. * * @param article the content of file to be counted. * @return string contains only letters and "'". */ private enum SPLIT_STATE {IN_WORD, NOT_IN_WORD}; /** * Go through article, find all the words and add to output list * with their count. * * @param article the content of the file to be counted. * @return words in the file and their counts. */ public ArrayList<WordCountNode> countWords(char[] article){ SPLIT_STATE state = SPLIT_STATE.NOT_IN_WORD; if(null == article) return null; char curr_ltr; int curr_start = 0; for(int i = 0; i < article.length; i++){ curr_ltr = Character.toUpperCase( article[i]); if(state == SPLIT_STATE.IN_WORD){ article[i] = curr_ltr; if ((curr_ltr < 'A' || curr_ltr > 'Z') && curr_ltr != '\'') { article[i] = ' '; //printf("\nthe word is %s\n\n",curr_start); if(i - curr_start < 0){ System.out.println("i = " + i + " curr_start = " + curr_start); } addWord(new String(article, curr_start, i-curr_start)); state = SPLIT_STATE.NOT_IN_WORD; } }else{ if (curr_ltr >= 'A' && curr_ltr <= 'Z') { curr_start = i; article[i] = curr_ltr; state = SPLIT_STATE.IN_WORD; } } } return outputlist; } /** * Add the word to output list. */ public void addWord(String word){ int pos = dobsearch(word); if(pos >= outputlist.size()){ outputlist.add(new WordCountNode(1L, word)); }else{ WordCountNode tmp = outputlist.get(pos); if(tmp.getWord().compareTo(word) == 0){ tmp.setCount(tmp.getCount() + 1); }else{ outputlist.add(pos, new WordCountNode(1L, word)); } } } /** * Search the output list and return the position to put word. * @param word is the word to be put into output list. * @return position in the output list to insert the word. */ public int dobsearch(String word){ int cmp, high = outputlist.size(), low = -1, next; // Binary search the array to find the key while (high - low > 1) { next = (high + low) / 2; // all in upper case cmp = word.compareTo((outputlist.get(next)).getWord()); if (cmp == 0) return next; else if (cmp < 0) high = next; else low = next; } return high; } public static void main(String args[]){ // handle input if (args.length == 0){ System.out.println("USAGE: WordCount <filename> [Top # of results to display]\n"); System.exit(1); } String filename = args[0]; int dispnum; try{ dispnum = Integer.parseInt(args[1]); }catch(Exception e){ dispnum = 10; } long start_time = Calendar.getInstance().getTimeInMillis(); WordCount wordcount = new WordCount(); System.out.println("Wordcount: Running..."); // read file char[] input = null; try { input = wordcount.readFile(filename); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); System.exit(1); } // count all word ArrayList<WordCountNode> result = wordcount.countWords(input); long end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordcount: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); System.out.println("wordsort: running ..."); start_time = Calendar.getInstance().getTimeInMillis(); Collections.sort(result); end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordsort: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); Collections.reverse(result); System.out.println("\nresults (TOP "+ dispnum +" from "+ result.size() +"):\n" ); // print out result String str ; for (int i = 0; i < result.size() && i < dispnum; i++){ if(result.get(i).getWord().length() > 15) str = result.get(i).getWord().substring(0, 14); else str = result.get(i).getWord(); System.out.println(str + " - " + result.get(i).getCount()); } } public class WordCountNode implements Comparable{ private String word; private long count; public WordCountNode(long count, String word){ this.count = count; this.word = word; } public String getWord() { return word; } public void setWord(String word) { this.word = word; } public long getCount() { return count; } public void setCount(long count) { this.count = count; } public int compareTo(Object arg0) { // TODO Auto-generated method stub WordCountNode obj = (WordCountNode)arg0; if( count - obj.getCount() < 0) return -1; else if( count - obj.getCount() == 0) return 0; else return 1; } } } Here's my attempt (so far) in C: #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <string.h> // Read in a file FILE *readFile (char filename[]) { FILE *inputFile; inputFile = fopen (filename, "r"); if (inputFile == NULL) { printf ("File could not be opened.\n"); exit (EXIT_FAILURE); } return inputFile; } // Return number of words in an array int wordCount (FILE *filePointer, char filename[]) {//, char *words[]) { // count words int count = 0; char temp; while ((temp = getc(filePointer)) != EOF) { //printf ("%c", temp); if ((temp == ' ' || temp == '\n') && (temp != '\'')) count++; } count += 1; // counting method uses space AFTER last character in word - the last space // of the last character isn't counted - off by one error // close file fclose (filePointer); return count; } // Print out the frequencies of the 10 most frequent words in the console int main (int argc, char *argv[]) { /* Step 1: Read in file and check for errors */ FILE *filePointer; filePointer = readFile (argv[1]); /* Step 2: Do a word count to prep for array size */ int count = wordCount (filePointer, argv[1]); printf ("Number of words is: %i\n", count); /* Step 3: Create a 2D array to store words in the file */ // open file to reset marker to beginning of file filePointer = fopen (argv[1], "r"); // store words in character array (each element in array = consecutive word) char allWords[count][100]; // 100 is an arbitrary size - max length of word int i,j; char temp; for (i = 0; i < count; i++) { for (j = 0; j < 100; j++) { // labels are used with goto statements, not loops in C temp = getc(filePointer); if ((temp == ' ' || temp == '\n' || temp == EOF) && (temp != '\'') ) { allWords[i][j] = '\0'; break; } else { allWords[i][j] = temp; } printf ("%c", allWords[i][j]); } printf ("\n"); } // close file fclose (filePointer); /* Step 4: Use a simple selection sort algorithm to sort 2D char array */ // PStep 1: Compare two char arrays, and if // (a) c1 > c2, return 2 // (b) c1 == c2, return 1 // (c) c1 < c2, return 0 qsort(allWords, count, sizeof(char[][]), pstrcmp); /* int k = 0, l = 0, m = 0; char currentMax, comparedElement; int max; // the largest element in the current 2D array int elementToSort = 0; // elementToSort determines the element to swap with starting from the left // Outer a iterates through number of swaps needed for (k = 0; k < count - 1; k++) { // times of swaps max = k; // max element set to k // Inner b iterates through successive elements to fish out the largest element for (m = k + 1; m < count - k; m++) { currentMax = allWords[k][l]; comparedElement = allWords[m][l]; // Inner c iterates through successive chars to set the max vars to the largest for (l = 0; (currentMax != '\0' || comparedElement != '\0'); l++) { if (currentMax > comparedElement) break; else if (currentMax < comparedElement) { max = m; currentMax = allWords[m][l]; break; } else if (currentMax == comparedElement) continue; } } // After max (count and string) is determined, perform swap with temp variable char swapTemp[1][20]; int y = 0; do { swapTemp[0][y] = allWords[elementToSort][y]; allWords[elementToSort][y] = allWords[max][y]; allWords[max][y] = swapTemp[0][y]; } while (swapTemp[0][y++] != '\0'); elementToSort++; } */ int a, b; for (a = 0; a < count; a++) { for (b = 0; (temp = allWords[a][b]) != '\0'; b++) { printf ("%c", temp); } printf ("\n"); } // Copy rows to different array and print results /* char arrayCopy [count][20]; int ac, ad; char tempa; for (ac = 0; ac < count; ac++) { for (ad = 0; (tempa = allWords[ac][ad]) != '\0'; ad++) { arrayCopy[ac][ad] = tempa; printf("%c", arrayCopy[ac][ad]); } printf("\n"); } */ /* Step 5: Create two additional arrays: (a) One in which each element contains unique words from char array (b) One which holds the count for the corresponding word in the other array */ /* Step 6: Sort the count array in decreasing order, and print the corresponding array element as well as word count in the console */ return 0; } // Perform housekeeping tasks like freeing up memory and closing file I'm really stuck on the selection sort algorithm. I'm currently using 2D arrays to represent strings, and that worked out fine, but when it came to sorting, using three level nested loops didn't seem to work, I tried to use qsort instead, but I don't fully understand that function as well. Constructive feedback and criticism greatly welcome (...and needed)!

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  • How to get a count of ManagementObjects (WMI results) without enumerating through the collection in

    - by Mark
    When querying for large ammount of data through WMI (say the windows events log Win32_NTLogEvent) it is very useful to know what kind of numbers you are getting yourself into before downloading all the content. Is there a way two do this? From what i know there is no "Select Count(*) FROM Win32_NTLogEvent" in WQL. From what i know the Count property of the ManagementObjectCollection actually enumerates through all the results whether you have the Rewindable property set to true or false. If it cannot be done in .NET, can it be done by directly using the underlying IWbem objects Thanks

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  • Echoing a pseudo column value after a COUNT

    - by rob - not a robber
    Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

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  • MySQL date query only returns one year, when multiple exist

    - by Bowman
    I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • noob iPhone "count" frustrations!?!?!

    - by codemonkey
    Okay, I know I must be doing something incredibly stupid here. Here's the sample code (which, when executed within a viewDidLoad block silently crashes... no error output to debug console). NSMutableArray *bs = [NSMutableArray arrayWithCapacity:10]; [bs addObject:[NSNumber numberWithInteger: 2]]; NSLog(@"%@", [bs count]); [bs release]; What am I missing? Oh... and in case anyone is wondering, this code is just me trying to figure out why I can't get the count of an NSMutableArray that actually matters somewhere else in the program.

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  • ASP.net MVC3 entities, don't know how to count

    - by Spedax
    I have 2 tables, 1 with countries, 1 with states. The states table has a column with Population. I'm using entities and I have created a List of states for the countries public class TblCountries { //Entities for my table country ... public List<tblStates> States { get; set; } } So now I can for example List all the states that belong to a country. Now what I want to do is count the population, so I can show the population that of an entire country. I tried using in my view @foreach (var item in Model.Countries) { @Html.DisplayFor(modelItem => item.States.Count<population>) } But this doesn't work, anyone know how to do this? Thanks in advanced!

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  • Sql Distinct Count of resulting table with no conditionals

    - by AfterImage
    Hello everyone, I want to count the number of accounts from the resulting table generated from this code. This way, I know how many people liked blue at one time. Select Distinct PEOPLE.FullName, PEOPLE.FavColor From PEOPLE Where FavColor='Blue' Lets say this is a history accounting of what people said their favorite color when they were asked so there may be multiple records of the same full name if asked again at a much later time; hence the distinct. The code I used may not be reusable in your answer so feel free to use what you think can work. I am sure I found a possible solution to my problem using declare and if statements but I lost that page... so I am left with no solution. However, I think there is a way to do it without using conditionals which is what I am asking and rather have. Thanks. Edit: My question is: From the code above, is there a way to count the number of accounts in the resulting table?

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  • Counting vowels in a string using recursion

    - by Daniel Love Jr
    In my python class we are learning about recursion. I understand that it's when a function calls itself, however for this particular assignment I can't figure out how exactly to get my function to call it self to get the desired results. I need to simply count the vowels in the string given to the function. def recVowelCount(s): 'return the number of vowels in s using a recursive computation' vowelcount = 0 vowels = "aEiou".lower() if s[0] in vowels: vowelcount += 1 else: ??? I'm really not sure where to go with this, it's quite frustrating. I came up with this in the end, thanks to some insight from here. def recVowelCount(s): 'return the number of vowels in s using a recursive computation' vowels = "aeiouAEIOU" if s == "": return 0 elif s[0] in vowels: return 1 + recVowelCount(s[1:]) else: return 0 + recVowelCount(s[1:])

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  • show count of only configurable products of current category

    - by hs19
    hello, i want to show count of only configurable products of current category on category page. for that I have written following code... <?php $cate = Mage::registry('current_category')->getName(); $total=0; $category = Mage::registry('current_category'); $products = $category->getProductCollection(); foreach ( $products as $_product ) if ($_product->isConfigurable()) { $total++; } echo $cate."(".$total.")"; ?> my problem is the code is showing the total count of configurable products of all child categories... can anyone help me with this?

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  • Is it faster to count down than it is to count up?

    - by Bob
    Our computer science teacher once said that for some reason it is more efficient to count down that count up. For example if you need to use a FOR loop and the loop index is not used somewhere (like printing a line of N * to the screen) I mean that code like this : for (i=N; i>=0; i--) putchar('*'); is better than: for (i=0; i<N; i++) putchar('*'); Is it really true? and if so does anyone know why?

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