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• Filter on count(*) in oracle

  - by chris

  I have a grouped query, and would like to filter it based on count(*) Can I do this without a subquery? This is what I have currently: select * from (select ID, count(*) cnt from name group by ID) where cnt > 1;

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• Bind to Count of items in the DataContext

  - by Organ Grinding Monkey

  I want to bind to the Count/amount of items within my DataContext. I have an object, lets say person which has a List<address> as a property. I would like to display the amount of addresses for that person ie: 5 or 6 or whatever the case may be. I've tried {Binding Path=address#.Count} and a few others but that doesnt seem to work. Any help would be appreciated, thanks.

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• Distributing Microsoft Office Template or Macro over the network

  - by zfranciscus

  We have around 400 users who use Word and we want to make their life easier by distributing templates and macros over the network. The easiest way to do this of course to setup a shared network folder and let them get the appropriate templates and macros. Of course, each user has to know where to copy these files to in their local PC, and we have to rely on constant email communication to let them know for newer version of the macro and templates. The next alternative is to ask them to configure Word to point to these network folder. But of course any disruption to the network means disruption to their work. We are thinking to setup a synchronization mechanism that downloads new templates to their local machine. We are also thinking to make this sync tool to prompt users that it will download new templates - you know just to give them visibility that they are receiving changes. We are wondering what is the best approach that people usually use in their workplaces ? Are there any specific tool that can make this task easier ?

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• Efficient SQL to count an occurrence in the latest X rows

  - by pulegium

  For example I have: create table a (i int); Assume there are 10k rows. I want to count 0's in the last 20 rows. Something like: select count(*) from (select i from a limit 20) where i = 0; Is that possible to make it more efficient? Like a single SQL statement or something? PS. DB is SQLite3 if that matters at all...

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• cakephp COUNT items per month in a year

  - by HyperCas

  How do you use cakephp to count, for example the number of posts, made every month in a year? Preferably using Model-find('count') and get the data in an array.

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• how to count NULL categories in one SQL question

  - by grzes

  hi, i have a blog application were Post belongsTo Category and Category hasMany Post Post can have a Category or not - in latter case NULL value is present in Post.category_id field. Now i would like to have following category count with single SQL query category|post_count -------------- PHP | 2 JavaScript | 4 SomeOtherCat | 1 NULL | 3 The clue here is that i also want to count posts without category (NULL row above). Is it posibble with one SQL query?

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• Returning Null values with COUNT

  - by Randy B.

  With this query, I get a result that is two short of the table because they are not included in count, and I would like get the NULL values in the result. To do this, I am pretty sure I need to use a subquery of some kind, but I am not sure how, since the attribute in question is an aggregate. SELECT Equipment.SerialNo , Name, COUNT(Assignment.SerialNo) FROM Equipment INNER JOIN Assignment ON Assignment.SerialNo = Equipment.SerialNo GROUP BY Equipment.SerialNo, Name

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• python count number of times the date has appeared

  - by Rajeev

  From the following array,how to count the dates for the number of times it has occured in the array.The output should be in the following format [date,count] new_dates = [['2012-12-02', 14],['2012-12-03',2],....] Input: dates = [['2012-12-02', 17], ['2012-12-01', 5], ['2012-12-02', 15], ['2012-12-02', 8], ['2012-12-02', 17], ['2012-12-02', 15], ['2012-12-11', 6], ['2012-12-02', 1], ['2012-12-02', 9], ['2012-12-02', 11], ['2012-12-03', 13], ['2012-12-03', 10], ['2012-12-02', 18], ['2012-12-02', 11], ['2012-12-02', 12], ['2012-12-05', 14], ['2012-12-02', 3], ['2012-12-02', 6], ['2012-12-06', 10], ['2012-12-07', 0], ['2012-12-08', 3], ['2012-12-09', 12], ['2012-12-02', 6]]

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• Count days within a month from date range

  - by G. Muqtada

  I have three date ranges in mysql table as follow from 2013-09-29 to 2013-10-02 from 2013-10-14 to 2013-10-16 from 2013-10-28 to 2013-11-05 I want to count only days that occur in Month of October, for example from first range (2013-09-29 to 2013-10-02) I should get difference of two days (1st and 2nd October) , and it should ignore days from September month, Finally i want to count total days in a given month from above date ranges. Can it be done from direct mysql query. or any short PHP logic.

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• mySQL JOIN wont return results with 0 count

  - by MPC

  SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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• Google App Engine - Delete until count() <= 0

  - by user365918

  What is the difference between these 2 pieces of code? query=Location.all(keys_only=True) while query.count()>0: db.delete(query.fetch(5)) # -- while True: query=Location.all(keys_only=True) if not query.count(): break db.delete(query.fetch(5)) They both work.

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• SQL count distinct subnets in an IP column

  - by renhack

  I need to get a get a count of all the distinct subnets in an IP column and group by the subnet on MS SQL. ie.. count all ips that have a subnet of 192.168.0,192.168.1,10.10.10 and so on. Any help is appreciated. Thanks

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• least value in count

  - by Nyfer

  i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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• sql count() query for tables

  - by air

  i have two tables table1 fields fid,fname,fage a ,abc ,20 b ,bcv ,21 c ,cyx ,19 table2 fields rcno,fid,status 1 ,a ,ok 2 ,c ,ok 3 ,a ,ok 4 ,b ,ok 5 ,a ,ok i want to display rectors like this fid from table1 , count(recno) from table 2 and fage from table1 fid,count(recno),fage a ,3 ,20 b ,2 ,21 c ,1 ,19 i try many sql queries but got error Thanks

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• Mysql Count

  - by Buda

  I have the following query: select MIN(q.a), * FROM ( sub-query1 ) as q UNION sub-query2 How can I return the number of elements in query1 as a row of master-query? If i use count (*) i´ve only the count CountElementSub-Query1 i need some like that rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1

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• Ladder word-like game GUI problems

  - by sasquatch90

  Ok so I've written my own version of game which should look like this : http://img199.imageshack.us/img199/6859/lab9a.jpg but mine looks like that : http://img444.imageshack.us/img444/7671/98921674.jpg How can I fix this ? Is there a way to do the layout completely differently ? Here's the code : Main.java : import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.X_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); for(int i = 0; i < game.length; i++){ panel.add(game[i].create()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String tekst; while( !end ){ while( !word ){ tekst = JOptionPane.showInputDialog("Input word: "); for(int i = 0; i< game.length; i++){ if(game[i].equalLength(tekst)){ if(game[i].equalValue(tekst)){ word = true; for(int j = 0; j< game.length; j++){ game[i].repaint(); } } } } } word = false; for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Grid.java import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ private Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } public JPanel create(){ JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.PAGE_AXIS)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } @Override public void repaint(){ } public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } @Override public String toString(){ return ""; } } Element.java import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(""); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } button.setSize(20,20); return button; } public void changeState(int s){ state = s; } public String letter(){ return letter; } public int getState(){ return state; } @Override public String toString(){ return "["+letter+"]"; } }

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• Microsoft Office 2003 document (Excel and Word) intermitently, takes 30 seconds to load

  - by Julio Nobre

  I am trying to figure out why a simple .XLS EXCEL workbook is taking, randomly, 30 seconds to open. Before answering: Please, bear mind the following: Problem symptoms Hanging is intermitent and it takes exactly 30 seconds; During hanging there is no cpu or disk activity; It only happens during document load. Every runs smooth after that; Windows Explorer.exe hangs on folder, but all other folders, system and applications are still responsive; There are no consecutive hangings. I have to wait for while to reproduce this behaviour; All samples documents are located on a local drive (C:\BPI); The no document has has macros and have any addins usage; The problem does occurs on others files extensions like .PDF, for example; Office 2003 is being used for several years; The computer is running Windows XP; Computer has several network mapped drives, all addressed to main file server; Recently, main fileserver was replaced by Windows 2011 SBS Standard Edition What I have done so far I have traced machine Explorer.exe, using Process Monitor, added Duration column, and filtered by Duration 1. That's is how I found that hanging was taking exactly 30 seconds. For further information, please refer to Oliver Salzburg tutorial. Using Process Monitor, I have also figured out than five operations were taking most of sample collecting duration. Looking at sample image below, column Operation below you will notice that one single operation was taking 29 seconds; I have tried different documents (.xls and .doc), all of them smaller than 30 KB; I have, temporarily, removed all shortcuts on User Document's folder that were pointing to network drives or shares; I have runned CCleaner to fix registry issues; I made sure that there were no external links on tested workbook or word documents; I have reproduced this behaviour for hours; I have extensivelly researched for hours on the web; Process Monitor's collected and filtered data

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• Using NHibernate Criteria API to select sepcific set of data together with a count

  - by mfloryan

  I have the following domain set up for persistence with NHibernate: I am using the PaperConfiguration as the root aggregate. I want to select all PaperConfiguration objects for a given Tier and AcademicYearConfiguration. This works really well as per the following example: ICriteria criteria = session.CreateCriteria<PaperConfiguration>() .Add(Restrictions.Eq("AcademicYearConfiguration", configuration)) .CreateCriteria("Paper") .CreateCriteria("Unit") .CreateCriteria("Tier") .Add(Restrictions.Eq("Id", tier.Id)) return criteria.List<PaperConfiguration>(); (Perhaps there is a better way of doing this though). Yet also need to know how many ReferenceMaterials there are for each PaperConfiguration and I would like to get it in the same call. Avoid HQL - I already have an HQL solution for it. I know this is what projections are for and this question suggests an idea but I can't get it to work. I have a PaperConfigurationView that has, instead of IList<ReferenceMaterial> ReferenceMaterials the ReferenceMaterialCount and was thinking along the lines of ICriteria criteria = session.CreateCriteria<PaperConfiguration>() .Add(Restrictions.Eq("AcademicYearConfiguration", configuration)) .CreateCriteria("Paper") .CreateCriteria("Unit") .CreateCriteria("Tier") .Add(Restrictions.Eq("Id", tier.Id)) .SetProjection( Projections.ProjectionList() .Add(Projections.Property("IsSelected"), "IsSelected") .Add(Projections.Property("Paper"), "Paper") // and so on for all relevant properties .Add(Projections.Count("ReferenceMaterials"), "ReferenceMaterialCount") .SetResultTransformer(Transformers.AliasToBean<PaperConfigurationView>()); return criteria.List< PaperConfigurationView >(); unfortunately this does not work. What am I doing wrong? The following simplified query: ICriteria criteria = session.CreateCriteria<PaperConfiguration>() .CreateCriteria("ReferenceMaterials") .SetProjection( Projections.ProjectionList() .Add(Projections.Property("Id"), "Id") .Add(Projections.Count("ReferenceMaterials"), "ReferenceMaterialCount") ).SetResultTransformer(Transformers.AliasToBean<PaperConfigurationView>()); return criteria.List< PaperConfigurationView >(); creates this rather unexpected SQL: SELECT this_.Id as y0_, count(this_.Id) as y1_ FROM Domain.PaperConfiguration this_ inner join Domain.ReferenceMaterial referencem1_ on this_.Id=referencem1_.PaperConfigurationId The above query fails with ADO.NET error as it obviously is not a correct SQL since it is missing a group by or the count being count(referencem1_.Id) rather than (this_.Id). NHibernate mappings: <class name="PaperConfiguration" table="PaperConfiguration"> <id name="Id" type="Int32"> <column name="Id" sql-type="int" not-null="true" unique="true" index="PK_PaperConfiguration"/> <generator class="native" /> </id> <!-- IPersistent --> <version name="VersionLock" /> <!-- IAuditable --> <property name="WhenCreated" type="DateTime" /> <property name="CreatedBy" type="String" length="50" /> <property name="WhenChanged" type="DateTime" /> <property name="ChangedBy" type="String" length="50" /> <property name="IsEmeEnabled" type="boolean" not-null="true" /> <property name="IsSelected" type="boolean" not-null="true" /> <many-to-one name="Paper" column="PaperId" class="Paper" not-null="true" access="field.camelcase"/> <many-to-one name="AcademicYearConfiguration" column="AcademicYearConfigurationId" class="AcademicYearConfiguration" not-null="true" access="field.camelcase"/> <bag name="ReferenceMaterials" generic="true" cascade="delete" lazy="true" inverse="true"> <key column="PaperConfigurationId" not-null="true" /> <one-to-many class="ReferenceMaterial" /> </bag> </class> <class name="ReferenceMaterial" table="ReferenceMaterial"> <id name="Id" type="Int32"> <column name="Id" sql-type="int" not-null="true" unique="true" index="PK_ReferenceMaterial"/> <generator class="native" /> </id> <!-- IPersistent --> <version name="VersionLock" /> <!-- IAuditable --> <property name="WhenCreated" type="DateTime" /> <property name="CreatedBy" type="String" length="50" /> <property name="WhenChanged" type="DateTime" /> <property name="ChangedBy" type="String" length="50" /> <property name="Name" type="String" not-null="true" /> <property name="ContentFile" type="String" not-null="false" /> <property name="Position" type="int" not-null="false" /> <property name="CommentaryName" type="String" not-null="false" /> <property name="CommentarySubjectTask" type="String" not-null="false" /> <property name="CommentaryPointScore" type="String" not-null="false" /> <property name="CommentaryContentFile" type="String" not-null="false" /> <many-to-one name="PaperConfiguration" column="PaperConfigurationId" class="PaperConfiguration" not-null="true"/> </class>

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• C++ Sentinel/Count Controlled Loop beginning programming

  - by Bryan Hendricks

  Hello all this is my first post. I'm working on a homework assignment with the following parameters. Piecework Workers are paid by the piece. Often worker who produce a greater quantity of output are paid at a higher rate. 1 - 199 pieces completed $0.50 each 200 - 399 $0.55 each (for all pieces) 400 - 599 $0.60 each 600 or more $0.65 each Input: For each worker, input the name and number of pieces completed. Name Pieces Johnny Begood 265 Sally Great 650 Sam Klutz 177 Pete Precise 400 Fannie Fantastic 399 Morrie Mellow 200 Output: Print an appropriate title and column headings. There should be one detail line for each worker, which shows the name, number of pieces, and the amount earned. Compute and print totals of the number of pieces and the dollar amount earned. Processing: For each person, compute the pay earned by multiplying the number of pieces by the appropriate price. Accumulate the total number of pieces and the total dollar amount paid. Sample Program Output: Piecework Weekly Report Name Pieces Pay Johnny Begood 265 145.75 Sally Great 650 422.50 Sam Klutz 177 88.5 Pete Precise 400 240.00 Fannie Fantastic 399 219.45 Morrie Mellow 200 110.00 Totals 2091 1226.20 You are required to code, compile, link, and run a sentinel-controlled loop program that transforms the input to the output specifications as shown in the above attachment. The input items should be entered into a text file named piecework1.dat and the ouput file stored in piecework1.out . The program filename is piecework1.cpp. Copies of these three files should be e-mailed to me in their original form. Read the name using a single variable as opposed to two different variables. To accomplish this, you must use the getline(stream, variable) function as discussed in class, except that you will replace the cin with your textfile stream variable name. Do not forget to code the compiler directive #include < string at the top of your program to acknowledge the utilization of the string variable, name . Your nested if-else statement, accumulators, count-controlled loop, should be properly designed to process the data correctly. The code below will run, but does not produce any output. I think it needs something around line 57 like a count control to stop the loop. something like (and this is just an example....which is why it is not in the code.) count = 1; while (count <=4) Can someone review the code and tell me what kind of count I need to introduce, and if there are any other changes that need to be made. Thanks. [code] //COS 502-90 //November 2, 2012 //This program uses a sentinel-controlled loop that transforms input to output. #include <iostream> #include <fstream> #include <iomanip> //output formatting #include <string> //string variables using namespace std; int main() { double pieces; //number of pieces made double rate; //amout paid per amount produced double pay; //amount earned string name; //name of worker ifstream inFile; ofstream outFile; //***********input statements**************************** inFile.open("Piecework1.txt"); //opens the input text file outFile.open("piecework1.out"); //opens the output text file outFile << setprecision(2) << showpoint; outFile << name << setw(6) << "Pieces" << setw(12) << "Pay" << endl; outFile << "_____" << setw(6) << "_____" << setw(12) << "_____" << endl; getline(inFile, name, '*'); //priming read inFile >> pieces >> pay >> rate; // ,, while (name != "End of File") //while condition test { //begining of loop pay = pieces * rate; getline(inFile, name, '*'); //get next name inFile >> pieces; //get next pieces } //end of loop inFile.close(); outFile.close(); return 0; }[/code]

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• What format is your documentation in?

  - by Ek0nomik

  I am going to be writing documentation for two web services that I developed, and I started wondering what people on here do for documentation. Do you create it in an HTML file so it can be viewed in the browser? Word document? Wiki? What do you guys/gals use? I was originally leaning towards creating an HTML page since it seems a little more open and friendly than a word document. Plus I can use the prettify javascript to make code samples look nice. Our company has a Sharepoint though, so an HTML file may not be the best choice given that most documentation is put up in spreadsheets and word documents.

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• SQL - Count grouped entries and then get the max values grouped by date

  - by Marcus

  hello, I am out of any logic how to write the right sql statment. I've got a sqlite table holding every played track in a row with played date/time Now I will count the plays of all artists, grouped by day and then find the artist with the max playcount per day. I used this Query SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname to get this result "93"|"The Skygreen Leopards"|"2010-06-16" "2" |"Arcade Fire" |"2010-06-15" "2" |"Dead Kennedys" |"2010-06-15" "2" |"Wolf People" |"2010-06-15" "3" |"16 Horsepower" |"2010-06-15" "3" |"Alela Diane" |"2010-06-15" "46"|"Motorama" |"2010-06-15" "1" |"Ariel Pink's Haunted" |"2010-06-14" I tried then to query this virtual table but I always get false results in artistname. SELECT MAX(artistcount), artistname , day_played FROM ( SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname ) GROUP BY strftime('%Y-%m-%d',day_played) result in this "93"|"lilium" |"2010-06-16" "46"|"Wolf People"|"2010-06-15" "30"|"of Montreal"|"2010-06-14" but the artist name is false. I think through the grouping by day, it just use the last artist, or so. I tested stuff like INNER JOIN or GROUP BY ... HAVING in trial and error, I read examples of similar issues but always get lost in columnnames and stuff (I am a bit burned out) I hope someone can give me a hint. thanks m

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• C# Entity FrameWork MySQL Slow Queries Count()

  - by Matthew M.

  Hello, I'm having a serious issue with MySQL and Entity Framework 4.0. I have dropped a Table onto the EF Designer surface, and everything seems OK. However, when I perform a query in the following fashion: using(entityContext dc = new entityContext()) { int numRows = dc.myTable.Count(); } The query that is generated looks something like this: SELECT `GroupBy1`.`A1` AS `C1` FROM (SELECT Count(1) AS `A1` FROM (SELECT `pricing table`.`a`, `pricing table`.`b`, `pricing table`.`c`, `pricing table`.`d`, `pricing table`.`e`, `pricing table`.`f`, `pricing table`.`g`, `pricing table`.`h`, `pricing table`.`i` FROM `pricing table` AS `pricing table`) AS `Extent1`) AS `GroupBy1` As should be evident, this is an excruciatingly unoptimized query. It is selecting every single row! This is not optimal, nor is it even possible for me to use MySQL + EF at this point. I have tried both the MySQL 6.3.1 [that was fun to install] and DevArt's dotConnect for MySQL and both produce the same results. This table has 1.5 million records.. and takes 6-11s to execute! What am I doing wrong ? Is there any way to optimize this [and other queries] to produce sane code like: SELECT COUNT(*) FROM table ? Generating the same query using SQLServer takes virtually no time and produces sane code. Help! Thanks! Matthew

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• Ordering view by highest group count question - Ruby on Rails

  - by bgadoci

  I've read the couple of questions about this on stack overflow but can't seem to find the answer. I am trying to display the tags in my blog by the ones with the highest count in the tags table. Thanks to KandadaBoggu for helping me get the tags feature of the blog I am designing working. Here is the basics and my question. Tag belongs_to :post and Post has_many :tags. The tags table is simple really, consisting of the normal scaffolded fields plus post_id and tag_name (I actually called the column 'tag_name' instead of just 'name'). in my /views/posts/index.html/erb file I correctly am displaying the tags by group and the amount of times they are being used (appearing in the tags table). I just want to know how to order them by the highest count. Here is the code, and I currently have it set to updated_at: PostsController def index @tag_counts = Tag.count(:group => :tag_name, :order => 'updated_at DESC', :limit => 10) conditions, joins = {}, nil unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = :tags end @posts=Post.all(:joins => joins, :conditions=> conditions, :order => 'created_at DESC').paginate :page => params[:page], :per_page => 5 respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end

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• maintaining continuous count in php

  - by LiveEn

  I have a small problem maintain a count for the position. i have written a function function that will select all the users within a page and positions them in the order. Eg: Mike Position 1 Steve Postion 2.............. .... Jacob Position 30 but the problem that i have when i move to the second page, the count is started from first Eg: Jenny should be number 31 but the list goes, Jenny Position 1 Tanya Position 2....... Below is my function function nrk($duty,$page,$position) { $url="http://www.test.com/people.php?q=$duty&start=$page"; $ch=curl_init(); curl_setopt($ch,CURLOPT_URL,$url); $result=curl_exec($ch); $dom = new DOMDocument(); @$dom->loadHTML($result); $xpath=new DOMXPath($dom); $elements = $xpath->evaluate("//div"); foreach ($elements as $element) { $name = $element->getElementsByTagName("name")->item(0)->nodeValue; $position=$position+1; echo $name." Position:".$position."<br>"; } return $position; } Below is the for loop where i try to loop thru the page count for ($page=0;$page<=$pageNumb;$page=$page + 10) { nrk($duty,$page,$position); } I dont want to maintain a array key value in the for each coz i drop certain names...

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• Total row count for pagination using JPA Criteria API

  - by ThinkFloyd

  I am implementing "Advanced Search" kind of functionality for an Entity in my system such that user can search that entity using multiple conditions(eq,ne,gt,lt,like etc) on attributes of this entity. I am using JPA's Criteria API to dynamically generate the Criteria query and then using setFirstResult() & setMaxResults() to support pagination. All was fine till this point but now I want to show total number of results on results grid but I did not see a straight forward way to get total count of Criteria query. This is how my code looks like: CriteriaBuilder builder = em.getCriteriaBuilder(); CriteriaQuery<Brand> cQuery = builder.createQuery(Brand.class); Root<Brand> from = cQuery.from(Brand.class); CriteriaQuery<Brand> select = cQuery.select(from); . . //Created many predicates and added to **Predicate[] pArray** . . select.where(pArray); // Added orderBy clause TypedQuery typedQuery = em.createQuery(select); typedQuery.setFirstResult(startIndex); typedQuery.setMaxResults(pageSize); List resultList = typedQuery.getResultList(); My result set could be big so I don't want to load my entities for count query, so tell me efficient way to get total count like rowCount() method on Criteria (I think its there in Hibernate's Criteria).

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