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  • Including a Django app's url.py is resulting in a 404

    - by 828
    I have the following code in the urls.py in mysite project. /mysite/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/$', include('mysite.gallery.urls')), ) This results in a 404 page when I try to access a url set in gallery/urls.py. /mysite/gallery/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/browse/$', 'mysite.gallery.views.browse'), (r'^gallery/photo/$', 'mysite.gallery.views.photo'), ) 404 error Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^gallery/$ The current URL, gallery/browse/, didn't match any of these. Also, the site is hosted on a media temple (dv) server and using mod_wsgi

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  • trying to load css/images in django

    - by tipu
    I looked http://docs.djangoproject.com/en/dev/howto/static-files/ already, but am still confused on how to get css/image files loaded. On my server, the images folder and css file are located at /srv/twingle/search my urls.py 1 from django.conf.urls.defaults import * 2 3 # Uncomment the next two lines to enable the admin: 4 # from django.contrib import admin 5 # admin.autodiscover() 6 7 urlpatterns = patterns('twingle.search.views', 8 url(r'^$', 'index'), 9 url(r'^search/(?P<param>\w+)$', 'index'), 10 ) 11 (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', 12 {'document_root': '/srv/twingle/search'}), 13 I try to access my css as follows, <link rel="stylesheet" type="text/css" href="/site_media/style.css" /> That's exactly how the tutorial says to do it, but it doesn't work. Any suggestions?

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  • Django: how to create sites dynamically?

    - by Leandro Ardissone
    Hi, I need to create an application for the company where I can create sites dynamically. For example, I need an admin interface (Django's admin is enough) where I can setup a new site and add some settings to it. Each site must hold a domain (domains can be manually added to apache conf, but if Django can handle it too would be awesome). Each site must be independent of the others, I mean, I shouldn't be able to see the data content of other sites but I can share same applications/models. I've seen the Django's Sites framework, but I'm not sure if it's possible to implement that way. Should I use Sites framework or create a new app that can handle sites better? What do you think?

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  • server reboot has caused django project to lose directories

    - by wmfox3
    A fully functional Django project as well as a couple in development have all broken following the rebooting of the server. In addition to some pieces of the Django admin returning errors as well as missing .js and .css files, I'm getting errors like this when viewing pages that include images uploaded through the admin. Exception Type: TemplateSyntaxError Exception Value: Caught an exception while rendering: (2, 'No such file or directory') Exception Location: /usr/lib/pymodules/python2.6/django/template/debug.py in render_node, line 81 Python Executable: /usr/bin/python Python Version: 2.6.4 So did the reboot stomp on some part of my configuration/setup or did it fail to restart a critical piece?

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  • Django: automatically import MEDIA_URL in context

    - by pistacchio
    Hi, like exposed here, one can set a MEDIA_URL in settings.py (for example i'm pointing to Amazon S3) and serve the files in the view via {{ MEDIA_URL }}. Since MEDIA_URL is not automatically in the context, one have to manually add it to the context, so, for example, the following works: #views.py from django.shortcuts import render_to_response from django.template import RequestContext def test(request): return render_to_response('test.html', {}, context_instance=RequestContext(request)) This means that in each view.py file i have to add from django.template import RequestContext and in each response i have to explicitly specify context_instance=RequestContext(request). Is there a way to automatically (DRY) add MEDIA_URL to the default context? Thanks in advance.

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  • Django: url and content creation results in 500 and no apache error log entry

    - by user1684082
    If i try to open a created url i get an 500 error. My procedure was: First python manage.py startapp black I added in project/settings.py under INSTALLED_APPS 'black', I added in project/urls.py url(r'^test/', include('black.urls')), Content of black/urls.py is: from django.conf.urls import patterns, url from black import views urlpatterns = patterns('', url(r'^$', views.index, name='index') ) And content of black/views.py: from django.http import HttpResponse def index(request): return HttpResponse("SHOW ME: BLACK") After all i synced the database. I can't see any error in apache-error-log and also not in my posted django files. What could cause this?

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  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

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  • Can Django flush its database(s) between every unit test

    - by mikem
    Django (1.2 beta) will reset the database(s) between every test that runs, meaning each test runs on an empty DB. However, the database(s) are not flushed. One of the effects of flushing the database is the auto_increment counters are reset. Consider a test which pulls data out of the database by primary key: class ChangeLogTest(django.test.TestCase): def test_one(self): do_something_which_creates_two_log_entries() log = LogEntry.objects.get(id=1) assert_log_entry_correct(log) log = LogEntry.objects.get(id=2) assert_log_entry_correct(log) This will pass because only two log entries were ever created. However, if another test is added to ChangeLogTest and it happens to run before test_one, the primary keys of the log entries are no longer 1 and 2, they might be 2 and 3. Now test_one fails. This is actually a two part question: Is it possible to force ./manage.py test to flush the database between each test case? Since Django doesn't flush the DB between each test by default, maybe there is a good reason. Does anyone know?

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  • django/apache permissions problem

    - by Kevin
    I'm running a django project on Centos 5.4 and serving it with httpd/mod_wsgi. I can't figure out the correct permissions for /home/website/django_project so that I don't get a 403 error. In my httpd.conf the user and group to run httpd as is apache. The group django is set up with website and apache as members. The owner of /home/website and all subdirs is website:django, and the permissions are rwxrwx---. Right now the project works fine with the dev server, but if I try to view it through apache, I get a 403 error. chmod -R o+rx /home/website/django_project fixes the problem, but this obviously isn't a good solution. Thanks

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  • Django logging in and out - doesn't work if prepend_www set

    - by ropz
    I'm a Django beginner. My site - let's call it abc.com - works fine, letting users log in and out (having originally registered via Django registratiaon). If it's relevant, my virtuahosts file has ServerName abc.com and ServerAlias www.abc.com directives. I don't want my visitors to sense that both abc.com and www.abc.com exist, and so discovered Django's prepend_www setting, which works as intended. In addition to working as intended, however, there's a side effect that disables logging in and out when visiting the www. variant of my site.

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • How to solve 404 for static files with Django and Nginx?

    - by Lucio
    I setup a Trusty VM with Django + Nginx (other stuffs too). The server is working, I get the "Welcome to Django" page. But when I enter to servername/admin it loads the HTML page but fails to load the static content. And the admin page have this links to static content: <link rel="stylesheet" type="text/css" href="/static/admin/css/base.css" /> <link rel="stylesheet" type="text/css" href="/static/admin/css/login.css" /> Both of the CSS files give me 404, as the Nginx log shows: 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin HTTP/1.1" 301 5 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin/ HTTP/1.1" 200 833 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/base.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/login.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" I think that the error is on my nginx.conf file, but do not know how to solve it.

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  • Trouble getting SSL to work with django + nginx + wsgi

    - by Kevin
    I've followed a couple of examples for Django + nginx + wsgi + ssl, but I can't get them to work. I simply get an error in my browser than I can't connect. I'm running two websites off the host. The config files are identical except for the ip addresses, server names, and directories. When neither use SSL, they work fine. When I try to listen on 443 with one of them, I can't connect to either. My config files are below, and any suggestions would be appreciated. server{ listen xxx.xxx.xxx.xxx:80; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } server{ listen xxx.xxx.xxx.xxx:443; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; ssl on; ssl_certificate sub.domain.com.crt; ssl_certificate_key sub.domain.com.key; ssl_prefer_server_ciphers on; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Protocol https; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } <VirtualHost *:8080> ServerName xxx.xxx.xxx.xxx ServerAlias xxx.xxx.xxx.xxx LogLevel warn ErrorLog /home/django/logs/apache_customerdb_error.log CustomLog /home/django/logs/apache_customerdb_access.log combined WSGIScriptAlias / /home/django/customerdb/apache/django.wsgi WSGIDaemonProcess customerdb_wsgi processes=4 threads=5 WSGIProcessGroup customerdb_wsgi SetEnvIf X-Forwarded-Protocol "^https$" HTTPS=on </VirtualHost> UDPATE: the existence of two sites (on separate IPs) on the host is the issue. if i delete the other site, the setting above mostly work. doing so also brings up another issue: chrome doesn't accept the site as secure saying that some content is not encrypted.

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  • Django | Apache | Deploy website behind SSL

    - by planet260
    So here are my requirements. I have a website built in Django. I deployed it on Apache Ubuntu. Before there was no SSL involved so the deployment was pretty simple. But now the requirements are changed. Now I have to take a few actions like signup and login behind SSL and present the admin panel and other normally via HTTP. By following the this tutorial I have set-up Apache and SSL and generated certificates for SSL communication. But I am not sure how to proceed, ie. how to serve only a few of my actions through SSL. Below is my configuration. The normal actions are working fine but I don't know how to configure SSL calls. WSGIScriptAlias / /home/ubuntu/myproject/src/myproject/wsgi.py WSGIPythonPath /home/ubuntu/myproject/src <VirtualHost *:80> ServerName mydomain.com <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> <Location "/login"> RewriteEngine on RewriteRule /admin(.*)$ https://mydomain.com/login$1 [L,R=301] </Location> </VirtualHost> <VirtualHost *:443> ServerName mydomain.com SSLEngine on SSLOptions +StrictRequire SSLCertificateFile /etc/apache2/ssl/apache.crt SSLCertificateKeyFile /etc/apache2/ssl/apache.key <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> </VirtualHost> Can you please help me out on how to achieve this? What am I doing wrong? I have read a lot of tutorials but honestly I am not really good at configurations. Any help is appreciated.

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  • Google Analytics Views - Why Use Them?

    - by pee2pee
    I've been reading about Google Analytics views but still not sure why I would use them. I'm the only person in the company who understands and uses Google Analytics. We have no subdomains. Is there any reason why I would want to use views? Google Analytics has been going for some years now and I just created a copy of the original view but this has zero data, so I can't see how it would benefit me.

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  • SQL Server Indexed Views

    Views can be an effective tool for speeding up your selects and simplifying complex queries. Learn what indexed views are, where you might want to use them, how to create them, and what constraints exist with their use.

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  • SQL Server Indexed Views

    Views can be an effective tool for speeding up your selects and simplifying complex queries. Learn what indexed views are, where you might want to use them, how to create them, and what constraints exist with their use.

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • django multiprocess problem

    - by iKiR
    I have django application, running under lighttpd via fastcgi. FCGI running script looks like: python manage.py runfcgi socket=<path>/main.socket method=prefork \ pidfile=<path>/server.pid \ minspare=5 maxspare=10 maxchildren=10 maxrequests=500 \ I use SQLite. So I have 10 proccess, which all work with the same DB. Next I have 2 views: def view1(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param1 = <some value> obj.save () def view2(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param2 = <some value> obj.save () And If this views are executed in two different threads sometimes I get MyModel instance in DB with id=1 and updated either param1 or param2 (BUT not both) - it depends on which process was the first. (of course in real life id changes, but sometimes 2 processes execute these two views with same id) The question is: What should I do to get instance with updated param1 and param2? I need something for merging changes in different processes. One decision is create interprocess lock object but in this case I will get sequence executing views and they will not be able to be executed simultaneously, so I ask help

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  • Can't get python.manage.py syncdb to work

    - by Diego
    I just created my first django app, initialized variables DATABASE_ENGINE and DATABASE_NAME in settings.py, but now when I run python manage.py syncdb, I get the following error Can somebody help? Does this have to do with having two python versions installed? I'm a django/python noob, please help. thanks!! my-computer:~/Django-1.1.1 mycomp$ python manage.py syncdb /Library/Frameworks/Python.framework/Versions/2.6/Resources/Python.app/Contents/MacOS/Python: can't open file 'manage.py': [Errno 2] No such file or directory my-computer:~/Django-1.1.1 mycomp$ export PATH=/Users/mycomp/bin:$PATH

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  • How to serve static files for multiple Django projects via nginx to same domain

    - by thanley
    I am trying to setup my nginx conf so that I can serve the relevant files for my multiple Django projects. Ultimately I want each app to be available at www.example.com/app1, www.example.com/app2 etc. They all serve static files from a 'static-files' directory located in their respective project root. The project structure: Home Ubuntu Web www.example.com ref logs app app1 app1 static bower_components templatetags app1_project templates static-files app2 app2 static templates templatetags app2_project static-files app3 tests templates static-files static app3_project app3 venv When I use the conf below, there are no problems for serving the static-files for the app that I designate in the /static/ location. I can also access the different apps found at their locations. However, I cannot figure out how to serve all of the static files for all the apps at the same time. I have looked into using the 'try_files' command for the static location, but cannot figure out how to see if it is working or not. Nginx Conf - Only serving static files for one app: server { listen 80; server_name example.com; server_name www.example.com; access_log /home/ubuntu/web/www.example.com/logs/access.log; error_log /home/ubuntu/web/www.example.com/logs/error.log; root /home/ubuntu/web/www.example.com/; location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; } location /media/ { alias /home/ubuntu/web/www.example.com/media/; } location /app1/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app1; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app1.sock; } location /app2/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app2; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app2.sock; } location /app3/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app3; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app3.sock; } # what to serve if upstream is not available or crashes error_page 400 /static/400.html; error_page 403 /static/403.html; error_page 404 /static/404.html; error_page 500 502 503 504 /static/500.html; # Compression gzip on; gzip_http_version 1.0; gzip_comp_level 5; gzip_proxied any; gzip_min_length 1100; gzip_buffers 16 8k; gzip_types text/plain text/css application/x-javascript text/xml application/xml application/xml+rss text/javascript; # Some version of IE 6 don't handle compression well on some mime-types, # so just disable for them gzip_disable "MSIE [1-6].(?!.*SV1)"; # Set a vary header so downstream proxies don't send cached gzipped # content to IE6 gzip_vary on; } Essentially I want to have something like (I know this won't work) location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; alias /home/ubuntu/web/www.example.com/app/app2/static-files/; alias /home/ubuntu/web/www.example.com/app/app3/static-files/; } or (where it can serve the static files based on the uri) location /static/ { try_files $uri $uri/ =404; } So basically, if I use try_files like above, is the problem in my project directory structure? Or am I totally off base on this and I need to put each app in a subdomain instead of going this route? Thanks for any suggestions TLDR: I want to go to: www.example.com/APP_NAME_HERE And have nginx serve the static location: /home/ubuntu/web/www.example.com/app/APP_NAME_HERE/static-files/;

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  • Django QuerySet API: How do I join iexact and icontains?

    - by Zeynel
    Hello, I have this join: lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) This is the site If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates. But if you try First name only it says that there are no lawyers in the database called amr (obviously there is). If I change (last__iexact=last_name) to (last__icontains=last_name) then leaving Last Name blank works fine and amr is found. But with last__icontains=last_name if you search for "collin" you also get "collins" and "collingwood" which is not what I want. Do you know how I can use iexact and also have it ignored if it is blank? Thanks This is the view function: def search_form(request): if request.method == 'POST': search_form = SearchForm(request.POST) if search_form.is_valid(): last_name = search_form.cleaned_data['last_name'] first_name = search_form.cleaned_data['first_name'] lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) if len(lawyers)==0: form = SearchForm() return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form}) if len(lawyers)>1: form = SearchForm(initial={'last_name': last_name}) return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form}) q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True) q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True) lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name) form = SearchForm() return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form}) else: form = SearchForm() return render_to_response('search_form.html', {'form': form, })

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  • Is there a Django template tag that lets me set a context variable?

    - by hekevintran
    I want to be able to set variables in a template to string values. I wrote a tag, but it doesn't seem to change the context. The intended use is: {% define my_var as "a string" %} class DefineNode(Node): def __init__(self, value, variable_name, nodelist): self.value = value self.variable_name = variable_name self.nodelist = nodelist def __repr__(self): return "<DefineNode>" def render(self, context): context[self.variable_name] = self.value return '' @register.tag def define(parser, token): bits = list(token.split_contents()) if len(bits) != 4: raise TemplateSyntaxError("%r expected format is 'value as variable'" % bits[0]) if bits[1][0] in ('"', "'") and bits[1][-1] == bits[1][0]: value = bits[1][1:-1] nodelist = parser.parse(('enddefine',)) parser.delete_first_token() return DefineNode(value, bits[3], nodelist) I

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  • Display a boolean model field in a django form as a radio button rather than the default Checkbox.

    - by Lakshman Prasad
    This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

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