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  • Add the "selected" attribute to a drop down option with jQuery

    - by gaoshan88
    How do I add the attribute "selected" to a drop down menu option based on that option matching some variable? Here is how the dropdown is populated... loginOptions = ["First", "Second", "Third]; var Login = $( '#Login' ); for ( var i = 0; i < loginOptions.length; i++ ) { Login.append('<option value="'+ loginOptions[i] +'">'+ loginOptions[i] +'</option>'); } I want to mark one option as "selected" based on whether or not its value matches another variable. so if loginOption[i] is equal to var existingLoginValue then set that option to 'selected' Something that would do if(loginOptions[i] === existingLoginValue){ print 'selected'; }; Thanks!

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  • jQuery drawing and modifying lines and positions

    - by Chris
    I want to allow people to select a feature region on an image using jQuery. This should work similarly to the Facebook tagger except once someone "tags" an area of the image an ellipse should appear with the ability for the user to rotate and scale it. How can I achieve this using jQuery?

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  • Need help with jquery ui slider

    - by Gandalf StormCrow
    I'm trying to create this slider http://jqueryui.com/demos/slider/#rangemax Is it possible to parametrize the max value? For ex: $("#slider-range-max").slider({ range: "max", min: 1, max: maxValue, value: 2, slide: function(event, ui) { $("#amount").val(ui.value); } }); Is it possible to pass maxValue value, when I click on something ?After its been initialized? not on document ready function, after that?

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  • How to read from CSS files with jQuery

    - by Neurofluxation
    Ok, I have a HTML page with jQuery included. I have a CSS file with a good load of lines in, I would like to read all styles for a given element from the external CSS file... Not the inline styles... I have the following code (which looks like it should work...): var styleProperties= {}; var getCssProperties = ['width', 'margin', 'height']; for (c=0;i<=returnStyleProps.length;c++) { styleProperties[returnStyleProps[c]] = $('div#container').css(returnStyleProps[c]); alert(styleProperties); } alert(styleProperties); But this only seems to alert: "[Object Object]" Any ideas you clever people?

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  • CakePHP: Ajax view problem (nothing in the view showing)

    - by Adim
    I created a function in my controller called addToPlaylist($songName). I wanted to add these song names to an array and then a session variable using an Ajax call. The first time i did this i got an error saying i do not have a template file to display in the chosen div ("add_to_playlist.ctp was missing"). I created this file and everything seemed to be working correctly. Basically I went to bed woke up and it is broken (it is possible I changed something before I went to bed). The problem now is that it does not show anything when i click the ajax link. when i click on the ajax link it seems to call the function but nothing displays in the view (except debug info) even when i delete the view (add_to_playlist.ctp) i get no errors, I just see debug info now.

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  • Jquery Hidden Field in Table

    - by zSysop
    Hi all, I was wondering if anyone knew of a way to access a hidden field (by client id) within a table row using jquery. $("#tblOne").find("tr").click(function() { var worker = $(this).find(":input").val(); }); I find that the above works for a row that has only one input, but i need some help figuring out a way to get the value by the inputs name. Here's the example of a table row. How would i access the two fields by their id's? <table id="tblOne"> <tr> <td> <asp:HiddenField id="hdnfld_Id" Text='<% Eval("ID") %>'></asp:HiddenField> </td> <td> <asp:HiddenField id="hdnfld_Id2" Text='<% Eval("ID2") %>'></asp:HiddenField> </td> </tr> </table>

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  • Working With Feeds and Lists

    - by Nathan Campos
    I'm using a ListView component to list up some informations at a RSS feed, but when the user clicks the row, I want to change into a detailed view of that RSS Item, so far I've done this: function parseFeed(feed) { var html = ""; for(var i = 0; i < feed.items.length && i < 5; i++) { var item = feed.items[i]; var title = item.title; html += "\n<li onClick='goDetailed()'>\n"; html += "<h3><a href='#' class='ui-link-inherit'>" + title + "</a></h3>\n"; html += "<p>" + item.description + "</p>\n"; html += "</li>"; } $("#dList").append(html); $("#dList").listview('refresh'); } function goDetailed() { $.mobile.changePage($('#detailedPage')); } One of my problems is that the Back button won't come back(it does nothing). My other question is how I can pass the item.title, item.description, item.link and item.updated of the selected row(feed item) to some <div data-role="content">'s at the detail page.

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  • Why NOT use POST method here?

    - by Camran
    I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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  • jQuery and PHP suggested answers

    - by Samir Ghobril
    Hey guys, there is a form where the user select some of his friends and I'm curious on how I can implement a list that searches simultaneously while the user is typing a friend's name and when he selects the name the name is written in the text box(jQuery). And if the user wants to select more than one friend, when I'm inserting the names in the database, how can I separate the names that are written in one input field?

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  • Flexslider position of previous and next slides

    - by TJ15
    I am using the basic flexslider, I wantto display some of the previous and next , so if slide 2 is showing you will see part of slide 1 to the left and part of slide 3 to the right. <!DOCTYPE html> <head> <link rel="stylesheet" href="flexslider.css" type="text/css"> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script> <style> .container {overflow: hidden; width: 100%} .flexslider {max-width: 500px; width: 500px; margin: 0 auto} .content {background: #f2f2f2; max-width: 500px; display: block; margin: 0 auto} .flex-viewport {overflow: visible !important} </style> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <div class="container"> <div class="flexslider"> <ul class="slides"> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> </ul> </div> </div> <script src="jquery.flexslider.js"></script> <script> jQuery(document).ready(function($) { // You can use the locally-scoped $ in here as an alias to jQuery. $(window).load(function() { $('.flexslider').flexslider(); }); }); </script> </body> </html> I have reduced the image to 70% and positioned it in the middle of the page. I want to have the next and previous slides visible on either side of the main pic but no idea where to make the appropriate changes (I assume in the js file). I thought this was a margin issue but setting this to 0 in styles makes no difference. Has anyone done this and can provide some advice?

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  • d3: Coloring Multiple Lines from Nested Data

    - by diet_coke
    I'm currently assembling some line graphs with circles at the datapoints from arrays of JSON objects formatted like so: var data = [{ "name": "metric1", "datapoints": [ [10.0, 1333519140], [48.0, 1333519200] ] }, { "name": "metric2", "datapoints": [ [48.0, 1333519200], [12.0, 1333519260] ] }] I want to have a color for each metric, so I'm trying to color them based on the index of the object within the array data. The code I have currently for just placing the circles looks like: // We bind an svg group to each metric. var metric_groups = this.vis.selectAll("g.metric_group") .data(data).enter() .append("g") .attr("class", "metric_group"); // Then bind a circle for each datapoint. var circles = metric_groups.selectAll("circle") .data(function(d) { return d.datapoints; }); circles.enter().append("circle") .attr("r", 3.5); Now if I change that last bit to something like: circles.enter().append("circle") .attr("r", 3.5); .style("fill", function(d,i) { return i%2 ? "red" : "blue"; } I get alternating red and blue circles, as could be expected. Taking some advice from Nested Selections : 'Nesting and Index', I tried: circles.enter().append("circle") .attr("r", 3.5); .style("fill", function(d,i,j) { return j%2 ? "red" : "blue"; } Which doesn't work (j is undefined), presumably because we are in the named property datapoints, rather than an array element. How might I go about doing the coloring that I want without changing my data structure? Thanks!

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  • how to assign the html value to the php variable without post or get method

    - by Meena
    hi , in my program i had a php value $test = 2 using this value i done some operation for example: in my page i had a 2 block A and B and one select box. If the test value is A it enable the div A, if the value is B it hide div A and also i am able to show and hide the div using the select box onchange event. please check my sample code given below $test = $_GET["id"]; <select name="hideme" id="hideme" onchange="enableme();"> <option value="A">Show</option> <option value="B">Hide</option> </select> if($test == 'A') { <div id="div1" name="div1"> xxxxxxxxxxxxx </div> } Js Function : function enableme() { if(document.getElementByID('hideme').value == "A") { document.getElementById.style.display ="block"; } else { document.getElementById.style.display ="none"; } } my issue is at fist time using the $test($_get) value it show the correct div but the on change event is not working because of , if condition. If i remove the if condition then it show div A even if the value of the $test is B. how could i handle both. Please Help me

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  • Delay function with greasemonkey

    - by Riccardo
    I need a code that when CheckForZero happens for the first time, after 30 seconds happens again. var waitForZeroInterval = setInterval (CheckForZero, 0); function CheckForZero () { if ( (unsafeWindow.seconds == 0) && (unsafeWindow.milisec == 0) ) { clearInterval (waitForZeroInterval); var targButton = document.getElementById ('bottone1799'); var clickEvent = document.createEvent ('MouseEvents'); clickEvent.initEvent ('click', true, true); targButton.dispatchEvent (clickEvent); } };

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  • Showing the next month

    - by Alex
    I wonder how to set next month with showing only mondays active: i tried to do smth like that but it wont work function onlyMondaysNextMonth(date){ var day = date.getDay(); var mDate = date.getMonth() + 1; return { minDate: mDate, } return [(day == 1),'']; } Thank you.

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  • CSS3 image rotation and reposition to fit in div

    - by blid
    I'll start with JS Fiddle: http://jsfiddle.net/zy2xy/4/ <div id="page" style="position: relative; background: #ccc; width: 500px; height: 600px;"> <div id="container" style="top: 50px; left: 100px; width: 200px; height: 200px; position: absolute; background: #fff;"> <img src="http://lorempixel.com/200/100/"> </div> </div>????????? I've got a whole page div #page, and inside that another div #container positioned absolute against #page. What I want to achieve, is to rotate image inside it 90deg, 180deg or 270deg but always move that image to top left corner of #container. I tried a little bit with transform-origin but I couldn't find any solution.

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  • CSS Z-Index with Gradient Background

    - by Jona
    I'm making a small webpage where the I would like the top banner with some text to remain on top, as such: HTML: <div id = "topBanner"> <h1>Some Text</h1> </div> CSS: #topBanner{ position:fixed; background-color: #CCCCCC; width: 100%; height:200px; top:0; left:0; z-index:900; background: -moz-linear-gradient(top, rgba(204,204,204,0.65) 0%, rgba(204,204,204,0.44) 32%, rgba(204,204,204,0.12) 82%, rgba(204,204,204,0) 100%); /* FF3.6+ */ background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(204,204,204,0.65)), color-stop(32%,rgba(204,204,204,0.44)), color-stop(82%,rgba(204,204,204,0.12)), color-stop(100%,rgba(204,204,204,0))); /* Chrome,Safari4+ */ background: -webkit-linear-gradient(top, rgba(204,204,204,0.65) 0%,rgba(204,204,204,0.44) 32%,rgba(204,204,204,0.12) 82%,rgba(204,204,204,0) 100%); /* Chrome10+,Safari5.1+ */ background: -o-linear-gradient(top, rgba(204,204,204,0.65) 0%,rgba(204,204,204,0.44) 32%,rgba(204,204,204,0.12) 82%,rgba(204,204,204,0) 100%); /* Opera 11.10+ */ background: -ms-linear-gradient(top, rgba(204,204,204,0.65) 0%,rgba(204,204,204,0.44) 32%,rgba(204,204,204,0.12) 82%,rgba(204,204,204,0) 100%); /* IE10+ */ background: linear-gradient(to bottom, rgba(204,204,204,0.65) 0%,rgba(204,204,204,0.44) 32%,rgba(204,204,204,0.12) 82%,rgba(204,204,204,0) 100%); /* W3C */ filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6cccccc', endColorstr='#00cccccc',GradientType=0 ); /* IE6-9 */ } /*WebPage Header*/ h1{ font-size:3em; color:blue; text-shadow:#CCCCCC 2px 2px 2px, #000 0 -1px 2px; position: absolute; width: 570px; left:50%; right:50%; line-height:20px; margin-left: -285px; z-index:999; } The z-index works fine, except that because I'm using a gradient any time I scroll down the elements behind the banner are still visible, albeit somewhat transparent. Is there any way to make them total invisible? i.e., what I'm trying to do is make it as though the banner is a solid color, even though it's a gradient. Thanks in advance for any help!

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  • Highlight DIV and dim the rest on mouseover

    - by Darren Sweeney
    I have a page full of DIVs which contain images. When I mouse over an image I can highlight it or add a shadow to accent it easily by adding class etc but is there a way to dim every other image instead. DIVs are loaded into DOM and I would like the DIV currently hovered over to retain 100% or 1 opacity and the rest of the DIVs on the page to fade to say 70% or 0.7 when one DIV is highlighted. Is this possible?

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  • Submit to open up a popup window and carry through input data

    - by zac
    Hi, I have a input box on one page that on submit opens a new page with a longer form and the first field is populated with what was entered from the previous pages input box. So on page 1 there is this code: <form action="sign-up.php"> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input value='Submit' /> </form> Then on the sign-up page the receiving form grabs the string out of the url //<!-- Begin function getParams() { var idx = document.URL.indexOf('?'); if (idx != -1) { var tempParams = new Object(); var pairs = document.URL.substring(idx+1,document.URL.length).split('&'); for (var i=0; i<pairs.length; i++) { nameVal = pairs[i].split('='); tempParams[nameVal[0]] = nameVal[1]; } return tempParams; } } var params = getParams(); // End --> I would like to keep all of this functionality but it have it occur in a popup. I added this function to the submit: function myPopup() { window.open( "sign-up.php", "myWindow", "status = 1, height = 300, width = 300, resizable = 0" ) and the form becomes <form> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input onClick="myPopup()" value='Submit' /> </form> But it no longer appends the input data to the url string. Anyone have any ideas on how I can accomplish this?

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  • How to display the dynamically created elements for some time?

    - by Holicreature
    i have some rows of data displayed in a table and on mouse over of each row i've list two buttons inside a div element and then display it for some time. And i've associated some functions to be called on clicking the buttons that are dynamically created and displayed elements.. So what i did was i wrote a function which will create elements dynamically and place them exactly where i wanted using styles. And i wrote another function which will remove these dynamically added elements. I called them on mouseover and mouseout events of the row. now when i move mouse out the row to click the button they get disappeared bcoz of my mouseout function. So how can i proceed this? And what is the perfect method to create these kind of stuffs?

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  • Scrolling in Webview Progmatically

    - by mindfreak
    Hello friends, I am having a webview which dispalys large amounbt of data. I want to scroll Webview progmatically. I know window.scrollto() method is there but ,god knows why, it is not working. Can anybody guide me step by step how to do this ? I am sure there is some minor problem. Pl. guide me.

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