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  • How to find the length of a linked list that is having cycles in it?

    - by Bragaadeesh
    This was one of the interview questions asked. How to find the length of a linked list that is having cycle in it. I know how to calculate whether a linked list has a cycle or not using Hare and Tortoise technique. I even know how to calculate the length by storing the addresses in a hashset. But what I was not able to tell is how to calculate the length of the linked list without using a external space of O(n). Please help me. Thanks.

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  • What are real world examples of when Linked Lists should be used?

    - by oo
    Another programmer was mentioning that they haven't found a use case for using a linked list data structure in any professional software in his career. I couldn't think of any good examples off the top of my head. He is mostly a C# and Java developer Can anyone give some examples where this was the correct data structure to solve a particular real world problem? Related: What is a practical, real world example of the Linked List?

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  • Effective backup and archive strategy for database and linked files

    - by busyspin
    I am using Postgres to store a variety of application data for a webapp. Part of the application involves storing and retrieving user uploaded files. I am storing the files in the filesystem with some associated metadata in the database. I am trying to come up with a backup and archive strategy so that I can effectively backup and archive/restore the database and the linked files. Here are the things I want to accomplish. Perform routine backups that can be used for recovery from failures and which include all DB data and the linked files. Ideally, this backup would be done while the app is running. Live backup is certainly possible with a DB but I am not sure how to keep the linked files consistent with the database during the backup process Archive chunks of data as they become "old". These chunks must includes the database data plus any linked files. It should be possible to put the archived data back into production again. It would be ideal if it were easy to determine which ranges of objects were stored in each chunk. Do you have any advice for how to accomplish these goals? If the files were in the database as BLOBS these tasks would be much easier since normal database backup and restore functionality would handle this. I am not sure how to accomplish the same thing when file data is linked to database rows.

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  • Oracle Linked Servers on Windows Server 2008 R2

    - by John Paul Cook
    Oracle hasn’t yet released versions of its client software for Windows Server 2008 R2. If you need to create an Oracle linked server, that’s a problem. You’ll see this installation block when attempting to install the Oracle client software for Windows Server 2008: It’s very simple to fix. Check the first checkbox to make the installer ignore the version check. Click Next and ignore the warning you’ll see. The installation should complete successfully. Windows does offer various strategies for mitigating...(read more)

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  • Why is a linked list implementation considered linear?

    - by VeeKay
    My apologies for asking such a simple question. Instead of posting such basic question in SO, I felt that this is more apt a question here. I tried finding an answer for this but none of them are logically appealing or convincing to my understanding. Typically, computer memory is always linear. So is the term non linear used for a data structure in a logical sense? If so, to logically achieve non linearity in a linear computer memory, we use pointers. Right? In that case, if pointers are virtual implementations for achieving non linearity, Why would a data structure like linked list be considered linear if in reality the nodes are never physically adjacent?

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  • SUN Java and GPL V2 licence issue for linked applications

    - by user255607
    I have recently noticed that the Sun Java code has been released as GPL V2 code (see Google code repo). Does that mean that all applications written in Java and linked to Sun APIs (beans, and so on) are also in GPL ? If we strictly follow the GPL then this should be the case (Libs should be in LGPL, not GPL if we want to build proprietary software on top of it). Is there another commercial licence which can avoid such an issue ? I cannot believe this is the case. There must be an explanation on this. Regards, Apple92

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  • Bad search result due to strange linked domains

    - by VDesign
    I have a website which is not scoring good in Google's search results. I use Majestic SEO and Open Site Explorer in order to have a view about my link profile. I now see different backlink domains, some of them already removed, that contains sexual content or other non relative content linking to my domain. How much influence does these strange linked domains have on my search result? Even if some of them are already removed for a couple of months. I have already disavow open sexual domains using the tool that Google provides.

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  • Array Vs. Linked List

    - by Onorio Catenacci
    I apologize--this question may be a bit open-ended but I think there are probably definite, quantifiable answers to it so I'll post it anyway. A person I know is trying to learn C++ and software development (+1 to him) and he asked me why someone would want to use a linked list in preference to an array. Coding a linked list is, no doubt, a bit more work than using an array and he wondered what would justify the additional effort. I gave him the answer I know: insertion of new elements is trivial in linked list but it's a major chore in an array. But then I got to thinking about it a bit more. Besides the ease of insertion of a new element into a linked list are there other advantages to using a linked list to store a set of data vs. storing it in an array? As I said, I'm not meaning to start a long and drawn-out discussion. I'm just looking for other reasons that a developer might prefer a linked list to an array.

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  • Bounding volume hierarchy - linked nodes (linear model)

    - by teodron
    The scenario A chain of points: (Pi)i=0,N where Pi is linked to its direct neighbours (Pi-1 and Pi+1). The goal: perform efficient collision detection between any two, non-adjacent links: (PiPi+1) vs. (PjPj+1). The question: it's highly recommended in all works treating this subject of collision detection to use a broad phase and to implement it via a bounding volume hierarchy. For a chain made out of Pi nodes, it can look like this: I imagine the big blue sphere to contain all links, the green half of them, the reds a quarter and so on (the picture is not accurate, but it's there to help understand the question). What I do not understand is: How can such a hierarchy speed up computations between segments collision pairs if one has to update it for a deformable linear object such as a chain/wire/etc. each frame? More clearly, what is the actual principle of collision detection broad phases in this particular case/ how can it work when the actual computation of bounding spheres is in itself a time consuming task and has to be done (since the geometry changes) in each frame update? I think I am missing a key point - if we look at the picture where the chain is in a spiral pose, we see that most spheres are already contained within half of others or do intersect them.. it's odd if this is the way it should work.

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  • MVC: How to Implement Linked Views?

    - by cw'
    I'm developing a java application to visualize time series. I need (at least) three linked views, meaning that interaction with one of them updates the others. The views are: A list represents the available and currently selected time series. The selected time series are used as input for subsequent computations. Changing the selection should update the other views. A line chart displays the available and selected time series. Time series should be selectable from here by clicking on them. A bar chart shows aggregated data on time series. When zooming in to a period of time, the line chart should zoom in to the same period (and vice versa). How to implement this nicely, from a software engineering point of view? I.e. I'd like to write reusable and clear, maintainable code. So I thought of the MVC pattern. At first I liked the idea of having the three view components observing my model class and to refresh views upon being notified. But then, it didn't feel right to store view related data in the model. Storing e.g. the time series selection or plot zoom level in the model makes implications about the view which I wouldn't want in a reusable model. On the other hand, having the controllers observe each other results in a lot of dependencies. When adding another view, I'd have to register all other views as observer of the new view and vice versa, passing around many references and introducing dependencies. Maybe another "model" storing only view-related data would be the solution?

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  • Why increase pointer by two while finding loop in linked list, why not 3,4,5?

    - by GG
    I had a look at question already which talk about algorithm to find loop in a linked list. I have read Floyd's cycle-finding algorithm solution, mentioned at lot of places that we have to take two pointers. One pointer( slower/tortoise ) is increased by one and other pointer( faster/hare ) is increased by 2. When they are equal we find the loop and if faster pointer reaches null there is no loop in the linked list. Now my question is why we increase faster pointer by 2. Why not something else? Increasing by 2 is necessary or we can increase it by X to get the result. Is it necessary that we will find a loop if we increment faster pointer by 2 or there can be the case where we need to increment by 3 or 5 or x.

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  • Is there a fast concat method for linked list in Java?

    - by rocker
    How can I concat two linked lists in O(1) with Java via jdk, google or apache commons collection or whatever? E.g. in jdk there is only the addAll method which is O(n). Another feature I miss is to concat two lists where each of them could be in inverse order. To illustrate this assume two lists a-b-c and e-f-g could merged into a-b-c-e-f-g a-b-c-g-f-e c-b-a-e-f-g c-b-a-g-f-e Do you know of such a list implemenation or do I have to implement my own linked list? It would be also helpful to know how to tweak existing solutions (e.g. the jdk LinkedList has a lot of private methods only). These features seems to me very obvious, hopefully I am not missing something stupid.

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  • learning C++ from java, trying to make a linked list.

    - by kyeana
    I just started learning c++ (coming from java) and am having some serious problems with doing anything :P Currently, i am attempting to make a linked list, but must be doing something stupid cause i keep getting "void value not ignored as it ought to be" compile errors (i have it marked where it is throwing it bellow). If anyone could help me with what im doing wrong, i would be very grateful :) Also, I am not used to having the choice of passing by reference, address, or value, and memory management in general (currently i have all my nodes and the data declared on the heap). If anyone has any general advice for me, i also wouldn't complain :P Key code from LinkedListNode.cpp LinkedListNode::LinkedListNode() { //set next and prev to null pData=0; //data needs to be a pointer so we can set it to null for //for the tail and head. pNext=0; pPrev=0; } /* * Sets the 'next' pointer to the memory address of the inputed reference. */ void LinkedListNode::SetNext(LinkedListNode& _next) { pNext=&_next; } /* * Sets the 'prev' pointer to the memory address of the inputed reference. */ void LinkedListNode::SetPrev(LinkedListNode& _prev) { pPrev=&_prev; } //rest of class Key code from LinkedList.cpp #include "LinkedList.h" LinkedList::LinkedList() { // Set head and tail of linked list. pHead = new LinkedListNode(); pTail = new LinkedListNode(); /* * THIS IS WHERE THE ERRORS ARE. */ *pHead->SetNext(*pTail); *pTail->SetPrev(*pHead); } //rest of class

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  • SQL Server 2008 to Sybase Linked Server (x64) -- Provider and permissions issues

    - by Cory Larson
    Good morning, We're testing a new SQL Server 2008 setup (64-bit) and one of our requirements was to get a linked server up and talking to a Sybase database. We've successfully done so using Sybase's 64-bit 15.5 drivers, however I can't expand the catalog list from a remote machine (connecting to the '08 box with SSMS) without having my network account being added as an Administrator on the actual box and then using Windows Authentication to connect to the server instance. This is going to be problematic when we go live. Has anybody experienced this, or have any input on the permissions in SQL Server 2008 with regards to linked servers? If I remove my network account from the Administrators group, the big error I'm getting is a 'Msg 7302, Level 16, State 1, Line 41' with a description something like "Cannot create an instance of OLE DB provider "ASEOLEDB" for linked server "", and all research points to permissions issues. Thoughts? This document talks about DCOM configuration and permissions, but we've tried all of it with no luck. Thanks

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  • How do I implement a remove by index method for a singly linked list in Java?

    - by Lars Flyger
    Hi, I'm a student in a programming class, and I need some help with this code I've written. So far I've written an entire linked list class (seen below), yet for some reason the "removeByIndex" method won't work. I can't seem to figure out why, the logic seems sound to me. Is there some problem I don't know about? public class List<T> { //private sub-class Link private class Link { private T value; private Link next; //constructors of Link: public Link (T val) { this.value = val; this.next = null; } public Link (T val, Link next) { this.value = val; this.next = next; } @SuppressWarnings("unused") public T getValue() { return value; } } private static final Exception NoSuchElementException = null; private static final Exception IndexOutOfBoundsException = null; private Link chain = null; //constructors of List: public List() { this.chain = null; } //methods of List: /** * Preconditions: none * Postconditions: returns true if list is empty */ public boolean isEmpty() { return this.chain == null; } /** * Preconditions: none * Postconditions: A new Link is added via add-aux * @param element */ public void add(T element) { this.add_aux(element, this.chain); } /** * Preconditions: none * Postconditions: A new Link is added to the current chain * @param element * @param chain */ private void add_aux(T element, Link chain) { if (chain == null) { //if chain is null set chain to a new Link with a value of //element this.chain = new Link(element); } else if (chain.next != null) { //if chain.next is not null, go to next item in chain and //try //to add element add_aux(element, chain.next); } else { //if chain.next is null, set chain.next equal to a new Link //with value of element. chain.next = new Link(element); } } /** * Preconditions: none * Postconditions: returns the link at the defined index via nthlink_aux * @param index * @return */ private Link nthLink (int index) { return nthLink_aux(index, this.chain); } /** * Preconditions: none * Postconditions: returns the link at the defined index in the specified *chain * @param i * @param c * @return */ private Link nthLink_aux (int i, Link c) { if (i == 0) { return c; } else return nthLink_aux(i-1, c.next); } /** * Preconditions: the specified element is present in the list * Postconditions: the specified element is removed from the list * @param element * @throws Exception */ public void removeElement(T element) throws Exception { if (chain == null) { throw NoSuchElementException; } //while chain's next is not null and the value of chain.next is not //equal to element, //set chain equal to chain.next //use this iteration to go through the linked list. else while ((chain.next != null) && !(chain.next.value.equals(element))){ Link testlink = chain.next; if (testlink.next.value.equals(element)) { //if chain.next is equal to element, bypass the //element. chain.next.next = chain.next.next.next; } else if (testlink.next == null) { throw NoSuchElementException; } } } /** * Preconditions: none * Postsconditions: the Link at the specified index is removed * @param index * @throws Exception */ public void removeByIndex(int index) throws Exception { if (index == 0) { //if index is 0, set chain equal to chain.next chain = chain.next; } else if (index > 0) { Link target = nthLink(index); while (target != null) { if (target.next != null) { target = target.next; } //if target.next is null, set target to null else { target = null; } } return; } else throw IndexOutOfBoundsException; } /** * Preconditions: none * Postconditions: the specified link's value is printed * @param link */ public void printLink (Link link) { if(link != null) { System.out.println(link.value.toString()); } } /** * Preconditions: none * Postconditions: all of the links' values in the list are printed. */ public void print() { //copy chain to a new variable Link head = this.chain; //while head is not null while (!(head == null)) { //print the current link this.printLink(head); //set head equal to the next link head = head.next; } } /** * Preconditions: none * Postconditions: The chain is set to null */ public void clear() { this.chain = null; } /** * Preconditions: none * Postconditions: Places the defined link at the defined index of the list * @param index * @param val */ public void splice(int index, T val) { //create a new link with value equal to val Link spliced = new Link(val); if (index <= 0) { //copy chain Link copy = chain; //set chain equal to spliced chain = spliced; //set chain.next equal to copy chain.next = copy; } else if (index > 0) { //create a target link equal to the link before the index Link target = nthLink(index - 1); //set the target's next equal to a new link with a next //equal to the target's old next target.next = new Link(val, target.next); } } /** * Preconditions: none * Postconditions: Check to see if element is in the list, returns true * if it is and false if it isn't * @param element * @return */ public boolean Search(T element) { if (chain == null) { //return false if chain is null return false; } //while chain's next is not null and the value of chain.next is not //equal to element, //set chain equal to chain.next //use this iteration to go through the linked list. else while ((chain.next != null) && !(chain.next.value.equals(element))) { Link testlink = chain.next; if (testlink.next.value.equals(element)) { //if chain.next is equal to element, return true return true; } else if (testlink.next == null) { return false; } } return false; } /** * Preconditions: none * Postconditions: order of the links in the list is reversed. */ public void reverse() { //copy chain Link current = chain; //set chain equal to null chain = null; while (current != null) { Link save = current; current = current.next; save.next = chain; chain = save; } } }'

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  • How can I do an "insert" statement from MS SQL -> MYSQL using linked servers

    - by bvandrunen
    Is it possible to do an "insert" statement through linked servers. I know it is possible by using MSDTC...but does this work between MS SQL and MYSQL? Any help would be greatly appreciated. As of right now...I can update and select between the 2 databases but it gives me an error when I try to run an insert statement. OLE DB provider "MSDASQL" for linked server "******" returned message "Query-based insertion or updating of BLOB values is not supported.". Msg 7343, Level 16, State 2, Line 1 The OLE DB provider "MSDASQL" for linked server "******" could not INSERT INTO table "[*********]...[******_options]". Location: memilb.cpp:1493 Expression: (*ppilb)-m_cRef == 0 SPID: 76 Process ID: 1644

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  • SQL Server (2005) Linked Server Issue

    - by David.Chu.ca
    I have SQL Server 2005 with several linked server defined. One of them is a connection to an Oracle server and another one is an ODBC bridge to another server on a remote machine (ODBC server). Recently I tried to use the linked server to Oracle to update data with two large size tables by using several joints. The update query took too long time and finally there was exception thrown: Update O set value = l.value FROM OracleServer..schema.largesizeTable O Join localLargeSizeTable l on .... The problem is that after the exception, I realized that another linked server to ODBC was not working any more. I had to restart SQL server to get the ODBC linked server back. It looks that the linked server pool could be crashed if any of them failed(not like sandbox in Chrome for each tab and no impact on other tabs or Chrome application at all). I am not sure if my assumption is correct or not. Is this a known issue of SQL server 2005?

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  • Cannot delete links to linked tables in Access 2007 - How delete linked tables?

    - by John316
    Cannot delete links to linked tables in Access 2007 I receive the following error " is not a valid name. Make sure that it does not include invalid characters or punctuation and that it is not too long. Please note that the quotation mark is part of the error message. Read the error as: Quotation mark is not a valid name. Make sure that it does not include invalid characters or punctuation and that it is not too long. The linked table name is tblStudies. What can I do to get around this problem and be able to unlink (delete) linked tables?

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  • I'm new to C++. Please Help me with the Linked List (What functions to add)?

    - by Igal
    DEAR All; Hi, I'm just beginner to C++; Please help me to understand: What functions should be in the Linked list class ? I think there should be overloaded operators << and ; Please help me to improve the code (style, errors, etc,) Thanks for advance. Igal. Please review the small code for the integer List (enclosed MyNODE.h and ListDriver1.cpp); MyNODE.h // This is my first attempt to write linked list. Igal Spector, June 2010. #include <iostream.h> #include <assert.h> //Forward Declaration of the classes: class ListNode; class TheLinkedlist; // Definition of the node (WITH IMPLEMENTATION !!!, without test drive): class ListNode{ friend class TheLinkedlist; public: // constructor: ListNode(const int& value, ListNode *next= 0); // note: no destructor, as this handled by TheLinkedList class. // accessor: return data in the node. // int Show() const {return theData;} private: int theData; //the Data ListNode* theNext; //points to the next node in the list. }; //Implementations: //constructor: inline ListNode::ListNode(const int &value,ListNode *next) :theData(value),theNext(next){} //end of ListNode class, now for the LL class: class TheLinkedlist { public: //constructors: TheLinkedlist(); virtual ~TheLinkedlist(); // Accessors: void InsertAtFront(const &); void AppendAtBack(const &); // void InOrderInsert(const &); bool IsEmpty()const;//predicate function void Print() const; private: ListNode * Head; //pointer to first node ListNode * Tail; //pointer to last node. }; //Implementation: //Default constructor inline TheLinkedlist::TheLinkedlist():Head(0),Tail(0) {} //Destructor inline TheLinkedlist::~TheLinkedlist(){ if(!IsEmpty()){ //list is not empty cout<<"\n\tDestroying Nodes"<<endl; ListNode *currentPointer=Head, *tempPtr; while(currentPointer != 0){ //Delete remaining Nodes. tempPtr=currentPointer; cout<<"The node: "<<tempPtr->theData <<" is Destroyed."<<endl<<endl; currentPointer=currentPointer->theNext; delete tempPtr; } Head=Tail = 0; //don't forget this, as it may be checked one day. } } //Insert the Node to the beginning of the list: void TheLinkedlist::InsertAtFront(const int& value){ ListNode *newPtr = new ListNode(value,Head); assert(newPtr!=0); if(IsEmpty()) //list is empty Head = Tail = newPtr; else { //list is NOT empty newPtr->theNext = Head; Head = newPtr; } } //Insert the Node to the beginning of the list: void TheLinkedlist::AppendAtBack(const int& value){ ListNode *newPtr = new ListNode(value, NULL); assert(newPtr!=0); if(IsEmpty()) //list is empty Head = Tail = newPtr; else { //list is NOT empty Tail->theNext = newPtr; Tail = newPtr; } } //is the list empty? inline bool TheLinkedlist::IsEmpty() const { return (Head == 0); } // Display the contents of the list void TheLinkedlist::Print()const{ if ( IsEmpty() ){ cout << "\n\t The list is empty!!"<<endl; return; } ListNode *tempPTR = Head; cout<<"\n\t The List is: "; while ( tempPTR != 0 ){ cout<< tempPTR->theData <<" "; tempPTR = tempPTR->theNext; } cout<<endl<<endl; } ////////////////////////////////////// The test Driver: //Driver test for integer Linked List. #include <iostream.h> #include "MyNODE.h" // main Driver int main(){ cout<< "\n\t This is the test for integer LinkedList."<<endl; const int arraySize=11, ARRAY[arraySize]={44,77,88,99,11,2,22,204,50,58,12}; cout << "\n\tThe array is: "; //print the numbers. for (int i=0;i<arraySize; i++) cout<<ARRAY[i]<<", "; TheLinkedlist list; //declare the list for(int index=0;index<arraySize;index++) list.AppendAtBack( ARRAY[index] );//create the list cout<<endl<<endl; list.Print(); //print the list return 0; //end of the program. }

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  • How to write a recursive function that returns a linked list of nodes, when given a binary tree of n

    - by Jian Lin
    I was once asked of this in an interview: How to write a recursive function that returns a linked list of nodes, when given a binary tree of nodes? (flattening the data) For some reason, I tend to need more than 3 to 5 minutes to solve any recursive problem. Usually, 15 to 20 minutes will be more like it. How could we attack this problem, such as a very systematic way of reaching a solution, so that they can be solved in 3 to 5 minute time frame?

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  • Setting up a linked server to another server which isn't in a domain without using SQL authenticatio

    - by Telos
    Server A (SQL2005) is in our primary domain, but server B (SQL2000) is just in a windows workgroup. We are not allowed to join it to the domain, or bad things happen... We also can't enable SQL authentication on server B. We've got domain accounts for A, and matching local accounts on server B. I can connect to B from my local PC or A using SSMS and a domain login, but I can't get the linked server to connect. Any ideas how to do this?

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  • Java - Adding a Node in a doubly-linked list.

    - by jacobnlsn
    Hi, I am working on some code were I need to add a Node into a doubly linked-list, this is the code I have so far: Node tempNext = cursor.getNext(); temp = new Node(item, null, cursor, tempNext); tempNext.setPrev(temp); cursor is the Node that is right before the new added Node should go.

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