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  • Feature activate via UI but does not show in the Libraries and Lists

    - by Justin Cullen
    I am really hating SharePoint as there are hardly any good/concrete documentation. I developed custom List "MainCatalog" with few columns (not site columns). Create features and elements with MOSS feature builder at Site collection level so scope="site" installed via stsadm activated via UI "went to site collection website", Site Setting Site collection Feature (and saw my custom list "MainCatalog") and was able to activate. then went to "mySiteCollection Site Settings Site Libraries and Lists " My list is showing But it shows in the "mySiteCollection Create Custom Lists "MainCatalog" I guess it's showing there as a template... But my intention is to deploy this list from development to test environment. EXTREMELY STRESSED. I AM ON THIS FOR LAST 8 DAYS.....

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  • filtering elements from list of lists in Python?

    - by user248237
    I want to filter elements from a list of lists, and iterate over the elements of each element using a lambda. For example, given the list: a = [[1,2,3],[4,5,6]] suppose that I want to keep only elements where the sum of the list is greater than N. I tried writing: filter(lambda x, y, z: x + y + z >= N, a) but I get the error: <lambda>() takes exactly 3 arguments (1 given) How can I iterate while assigning values of each element to x, y, and z? Something like zip, but for arbitrarily long lists. thanks, p.s. I know I can write this using: filter(lambda x: sum(x)..., a) but that's not the point, imagine that these were not numbers but arbitrary elements and I wanted to assign their values to variable names.

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  • Updating Lists of Lists in Tapestry4 using textfields and a single submit button

    - by Nicolas Scarrci
    In Tapestry 4 I am trying it iterate over a list of lists (technically a list of objects who have a list of strings as a data field). I am currently doing this by using 'nested' for components. (This is pseudo code) <span jwcid="Form"> <span jwcid="@For" source="ognl:Javaclass.TopLevelList" value="ognl:SecondLevelList" index="ognl:index"> <span jwcid="@For" source="ognl:SecondLevelList.List" value="ognl:ListItem" index="ListItemIndex"> <span jwcid="@TextField" value="ognl:ListItem"/> <span jwcid="@Submit" listener="ognl:listeners.onSubmit"/> </span></span></span> The onSubmit listener then accesses the index and ListItem index page properties, as well as the ListItem page property in order to correctly update the list in Javaclass.TopLevelList. This works fine, but it looks terrible, and is cumbersome to the end user. I would prefer to somehow simulate this functionality using only one submit button at the bottom of the page. I have looked into somehow using the overlying form component to obtain a list of the 'form control components' within it, and then (with great care) parsing through tapestry's naming conventions to recover the functionality of the indexes. If anyone knows how to do this, or could explain the form component (how/when it submits, etc.) it would be greatly appreciated.

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  • print a linear linked list into a table

    - by user1796970
    I am attempting to print some values i have stored into a LLL into a readable table. The data i have stored is the following : DEBBIE STARR F 3 W 1000.00 JOAN JACOBUS F 9 W 925.00 DAVID RENN M 3 H 4.75 ALBERT CAHANA M 3 H 18.75 DOUGLAS SHEER M 5 W 250.00 SHARI BUCHMAN F 9 W 325.00 SARA JONES F 1 H 7.50 RICKY MOFSEN M 6 H 12.50 JEAN BRENNAN F 6 H 5.40 JAMIE MICHAELS F 8 W 150.00 i have stored each firstname, lastname, gender, tenure, payrate, and salary into their own List. And would like to be able to print them out in the same format that they are viewed on the text file i read them in from. i have messed around with a few methods that allow me to traverse and print the Lists, but i end up with ugly output. . . here is my code for the storage of the text file and the format i would like to print out: public class Payroll { private LineWriter lw; private ObjectList output; ListNode input; private ObjectList firstname, lastname, gender, tenure, rate, salary; public Payroll(LineWriter lw) { this.lw = lw; this.firstname = new ObjectList(); this.lastname = new ObjectList(); this.gender = new ObjectList(); this.tenure = new ObjectList(); this.rate = new ObjectList(); this.salary = new ObjectList(); this.output = new ObjectList(); this.input = new ListNode(); } public void readfile() { File file = new File("payfile.txt"); try{ Scanner scanner = new Scanner(file); while(scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s+"); while(lineScanner.hasNext()) { firstname.insert1(lineScanner.next()); lastname.insert1(lineScanner.next()); gender.insert1(lineScanner.next()); tenure.insert1(lineScanner.next()); rate.insert1(lineScanner.next()); salary.insert1(lineScanner.next()); } } }catch(FileNotFoundException e) {e.printStackTrace();} } public void printer(LineWriter lw) { String msg = " FirstName " + " LastName " + " Gender " + " Tenure " + " Pay Rate " + " Salary "; output.insert1(msg); System.out.println(output.getFirst()); System.out.println(" " + firstname.getFirst() + " " + lastname.getFirst() + "\t" + gender.getFirst() + "\t" + tenure.getFirst() + "\t" + rate.getFirst() + "\t" + salary.getFirst()); } }

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  • Recursively created linked lists with a class, C++

    - by Jon Brant
    I'm using C++ to recursively make a hexagonal grid (using a multiply linked list style). I've got it set up to create neighboring tiles easily, but because I'm doing it recursively, I can only really create all 6 neighbors for a given tile. Obviously, this is causing duplicate tiles to be created and I'm trying to get rid of them in some way. Because I'm using a class, checking for null pointers doesn't seem to work. It's either failing to convert from my Tile class to and int, or somehow converting it but not doing it properly. I'm explicitly setting all pointers to NULL upon creation, and when I check to see if it still is, it says it's not even though I never touched it since initialization. Is there a specific way I'm supposed to do this? I can't even traverse the grid without NULLs of some kind Here's some of my relevant code. Yes, I know it's embarassing. Tile class header: class Tile { public: Tile(void); Tile(char *Filename); ~Tile(void); void show(void); bool LoadGLTextures(); void makeDisplayList(); void BindTexture(); void setFilename(char *newName); char Filename[100]; GLuint texture[2]; GLuint displayList; Tile *neighbor[6]; float xPos, yPos,zPos; };` Tile Initialization: Tile::Tile(void) { xPos=0.0f; yPos=0.0f; zPos=0.0f; glEnable(GL_DEPTH_TEST); strcpy(Filename, strcpy(Filename, "Data/BlueTile.bmp")); if(!BuildTexture(Filename, texture[0]))MessageBox(NULL,"Texture failed to load!","Crap!",MB_OK|MB_ICONASTERISK); for(int x=0;x<6;x++) { neighbor[x]=NULL; } } Creation of neighboring tiles: void MakeNeighbors(Tile *InputTile, int stacks) { for(int x=0;x<6;x++) { InputTile->neighbor[x]=new Tile();InputTile->neighbor[x]->xPos=0.0f;InputTile->neighbor[x]->yPos=0.0f;InputTile->zPos=float(stacks); } if(stacks) { for(int x=0;x<6;x++)MakeNeighbors(InputTile->neighbor[x],stacks-1); } } And finally, traversing the grid: void TraverseGrid(Tile *inputTile) { Tile *temp; for(int x=0;x<6;x++) if(inputTile->neighbor[x]) { temp=inputTile->neighbor[x]; temp->xPos=0.0f; TraverseGrid(temp); //MessageBox(NULL,"Not Null!","SHUTDOWN ERROR",MB_OK | MB_ICONINFORMATION); } } The key line is "if(inputTile-neighbor[x])" and whether I make it "if(inputTile-neighbor[x]==NULL)" or whatever I do, it just isn't handling it properly. Oh and I'm also aware that I haven't set up the list fully. It's only one direction now.

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  • Maddening Linked List problem

    - by Mike
    This has been plaguing me for weeks. It's something really simple, I know it. Every time I print a singly linked list, it prints an address at the end of the list. #include <iostream> using namespace std; struct node { int info; node *link; }; node *before(node *head); node *after(node *head); void middle(node *head, node *ptr); void reversep(node *head, node *ptr); node *head, *ptr, *newnode; int main() { head = NULL; ptr = NULL; newnode = new node; head = newnode; for(int c1=1;c1<11;c1++) { newnode->info = c1; ptr = newnode; newnode = new node; ptr->link = newnode; ptr = ptr->link; } ptr->link=NULL; head = before(head); head = after(head); middle(head, ptr); //reversep(head, ptr); ptr = head; cout<<ptr->info<<endl; while(ptr->link!=NULL) { ptr=ptr->link; cout<<ptr->info<<endl; } system("Pause"); return 0; } node *before(node *head) { node *befnode; befnode = new node; cout<<"What should go before the list?"<<endl; cin>>befnode->info; befnode->link = head; head = befnode; return head; } node *after(node *head) { node *afnode, *ptr2; afnode = new node; ptr2 = head; cout<<"What should go after the list?"<<endl; cin>>afnode->info; ptr2 = afnode; afnode->link=NULL; ptr2 = head; return ptr2; } void middle(node *head, node *ptr) { int c1 = 0, c2 = 0; node *temp, *midnode; ptr = head; while(ptr->link->link!=NULL) { ptr=ptr->link; c1++; } c1/=2; c1-=1; ptr = head; while(c2<c1) { ptr=ptr->link; c2++; } midnode = new node; cout<<"What should go in the middle of the list?"<<endl; cin>>midnode->info; cout<<endl; temp=ptr->link; ptr->link=midnode; midnode->link=temp; } void reversep(node *head, node *ptr) { node *last, *ptr2; ptr=head; ptr2=head; while(ptr->link!=NULL) ptr = ptr->link; last = ptr; cout<<last->info; while(ptr!=head) { while(ptr2->link!=ptr) ptr2=ptr2->link; ptr = ptr2; cout<<ptr->info; } } I'll admit that this is class work, but even the professor can't figure it out, and says that its probably something insignificant that we're overlooking, but I can't put my mind to rest until I find out what it is.

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  • Combining lists of objects containing lists of objects in c#

    - by Dan H
    The title is a little prosaic, I know. I have 3 classes (Users, Cases, Offices). Users and Cases contain a list of Offices inside of them. I need to compare the Office lists from Users and Cases and if the ID's of Offices match, I need to add those IDs from Cases to the Users. So the end goal is to have the Users class have any Offices that match the Offices in the Cases class. Any ideas? My code (which isnt working) foreach (Users users in userList) foreach (Cases cases in caseList) foreach (Offices userOffice in users.officeList) foreach (Offices caseOffice in cases.officeList) { if (userOffice.ID == caseOffice.ID) users.caseAdminIDList.Add(cases.adminID); }//end foreach //start my data classes class Users { public Users() { List<Offices> officeList = new List<Offices>(); List<int> caseAdminIDList = new List<int>(); ID = 0; }//end constructor public int ID { get; set; } public string name { get; set; } public int adminID { get; set; } public string ADuserName { get; set; } public bool alreadyInDB { get; set; } public bool alreadyInAdminDB { get; set; } public bool deleted { get; set; } public List<int> caseAdminIDList { get; set; } public List<Offices> officeList { get; set; } } class Offices { public int ID { get; set; } public string name { get; set; } } class Users { public Users() { List<Offices> officeList = new List<Offices>(); List<int> caseAdminIDList = new List<int>(); ID = 0; }//end constructor public int ID { get; set; } public string name { get; set; } public int adminID { get; set; } public string ADuserName { get; set; } public bool alreadyInDB { get; set; } public bool alreadyInAdminDB { get; set; } public bool deleted { get; set; } public List<int> caseAdminIDList { get; set; } public List<Offices> officeList { get; set; } }

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  • Linked list in C

    - by ScReYm0
    I am still new at lists in C and i got a big problem... First i wanna show you my code for inserting item to the list: void input_books_info(int number_of_books, BOOK *current) { int i; for(i = 0; i < number_of_books; i++) { while(current->next != NULL) current = current->next; current->next = (BOOK *)malloc(sizeof(BOOK)); printf_s("%d book catalog number: ", i + 1); scanf_s("%s", &current->next->catalog_number , 20); printf_s("%d book title: ", i + 1); scanf_s("%s", current->next->title ,80); printf_s("%d book author: ", i + 1); scanf_s("%s", current->next->author ,40); printf_s("%d book publisher: ", i+1); scanf_s("%s", current->next->publisher,80); printf_s("%d book price: ", i + 1); scanf_s("%f", &current->next->price, 5); printf_s("%d book year published: ", i + 1); scanf_s("%d", &current->next->year_published, 5); current->next->next = NULL; printf_s("\n\n"); } } And this is my main function: void main (void) { int number_of_books, t = 1; char book_catalog_number[STRMAX]; char book_title[STRMAX]; char book_author[STRMAX]; char reading_file[STRMAX]; char saving_file[STRMAX]; first = malloc(sizeof(BOOK)); first->next = NULL; /* printf_s("Enter file name: "); gets(saving_file); first->next = book_open(first, saving_file); */ while(t) { char m; printf_s("1. Input \n0. Exit \n\n"); printf_s("Choose operation: "); m = getch(); switch(m) { case '1': printf_s("\ninput number of books: "); scanf_s("%d", &number_of_books); input_books_info(number_of_books, first); printf_s("\n"); break; default: printf_s("\nNo entry found!\n\n\n\n\n"); break; } } } and last maybe here is the problem the printing function: void print_books_info(BOOK *current) { while(current->next != NULL && current != NULL) { printf_s("%s, ", current->next->catalog_number); printf_s("%s, ", current->author); printf_s("%s, ", current->next->title); printf_s("%s, ", current->next->author); printf_s("%s, ", current->next->publisher); printf_s("%.2f, ", current->next->price); printf_s("%d", current->next->year_published); printf_s("\n\n"); current = current->next; } } And my problem is that, when i run the app, program is moving good. But when I start the app, the program is storing only first input of data second and third are lost ... Can you help me to figure out it... ???

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  • C++ Bubble Sorting for Singly Linked List [closed]

    - by user1119900
    I have implemented a simple word frequency program in C++. Everything but the sorting is OK, but the sorting in the following script does not work. Any emergent help will be great.. #include <stdio.h> #include <string.h> #include <stdlib.h> #include <ctype.h> #include <iostream> #include <fstream> #include <cstdio> using namespace std; #include "ProcessLines.h" struct WordCounter { char *word; int word_count; struct WordCounter *pNext; // pointer to the next word counter in the list }; /* pointer to first word counter in the list */ struct WordCounter *pStart = NULL; /* pointer to a word counter */ struct WordCounter *pCounter = NULL; /* Print statistics and words */ void PrintWords() { ... pCounter = pStart; bubbleSort(pCounter); ... } //end-PrintWords void bubbleSort(struct WordCounter *ptr) { WordCounter *temp = ptr; WordCounter *curr; for (bool didSwap = true; didSwap;) { didSwap = false; for (curr = ptr; curr->pNext != NULL; curr = curr->pNext) { if (curr->word > curr->pNext->word) { temp->word = curr->word; curr->word = curr->pNext->word; curr->pNext->word = temp->word; didSwap = true; } } } }

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  • Is this good code? Linked List Stack Implementation

    - by Quik Tester
    I have used the following code for a stack implementation. The top keeps track of the topmost node of the stack. Now since top is a data member of the node function, each node created will have a top member, which ideally we wouldn't want. Firstly, is this good approach to coding? Secondly, will making top as static make it a better coding practice? Or should I have a global declaration of top? #include<iostream> using namespace std; class node { int data; node *top; node *link; public: node() { top=NULL; link=NULL; } void push(int x) { node *n=new node; n->data=x; n->link=top; top=n; cout<<"Pushed "<<n->data<<endl; } void pop() { node *n=new node; n=top; top=top->link; n->link=NULL; cout<<"Popped "<<n->data<<endl; delete n; } void print() { node *n=new node; n=top; while(n!=NULL) { cout<<n->data<<endl; n=n->link; } delete n; } }; int main() { node stack; stack.push(5); stack.push(7); stack.push(9); stack.pop(); stack.print(); } Any other suggestions welcome. I have also seen codes where there are two classes, where the second one has the top member. What about this? Thanks. :)

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  • The difference between lists and sequences

    - by Peanut
    I'm trying to understand the difference between sequences and lists. In F# there is a clear distinction between the two. However in C# I have seen programmers refer to IEnumerable collections as a sequence. Is what makes IEnumerable a sequence the fact that it returns an object to iterate through the collection? Perhaps the real distinction is purely found in functional languages?

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  • Is there a simple way to make lists behave as files (with ftplib)

    - by Brent.Longborough
    I'd like to use ftplib to upload program-generated data as lists. The nearest method I can see for doing this is ftp.storlines, but this requires a file object with a readlines() method. Obviously I could create a file, but this seems like overkill as the data isn't persistent. Is there anything that could do this?: session = ftp.new(...) upload = convertListToFileObject(mylist) session.storlines("STOR SOMETHING",upload) session.quit

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  • All possible permutations of a set of lists in Python

    - by Ian Davis
    In Python I have a list of n lists, each with a variable number of elements. How can I create a single list containing all the possible permutations: For example [ [ a, b, c], [d], [e, f] ] I want [ [a, d, e] , [a, d, f], [b, d, e], [b, d, f], [c, d, e], [c, d, f] ] Note I don't know n in advance. I thought itertools.product would be the right approach but it requires me to know the number of arguments in advance

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  • .net databound lists

    - by d daly
    Hi, Is there any way around this? I have a few dropdown lists bound to lookup tables in sql server. some old records imported from a previos version of the system wont open due to data in these fields not matching the current dropdown data. Other than adding the old data to the lookup table (which I dont want to do) is there a way around this? Thanks DD

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  • linked list problem (with insert)

    - by JohnWong
    The problem appears with the insert function that I wrote. 3 conditions must work, I tested b/w 1 and 2, b/w 2 and 3 and as last element, they worked. But b/w 3 and 4, it did not work. It only display up to the new added record, and did not show the fourth element. Efficiency is not my concern here (not yet). Please guide me through this debug process. Thank you very much. #include<iostream> #include<string> using namespace std; struct List // we create a structure called List { string name; string tele; List *nextAddr; }; void populate(List *); void display(List *); void insert(List *); int main() { const int MAXINPUT = 3; char ans; List * data, * current, * point; // create two pointers data = new List; current = data; for (int i = 0; i < (MAXINPUT - 1); i++) { populate(current); current->nextAddr = new List; current = current->nextAddr; } // last record we want to do it sepeartely populate(current); current->nextAddr = NULL; cout << "The current list consists of the following data records: " << endl; display(data); // now ask whether user wants to insert new record or not cout << "Do you want to add a new record (Y/N)?"; cin >> ans; if (ans == 'Y' || ans == 'y') { /* To insert b/w first and second, use point as parameter between second and third uses point->nextAddr between third and fourth uses point->nextAddr->nextAddr and insert as last element, uses current instead */ point = data; insert(()); display(data); } return 0; } void populate(List *data) { cout << "Enter a name: "; cin >> data->name; cout << "Enter a phone number: "; cin >> data->tele; return; } void display(List *content) { while (content != NULL) { cout << content->name << " " << content->tele; content = content->nextAddr; cout << endl; // we skip to next line } return; } void insert(List *last) { List * temp = last->nextAddr; //save the next address to temp last->nextAddr = new List; // now modify the address pointed to new allocation last = last->nextAddr; populate(last); last->nextAddr = temp; // now link all three together, eg 1-NEW-2 return; }

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  • What's the best way to read mailing lists in 2011?

    - by Avdi
    I used to use Emacs/GNUS for reading mailing lists, but that feels very 1990. Plus, it doesn't sync my scoring across PCs. GMail is wonderful, but it kind of sucks for mailing lists. The essential "mute" feature doesn't even work unless the mail is in the Inbox. I'd read my mailing lists on the Google Groups site, but not all of them are Google Groups. Basically, I'm looking for the "Google Reader" of mailing lists. Any suggestions?

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  • jQuery.each for lists and non-lists

    - by Brian M. Hunt
    I've a jQuery.each(data, foo), where data is either a string or a list of strings. I'd like to know if there's an existing utility function to convert the string to a list, or otherwise perform foo on just the string. So instead of the easy route: if (!$.isArray(data)) { foo(0, data); // can't rely on `this` variable } else { $.each(data,foo); } I was just wondering if there was already a builtin function of jQuery or Javascript that would convert data to a list automatically, like this: function convert_to_list(data) { return $.isArray(data) ? data : [data]; } $.each(convert_to_list(data), foo); Just curious! Thanks for reading. Brian

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  • Linked list recursive reverse

    - by Phoenix
    I was looking at the code below from stanford library: void recursiveReverse(struct node** head_ref) { struct node* first; struct node* rest; /* empty list */ if (*head_ref == NULL) return; /* suppose first = {1, 2, 3}, rest = {2, 3} */ first = *head_ref; rest = first->next; /* List has only one node */ if (rest == NULL) return; /* put the first element on the end of the list */ recursiveReverse(&rest); first->next->next = first; /* tricky step -- see the diagram */ first->next = NULL; /* fix the head pointer */ *head_ref = rest; } What I don't understand is in the last recursive step for e.g if list is 1-2-3-4 Now for the last recursive step first will be 1 and rest will be 2. So if you set *head_ref = rest .. that makes the head of the list 2 ?? Can someone please explain how after reversing the head of the list becomes 4 ??

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  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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  • Linked List pop() function

    - by JKid314159
    Consider the following list: [LinkNode * head -- LinkNode * node1 -- LinkNode * node2] I'm creating a stack of FIFO. I Call pop() which I want to pop node1. LinkNode::LinkNode(int numIn) { this->numIn = numIn; next = null; } . . . int LinkNode::pop() { Link * temp = head->next; head = temp->next; int popped = head->nodeNum; delete temp; Return numOut; Question: 1) head should be a pointer or a LinkNode *? 2) Link * temp is created on the call stack and when pop finishes doesn't temp delete automatically? 3) My major confusion is on what is the value of temp-next? Does this point to node1.next which equals node2? Appreciate your help? My reference is C++ for Java Programmers by Weiss.

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  • adding a node to a linked list.

    - by sil3nt
    Hi there, ive been given the following code, And im just wondering, what does *&listpointer mean in the argument of the addnode function? struct Node { int accnumber; float balance; Node *next; }; Node *A, *B; int main() { A = NULL; B = NULL; AddNode(A, 123, 99.87); AddNode(B, 789, 52.64); } void AddNode(Node * & listpointer, int a, float b) { // add a new node to the FRONT of the list Node *temp; temp = new Node; temp->accnumber = a; temp->balance = b; temp->next = listpointer; listpointer = temp; }

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  • pointer and reference question (linked lists)

    - by sil3nt
    Hi there, I have the following code struct Node { int accnumber; float balance; Node *next; }; Node *A, *B; int main() { A = NULL; B = NULL; AddNode(A, 123, 99.87); AddNode(B, 789, 52.64); etc… } void AddNode(Node * & listpointer, int a, float b) { // add a new node to the FRONT of the list Node *temp; temp = new Node; temp->accnumber = a; temp->balance = b; temp->next = listpointer; listpointer = temp; } in this here void AddNode(Node * & listpointer, int a, float b) { what does *& listpointer mean exactly.

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  • Removing a node from a linked list

    - by lost_with_coding
    I would like to create a delete_node function that deletes the node at the location in the list as a count from the first node. So far this is the code I have: class node: def __init__(self): self.data = None # contains the data self.next = None # contains the reference to the next node class linked_list: def __init__(self): self.cur_node = None def add_node(self, data): new_node = node() # create a new node new_node.data = data new_node.next = self.cur_node # link the new node to the 'previous' node. self.cur_node = new_node # set the current node to the new one. def list_print(self): node = ll.cur_node while node: print node.data node = node.next def delete_node(self,location): node = ll.cur_node count = 0 while count != location: node = node.next count+=1 delete node ll = linked_list() ll.add_node(1) ll.add_node(2) ll.add_node(3) ll.list_print()

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  • Linked List push()

    - by JKid314159
    The stack is initialized with a int MaxSize =3. Then I push one int onto the list. " Pushed:" is returned to the console. Program crashes here. I think my logic is flawed but unsure. Maybe an infinite loop or unmet condition? Thanks for your help. I'm trying to traverse the list to the last node in the second part of the full() method. I implemented this stack as array based so must implement this method full() as this method is inside of main class. while(!stacker.full()) { cout << "Enter number = "; cin >> intIn; stacker.push(intIn); cout << "Pushed: " << intIn << endl; }//while Call to LinkListStack.cpp to class LinkList full(). int LinkList::full() { if(head == NULL) { top = 0; } else { LinkNode * tmp1; LinkNode * tmp2; tmp1 = head; while(top != MaxSize) { if(tmp1->next != NULL){ tmp2 = tmp1->next; tmp1 = tmp2; ++top; }//if }//while }//else return (top + 1 == MaxSize); }

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  • Appending unique values only in a linked list in C

    - by LuckySlevin
    typedef struct child {int count; char word[100]; inner_list*next;} child; typedef struct parent { char data [100]; inner_list * head; int count; outer_list * next; } parent; void append(child **q,char num[100],int size) { child *temp,*r,*temp2,*temp3; parent *out=NULL; temp = *q; temp2 = *q; temp3 = *q; char *str; if(*q==NULL) { temp = (child *)malloc(sizeof(child)); strcpy(temp->word,num); temp->count =size; temp->next=NULL; *q=temp; } else { temp = *q; while(temp->next !=NULL) { temp=temp->next; } r = (child *)malloc(sizeof(child)); strcpy(r->word,num); r->count = size; r->next=NULL; temp->next=r; } } This is my append function which I use for adding an element to my child list. But my problem is it only should append unique values which are followed by a string. Which means : Inputs : aaa bbb aaa ccc aaa bbb ccc aaa Append should act : For aaa string there should be a list like bbb->ccc(Not bbb->ccc->bbb since bbb is already there if bbb is coming more than one time it should be increase count only.) For bbb string there should be list like aaa->ccc only For ccc string there should be list like aaa only I hope i could make myself clear. Is there any ideas? Please ask for further info.

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