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  • Shortest Distance From An Array

    - by notyou61
    I have an ajax function which returns the latitudes and longitudes of locations stored in a database. These are returned and placed in an array. A calculation is performed to return their distance from the users current location based on the latitude/longitude. I would like to return only the record with the shortest calculated distance. My code is as follows: Ajax Success // Success success: function (data) { // Obtain Log/Lat navigator.geolocation.getCurrentPosition(function(position) { // Obtain Current Position Lat/Lon glbVar.latitude = position.coords.latitude; glbVar.longitude = position.coords.longitude; // Console Log //console.log('Lat: ' + glbVar.latitude + ' Lon: ' + glbVar.longitude); // Obtain Location Distances for ( var i = 0; i < data.length; i++ ) { // Location Instances var varLocation = data[i]; // Location Distance varLocation.distance = calculateDistance(glbVar.longitude, glbVar.latitude, varLocation.locationLongitude, varLocation.locationLatitude); } // Sort Locations By Distance var sortedData = data.sort(function(a, b) { // Return Locations return a.distance - b.distance; }); // Output Results $.map(sortedData, function(item) { // Obtain Location Distance varLocationsDistance = calculateDistance(glbVar.longitude, glbVar.latitude, item.locationLongitude, item.locationLatitude); // Obtain Location Radius Assignment if (varLocationsDistance <= varLocationRadius) { // Function Return functionReturn = $({locationID : item.locationID + ', Distance : ' + varLocationsDistance + ' m'}); // Return // Function to get the Min value in Array Array.min = function( sortedData ){ functionReturn = Math.min.apply( Math, sortedData ); // console.log(functionReturn); }; } }); }); } The calculateDistance function returns the distance from the users current location and those from the database. The varLocationsDistance <= varLocationRadius "If" statement returns records within a certain distance radius (100 meters), within that statement I would like to return the shortest distance. I am a self taught amateur web developer and as a result may not have provide enough information for an answer, please let me know. Thanks,

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  • Basic Spatial Data with SQL Server and Entity Framework 5.0

    - by Rick Strahl
    In my most recent project we needed to do a bit of geo-spatial referencing. While spatial features have been in SQL Server for a while using those features inside of .NET applications hasn't been as straight forward as could be, because .NET natively doesn't support spatial types. There are workarounds for this with a few custom project like SharpMap or a hack using the Sql Server specific Geo types found in the Microsoft.SqlTypes assembly that ships with SQL server. While these approaches work for manipulating spatial data from .NET code, they didn't work with database access if you're using Entity Framework. Other ORM vendors have been rolling their own versions of spatial integration. In Entity Framework 5.0 running on .NET 4.5 the Microsoft ORM finally adds support for spatial types as well. In this post I'll describe basic geography features that deal with single location and distance calculations which is probably the most common usage scenario. SQL Server Transact-SQL Syntax for Spatial Data Before we look at how things work with Entity framework, lets take a look at how SQL Server allows you to use spatial data to get an understanding of the underlying semantics. The following SQL examples should work with SQL 2008 and forward. Let's start by creating a test table that includes a Geography field and also a pair of Long/Lat fields that demonstrate how you can work with the geography functions even if you don't have geography/geometry fields in the database. Here's the CREATE command:CREATE TABLE [dbo].[Geo]( [id] [int] IDENTITY(1,1) NOT NULL, [Location] [geography] NULL, [Long] [float] NOT NULL, [Lat] [float] NOT NULL ) Now using plain SQL you can insert data into the table using geography::STGeoFromText SQL CLR function:insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.527200 45.712113)', 4326), -121.527200, 45.712113 ) insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.517265 45.714240)', 4326), -121.517265, 45.714240 ) insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.511536 45.714825)', 4326), -121.511536, 45.714825) The STGeomFromText function accepts a string that points to a geometric item (a point here but can also be a line or path or polygon and many others). You also need to provide an SRID (Spatial Reference System Identifier) which is an integer value that determines the rules for how geography/geometry values are calculated and returned. For mapping/distance functionality you typically want to use 4326 as this is the format used by most mapping software and geo-location libraries like Google and Bing. The spatial data in the Location field is stored in binary format which looks something like this: Once the location data is in the database you can query the data and do simple distance computations very easily. For example to calculate the distance of each of the values in the database to another spatial point is very easy to calculate. Distance calculations compare two points in space using a direct line calculation. For our example I'll compare a new point to all the points in the database. Using the Location field the SQL looks like this:-- create a source point DECLARE @s geography SET @s = geography:: STGeomFromText('POINT(-121.527200 45.712113)' , 4326); --- return the ids select ID, Location as Geo , Location .ToString() as Point , @s.STDistance( Location) as distance from Geo order by distance The code defines a new point which is the base point to compare each of the values to. You can also compare values from the database directly, but typically you'll want to match a location to another location and determine the difference for which you can use the geography::STDistance function. This query produces the following output: The STDistance function returns the straight line distance between the passed in point and the point in the database field. The result for SRID 4326 is always in meters. Notice that the first value passed was the same point so the difference is 0. The other two points are two points here in town in Hood River a little ways away - 808 and 1256 meters respectively. Notice also that you can order the result by the resulting distance, which effectively gives you results that are ordered radially out from closer to further away. This is great for searches of points of interest near a central location (YOU typically!). These geolocation functions are also available to you if you don't use the Geography/Geometry types, but plain float values. It's a little more work, as each point has to be created in the query using the string syntax, but the following code doesn't use a geography field but produces the same result as the previous query.--- using float fields select ID, geography::STGeomFromText ('POINT(' + STR (long, 15,7 ) + ' ' + Str(lat ,15, 7) + ')' , 4326), geography::STGeomFromText ('POINT(' + STR (long, 15,7 ) + ' ' + Str(lat ,15, 7) + ')' , 4326). ToString(), @s.STDistance( geography::STGeomFromText ('POINT(' + STR(long ,15, 7) + ' ' + Str(lat ,15, 7) + ')' , 4326)) as distance from geo order by distance Spatial Data in the Entity Framework Prior to Entity Framework 5.0 on .NET 4.5 consuming of the data above required using stored procedures or raw SQL commands to access the spatial data. In Entity Framework 5 however, Microsoft introduced the new DbGeometry and DbGeography types. These immutable location types provide a bunch of functionality for manipulating spatial points using geometry functions which in turn can be used to do common spatial queries like I described in the SQL syntax above. The DbGeography/DbGeometry types are immutable, meaning that you can't write to them once they've been created. They are a bit odd in that you need to use factory methods in order to instantiate them - they have no constructor() and you can't assign to properties like Latitude and Longitude. Creating a Model with Spatial Data Let's start by creating a simple Entity Framework model that includes a Location property of type DbGeography: public class GeoLocationContext : DbContext { public DbSet<GeoLocation> Locations { get; set; } } public class GeoLocation { public int Id { get; set; } public DbGeography Location { get; set; } public string Address { get; set; } } That's all there's to it. When you run this now against SQL Server, you get a Geography field for the Location property, which looks the same as the Location field in the SQL examples earlier. Adding Spatial Data to the Database Next let's add some data to the table that includes some latitude and longitude data. An easy way to find lat/long locations is to use Google Maps to pinpoint your location, then right click and click on What's Here. Click on the green marker to get the GPS coordinates. To add the actual geolocation data create an instance of the GeoLocation type and use the DbGeography.PointFromText() factory method to create a new point to assign to the Location property:[TestMethod] public void AddLocationsToDataBase() { var context = new GeoLocationContext(); // remove all context.Locations.ToList().ForEach( loc => context.Locations.Remove(loc)); context.SaveChanges(); var location = new GeoLocation() { // Create a point using native DbGeography Factory method Location = DbGeography.PointFromText( string.Format("POINT({0} {1})", -121.527200,45.712113) ,4326), Address = "301 15th Street, Hood River" }; context.Locations.Add(location); location = new GeoLocation() { Location = CreatePoint(45.714240, -121.517265), Address = "The Hatchery, Bingen" }; context.Locations.Add(location); location = new GeoLocation() { // Create a point using a helper function (lat/long) Location = CreatePoint(45.708457, -121.514432), Address = "Kaze Sushi, Hood River" }; context.Locations.Add(location); location = new GeoLocation() { Location = CreatePoint(45.722780, -120.209227), Address = "Arlington, OR" }; context.Locations.Add(location); context.SaveChanges(); } As promised, a DbGeography object has to be created with one of the static factory methods provided on the type as the Location.Longitude and Location.Latitude properties are read only. Here I'm using PointFromText() which uses a "Well Known Text" format to specify spatial data. In the first example I'm specifying to create a Point from a longitude and latitude value, using an SRID of 4326 (just like earlier in the SQL examples). You'll probably want to create a helper method to make the creation of Points easier to avoid that string format and instead just pass in a couple of double values. Here's my helper called CreatePoint that's used for all but the first point creation in the sample above:public static DbGeography CreatePoint(double latitude, double longitude) { var text = string.Format(CultureInfo.InvariantCulture.NumberFormat, "POINT({0} {1})", longitude, latitude); // 4326 is most common coordinate system used by GPS/Maps return DbGeography.PointFromText(text, 4326); } Using the helper the syntax becomes a bit cleaner, requiring only a latitude and longitude respectively. Note that my method intentionally swaps the parameters around because Latitude and Longitude is the common format I've seen with mapping libraries (especially Google Mapping/Geolocation APIs with their LatLng type). When the context is changed the data is written into the database using the SQL Geography type which looks the same as in the earlier SQL examples shown. Querying Once you have some location data in the database it's now super easy to query the data and find out the distance between locations. A common query is to ask for a number of locations that are near a fixed point - typically your current location and order it by distance. Using LINQ to Entities a query like this is easy to construct:[TestMethod] public void QueryLocationsTest() { var sourcePoint = CreatePoint(45.712113, -121.527200); var context = new GeoLocationContext(); // find any locations within 5 kilometers ordered by distance var matches = context.Locations .Where(loc => loc.Location.Distance(sourcePoint) < 5000) .OrderBy( loc=> loc.Location.Distance(sourcePoint) ) .Select( loc=> new { Address = loc.Address, Distance = loc.Location.Distance(sourcePoint) }); Assert.IsTrue(matches.Count() > 0); foreach (var location in matches) { Console.WriteLine("{0} ({1:n0} meters)", location.Address, location.Distance); } } This example produces: 301 15th Street, Hood River (0 meters)The Hatchery, Bingen (809 meters)Kaze Sushi, Hood River (1,074 meters)   The first point in the database is the same as my source point I'm comparing against so the distance is 0. The other two are within the 5 mile radius, while the Arlington location which is 65 miles or so out is not returned. The result is ordered by distance from closest to furthest away. In the code, I first create a source point that is the basis for comparison. The LINQ query then selects all locations that are within 5km of the source point using the Location.Distance() function, which takes a source point as a parameter. You can either use a pre-defined value as I'm doing here, or compare against another database DbGeography property (say when you have to points in the same database for things like routes). What's nice about this query syntax is that it's very clean and easy to read and understand. You can calculate the distance and also easily order by the distance to provide a result that shows locations from closest to furthest away which is a common scenario for any application that places a user in the context of several locations. It's now super easy to accomplish this. Meters vs. Miles As with the SQL Server functions, the Distance() method returns data in meters, so if you need to work with miles or feet you need to do some conversion. Here are a couple of helpers that might be useful (can be found in GeoUtils.cs of the sample project):/// <summary> /// Convert meters to miles /// </summary> /// <param name="meters"></param> /// <returns></returns> public static double MetersToMiles(double? meters) { if (meters == null) return 0F; return meters.Value * 0.000621371192; } /// <summary> /// Convert miles to meters /// </summary> /// <param name="miles"></param> /// <returns></returns> public static double MilesToMeters(double? miles) { if (miles == null) return 0; return miles.Value * 1609.344; } Using these two helpers you can query on miles like this:[TestMethod] public void QueryLocationsMilesTest() { var sourcePoint = CreatePoint(45.712113, -121.527200); var context = new GeoLocationContext(); // find any locations within 5 miles ordered by distance var fiveMiles = GeoUtils.MilesToMeters(5); var matches = context.Locations .Where(loc => loc.Location.Distance(sourcePoint) <= fiveMiles) .OrderBy(loc => loc.Location.Distance(sourcePoint)) .Select(loc => new { Address = loc.Address, Distance = loc.Location.Distance(sourcePoint) }); Assert.IsTrue(matches.Count() > 0); foreach (var location in matches) { Console.WriteLine("{0} ({1:n1} miles)", location.Address, GeoUtils.MetersToMiles(location.Distance)); } } which produces: 301 15th Street, Hood River (0.0 miles)The Hatchery, Bingen (0.5 miles)Kaze Sushi, Hood River (0.7 miles) Nice 'n simple. .NET 4.5 Only Note that DbGeography and DbGeometry are exclusive to Entity Framework 5.0 (not 4.4 which ships in the same NuGet package or installer) and requires .NET 4.5. That's because the new DbGeometry and DbGeography (and related) types are defined in the 4.5 version of System.Data.Entity which is a CLR assembly and is only updated by major versions of .NET. Why this decision was made to add these types to System.Data.Entity rather than to the frequently updated EntityFramework assembly that would have possibly made this work in .NET 4.0 is beyond me, especially given that there are no native .NET framework spatial types to begin with. I find it also odd that there is no native CLR spatial type. The DbGeography and DbGeometry types are specific to Entity Framework and live on those assemblies. They will also work for general purpose, non-database spatial data manipulation, but then you are forced into having a dependency on System.Data.Entity, which seems a bit silly. There's also a System.Spatial assembly that's apparently part of WCF Data Services which in turn don't work with Entity framework. Another example of multiple teams at Microsoft not communicating and implementing the same functionality (differently) in several different places. Perplexed as a I may be, for EF specific code the Entity framework specific types are easy to use and work well. Working with pre-.NET 4.5 Entity Framework and Spatial Data If you can't go to .NET 4.5 just yet you can also still use spatial features in Entity Framework, but it's a lot more work as you can't use the DbContext directly to manipulate the location data. You can still run raw SQL statements to write data into the database and retrieve results using the same TSQL syntax I showed earlier using Context.Database.ExecuteSqlCommand(). Here's code that you can use to add location data into the database:[TestMethod] public void RawSqlEfAddTest() { string sqlFormat = @"insert into GeoLocations( Location, Address) values ( geography::STGeomFromText('POINT({0} {1})', 4326),@p0 )"; var sql = string.Format(sqlFormat,-121.527200, 45.712113); Console.WriteLine(sql); var context = new GeoLocationContext(); Assert.IsTrue(context.Database.ExecuteSqlCommand(sql,"301 N. 15th Street") > 0); } Here I'm using the STGeomFromText() function to add the location data. Note that I'm using string.Format here, which usually would be a bad practice but is required here. I was unable to use ExecuteSqlCommand() and its named parameter syntax as the longitude and latitude parameters are embedded into a string. Rest assured it's required as the following does not work:string sqlFormat = @"insert into GeoLocations( Location, Address) values ( geography::STGeomFromText('POINT(@p0 @p1)', 4326),@p2 )";context.Database.ExecuteSqlCommand(sql, -121.527200, 45.712113, "301 N. 15th Street") Explicitly assigning the point value with string.format works however. There are a number of ways to query location data. You can't get the location data directly, but you can retrieve the point string (which can then be parsed to get Latitude and Longitude) and you can return calculated values like distance. Here's an example of how to retrieve some geo data into a resultset using EF's and SqlQuery method:[TestMethod] public void RawSqlEfQueryTest() { var sqlFormat = @" DECLARE @s geography SET @s = geography:: STGeomFromText('POINT({0} {1})' , 4326); SELECT Address, Location.ToString() as GeoString, @s.STDistance( Location) as Distance FROM GeoLocations ORDER BY Distance"; var sql = string.Format(sqlFormat, -121.527200, 45.712113); var context = new GeoLocationContext(); var locations = context.Database.SqlQuery<ResultData>(sql); Assert.IsTrue(locations.Count() > 0); foreach (var location in locations) { Console.WriteLine(location.Address + " " + location.GeoString + " " + location.Distance); } } public class ResultData { public string GeoString { get; set; } public double Distance { get; set; } public string Address { get; set; } } Hopefully you don't have to resort to this approach as it's fairly limited. Using the new DbGeography/DbGeometry types makes this sort of thing so much easier. When I had to use code like this before I typically ended up retrieving data pks only and then running another query with just the PKs to retrieve the actual underlying DbContext entities. This was very inefficient and tedious but it did work. Summary For the current project I'm working on we actually made the switch to .NET 4.5 purely for the spatial features in EF 5.0. This app heavily relies on spatial queries and it was worth taking a chance with pre-release code to get this ease of integration as opposed to manually falling back to stored procedures or raw SQL string queries to return spatial specific queries. Using native Entity Framework code makes life a lot easier than the alternatives. It might be a late addition to Entity Framework, but it sure makes location calculations and storage easy. Where do you want to go today? ;-) Resources Download Sample Project© Rick Strahl, West Wind Technologies, 2005-2012Posted in ADO.NET  Sql Server  .NET   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • current location too slow for view

    - by Christian
    Hi, I make an App with a Map in the App and a button to change to the google.Map-App. The code for my position is: -(void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation { float avgAccuracy = (newLocation.verticalAccuracy + newLocation.horizontalAccuracy)/2.0; if (avgAccuracy < 500) { [locationManager stopUpdatingLocation]; locationManager.delegate = nil; } storedLocation = [newLocation coordinate]; The code for the view is: - (void)viewDidLoad { [super viewDidLoad]; UIImage *image = [UIImage imageNamed: @"LogoNavBar.png"]; UIImageView *imageview = [[UIImageView alloc] initWithImage: image]; UIBarButtonItem *button = [[UIBarButtonItem alloc] initWithCustomView: imageview]; self.navigationItem.rightBarButtonItem = button; [imageview release]; [button release]; locationManager=[[CLLocationManager alloc] init]; locationManager.delegate = self; locationManager.desiredAccuracy = kCLLocationAccuracyBest; locationManager.distanceFilter = kCLDistanceFilterNone; [locationManager startUpdatingLocation]; mapView.showsUserLocation = YES; NSLog(@"storedLocation-latitude für MKregion: %f", storedLocation.latitude); MKCoordinateRegion region; region.center.latitude = (storedLocation.latitude + 45.58058)/2.0; region.center.longitude = (storedLocation.longitude - 0.546835)/2.0; region.span.latitudeDelta = ABS(storedLocation.latitude - 45.58058); region.span.longitudeDelta = ABS(storedLocation.longitude + 0.546835); [mapView setRegion:region animated:TRUE]; MKCoordinateRegion hotel; hotel.center.latitude = 45.58058; hotel.center.longitude = -0.546835; HotelPositionMarker* marker = [[HotelPositionMarker alloc] initWithCoordinate:hotel.center]; [mapView addAnnotation:marker]; [marker release]; } My problem: when the "viewDidLoad" start, the "storedLocation" is still 0.0000 it takes a bit longer to get the own position than to start the view. The Log for the "storedLocation" in the "viewDidLoad"-section is 0 while the Log of the "storedLocation" in the "-(IBAction)" when the map is visible contains the right values. How can I manage it to have my coordinates before the view load? I need them to center the view concerning the own position and the position given by me. MKCoordinateRegion region; region.center.latitude = (storedLocation.latitude + 45.58058)/2.0; region.center.longitude = (storedLocation.longitude - 0.546835)/2.0; region.span.latitudeDelta = ABS(storedLocation.latitude - 45.58058); region.span.longitudeDelta = ABS(storedLocation.longitude + 0.546835); [mapView setRegion:region animated:TRUE];

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  • iPhone Objective C - error: pointer value used where a floating point value was expected

    - by Mausimo
    I do not understand why i am getting this error. Here is the related code: Photo.h #import <CoreData/CoreData.h> @class Person; @interface Photo : NSManagedObject { } @property (nonatomic, retain) NSData * imageData; @property (nonatomic, retain) NSNumber * Latitude; @property (nonatomic, retain) NSString * ImageName; @property (nonatomic, retain) NSString * ImagePath; @property (nonatomic, retain) NSNumber * Longitude; @property (nonatomic, retain) Person * PhotoToPerson; @end Photo.m #import "Photo.h" #import "Person.h" @implementation Photo @dynamic imageData; @dynamic Latitude; @dynamic ImageName; @dynamic ImagePath; @dynamic Longitude; @dynamic PhotoToPerson; @end This is a mapViewController.m class i have created. If i run this, the CLLocationDegrees CLLat and CLLong lines: CLLocationDegrees CLLat = (CLLocationDegrees)photo.Latitude; CLLocationDegrees CLLong = (CLLocationDegrees)photo.Longitude; give me the error : pointer value used where a floating point value was expected. for(int i = 0; i < iPerson; i++) { //get the person that corresponds to the row indexPath that is currently being rendered and set the text Person * person = (Person *)[myArrayPerson objectAtIndex:i]; //get the photos associated with the person NSArray * PhotoArray = [person.PersonToPhoto allObjects]; int iPhoto = [PhotoArray count]; for(int j = 0; j < iPhoto; j++) { //get the first photo (all people will have atleast 1 photo, else they will not exist). Set the image Photo * photo = (Photo *)[PhotoArray objectAtIndex:j]; if(photo.Latitude != nil && photo.Longitude != nil) { MyAnnotation *ann = [[MyAnnotation alloc] init]; ann.title = photo.ImageName; ann.subtitle = photo.ImageName; CLLocationCoordinate2D cord; CLLocationDegrees CLLat = (CLLocationDegrees)photo.Latitude; CLLocationDegrees CLLong = (CLLocationDegrees)photo.Longitude; cord.latitude = CLLat; cord.longitude = CLLong; ann.coordinate = cord; [mkMapView addAnnotation:ann]; } } }

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  • what to do when Bing api provides inaccurate results

    - by hao
    I am trying to use the bing Phonebook search for locations in China, but all the latitude and longitude are inaccurate. Using the following http://api.bing.net/xml.aspx?AppId=appid&Query=nike&Sources=Phonebook&Latitude=39.9883699&Longitude=116.3309665&Radius=30.0&Phonebook.Count=10&Phonebook.Offset=30 I get multiple locations with the same latitude and longitude, and the rounding is off as well. The latitude and longitude will always end with either .x00001 or .0. The results from the pho:LocalSerpUrl http://www.bing.com/shenghuo/default.aspx?what=nike&where=&s_cid=ansPhBkYp01&ac=false&FORM=SOAPGN /pho:LocalSerpUrl Is right, but the results from the returned xml is off. Also it seems users outside of China can't hit that url and get the result. So I am wondering how I can contact bing and inquire about this problem

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  • Blackberry.location API not working correctly

    - by chibineku
    I am experimenting with making Blackberry widgets but having a little trouble. My first trial involves displaying a button which, when clicked, calls a JavaScript function that should alert the phones latitude and longitude. The function looks: function whereAmI() { var latitude = blackberry.location.latitude; var longitude = blackberry.location.longitude; alert("Lat: "+latitude+", Long: "+longitude); } But it only ever alerts "Lat: 0, Long: 0". I've checked and my GPS seems to be working ok. I'm running OS 5.* on a Curve 8900. Any help would be appreciated :)

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  • Setting corelocation results to NSNumber object parameters

    - by Dan Ray
    This is a weird one, y'all. - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation { CLLocationCoordinate2D coordinate = newLocation.coordinate; self.mark.longitude = [NSNumber numberWithDouble:coordinate.longitude]; self.mark.latitude = [NSNumber numberWithDouble:coordinate.latitude]; NSLog(@"Got %f %f, set %f %f", coordinate.latitude, coordinate.longitude, self.mark.latitude, self.mark.longitude); [manager stopUpdatingLocation]; manager.delegate = nil; if (self.waitingForLocation) { [self completeUpload]; } } The latitude and longitude in that "mark" object are synthesized parameters referring to NSNumber iVars. In the simulator, my NSLog output for that line in the middle there reads: 2010-05-28 15:08:46.938 EverWondr[8375:207] Got 37.331689 -122.030731, set 0.000000 -44213283338325225829852024986561881455984640.000000 That's a WHOLE lot further East than 1 Infinite Loop! The numbers are different on the device, but similar--lat is still zero and long is a very unlikely high negative number. Elsewhere in the controller I'm accepting a button press and uploading a file (an image I just took with the camera) with its geocoding info associated, and I need that self.waitingForLocation to inform the CLLocationManager delegate that I already hit that button and once its done its deal, it should go ahead and fire off the upload. Thing is, up in the button-click-receiving method, I test see if CL is finished by testing self.mark.latitude, which seems to be getting set zero...

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  • Updating / refreshing a live geojson layer | JSON & JS Variable

    - by Ozaki
    TLDR I am trying to get my geoJSON layer to update, currently it will 1. Create the vector mark, 2. Remove the vector mark, 3. Set the JS variable for lat and lon, 4. Unset the variable??? :S Hey S O. I have a geojson layer set up as follows: //GeoJSON Layer// var layer1 = new OpenLayers.Layer.GML("My GeoJSON Layer", "coordinates", {format: OpenLayers.Format.GeoJSON, styleMap: style_red}); My features are set up as follows: var latitude = 0.0; // as 0.0 it will draw the point in. var longitude = 0.0; // as 0.0 it will draw the point in. //var longitude = getlongitude; where getlongitude = JSON string of longitude. var point = new OpenLayers.Geometry.Point(longitude, latitude); pointFeature = new OpenLayers.Feature.Vector(point, null, style_red); var style_red = OpenLayers.Util.extend({}, layer_style); style_red.strokeColor = "red"; style_red.fillColor = "black"; style_red.fillOpacity = 0.5; style_red.graphicName = "circle"; style_red.pointRadius = 3.8; style_red.strokeWidth = 2; style_red.strokeLinecap = "butt"; and my layer updating function: function UpdateLayer(){ var p = new OpenLayers.Format.GeoJSON({ 'internalProjection': new OpenLayers.Projection("EPSG:900913"), 'externalProjection': new OpenLayers.Projection("EPSG:4326") }); var url = "coordinates"; OpenLayers.loadURL(url, {}, null, function(r) { var f = p.read(r.responseText); map.layers[2].destroyFeatures(); map.layers[2].addFeatures(pointFeature); }); setTimeout("UpdateLayer()",1000) } Any idea what I am doing wrong or what I am missing? Edit1 It now removes the feature (was map.layers[1]) previously... But will not add the new feature.. Edit2 I managed to get it to redraw a point but not with live data. It should draw the point at what (latitude) & (longitude) are equal to. I am trying to set latitude & longitude to some JSON string but every time straight after it sets the variable it changes it back to "undefined" as soon as it passes the line after var latitude? (using firebug & firequery to debug)

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  • Geolocation SQL query not finding exact location

    - by Iridium52
    I have been testing my geolocation query for some time now and I haven't found any issues with it until now. I am trying to search for all cities within a given radius, often times I'm searching for cities surrounding a city using that city's coords, but recently I tried searching around a city and found that the city itself was not returned. I have these cities as an excerpt in my database: city latitude longitude Saint-Mathieu 45.316708 -73.516253 Saint-Édouard 45.233374 -73.516254 Saint-Michel 45.233374 -73.566256 Saint-Rémi 45.266708 -73.616257 But when I run my query around the city of Saint-Rémi, with the following query... SELECT tblcity.city, tblcity.latitude, tblcity.longitude, truncate((degrees(acos( sin(radians(tblcity.latitude)) * sin(radians(45.266708)) + cos(radians(tblcity.latitude)) * cos(radians(45.266708)) * cos(radians(tblcity.longitude - -73.616257) ) ) ) * 69.09*1.6),1) as distance FROM tblcity HAVING distance < 10 ORDER BY distance desc I get these results: city latitude longitude distance Saint-Mathieu 45.316708 -73.516253 9.5 Saint-Édouard 45.233374 -73.516254 8.6 Saint-Michel 45.233374 -73.566256 5.3 The town of Saint-Rémi is missing from the search. So I tried a modified query hoping to get a better result: SELECT tblcity.city, tblcity.latitude, tblcity.longitude, truncate(( 6371 * acos( cos( radians( 45.266708 ) ) * cos( radians( tblcity.latitude ) ) * cos( radians( tblcity.longitude ) - radians( -73.616257 ) ) + sin( radians( 45.266708 ) ) * sin( radians( tblcity.latitude ) ) ) ),1) AS distance FROM tblcity HAVING distance < 10 ORDER BY distance desc But I get the same result... However, if I modify Saint-Rémi's coords slighly by changing the last digit of the lat or long by 1, both queries will return Saint-Rémi. Also, if I center the query on any of the other cities above, the searched city is returned in the results. Can anyone shed some light on what may be causing my queries above to not display the searched city of Saint-Rémi? I have added a sample of the table (with extra fields removed) below. I'm using MySQL 5.0.45, thanks in advance. CREATE TABLE `tblcity` ( `IDCity` int(1) NOT NULL auto_increment, `City` varchar(155) NOT NULL default '', `Latitude` decimal(9,6) NOT NULL default '0.000000', `Longitude` decimal(9,6) NOT NULL default '0.000000', PRIMARY KEY (`IDCity`) ) ENGINE=MyISAM AUTO_INCREMENT=52743 DEFAULT CHARSET=latin1 AUTO_INCREMENT=52743; INSERT INTO `tblcity` (`city`, `latitude`, `longitude`) VALUES ('Saint-Mathieu', 45.316708, -73.516253), ('Saint-Édouard', 45.233374, -73.516254), ('Saint-Michel', 45.233374, -73.566256), ('Saint-Rémi', 45.266708, -73.616257);

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  • iPhone current user location coordinates showing as (0,0)

    - by ennuikiller
    I'm trying to get the users current latitude and longitude with this viewDidLoad method. The resulting map is correctly indicating the current location however the NSLog consistently shows: 2009-09-19 16:45:29.765 Mapper[671:207] user latitude = 0.000000 2009-09-19 16:45:29.772 Mapper[671:207] user longitude = 0.000000 Anyone know what I am missing here? Thanks in advance for your help! - (void)viewDidLoad { [super viewDidLoad]; [mapView setMapType:MKMapTypeStandard]; [mapView setZoomEnabled:YES]; [mapView setScrollEnabled:YES]; [mapView setShowsUserLocation:YES]; CLLocation *userLoc = mapView.userLocation.location; CLLocationCoordinate2D userCoordinate = userLoc.coordinate; NSLog(@"user latitude = %f",userCoordinate.latitude); NSLog(@"user longitude = %f",userCoordinate.longitude); }

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  • Rails Pretty URL with Decimals

    - by Kevin Sylvestre
    I have a rails application that allows searches using longitude and latitude. I have added a 'pretty' route with: map.connect 'stores/near/:longitude/:latitude', :controller => 'stores', :action => 'index' This works for integer latitude and longitude values (http://localhost:3000/stores/near/-88/49) but fails for decimal values (http://localhost:3000/stores/near/-88.341/49.123) giving: Routing Error No route matches "/stores/near/-88/49.0" with {:method=>:get} Any ideas how to use pretty URLs in rails with decimals?

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  • WCF RIA Services Custom Type with Collection of Custom Types

    - by Blakewell
    Is it possible to have a custom type within a custom type and have the result returned via WCF RIA services? I have the following two classes below, but I can't gain access to the Verticies property within the Polygon class. I assume it is because it is a custom class, or something to do with it being a List collection. Polygon Class public class Polygon { public Polygon() { _vertices = new List<Location>(); } private int _id; [Key] public int Id { get; set; } private List<Location> _vertices; public List<Location> Vertices { get { return _vertices; } set { _vertices = value; } } } Location Class public class Location { public Location() { } /// <summary> /// Default constructor for creating a Location object /// </summary> /// <param name="latitude"></param> /// <param name="longitude"></param> public Location( double latitude, double longitude ) { _latitude = latitude; _longitude = longitude; } private int _id; [Key] public int Id { get { return _id; } set { _id = value; } } private double _latitude; /// <summary> /// Latitude coordinate of the location /// </summary> public double Latitude { get { return _latitude; } set { _latitude = value; } } private double _longitude; /// <summary> /// Longitude coordiante of the location /// </summary> public double Longitude { get { return _longitude; } set { _longitude = value; } } }

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  • Undefined return value

    - by yynneejj
    what's wrong to my code..where my return value found undefind... var so; var imgid_callback1; const DIV_ID = 'locationsample'; function setup(){ try { so = device.getServiceObject("Service.Location", "ILocation"); } catch (e) { alert('<setup> ' +e); } } function getLocation(imgId) { var updateoptions = new Object(); // Setting PartialUpdates to 'FALSE' ensures that user get atleast // BasicLocationInformation (Longitude, Lattitude, and Altitude.) updateoptions.PartialUpdates = false; var criteria = new Object(); criteria.LocationInformationClass = "BasicLocationInformation"; criteria.Updateoptions = updateoptions; try { var result = so.ILocation.GetLocation(criteria); if(!checkError("ILocation::getLocation",result,DIV_ID,imgId)) { document.getElementById(DIV_ID).innerHTML = showObject(result.ReturnValue); } } catch (e) { alert ("getLocation: " + e); } } function getLocationAsync(imgId) { var updateoptions = new Object(); updateoptions.PartialUpdates = false; var criteria = new Object(); criteria.LocationInformationClass = "BasicLocationInformation"; criteria.Updateoptions = updateoptions; imgid_callback1 = imgId; try { var result = so.ILocation.GetLocation(criteria, callback1); if(!checkError("ILocation::getLocationAsync",result,DIV_ID,imgId)) { showIMG(imgId,""); } } catch (e) { alert ("getLocationAsync: " + e); } } function callback1(transId, eventCode, result){ var latitude = result.ReturnValue.Latitude; //<-----Error: Undefined Value var longitude = result.ReturnValue.Longitude; var req = null; try { req = new XMLHttpRequest(); if (typeof req.overrideMimeType != "undefined") { req.overrideMimeType("text/xml"); } req.onreadystatechange = function() { if (req.readyState == 4) { if (req.status == 200) { } } else { alert("Error"); } } req.open("POST","http://localhost:8080/GPS/location",true); req.setRequestHeader("longitude",+longitude); req.setRequestHeader("latitude",+latitude); req.send(); } catch (ex) { alert(ex); } }

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  • Formating with printf in using two functions

    - by user317203
    I am trying to output a document that looks like this. http://pastebin.com/dpBAY8Sb my issue is that I cannot find how to format the output I have to have a floating poing and format the distance between columns. My current code looks something like this. if (defined $longitude){ printf FILE ("%-8s %.6f","",$longitude); }else{ $longitude = ""; printf FILE ("%-20s ",$longitude); } but the extra "" throws off the whole column and it looks like this. pastebin.com/kcwHyNwb

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  • Updating the getDistanceFrom between two annotations in MapKit

    - by Krismutt
    Hey everybody! I wanna have a UILabel that shows the distance between two annotations... but how do I get it to update the distance each time the current location is updated (location)?? CLLocationCoordinate2 savedPlace = savedPosition; CLLocationCoordinate2D currentPlace = location; CLLocation *locCurrent = [[CLLocation alloc] initWithLatitude:currentPlace.latitude longitude:currentPlace.longitude]; CLLocation *locSaved = [[CLLocation alloc] initWithLatitude:savedPlace.latitude longitude:savedPlace.longitude]; CLLocationDistance distance = [locSaved distanceFromLocation:locCurrent]; [showDistance setText:[NSString stringWithFormat:@"%g", distance]]; Thanks in advance!

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  • Getting Segmentation Fault in C++, but why?

    - by Carlos
    I am getting segmentation fault in this code but i cant figure out why. I know a segmentation fault happens when a pointer is NULL, or when it points to a random memory address. #include <iostream> #include <fstream> #include <cmath> using namespace std; //**************************** CLASS ******************************* class Database { struct data{ string city; float latitude, longitude; data *link; }*p; public: Database(); void display(); void add(string cityName, float lat, float lon); private: string cityName; float lat, lon; }; //************************** CLASS METHODS ************************** Database::Database() { p = NULL; } void Database::add(string cityName, float lat, float lon){ data *q, *t; if(p == NULL){ p = new data; p -> city = cityName; p -> latitude = lat; p -> longitude = lon; p -> link = NULL; } else{ q = p; while(q -> link != NULL){ q = q -> link; } t = new data; t -> city = cityName; t -> latitude = lat; t -> longitude = lon; q -> link = t; } } void Database::display() { data *q; cout<<endl; for( q = p ; q != NULL ; q = q->link ) cout << endl << q -> city; } //***************************** MAIN ******************************* //*** INITIALIZATION *** Database D; void loadDatabase(); //****** VARIABLES ***** //******* PROGRAM ****** int main() { loadDatabase(); D.display(); } void loadDatabase() { int i = 0; string cityName; float lat, lon; fstream city; city.open("city.txt", ios::in); fstream latitude; latitude.open("lat.txt", ios::in); fstream longitude; longitude.open("lon.txt", ios::in); while(!city.eof()){ //************************************ city >> cityName; //* * latitude >> lat; //Here is where i think is the problem longitude >> lon; //* * D.add(cityName, lat, lon); //************************************ } city.close(); latitude.close(); longitude.close(); } This is the error am actually getting in console

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  • Why is this postgresql query so slow?

    - by user315975
    I'm no database expert, but I have enough knowledge to get myself into trouble, as is the case here. This query SELECT DISTINCT p.* FROM points p, areas a, contacts c WHERE ( p.latitude > 43.6511659465 AND p.latitude < 43.6711659465 AND p.longitude > -79.4677941889 AND p.longitude < -79.4477941889) AND p.resource_type = 'Contact' AND c.user_id = 6 is extremely slow. The points table has fewer than 2000 records, but it takes about 8 seconds to execute. There are indexes on the latitude and longitude columns. Removing the clause concering the resource_type and user_id make no difference. The latitude and longitude fields are both formatted as number(15,10) -- I need the precision for some calculations. There are many, many other queries in this project where points are compared, but no execution time problems. What's going on?

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  • Filtering null values with pig

    - by arianp
    It looks like a silly problem, but I can´t find a way to filter null values from my rows. This is the result when I dump the object geoinfo: DUMP geoinfo; ([longitude#70.95853,latitude#30.9773]) ([longitude#-9.37944507,latitude#38.91780853]) (null) (null) (null) ([longitude#-92.64416,latitude#16.73326]) (null) (null) ([longitude#-9.15199849,latitude#38.71179122]) ([longitude#-9.15210796,latitude#38.71195131]) here is the description DESCRIBE geoinfo; geoinfo: {geoLocation: bytearray} What I'm trying to do is to filter null values like this: geoinfo_no_nulls = FILTER geoinfo BY geoLocation is not null; but the result remains the same. nothing is filtered. I also tried something like this geoinfo_no_nulls = FILTER geoinfo BY geoLocation != 'null'; and I got an error org.apache.pig.backend.executionengine.ExecException: ERROR 1071: Cannot convert a map to a String What am I doing wrong? details, running on ubuntu, hadoop-1.0.3 with pig 0.9.3 pig -version Apache Pig version 0.9.3-SNAPSHOT (rexported) compiled Oct 24 2012, 19:04:03 java version "1.6.0_24" OpenJDK Runtime Environment (IcedTea6 1.11.4) (6b24-1.11.4-1ubuntu0.12.04.1) OpenJDK 64-Bit Server VM (build 20.0-b12, mixed mode)

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  • unable to set href inside click event of Jquery

    - by akshatrautela
    Hi I am trying to set href using Jquery inside click event of RadioButtonList but that doesnt work If I take the same code to document.ready event it works fine but not in click event. Please advice. $(document).ready(function() { url = "Results.aspx?latitude=" +latitude + "&Longitude=" + longitude; $("a[href='http://www.google.com/']").attr("href", url); // this works.. } $('.rbl input').click(function() { id = $(this).parent().children("input").val(); url = "Results.aspx?latitude=" + latitude + "&Longitude=" + longitude + "&ServiceCenterProductTypeId=" + id; //alert(url); $("a[href='http://www.google.com/']").attr("href", url); //this doesnt work.... }); });

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  • Text being printed twice in uitableview

    - by user337174
    I have created a uitableview that calculates the distance of a location in the table. I used this code in cell for row at index path. NSString *lat1 = [object valueForKey:@"Lat"]; NSLog(@"Current Spot Latitude:%@",lat1); float lat2 = [lat1 floatValue]; NSLog(@"Current Spot Latitude Float:%g", lat2); NSString *long1 = [object valueForKey:@"Lon"]; NSLog(@"Current Spot Longitude:%@",long1); float long2 = [long1 floatValue]; NSLog(@"Current Spot Longitude Float:%g", long2); //Getting current location from NSDictionary CoreDataTestAppDelegate *appDelegate = (CoreDataTestAppDelegate *) [[UIApplication sharedApplication] delegate]; NSString *locLat = [NSString stringWithFormat:appDelegate.latitude]; float locLat2 = [locLat floatValue]; NSLog(@"Lat: %g",locLat2); NSString *locLong = [NSString stringWithFormat:appDelegate.longitude]; float locLong2 = [locLong floatValue]; NSLog(@"Long: %g",locLong2); //Location of selected spot CLLocation *loc1 = [[CLLocation alloc] initWithLatitude:lat2 longitude:long2]; //Current Location CLLocation *loc2 = [[CLLocation alloc] initWithLatitude:locLat2 longitude:locLong2]; double distance = [loc1 getDistanceFrom: loc2] / 1600; NSMutableString* converted = [NSMutableString stringWithFormat:@"%.1f", distance]; [converted appendString: @" m"]; It works fine apart from a problem i have just discovered where the distance text is duplicated over the top of the detailed text label when you scroll beyond the height of the page. here's a screen shot of what i mean. Any ideas why its doing this?

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  • Rails 3.0 method_missing: undefined method in validator

    - by user567592
    == Schema Information Schema version: 20110111000403 # Table name: places # id :integer not null, primary key name :string(255) latitude :float longitude :float a place can be defined by latitude and longitude or by name # class Place < ActiveRecord::Base validates_precence_of :name, :if = lat_long_not_def? def lat_long_not_def? latitude.blank? || longitude.blank? end end

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  • Easily use google maps, openstreet maps etc offline.

    - by samkea
    I did it and i am going to explain step by step. The explanatination may appear long but its simple if you follow. Note: All the softwares i have used are the latest and i have packaged them and provided them in the link below. I use Nokia N96 1) RootSign smartComGPS and install it on your phone(i havent provided the signer so that u wuld do some little work. i used Secman' rootsign). 2) Install Universal Maps Downloader, SmartCom OGF2 converter and OziExplorer 3.95.4s on my PC. a) UMD is used to download map tiles from any map source like googlemaps,opensourcemaps etc... and also combine the tiles into an image file like png,jpg,bmp etc... b) SmartCom OGF2 converter is used to convert the image file into a format usable on your mobile phone. c) OziExplorer will help you to calibrate the usable map file so that it can be used with GPS on your mobile phone without the use of internet. 3) Go to google maps or where u pick your maps and pan to the area of your interest. Zoom the map to at least 15 or 16 zoom level where you can see your area clearly and the streets. 4) copy this script in a notepad file and save it on your desktop: javascript:void(prompt('',gApplication.getMap().ge tCenter())); 5) Open the universal maps downloader. You will notice that you are required to add the: left longitude, right longitude,top latitude, bottom latitude. 6) On your map in google maps, doubleclick on the your prefered to most middle point. you will notice that the map will center in that area. 7) copy the script and paste it in the address bar then press enter. You will notice that a dialog with your (top latitude) and longitude respectively pops up. 8) copy the top latitude ONLY and paste it in the corresponding textbox in the UMD. 9) repeat steps 6-7 for the botton latitude. 10)repeat steps 6-7 for left longitude and right longitude too, but u have to copy the longitudes here. (***BTW record these points in the text file as they may be needed later in calibration) 11) Give the zoom level to the same zoom level that you prefered in google maps. 12) Dont forget to choose a path to save your files and under options set the proxy connection settings in UMD if you are using so. 13) Click on start and bingo! there you have your image tiles and a file with an extension .umd will be saved in the same folder. 14) On the UMD, go to tools, click on MapViewer and choose the .umd file. you will now see your map in one piece....and you will smile! 15) Still go to tools and click on map combiner. A dialog will popup for you to choose the .umd file and to enter the IMAGE file name. u can use another extension for the image file like png, jpg etc...i usually use png. 16) Combine.....bingo! there u go! u have an IMAGE file for your map. *I SUGGEST THAT CREATE A .BMP FILE and A .PNG file* 17) Close UMD and open SmartCom OGF2 converter. 18) Choose your .png image and create an ogf2 file. 19) Connect your phone to your PC in Mass Memory mode and transfer the file to the smartComGPS\Maps folder. 20) Now disconnect your phone and load smartComGPS. it will load the map and propt you to add a calibration point. Go ahead and add one calibration point with dummy coordinates. You will notice that it will add another file with extension .map in the smartComGPS\Maps folder. 21) Connect yiur ohone and copy that file and paste it in your working folder on your PC. Delete that .map file from the phone too because you are going to edit it from your PC and put it back. 22) Now Open the OziExplorer, go to file-->Load and Calibrate Map Image. 23) Choose the .bmp image and bingo! it will load with your map in the same zoom level. 24) Now you are going to calibrate. Use the MapView window and take the small box locater to all the 4 cornners of the map. You will notice that the map in the back ground moves to that area too. 25)On the right side, select the Point1 tab. Now you are in calibration mode. Now move the red box in mapview in the left upper corner to calibrate point1. 26) out of mapview go to the the left upper corner of the background map and choose poit (0,0) and your 1st calibration point. You will notice that these X,Y cordinated will be reflected in the Point1 image cordinates. 27) now go back to the text file where you saved your coordibates and enter the top latitude and the left longitude in the corresponding places. 28) Repeat steps 25-27 for point2,point3,point4 and click on save. Thats it, you have calibrated your image and you are about to finish. 29) Go to save and a dilaog which prompts you to save a .map file will poop up. Do save the map file in your working folder. 30) Right click that .map file and edit the filename in the .map file to remove the pc's directory structure. Eg. Change C\OziExplorer\data\Kampala.bmp to Kampala.ogf2. 31) Save the .map file in the smartComGPS\Maps folder on your phone. 32) now open smartComGPS on your phone and bingo! there is your map with GPS capability and in the same zoom level. 33) In smartComGPS options, choose connect and simulate. By now you should be smiling. Whoa! Hope i was of help. i case you get a problem, please inform me Below is the link to the software. regards. http://rapidshare.com/files/230296037/Utilities_Used.rar.html Ok, the Rapidshare files i posted are gone, so you will have to download as described in the solution. If you need more help, go here: http://www.dotsis.com/mobile_phone/sitemap/t-160491.html Some months later, someone else gave almost the same kind of solution here. http://www.dotsis.com/mobile_phone/sitemap/t-180123.html Note: the solutions were mean't to help view maps on Symbian phones, but i think now they ca even do for Windows Phones, iphones and others so read, extract what you want and use it. Hope it helps. Sam Kea

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  • JavaFX, Google Maps, and NetBeans Platform

    - by Geertjan
    Thanks to a great new article by Rob Terpilowski, and other work and research he describes in that article, it's now trivial to introduce a map component to a NetBeans Platform application. Making use of the GMapsFX library, as described in Rob's article, which provides a JavaFX API for Google Maps, you can very quickly knock this application together. Click to enlarge the image. Here's all the code (from Rob's article): @TopComponent.Description( preferredID = "MapTopComponent", persistenceType = TopComponent.PERSISTENCE_ALWAYS ) @TopComponent.Registration(mode = "editor", openAtStartup = true) @ActionID(category = "Window", id = "org.map.MapTopComponent") @ActionReference(path = "Menu/Window" /*, position = 333 */) @TopComponent.OpenActionRegistration( displayName = "#CTL_MapWindowAction", preferredID = "MapTopComponent" ) @NbBundle.Messages({ "CTL_MapWindowAction=Map", "CTL_MapTopComponent=Map Window", "HINT_MapTopComponent=This is a Map window" }) public class MapWindow extends TopComponent implements MapComponentInitializedListener { protected GoogleMapView mapComponent; protected GoogleMap map; private static final double latitude = 52.3667; private static final double longitude = 4.9000; public MapWindow() { setName(Bundle.CTL_MapTopComponent()); setToolTipText(Bundle.HINT_MapTopComponent()); setLayout(new BorderLayout()); JFXPanel panel = new JFXPanel(); Platform.setImplicitExit(false); Platform.runLater(() -> { mapComponent = new GoogleMapView(); mapComponent.addMapInializedListener(this); BorderPane root = new BorderPane(mapComponent); Scene scene = new Scene(root); panel.setScene(scene); }); add(panel, BorderLayout.CENTER); } @Override public void mapInitialized() { //Once the map has been loaded by the Webview, initialize the map details. LatLong center = new LatLong(latitude, longitude); MapOptions options = new MapOptions(); options.center(center) .mapMarker(true) .zoom(9) .overviewMapControl(false) .panControl(false) .rotateControl(false) .scaleControl(false) .streetViewControl(false) .zoomControl(false) .mapType(MapTypeIdEnum.ROADMAP); map = mapComponent.createMap(options); //Add a couple of markers to the map. MarkerOptions markerOptions = new MarkerOptions(); LatLong markerLatLong = new LatLong(latitude, longitude); markerOptions.position(markerLatLong) .title("My new Marker") .animation(Animation.DROP) .visible(true); Marker myMarker = new Marker(markerOptions); MarkerOptions markerOptions2 = new MarkerOptions(); LatLong markerLatLong2 = new LatLong(latitude, longitude); markerOptions2.position(markerLatLong2) .title("My new Marker") .visible(true); Marker myMarker2 = new Marker(markerOptions2); map.addMarker(myMarker); map.addMarker(myMarker2); //Add an info window to the Map. InfoWindowOptions infoOptions = new InfoWindowOptions(); infoOptions.content("<h2>Center of the Universe</h2>") .position(center); InfoWindow window = new InfoWindow(infoOptions); window.open(map, myMarker); } } Awesome work Rob, will be useful for many developers out there.

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  • Building a Store Locator ASP.NET Application Using Google Maps API (Part 1)

    Over the past couple of months I've been working on a couple of projects that have used the free Google Maps API to add interactive maps and geocoding capabilities to ASP.NET websites. In a nutshell, the Google Maps API allow you to display maps on your website, to add markers onto the map, and to compute the latitude and longitude of an address, among many other tasks. With some Google Maps API experience under my belt, I decided it would be fun to implement a store locator feature and share it here on 4Guys. A store locator lets a visitor enter an address or postal code and then shows the nearby stores. Typically, store locators display the nearby stores on both a map and in a grid, along with the distance between the entered address and each store within the area. To see a store locator in action, check out the Wells Fargo store locator. This article is the first in a multi-part series that walks through how to add a store locator feature to your ASP.NET application. In this inaugural article, we'll build the database table to hold the store information. Next, we'll explore how to use the Google Maps API's geocoding feature to allow for flexible address entry and how to translate an address into latitude and longitude pairs. Armed with the latitude and longitude coordinates, we'll see how to retrieve nearby locations as well as how to compute the distance between the address entered by the visitor and the each nearby store. (A future installment will examine how to display a map showing the nearby stores.) Read on to learn more! Read More >

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  • Building a Store Locator ASP.NET Application Using Google Maps API (Part 1)

    Over the past couple of months I've been working on a couple of projects that have used the free Google Maps API to add interactive maps and geocoding capabilities to ASP.NET websites. In a nutshell, the Google Maps API allow you to display maps on your website, to add markers onto the map, and to compute the latitude and longitude of an address, among many other tasks. With some Google Maps API experience under my belt, I decided it would be fun to implement a store locator feature and share it here on 4Guys. A store locator lets a visitor enter an address or postal code and then shows the nearby stores. Typically, store locators display the nearby stores on both a map and in a grid, along with the distance between the entered address and each store within the area. To see a store locator in action, check out the Wells Fargo store locator. This article is the first in a multi-part series that walks through how to add a store locator feature to your ASP.NET application. In this inaugural article, we'll build the database table to hold the store information. Next, we'll explore how to use the Google Maps API's geocoding feature to allow for flexible address entry and how to translate an address into latitude and longitude pairs. Armed with the latitude and longitude coordinates, we'll see how to retrieve nearby locations as well as how to compute the distance between the address entered by the visitor and the each nearby store. (A future installment will examine how to display a map showing the nearby stores.) Read on to learn more! Read More >Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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