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Search found 573 results on 23 pages for 'longitude'.

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  • Mapview getLatitudeSpan and getLongitudeSpan not working

    - by janfsd
    Hi! Sometimes when trying to get the Latitude span or Longitude span of a mapview with getLatitudeSpan() and getLongitudeSpan() I get 0 and 360*1E6 respectively. This doesn't happen always but it is a problem, has anybody got this problem? Any workarounds? I tried using getProjection() too but I get the same problem. Here is the piece of code: MapView mapView = (MapView) findViewById(R.id.mapview); int lat = mapView.getLatitudeSpan(); // sometimes returns 0 int long = mapView.getLongitudeSpan(); // sometimes returns 360*1E6

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  • Relative Position in PHP between 2 points (Lat/Long)

    - by Brian H
    I have a database of airports with Latitude and Longitude for each point. I want to run a PHP script to find all airports that are nearby a given airport, with their distance and relative direction. I.e. for Airport KLDJ (40-37-02.810N 074-14-40.539W) Airport Nearby KJFK - John F Kennedy Airport (21.2 nm NE) (40-38-23.104N 073-46-44.132W) I have used code from http://www.movable-type.co.uk/scripts/latlong.html to find distance, and tried to use it to find bearing, which might not be right. //BEARING RHUMB LINE $phi = log(tan($lat2/2+pi/4)/tan($lat1/2+pi/4)); $distance['bearing'] = (rad2deg(atan2($theta, $phi)) +180) % 360; I basically want to run all points through this script and find the distance, which I have already, but then the direction. (i.e. N, S, W, E, NW, SW, NE, SE)

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  • Converting an equation into a way java script can interpret it

    - by GeorgeTaylor
    So I have this code that is meant to do this equation: (1 / 15) * arccos(-tan(L) * tan(23.44 * sin(360 * (D + 284) / 365))) and for testing purposes alert it! But for some reason it returns "NaN". I've probably done something really stupid :P var now = new Date(); var start = new Date(now.getFullYear(), 0, 0); var diff = now - start; var oneDay = 1000 * 60 * 60 * 24; var d = Math.floor(diff / oneDay); var lat = position.coords.latitude; var long = position.coords.longitude; var tanlat = Math.atan(lat); var tantwentythree = Math.tan(23.44); var dayplus = d + 284; var sinday = Math.sin(360 * dayplus); var arccos = Math.acos(tanlat); var start = 1 / 15; var equation = start * arccos * tantwentythree * sinday / 365; alert(equation);

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  • Calculating bounding box a certain distance away from a lat/long coordinate in Java

    - by Bryce Thomas
    Given a coordinate (lat, long), I am trying to calculate a square bounding box that is a given distance (e.g. 50km) away from the coordinate. So as input I have lat, long and distance and as output I would like two coordinates; one being the south-west (bottom-left) corner and one being the north-east (top-right) corner. I have seen a couple of answers on here that try to address this question in Python, but I am looking for a Java implementation in particular. Just to be clear, I intend on using the algorithm on Earth only and so I don't need to accommodate a variable radius. It doesn't have to be hugely accurate (+/-20% is fine) and it'll only be used to calculate bounding boxes over small distances (no more than 150km). So I'm happy to sacrifice some accuracy for an efficient algorithm. Any help is much appreciated. Edit: I should have been clearer, I really am after a square, not a circle. I understand that the distance between the center of a square and various points along the square's perimeter is not a constant value like it is with a circle. I guess what I mean is a square where if you draw a line from the center to any one of the four points on the perimeter that results in a line perpendicular to a side of the perimeter, then those 4 lines have the same length.

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  • Calculating co-ordinate of a point on a path given a distance

    - by Alex
    I'm working on a project that surveys the condition of a road or highway using a calibrated trip computer connected to a rugged-PC. An operator keys in defect codes as they travel along a pre-defined route. I need to show an indicator on the map screen that shows the vehicles current position, taking into account the distance data from the trip computer. I know the exact lat lon co-ordinates at the starting point of each section of road, and the road is made up of a series of points. The question is: how can I calculate the lat lon co-ordinates of the vehicle assuming that it has continued on the route and traveled a certain distance (e.g. 1.4km). The co-ordinates would be 'locked onto' the road line, as shown in blue on the diagram below. Thanks, Alex

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  • get location(lat/long) without gps just like my location feature of google maps

    - by Suriyan Suresh
    Get location(lat/long) without GPS, just like my location feature in Google maps. I have Google Maps in my mobile (Sony Ericsson G502 without GPS). It works fine without GPS in India. 1.How Google finds my position? 2. When i am searching cellid in opencellid database, it has less number of records for India. but Google Maps works fine in my mobile(India) 3.Is Google uses opencellid database or its own?. if Google uses its own, shall we have access to it database

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  • Using Google Weather API with Lat and Lon - how to format?

    - by Paul
    I am wanting to use the Google Weather API - by passing lat and long values. However it seems Google is needing these formatted differently to the values I have stored. i.e. For the town of McTavish I have values of 45.5 and -73.583 This works here: http://api.wunderground.com/auto/wui/geo/WXCurrentObXML/index.xml?query=45.5,-73.583 But when I use Google it does not: See: www.google.com/ig/api?weather=,,,45.5,-73.583 Any help appreciated. I would prefer to use the Google Data.

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  • Get variable value from XML to JavaScript. Pure way.

    - by kalininew
    I have XML: <point> ... <longitude>34.123123</longitude> </point> <point> ... <longitude>11.12534534</longitude> </point> <point> ... <longitude>32.567653</longitude> </point> <point> ... <longitude>33.345345</longitude> </point> ... Task: get values of <longitude> in javascript (in variable). Which is purest way? It is possible to do it without XSLT (without making dummy elements)?

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  • Convert to valid lat/long codes

    - by Henk
    Hi all, My source gave me the following lat and long codes from Amsterdam. But I can't get them working with Google Maps. Is there some logic behind it, or some kind of algorithm to convert them? 5,237,300,539,279,090 | 489,290,714,263,916 Should be something like this: 52.378268, 4.888859 How can one tell where the dots should be? Thanks!

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  • Is there an algorithm for determining how much daylight there is?

    - by Pharaun
    Is there a function/algorithm that allows me to input the latitude and the approximate orbital position of the earth in so that I can determine how long the sun is up? IE during the winter it would show that the sun is only up a few hours in the far north hemisphere. I did some basic Google search and didn't find much so I was thinking that I might have to do some trigonometry that would allow me to calculate how much the earth is inclined or not toward the sun then use that information along with the latitude to figure out how much sunshine a site would be getting.

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  • Querying a perimeter around a Geocode-Location (Lat/Lon)

    - by Tim
    Hi, how can I search for geo-objects in a certain perimeter ? E.g. I have several objects with Lat/Lon coordinates stored in my DB. Now I want to retrieve all the objects which lie in a specific perimeter (10 miles or 20 miles) around a given point. I guess what I would have to do is to form some query like: SELECT * FROM objects o where o.lat < (myPositionLat+x) AND o.lon < (myPositionLon+y) Is this right? How do I determine/set the values for x and y?

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  • Uncenter MkMapView

    - by Makinitez21
    I am trying to "uncenter" the map view and remove all annotations. the reason for this is that the mapView will be used by different view controllers to display different annotations and locations. What's happening now is that i am using the "remove annotations" method and i removes them, but the map stays centered on the spot and thus when the new annotations come in, it does not move. Is there a way to reset the region and if so, what value do i reset it to. I tried nil, zero and some calculated value but "core animation" says they are all invalid. how do i get that to zoom out and back in on my new annotations? here is some code -(void)recenterMap { NSArray *coordinates = [_mapView valueForKeyPath:@"annotations.coordinate"]; CLLocationCoordinate2D maxCoord = {-90.0f, -180.0f}; CLLocationCoordinate2D minCoord = {90.0f, 180.0f}; //NSLog(@"%@", [coordinates description]); for (NSValue *value in coordinates) { CLLocationCoordinate2D coord = {0.0f, 0.0f}; [value getValue: &coord]; if(coord.longitude > maxCoord.longitude) { maxCoord.longitude = coord.longitude; } if(coord.latitude > maxCoord.latitude){ maxCoord.latitude = coord.latitude; } if(coord.longitude < minCoord.longitude){ minCoord.longitude = coord.longitude; } if(coord.latitude < minCoord.latitude){ minCoord.latitude = coord.latitude; } } MKCoordinateRegion region = {{0.0f, 0.0f}, {0.0f, 0.0f}}; region.center.longitude = (minCoord.longitude + maxCoord.longitude) / 2.0; region.center.latitude = (minCoord.latitude + maxCoord.latitude) / 2.0; region.span.longitudeDelta = maxCoord.longitude - minCoord.longitude; region.span.latitudeDelta = maxCoord.latitude - minCoord.latitude; [_mapView setRegion: region animated: YES]; } Thats the recenter methos i'm using - (MKAnnotationView *)mapView: (MKMapView *)mapView viewForAnnotation: (id <MKAnnotation>)annotation{ MKAnnotationView *view = nil; if(annotation != mapView.userLocation){ Annotation *schoolAnn = (Annotation*)annotation; view = [self.mapView dequeueReusableAnnotationViewWithIdentifier:@"schoolLoc"]; if(nil == view){ view = [[[MKPinAnnotationView alloc] initWithAnnotation:schoolAnn reuseIdentifier:@"schoolLoc"]autorelease]; } [(MKPinAnnotationView *)view setAnimatesDrop:YES]; [view setCanShowCallout:YES]; } else { [self recenterMap]; } return view; } This "else" piece waits until the blue marble drops in then recenters the map. The problem i have with that part is that when i go back to the previous View Controller i remove all annotations, so when i come back in the User location (for some reason) does not pop back in. How do i get this to pop back in? thanks in advance guys

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  • Zooming out to fit all annotations in MapKit

    - by Krismutt
    Hey everybody!! I wanna zoom out so that all my annotations(my location and one more annotation) fit to the screen...what do I do wrong?? I get the following warning: "'getDistanceFrom:' is deprecated".... -(void)viewDidLoad { [super viewDidLoad]; mapView = [[MKMapView alloc] initWithFrame:self.view.bounds]; mapView.showsUserLocation = TRUE; mapView.delegate = self; mapView.mapType = MKMapTypeStandard; mapView.zoomEnabled = YES; mapView.scrollEnabled = YES; mapView.userInteractionEnabled = YES; [mapView.userLocation setTitle:@"Nuvarande plats"]; [mapView.userLocation setSubtitle:@"Du är här"]; [self.view insertSubview:mapView atIndex:0]; self.locationManager = [[[CLLocationManager alloc] init] autorelease]; locationManager.delegate = self; locationManager.desiredAccuracy = kCLLocationAccuracyBest; [locationManager startUpdatingLocation]; [mapView release]; } -(void) locationManager: (CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation{ NSLog (@"Position uppdateras" ); location = newLocation.coordinate; if (friZoom) { MKCoordinateRegion region; region.center.latitude = location.latitude; region.center.longitude= location.longitude; MKCoordinateSpan span; span.latitudeDelta = 0.01; span.longitudeDelta = 0.01; region.span = span; [mapView setRegion:region animated:TRUE];} } - (MKAnnotationView *)mapView:(MKMapView *)mapview viewForAnnotation:(id <MKAnnotation>)knappnal { if ([knappnal isKindOfClass:MKUserLocation.class]) { return nil; } MKPinAnnotationView *knappnalView = (MKPinAnnotationView*)[mapview dequeueReusableAnnotationViewWithIdentifier:@"annot"]; if (!knappnalView) { knappnalView = [[[MKPinAnnotationView alloc] initWithAnnotation:knappnal reuseIdentifier:@"annot"] autorelease]; knappnalView.pinColor = MKPinAnnotationColorRed; knappnalView.animatesDrop = YES; knappnalView.canShowCallout = YES; } else { knappnalView.annotation = knappnal; } return knappnalView; } - (IBAction)storeLocationInfo:(id) sender{ SparaPosition *position=[[SparaPosition alloc] initWithCoordinate:location]; [mapView addAnnotation:position]; savedPosition = location; } - (IBAction)visaPosition:(id)sender{ CLLocationCoordinate2D southWest =location; CLLocationCoordinate2D northEast =savedPosition; southWest.latitude = MIN(southWest.latitude, location.latitude); southWest.longitude = MIN(southWest.longitude, location.longitude); northEast.latitude = MAX(northEast.latitude, savedPosition.latitude); northEast.longitude = MAX(northEast.longitude, savedPosition.longitude); CLLocation *locSouthWest = [[CLLocation alloc] initWithLatitude:southWest.latitude longitude:southWest.longitude]; CLLocation *locNorthEast = [[CLLocation alloc] initWithLatitude:northEast.latitude longitude:northEast.longitude]; CLLocationDistance meters = [locSouthWest getDistanceFrom:locNorthEast]; MKCoordinateRegion region; region.center.latitude = (southWest.latitude + northEast.latitude) / 2.0; region.center.longitude = (southWest.longitude + northEast.longitude) / 2.0; region.span.latitudeDelta = meters / 111319.5; region.span.longitudeDelta = 0.0; region = [mapView regionThatFits:region]; [mapView setRegion:region animated:YES]; [locSouthWest release]; [locNorthEast release]; } Would really appreciate an answer!

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  • How do I get the users location latitude and longitude?

    - by kevin Mendoza
    I need to access the users location in this method contained in the mainViewController -(void)loadAnnotations{ [mapView removeAnnotations:mapView.annotations]; CLLocationCoordinate2D workingCoordinate; workingCoordinate.latitude= //here i need the users latitude workingCoordinate.longitude= //here i need the users longitude NSLog(@" this is %@", workingCoordinate.latitude); iProspectLiteAnnotation *tempMine = [[iProspectLiteAnnotation alloc] initWithCoordinate:workingCoordinate]; [tempMine setTitle:@"Present Location"]; [tempMine setAnnotationType:iProspectLiteAnnotationTypeUser]; [mapView addAnnotation:tempMine]; } however the mainViewController is already set to <fipsideViewControllerDelegate> What should I add to the header file and the implementation file to poll the location Manager for the users current latitude and longitude?

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  • what is the difference between latitude, longitude and their delat values.

    - by Mas
    Hi! I'm new to the MKMapView (iPhone). I want to add several annotations to the map of Copenhagen (Denmark). I have the latitude and longitude values of different locations of the city. But I don't know how to get the longitudeDelta and latitudeDelta of these locations. I'm using the Google Map API's to calculate the latitude and longitude values (By web services) of each location in the city map. I need help on how to calculate delta values Thanks

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  • How can I pass latitude and longitude values from UIViewController to MKMapView?

    - by jerincbus
    I have a detail view that includes three UIButtons, each of which pushes a different view on to the stack. One of the buttons is connected to a MKMapView. When that button is pushed I need to send the latitude and longitude variables from the detail view to the map view. I'm trying to add the string declaration in the IBAction: - (IBAction)goToMapView { MapViewController *mapController = [[MapViewController alloc] initWithNibName:@"MapViewController" bundle:nil]; mapController.mapAddress = self.address; mapController.mapTitle = self.Title; mapController.mapLat = self.lat; mapController.mapLng = self.lng; //Push the new view on the stack [[self navigationController] pushViewController:mapController animated:YES]; [mapController release]; //mapController = nil; } And on my MapViewController.h file I have: #import <UIKit/UIKit.h> #import <MapKit/MapKit.h> #import "DetailViewController.h" #import "CourseAnnotation.h" @class CourseAnnotation; @interface MapViewController : UIViewController <MKMapViewDelegate> { IBOutlet MKMapView *mapView; NSString *mapAddress; NSString *mapTitle; NSNumber *mapLat; NSNumber *mapLng; } @property (nonatomic, retain) IBOutlet MKMapView *mapView; @property (nonatomic, retain) NSString *mapAddress; @property (nonatomic, retain) NSString *mapTitle; @property (nonatomic, retain) NSNumber *mapLat; @property (nonatomic, retain) NSNumber *mapLng; @end And on the pertinent parts of the MapViewController.m file I have: @synthesize mapView, mapAddress, mapTitle, mapLat, mapLng; - (void)viewDidLoad { [super viewDidLoad]; [mapView setMapType:MKMapTypeStandard]; [mapView setZoomEnabled:YES]; [mapView setScrollEnabled:YES]; MKCoordinateRegion region = { {0.0, 0.0 }, { 0.0, 0.0 } }; region.center.latitude = mapLat; //40.105085; region.center.longitude = mapLng; //-83.005237; region.span.longitudeDelta = 0.01f; region.span.latitudeDelta = 0.01f; [mapView setRegion:region animated:YES]; [mapView setDelegate:self]; CourseAnnotation *ann = [[CourseAnnotation alloc] init]; ann.title = mapTitle; ann.subtitle = mapAddress; ann.coordinate = region.center; [mapView addAnnotation:ann]; } But I get this when I try to build: 'error: incompatible types in assignment' for both lat and lng variables. So my questions are am I going about passing the variables from one view to another the right way? And does the MKMapView accept latitude and longitude as a string or a number?

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  • How would you parse the location text from Twitter to get the latitude/longitude in Objective-C?

    - by Brennan
    The location text from Twitter could be just about anything. Sometimes Twitter clients set the location with the user's latitude and longitude in the following format. "\U00dcT: 43.05948,-87.908409" Since there is no built-in support for Regular Expressions in Objective-C I am considering using the NSString functions like rangeOfString to pull the float values out of this string. For my current purpose I know the values with start with 43 and 87 so I can key off those values this time but I would prefer to do better than that. What would you do to parse the latitude/longitude from this string?

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  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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  • How to speed up this simple mysql query?

    - by Jim Thio
    The query is simple: SELECT TB.ID, TB.Latitude, TB.Longitude, 111151.29341326*SQRT(pow(-6.185-TB.Latitude,2)+pow(106.773-TB.Longitude,2)*cos(-6.185*0.017453292519943)*cos(TB.Latitude*0.017453292519943)) AS Distance FROM `tablebusiness` AS TB WHERE -6.2767668133836 < TB.Latitude AND TB.Latitude < -6.0932331866164 AND FoursquarePeopleCount >5 AND 106.68123318662 < TB.Longitude AND TB.Longitude <106.86476681338 ORDER BY Distance See, we just look at all business within a rectangle. 1.6 million rows. Within that small rectangle there are only 67,565 businesses. The structure of the table is 1 ID varchar(250) utf8_unicode_ci No None Change Change Drop Drop More Show more actions 2 Email varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 3 InBuildingAddress varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 4 Price int(10) Yes NULL Change Change Drop Drop More Show more actions 5 Street varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 6 Title varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 7 Website varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 8 Zip varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 9 Rating Star double Yes NULL Change Change Drop Drop More Show more actions 10 Rating Weight double Yes NULL Change Change Drop Drop More Show more actions 11 Latitude double Yes NULL Change Change Drop Drop More Show more actions 12 Longitude double Yes NULL Change Change Drop Drop More Show more actions 13 Building varchar(200) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 14 City varchar(100) utf8_unicode_ci No None Change Change Drop Drop More Show more actions 15 OpeningHour varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 16 TimeStamp timestamp on update CURRENT_TIMESTAMP No CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP Change Change Drop Drop More Show more actions 17 CountViews int(11) Yes NULL Change Change Drop Drop More Show more actions The indexes are: Edit Edit Drop Drop PRIMARY BTREE Yes No ID 1965990 A Edit Edit Drop Drop City BTREE No No City 131066 A Edit Edit Drop Drop Building BTREE No No Building 21 A YES Edit Edit Drop Drop OpeningHour BTREE No No OpeningHour (255) 21 A YES Edit Edit Drop Drop Email BTREE No No Email (255) 21 A YES Edit Edit Drop Drop InBuildingAddress BTREE No No InBuildingAddress (255) 21 A YES Edit Edit Drop Drop Price BTREE No No Price 21 A YES Edit Edit Drop Drop Street BTREE No No Street (255) 982995 A YES Edit Edit Drop Drop Title BTREE No No Title (255) 1965990 A YES Edit Edit Drop Drop Website BTREE No No Website (255) 491497 A YES Edit Edit Drop Drop Zip BTREE No No Zip (255) 178726 A YES Edit Edit Drop Drop Rating Star BTREE No No Rating Star 21 A YES Edit Edit Drop Drop Rating Weight BTREE No No Rating Weight 21 A YES Edit Edit Drop Drop Latitude BTREE No No Latitude 1965990 A YES Edit Edit Drop Drop Longitude BTREE No No Longitude 1965990 A YES The query took forever. I think there has to be something wrong there. Showing rows 0 - 29 ( 67,565 total, Query took 12.4767 sec)

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