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  • Cannot change password for user postgres in postgresql

    - by dhaval
    I have made the following entry in pg_hba.conf local all all trust but still su postgres does not accept blank as password. I am not able to run psql nor pg_ctl for same reason as most of the files are owned by postgres. EDIT1 dhaval@ubuntu:~$ su -c "pg_ctl reload -D template1" Password: su: Authentication failure dhaval@ubuntu:~$ su -c psql Password: su: Authentication failure I am giving the root password above but I guess its expecting "postgres" superuser password. I dont have the same. I need to reset it. EDIt2 dhaval@ubuntu:~$ sudo -i -u postgres [sudo] password for dhaval: postgres@ubuntu:~$ psql Welcome to psql 8.3.7, the PostgreSQL interactive terminal. The above has taken me postgreSQL command prompt. But I am still not sure why the "trust" was not working.

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  • How to let users change linux password from web browser?

    - by wag2639
    I'm not sure if this is a stackoverflow question or serverfault but here goes: I have an Ubuntu 10.04 file server (Samba/FTP/HTTP) and I would like to have the ability to give users the ability to change their password to the server using their web browser. I've written a similar script before using PHP and a mess of exec but I believe that isn't secure because it can be listened to by someone looking at the list of processes on the server. Is there some kind of plugin (PHP or Python or other) that can do this easily? I rather not use something like webmin as it's overkill for this.

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  • Disable password complexity rule in Active Directory

    - by Dan Revell
    Where do I go to disable the password complexity policy for the domain. I've logged onto the domain controller (Windows Server 2008) and found the option in local policies which is of course locked from any changes. However I can't find the same sort of policies in the group policy manager. Which nodes do I have to expand out to find it?

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  • Time complexity of a sorting algorithm

    - by Passonate Learner
    The two programs below get n integers from file and calculates the sum of ath to bth integers q(number of question) times. I think the upper program has worse time complexity than the lower, but I'm having problems calculating the time complexity of these two algorithms. [input sample] 5 3 5 4 3 2 1 2 3 3 4 2 4 [output sample] 7 5 9 Program 1: #include <stdio.h> FILE *in=fopen("input.txt","r"); FILE *out=fopen("output.txt","w"); int n,q,a,b,sum; int data[1000]; int main() int i,j; fscanf(in,"%d%d",&n,&q); for(i=1;i<=n;i++) fscanf(in,"%d",&data[i]); for i=0;i<q;i++) { fscanf(in,"%d%d",&a,&b); sum=0; for(j=a;j<=b;j++) sum+=data[j]; fprintf(out,"%d\n",sum); } return 0; } Program 2: #include <stdio.h> FILE *in=fopen("input.txt","r"); FILE *out=fopen("output.txt","w"); int n,q,a,b; int data[1000]; int sum[1000]; int main() { int i,j; fscanf(in,"%d%d",&n,&q); for(i=1;i<=n;i++) fscanf(in,"%d",&data[i]); for(i=1;i<=n;i++) sum[i]=sum[i-1]+data[i]; for(i=0;i<q;i++) { fscanf(in,"%d%d",&a,&b); fprintf(out,"%d\n",sum[b]-sum[a-1]); } return 0; } The programs below gets n integers from 1 to m and sorts them. Again, I cannot calculate the time complexity. [input sample] 5 5 2 1 3 4 5 [output sample] 1 2 3 4 5 Program: #include <stdio.h> FILE *in=fopen("input.txt","r") FILE *out=fopen("output.txt","w") int n,m; int data[1000]; int count[1000]; int main() { int i,j; fscanf(in,"%d%d",&n,&m); for(i=0;i<n;i++) { fscanf(in,"%d",&data[i]); count[data[i]]++ } for(i=1;i<=m;i++) { for(j=0;j<count[i];j++) fprintf(out,"%d ",i); } return 0; } It's ironic(or not) that I cannot calculate the time complexity of my own algorithms, but I have passions to learn, so please programming gurus, help me!

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  • Computational complexity of Fibonacci Sequence

    - by Juliet
    I understand Big-O notation, but I don't know how to calculate it for many functions. In particular, I've been trying to figure out the computational complexity of the naive version of the Fibonacci sequence: int Fib(int n) { if (n <= 1) return 1; else return Fib(n - 1) + Fib(n - 2); } What is the computational complexity of the Fibonnaci sequence and how is it calculated?

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  • Unable to retrive open-id password wheras able to login via gmail only???

    - by diEcho
    Hello All, I have two OPEN-ID accounts referenced with same gmail address, now i forget one of my Open ID account's password and when i tried to recover my password then the mail sent by The MyOpen ID Team having second one open-id account's password change link whereas i need first one open-id password. i tries a lot of times to recover but each time mail having second open-id passord change link so what do i do to recover my first open-id password whereas i m able to login from that open-id via gmail account. i have mailed to open id teams many times already? but no answer?? how do i collect all open ID password reset link referencing same email address??

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  • Password protected website

    - by danie7L T
    I need to add a user authentication page before the actual homepage of the website. In Joomla! I just set the website offline and the offline page loads in place of the homepage but then it's automatically throwing a "503 Service Temporarily Unavailable" error which I would like to avoid. That's why I would like to know the other ways to load an authentication page before the homepage. NB: I'm using Apache servers if that's relevant Thank you

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  • Password value on click is not changing the text to 'Password'

    - by Sam
    window.onload=function() { var password = document.getElementById('apassword'); var real = document.getElementById('password'); var fake = document.createElement('input'); fake.setAttribute('type', 'text'); /*fake.setAttribute('id', 'password');*/ fake.setAttribute('class', 'contact-input contact-right'); password.appendChild(fake); fake.setAttribute('value', 'Password'); fake.onfocus = function() {this.style.display='none';real.style.display=''; real.focus();}; real.style.display = 'none'; real.setAttribute('value', ''); real.onblur = function() {if(this.value==''){this.style.display='none';fake.style.display=''}}; }; AND <label id="apassword"> <input type="password" title="Password" id="password" class="contact-input contact-right" name="password" /> </label> What is supposed to happen is that when you click on the input box, it changes from 'Password' to a blank type="password" input box, however it doesn't happen. This originally worked, but then I had to change some ID's and classes etc. I'm not sure how to debug scripts, so hopefully someone can help me with that, and also with my question :). Thankyou :).

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  • no administrator password for Windows 7

    - by huskergirl78
    I'm a secretary and my boss set up my new Windows 7 OptiPlex 7010 (Dell) computer for me while I was on vacation (he does not remember setting any "administrator" password). We are a small office so there is no system password set, either. I've used it for 6 months, all the while I couldn't access network drives, etc., without an administrator password. It was annoying, but I could still get my work done. Finally, on a slow day I took it upon myself to "fix" the problem, and in all my infinite wisdom, I managed to change my user account from administrator to standard user, so now I really can't do anything. I can't download or install any programs, move or rename files, etc. I tried the Dell suggested solution, but the BIOS tells me there is no password set, so it has to be a Windows 7 problem. All the solutions I have come across require an administrator password to let me do them. What can I do to find out the admin password so I can use my own darn computer!? Is there a default admin password?

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  • Pseudo-quicksort time complexity

    - by Ord
    I know that quicksort has O(n log n) average time complexity. A pseudo-quicksort (which is only a quicksort when you look at it from far enough away, with a suitably high level of abstraction) that is often used to demonstrate the conciseness of functional languages is as follows (given in Haskell): quicksort :: Ord a => [a] -> [a] quicksort [] = [] quicksort (p:xs) = quicksort [y | y<-xs, y<p] ++ [p] ++ quicksort [y | y<-xs, y>=p] Okay, so I know this thing has problems. The biggest problem with this is that it does not sort in place, which is normally a big advantage of quicksort. Even if that didn't matter, it would still take longer than a typical quicksort because it has to do two passes of the list when it partitions it, and it does costly append operations to splice it back together afterwards. Further, the choice of the first element as the pivot is not the best choice. But even considering all of that, isn't the average time complexity of this quicksort the same as the standard quicksort? Namely, O(n log n)? Because the appends and the partition still have linear time complexity, even if they are inefficient.

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  • Back up and restore Active Directory password per user

    - by Robert Perlberg
    For administrative purposes, I sometimes need to log in as another user to diagnose a problem with their account. I'd like to be able to do this without having to change their password so I don't have to keep bothering them. Under Unix, I can just save the encrypted password from the passwd file, change the password, then edit the old encrypted password back into the passwd file. Is there a way of doing something similar in AD?

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  • Windows Web Server 2008 R2 Server Core local password complexity

    - by Dennis Allen
    How can I disable the local user account password complexity settings on Windows 2008 R2 "Server Core"? I am trying to migrate our windows 2003 web server to windows 2008 R2. I am trying to see if I can use the "Server Core" install, and it has been a very internet search intensive experience. What I can't find out how to do is to find out how to disable password complexity for local user accounts. While our user account generator currently creates nice strong passwords, there was a time when this was not the case and unfortunately forcing the users to change their password is not an option at this time. Any help greatly appreciated. Dennis

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  • Firefox requests the master password twice

    - by Mehper C. Palavuzlar
    I've set a master password for Firefox. When Firefox starts, it strangely opens two separate password request windows. When I type in the master password and hit enter, Firefox opens without problems, but the other password request window stays there. I simply close it but it's annoying. Why are there 2 windows as it's enough to type the password once? I've upgraded Firefox from 3.5.5 to 3.5.6 but the problem remains. Any comments? PS: The latest news from this issue can be followed from the related Mozilla Support Forum.

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  • Active Directory Password Policy Problem

    - by Will
    To Clarify: my question is why isn't my password policy applying to people in the domain. Hey guys, having trouble with our password policy in Active Directory. Sometimes it just helps me to type out what I’m seeing It appears to not be applying properly across the board. I am new to this environment and AD in general but I think I have a general grasp of what should be going on. It’s a pretty simple AD setup without too many Group Policies being applied. It looks something like this DOMAIN Default Domain Policy (link enabled) Password Policy (link enabled and enforce) Personal OU Force Password Change (completely empty nothing in this GPO) IT OU Lockout Policy (link enabled and enforced) CS OU Lockout Policy Accouting OU Lockout Policy The password policy and default domain policy both define the same things under Computer ConfigWindows seetings sec settings Account Policies / Password Policy Enforce password History : 24 passwords remembered Maximum Password age : 180 days Min password age: 14 days Minimum Password Length: 6 characters Password must meet complexity requirements: Enabled Store Passwords using reversible encryption: Disabled Account Policies / Account Lockout Policy Account Lockout Duration 10080 Minutes Account Lockout Threshold: 5 invalid login attempts Reset Account Lockout Counter after : 30 minutes IT lockout This just sets the screen saver settings to lock computers when the user is Idle. After running Group Policy modeling it seems like the password policy and default domain policy is getting applied to everyone. Here is the results of group policy modeling on MO-BLANCKM using the mblanck account, as you can see the policies are both being applied , with nothing important being denied Group Policy Results NCLGS\mblanck on NCLGS\MO-BLANCKM Data collected on: 12/29/2010 11:29:44 AM Summary Computer Configuration Summary General Computer name NCLGS\MO-BLANCKM Domain NCLGS.local Site Default-First-Site-Name Last time Group Policy was processed 12/29/2010 10:17:58 AM Group Policy Objects Applied GPOs Name Link Location Revision Default Domain Policy NCLGS.local AD (15), Sysvol (15) WSUS-52010 NCLGS.local/WSUS/Clients AD (54), Sysvol (54) Password Policy NCLGS.local AD (58), Sysvol (58) Denied GPOs Name Link Location Reason Denied Local Group Policy Local Empty Security Group Membership when Group Policy was applied BUILTIN\Administrators Everyone S-1-5-21-507921405-1326574676-682003330-1003 BUILTIN\Users NT AUTHORITY\NETWORK NT AUTHORITY\Authenticated Users NCLGS\MO-BLANCKM$ NCLGS\Admin-ComputerAccounts-GP NCLGS\Domain Computers WMI Filters Name Value Reference GPO(s) None Component Status Component Name Status Last Process Time Group Policy Infrastructure Success 12/29/2010 10:17:59 AM EFS recovery Success (no data) 10/28/2010 9:10:34 AM Registry Success 10/28/2010 9:10:32 AM Security Success 10/28/2010 9:10:34 AM User Configuration Summary General User name NCLGS\mblanck Domain NCLGS.local Last time Group Policy was processed 12/29/2010 11:28:56 AM Group Policy Objects Applied GPOs Name Link Location Revision Default Domain Policy NCLGS.local AD (7), Sysvol (7) IT-Lockout NCLGS.local/Personal/CS AD (11), Sysvol (11) Password Policy NCLGS.local AD (5), Sysvol (5) Denied GPOs Name Link Location Reason Denied Local Group Policy Local Empty Force Password Change NCLGS.local/Personal Empty Security Group Membership when Group Policy was applied NCLGS\Domain Users Everyone BUILTIN\Administrators BUILTIN\Users NT AUTHORITY\INTERACTIVE NT AUTHORITY\Authenticated Users LOCAL NCLGS\MissingSkidEmail NCLGS\Customer_Service NCLGS\Email_Archive NCLGS\Job Ticket Users NCLGS\Office Staff NCLGS\CUSTOMER SERVI-1 NCLGS\Prestige_Jobs_Email NCLGS\Telecommuters NCLGS\Everyone - NCL WMI Filters Name Value Reference GPO(s) None Component Status Component Name Status Last Process Time Group Policy Infrastructure Success 12/29/2010 11:28:56 AM Registry Success 12/20/2010 12:05:51 PM Scripts Success 10/13/2010 10:38:40 AM Computer Configuration Windows Settings Security Settings Account Policies/Password Policy Policy Setting Winning GPO Enforce password history 24 passwords remembered Password Policy Maximum password age 180 days Password Policy Minimum password age 14 days Password Policy Minimum password length 6 characters Password Policy Password must meet complexity requirements Enabled Password Policy Store passwords using reversible encryption Disabled Password Policy Account Policies/Account Lockout Policy Policy Setting Winning GPO Account lockout duration 10080 minutes Password Policy Account lockout threshold 5 invalid logon attempts Password Policy Reset account lockout counter after 30 minutes Password Policy Local Policies/Security Options Network Security Policy Setting Winning GPO Network security: Force logoff when logon hours expire Enabled Default Domain Policy Public Key Policies/Autoenrollment Settings Policy Setting Winning GPO Enroll certificates automatically Enabled [Default setting] Renew expired certificates, update pending certificates, and remove revoked certificates Disabled Update certificates that use certificate templates Disabled Public Key Policies/Encrypting File System Properties Winning GPO [Default setting] Policy Setting Allow users to encrypt files using Encrypting File System (EFS) Enabled Certificates Issued To Issued By Expiration Date Intended Purposes Winning GPO SBurns SBurns 12/13/2007 5:24:30 PM File Recovery Default Domain Policy For additional information about individual settings, launch Group Policy Object Editor. Public Key Policies/Trusted Root Certification Authorities Properties Winning GPO [Default setting] Policy Setting Allow users to select new root certification authorities (CAs) to trust Enabled Client computers can trust the following certificate stores Third-Party Root Certification Authorities and Enterprise Root Certification Authorities To perform certificate-based authentication of users and computers, CAs must meet the following criteria Registered in Active Directory only Administrative Templates Windows Components/Windows Update Policy Setting Winning GPO Allow Automatic Updates immediate installation Enabled WSUS-52010 Allow non-administrators to receive update notifications Enabled WSUS-52010 Automatic Updates detection frequency Enabled WSUS-52010 Check for updates at the following interval (hours): 1 Policy Setting Winning GPO Configure Automatic Updates Enabled WSUS-52010 Configure automatic updating: 4 - Auto download and schedule the install The following settings are only required and applicable if 4 is selected. Scheduled install day: 0 - Every day Scheduled install time: 03:00 Policy Setting Winning GPO No auto-restart with logged on users for scheduled automatic updates installations Disabled WSUS-52010 Re-prompt for restart with scheduled installations Enabled WSUS-52010 Wait the following period before prompting again with a scheduled restart (minutes): 30 Policy Setting Winning GPO Reschedule Automatic Updates scheduled installations Enabled WSUS-52010 Wait after system startup (minutes): 1 Policy Setting Winning GPO Specify intranet Microsoft update service location Enabled WSUS-52010 Set the intranet update service for detecting updates: http://lavender Set the intranet statistics server: http://lavender (example: http://IntranetUpd01) User Configuration Administrative Templates Control Panel/Display Policy Setting Winning GPO Hide Screen Saver tab Enabled IT-Lockout Password protect the screen saver Enabled IT-Lockout Screen Saver Enabled IT-Lockout Screen Saver executable name Enabled IT-Lockout Screen Saver executable name sstext3d.scr Policy Setting Winning GPO Screen Saver timeout Enabled IT-Lockout Number of seconds to wait to enable the Screen Saver Seconds: 1800 System/Power Management Policy Setting Winning GPO Prompt for password on resume from hibernate / suspend Enabled IT-Lockout

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  • Domain Outlook user is asked for password every time despite checking the 'remember password' button

    - by MrVimes
    We have a windows 2003 domain. All users have roaming profiles. We have a couple of users who, when they log into outlook, are asked for their password every time, despite selecting the 'remember my password' option. Our email is externally hosted exchange email. I've tried several fixes found on google such as deleting 'protect' folder in the user's profile, and deleting protect key in the registry but none work. I tried storing the password in windows' password/credentials manager, didn't work. It happens on any PC the users log into so it's not a machine specific problem. Any ideas? OS is Windows XP pro. Outlook is 2007.

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  • Managing service passwords with Puppet

    - by Jeff Ferland
    I'm setting up my Bacula configuration in Puppet. One thing I want to do is ensure that each password field is different. My current thought is to hash the hostname with a secret value that would ensure each file daemon has a unique password and that password can be written to both the director configuration and the file server. I definitely don't want to use one universal password as that would permit anybody who might compromise one machine to get access to any machine through Bacula. Is there another way to do this other than using a hash function to generate the passwords? Clarification: This is NOT about user accounts for services. This is about the authentication tokens (to use another term) in the client / server files. Example snippet: Director { # define myself Name = <%= hostname $>-dir QueryFile = "/etc/bacula/scripts/query.sql" WorkingDirectory = "/var/lib/bacula" PidDirectory = "/var/run/bacula" Maximum Concurrent Jobs = 3 Password = "<%= somePasswordFunction =>" # Console password Messages = Daemon }

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  • Time complexity O() of isPalindrome()

    - by Aran
    I have this method, isPalindrome(), and I am trying to find the time complexity of it, and also rewrite the code more efficiently. boolean isPalindrome(String s) { boolean bP = true; for(int i=0; i<s.length(); i++) { if(s.charAt(i) != s.charAt(s.length()-i-1)) { bP = false; } } return bP; } Now I know this code checks the string's characters to see whether it is the same as the one before it and if it is then it doesn't change bP. And I think I know that the operations are s.length(), s.charAt(i) and s.charAt(s.length()-i-!)). Making the time-complexity O(N + 3), I think? This correct, if not what is it and how is that figured out. Also to make this more efficient, would it be good to store the character in temporary strings?

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  • What is the complexity of this c function

    - by Bunny Rabbit
    what is the complexity of the following c Function ? double foo (int n) { int i; double sum; if (n==0) return 1.0; else { sum = 0.0; for (i =0; i<n; i++) sum +=foo(i); return sum; } } Please don't just post the complexity can you help me in understanding how to go about it . EDIT: It was an objective question asked in an exam and the Options provided were 1.O(1) 2.O(n) 3.O(n!) 4.O(n^n)

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  • change password code error.......

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error. When before I fill in the form to change password.the error is: Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php:7) in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 126 the code: <?php # userChangePass.php //this page allows logged in user to change their password. $page_title='Change Your Password'; //if no first_name variable exists, redirect the user if(!isset($_SESSION['userid'])){ header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); ob_end_clean(); exit(); }else{ if(isset($_POST['submit'])) {//handle form. require_once('connectioncomplaint.php'); //connec to the database //check for a new password and match againts the confirmed password. if(eregi ("^[[:alnum:]]{4,20}$", stripslashes(trim($_POST['password1'])))){ if($_POST['password1'] == $_POST['password2']){ $p =escape_data($_POST['password1']); }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Your password did not match the confirmed password!</font></p>'; } }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Please Enter a valid password!</font></p>'; } if($p){ //if everything OK. //make the query $query="UPDATE access SET password=PASSWORD('$p') WHERE userid={$_SESSION['userid']}"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit(); }else{//if it did not run ok $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } mysql_close();//close the database connection. }else{//failed the validation test. echo '<p><font color="red" size="+1"> Please try again.</font></p>'; } }//end of the main Submit conditional. } ?> the error at this line:- header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); please help me guy...

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  • Help with algorithmic complexity in custom merge sort implementation

    - by bitcycle
    I've got an implementation of the merge sort in C++ using a custom doubly linked list. I'm coming up with a big O complexity of n^2, based on the merge_sort() slice operation. But, from what I've read, this algorithm should be n*log(n), where the log has a base of two. Can someone help me determine if I'm just determining the complexity incorrectly, or if the implementation can/should be improved to achieve n*log(n) complexity? If you would like some background on my goals for this project, see my blog. I've added comments in the code outlining what I understand the complexity of each method to be. Clarification - I'm focusing on the C++ implementation with this question. I've got another implementation written in Python, but that was something that was added in addition to my original goal(s).

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  • Online Password Security Tactics

    - by BuckWoody
    Recently two more large databases were attacked and compromised, one at the popular Gawker Media sites and the other at McDonald’s. Every time this kind of thing happens (which is FAR too often) it should remind the technical professional to ensure that they secure their systems correctly. If you write software that stores passwords, it should be heavily encrypted, and not human-readable in any storage. I advocate a different store for the login and password, so that if one is compromised, the other is not. I also advocate that you set a bit flag when a user changes their password, and send out a reminder to change passwords if that bit isn’t changed every three or six months.    But this post is about the *other* side – what to do to secure your own passwords, especially those you use online, either in a cloud service or at a provider. While you’re not in control of these breaches, there are some things you can do to help protect yourself. Most of these are obvious, but they contain a few little twists that make the process easier.   Use Complex Passwords This is easily stated, and probably one of the most un-heeded piece of advice. There are three main concepts here: ·         Don’t use a dictionary-based word ·         Use mixed case ·         Use punctuation, special characters and so on   So this: password Isn’t nearly as safe as this: P@ssw03d   Of course, this only helps if the site that stores your password encrypts it. Gawker does, so theoretically if you had the second password you’re in better shape, at least, than the first. Dictionary words are quickly broken, regardless of the encryption, so the more unusual characters you use, and the farther away from the dictionary words you get, the better.   Of course, this doesn’t help, not even a little, if the site stores the passwords in clear text, or the key to their encryption is broken. In that case…   Use a Different Password at Every Site What? I have hundreds of sites! Are you kidding me? Nope – I’m not. If you use the same password at every site, when a site gets attacked, the attacker will store your name and password value for attacks at other sites. So the only safe thing to do is to use different names or passwords (or both) at each site. Of course, most sites use your e-mail as a username, so you’re kind of hosed there. So even though you have hundreds of sites you visit, you need to have at least a different password at each site.   But it’s easier than you think – if you use an algorithm.   What I’m describing is to pick a “root” password, and then modify that based on the site or purpose. That way, if the site is compromised, you can still use that root password for the other sites.   Let’s take that second password: P@ssw03d   And now you can append, prepend or intersperse that password with other characters to make it unique to the site. That way you can easily remember the root password, but make it unique to the site. For instance, perhaps you read a lot of information on Gawker – how about these:   P@ssw03dRead ReadP@ssw03d PR@esasdw03d   If you have lots of sites, tracking even this can be difficult, so I recommend you use password software such as Password Safe or some other tool to have a secure database of your passwords at each site. DO NOT store this on the web. DO NOT use an Office document (Microsoft or otherwise) that is “encrypted” – the encryption office automation packages use is very trivial, and easily broken. A quick web search for tools to do that should show you how bad a choice this is.   Change Your Password on a Schedule I know. It’s a real pain. And it doesn’t seem worth it…until your account gets hacked. A quick note here – whenever a site gets hacked (and I find out about it) I change the password at that site immediately (or quit doing business with them) and then change the root password on every site, as quickly as I can.   If you follow the tip above, it’s not as hard. Just add another number, year, month, day, something like that into the mix. It’s not unlike making a Primary Key in an RDBMS.   P@ssw03dRead10242010   Change the site, and then update your password database. I do this about once a month, on the first or last day, during staff meetings. (J)   If you have other tips, post them here. We can all learn from each other on this.

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  • Is there a way to change the root password while still logged in? I did something bad by accdient -_-

    - by Robert
    So I was trying to add my printer, and I wasn't able to make any changes due to the fact that cups was not accepting my root password. I was Googling some changes and trying to fix the problem when one of the commands CHANGED MY SUDO PASSWORD! Can someone please tell me which one of these is the culprit? I was trying to these commands: cat /etc/group | grep root cat /etc/group | grep myUserName usermod -a -G lpadmin myUserName sudo usermod -a -G lpadmin myUserName sudo gedit /etc/cups/cupsd.conf lppasswd -a myUserName lppasswd -a root sudo lppasswd -a myUserName I think it was this one, but I know which passwords I put in! There was nothing which I typed in besides my strong password or my easy temporary password. Unless I made a typo... please no. restart cups sudo password root This is so not cool, I was just trying to add a printer :'( Please help my stupidity!

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