Search Results

Search found 15846 results on 634 pages for 'pom xml'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 6/634 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • RESTful Web Services: Different XML Representation for the same resource

    - by AlexImmelman
    Hi, I'm developing a REST Web Service using a XML format response and I have some problems (Really, one problem). One of my resources has some final fields so once they're created, they can't be modified. According to that, I need different representations for this resource depending on what I'm doing: Creating or modifiying it. What should I do, give to the user different XML-Schemas for the same resource or write just one XML-Schema and read some fields or not depending on the method I'm being requested?? Thanks

    Read the article

  • LINQ to XML via C#

    - by user70192
    Hello, I'm new to LINQ. I understand it's purpose. But I can't quite figure it out. I have an XML set that looks like the following: <Results> <Result> <ID>1</ID> <Name>John Smith</Name> <EmailAddress>[email protected]</EmailAddress> </Result> <Result> <ID>2</ID> <Name>Bill Young</Name> <EmailAddress>[email protected]</EmailAddress> </Result> </Results> I have loaded this XML into an XDocument as such: string xmlText = GetXML(); XDocument xml = XDocument.Parse(xmlText); Now, I'm trying to get the results into POCO format. In an effort to do this, I'm currently using: var objects = from results in xml.Descendants("Results") select new Results // I'm stuck How do I get a collection of Result elements via LINQ? I'm particularly confused about navigating the XML structure at this point in my code. Thank you!

    Read the article

  • Parsing JSON into XML using Windows Phone

    - by Henry Edwards
    I have this code, but can't get it all working. I am trying to get a json string into xml. So that I can get a list of items when i parse the data. Is there a better way to parse json into xml. If so what's the best way to do it, and if possible could you give me a working example? The URL that is in the code is not the URL that i am using using System; using System.Collections.Generic; using System.Linq; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Documents; using System.Windows.Input; using System.Windows.Media; using System.Windows.Media.Animation; using System.Windows.Shapes; using Microsoft.Phone.Controls; using Newtonsoft.Json; using Newtonsoft.Json.Serialization; using Newtonsoft.Json.Converters; using Newtonsoft.Json.Utilities; using Newtonsoft.Json.Linq; using Newtonsoft.Json.Schema; using Newtonsoft.Json.Bson; using System.Xml; using System.Xml.Serialization; using System.Xml.Linq; using System.Xml.Linq.XDocument; using System.IO; namespace WindowsPhonePanoramaApplication3 { public partial class Page2 : PhoneApplicationPage { public Page2() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e1) { /* because the origional JSON string has multiple root's this needs to be added */ string json = "{BFBC2_GlobalStats:"; json += DownlodUrl("http://api.bfbcs.com/api/xbox360?globalstats"); json += "}"; XmlDocument doc = (XmlDocument)JsonConvert.DeserializeObject(json); textBox1.Text = GetXmlString(doc); } private string GetXmlString() { throw new NotImplementedException(); } private string DownlodUrl(string url) { string result = null; try { WebClient client = new WebClient(); result = client.DownloadString(url); } catch (Exception ex) { // handle error result = ex.Message; } return result; } private string GetXmlString(XmlDocument xmlDoc) { sw = new StringWriter(); XmlTextWriter xw = new XmlTextWriter(sw); xw.Formatting = System.Xml.Formatting.Indented; xmlDoc.WriteTo(xw); return sw.ToString(); } } } The URL outputs the following code: {"StopName":"Race Hill", "stopId":7553, "NaptanCode":"bridwja", "LongName":"Race Hill", "OperatorsCode1":" 5", "OperatorsCode2":" ", "OperatorsCode3":" ", "OperatorsCode4":"bridwja", "Departures":[ { "ServiceName":"", "Destination":"", "DepartureTimeAsString":"", "DepartureTime":"30/01/2012 00:00:00", "Notes":""}` Thanks for your responses. So Should i just leave the data a json and then view the data via that??? Is this a way to show the data from a json string. public void Load() { // form the URI UriBuilder uri = new UriBuilder("http://mysite.com/events.json"); WebClient proxy = new WebClient(); proxy.OpenReadCompleted += new OpenReadCompletedEventHandler(OnReadCompleted); proxy.OpenReadAsync(uri.Uri); } void OnReadCompleted(object sender, OpenReadCompletedEventArgs e) { if (e.Error == null) { var serializer = new DataContractJsonSerializer(typeof(EventList)); var events = (EventList)serializer.ReadObject(e.Result); foreach (var ev in events) { Items.Add(ev); } } } public ObservableCollection<EventDetails> Items { get; private set; } Edit: Have now kept the url as json and have now got it working by using the json way.

    Read the article

  • Formatting datetime values returned in a SELECT..FOR XML statement

    - by TelJanini
    Consider the following table: Orders OrderId Date CustomerId 1000 2012-06-05 20:03:12.000 51 1001 2012-06-16 12:02:31.170 48 1002 2012-06-18 19:45:16.000 33 When I extract the Order data using FOR XML: SELECT OrderId AS 'Order/@Order-Id', Date AS 'Order/ShipDate', CustomerId AS 'Order/Customer' FROM Orders WHERE OrderId = 1000 FOR XML PATH ('') I get the following result: <Order Order-Id="1000"> <ShipDate>2010-02-20T16:03:12</ShipDate> <Customer>51</Customer> </Order> The problem is, the ShipDate value in the XML file needs to be in the format M/DD/YYYY H:mm:ss PM. How can I change the output of the ShipDate in the XML file to the desired format? Any help would be greatly appreciated!

    Read the article

  • C# encrypt whole XML File

    - by René
    I already have a solution for encrypting of several XML nodes or strings. But of course, you can open the local saved XML file and you should see the node tags. For some intelligent people it could be a reference for hidden informations. Is there any way to encrypt and decrypt the whole xml content including all node tags?

    Read the article

  • Code to read & write in XML

    - by user2954088
    I am trying to write code to read and write the XML but I am facing some errors, Could please someone provide the sample code to read XML in grid and can update/insert data from grid which will be saved in following sample xml file. Sample XML file: I am facing the below exception: The assembly with display name '...XmlSerializers' failed to load in the 'LoadFrom' binding context of the AppDomain with ID 1. The cause of the failure was: System.IO.FileNotFoundException: Could not load file or assembly '.....XmlSerializers, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null' or one of its dependencies. The system cannot find the file specified.

    Read the article

  • .NET XML Serialization without <?xml> root node

    - by Graphain
    Hi, I'm trying to generate XML like this: <?xml version="1.0"?> <!DOCTYPE APIRequest SYSTEM "https://url"> <APIRequest> <Head> <Key>123</Key> </Head> <ObjectClass> <Field>Value</Field </ObjectClass> </APIRequest> I have a class (ObjectClass) decorated with XMLSerialization attributes like this: [XmlRoot("ObjectClass")] public class ObjectClass { [XmlElement("Field")] public string Field { get; set; } } And my really hacky intuitive thought to just get this working is to do this when I serialize: ObjectClass inst = new ObjectClass(); XmlSerializer serializer = new XmlSerializer(inst.GetType(), ""); StringWriter w = new StringWriter(); w.WriteLine(@"<?xml version=""1.0""?>"); w.WriteLine("<!DOCTYPE APIRequest SYSTEM"); w.WriteLine(@"""https://url"">"); w.WriteLine("<APIRequest>"); w.WriteLine("<Head>"); w.WriteLine(@"<Field>Value</Field>"); w.WriteLine(@"</Head>"); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); serializer.Serialize(w, inst, ns); w.WriteLine("</APIRequest>"); However, this generates XML like this: <?xml version="1.0"?> <!DOCTYPE APIRequest SYSTEM "https://url"> <APIRequest> <Head> <Key>123</Key> </Head> <?xml version="1.0" encoding="utf-16"?> <ObjectClass> <Field>Value</Field> </ObjectClass> </APIRequest> i.e. the serialize statement is automatically adding a <?xml root element. I know I'm attacking this wrong so can someone point me in the right direction? As a note, I don't think it will make practical sense to just make an APIRequest class with an ObjectClass in it (because there are say 20 different types of ObjectClass that each needs this boilerplate around them) but correct me if I'm wrong.

    Read the article

  • SSIS - XML Source Script

    - by simonsabin
    The XML Source in SSIS is great if you have a 1 to 1 mapping between entity and table. You can do more complex mapping but it becomes very messy and won't perform. What other options do you have? The challenge with XML processing is to not need a huge amount of memory. I remember using the early versions of Biztalk with loaded the whole document into memory to map from one document type to another. This was fine for small documents but was an absolute killer for large documents. You therefore need a streaming approach. For flexibility however you want to be able to generate your rows easily, and if you've ever used the XmlReader you will know its ugly code to write. That brings me on to LINQ. The is an implementation of LINQ over XML which is really nice. You can write nice LINQ queries instead of the XMLReader stuff. The downside is that by default LINQ to XML requires a whole XML document to work with. No streaming. Your code would look like this. We create an XDocument and then enumerate over a set of annoymous types we generate from our LINQ statement XDocument x = XDocument.Load("C:\\TEMP\\CustomerOrders-Attribute.xml");   foreach (var xdata in (from customer in x.Elements("OrderInterface").Elements("Customer")                        from order in customer.Elements("Orders").Elements("Order")                        select new { Account = customer.Attribute("AccountNumber").Value                                   , OrderDate = order.Attribute("OrderDate").Value }                        )) {     Output0Buffer.AddRow();     Output0Buffer.AccountNumber = xdata.Account;     Output0Buffer.OrderDate = Convert.ToDateTime(xdata.OrderDate); } As I said the downside to this is that you are loading the whole document into memory. I did some googling and came across some helpful videos from a nice UK DPE Mike Taulty http://www.microsoft.com/uk/msdn/screencasts/screencast/289/LINQ-to-XML-Streaming-In-Large-Documents.aspx. Which show you how you can combine LINQ and the XmlReader to get a semi streaming approach. I took what he did and implemented it in SSIS. What I found odd was that when I ran it I got different numbers between using the streamed and non streamed versions. I found the cause was a little bug in Mikes code that causes the pointer in the XmlReader to progress past the start of the element and thus foreach (var xdata in (from customer in StreamReader("C:\\TEMP\\CustomerOrders-Attribute.xml","Customer")                                from order in customer.Elements("Orders").Elements("Order")                                select new { Account = customer.Attribute("AccountNumber").Value                                           , OrderDate = order.Attribute("OrderDate").Value }                                ))         {             Output0Buffer.AddRow();             Output0Buffer.AccountNumber = xdata.Account;             Output0Buffer.OrderDate = Convert.ToDateTime(xdata.OrderDate);         } These look very similiar and they are the key element is the method we are calling, StreamReader. This method is what gives us streaming, what it does is return a enumerable list of elements, because of the way that LINQ works this results in the data being streamed in. static IEnumerable<XElement> StreamReader(String filename, string elementName) {     using (XmlReader xr = XmlReader.Create(filename))     {         xr.MoveToContent();         while (xr.Read()) //Reads the first element         {             while (xr.NodeType == XmlNodeType.Element && xr.Name == elementName)             {                 XElement node = (XElement)XElement.ReadFrom(xr);                   yield return node;             }         }         xr.Close();     } } This code is specifically designed to return a list of the elements with a specific name. The first Read reads the root element and then the inner while loop checks to see if the current element is the type we want. If not we do the xr.Read() again until we find the element type we want. We then use the neat function XElement.ReadFrom to read an element and all its sub elements into an XElement. This is what is returned and can be consumed by the LINQ statement. Essentially once one element has been read we need to check if we are still on the same element type and name (the inner loop) This was Mikes mistake, if we called .Read again we would advance the XmlReader beyond the start of the Element and so the ReadFrom method wouldn't work. So with the code above you can use what ever LINQ statement you like to flatten your XML into the rowsets you want. You could even have multiple outputs and generate your own surrogate keys.        

    Read the article

  • Parse an XML file

    - by karan@dotnet
    The following code shows a simple method of parsing through an XML file/string. We can get the parent name, child name, attributes etc from the XML. The namespace System.Xml would be the only additional namespace that we would be using. string myXMl = "<Employees>" + "<Employee ID='1' Name='John Mayer'" + "Address='12th Street'" + "City='New York' Zip='10004'>" + "</Employee>" + "</Employees>"; XmlDocument xDoc = new XmlDocument();xDoc.LoadXml(myXMl);XmlNodeList xNodeList = xDoc.SelectNodes("Employees/child::node()");foreach (XmlNode xNode in xNodeList){ if (xNode.Name == "Employee") { string ID = xNode.Attributes["ID"].Value; //Outputs: 1 string Name = xNode.Attributes["Name"].Value;//Outputs: John Mayer string Address = xNode.Attributes["Address"].Value;//Outputs: 12th Street string City = xNode.Attributes["City"].Value;//Outputs: New York string Zip = xNode.Attributes["Zip"].Value; //Outputs: 10004 }} Lets look at another XML: string myXMl = "<root>" + "<parent1>..some data</parent1>" + "<parent2>" + "<Child1 id='1' name='Adam'>data1</Child1>" + "<Child2 id='2' name='Stanley'>data2</Child2>" + "</parent2>" + "</root>"; XmlDocument xDoc = new XmlDocument();xDoc.LoadXml(myXMl);XmlNodeList xNodeList = xDoc.SelectNodes("root/child::node()"); //Traverse the entire XML nodes.foreach (XmlNode xNode in xNodeList) { //Looks for any particular nodes if (xNode.Name == "parent1") { //some traversing.... } if (xNode.Name == "parent2") { //If the parent node has child nodes then //traverse the child nodes foreach (XmlNode xNode1 in xNode.ChildNodes) { string childNodeName = xNode1.Name; //Ouputs: Child1 string childNodeData = xNode1.InnerText; //Outputs: data1 //Loop through each attribute of the child nodes foreach (XmlAttribute xAtt in xNode1.Attributes) { string attrName = xAtt.Name; //Outputs: id string attrValue = xAtt.Value; //Outputs: 1 } } }}  

    Read the article

  • IIS MIME type for XML content

    - by Rodolfo
    recently a third party plugin I'm using to display online magazines stopped working on mobile devices. According to their help page, this happens for people serving with IIS. Their solution is to set the MIME type .xml to "application/xml". It's by default set to "text/xml". Changing it does work, but would that have unintended side effects or is it actually the correct way and IIS just set it wrong?

    Read the article

  • .XML Sitemaps and HTML Sitemaps Clarification

    - by MSchumacher
    I've got a website with about 170 pages and I want to create an effective Sitemap for it as it is long due. The website is internally linked very well but I still want to take advantage of creating a sitemap to allow SE's to crawl my site easier and to hopefully increase my websites PR. Though I am slightly confused to what I must do: Is it necessary to create a .xml sitemap AND a HTML Sitemap (both)? ... Because I've never worked with .xml ... where do I put this file once it's created? In the Root folder? So I assume that this sitemap.xml is ONLY to be read by spiders and NOT by website visitors. IE: No visitor on my website is going to visit the page sitemap.xml, am I correct? ... Hence why I should also create an HTML sitemap (sitemap.htm)?

    Read the article

  • Convenience of mySQL over xml

    - by Bonechilla
    Currently I use XML to store specific information to correctly load a few things such as a list of specfied characters, scenes and music, Once more I use JAXB in combination with standard compression/decompression(ZIP) functionality to store a list of extrenous data. This data is called to add functionality to the character, somewhat like Skills in an RPG. Each skill is seperated into its own XML file with a grandlist which contains the names of each file with their extensions omitted and zipped in folder that gets encrypted. At first using xml was working fine however as the skill list grow i worry about its stability. I was wondering if I should begin storing the data in mySQL. Originally I planned to simply convert everything to JSON over xml but i think possibly mySQL would be a better move. Can anyone inform me of the key difference and pros and cons of each I guess i'm looking for the best way to store the data more conviently and would be easier to operate on. The data is mostly primatives and strings and the only arraylist of values i have i can just concat into a single field and parse later Edit: If I am going in the right direction with XML would it make sense to convert it to JSON and use maybe Kyro or EclipseLink JAXB (MOXy)

    Read the article

  • Opening an XML in Unity3D when the game is built

    - by N0xus
    At the moment, my game can open up an XML file inside the editor when I run it. In my XMLReader.cs I'm loading in my file like so: _xmlDocument.Load(Application.dataPath + "\\HV_Settings\\Settings.xml"); This class also deals with what the XML should do once it has been read in. However, when I build the game and run the exe, this file isn't called. I know that I can store this file in the C drive, but I want to keep everything in one place so when I start to release what I'm working on, the user doesn't need to do anything. Am I doing something silly which is causing the XML not to be read?

    Read the article

  • Problem deserializing xml file

    - by Andy
    I auto generated an xsd file from the below xml and used xsd2code to get a c# class. The problem is the entire xml doesn't deserialize. Here is how I'm attempting to deserialize: static void Main(string[] args) { using (TextReader textReader = new StreamReader("config.xml")) { // string temp = textReader.ReadToEnd(); XmlSerializer deserializer = new XmlSerializer(typeof(project)); project p = (project)deserializer.Deserialize(textReader); } } here is the actual XML: <?xml version='1.0' encoding='UTF-8'?> <project> <scm class="hudson.scm.SubversionSCM"> <locations> <hudson.scm.SubversionSCM_-ModuleLocation> <remote>https://svn.xxx.com/test/Validation/CPS DRTest DLL/trunk</remote> </hudson.scm.SubversionSCM_-ModuleLocation> </locations> <useUpdate>false</useUpdate> <browser class="hudson.scm.browsers.FishEyeSVN"> <url>http://fisheye.xxxx.net/browse/Test/</url> <rootModule>Test</rootModule> </browser> <excludedCommitMessages></excludedCommitMessages> </scm> <openf>Hello there</openf> <buildWrappers/> </project> When I run the above, the locations node remains null. Here is the xsd that I'm using: <?xml version="1.0" encoding="utf-8"?> <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> <xs:element name="project"> <xs:complexType> <xs:all> <xs:element name="openf" type="xs:string" minOccurs="0" /> <xs:element name="buildWrappers" type="xs:string" minOccurs="0" /> <xs:element name="scm" minOccurs="0"> <xs:complexType> <xs:sequence> <xs:element name="useUpdate" type="xs:string" minOccurs="0" msdata:Ordinal="1" /> <xs:element name="excludedCommitMessages" type="xs:string" minOccurs="0" msdata:Ordinal="2" /> <xs:element name="locations" minOccurs="0"> <xs:complexType> <xs:sequence> <xs:element name="hudson.scm.SubversionSCM_-ModuleLocation" minOccurs="0"> <xs:complexType> <xs:sequence> <xs:element name="remote" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> <xs:element name="browser" minOccurs="0"> <xs:complexType> <xs:sequence> <xs:element name="url" type="xs:string" minOccurs="0" msdata:Ordinal="0" /> <xs:element name="rootModule" type="xs:string" minOccurs="0" msdata:Ordinal="1" /> </xs:sequence> <xs:attribute name="class" type="xs:string" /> </xs:complexType> </xs:element> </xs:sequence> <xs:attribute name="class" type="xs:string" /> </xs:complexType> </xs:element> </xs:all> </xs:complexType> </xs:element> <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true"> <xs:complexType> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element ref="project" /> </xs:choice> </xs:complexType> </xs:element> </xs:schema>

    Read the article

  • XSD Schema for XML with multiple structures

    - by Xetius
    I am attempting to write an XML Schema to cover a number of XML conditions which I may encounter. I have the same root element (serviceRequest) with different child elements. I was trying to use the xs:extension element to define multiple versions, but it is complaining about unexpected element orderInclusionCriteria etc. Am I going about this the right way, or is there a better way to define this? The other way I thought about this was to have a single xs:choice with all the options inside it, but this seemed somewhat inelegant. These XSD files are for use within XMLBeans if that makes any difference. I have Given the following 2 examples of XML: 1) <?xml version="1.0" encoding="utf-8"?> <serviceRequest method="GOO" debug="NO"> <sessionId sID="ABC1234567" /> <orderInclusionCriteria accountId="1234567" accountNum="1234567890" /> </serviceRequest> 2) <?xml version="1.0" encoding="utf-8"?> <serviceRequest method="GOO" debug="NO"> <sessionId sID="ABC1234567" /> <action aType='MakePayment'> <makePayment accountID='CH91015165S' amount='5.00' /> </action> </serviceRequest> I thought I could use the following schema file: <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="serviceRequest" type="ServiceRequestType" /> <xs:element name="session" type="SessionType" /> <xs:attribute name="method" type="xs:string" /> <xs:attribute name="debug" type="xs:string" /> <xs:complexType name="SessionType"> <xs:attribute name="sID" use="required"> <xs:simpleType> <xs:restriction base="xs:string"/> </xs:simpleType> </xs:attribute> </xs:complexType> <xs:complexType name="ServiceRequestType"> <xs:sequence> <xs:element ref="session" /> </xs:sequence> <xs:attribute ref="method" /> <xs:attribute ref="debug" /> </xs:complexType> <xs:complexType name="OrderTrackingServiceRequest"> <xs:complexContent> <xs:extension base="ServiceRequestType"> <xs:complexType> <xs:sequence> <xs:element name="OrderInclusionCriteria" type="xs:string" /> </xs:sequence> </xs:complexType> </xs:extension> </xs:complexContent> </xs:complexType> <xs:complexType name="Action"> <xs:complexContent> <xs:extension base="ServiceRequestType"> <xs:complexType> <xs:sequence> <xs:element name="makePayment"> <xs:complexType> <xs:attribute name="accountID" type="xs:string" /> <xs:attribute name="amount" type="xs:string" /> <xs:complexType> </xs:element> </xs:sequence> <xs:attribute name="aType" type="xs:string" /> </xs:complexType> </xs:extension> </xs:complexContent> </xs:complexType> </xs:schema>

    Read the article

  • XML deserializer (Iserialzable)

    - by user311130
    Hey everybody, I have a class in c# that implements Iserialzable. I'm using a XMLSerializer that produces a XML from instance of that class. I get the following XML: <?xml version="1.0"?> <Configuration xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <SessionConfiguration> <RemoteMachineName>HV-BENDA</RemoteMachineName> </SessionConfiguration> <SessionsCredentialsList> <CredentialsItem> <User>test0</User> <Password>Pa$$word1</Password> </CredentialsItem> <CredentialsItem> <User>test1</User> <Password>Pa$$word1</Password> </CredentialsItem> <CredentialsItem> <User>test2</User> <Password>Pa$$word1</Password> </CredentialsItem> <CredentialsItem> <User>test3</User> <Password>Pa$$word1</Password> </CredentialsItem> <CredentialsItem> <User>test4</User> <Password>Pa$$word1</Password> </CredentialsItem> </SessionsCredentialsList> <TIME_OUT /> <LOCAL_USERS_NUM>5</LOCAL_USERS_NUM> </Configuration> At some later point in the code I use a XMLSerializer again to deserial that XML document. and I get the following error: {"There is an error in XML document (1, 1)."} Inner exception: {"Data at the root level is invalid. Line 1, position 1."} Do someone knows wat could be the problem? All the best

    Read the article

  • How do I serialize an object to xml but not have it be the root element of the xml document

    - by mezoid
    I have the following object: public class MyClass { public int Id { get; set;} public string Name { get; set; } } I'm wanting to serialize this to the following xml string: <MyClass> <Id>1</Id> <Name>My Name</Name> </MyClass> Unfortunately, when I use the XMLSerializer I get a string which looks like: <?xml version="1.0" encoding="utf-8"?> <MyClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Id>1</Id> <Name>My Name</Name> </MyClass> I'm not wanting MyClass to be the root element the document, rather I'm eventually wanting to add the string with other similar serialized objects which will be within a larger xml document. i.e. Eventually I'll have a xml string which looks like this: <Classes> <MyClass> <Id>1</Id> <Name>My Name</Name> </MyClass> <MyClass> <Id>1</Id> <Name>My Name</Name> </MyClass> </Classes>" My first thought was to create a class as follows: public class Classes { public List<MyClass> MyClasses { get; set; } } ...but that just addes an additional node called MyClasses to wrap the list of MyClass.... My gut feeling is that I'm approaching this the wrong way and that my lack of experience with creating xml files isn't helping to point me to some part of the .NET framework or some other library that simplifies this.

    Read the article

  • How to change the extension of a processed xml file (using eXist & cocoon)

    - by Carsten C.
    Hi all, I'm really new to this whole web stuff, so please be nice if I missed something important to post. Short: Is there a possibility to change the name of a processed file (eXist-DB) after serialization? Here my case, the following request to my eXist-db: http://localhost:8080/exist/cocoon/db/caos/test.xml and I want after serialization the follwing (xslt is working fine): http://localhost:8080/exist/cocoon/db/caos/test.html I'm using the followong sitemap.xmap with cocoon (hoping this is responsible for it) <map:match pattern="db/caos/**"> <!-- if we have an xpath query --> <map:match pattern="xpath" type="request-parameter"> <map:generate src="xmldb:exist:///db/caos/{../1}/#{1}"/> <map:act type="request"> <map:parameter name="parameters" value="true"/> <map:parameter name="default.howmany" value="1000"/> <map:parameter name="default.start" value="1"/> <map:transform type="filter"> <map:parameter name="element-name" value="result"/> <map:parameter name="count" value="{howmany}"/> <map:parameter name="blocknr" value="{start}"/> </map:transform> <map:transform src=".snip./webapp/stylesheets/db2html.xsl"> <map:parameter name="block" value="{start}"/> <map:parameter name="collection" value="{../../1}"/> </map:transform> </map:act> <map:serialize type="html" encoding="UTF-8"/> </map:match> <!-- if the whole file will be displayed --> <map:generate src="xmldb:exist:/db/caos/{1}"/> <map:transform src="..snip../stylesheets/caos2soac.xsl"> <map:parameter name="collection" value="{1}"/> </map:transform> <map:transform type="encodeURL"/> <map:serialize type="html" encoding="UTF-8"/> </map:match> So my Question is: How do I change the extension of the test.xml to test.html after processing the xml file? Background: I'm generating some information out of some xml-dbs, this infos will be displayed in html (which is working), but i want to change some entrys later, after I generated the html site. To make this confortable, I want to use Jquery & Jeditable, but the code does not work on the xml files. Saving the generated html is not an option. tia for any suggestions [and|or] help CC Edit: After reading all over: could it be, that the extension is irrelevant and that this is only a problem of port 8080? I'm confused...

    Read the article

  • c# linq to xml to list

    - by WtFudgE
    I was wondering if there is a way to get a list of results into a list with linq to xml. If I would have the following xml for example: <?xml version="1.0"?> <Sports xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <SportPages> <SportPage type="test"> <LinkPage> <IDList> <string>1</string> <string>2</string> </IDList> </LinkPage> </SportPage> </SportPages> </Sports> How could I get a list of strings from the IDList? I'm fairly new to linq to xml so I just tried some stuff out, I'm currently at this point: var IDs = from sportpage in xDoc.Descendants("SportPages").Descendants("SportPage") where sportpage.Attribute("type").Value == "Karate" select new { ID = sportpage.Element("LinkPage").Element("IDList").Elements("string") }; But the var is to chaotic to read decently. Isn't there a way I could just get a list of strings from this? Thanks

    Read the article

  • Best approach to convert XML to RDF/XML using an ontology

    - by krisvandenbergh
    I have an XML which uses the XPDL standard (which has an XML schema). What I'm trying to do now is to convert its content to RDF format (serialized in XML), in terms of a certain ontology. Clearly, there needs to be some sort of mapping here. I would like to do this using PHP. The thing is, I have no idea how to do this best. I know how to read an XML file, but how would the mappings occur? What would be a good approach?

    Read the article

  • How to generate XML with attributes in c#.

    - by user292815
    I have that code: ... request data = new request(); data.username = formNick; xml = data.Serialize(); ... [System.Serializable] public class request { public string username; public string password; static XmlSerializer serializer = new XmlSerializer(typeof(request)); public string Serialize() { StringBuilder builder = new StringBuilder(); XmlWriterSettings settings = new XmlWriterSettings(); settings.OmitXmlDeclaration = true; settings.Encoding = Encoding.UTF8; serializer.Serialize( System.Xml.XmlWriter.Create(builder, settings ), this); return builder.ToString(); } public static request Deserialize(string serializedData) { return serializer.Deserialize(new StringReader(serializedData)) as request; } } I want to add attributes to some nodes and create some sub-nodes. Also how to parse xml like that: <answer> <player id="2"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="nothing"></action> </player> <player id="3"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="boom"> <1>1</1> <2>2</2> </action> </player> </answer> p.s. it is not a xml file, it's answer from http server.

    Read the article

  • How to generate XML with attributes in .NET?

    - by user292815
    I have that code: ... request data = new request(); data.username = formNick; xml = data.Serialize(); ... [System.Serializable] public class request { public string username; public string password; static XmlSerializer serializer = new XmlSerializer(typeof(request)); public string Serialize() { StringBuilder builder = new StringBuilder(); XmlWriterSettings settings = new XmlWriterSettings(); settings.OmitXmlDeclaration = true; settings.Encoding = Encoding.UTF8; serializer.Serialize( System.Xml.XmlWriter.Create(builder, settings ), this); return builder.ToString(); } public static request Deserialize(string serializedData) { return serializer.Deserialize(new StringReader(serializedData)) as request; } } I want to add attributes to some nodes and create some sub-nodes. Also how to parse xml like that: <answer> <player id="2"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="nothing"></action> </player> <player id="3"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="boom"> <1>1</1> <2>2</2> </action> </player> </answer> p.s. it is not a xml file, it's answer from http server.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >