Search Results

Search found 6107 results on 245 pages for 'reserved words'.

Page 6/245 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • Reading three words and sorting them in lexicographic order

    - by Derrick
    I am trying to create a program that asks the User to type three words and sort them in lexicographic order. EXAMPLE; Enter three words separated by spaces: Pear Orange Apple Apple Orange Pear The program is working fine (if I attempt the above example) except for one type of combination example that I will show below. EXAMPLE; Enter three words separated by spaces: Orange Apple Pear Apple Pear Pear The program is skipping the first word (Orange) if it is supposed to appear in the middle of the three words. I believe that this line of code is affecting the program because it says that "this assigned value is never used" but I'm not sure how to fix it since I'm still an entry Java learner. middle = firstWord; Because of that line being unused, it's why Pear appeared twice. import java.util.*; public static void main(String[] args) { Scanner wordInput = new Scanner(System.in); String firstWord; String secondWord; String thirdWord; System.out.println("Enter three words separated by spaces: "); firstWord = wordInput.next(); secondWord = wordInput.next(); thirdWord = wordInput.next(); String top = firstWord; String bottom = firstWord; if( top.compareTo(secondWord) > 0) { top = secondWord; } if( top.compareTo(thirdWord) > 0) { top = thirdWord; } if( bottom.compareTo(secondWord) < 0) { bottom = secondWord; } if( bottom.compareTo(thirdWord) < 0) { bottom = thirdWord; } String middle; if( !firstWord.equals(bottom) && !firstWord.equals(top) ) { middle = firstWord; } if( !secondWord.equals(bottom) && !secondWord.equals(top) ) { middle = secondWord; } else { middle = thirdWord; } System.out.println( top ); System.out.println( middle ); System.out.println( bottom ); } } Does anyone what I am missing or doing wrong? :( Please and thank you for any help!

    Read the article

  • cannot paste words with pictures in ms word 2010

    - by user23950
    Is there any option that will correct this? I'm pasting my assignment with some pictures in it in ms word 2010 from a webpage but it doesn't seem to be showing the picture that is copied along with the words. When I try to right click and see the paste options. The only option that I can see is text. Please help.

    Read the article

  • Selectively replacing words outside of tags using regular expressions in PHP?

    - by Gary Willoughby
    I have a paragraph of text and i want to replace some words using PHP (preg_replace). Here's a sample piece of text: This lesson addresses rhyming [one]words and ways[/one] that students may learn to identify these words. Topics include learning that rhyming words sound alike and these sounds all come from the [two]ending of the words[/two]. This can be accomplished by having students repeat sets of rhyming words so that they can say them and hear them. The students will also participate in a variety of rhyming word activities. In order to demonstrate mastery the students will listen to [three]sets of words[/three] and tell the teacher if the words rhyme or not. If you notice there are many occurances of the word 'words'. I want to replace all the occurances that don't occur inside any of the tags with the word 'birds'. So it looks like this: This lesson addresses rhyming [one]words and ways[/one] that students may learn to identify these birds. Topics include learning that rhyming birds sound alike and these sounds all come from the [two]ending of the words[/two]. This can be accomplished by having students repeat sets of rhyming birds so that they can say them and hear them. The students will also participate in a variety of rhyming word activities. In order to demonstrate mastery the students will listen to [three]sets of words[/three] and tell the teacher if the birds rhyme or not. Would you use regular expressions to accomplish this? Can a regular expression accomplish this?

    Read the article

  • Combine regular expressions for splitting camelCase string into words

    - by stou
    I managed to implement a function that converts camel case to words, by using the solution suggested by @ridgerunner in this question: Split camelCase word into words with php preg_match (Regular Expression) However, I want to also handle embedded abreviations like this: 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' I came up with this solution: <?php function camelCaseToWords($camelCaseStr) { // Convert: "TestASAPTestMore" to "TestASAP TestMore" $abreviationsPattern = '/' . // Match position between UPPERCASE "words" '(?<=[A-Z])' . // Position is after group of uppercase, '(?=[A-Z][a-z])' . // and before group of lowercase letters, except the last upper case letter in the group. '/x'; $arr = preg_split($abreviationsPattern, $camelCaseStr); $str = implode(' ', $arr); // Convert "TestASAP TestMore" to "Test ASAP Test More" $camelCasePattern = '/' . // Match position between camelCase "words". '(?<=[a-z])' . // Position is after a lowercase, '(?=[A-Z])' . // and before an uppercase letter. '/x'; $arr = preg_split($camelCasePattern, $str); $str = implode(' ', $arr); $str = ucfirst(trim($str)); return $str; } $inputs = array( 'oneTwoThreeFour', 'StartsWithCap', 'hasConsecutiveCAPS', 'ALLCAPS', 'ALL_CAPS_AND_UNDERSCORES', 'hasABREVIATIONEmbedded', ); echo "INPUT"; foreach($inputs as $val) { echo "'" . $val . "' translates to '" . camelCaseToWords($val). "'\n"; } The output is: INPUT'oneTwoThreeFour' translates to 'One Two Three Four' 'StartsWithCap' translates to 'Starts With Cap' 'hasConsecutiveCAPS' translates to 'Has Consecutive CAPS' 'ALLCAPS' translates to 'ALLCAPS' 'ALL_CAPS_AND_UNDERSCORES' translates to 'ALL_CAPS_AND_UNDERSCORES' 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' It works as intended. My question is: Can I combine the 2 regular expressions $abreviationsPattern and camelCasePattern so i can avoid running the preg_split() function twice?

    Read the article

  • How to remove words based on a word count

    - by Chris
    Here is what I'm trying to accomplish. I have an object coming back from the database with a string description. This description can be up to 1000 characters long, but we only want to display a short view of this. So I coded up the following, but I'm having trouble in actually removing the number of words after the regular expression finds the total count of words. Does anyone have good way of dispalying the words which are less than the Regex.Matches? Thanks! if (!string.IsNullOrEmpty(myObject.Description)) { string original = myObject.Description; MatchCollection wordColl = Regex.Matches(original, @"[\S]+"); if (wordColl.Count < 70) // 70 words? { uxDescriptionDisplay.Text = string.Format("<p>{0}</p>", myObject.Description); } else { string shortendText = original.Remove(200); // 200 characters? uxDescriptionDisplay.Text = string.Format("<p>{0}</p>", shortendText); } }

    Read the article

  • Identify words with ascending characters from text file

    - by user2914000
    I am having a fair amount of trouble trying to write a program that counts the amount of ascending words (words in which each character is larger than the previous character) in a text file. I have tried a few different methods to solve this but cannot seem to get it working. If anyone could help me revise the code to work properly it would be appreciated. The code will print about 5 of the words from the list of nearly 20000, but none considered are ascending (the file does have many ascending words) and it sometimes prints the same word twice. I am printing theWord to the console simply to see if the code works. import java.util.Scanner; import java.io.*; public class { public static void main (String [] args) throws FileNotFoundException{ String theWord; Scanner inputFile = new Scanner(new File("file.txt")); boolean ascending = true; int i = 1; while(inputFile.hasNextLine()){ theWord = inputFile.nextLine(); if(theWord.length() >= 2){ while(i < theWord.length() - 1){ if(theWord.charAt(i) <= theWord.charAt(i + 1)){ ascending = true; System.out.println("+ " + theWord); totalNum = totalNum + 1; } else{ ascending = false; System.out.println("= " + theWord); } i++; } } }

    Read the article

  • Search for short words with SOLR

    - by Carsten Gehling
    I am using SOLR along with NGramTokenizerFactory to help create search tokens for substrings of words NGramTokenizer is configured with a minimum word length of 3 This means that I can search for e.g. "unb" and then match the word "unbelievable". However I have a problem with short words like "I" and "in". These are not indexed by SOLR (I suspect it is because of NGramTokenizer) and therefore I cannot search for them. I don't want to reduce the minimum word length to 1 or 2, since this creates a huge search index. But I would like SOLR to include whole words whose length is already below this minimum. How can I do that? /Carsten

    Read the article

  • Find all words containing characters in UNIX

    - by fahdshariff
    Given a word W, I want to find all words containing the letters in W from /usr/dict/words. For example, "bat" should return "bat" and "tab" (but not "table"). Here is one solution which involves sorting the input word and matching: word=$1 sortedWord=`echo $word | grep -o . | sort | tr -d '\n'` while read line do sortedLine=`echo $line | grep -o . | sort | tr -d '\n'` if [ "$sortedWord" == "$sortedLine" ] then echo $line fi done < /usr/dict/words Is there a better way? I'd prefer using basic commands (instead of perl/awk etc), but all solutions are welcome! To clarify, I want to find all permutations of the original word. Addition or deletion of characters is not allowed.

    Read the article

  • All words in a trie data-structure

    - by John Smith
    I'm trying to put all words in a trie in a string, a word is detonated by the eow field being true for a certain character in the trie data structure, hence a trie can could have letters than lead up to no word, for ex "abc" is in the trie but "c"'s eow field is false so "abc" is not a word Here is my Data structure struct Trie { bool eow; //when a Trie field isWord = true, hence there is a word char letter; Trie *letters[27]; }; and here is my attemped print-all function, basically trying to return all words in one string seperated by spaces for words string printAll( string word, Trie& data) { if (data.eow == 1) return word + " "; for (int i = 0; i < 26; i++) { if (data.letters[i] != NULL) printAll( word + data.letters[i]->letter, *(data.letters[i])); } return ""; } Its not outputting what i want, any suggestions?

    Read the article

  • SQL Server union selects built dynamically from list of words

    - by Adam Tuttle
    I need to count occurrence of a list of words across all records in a given table. If I only had 1 word, I could do this: select count(id) as NumRecs where essay like '%word%' But my list could be hundreds or thousands of words, and I don't want to create hundreds or thousands of sql requests serially; that seems silly. I had a thought that I might be able to create a stored procedure that would accept a comma-delimited list of words, and for each word, it would run the above query, and then union them all together, and return one huge dataset. (Sounds reasonable, right? But I'm not sure where to start with that approach...) Short of some weird thing with union, I might try to do something with a temp table -- inserting a row for each word and record count, and then returning select * from that temp table. If it's possible with a union, how? And does one approach have advantages (performance or otherwise) over the other?

    Read the article

  • Pros and cons of Localisation of technical words ?

    - by paercebal
    This question is directed to the non-english speaking people here. It is somewhat biased because SO is an "english-speaking" web forum, so... In the other hand, most developers would know english anyway... In your locale culture, are technical words translated into locale words ? For example, how "Design Pattern", or "Factory", or whatever are written/said in german, spanish, etc. etc. when used by IT? Are the english words prefered? The local translation? Do the two version (english/locale) are evenly used? Edit Could you write with your answer the locale translation of "Design Pattern"? In french, according to Wikipedia.fr, it is "Patron de conception", which translates back as "Model of Conceptualization" (I guess).

    Read the article

  • UITextView or UIWebView with normal words looking like links

    - by diwup
    Hey guys, I was looking at the Twitter for iPhone app and was puzzled. First of all, there are normal words looking like links inside. Second, when I touch those link-like words, the text view (or maybe web view) jumps to the corresponding part below (yes, it doesn't open Safari, it just jumps to the text within that text/web view) Now I want to implement the same effects. I should base my implementation on what? UITextView or UIWebView? How to make normal words look like links? How to make those smooth jumps within such a text/web views? Thanks in advance.

    Read the article

  • Add Words to Android's UserDictionary

    - by SaulBack
    I want to add an entire medical dictionary to my android (Moto Droid). I would like to be able to send text messages and have the medical words be in the predictable text. I've been trying to write a small app that would accomplish this, but everything I try the app crashes on startup. I've never written an app for a mobile platform so that is a first for me. Here is what is not working properly. public class WordAdd extends Activity { /** Called when the activity is first created. */ public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); UserDictionary.Words.addWord( this , "newMedicalWord", 1, UserDictionary.Words.LOCALE_TYPE_CURRENT); } } It seems so simple to do, yet I am so stuck. Thanks for any help you can provide.

    Read the article

  • List of uninteresting words

    - by Hooked
    [Caveat] This is not directly a programing question, but it is something that comes up so often in language processing that I'm sure it's of some use to the community. Does anyone have a good list of uninteresting (English) words that have been tested by more then a casual look? This would include all prepositions, conjunctions, etc... words that may have semantic meaning, but are often frequent in every sentence, regardless of the subject. I've built my own lists from time to time for personal projects but they've been ad-hoc; I continuously add words that I forgotten as they come in.

    Read the article

  • Splitting html string after so many words

    - by jimbo
    Hi all, I have a string that if it is longer than lets say 10 words, I want to split it into two parts. The second part will be included else-where after a 'more' link. The string will hold html tags too though. For an example the string could be: <p>This is just a test string with more words than the <strong>amount allow</strong> before split, blah blah blah</p> So in the case I would want: $string[0] // <p>This is just a test string with more words than</p>; $string[1] // <p>the <strong>amount allow</strong> before split, blah blah blah</p>; Thanks in advance

    Read the article

  • Find words in many files

    - by ant2009
    Hello, I am looking for this struct messages_sdd_t and I need to search through a lot of *.c files to find it. However, I can't seen to find a match as I want to exclude all the words 'struct' and 'messages_sdd_t'. As I want to search on this only 'struct messages_sdd_t' The reason for this is, as struct is used many times and I keep getting pages or search results. I have been doing this without success: find . -type f -name '*.c' | xargs grep 'struct messages_sdd_t' and this find . -type f -name '*.c' | xargs egrep -w 'struct|messages_sdd_t' Many thanks for any suggestions,

    Read the article

  • Find Files That Contain Both Words in Notepad++

    - by SethO
    In Notepad++ (v5.9), I want to search for files which contain two words. For example, I would like to find all text files in a directory that have both Alpha and Bravo in the file. They may not be next to each other and they may have multiple occurrences of either. I just want to find the files that have at least one instance of each. Is there a way to structure this search without resorting to Regular Expressions? Thanks for the advice.

    Read the article

  • How to force MS Word 2010 to split words anywhere

    - by Petr Újezdský
    I want Microsoft Word 2010 to force split words exactly where the line ends, even if it is "wrong and unreadable". Font is some monotype (Courier New). The text is in Text field which has fixed width. I found some option in Text field Format - Wrap lines inside. But it only disables / enables whole wrapping. The text will be printed over uniform spaced boxes, each for one letter (postal order). Examples: Current: some text with | looooooooooong word | What i want: some text with looooooo | oooong word | I tried to google it for an hour, but everybody wants the exact opposite (hard spaces etc..)

    Read the article

  • Windows 8 start screen will only find apps matching full words

    - by Ian Oakes
    Since doing a fresh install of Windows 8 x64 RTM I'm having trouble starting apps from the start screen. In previous version I could just start typing the apps name and I would be presented with a list of matches that decreased in number as I continued typing. In the RTM version I have to type complete words to find a match. i.e. if I want to run powershell I have to type in powershell before I get any hits. Like wise if I want to start Visual Studio I have to type visual before I get a match. If I continue and start typing Studio the match goes away and doesn't return until I finish typing studio. This problem does not affect Setting or Files which show all possible matches. Any ideas what is wrong?

    Read the article

  • Make words look like keystrokes in Microsoft Word

    - by techturtle
    Is there an easy way in Microsoft Word 2010 to make words appear like keystrokes the way we can here in Superuser? Something like this: Ctrl + V I know that <kbd> is an HTML tag, but in normal HTML that just switches to a fixed-width font. In fact, that's how Word treats it if you paste something from SU into a Word doc: If there's not a standard way to do this in Word, is there a free font that might accomplish the same thing? I thought I'd seen some before but couldn't find any at the regular places I find fonts (dafont.com, fontspace.com).

    Read the article

  • Find words from a list within a website

    - by Senoculus
    Summary: I need to find out if any items in my list occur in a website. I could do it manually with ctrl+f, but it would take a long time. Description I have a text file with key words in this format: word1 word4 word12 word24 ... I need to search text in a table on a website (in Internet Explorer) with this format: RandomWord version 1.3 ... word1 version 1.3 ... word2 version 2.6 ... word5 version 1.1 ... randomword version 9.0 ... word12 version 1.0 ... ... ... ... If the above data was what I had, it would be nice to end up with this list: word1 word12

    Read the article

  • Limit user input to allowable comma delimited words with regular expression using javascript

    - by Marc
    I want to force the user to enter any combination of the following words. the words need to be comma delimited and no comma at the beginning or end of the string the user should only be able to enter one of each word. Examples admin basic,ectech admin,ectech,advanced basic,advanced,admin,ectech my attempt ^((basic|advanced)|admin|ectech)((,basic|,advanced)|,admin|,ectech){0,2}$ Thanks Marc

    Read the article

  • Splitting a filename into words and numbers in Python

    - by danspants
    The following code splits a string into a list of words but does not include numbers: txt="there_once was,a-monkey.called phillip?09.txt" sep=re.compile(r"[\s\.,-_\?]+") sep.split(txt) ['there', 'once', 'was', 'a', 'monkey', 'called', 'phillip', 'txt'] This code gives me words and numbers but still includes "_" as a valid character: re.findall(r"\w+|\d+",txt) ['there_once', 'was', 'a', 'monkey', 'called', 'phillip', '09', 'txt'] What do I need to alter in either piece of code to end up with the desired result of: ['there', 'once', 'was', 'a', 'monkey', 'called', 'phillip', '09', 'txt']

    Read the article

  • Regex to match words and those with an apostrophe

    - by Beau Martínez
    I'm looking for a regex to only match words, possibly including numbers, and possibly with an apostrophe at the beginning, middle, or end; and ignore everything else. So these would be matched verbatim: 'bout it's persons' But these would be ignored: ' '' However, for words like 'open', open should be matched.

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >