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  • how to bind super+s to indicator applete complete? - gnome classic

    - by rrosa
    i use gnome classic, i'm not a mouse fan. when i get an email while i'm writing code, i i would super+s to get to the indicator-applet-complete and read it. also to write emails, or check unread instant messages. upgrading from 12.04 to 14.04 made super+s bind to applications menu rather than the indicator applet complete. i removed the binding from the applications using dconf-editor, navigating to: org-gnome-desktop-wm-keybindings and disabling (['disabled']) the panel-main-menu key. now, how do i bind super+s to the indicator applet complete? it seems to be some how binded, since if if press super+s and then move the cursor over the applet it'll open the drop down menus (and it won't if i hover without pressing super+s) but i don't want to have to use the mouse...

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  • Getting Internet Explorer to Open Different Sets of Tabs Based on the Day of the Week

    - by Akemi Iwaya
    If you have to use Internet Explorer for work and need to open a different set of work-specific tabs every day, is there a quick and easy way to do it instead of opening each one individually? Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-driven grouping of Q&A web sites. The Question SuperUser reader bobSmith1432 is looking for a quick and easy way to open different daily sets of tabs in Internet Explorer for his work: When I open Internet Explorer on different days of the week, I want different tabs to be opened automatically. I have to run different reports for work each day of the week and it takes a lot of time to open the 5-10 tabs I use to run the reports. It would be a lot faster if, when I open Internet Explorer, the tabs I needed would automatically load and be ready. Is there a way to open 5-10 different tabs in Internet Explorer depending on the day of the week? Example: Monday – 6 Accounting Pages Tuesday – 7 Billing Pages Wednesday – 5 HR Pages Thursday – 10 Schedule Pages Friday – 8 Work Summary/Order Pages Is there an easier way for Bob to get all those tabs to load and be ready to go each day instead of opening them individually every time? The Answer SuperUser contributor Julian Knight has a simple, non-script solution for us: Rather than trying the brute force method, how about a work around? Open up each set of tabs either in different windows, or one set at a time, and save all tabs to bookmark folders. Put the folders on the bookmark toolbar for ease of access. Each day, right-click on the appropriate folder and click on ‘Open in tab group’ to open all the tabs. You could put all the day folders into a top-level folder to save space if you want, but at the expense of an extra click to get to them. If you really must go further, you need to write a program or script to drive Internet Explorer. The easiest way is probably writing a PowerShell script. Special Note: There are various scripts shared on the discussion page as well, so the solution shown above is just one possibility out of many. If you love the idea of using scripts for a function like this, then make sure to browse on over to the discussion page to see the various ones SuperUser members have shared! Have something to add to the explanation? Sound off in the comments. Want to read more answers from other tech-savvy Stack Exchange users? Check out the full discussion thread here.

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  • Why would Copying a Large Image to the Clipboard Freeze a Computer?

    - by Akemi Iwaya
    Sometimes, something really odd happens when using our computers that makes no sense at all…such as copying a simple image to the clipboard and the computer freezing up because of it. An image is an image, right? Today’s SuperUser post has the answer to a puzzled reader’s dilemna. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-driven grouping of Q&A web sites. Original image courtesy of Wikimedia. The Question SuperUser reader Joban Dhillon wants to know why copying an image to the clipboard on his computer freezes it up: I was messing around with some height map images and found this one: (http://upload.wikimedia.org/wikipedia/commons/1/15/Srtm_ramp2.world.21600×10800.jpg) The image is 21,600*10,800 pixels in size. When I right click and select “Copy Image” in my browser (I am using Google Chrome), it slows down my computer until it freezes. After that I must restart. I am curious about why this happens. I presume it is the size of the image, although it is only about 6 MB when saved to my computer. I am also using Windows 8.1 Why would a simple image freeze Joban’s computer up after copying it to the clipboard? The Answer SuperUser contributor Mokubai has the answer for us: “Copy Image” is copying the raw image data, rather than the image file itself, to your clipboard. The raw image data will be 21,600 x 10,800 x 3 (24 bit image) = 699,840,000 bytes of data. That is approximately 700 MB of data your browser is trying to copy to the clipboard. JPEG compresses the raw data using a lossy algorithm and can get pretty good compression. Hence the compressed file is only 6 MB. The reason it makes your computer slow is that it is probably filling your memory up with at least the 700 MB of image data that your browser is using to show you the image, another 700 MB (along with whatever overhead the clipboard incurs) to store it on the clipboard, and a not insignificant amount of processing power to convert the image into a format that can be stored on the clipboard. Chances are that if you have less than 4 GB of physical RAM, then those copies of the image data are forcing your computer to page memory out to the swap file in an attempt to fulfil both memory demands at the same time. This will cause programs and disk access to be sluggish as they use the disk and try to use the data that may have just been paged out. In short: Do not use the clipboard for huge images unless you have a lot of memory and a bit of time to spare. Like pretty graphs? This is what happens when I load that image in Google Chrome, then copy it to the clipboard on my machine with 12 GB of RAM: It starts off at the lower point using 2.8 GB of RAM, loading the image punches it up to 3.6 GB (approximately the 700 MB), then copying it to the clipboard spikes way up there at 6.3 GB of RAM before settling back down at the 4.5-ish you would expect to see for a program and two copies of a rather large image. That is a whopping 3.7 GB of image data being worked on at the peak, which is probably the initial image, a reserved quantity for the clipboard, and perhaps a couple of conversion buffers. That is enough to bring any machine with less than 8 GB of RAM to its knees. Strangely, doing the same thing in Firefox just copies the image file rather than the image data (without the scary memory surge). Have something to add to the explanation? Sound off in the comments. Want to read more answers from other tech-savvy Stack Exchange users? Check out the full discussion thread here.

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  • What Is Disk Fragmentation and Do I Still Need to Defragment?

    - by Jason Fitzpatrick
    Do modern computers still need the kind of routine defragmentation procedures that older computers called for? Read on to learn about fragmentation and what modern operating systems and file systems do to minimize performance impacts. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-drive grouping of Q&A web sites. Secure Yourself by Using Two-Step Verification on These 16 Web Services How to Fix a Stuck Pixel on an LCD Monitor How to Factory Reset Your Android Phone or Tablet When It Won’t Boot

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  • Do Limited Wi-Fi Channels Restrict Network Availability?

    - by Jason Fitzpatrick
    Wi-Fi protocol supports 13 communication channels; how do these channels relate to the volume of devices you can have on the network and the quality of the connection? Read on learn more about Wi-Fi channel usage. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-drive grouping of Q&A web sites. Why Does 64-Bit Windows Need a Separate “Program Files (x86)” Folder? Why Your Android Phone Isn’t Getting Operating System Updates and What You Can Do About It How To Delete, Move, or Rename Locked Files in Windows

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  • What can a Service do on Windows?

    - by Akemi Iwaya
    If you open up Task Manager or Process Explorer on your system, you will see many services running. But how much of an impact can a service have on your system, especially if it is ‘corrupted’ by malware? Today’s SuperUser Q&A post has the answers to a curious reader’s questions. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-driven grouping of Q&A web sites. The Question SuperUser reader Forivin wants to know how much impact a service can have on a Windows system, especially if it is ‘corrupted’ by malware: What kind malware/spyware could someone put into a service that does not have its own process on Windows? I mean services that use svchost.exe for example, like this: Could a service spy on my keyboard input? Take screenshots? Send and/or receive data over the internet? Infect other processes or files? Delete files? Kill processes? How much impact could a service have on a Windows installation? Are there any limits to what a malware ‘corrupted’ service could do? The Answer SuperUser contributor Keltari has the answer for us: What is a service? A service is an application, no more, no less. The advantage is that a service can run without a user session. This allows things like databases, backups, the ability to login, etc. to run when needed and without a user logged in. What is svchost? According to Microsoft: “svchost.exe is a generic host process name for services that run from dynamic-link libraries”. Could we have that in English please? Some time ago, Microsoft started moving all of the functionality from internal Windows services into .dll files instead of .exe files. From a programming perspective, this makes more sense for reusability…but the problem is that you can not launch a .dll file directly from Windows, it has to be loaded up from a running executable (exe). Thus the svchost.exe process was born. So, essentially a service which uses svchost is just calling a .dll and can do pretty much anything with the right credentials and/or permissions. If I remember correctly, there are viruses and other malware that do hide behind the svchost process, or name the executable svchost.exe to avoid detection. Have something to add to the explanation? Sound off in the comments. Want to read more answers from other tech-savvy Stack Exchange users? Check out the full discussion thread here.

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  • What Exactly Does the Wattage Rating on a Power Supply Unit Mean?

    - by Jason Fitzpatrick
    Your PSU is rated 80 Plus Bronze and for 650 watts, but what exactly does that mean? Read on to see how wattage and power efficiency ratings translate to real world use. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-drive grouping of Q&A web sites. How To Use USB Drives With the Nexus 7 and Other Android Devices Why Does 64-Bit Windows Need a Separate “Program Files (x86)” Folder? Why Your Android Phone Isn’t Getting Operating System Updates and What You Can Do About It

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  • how do I know when/where to invoke the overridden method of the super class

    - by Henry
    Hi, This question occured to me while programming a Android application, but it seems to be a general programming question more. The situation is, I am extending (subclass-ing) an class from a library, and overriding a method. how do I know if I should invoke the method of super-class? and when? (in the beginning of the overridden method or in the end?) For example, I am overriding the method "public boolean onCreateOptionsMenu(Menu menu)" from class "Activity" in Android platform. And I saw someone write "return super.onCreateOptionsMenu(menu)" in the end of the method, in an example. But how do I know it should be done this way? and it is correct or not? what's the difference if I begin my method with "super.onCreateOptionsMenu(menu)"? BR, Henry

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  • Ruby/RoR: calling original method via super()?

    - by fearless_fool
    In a RoR app, I want to specialize ActiveRecord's update_attributes() method in one of my models, extracting some of the attributes for special handling and passing the rest of them to the original update_attributes() method. The details: class Premise < ActiveRecord::Base ... def update_attributes(attrs) attrs.each_pair do |key, val| unless has_attribute?(key) do_special_processing(key, val) attrs.delete(key) end end # use original update_attributes() to process non-special pairs super.update_attributes(attrs) end ... end The call to super.update_attributes(attr) raises an error: undefined method `update_attributes' for true:TrueClass ... which makes me suspect I really don't understand the super keyword in Ruby. What am I missing? Specifically, how do I call the original update_attributes() method?

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  • Java - Syntax Question: What is <? super T>

    - by aloh
    I'm having trouble understanding the following syntax: public class SortedList< T extends Comparable< ? super T> > extends LinkedList< T > I see that class SortedList extends LinkedList. I just don't know what T extends Comparable< ? super T> means. My understanding of it so far is that type T must be a type that implements Comparable...but what is "< ? super T "?

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  • [super init] and loading NIB / XIB files?

    - by fuzzygoat
    I am a little curious, I have a view controller class and an NIB/XIB (both are named "MapViewController") If I do the following it loads the NIB with the matching name. -(id)init { self = [super initWithNibName:@"MapViewController" bundle:nil]; if(self) { do things ... } return self; } if on the other hand I just specify [super init] does Xcode just look for a NIB that matches the name of the controller, is that how this is working? -(id)init { self = [super init]; if(self) { do things ... } return self; } cheers Gary.

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  • if (self = [super init]) vs. if ((self = [super init]))

    - by JOM
    Was just doing a code review and started to wonder: I thought if (self = [super init]) checks whether assigning return value of [super init] to variable self was successful or not (value of operation). Thus (self = nil) would actually be TRUE. I thought if ((self = [super init])) checks what is the value of self after assignment (value of variable). Thus ((self = nil)) would be FALSE. Which one is the correct way to use when initializing your own classes? Apple documentation uses the former one (for example here), which style I'm actually using now.

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  • Update RDS db via mysqlbinlog: "you need (at least one of) the SUPER privilege(s)"

    - by timoxley
    We are moving a production site to EC2/RDS Followed these instructions: http://geehwan.posterous.com/moving-a-production-mysql-database-to-amazon I have set up row-based binary logging on the production server did a: mysqldump --single-transaction --master-data=2 -C -q -u root -p backup.sql then imported to RDS instance. No dramas. Due to the size of the db, and minimal downtime requirements, I've got to update the ec2 db to the latest datas via the binlogs, and it won't let me. mysqlbinlog mysql-bin.000004 --start-position=360812488 | mysql -uroot -p -h and it says: ERROR 1227 (42000) at line 6: Access denied; you need (at least one of) the SUPER privilege(s) for this operation My guess, based on what is on line 6 of the binlog, is that it's the 'write to the BINLOG' statements in the SQL backup, and because RDS doesn't support this, it can't run these statements, or something, I don't really know. Please help.

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  • Create a super user in MySQL 5.5 not working: Permission denied for root@localhost

    - by GHarping
    Using CentOS 6, logged in to MySQL as root, entering the command: create user 'user123' identified by 'pass123'; works fine. But when I try and give that user super user privileges with: grant all on *.* to 'user123' identified by 'pass123'; I get the error: ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES) Then select * from mysql.user; shows that root has Y in all columns, so should have all privileges. I'd be very grateful if anyone could help me find why root is unable to grant privileges as I can't see why it wouldn't be working. Thanks

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  • When overriding initWithCoder is it always necessary to call [super initWithCoder: coder]

    - by Evan
    In this code I am loading a View Controller (and associated View) from a .xib: -(id)initWithCoder:(NSCoder *)coder { [super initWithCoder:coder]; return self; } This successfully works, but I do not really understand what the line [super initWithCoder:coder] is accomplishing. Is that initializing my View Controller after my View has been initialized? Please be as explicit as possible when explaining. Thanks.

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  • super function doesn't work inside a maya python module

    - by sfjedi
    Somehow, this works fine in the Maya/Python script editor, but fails when it's inside of my module code. Anyone have any ideas? class ControlShape(object): def __init__(self, *args, **kwargs): print 'Inside ControlShape...' class Cross(ControlShape): def __init__(self, *args, **kwargs): print 'Entering Cross...' super(Cross, self).__init__(*args, **kwargs) print 'Leaving Cross...' x = Cross() This gives me a TypeError: super(type, obj): obj must be an instance or subtype of type.

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  • why Cannot invoke super constructor from enum constructor ?

    - by hilal
    public enum A { A(1); private A(int i){ } private A(){ super(); // compile - error // Cannot invoke super constructor from enum constructor A() } } and here is the hierarchy of enum A extends from abstract java.lang.Enum extends java.lang.Object Class c = Class.forName("/*path*/.A"); System.out.println(c.getSuperclass().getName()); System.out.println(Modifier.toString(c.getSuperclass().getModifiers()).contains("abstract")); System.out.println(c.getSuperclass().getSuperclass().getName());

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  • Python, invoke super constructor

    - by Mike
    class A: def __init__(self): print "world" class B(A): def __init__(self): print "hello" B() hello In all other languages I've worked with the super constructor is invoked implicitly. How does one invoke it in Python? I would expect super(self) but this doesn't work

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  • Calling super()

    - by Mike
    When do you call super() in Java? I see it in some constructors of the derived class, but isn't the constructors for each of the parent class called automatically? Why would you need to use super?

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  • Java inheritance and super() isn't working as expected

    - by dwwilson66
    For a homework assignment, I'm working with the following. It's an assigned class structure, I know it's not the best design by a long shot. Class | Extends | Variables -------------------------------------------------------- Person | None | firstName, lastName, streetAddress, zipCode, phone CollegeEmployee | Person | ssn, salary,deptName Faculty | CollegeEmployee | tenure(boolean) Student | person | GPA,major So in the Faculty class... public class Faculty extends CollegeEmployee { protected String booleanFlag; protected boolean tenured; public Faculty(String firstName, String lastName, String streetAddress, String zipCode, String phoneNumber,String ssn, String department,double salary) { super(firstName,lastName,streetAddress,zipCode,phoneNumber, ssn,department,salary); String booleanFlag = JOptionPane.showInputDialog (null, "Tenured (Y/N)?"); if(booleanFlag.equals("Y")) tenured = true; else tenured = false; } } It was my understanding that super() in Faculty would allow access to the variables in CollegeEmployee as well as Person. With the code above, it compiles fine when I ONLY include the Person variables. As soon as I try to use ssn, department, or salary I get the following compile errors. Faculty.java:15: error: constructor CollegeEmployee in class CollegeEmployee can not be applied to the given types: super(firstName,lastName,streetAddress,zipCode,phoneNumber,ssn,department,salary); ^ Required: String,String,String,String,String Found: String,String,String,String,String,String,String,String reason: actual and formal argument lists differ in length I'm completely confused by this error...which is the actual and formal? Person has five arguments, CollegeEmployee has 3, so my guess is that something's funky with how the parameters are being passed...but I'm not quite sure where to begin fixing it. What am I missing?

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  • How to create water like in new super mario bros?

    - by user1103457
    I assume the water in New super mario bros works the same as in the first part of this tutorial: http://gamedev.tutsplus.com/tutorials/implementation/make-a-splash-with-2d-water-effects/ But in new super mario bros the water also has constant waves on the surface, and the splashes look very different. What's also a difference is that in the tutorial, if you create a splash, it first creates a deep "hole" in the water at the origin of the splash. In new super mario bros this hole is absent or much smaller. When I refer to the splashes in new super mario bros I am referring to the splashes that the player creates when jumping in and out of the water. For reference you could use this video: http://www.ign.com/videos/2012/11/17/new-super-mario-bros-u-3-star-coin-walkthrough-sparkling-waters-1-waterspout-beach just after 00:50, when the camera isn't moving you can get a good look at the water and the constant waves. there are also some good examples of the splashes during that time. How do they create the constant waves and the splashes? I am programming in XNA. (I have tried this myself but couldn't really get it all to work well together) (and as bonus questions: how do they create the light spots just under the surface of the waves, and how do they texture the deeper parts of the water? This is the first time I try to create water like this.)

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  • Can I change Synapse shortcut to Super/Windows key alone?

    - by Capt.Nemo
    When I'm trying to edit synapse config, it does not allow me to use Super_L as a direct shortcut for invoking it. Is there a round-about way that I can go through. When I just press the Windows/Super key, the configuration window does not acknowledge it. However, a combination shortcut (such as Super+a) do work fine. Since I'm using Precise, with unity, I'd also need a way to change the default dash behavior from Windows/Super key to something else.

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  • Error: Can't find common super class of ...

    - by PatlaDJ
    I am trying to process with Proguard a MS Windows desktop application (Java 6 SE using the SWT lib provided by Eclipse). And I get the following critical error: Unexpected error while performing partial evaluation: Class = [org/eclipse/swt/widgets/DateTime] Method = [<init>(Lorg/eclipse/swt/widgets/Composite;I)V] Exception = [java.lang.IllegalArgumentException] (Can't find common super class of [java/lang/StringBuffer] and [org/eclipse/swt/internal/win32/TCHAR]) Error: Can't find common super class of [java/lang/StringBuffer] and [org/eclipse/swt/internal/win32/TCHAR] ---------------------------- When I tried to Google the error, it came out only on two spots on the entire web, that astonished me greatly. I am newbie using Proguard and Java code optimization tools at all. Any thoughts and suggestions how to fix this, will be appreciated. Thanks in advance.

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  • groovy call private method in Java super class

    - by Jeff Storey
    I have an abstract Java class MyAbstractClass with a private method. There is a concrete implementation MyConcreteClass. public class MyAbstractClass { private void somePrivateMethod(); } public class MyConcreteClass extends MyAbstractClass { // implementation details } In my groovy test class I have class MyAbstractClassTest { void myTestMethod() { MyAbstractClass mac = new MyConcreteClass() mac.somePrivateMethod() } } I get an error that there is no such method signature for somePrivateMethod. I know groovy can call private methods but I'm guessing the problem is that the private method is in the super class, not MyConcreteClass. Is there a way to invoke a private method in the super class like this (other than using something like PrivateAccessor)? thanks Jeff

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