Search Results

Search found 39406 results on 1577 pages for 'two legged'.

Page 606/1577 | < Previous Page | 602 603 604 605 606 607 608 609 610 611 612 613  | Next Page >

  • How to use a ListView and a ViewFlipper to navigate user in an Android app?

    - by virsir
    I want to set up some menu-like navigator for my app. There is a listView in the main page and it contains two items, click each one will show its child view with ViewFlipper, and if user clicked the back button, he will return to the homepage again. The question is how to make it, I can only use ViewFlipper to flip to next screen or prev screen, how to manage these child views here? How to put them in my layout xml file?

    Read the article

  • Modifying vertex properties in a Boost::Graph

    - by Paul Nathan
    I am trying to figure out how to use boost::graph to store some information. However, there is information I want tied to each vertex. Staring at the documentation for the library reveals either(a)badly written documentation, or (b), I'm obviously not as good at C++ as I thought. Pick two. I am looking for either a tutorial on assigning properties, or a simple example use.

    Read the article

  • android: how to specify multipe listivews

    - by Yang
    It seems that android has enforced that a listview must have the name android:id="@android:id/list", is there anyway to create multiple listview then? I have two activities which are both listview but have to control different format of Lists, one with image+text the other is just text.

    Read the article

  • Segmenting a double array of labels

    - by Ami
    The Problem: I have a large double array populated with various labels. Each element (cell) in the double array contains a set of labels and some elements in the double array may be empty. I need an algorithm to cluster elements in the double array into discrete segments. A segment is defined as a set of pixels that are adjacent within the double array and one label that all those pixels in the segment have in common. (Diagonal adjacency doesn't count and I'm not clustering empty cells). |-------|-------|------| | Jane | Joe | | | Jack | Jane | | |-------|-------|------| | Jane | Jane | | | | Joe | | |-------|-------|------| | | Jack | Jane | | | Joe | | |-------|-------|------| In the above arrangement of labels distributed over nine elements, the largest cluster is the “Jane” cluster occupying the four upper left cells. What I've Considered: I've considered iterating through every label of every cell in the double array and testing to see if the cell-label combination under inspection can be associated with a preexisting segment. If the element under inspection cannot be associated with a preexisting segment it becomes the first member of a new segment. If the label/cell combination can be associated with a preexisting segment it associates. Of course, to make this method reasonable I'd have to implement an elaborate hashing system. I'd have to keep track of all the cell-label combinations that stand adjacent to preexisting segments and are in the path of the incrementing indices that are iterating through the double array. This hash method would avoid having to iterate through every pixel in every preexisting segment to find an adjacency. Why I Don't Like it: As is, the above algorithm doesn't take into consideration the case where an element in the double array can be associated with two unique segments, one in the horizontal direction and one in the vertical direction. To handle these cases properly, I would need to implement a test for this specific case and then implement a method that will both associate the element under inspection with a segment and then concatenate the two adjacent identical segments. On the whole, this method and the intricate hashing system that it would require feels very inelegant. Additionally, I really only care about finding the large segments in the double array and I'm much more concerned with the speed of this algorithm than with the accuracy of the segmentation, so I'm looking for a better way. I assume there is some stochastic method for doing this that I haven't thought of. Any suggestions?

    Read the article

  • Binding class to ListView

    - by Neir0
    Hi, I have a class public class Foo { public List<string> list1 { get; set;} public List<string> list2 { get; set; } public string url; } and a ListView with two columns How i can to bind instance of Foo class to ListView?

    Read the article

  • Having trouble with a small example from school

    - by Kalec
    The example is from a course, it's for comparing two objects in java: public class Complex { ... public boolean equals (Object obj) { if (obj instanceof Complex) { // if obj is "Complex" (complex number) Complex c = (Complex) obj // No idea return (real == c.real) && (imag == c.imag); // I'm guessing real means [this].real } return false; } } So, my question is: "what does this: Complex c = (Complex) obj actually mean" ? Also I've worked with python and c++, java is new for me.

    Read the article

  • How can I determine a file extension given a file path in LaTeX?

    - by Frank
    I am attempting to write a LaTeX package which leverages the minted package's \inputminted command. My \mycommand command takes two parameters, the first being a path to a file, and I want to pass the file's extension to the \inputminted command: \newcommand\mycommand[2]{ \inputminted{#1}{...} } Note that the above won't work since the full path is passed to \inputminted. Example: \mycommand{/path/to/Test.java}{blah} should invoke \inputminted{java}{...}

    Read the article

  • Brute force a website

    - by bigbrute
    Hi, there's a website i visit that always has these code giveaways where you get a prize for cracking the code. The code is in a format like this: QBYQC-Y??T3-W7G4R-QP4HG-2WQPT and they'll give you a hint such as two letters or a number and a letter. The solution to this is easy, brute-forcing it. However, I need the software that will make my browser repeatedly enter a new combination. What software can I use on Mac (and if not, Windows)?

    Read the article

  • What stereotypes about developers are there?

    - by lkessler
    I was filling out a Delphi Developer Survey and two questions were asking about developer stereotypes: Which stereotype about developers do you think is most true? Which stereotype about developers do you think is least true? That was a hard one for me to answer. I couldn't even think of very many developer stereotypes to choose from. What do you think are the most common ones?

    Read the article

  • How to generate a unified diff in Ruby?

    - by jstayton
    After reading through this question about Ruby diff packages, I'm still not sure how to generate a unified diff from two text files. I'm not having trouble reading each file into a string (IO.read()), but I'm not finding any package that can generate a unified diff. Does one exist? Is doing a system call to diff even an option I should consider? (I'm thinking no.) Any help is appreciated! Thanks.

    Read the article

  • Silverlight with MVVM Inheritance: ModelView and View matching the Model

    - by moonground.de
    Hello Stackoverflowers! :) Today I have a special question on Silverlight (4 RC) MVVM and inheritance concepts and looking for a best practice solution... I think that i understand the basic idea and concepts behind MVVM. My Model doesn't know anything about the ViewModel as the ViewModel itself doesn't know about the View. The ViewModel knows the Model and the Views know the ViewModels. Imagine the following basic (example) scenario (I'm trying to keep anything short and simple): My Model contains a ProductBase class with a few basic properties, a SimpleProduct : ProductBase adding a few more Properties and ExtendedProduct : ProductBase adding another properties. According to this Model I have several ViewModels, most essential SimpleProductViewModel : ViewModelBase and ExtendedProductViewModel : ViewModelBase. Last but not least, according Views SimpleProductView and ExtendedProductView. In future, I might add many product types (and matching Views + VMs). 1. How do i know which ViewModel to create when receiving a Model collection? After calling my data provider method, it will finally end up having a List<ProductBase>. It containts, for example, one SimpleProduct and two ExtendedProducts. How can I transform the results to an ObservableCollection<ViewModelBase> having the proper ViewModel types (one SimpleProductViewModel and two ExtendedProductViewModels) in it? I might check for Model type and construct the ViewModel accordingly, i.e. foreach(ProductBase currentProductBase in resultList) if (currentProductBase is SimpleProduct) viewModels.Add( new SimpleProductViewModel((SimpleProduct)currentProductBase)); else if (currentProductBase is ExtendedProduct) viewModels.Add( new ExtendedProductViewModels((ExtendedProduct)currentProductBase)); ... } ...but I consider this very bad practice as this code doesn't follow the object oriented design. The other way round, providing abstract Factory methods would reduce the code to: foreach(ProductBase currentProductBase in resultList) viewModels.Add(currentProductBase.CreateViewModel()) and would be perfectly extensible but since the Model doesn't know the ViewModels, that's not possible. I might bring interfaces into game here, but I haven't seen such approach proven yet. 2. How do i know which View to display when selecting a ViewModel? This is pretty the same problem, but on a higher level. Ended up finally having the desired ObservableCollection<ViewModelBase> collection would require the main view to choose a matching View for the ViewModel. In WPF, there is a DataTemplate concept which can supply a View upon a defined DataType. Unfortunately, this doesn't work in Silverlight and the only replacement I've found was the ResourceSelector of the SLExtensions toolkit which is buggy and not satisfying. Beside that, all problems from Question 1 apply as well. Do you have some hints or even a solution for the problems I describe, which you hopefully can understand from my explanation? Thank you in advance! Thomas

    Read the article

  • Select between dates with wildcard mysql

    - by Michael
    Hi, I am trying to select between two dates, but in the table they have timestamps after them. Example: calldate is 2010-03-16 22:43:28 How would I select this using calldate between '$date1' AND '$date2' to wildcard the timestamp after the date? I tried using like but it didn't work I just want to do between '$date1%' AND '$date2%' Anyone know how to do this? Thank you in advance!

    Read the article

  • jQuery click(): overriding previously-bound click events

    - by JamesBrownIsDead
    When I use this code with an element whose id is "foobar": $("#foobar").click(function () { alert("first"); }); $("#foobar").click(function () { alert("second"); }); I get two alerts: "first" and "second" second. How do I specify a click event that also clears out any previous click events attached to the element? I want the last $("#foobar").click(...) to erase any previously bound events.

    Read the article

  • TicTacToe AI Making Incorrect Decisions

    - by Chris Douglass
    A little background: as a way to learn multinode trees in C++, I decided to generate all possible TicTacToe boards and store them in a tree such that the branch beginning at a node are all boards that can follow from that node, and the children of a node are boards that follow in one move. After that, I thought it would be fun to write an AI to play TicTacToe using that tree as a decision tree. TTT is a solvable problem where a perfect player will never lose, so it seemed an easy AI to code for my first time trying an AI. Now when I first implemented the AI, I went back and added two fields to each node upon generation: the # of times X will win & the # of times O will win in all children below that node. I figured the best solution was to simply have my AI on each move choose and go down the subtree where it wins the most times. Then I discovered that while it plays perfect most of the time, I found ways where I could beat it. It wasn't a problem with my code, simply a problem with the way I had the AI choose it's path. Then I decided to have it choose the tree with either the maximum wins for the computer or the maximum losses for the human, whichever was more. This made it perform BETTER, but still not perfect. I could still beat it. So I have two ideas and I'm hoping for input on which is better: 1) Instead of maximizing the wins or losses, instead I could assign values of 1 for a win, 0 for a draw, and -1 for a loss. Then choosing the tree with the highest value will be the best move because that next node can't be a move that results in a loss. It's an easy change in the board generation, but it retains the same search space and memory usage. Or... 2) During board generation, if there is a board such that either X or O will win in their next move, only the child that prevents that win will be generated. No other child nodes will be considered, and then generation will proceed as normal after that. It shrinks the size of the tree, but then I have to implement an algorithm to determine if there is a one move win and I think that can only be done in linear time (making board generation a lot slower I think?) Which is better, or is there an even better solution?

    Read the article

  • iPhone SDK reload UIView's content

    - by Matt S.
    I have two views, one view takes the whole screen, the second view covers only a little portion. What I want is for that second view to be on the first view (which I already have done), but the problem is, when I set values (in this case UILabel's) the label on the screen doesn't display that new value. I know for a fact the method gets called, but for some reason it won't change the label's value.

    Read the article

  • How to call Json objects dynamically?

    - by Devyn
    Hi, I have like this var house = {'floor':{'one':'3 people','two':'1 people'}} var tmp = 'one'; and I want to call like this.. console.log(house.floor.tmp) // expecting '3 people' result tmp value will get from somewhere dynamically but it's not working. How can I solve this?

    Read the article

  • What is hi-lo-hi?

    - by HollerTrain
    I have a project in C but have no clue what 'hi-lo-hi' is: The function is to count how many occurrences of hi – lo – hi in an array. For example, given the target array of 0 7 4 3 5 2 1 6, there are two occurrences. So the function would return the value of 2. Any help would be greatly appreciated.

    Read the article

  • Multiple accordion panes open

    - by Kevin
    We are using a jquery accordion on our site : http://www.racedayworld.com It basically lists events under each month... Apparently people are finding difficulties knowing how it really works and they don't see at first glance that there are more events under each month (that you click to expand) So I was thinking about opening two at a time (the current month and the next) .. but I'm not sure how to enable both to be open at once ... any ideas?

    Read the article

< Previous Page | 602 603 604 605 606 607 608 609 610 611 612 613  | Next Page >