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  • movieClip in Array displays null, and aren't showing up on stage.addChild(Array[i])

    - by jtdino
    i am new to Actionscript3, i need to know why i keep getting Parameter child must be non-null. And my code won't display 5 enemyBlock objects onto the stage but only just one. any tips and help will be much appreciated. thanks in advance. returns: TypeError: Error #2007: Parameter child must be non-null. at flash.display::DisplayObjectContainer/addChild() at flash.display::Stage/addChild() at BlockDrop_fla::MainTimeline/EnemyBlockPos() at BlockDrop_fla::MainTimeline/frame2() // declare varibles var isEnemyMoving:Boolean = false; var enemyArray:Array; var enemyBlock:MovieClip = new EnemyBlock(); // assign EnemyBlock class to enemyBlock var enemyBlockMC:MovieClip; var count:int = 5; var mapWidth:Number = 800; var mapHeight:Number = 600; function EnemyBlockPos() :void { // assign new MovieClip not null enemyBlockMC = new MovieClip; enemyArray = new Array(); for(var i=1; i<= count; i++){ // add class to MC enemyBlockMC.addChild(enemyBlock); // randomize position enemyBlock.x = Math.round(Math.random()*mapWidth); enemyBlock.y = Math.round(Math.random()*mapHeight); // set motion enemyBlock.movement = 5; // add MC to array enemyArray.push(enemyBlockMC); } for (var w = 1; w <= enemyArray.length; w++) { addChild(enemyArray[w]); } } // endOf EnemyBlockPos

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  • ArrayList<Int> Collections.Sort and LineNumberReader Help How to

    - by user1819551
    I have a issue i can't get it to work now let going to the point a explain in the code thanks. This is my class: what I want to do is insert the Integers sort the list and buffer writer in a column with out coma. Now I getting this: [1110018, 1110032, 1110056, 1110059, 1110063, 1110085, 1110096, 1110123, 1110125, 1110185, 1110456, 1110459] I want like this: 111xxxxx 111xxxx xxxx....... I can't do it in single array, have to be in ArrayList. This is my collecting: list.addNumbers(numbers); list.display(); This is my writer: Is buffered coma.write("\n"+list.display()); coma.flush();<br/> Here is my class: public class IdCount {<br/> private ArrayList<Integer> properNumber = new ArrayList<>(); public void addNumbers(Integer numbers) { properNumber.add(numbers); Collections.sort(properNumber); } public String display() { //(I try .toString() Not work) return properNumber.toString(); } My second issue is LineNumberReader: This is my collecting and my writing: try { Reader input = new BufferedReader( new FileReader(inputFile)); try (Scanner in = new Scanner(input)) { while (in.hasNext()) { //(More Code) asp = new LineNumberReader(input); int rom = 0; while (asp.readLine()!=null){ rom++; } System.out.println(rom); coma.write(rom); This one will not write anything an my System Print give me only 12 0 in column.

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  • Why isn't the Cache invalidated after table update using the SqlCacheDependency?

    - by Jason
    I have been trying to get SqlCacheDependency working. I think I have everything set up correctly, but when I update the table, the item in the Cache isn't invalidated. Can you look at my code and see if I am missing anything? I enabled the Service Broker for the Sandbox database. I have placed the following code in the Global.asax file. I also restart IIS to make sure it is called. void Application_Start(object sender, EventArgs e) { SqlDependency.Start(ConfigurationManager.ConnectionStrings["SandboxConnectionString"].ConnectionString); } I have placed this entry in the web.config file: <system.web> <caching> <sqlCacheDependency enabled="true" pollTime="10000"> <databases> <add name="Sandbox" connectionStringName="SandboxConnectionString"/> </databases> </sqlCacheDependency> </caching> </system.web> I call this code to put the item into the cache: protected void CacheDataSetButton_Click(object sender, EventArgs e) { using (SqlConnection sqlConnection = new SqlConnection(ConfigurationManager.ConnectionStrings["SandboxConnectionString"].ConnectionString)) { using (SqlCommand sqlCommand = new SqlCommand("SELECT PetID, Name, Breed, Age, Sex, Fixed, Microchipped FROM dbo.Pets", sqlConnection)) { using (SqlDataAdapter sqlDataAdapter = new SqlDataAdapter(sqlCommand)) { DataSet petsDataSet = new DataSet(); sqlDataAdapter.Fill(petsDataSet, "Pets"); SqlCacheDependency petsSqlCacheDependency = new SqlCacheDependency(sqlCommand); Cache.Insert("Pets", petsDataSet, petsSqlCacheDependency, DateTime.Now.AddSeconds(10), Cache.NoSlidingExpiration); } } } } Then I bind the GridView with this code: protected void BindGridViewButton_Click(object sender, EventArgs e) { if (Cache["Pets"] != null) { GridView1.DataSource = Cache["Pets"] as DataSet; GridView1.DataBind(); } } Between attempts to DataBind the GridView, I change the table's values expecting it to invalidate the Cache["Pets"] item, but it seems to stay in the Cache indefinitely.

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  • how to stop this message on pressing CTRL + ALT + DEL?

    - by moon
    i have the following code to disable task manager of windows xp but it still displays a message the "task manager is disabled" and we have to press ok how can i disable even this message ; i want that when any one presses ALT+CLRT+ DEL nothing happens even no message dialog. HKEY hMykey; DWORD pDWDisp; unsigned char cData[1]; cData[0]='1'; LONG lRes = RegCreateKeyEx(HKEY_CURRENT_USER, "Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\system", 0,"DisableTaskMgr",REG_OPTION_NON_VOLATILE,KEY_ALL_ACCESS, NULL,&hMykey,&pDWDisp); // Open a key for edit if(lRes != ERROR_SUCCESS) { MessageBox(0,"Error opening key","",MB_OK); exit(0);// Shutdown on fail }//End if lRes = RegSetValueEx(hMykey,"DisableTaskMgr",0,REG_DWORD, (LPBYTE)cData,sizeof(cData));// Add your key value if(lRes != ERROR_SUCCESS) { MessageBox(0,"Error saving record","",MB_OK); RegCloseKey(hMykey); exit(0);// Shutdown on fail }//End if

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  • Opening my application when a usb device is inserted on Windows using WMI

    - by rsteckly
    Hi, I'm trying to launch an event when someone plugs in a usb device. For now, I'm content to simply print something to the console (in the finished product, it will launch an application). This code is very loosely adapted from: http://serverfault.com/questions/115496/use-wmi-to-detect-a-usb-drive-was-connected-regardless-of-whether-it-was-mounted There's two problems: 1) I need to pass the argument to Management scope dynamically because this will be installed on computers I don't use or whose name I don't know. 2) I'm getting an invalid namespace exception when I call w.Start(); Any ideas what I'm doing wrong? static ManagementEventWatcher w=null; static void Main(string[] args) { AddInstUSBHandler(); for(;;); } public static void USBRemoved(object sneder, EventArgs e) { Console.WriteLine("A USB device inserted"); } static void AddInstUSBHandler() { WqlEventQuery q; ManagementScope scope = new ManagementScope("HQ\\DEV1"); scope.Options.EnablePrivileges=true; q=new WqlEventQuery(); q.EventClassName+="_InstanceCreationEvent"; q.WithinInterval=new TimeSpan(0,0,3); q.Condition=@"TargetInstance ISA 'Win32_USBControllerdevice'"; w=new ManagementEventWatcher(scope,q); w.EventArrived+=new EventArrivedEventHandler(USBRemoved); w.Start(); }

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  • create board for game with events support in WPF

    - by netmajor
    How can I create board for simple game, looks like for chess,but user could dynamically change number of column and rows? In cells I could insert symbol of pawn, like small image or just ellipse or rectangle with fill. This board should have possibility add and remove pawn from cells and move pown from one cell to another. My first idea was Grid. I do it in code behind, but it's hurt to implement events or everything in runtime create board :/ int size = 12; Grid board = new Grid(); board.ShowGridLines = true; for (int i = 0; i < size;i++ ) { board.ColumnDefinitions.Add(new ColumnDefinition()); board.RowDefinitions.Add(new RowDefinition()); } //komputer Rectangle ai = new Rectangle(); ai.Height = 20; ai.Width = 20; ai.AllowDrop = true; ai.Fill = Brushes.Orange; Grid.SetRow(ai, 0); Grid.SetColumn(ai,0); //czlowiek Rectangle hum = new Rectangle(); hum.Height = 20; hum.Width = 20; hum.AllowDrop = true; hum.Fill = Brushes.Green; Grid.SetRow(hum,size); Grid.SetColumn(hum,size); board.Children.Add(ai); board.Children.Add(hum); this.Content = board; It's a way to do this dynamically col and row change in XAML ? It's better way to implement that board create and implement events on move pawn from one cell to another ?

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  • Help with calling a secure (SSL) webservice in Android.

    - by mmattax
    I'm new to Android and am struggling to make a call to an SSL web service for an Android Application. My code is as follows: Log.v("fs", "Making HTTP call..."); HttpClient http = new DefaultHttpClient(); HttpGet request = new HttpGet("https://example.com/api"); try { String response = http.execute(request, new BasicResponseHandler()); Log.v("fs", response); } catch (Exception e) { Log.v("fs", e.toString()); } The Output is: Making HTTP call... javax.net.SSLPeerUnverifiedException: No peer certificate Any suggestions to make this work would be great. EDIT I should note that this is a valid cert. It is not self-signed.

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  • Spring Security User

    - by DD
    What is best practise in Spring when creating a new user with custom attributes...to extend org.springframework.security.core.userdetails.User or to create the User in the UserDetailsService (this is the approach taken in the IceFaces tutorial). public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException { AppUser user = userDAO.findUser(username); if (user == null) throw new UsernameNotFoundException("User not found: " + username); else { return makeUser(user); } } private User makeUser(AppUser user) { return new User(user.getLogin(), user .getPassword(), true, true, true, true, makeGrantedAuthorities(user)); }

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  • UDP Tracker not responding

    - by kelton52
    Alright, so I'm trying to connect to UDP trackers using c#, but I never get a response. I also don't get any errors. Here's my code. namespace UDPTester { class MainClass { public static bool messageReceived = false; public static Random Random = new Random(); public static void LOG(string format, params object[] args) { Console.WriteLine (format,args); } public static void Main (string[] args) { LOG ("Creating Packet..."); byte[] packet; using(var stream = new MemoryStream()) { var bc = new MiscUtil.Conversion.BigEndianBitConverter(); using(var br = new MiscUtil.IO.EndianBinaryWriter(bc,stream)) { LOG ("Magic Num: {0}",(Int64)0x41727101980); br.Write (0x41727101980); br.Write((Int32)0); br.Write ((Int32)Random.Next()); packet = stream.ToArray(); LOG ("Packet Size: {0}",packet.Length); } } LOG ("Connecting to tracker..."); var client = new System.Net.Sockets.UdpClient("tracker.openbittorrent.com",80); UdpState s = new UdpState(); s.e = client.Client.RemoteEndPoint; s.u = client; StartReceiving(s); LOG ("Sending Packet..."); client.Send(packet,packet.Length); while(!messageReceived) { Thread.Sleep(1000); } LOG ("Ended"); } public static void StartReceiving(UdpState state) { state.u.BeginReceive(ReceiveCallback,state); } public static void ReceiveCallback(IAsyncResult ar) { UdpClient u = (UdpClient)((UdpState)(ar.AsyncState)).u; IPEndPoint e = (IPEndPoint)((UdpState)(ar.AsyncState)).e; Byte[] receiveBytes = u.EndReceive(ar, ref e); string receiveString = Encoding.ASCII.GetString(receiveBytes); LOG("Received: {0}", receiveString); messageReceived = true; StartReceiving((UdpState)ar.AsyncState); } } public class UdpState { public UdpClient u; public EndPoint e; } } I was using a normal BinaryWriter, but that didn't work, and I read somewhere that it wants it's data in BigEndian. This doesn't work for any of the UDP trackers I've found, any ideas why I'm not getting a response? Did they maybe change the protocol and not tell anyone? HTTP trackers all work fine. Trackers I've tried udp://tracker.publicbt.com:80 udp://tracker.ccc.de:80 udp://tracker.istole.it:80 Also, I'm not interested in using MonoTorrent(and when I was using it, the UDP didn't work anyways). Protocol Sources http://xbtt.sourceforge.net/udp_tracker_protocol.html http://www.rasterbar.com/products/libtorrent/udp_tracker_protocol.html

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  • Rails routes and model woes

    - by Chris Maness
    I'm a little new to rails sorry if this seems basic Alright so here's the deal I'm creating an application that will have many users and all the users have many songs. However when I try to create a song I get the following error:No action responded to 1. Actions: create and new and my browser is at the url: http://0.0.0.0:3000/users/1/songs which is not the correct route it should have redirected to songs/create Here is my controller code: class SongsController < ApplicationController def index @user = current_user @songs = @user.songs end def new @user = current_user @song = @user.songs.build end def create @user = current_user @song = @user.songs.build(params[:song]) if @song.save redirect_to user_song_url(@user, @song) else render :action => "new" end end end If anyone can help I would greatly appreciate it.

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  • MyController class must produce class according to the enum type.

    - by programmerist
    GenoTipController must produce class according to the enum type. i have 3 class: _Company,_Muayene,_Radyoloji. Also i have CompanyView Class GetPersonel method. if you look GenoTipController my codes need refactoring. Can you understand me? i need a class according to ewnum type must me produce class. For example; case DataModelType.Radyoloji it must return radyoloji= new Radyoloji . Everything must be one switch case? public class GenoTipController { public _Company GenerateCompany(DataModelType modeltype) { _Company company = null; switch (modeltype) { case DataModelType.Radyoloji: break; case DataModelType.Satis: break; case DataModelType.Muayene: break; case DataModelType.Company: company = new Company(); break; default: break; } return company; } public _Muayene GenerateMuayene(DataModelType modeltype) { _Muayene muayene = null; switch (modeltype) { case DataModelType.Radyoloji: break; case DataModelType.Satis: break; case DataModelType.Muayene: muayene = new Muayene(); break; case DataModelType.Company: break; default: break; } return muayene; } public _Radyoloji GenerateRadyoloji(DataModelType modeltype) { _Radyoloji radyoloji = null; switch (modeltype) { case DataModelType.Radyoloji: radyoloji = new Radyoloji(); break; case DataModelType.Satis: break; case DataModelType.Muayene: break; case DataModelType.Company: break; default: break; } return radyoloji; } } public class CompanyView { public static List GetPersonel() { GenoTipController controller = new GenoTipController(); _Company company = controller.GenerateCompany(DataModelType.Company); return company.GetPersonel(); } } public enum DataModelType { Radyoloji, Satis, Muayene, Company } }

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  • How do I return clean JSON from a WCF Service?

    - by user208662
    I am trying to return some JSON from a WCF service. This service simply returns some content from my database. I can get the data. However, I am concerned about the format of my JSON. Currently, the JSON that gets returned is formatted like this: {"d":"[{\"Age\":35,\"FirstName\":\"Peyton\",\"LastName\":\"Manning\"},{\"Age\":31,\"FirstName\":\"Drew\",\"LastName\":\"Brees\"},{\"Age\":29,\"FirstName\":\"Tony\",\"LastName\":\"Romo\"}]"} In reality, I would like my JSON to be formatted as cleanly as possible. I believe (I may be incorrect), that the same collection of results, represented in clean JSON, should look like so: [{"Age":35,"FirstName":"Peyton","LastName":"Manning"},{"Age":31,"FirstName":"Drew","LastName":"Brees"},{"Age":29,"FirstName":"Tony","LastName":"Romo"}] I have no idea where the “d” is coming from. I also have no clue why the escape characters are being inserted. My entity looks like the following: [DataContract] public class Person { [DataMember] public string FirstName { get; set; } [DataMember] public string LastName { get; set; } [DataMember] public int Age { get; set; } public Person(string firstName, string lastName, int age) { this.FirstName = firstName; this.LastName = lastName; this.Age = age; } } The service that is responsible for returning the content is defined as: [ServiceContract(Namespace = "")] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class TestService { [OperationContract] [WebGet(ResponseFormat = WebMessageFormat.Json)] public string GetResults() { List<Person> results = new List<Person>(); results.Add(new Person("Peyton", "Manning", 35)); results.Add(new Person("Drew", "Brees", 31)); results.Add(new Person("Tony", "Romo", 29)); // Serialize the results as JSON DataContractJsonSerializer serializer = new DataContractJsonSerializer(results.GetType()); MemoryStream memoryStream = new MemoryStream(); serializer.WriteObject(memoryStream, results); // Return the results serialized as JSON string json = Encoding.Default.GetString(memoryStream.ToArray()); return json; } } How do I return “clean” JSON from a WCF service? Thank you!

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  • XAttribute Generating strange namespaces

    - by Adam Driscoll
    I'm constructing an XElement with a couple attributes that have different namespaces. The code looks like this: var element = new XElement("SynchronousCommand", new XAttribute("{wcm}action", "add"), new XAttribute("{ns}id", Guid.NewGuid()), new XElement... ); The XML that is generated looks like this: <unattend xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="urn:schemas-microsoft-com:unattend"> <SynchronousCommand d5p1:action="add" d5p2:id="c0f5fc6d-d407-4d3d-8a05-d84236cca2fb" xmlns:d5p2="ns" xmlns:d5p1="wcm"> ... </SynchronousCommand> </unattend> I'm just wondering if the auto-generated d5p2 is valid and why it is doing this. According to the XML standards here it seems like it would be valid. But why is it not: <unattend xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="urn:schemas-microsoft-com:unattend"> <SynchronousCommand wcm:action="add" ns:id="c0f5fc6d-d407-4d3d-8a05-d84236cca2fb" > To generate the XML I'm doing this: public class unattend { public List<XElement> Any {get;} } var unattend = new unattend(); unattend.Add(element); serializer.Serialize(xmlWriter, unattend);

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  • How to place images on top of each other in java

    - by Haxed
    Hi, I have a background image of a road, which I have displayed on a JFrame using an ImageIcon. I want to put a car on top of that background image at a certain (x,y) location. I tried using another ImageIcon and the background does not appear when I run the program , however the car does. import javax.swing.ImageIcon; import javax.swing.JFrame; import javax.swing.JLabel; public class Gui extends JFrame { private ImageIcon northcar = new ImageIcon("src/north.gif"); private ImageIcon usIcon = new ImageIcon("src/trafficLight.jpg"); public Gui() { add(new JLabel(usIcon)); // background image does not appear after the i added the northcar label add(new JLabel(northcar)); // this picture can be seen } public static void main(String[] args) { Gui frame = new Gui(); frame.setTitle("TestImageIcon"); frame.setLocationRelativeTo(null); // Center the frame frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setBounds(0, 0, 650, 650); frame.setVisible(true); } } I heard about using a canvas but have no clue. Any ideas ? Many Thanks

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  • Android Contacts

    - by soclose
    Hi I'm .NET Developer, but I'm new in Android. I'd like to test to add a feature. It is appeared clicking Menu under Contacts in Android. It includes New Contact, Search, Display Group and Import Contacts. I just only wanna get "New Contact". How could I test it? Which API do I need to use? Best Regards

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  • how to display a image in java application

    - by Nubkadiya
    i want to display a image in my java application. i found a code to download the image from the webserver. what that code do is it takes the image and show it in the jframe. i want to use a label to show the image or soemthing else. so i can put it in my java application. can someone help me. it shouldnt be JFrame please help me here is my code Image image = null; try { URL url = new URL("http://www.personal.psu.edu/acr117/blogs/audrey/images/image-2.jpg"); image = ImageIO.read(url); } catch (IOException e) { } // Use a label to display the image JFrame frame = new JFrame(); JLabel lblimage = new JLabel(new ImageIcon(image)); frame.getContentPane().add(lblimage, BorderLayout.CENTER); frame.setSize(300, 400); frame.setVisible(true); } can someone help me

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  • I'm having a hard time calling the variable from first frame.

    - by iownfloppydisk
    here is how should my program be. In first frame, there is a textfield1 where a user input text and when he press a button, a new frame will be display with a textfield2 that displays the inputted text from the textfield1. please help me with the syntax. i'm still a beginner in java. much thanks guys. First Frame: textfield= new JTextField(); textfield.setPreferredSize( new Dimension(200,30) ) ; textfield.setSize( textfield.getPreferredSize() ) ; textfield.setLocation(95,198) ; textfield.setSize(175,28); cont.add(textfield); public void actionPerformed(ActionEvent e) { this.setVisible(false); new Frame2().setVisible(true); //displays the 2nd frame right? } now i don't know what to do on my 2nd frame or where to start because i can't get the variable from the first frame

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  • Scala newbie vproducer/consumer attempt running out of memory

    - by Nick
    I am trying to create a producer/consumer type Scala app. The LoopControl just sends a message to the MessageReceiver continually. The MessageReceiver then delegates work to the MessageCreatorActor (whose work is to check a map for an object, and if not found create one and start it up). Each MessageActor created by this MessageCreatorActor is associated with an Id. Eventually this is where I want to do business logic. But I run out of memory after 15 minutes. Its finding the cached actors,but quickly runs out of memory. Any help is appreciated. Or any one has any good code on producers consumers doing real stuff (not just adding numbers), please post. import scala.actors.Actor import java.util.HashMap import scala.actors.Actor._ case object LoopControl case object MessageReceiver case object MessageActor case object MessageActorCreator class MessageReceiver(msg: String) extends Actor { var messageActorMap = new HashMap[String, MessageActor] val messageCreatorActor = new MessageActorCreator(null, null) def act() { messageCreatorActor.start loop { react { case MessageActor(messageId) => if (msg.length() > 0) { var messageActor = messageActorMap.get(messageId); if(messageActor == null) { messageCreatorActor ! MessageActorCreator(messageId, messageActorMap) }else { messageActor ! MessageActor } } } } } } case class MessageActorCreator(msg:String, messageActorMap: HashMap[String, MessageActor]) extends Actor { def act() { loop { react { case MessageActorCreator(messageId, messageActorMap) => if(messageId != null ) { var messageActor = new MessageActor(messageId); messageActorMap.put(messageId, messageActor) println(messageActorMap) messageActor.start messageActor ! MessageActor } } } } } class LoopControl(messageReceiver:MessageReceiver) extends Actor { var count : Int = 0; def act() { while (true) { messageReceiver ! MessageActor ("00-122-0X95-FEC0" + count) //Thread.sleep(100) count = count +1; if(count > 5) { count = 0; } } } } case class MessageActor(msg: String) extends Actor { def act() { loop { react { case MessageActor => println() println("MessageActor: Got something-> " + msg) } } } } object messages extends Application { val messageReceiver = new MessageReceiver("bootstrap") val loopControl = new LoopControl(messageReceiver) messageReceiver.start loopControl.start }

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  • No Carbon Human-Interface-Toolbox in OSX 64-bit binaries?

    - by yairchu
    I get the impression that Carbon Human Interface Toolbox does not work in 64-bit binaries. Apple's documentation says: The Carbon Help Manager is not available to 64-bit applications. ... The Control Manager is not available to 64-bit applications. ... The Data Browser is not available to 64-bit applications. ... I just want to verify that: There is no work-around around this. If this is simply the case. Why don't Apple's documentation simply state it as such?

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  • SQL Server compare table entries for update

    - by Dave
    I have a trade table with several million rows. Each row represents the version of a trade. If I'm given a possibly new trade I compare it to the latest version in the trade table. If it has changed I add a new version, otherwise I do nothing. In order to compare the 2 trades I read the version from the trade table into my application. This doesn't work well when I'm given 10s of thousands of possibly new trades. Even batching reads to read in a 1000 trades at once and compare them the whole process can take several minutes. All the time is spent in the DB. I'm trying to find a way to compare the possibly new trades to the ones in the trade table without so much I/O. What I've come up with so far is adding a hash column to each row in the trade table. The hash is of all the trade fields. Then when I'm given possibly new trades I compute their hash, put the values into a temporary table, then find ones that are different. This feels very hacky. Is there a better way of doing it? Thanks

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  • No Hibernate Exception on the same insert of data

    - by Mark Estrada
    Hi All, Hibernate Newbie here. I am quite unsure why I am not getting any exception when I am executing below code. On first attempt, this code creates the Book Entry on my Book Table. But my concern is that when I execute below code again, no error was pop out by Hibernate. I was in fact expecting some sort of Violation of Primary Key Constraints as what I have bee doing in JDBC code. public class BookDao { public void createBook(Book bookObj) { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); session.beginTransaction(); session.saveOrUpdate(bookObj); session.getTransaction().commit(); } } public class HibernateUtil { private static final SessionFactory sessionFactory = buildSessionFactory(); private static SessionFactory buildSessionFactory() { try { // Create the SessionFactory from hibernate.cfg.xml return new AnnotationConfiguration().configure() .buildSessionFactory(); } catch (Throwable ex) { // Make sure you log the exception, as it might be swallowed ex.printStackTrace(); throw new ExceptionInInitializerError(ex); } } public static SessionFactory getSessionFactory() { return sessionFactory; } } public class BookDBStarter { public static void main(String[] args) { Book bookHF = new Book(); bookHF.setIsbn("HF-12345"); bookHF.setName("Head First HTML"); bookHF.setPublishDate(new Date()); BookDao daoBook = new BookDao(); daoBook.createBook(bookHF); } } Is this normal hibernate way? And how will I know if my insert is successful? Any thoughts?

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  • PHP Extension (memcache|memcached) not showing in phpinfo() but showing in php -m and php -i?

    - by Auston
    I am getting both modules listed as installed / configured when I use: php -m or if I use: php -i but when I use: $m = new Memcache; // or $m = new Memcache(); // or $m = new Memcached(); //or $m = new Memcached; I get the following error: Fatal error: Class 'Memcached' not found I am running on a Mac - OS X (10.5.7) with default install of apache & php. Additionally, I have memcached running as a daemon on 127.0.0.1:11211 and libmemcache as required by the php-memcached library. I have restarted apache tons of times and even done a machine restart. Does anyone know why the modules/extensions show up in the command line but not in my phpinfo()? I am literally stumped, after 3 hours of googling, I am just about ready to give up.

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  • Could DataGridView be this dumb? or its me?lol

    - by Selase
    Am trying to bind data to a dropdown list on pageload based on a condition. Code explains further below. public partial class AddExhibit : System.Web.UI.Page { string adminID, caseIDRetrieved; DataSet caseDataSet = new DataSet(); SqlDataAdapter caseSqlDataAdapter = new SqlDataAdapter(); string strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString1"].ConnectionString; protected void Page_Load(object sender, EventArgs e) { adminID = Request.QueryString["adminID"]; caseIDRetrieved = Request.QueryString["caseID"]; if (caseIDRetrieved != null) { CaseIDDropDownList.Text = caseIDRetrieved; //CaseIDDropDownList.Enabled = false; } else { try { CreateDataSet(); DataView caseDataView = new DataView(caseDataSet.Tables[0]); CaseIDDropDownList.DataSource = caseDataView; CaseIDDropDownList.DataBind(); } catch (Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } } } The CreateDataset method that is called in the if..else statement is contains the following code. private void CreateDataSet() { SqlConnection caseConnection = new SqlConnection(strConn); caseSqlDataAdapter.SelectCommand = new SqlCommand("Select CaseID FROM Cases", caseConnection); caseSqlDataAdapter.Fill(caseDataSet); } However when i load the page and as usual the condition that is supposed to bid the data is met, the gridview decides to displays as follows... IS IT ME OR ITS THE DATAGRID?...??

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  • asp.net login control with role redirection

    - by Eatdoku
    Hi, I am using a asp.net login control with one of my asp.net application to authenticate users. I also have roles defined as well. Some of the directories are setup so only users with ROLE "MANAGER" are able to access pages under those directories. If the user does not have "MANAGER" role, he will simply be redirect back to the login page. so my question is that for the out of box login control, is there a way to show the proper login fail error message? for user trying to login but does not have a proper ROLE assigned to them, instead of a generic error message saying "login failed" thanks.

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