Search Results

Search found 15731 results on 630 pages for 'showplan xml'.

Page 61/630 | < Previous Page | 57 58 59 60 61 62 63 64 65 66 67 68  | Next Page >

  • Can Qt's QWebView display programatically generated XML?

    - by Dan Ellis
    Using Qt 4.6, I can dynamically add to an HTML page like this: ui->webView->page()->mainFrame()->documentElement().findFirst("body").appendInside("<i>some text</i>\n"); However, if I QWebView::load() an XML file, it displays it with the correct CSS styling (from an processing instruction), but doesn't show any changes when I do something like: ui->webView->page()->mainFrame()->documentElement().findFirst("lines").appendInside("<line>hello</line>\n"); Why is it treating them differently, and is there a way to modify an XML document in the same way I can an HTML one?

    Read the article

  • How to remove not required Elements from generated XML via jaxb

    - by Dangling Piyush
    I want to know if there is anyway for removing not required elements from generated xml using jaxb.I have my xsd element definition as follows. <xsd:element name="Title" maxOccurs="1" minOccurs="0"> <xsd:annotation> <xsd:documentation> A name given to the digital record. </xsd:documentation> </xsd:annotation> <xsd:simpleType> <xsd:restriction base="xsd:string"> <xsd:minLength value="1"></xsd:minLength> </xsd:restriction> </xsd:simpleType> </xsd:element> As you can see it is not a mandatory element because minOccurs="0" But if it is not empty the length should be 1. <xsd:minLength value="1"></xsd:minLength> At the time of marshalling if I left the Title field blank it is throwing the SAXException because of min-length restriction. So what I want to do is to remove the whole occurrence of <Title/> from generated XML.Right now i have removed the min-length restriction so it is adding the <Title> element as EMPTY <Title></Title> But I do not want it like this.Any help is appreciated.I am using jaxb 2.0 for Marshalling. UPDATE: Following is my variable definiton : private JAXBContext jaxbContext; private Unmarshaller unmarshaller; private SchemaFactory factory; private Schema schema; private Marshaller marshaller; Marshalling code. jaxbContext = JAXBContext.newInstance(ERecordType.class); marshaller = jaxbContext.createMarshaller(); factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); schema = factory.newSchema((new File(xsdLocation))); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); ERecordType e = new ERecordType(); e.setCataloging(rc); /** * Validate Against Schema. */ marshaller.setSchema(schema); /** * Marshal will throw an exception if XML not validated against * schema. */ marshaller.marshal(e, System.out);

    Read the article

  • get xml attribute named xlink:href using xsl

    - by awe
    How can I get the value of an attribute called xlink:href of an xml node in xsl template? I have this xml node: <DCPType> <HTTP> <Get> <OnlineResource test="hello" xlink:href="http://localhost/wms/default.aspx" xmlns:xlink="http://www.w3.org/1999/xlink" xlink:type="simple" /> </Get> </HTTP> </DCPType> When I try the following xsl, I get an error saying "Prefix 'xlink' is not defined." : <xsl:value-of select="DCPType/HTTP/Get/OnlineResource/@xlink:href" /> When I try this simple attribute, it works: <xsl:value-of select="DCPType/HTTP/Get/OnlineResource/@test" />

    Read the article

  • XML and ServerXMLHTTP problem

    - by ZAfrican
    Error Type: msxml3.dll (0x80072F0C) A certificate is required to complete client authentication I am sending an XML file to a remote server putUrl =https://www.myweb.com/test/drhandler.php xml_put = "<?xml version=""1.0""?><subscription id=""" & "14" &"""><status>" &"das" & "</status></subscription>" Public Function SendBatch(xml_put,putUrl) Set xmlhttp = CreateObject("MSXML3.ServerXMLHTTP") xmlhttp.Open "PUT", putUrl , False xmlhttp.setRequestHeader "Content-Type", "application/x-www-form-urlencoded" xmlhttp.send(xml_put) Set xmlhttp = Nothing end function Any help out there?

    Read the article

  • remove parent xml tag

    - by cru3l
    For example, we have xml file with this format: <A> <B> <C></C> <D></D> <D></D> </B> </A> i need that: if all "D"-tags elements are empty, then we need to delete whole "A"-tag element and, of course, we need to do this with all "A"-tags in xml.

    Read the article

  • Using GWT to output XML, JSON and regular HTML

    - by Artem
    Sorry, this is a very basic question, as we are just getting started with exploring GWT. We would like to know if it's easy and possible to get GWT to "output" XML, JSON and regular HTML. I would like to know this because ideally we would port parts of our backends over slowly, and it would be nice to drop in GWT in place of AJAX wherever we need it during the transition period. Places that we would like to be able to use: 1) We have a pure XML page that we return to our client (mobile) app and right now this is handled through Spring MVC with a nice template. What's the best replacement for this? 2) We have a regular AJAX page that makes async requests and expects replies in JSON. Can we easily replace this backend? 3) We have some regular webpages where we use templates to output them, and we would like to first switch them over in the simplest possible way, without converting them to the regular GWT UI framework. Thanks!

    Read the article

  • Regexp to add attribute in any xml tags

    - by katsuo11
    Hello, I have well-formed xml documents into string variables. I want to use preg_replace to add a defined attribute to every xml tags. For example replace: <tag1> <tag2> some text </tag2> </tag1> by: <tag1 attr="myAttr"> <tag2 attr="myAttr"> some text </tag2> </tag1> So I basically need the regex expression to find any start tags and add my attribute, but I'm a complete regex noob. Thanks, kats

    Read the article

  • XML DOM Manipuation

    - by kunalsawlani
    Hi, I am new to XML and have been trying some simple examples and they work fine. I want to do something like the following, but I am not able to figure out how to go about doing this. I have a HTML web page, where the user types in some data in an input field. I want to take that data, parse it to create an XML string, and the apply XSLT transformation to it, and display the result back on the page. All this needs to be done on the client browser, with JavaScript. If some one could point out the steps or the general procedure to go about doing this, it would be great. I have been looking over the net, but the information is so vast, that I have not been able to locate exactly what I need. Thanks

    Read the article

  • XML Parsing in Groovy strips attribute new lines

    - by Bill James
    I'm writing code where I retrieve XML from a web api, then parse that XML using Groovy. Unfortunately, it seems that both XmlParser and XmlSlurper for Groovy strip newline characters from the attributes of nodes when .text() is called. How can I get at the text of the attribute including the newlines? Sample code: def xmltest = ''' <snippet> <preSnippet att1="testatt1" code="This is line 1 This is line 2 This is line 3" > <lines count="10" /> </preSnippet> </snippet>''' def parsed = new XmlParser().parseText( xmltest ) println "Parsed" parsed.preSnippet.each { pre -> println pre.attribute('code'); } def slurped = new XmlSlurper().parseText( xmltest ) println "Slurped" slurped.children().each { preSnip -> println [email protected]() } the output of which is: Parsed This is line 1 This is line 2 This is line 3 Slurped This is line 1 This is line 2 This is line 3

    Read the article

  • Unable to output XML data in a manageable way

    - by Rob
    I've been given data from a previous version of a website (it was a custom CMS) and am looking to get it into a state that I can import it into my Wordpress site. This is what I'm working on - http://www.teamworksdesign.com/clients/ciw/datatest/index.php. If you scroll down to row 187 the data starts to fail (there should be a red message) with the following error message: Fatal error: Uncaught exception 'Exception' with message 'String could not be parsed as XML' in /home/teamwork/public_html/clients/ciw/datatest/index.php:132 Stack trace: #0 /home/teamwork/public_html/clients/ciw/datatest/index.php(132): SimpleXMLElement-__construct(' Can anyone see what the problem is and how to fix it? This is how I'm outputting the date: <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> </head> <body> <?php ini_set('memory_limit','1024M'); ini_set('max_execution_time', 500); //300 seconds = 5 minutes echo "<br />memory_limit: " . ini_get('memory_limit') . "<br /><br />"; echo "<br />max_execution_time: " . ini_get('max_execution_time') . "<br /><br />"; libxml_use_internal_errors(true); $z = new XMLReader; $z->open('dbo_Content.xml'); $doc = new DOMDocument; $doc->preserveWhiteSpace = false; // move to the first <product /> node while ($z->read() && $z->name !== 'dbo_Content'); $c = 0; // now that we're at the right depth, hop to the next <product/> until the end of the tree while ($z->name === 'dbo_Content') { if($c < 201) { // either one should work $node = simplexml_import_dom($doc->importNode($z->expand(), true)); if($node->ClassId == 'policydocument') { $c++; echo "<h1>Row: $c</h1>"; echo "<pre>"; echo htmlentities($node->XML) . "<br /><br /><br /><b>*******</b><br /><br /><br />"; echo "</pre>"; try{ $xmlObject = new SimpleXMLElement($node->XML); foreach ($xmlObject->fields[0]->field as $field) { switch((string) $field['name']) { case 'parentId': echo "<b>PARENT ID: </b> " . $field->value . "<br />"; break; case 'title': echo "<b>TITLE: </b> " . $field->value . "<br />"; break; case 'summary': echo "<b>SUMMARY: </b> " . $field->value . "<br />"; break; case 'body': echo "<b>BODY:</b> " . $field->value . "<br />"; break; case 'published': echo "<b>PUBLISHED:</b> " . $field->value . "<br />"; break; } } echo '<br /><h2 style="color:green;">Success on node: '.$node->ContentId.'</h2><hr /><br />'; } catch (Exception $e){ echo '<h2 style="color:red;">Failed on node: '.$node->ContentId.'</h2>'; } } // go to next <product /> $z->next('dbo_Content'); } } ?> </body> </html>

    Read the article

  • How to create and download an XML without storing it on the server

    - by CiccioMiami
    NET Web Forms** application. I would like to create a download link to make available to the user the possibility to download an XML file. However the file does not have to be stored on the server. In my aspx file I have the download link (placed inside a GridView): <asp:HyperLinField Text="Download" DataNavigateUrlFormatString="download.aspx?ProductId={0}" DataNavigateUrlFields="ProductId"> In the download.aspx.vb page: Dim productId As String = Request.QueryString("productId") Dim xmlDoc As String = _ProductServices.GetXmlDocPerId(productId) Dim xdoc As XmlDocument = New XmlDocument() xdoc.LoadXml(xmlLicense) Now I would like to create a file, place the XML content inside and deliver it to the user without saving it to the server. Shall I use a MemoryStream combined with a StreamReader?

    Read the article

  • how to remove empty tags in input xml

    - by SGB
    My java module gets a huge input xml from a mainframe. Unfortunately, the mainframe is unable to skip optional elements when it is not a leaf node, with the result that I get a LOT of empty tags in my input : So, <pre><code><SSN>111111111</SSN> <Employment> <Current> <Address> <line1/> <line2/> <line3/> <city/> <state/> <country/> </Address> <Phone> <phonenumber/> <countryCode/> </Phone> </Current> <Previous> <Address> <line1/> <line2/> <line3/> <city/> <state/> <country/> </Address> <Phone> <phonenumber/> <countryCode/> </Phone> </Previous> </Employment> <MaritalStatus>Single</MaritalStatus> </code></pre> should be <SSN>111111111</SSN> <MaritalStatus>Single</MaritalStatus> I use jaxb to unmarshall the input xml string that the mainframe sends it. Is there a clean/ easy way to remove all the empty group tags, or do I have to do this manuall in the code for each element. I have over 35 elements in my input xml, so I would love to it if jaxb itself had a way of doing this automatically? Thanks, SGB

    Read the article

  • bloated jquery xml requests

    - by Tim Joyce
    Hi, I was wondering if anyone had an alternative to this. $(xml).find("a").each(function(){ $(this).find('b').each(function(){ $(this).find('c').each(function(){ $(this).find('d1').each(function(){ sectionValidation.RegisterTerms.setRegisterTermsArray(this); }); $(this).find('d2').each(function(){ sectionValidation.RegisterTerms.checkValidVariations(this, val); }); }); }); }); It seems really bloated and there has to be a more elegant approach to getting nested xml data. Thank you

    Read the article

  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

    Read the article

  • PHP Xml add edit delete

    - by user560411
    Hi there. I am kind of new and I have the following XML structure an I would like to have codes that INSERTS DELETES Delete an entire element based on it's TITLE value. EDIT Replace Publisher's value with another value <Game type="XXX"> <TITLE>XXX</TITLE> <PUBLISHER>XXX</PUBLISHER> </Game> This is my XML structure <Game type="adventure"> <TITLE>Assassin's Creed: Brotherhood</TITLE> <PUBLISHER>Ubisoft</PUBLISHER> </Game> <Game type="adventure"> <TITLE>Batman: Arkham Asylum</TITLE> <PUBLISHER>Eidos</PUBLISHER> </Game> </GameStore> Any help would be great and thank you in avdance!

    Read the article

  • dynamically updating a datagrid from a XML file c# 3.5

    - by Farstucker
    I have a datagrid that is populated via XML file when the form loads. Everything is working great but I would like the datagrid to update dynamically when a new order is received (Separate class receives a data stream and updates the file). Im looking for suggestions on how this should be done. (ie using a timer update every second, or monitor the file using FileSystemWatcher.. etc) Since where here, I might as well mention that in order to update the datagrid Im clearing the whole data set and Re-reading the file using: DataSet.Clear(); DataSet.ReadXml("file.xml"); dataGridView1.DataSource = DataSet; if this is not the proper approach, please offer any alternate suggestions.

    Read the article

  • Validating XML with multiple XSDs in Java

    - by Arian
    Hello! I want to parse an XML file with Java and validate it in the same step against an XSD schema. An XML file may contain content of several schemas, like this: <outer xmlns="my.outer.namespace" xmlns:x="my.third.namespace"> <foo>hello</foo> <inner xmlns="my.inner.namespace"> <bar x:id="bar">world</bar> </inner> </outer> Given a namespace the corresponding xsd file can be provided, but the used namespaces are unknown before parsing. If a schema defines default values for attributes, I also want to know that somehow. I was able to validate a file if the schemas are known, I was able to parse a file without validation and I implemented a LSResourceResolver. However, I can't get all of it working together. How do I have to set up my (SAX) parser?

    Read the article

  • Validate an XML File Against Multiple Schema Definitions

    - by Jon
    I'm trying to validate an XML file against a number of different schemas (apologies for the contrived example): a.xsd b.xsd c.xsd c.xsd in particular imports b.xsd and b.xsd imports a.xsd, using: <xs:include schemaLocation="b.xsd"/> I'm trying to do this via Xerces in the following manner: XMLSchemaFactory xmlSchemaFactory = new XMLSchemaFactory(); Schema schema = xmlSchemaFactory.newSchema(new StreamSource[] { new StreamSource(this.getClass().getResourceAsStream("a.xsd"), "a.xsd"), new StreamSource(this.getClass().getResourceAsStream("b.xsd"), "b.xsd"), new StreamSource(this.getClass().getResourceAsStream("c.xsd"), "c.xsd")}); Validator validator = schema.newValidator(); validator.validate(new StreamSource(new StringReader(xmlContent))); but this is failing to import all three of the schemas correctly resulting in cannot resolve the name 'blah' to a(n) 'group' component. I've validated this successfully using Python, but having real problems with Java 6.0 and Xerces 2.8.1. Can anybody suggest what's going wrong here, or an easier approach to validate my XML documents?

    Read the article

  • VB.NET looping through XML to store in singleton

    - by rockinthesixstring
    I'm having a problem with looping through an XML file and storing the value in a singleton My XML looks like this <values> <value></value> <value>$1</value> <value>$5,000</value> <value>$10,000</value> <value>$15,000</value> <value>$25,000</value> <value>$50,000</value> <value>$75,000</value> <value>$100,000</value> <value>$250,000</value> <value>$500,000</value> <value>$750,000</value> <value>$1,000,000</value> <value>$1,250,000</value> <value>$1,500,000</value> <value>$1,750,000</value> <value>$2,000,000</value> <value>$2,500,000</value> <value>$3,000,000</value> <value>$4,000,000</value> <value>$5,000,000</value> <value>$7,500,000</value> <value>$10,000,000</value> <value>$15,000,000</value> <value>$25,000,000</value> <value>$50,000,000</value> <value>$100,000,000</value> <value>$100,000,000+</value> </values> And my function looks like this Public Class LoadValues Private Shared SearchValuesInstance As List(Of SearchValues) = Nothing Public Shared ReadOnly Property LoadSearchValues As List(Of SearchValues) Get Dim sv As New List(Of SearchValues) If SearchValuesInstance Is Nothing Then Dim objDoc As XmlDocument = New XmlDataDocument Dim objRdr As XmlTextReader = New XmlTextReader(HttpContext.Current.Server.MapPath("~/App_Data/Search-Values.xml")) objRdr.Read() objDoc.Load(objRdr) Dim root As XmlElement = objDoc.DocumentElement Dim itemNodes As XmlNodeList = root.SelectNodes("/values") For Each n As XmlNode In itemNodes sv.Add(New SearchValues(n("@value").InnerText, n("@value").InnerText)) Next SearchValuesInstance = sv Else : sv = SearchValuesInstance End If Return sv End Get End Property End Class My problem is that I'm getting an object not set to an instance of an object on the sv.Add(New SearchValues(n("@value").InnerText, n("@value").InnerText)) line.

    Read the article

< Previous Page | 57 58 59 60 61 62 63 64 65 66 67 68  | Next Page >