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  • How do I add more than one command to /etc/rc.local?

    - by Andreas
    I want to add two power saving commands to /etc/rc.local file. This to dissable bluetooth: rfkill block bluetooth And this to reduce screen brightness: echo 3024 > /sys/class/backlight/intel_backlight/brightness Separately added to /etc/rc.local they work but not both of them together like this: #/bin/sh -e # # rc.local # # This script is executed at the end of each multiuser runlevel. # Make sure that the script will "exit 0" on success or any other # value on error. # # In order to enable or disable this script just change the execution # bits. # # By default this script does nothing. echo 3024 > /sys/class/backlight/intel_backlight/brightness rfkill block bluetooth exit 0 How do I add the two commands to get them properly executed at start-up? Update It turned out to be a timing issue. I fixed it by delaying the execution of the first command thus: (sleep 5; echo 3021 > /sys/class/backlight/intel_backlight/brightness)&

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  • How to solve Fatal error: Call to undefined function readline()? readline library not found?

    - by SirBT
    I have an Ubuntu 12.04 LTS. And XAMPP for linux 1.7.7. When I code in php with and call the readline function I get this error message? "Fatal error: Call to undefined function readline()" I recently found the below thread which pointed out the name of the package that contained the desired readline: How to solve configure: error: readline library not found? I went ahead and installed # apt-get install libreadline6. But this didnt seem to make a difference. I still get the same error message: "Fatal error: Call to undefined function readline()". Was the thread missing further steps? Can anyone help me? I am new to Ubuntu. <?php echo "Simple menu \n" ; echo "1. Play Sports \n"; echo "2. Play Strategy games \n"; $userInput = readline('Enter something here: '); ?>

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  • About output of vga_switcher

    - by zhangjie
    When IGD and DIS both exist in my pc,and I want to disable DIS,so I create a service to switch on and off the DIS.It works.Finally,I decide to add the service command into /etc/rc.local so that DIS will be powered off automatically.Unfortunately,it fails.There's only one command added by myself in the file /etc/rc.local,so I can affirm failure is caused by that added command. Before,I directly added the command "echo OFF /sys/kernel/debug..." into /etc/rc.local,and when I restarted,the system startup fails.So I thought maybe when the command is executed,the DIS hasn't been powered on or ready for work.So conflict occurs!It's just my prediction.Then I added one line command "sleep 1s" before the "echo OFF ...",it works nearly everytime when I start or restart pc,while fails sometimes. The output result of "cat /sys/kernel/debug..." is as following: 0:IGD:+:Pwr:0000:00:02.0 1:DIS: :Pwr:0000:01:00.0 I want know 0000:00:02.0 means what?Time of first power on? If it was really time,I can set the command "sleep 2s" to wait for DIS powered on then "echo OFF ..." Thanks for your advice!

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  • Help to Install STLPort in VC6

    - by Yan Cheng CHEOK
    I try to follow the following steps to install STLPort in VC6 1) I change C:\Program Files\Microsoft Visual Studio\VC98\Bin\VCVARS32.BAT content set INCLUDE=%MSVCDir%\ATL\INCLUDE;%MSVCDir%\INCLUDE;%MSVCDir%\MFC\INCLUDE;%INCLUDE% set LIB=%MSVCDir%\LIB;%MSVCDir%\MFC\LIB;%LIB% to (The directory C:\STLport-5.2.1\lib is not exsits?) set INCLUDE=C:\STLport-5.2.1\stlport;%MSVCDir%\ATL\INCLUDE;%MSVCDir%\INCLUDE;%MSVCDir%\MFC\INCLUDE;%INCLUDE% set LIB=C:\STLport-5.2.1\lib;%MSVCDir%\LIB;%MSVCDir%\MFC\LIB;%LIB% 2) I C:\>cd C:\STLport-5.2.1\build\lib C:\STLport-5.2.1\build\lib>"c:\Program Files\Microsoft Visual Studio\VC98\bin\VCVARS32.BAT" Setting environment for using Microsoft Visual C++ tools. C:\STLport-5.2.1\build\lib>c:\STLport-5.2.1\configure.bat msvc6 STLport Configuration Tool for Windows The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. Setting compiler: Microsoft Visual C++ 6.0 The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. The system cannot find the path specified. Setting platform: Windows XP The system cannot find the path specified. Done configuring STLport. Go to build/lib folder and type "nmake clean install" to build and install STLport to the "lib" and "bin" folders. Go to build/test/unit folder and type nmake clean install to build unit tests and install them in bin folder. 3) The code within configure.bat, which give me The system cannot find the path specified is REM initially create/overwrite config.mak echo # STLport Configuration Tool for Windows > build\Makefiles\nmake\config.mak echo # >> build\Makefiles\nmake\config.mak echo # config.mak generated with command line: >> build\Makefiles\nmake\config.mak echo # configure %1 %2 %3 %4 %5 %6 %7 %8 %9 >> build\Makefiles\nmake\config.mak echo # >> build\Makefiles\nmake\config.mak What I shall change them to? How can I continue the build? Thanks.

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  • json problems with making a ruby on rails application

    - by Prince Merdz
    So I'm using Bitnami to learn Ruby on Rails. I have also previously tried the manual installation for ruby and rails and was met by the same problem so I thought I should try first the easy package deal of Bitnami. Anyway my problem with json is that it causes the bundle install to fail. First the auto bundle install that rails new does fails because of an ssl error. Which is easily solved by changing the source in the gemfile which is https to http. However when I try to bundle install it does another error when it tries to install json. C:\RubyStack-3.2.7-0\projects\testing>bundle install Fetching gem metadata from http://rubygems.org/......... Using rake (0.9.2.2) Using i18n (0.6.0) Using multi_json (1.3.6) Installing activesupport (3.2.8) Using builder (3.0.0) Installing activemodel (3.2.8) Using erubis (2.7.0) Using journey (1.0.4) Using rack (1.4.1) Using rack-cache (1.2) Using rack-test (0.6.1) Using hike (1.2.1) Using tilt (1.3.3) Using sprockets (2.1.3) Installing actionpack (3.2.8) Using mime-types (1.19) Using polyglot (0.3.3) Using treetop (1.4.10) Using mail (2.4.4) Installing actionmailer (3.2.8) Using arel (3.0.2) Using tzinfo (0.3.33) Installing activerecord (3.2.8) Installing activeresource (3.2.8) Using bundler (1.1.5) Using coffee-script-source (1.3.3) Using execjs (1.4.0) Using coffee-script (2.2.0) Using rack-ssl (1.3.2) Installing json (1.7.5) with native extensions Gem::Installer::ExtensionBuildError: ERROR: Failed to build gem native extension . C:/RUBYST~1.7-0/ruby/bin/ruby.exe extconf.rb creating Makefile make 0 [main] echo 5244 open_stackdumpfile: Dumping stack trace to echo.exe.sta ckdump make: *** [generator-i386-mingw32.def] Error 5 Gem files will remain installed in C:/RUBYST~1.7-0/ruby/lib/ruby/gems/1.9.1/gems /json-1.7.5 for inspection. Results logged to C:/RUBYST~1.7-0/ruby/lib/ruby/gems/1.9.1/gems/json-1.7.5/ext/j son/ext/generator/gem_make.out An error occured while installing json (1.7.5), and Bundler cannot continue. Make sure that `gem install json -v '1.7.5'` succeeds before bundling. This is the gem_make.out file it produces after trying to install json (btw windows also produces an error that echo.exe has stopped working while running the gem install json) C:/RUBYST~1.7-0/ruby/bin/ruby.exe extconf.rb creating Makefile make 0 [main] echo 5244 open_stackdumpfile: Dumping stack trace to echo.exe.stackdump make: *** [generator-i386-mingw32.def] Error 5 I can't even start learning ror for the setup is already a huge pain. (btw I have no prior experience with web frameworks, just desktop programming). help?

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  • foreach loop corrupting my array?

    - by WmasterJ
    Explanation I have a multidimensional array that is iterated over to created a categorized view of people with different research interests. The main array look something like this: Array ( ... ['Cell Biology'] => Array(4 elements) ['Molecular'] => Array(6 elements) ['Biology Education'] => Array(14 elements) ['Plant Biology'] => Array(19 elements) <--- Last element in array ) I know that the entire array is intact and correctly structured. The only information that is inside these array is an user id, like so: Array ('Plant Biology') 19 elements ( [0] => 737 [1] => 742 [2] => 748 ... ) My problem is that after i run the main array through a foreach loop the last 'sub-array' gets messed up. By messed up I mean that what you see about instead look like: String (13 characters) 'Plant Biology' This is without doing at all anything inside the loop with to the array that gets corrupted. Any tips to what it might be? PHP Code // ---> Array is OK here echo "<h2>Research divided</h2>"; // Loop areas and list them in 2 columns foreach($research['areas'] as $area => $areaArray) { // ---> Here it is already corrupted $count = count($areaArray); if($count > 0) { echo "<h3>$area</h3><hr/>"; echo "<table class='area_list'><tr>"; // Loop users within areas, divided up in 2 columns for($i=0 ; $i<$count ; $i++) { $uid = $areaArray[$i]; echo "<li>$uid</li>"; } echo "</tr></table>"; } }

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  • [solved] PHP-called hyperlink stopped showing when CSS table implemented

    - by Luke
    EDIT: Solved - was not flutter's tag stripping, should work as advertised. I'm using Flutter (which creates custom fields) in Wordpress to display profile information entered as a Post. Before I implemented the CSS tables the link showed up and was clickable. Now I get nothing returned, even when I try to call the link outside the table. If you know anything about this, here's my code in the index.php file and I remain available for any questions. <?php if (in_category('Profile')) { ?> <table id="mytable" cellspacing="0"> -snip- <tr> <th class="row1" valign="top">Website </td> <td>Link: <a href="<?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?>"> <?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?></a></td> </tr> -snip- </table> Thanks, L Edit: @Josh - there is a foreach looping construct in the table and it is reading and displaying the code correctly, I see what you're getting at now: <tr> <th class="row2" valign="top">Specialities </td> <td class="alt" valign="top"><?php $my_array = get('Expertise'); $output = ""; foreach($my_array as $check) { $output .= "<span>$check</span><br/> "; } echo $output; ?></td> </tr> Edit - @Josh - here's the old code as far as I can remember it, there was no major difference just a <td> tag where there now stands a <th>, there wasn't the class="" and there was no "Link:" and FrWebsite was called Website, but it still didn't work when called Website so I changed to see if that was the error. <tr> <td width="200" valign="top">Website </td> <td><a href="<?php echo get_post_meta($post->ID, 'Website', $single=true) ?>"><?php echo get_post_meta($post->ID, 'Website', $single=true) ?></a></td> </tr>

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  • Displaying a message in a dialog box using AJAX, jQuery, and CakePHP

    - by LainIwakura
    I have a form, and when users submit this form, it should pass the data along to a function using AJAX. Then, the result of that is displayed to the user in a dialog box. I'm using CakePHP (1.3) and jQuery to try and accomplish this but I feel like I'm running into the ground. The form will eventually be used for uploading images with tags, but for now I just want to see a message pop up in the box.. The form: <?php echo $this->Form->create('Image', array('type' => 'file', 'controller' => 'images', 'action' => 'upload', 'method' => 'post')); echo $this->Form->input('Wallpaper', array('type' => 'file')); echo $this->Form->input('Tags'); echo $this->Form->end('Upload!'); ?> The AJAX: $(document).ready(function() { $("#ImageUploadForm").submit(function() { $.ajax({ type: "POST", url: "/images/upload/", data: $(this).serialize(), async: false, success: function(html){ $("#dialog-modal").dialog({ $("#dialog-modal").append("<p>"+html+"</p>"); height: 140, modal: true, buttons: { Ok: function() { $(this).dialog('close'); } } }) } }); return false; }); }); NOTE: if I put $("#dialog-modal").dialog({ height: 140, modal: true }); OUTSIDE of the $.ajax but inside the $("#ImageUploadForm").submit(function() { and comment out the $.ajax stuff, I WILL see a dialog box pop up and then I have to click it for it to go away. After this, it will not forward to the location /images/upload/ The method that AJAX calls: public function upload() { $this->autoRender = false; if ($this->RequestHandler->isAjax()) { echo 'Hi!'; exit(); } } $this-RequestHandler-isAjax() seems to do either absolutely nothing, or it is always returning false. I have never entered an if statement with that as the condition. Thanks for all the help, if you need more information let me know.

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  • Populating fields in modal form using PHP, jQuery

    - by Benjamin
    I have a form that adds links to a database, deletes them, and -- soon -- allows the user to edit details. I am using jQuery and Ajax heavily on this project and would like to keep all control in the same page. In the past, to handle editing something like details about another website (link entry), I would have sent the user to another PHP page with form fields populated with PHP from a MySQL database table. How do I accomplish this using a jQuery UI modal form and calling the details individually for that particular entry? Here is what I have so far- <?php while ($linkDetails = mysql_fetch_assoc($getLinks)) {?> <div class="linkBox ui-corner-all" id="linkID<?php echo $linkDetails['id'];?>"> <div class="linkHeader"><?php echo $linkDetails['title'];?></div> <div class="linkDescription"><p><?php echo $linkDetails['description'];?></p> <p><strong>Link:</strong><br/> <span class="link"><a href="<?php echo $linkDetails['url'];?>" target="_blank"><?php echo $linkDetails['url'];?></a></span></p></div> <p align="right"> <span class="control"> <span class="delete addButton ui-state-default">Delete</span> <span class="edit addButton ui-state-default">Edit</span> </span> </p> </div> <?php }?> And here is the jQuery that I am using to delete entries- $(".delete").click(function() { var parent = $(this).closest('div'); var id = parent.attr('id'); $("#delete-confirm").dialog({ resizable: false, modal: true, title: 'Delete Link?', buttons: { 'Delete': function() { var dataString = 'id='+ id ; $.ajax({ type: "POST", url: "../includes/forms/delete_link.php", data: dataString, cache: false, success: function() { parent.fadeOut('slow'); $("#delete-confirm").dialog('close'); } }); }, Cancel: function() { $(this).dialog('close'); } } }); return false; }); Everything is working just fine, just need to find a solution to edit. Thanks!

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  • Running same powershell script multiple asynchronous times with separate runspace

    - by teqnomad
    Hi, I have a powershell script which is called by a batch script which is called by Trap Receiver (which also passes environment variables) (running on windows 2008). The traps are flushed out at times in sets of 2-4 trap events, and the batch script will echo the trap details for each message to a logfile, but the powershell script on the next line of the batch script will only appear to process the first trap message (the powershell script writes to the same logfile). My interpetation is that the defaultrunspace is common to all iterations of the script running and this is why the others appear to be ignored. I've tried adding "-sta" when I invoke the powershell script using "powershell.exe -command", but this didn't help. I've researched and found a method using C# but I don't know this language, and busy enough learning powershell, so hoping to find a more direct solution especially as interleaving a "wrapper" between batch and powershell will involve passing the environment variables. http://www.codeproject.com/KB/threads/AsyncPowerShell.aspx I've hunted through stackoverflow, and again the only question of similar vein was using C#. Any suggestions welcome. Some script background: The powershell script is actually a modification of a great script found at gregorystrike website - cant post the link as I'm limited to one link but its the one for Lefthand arrays. Lots of mods so it can do multiple targets from one .ini file, taking in the environment variables, and options to run portions of the script interactively with winform. But you can see the gist of the original script. The batch script is pretty basic. The keys things are I'm trying to filter out trap noise using the :~ operator, and I tried -sta option to see if this would compartmentalise the powershell script. set debug=off set CMD_LINE_ARGS="%*" set LHIPAddress="%2" set VARBIND8="%8" shift shift shift shift shift shift shift set CHASSIS="%9" echo %DATE% %TIME% "Trap Received: %LHIPAddress% %CHASSIS% %VARBIND8%" >> C:\Logs\trap_out.txt set ACTION="%VARBIND8:~39,18%" echo %DATE% %TIME% "Action substring is %ACTION%" 2>&1 >> C:\Logs\trap_out.txt if %ACTION%=="Remote Copy Volume" ( echo Prepostlefthand_env_v2.9 >> C:\Logs\trap_out.txt c:\Windows\System32\WindowsPowerShell\v1.0\PowerShell.exe -sta -executionpolicy unrestricted -command " & 'C:\Scripts\prepostlefthand_env_v2.9.ps1' Backupsettings.ini ALL" 2>&1 >> C:\Logs\trap_out.txt ) ELSE ( echo %DATE% %TIME% Action substring is %ACTION% so exiting" 2>&1 >> C:\Logs\trap.out.txt ) exit

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  • PHP and MySQL problem?

    - by TaG
    When my code is stored and saved and out putted I keep getting these slashes \\\\\ in my output text. how can I get rid of these slashes? Here is the PHP code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="about_me">About Me: </label> <textarea rows="8" cols="60" name="about_me" id="about_me"><?php if (isset($_POST['about_me'])) { echo mysqli_real_escape_string($mysqli, $_POST['about_me']); } else if(!empty($about_me)) { echo mysqli_real_escape_string($mysqli, $about_me); } ?></textarea></li> <li><label for="my-interests">My Interests: </label> <textarea rows="8" cols="60" name="interests" id="interests"><?php if (isset($_POST['interests'])) { echo mysqli_real_escape_string($mysqli, $_POST['interests']); } else if(!empty($interests)) { echo mysqli_real_escape_string($mysqli, $interests); } ?></textarea></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • NO FBML is working in iframe in facebook using PHP (ie or ff or anywhere else!)

    - by Cyprus106
    I have tried for three days now and gotten nowhere on this.... I absolutely can not get any "fb:" code to render anything! I've tried the exact code in the sandbox and it works fine. I've read through every search result I could find and gotten nowhere... I'm using a standard xd_receiver page, and in the body there's this line: < script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/XdCommReceiver.js" type="text/javascript"></script> Here's my index page. It's basically the stock facebook example code.... <?php require_once 'facebook-platform/php/facebook.php'; //Authentication Keys $appapikey = 'MY_KEY'; // obviously this is my real key $appsecret = 'MY_SECRET'; // same thing $facebook = new Facebook($appapikey, $appsecret); $user_id = $facebook->require_login(); ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml"> <head></head> <body> <script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php" type="text/javascript"></script> <? echo "<p>Hello, <fb:name uid=\"$user_id\" useyou=\"false\"></fb:name>!</p>"; ?> <script type="text/javascript"> FB_RequireFeatures(["XFBML"], function(){ FB.Facebook.init("<?php echo $appapikey; ?>", "xd_receiver.htm"); }); </script> </body> </html> oddly enough, when I put this code below where it echos the logged in user's name, it does show the id numbers of friends. But again, it won't render their names <?php friends.get API method echo "<p>Friends:"; $friends = $facebook->api_client->friends_get(); $friends = array_slice($friends, 0, 25); foreach ($friends as $friend) { echo "<br>".$friend." - <fb:name uid=\".$user_id.\" useyou=\"false\"></fb:name>"; } echo "</p>"; ?> Here's my settings: Canvas Callback URL http://www.my-actual-website.com/test/ Canvas URL http://apps.facebook.com/gogre_testapp/ FBML/iframe iframe Application Type Website Post-Remove URL http://www.my-actual-website.com/test/ Post-Authorize URL http://www.my-actual-website.com/test/ Please, somebody help me out! I've been trying unsuccessfully for days

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  • Newbie's problems with MySQL and php

    - by Mirage81
    I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

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  • Anyway that I can get the values of a PHP array through ajax?

    - by Jerry
    Hi All, I am trying to build a shopping cart site. When a user click add to cart image on the product page, The product title will show a "The product is in your cart" text without reloading the page. I am using session and ajax but no luck so far. I appreciate any helps. My html cold <table id="<?php echo $productId; ?>" width="594" border="0" cellpadding="5" cellspacing="0"> <tr> <td><img src="<?php echo "$brandImage"; ?></td> <td <?php echo $productName; ?> //The "The product is in your cart" will be showed here</td> </tr> <tr> <td><a class="addToCart" href="javascript:void(0);" onclick="addToCart(<?php echo $productId?>)"> </td> My Javascript file (addToCart.js) function addToCart(productId){ var url="addToCart.php"; url=url+"?productId="+productId; url=url+"&sid="+Math.random(); $.post( url, function(responseText){ alert(responseText); //I wish I can get productData value from addToCart.php }, "html" ) My php file (addToCart.php) <?php SESSION_START(); $productId=$_GET['productId']; $cart=$_SESSION['cart']; if(isset($cart)){ $cart.=",".$productId; $product=explode(',',$cart); $totalItem=count($product); }else{ $cart=$productId; $totalItem=1; }; $productData=array(); foreach($product as $id){ $productData[$id]=(isset($productData[$id])) ? $productData[$id]+1 :1; }; $_SESSION['cart']=$cart; //print_r($productData); echo $productData; //Not sure what to do to send $productData back to my addToCart.js variable ?> I tried to make the code look simple. Any suggestion will be a great help. Thanks

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  • div automatically added in $item->get_description(); using simplepie

    - by Carey Estes
    I am getting a div that is appearing in the output from calling a RSS feed. It is ignoring my attempts to wrap it in a paragraph tag and pushes the data out to the div. foreach ($feed->get_items(0 , 3) as $item): $feedDescription = $item->get_content(); $image = returnImage($feedDescription); $image = scrapeImage($image); $image_url= $item->get_permalink(); $description = $item->get_description(); ?> <div class="item"> <h4><a href="<?php echo $item->get_permalink(); ?>"><?php echo $item->get_title(); ?></a></h4> <div class="image-box"><?php echo '<a href="' . $image_url . '"><img src="' . $image . '" /></a>'."\n";?></div> <p><?php echo $description ?></p> <p><a href="<?php echo $item->get_permalink(); ?>">Continue Reading</a></p> </div> <?php endforeach; ?> Here is the html output: <div class="item"> <h4><a href="#">Lorem Ipsum</a></h4> <div class="image-box"><a href="#"><img src="image.jpg"></a> </div> <p></p> <div>Lorem Ipsum description [...]</div> <p></p> <p><a href="#">Continue Reading</a></p> </div> Why does the description call add a div tag and not get wrapped in the paragraph tag?

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  • PHP image resize and rounded image corners dynamically

    - by Dan
    I'm working of a script that dynamically ads rounded edges to an image then crops it down to a certain size. At the moment the script ads the rounded edges to the picture but i cannot get it so the original image is resized to fit within the dimensons of the final outputted image (140px x 120px) The problem is that the orginal uploaded image depending on it's orginal dimensions change the size it is in the final PNG { $image_file = $_FILES['image']['tmp_name']; $corner_radius = isset($_GET['radius']) ? $_GET['radius'] : 20; // The default corner radius is set to 20px $topleft = (isset($_GET['topleft']) and $_GET['topleft'] == "no") ? false : true; // Top-left rounded corner is shown by default $bottomleft = (isset($_GET['bottomleft']) and $_GET['bottomleft'] == "no") ? false : true; // Bottom-left rounded corner is shown by default $bottomright = (isset($_GET['bottomright']) and $_GET['bottomright'] == "no") ? false : true; // Bottom-right rounded corner is shown by default $topright = (isset($_GET['topright']) and $_GET['topright'] == "no") ? false : true; // Top-right rounded corner is shown by default $imagetype=$_FILES['image']['type']; $endsize=$corner_radius; $startsize=$endsize*3-1; $arcsize=$startsize*2+1; if (($imagetype=='image/jpeg') or ($imagetype=='jpg')) { $image = imagecreatefromjpeg($image_file); } else { if (($imagetype=='GIF') or ($imagetype=='gif')) { $image = imagecreatefromgif($image_file); } else { $image = imagecreatefrompng($image_file); } } $forecolor ='#ffffff'; $size = getimagesize($image_file); // Top-left corner $background = imagecreatetruecolor($size[0],$size[1]); imagecopymerge($background, $image, 0, 0, 0, 0, $size[0], $size[1], 100); $startx=$size[0]*2-1; $starty=$size[1]*2-1; $im_temp = imagecreatetruecolor($startx,$starty); imagecopyresampled($im_temp, $background, 0, 0, 0, 0, $startx, $starty, $size[0], $size[1]); $bg = imagecolorallocate($im_temp, 255,255,255); $fg = imagecolorallocate($im_temp, 255,255,255); if ($topleft == true) { if(!imagearc($im_temp, $startsize, $startsize, $arcsize, $arcsize, 180,270,$bg))echo "nope"; imagefilltoborder($im_temp,0,0,$bg,$bg); } // Bottom-left corner // Top-right corner if ($topright == true) { imagearc($im_temp, $startx-$startsize, $startsize,$arcsize, $arcsize, 270,360,$bg); imagefilltoborder($im_temp,$startx,0,$bg,$bg); } $image = imagecreatetruecolor(140,120); imagecopyresampled($image, $im_temp, 0, 0, 0, 0, $size[0],$size[1],$starty+1310,$startx+1500); // Output final image if(!imagepng($image,'hello.png')) echo "boo"; if(!imagedestroy($image)) echo "2"; if(!imagedestroy($background)) echo "3"; if(!imagedestroy($im_temp)) echo "4"; } EDIT: My question is how to get the orginal image reized so it fits into the 140 x 120 image that is processed with the rounded edges?

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • checkbox update the record using jquery?

    - by python
    <? include("connect.php"); $sql="select * from sampledb"; $res=mysql_query($sql) or die("query failed"); ?> <script type="text/javascript" src="scripts/jquery.js"></script> <script type="text/javascript"> function updateCheckVal() { var valcheck = []; $('#checkbox :checked').each(function() { valcheck.push($(this).val()); }); $('#store_checkbox').val(valcheck) } $(function() { $('#checkbox input').click(updateCheckVal); updateCheckVal(); }); $(function(){ $("a.modify").click(function(){ var val = []; $(':checkbox:checked').each(function(i){ val[i] = $(this).val(); }); $("#deleted_id").val(val); page=$(this).attr("href"); $("#Formcontent").html("loading...").load(page); return false; }); }); </script <form name=""> <table width="100%" border="1" cellpadding="1" cellspacing="1"> <thead> <tr bgcolor="#CCCCCC"> <th></th> <th>ID</th> <th>Fullname</th> </tr> </thead> <tbody> <? while($row=mysql_fetch_assoc($res)){?> <tr> <td id="checkbox"><input type="checkbox" name="chk[]" class="chk" value=<?php echo $row["student_id"];?> ></td> <td><?php echo $row["id"];?></td> <td><?php echo $row["fullname"];?></td> </tr> <? }?> </tbody> </table> <input type="hidden" name="store_checkbox" id="store_checkbox" value=""> <a href="formstudent.php?action=update&id=<?php echo $_POST["store_checkbox"]; ?>" class="modify">modify</a> I want to pass the checkbox value that is checked in something like this: example :formstudent.php?action=update&id=1, I am doing here is pass like this but does not work. <a href="formstudent.php?action=update&id=<?php echo $_POST["store_checkbox"]; ?>" Anybody know how to do this?

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  • How do I use ViewScripts on Zend_Form File Elements?

    - by Sonny
    I am using this ViewScript for my standard form elements: <div class="field" id="field_<?php echo $this->element->getId(); ?>"> <?php if (0 < strlen($this->element->getLabel())) : ?> <?php echo $this->formLabel($this->element->getName(), $this->element->getLabel());?> <?php endif; ?> <span class="value"><?php echo $this->{$this->element->helper}( $this->element->getName(), $this->element->getValue(), $this->element->getAttribs() ) ?></span> <?php if (0 < $this->element->getMessages()->length) : ?> <?php echo $this->formErrors($this->element->getMessages()); ?> <?php endif; ?> <?php if (0 < strlen($this->element->getDescription())) : ?> <span class="hint"><?php echo $this->element->getDescription(); ?></span> <?php endif; ?> </div> Trying to use that ViewScript alone results in an error: Exception caught by form: No file decorator found... unable to render file element Looking at this FAQ revealed part of my problem, and I updated my form element decorators like this: 'decorators' => array( array('File'), array('ViewScript', array('viewScript' => 'form/field.phtml')) ) Now it's rendering the file element twice, once within my view script, and extra elements with the file element outside my view script: <input type="hidden" name="MAX_FILE_SIZE" value="8388608" id="MAX_FILE_SIZE" /> <input type="hidden" name="UPLOAD_IDENTIFIER" value="4b5f7335a55ee" id="progress_key" /> <input type="file" name="upload_file" id="upload_file" /> <div class="field" id="field_upload_file"> <label for="upload_file">Upload File</label> <span class="value"><input type="file" name="upload_file" id="upload_file" /></span> </div> Any ideas on how to handle this properly with a ViewScript?

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  • Matching array elements to get an array element at another index

    - by bccarlso
    I have a PHP array that I'm using to generate an HTML form. The PHP array is this: <?php $vdb = array ( array( "Alabama", 275), array( "Alaska", 197), array( "Arizona", 3322)); ?> The PHP to generate the HTML form is below. I need to have the value be the name of the state, because there is some AJAX I'm using to display which states a user has chosen. <?php echo "<table border='1'><thead><tr><th></th><th>State</th><th>Contacts</th><th>Email</th></tr></thead>"; for ($row = 0; $row < 42; $row++) { echo "<tr><td class='input_button'><input type='checkbox' name='vdb[]' value='".$vdb[$row][0]."' title='".$vdb[$row][1]."' /></td>"; echo "<td>".$vdb[$row][0]."</td>"; echo "<td>".$vdb[$row][1]."</td>"; } echo "</table>"; ?> What I'm trying to do is, on submission of the form, with the states the user selected, loop through the PHP array and total the numbers from the selected states. So if I checked Alabama and Alaska, I'd want to add 275 + 197. This is what I thought would have worked, but it's not: <?php $vendors = array(); if (isset($_POST["vdb"])) { $vendors = $_POST["vdb"]; } $ven_i = 0; $ven_j = 0; $ven_total = 0; foreach ($vendors as $value) { foreach ($vdb as $vdb_value) { if ($vendors[$ven_i] == $vdb[$ven_j][0]) { $ven_total += $vdb[$ven_j][1]; } $ven_j++; } $ven_i++; } ?> and then $ven_total should be the total I'm looking for. However, $ven_total just ends up being the first checkbox selected, and it ignores the rest. I am doing this correctly with the AJAX, displaying the total on the front end, but I don't know how to pass that on to the form submission. I'd rather not using GET and URL variables, because a user could type something into the URL and modify the count. Any idea what I'm doing wrong, or a better way to approach this that I would be able to understand? (Very much a novice programmer.)

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  • Problem passing variables in php form.

    - by Joshxtothe4
    I have the following php form. I am trying to make it so that when the form is loaded, the values will be assigned the appropriate check- variable. This variable will contain either "checked or "". If it contains checked, the way it is displayed with the html should cause the relevant checkbox to be checked. As it is, the variables do not seem to be being passed. When I echo out $deleted or $notice from within the submitinfo branch, they are blank. Furthermore, nothing is being inserted into the database, and I am not getting any database error. How can I check this? <?php if (isset($_GET["cmd"])) $cmd = $_GET["cmd"]; else if (isset($_POST["cmd"])) $cmd = $_POST["cmd"]; else die("Invalid URL"); if (isset($_GET["pk"])) { $pk = $_GET["pk"]; } if (isset($_POST["deleted"])) { $deleted = $_POST["deleted"]; } if (isset($_POST["notice"])) { $notice = $_POST["notice"]; } $con = mysqli_connect("localhost","user","password", "db"); if (!$con) { echo "Can't connect to MySQL Server. Errorcode: %s\n". mysqli_connect_error(); exit; } $con->set_charset("utf8"); $getformdata = $con->query("select * from STATUS where ARTICLE_NO = '$pk'"); $checkDeleted = ""; $checkNotice = ""; while ($row = mysqli_fetch_assoc($getformdata)) { $checkDeleted = $row['deleted']; $checkNotice = $row['notice']; } if($cmd=="submitinfo") { $statusQuery = "INSERT INTO STATUS VALUES (?, ?)"; if ($statusInfo = $con->prepare($statusQuery)) { $statusInfo->bind_param("ss", $deleted, $notice); $statusInfo->execute(); $statusInfo->close(); echo "true"; } else { echo "false"; } print_r($con->error); } if($cmd=="EditStatusData") { echo "<form name=\"statusForm\" action=\"test.php\" method=\"post\" enctype=\"multipart/form-data\"> <h1>Editing information for auction: ".$pk."</h1> Löschung Ebay: <input type=\"checkbox\" name=\"deleted\" value=\"checked\" ".$checkDeleted." /> <br /> Abmahnung: <input type=\"checkbox\" name=\"notice\" value=\"checked\" ".$checkNotice." /> <br /> <input type=\"hidden\" name=\"cmd\" value=\"submitinfo\" /> <input name=\"Submit\" type=\"submit\" value=\"submit\" /> </form>"; } else { print_r($con->error); }

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  • foreach: how to iterate this

    - by ilnur777
    object(stdClass)[1] public 'inbox' => array 0 => object(stdClass)[2] public 'from' => string '55512351' (length=8) public 'date' => string '29/03/2010' (length=10) public 'time' => string '21:24:10' (length=8) public 'utcOffsetSeconds' => int 3600 public 'recipients' => array 0 => object(stdClass)[3] public 'address' => string '55512351' (length=8) public 'name' => string '55512351' (length=8) public 'deliveryStatus' => string 'notRequested' (length=12) public 'body' => string 'This is message text.' (length=21) 1 => object(stdClass)[4] public 'from' => string '55512351' (length=8) public 'date' => string '29/03/2010' (length=10) public 'time' => string '21:24:12' (length=8) public 'utcOffsetSeconds' => int 3600 public 'recipients' => array 0 => object(stdClass)[5] public 'address' => string '55512351' (length=8) public 'name' => string '55512351' (length=8) public 'deliveryStatus' => string 'notRequested' (length=12) public 'body' => string 'This is message text.' (length=21) .... .... I have this foreach, but it does not iterate address, name, deliveryStatus! Could you show how to get this data? foreach ($data->inbox as $note) { echo '<p>'; echo 'From : ' . htmlspecialchars($note->from) . '<br />'; echo 'Date : ' . htmlspecialchars($note->date) . '<br />'; echo 'Time : ' . htmlspecialchars($note->time) . '<br />'; echo 'Body : ' . htmlspecialchars($note->body) . '<br />'; }

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  • Having issues with JQuery progress bar

    - by Roland
    I'm busy creating a poll but am experiencing issues creating a progress bar for a poll using jquery, thus I have a couple of options and then when the page loads the div tags should increase in width, but it's not doing anything only if I have on option in the poll code <?php foreach($votes as $v): ?> <div><?php echo $v['name'].':'; ?></div> <div> <?php echo 'Votes: '.$v['num'].' | '.$v['percent'].'%'; ?> </div> <script type="text/javascript"> load(<?=$v['name']?>,<?=$v['percent']?>); </script> <div style="width:100%; height:10px; background-color:#effdff;"><div id="<?=$v['name']?>" style=" height:10px; background-color:#ff0000;"></div></div> <br /> <?php endforeach; ?> <?php if(!empty($loginMsg)): ?> <?php echo $loginMsg; ?><br /> <?php endif; ?> Votes: <?php echo $totalVotes+$totalComments; ?> | Comments: <?php echo $totalComments ?> <script type="text/javascript"> var interval=''; var progress = 0; function load(id,val){ alert(id); if (interval=="") { interval=window.setInterval("display('"+id+"','"+val+"')",200); } } function display(id,val) { progress += 1; if(progress == val){ window.clearInterval(interval) interval = ''; progress = 0; } $("#"+id).css("width",progress+'%'); } </script>

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  • Problems with MYSQL database

    - by shinjuo
    I have a database that worked fine until I decided to add a log onto the page. here is what I have now: <body> <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); echo "\"" .$_POST['Add'] ."\" has been added to the inventory amount for the card \"". $_POST['Cards']. "\""; mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" maxlength="8" /> Changes Made By: <select name="Person"> <option value="justin">Justin</option> <option value="chris">Chris</option> <option value="matt">Matt</option> <option value="dan">Dan</option> <option value="tim">Tim</option> <option value="amanda">Amanda</option> </select> <input type="submit" name ="submit" onClick= "return confirm( 'Are you sure you want to add this amount?');"> </form> <br /> <input type="button" name="main" value="Return To Main" onclick="window.location.href='index.php';" /> </body> </html> it works fine until I added the: mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); Can anyone see what is going on?

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  • How do I add a filter button to this pagination?

    - by ClarkSKent
    Hey, I want to add a button(link), that when clicked will filter the pagination results. I'm new to php (and programming in general) and would like to add a button like 'Automotive' and when clicked it updates the 2 mysql queries in my pagination script, seen here: As you can see, the category automotive is hardcoded in, I want it to be dynamic, so when a link is clicked it places whatever the id or class is in the category part of the query. 1: $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); 2: $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); This is the entire current php pagination script that I am using: <?php //connecting to the database $error = "Could not connect to the database"; mysql_connect('localhost','root','root') or die($error); mysql_select_db('ajax_demo') or die($error); //max displayed per page $per_page = 2; //get start variable $start = $_GET['start']; //count records $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); //count max pages $max_pages = $record_count / $per_page; //may come out as decimal if (!$start) $start = 0; //display data $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); while ($row = mysql_fetch_assoc($get)) { // get data $name = $row['id']; $age = $row['site_name']; echo $name." (".$age.")<br />"; } //setup prev and next variables $prev = $start - $per_page; $next = $start + $per_page; //show prev button if (!($start<=0)) echo "<a href='pagi_test.php?start=$prev'>Prev</a> "; //show page numbers //set variable for first page $i=1; for ($x=0;$x<$record_count;$x=$x+$per_page) { if ($start!=$x) echo " <a href='pagi_test.php?start=$x'>$i</a> "; else echo " <a href='pagi_test.php?start=$x'><b>$i</b></a> "; $i++; } //show next button if (!($start>=$record_count-$per_page)) echo " <a href='pagi_test.php?start=$next'>Next</a>"; ?>

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