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  • MySQL database Int overflow and can’t login in.

    - by Ryan Smith
    I have a MySQL database on my server and I"m pretty sure it's an int over flow on one table with an auto_increment field that's crashing it. I can delete the table, it's not very important, but I can't get into the server. Is there anyway to delete that database from the file system or without logging into MySQL? HELP! THE WORLD IS ENDING!

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  • Determine Configured Location of MySQL's data directory OR all loaded *.cfn Locations

    - by alanstorm
    I'm not a sys-admin, but sometimes I play one at work. I've inherited a virtual server that had MySQL installed from source. I'm gathering as much information about the install as I can (original people who installed it are, of course, not a resource). How can I find The default/current location of the MySQL binary files (often stored in a directory named data?) Any default or custom loaded cnf files? Looking for solutions that are a bit more sophisticated than a find / -iname '*.cnf' :)

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  • how do I allow mysql connections through selinux

    - by xivix
    I'd like to for once leave selinux running on a server for the alleged increased security. I usually disable selinux to get anything to work. How do I tell selinux to allow mysql connections? The most documentation I've found is this line from mysql.com: If you are running under Linux and Security-Enhanced Linux (SELinux) is enabled, make sure you have disabled SELinux protection for the mysqld process. wow ... that's really helpful.

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  • MySQL query cache is enabled but not being used

    - by Yoga
    I've checked the query cache is enabled mysql> SHOW VARIABLES LIKE 'have_query_cache'; +------------------+-------+ | Variable_name | Value | +------------------+-------+ | have_query_cache | YES | +------------------+-------+ 1 row in set (0.00 sec) But seems it is not being used mysql> SHOW STATUS LIKE 'Qcache%'; +-------------------------+----------+ | Variable_name | Value | +-------------------------+----------+ | Qcache_free_blocks | 1 | | Qcache_free_memory | 16759648 | | Qcache_hits | 0 | | Qcache_inserts | 0 | | Qcache_lowmem_prunes | 0 | | Qcache_not_cached | 21555882 | | Qcache_queries_in_cache | 0 | | Qcache_total_blocks | 1 | +-------------------------+----------+ 8 rows in set (0.00 sec) Any reason?

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  • how do I allow mysql connections through selinux

    - by xivix
    I'd like to for once leave selinux running on a server for the alleged increased security. I usually disable selinux to get anything to work. How do I tell selinux to allow mysql connections? The most documentation I've found is this line from mysql.com: If you are running under Linux and Security-Enhanced Linux (SELinux) is enabled, make sure you have disabled SELinux protection for the mysqld process. wow ... that's really helpful.

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  • Best approach for Synchronization Mysql databases using C# [closed]

    - by nirmal90
    I have a requirement as below. Windows application in c# with MySQL database MySQL database in both local and server One centralized server with many client synchronizing the server database at each time when the new entry or update is happen in local machine The server data also needs to be updated in local at regular intervals in order to avoid conflicts I need to know what is the best approach to follow to make this synchronization without any conflicts.

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  • Installing mysql-server with python ssh connection

    - by mrbox
    I'm writing a script in Python, which is connecting to server via ssh, then installing some packages. But there is problem with dialogue box, where i can type in a root password- i don't know how to send data there. Once I tried to do this, my apt(using Debian Lenny) gone crazy. Here is some info: - Debian Lenny - Using PySSH with easier interface, code looks like this: clientSSH = SSHClient( self.ip, 'root', self.rootPassword, None ) clientSSH.login() clientSSH.run_command('apt-get install mysql-server mysql-client php5') clientSSH.run_command('Y') #I Don't know how send root passwd here clientSSH.logout()

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  • Access denied for user 'diduser'@'localhost' to database 'diddata' (1044, 42000)

    - by Arlen Beiler
    I am trying to setup a MySQL server and when I went to create a second user it wouldn't give it permissions for the database. I can connect fine as long as I don't specify a database. Access denied for user 'user'@'localhost' to database 'diddata' The connection details are: { 'host' : 'localhost', 'user' : 'user', 'password' : 'password' , 'database': 'diddata' }; And to create the DB and table I did: CREATE DATABASE IF NOT exists diddata; CREATE USER 'user'@'localhost' IDENTIFIED BY 'password'; GRANT ALL ON user.* TO 'user'@'localhost'; Note that I've changed the username and password in this question. I've already checked the privileges in MySQL workbench and they are there.

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  • MySQL for SQL Server DBAs

    - by SQL3D
    I've been tasked with taking over the administration of a MySQL installation (running on Red Hat Linux) that will become fairly critical to our business in the near future. I was wondering if anyone could recommend some resources in regards to administering MySQL for DBAs already experienced with other relational database (SQL Server and some Oracle in my case). Specifically I'm looking for information around disaster recovery as well as high availability to start with, but I do want to get well rounded with the entire system. Thanks in advance, Dan

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  • creation of accounts for each users in mysql / phpmyadmin

    - by user1666411
    I am planning to create mysql accounts for each of my web devs and build their own databases. I need these devs to have accounts to access their own phpmyadmin where they can manipulate their own sets of databases. I am kind of new to web services deployment, so should this setup be configured in phpmyadmin or in mysql? Will this kind of deployment need web management like cpanel? I hope you can enlighten me with this.

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  • Allowing wildcard (%) access on MySQL db, getting error "access denied for '<user>'@'localhost'"

    - by Wayne M
    I've created a database and a user, and allowed access via the following: create user 'someuser'@'%' identified by 'password'; grant all privileges on somedb.* to 'someuser' with grant option; however, when I try to connect to MySQL I get the following error: $ mysql -u someuser -p > Enter Password: > ERROR 1045 (28000): Access denied for user 'someuser'@'localhost' (using password: YES) If "%" is the wildcard, then wouldn't it also enable localhost?

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  • MySQL not respond when overheaded

    - by Michal Gow
    I have few Drupal 6 websites on webhosting, which causes this strange problem: some tables, especially Cache and Watchdog, tend to overhead, when overhead is bigger than some amount of kB, MySQL server is refusing connection to given Drupal database or connection is broken during query execution, Optimizing table (just overheaded rows) in phpMyAdmin is putting all back to normal. But - until database is optimized, site is showing just MySQL errors, which is ugly... Where is a problem? Thank you for any hints I could pass back to the hosting admins!

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  • MySQL Continuosuly crahsing

    - by Phanindra
    I am continuously receiving below error in event viewer... from which it stop mysql service... This is the following error, Faulting application mysqld-nt.exe, version 0.0.0.0, faulting module mysqld-nt.exe, version 0.0.0.0, fault address 0x0022401c. When I checked MySQL error log file, there is no ERROR or WARNING message regarding crash, it is showing normal shutdown. Can any help me out of this.

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  • MYSQL join - reference external field from nested select?

    - by PHP thinker
    Is it allowed to reference external field from nested select? E.g. SELECT FROM ext1 LEFT JOIN (SELECT * FROM int2 WHERE int2.id = ext1.some_id ) as x ON 1=1 in this case, this is referencing ext1.some_id in nested select. I am getting errors in this case that field ext1.some_id is unknow. Is it possible? Is there some other way?

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  • Autopopulate from Select box from database

    - by Chris Spalton
    hope you can help, please forgive any poor coding or anytihng, I'm new to this and just hacking my way through to get things to work. That said, on one of my projects I have this code, which successfully populates the dropdown from a database when the page is loaded: <select name="Region" id="Region"> <option value="">-- Select Region --</option> <?php $region=$POST['Region']; if ($region); { $regionquery = "SELECT DISTINCT REGION FROM Sales_Execs "; $regionresult = mysql_query($regionquery); while($row = mysql_fetch_array($regionresult)) { echo "<option value=\"".$row['REGION']."\">".$row['REGION']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Region').value = <?php echo json_encode(trim($_POST['Region']));?>; </script> </select> On my next project that I'm working on now, I need to do the same thing, so I copied the above code amended, and placed in my new project: <select name="Sales_Exec" id="Sales_Exec"> <option value="">-- Select SE --</option> <?php $salesexec=$POST['Sales_Exec']; if ($salesexec); { $salesexecquery = "SELECT DISTINCT Assigned FROM Data "; $salesexecresult = mysql_query($salesexecquery); while($row = mysql_fetch_array($salesexecresult)) { echo "<option value=\"".$row['ASSIGNED']."\">".$row['ASSIGNED']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Sales_Exec').value = <?php echo json_encode(trim($_POST['Sales_Exec']));?>; </script> </select> This second chunk of code doesn't work... and I can't work out why as it seems I've copied it all and amended all the neccersary parts, can anyone spot what is wrong? Thankyou!

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  • Play Framework: Error getting sequence nextval using H2 in-memory database

    - by alexhanschke
    As the title suggests, I get an error running Play 2.0.1 Tests using a FakeApplication w/ H2 in memory. I set up a basic unit test: public class ModelTest { @Test public void checkThatIndustriesExist() { running(fakeApplication(inMemoryDatabase()), new Runnable() { public void run() { Industry industry = new Industry(); industry.name = "Some name"; industry.shortname = "some-name"; industry.save(); assertThat(Industry.find.all()).hasSize(1); } }); } Which yields the following exception: [info] test.ModelTest [error] Test test.ModelTest.checkThatIndustriesExist failed: Error getting sequence nextval [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:213) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.loadMoreIds(SequenceIdGenerator.java:163) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.nextId(SequenceIdGenerator.java:118) [error] at com.avaje.ebeaninternal.server.deploy.BeanDescriptor.nextId(BeanDescriptor.java:1218) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.setIdGenValue(DefaultPersister.java:1304) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.insert(DefaultPersister.java:403) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveEnhanced(DefaultPersister.java:345) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveRecurse(DefaultPersister.java:315) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.save(DefaultPersister.java:282) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1577) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1567) [error] at com.avaje.ebean.Ebean.save(Ebean.java:538) [error] at play.db.ebean.Model.save(Model.java:76) [error] at test.ModelTest$1.run(ModelTest.java:24) [error] at play.test.Helpers.running(Helpers.java:277) [error] at test.ModelTest.checkThatIndustriesExist(ModelTest.java:21) [error] ... [error] Caused by: org.h2.jdbc.JdbcSQLException: Syntax Fehler in SQL Befehl "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; erwartet "identifier" [error] Syntax error in SQL statement "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; expected "identifier"; SQL statement: [error] select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval [42001-158] [error] at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) [error] at org.h2.message.DbException.get(DbException.java:169) [error] at org.h2.message.DbException.getSyntaxError(DbException.java:194) [error] at org.h2.command.Parser.readColumnIdentifier(Parser.java:2777) [error] at org.h2.command.Parser.readTermObjectDot(Parser.java:2336) [error] at org.h2.command.Parser.readTerm(Parser.java:2453) [error] at org.h2.command.Parser.readFactor(Parser.java:2035) [error] at org.h2.command.Parser.readSum(Parser.java:2022) [error] at org.h2.command.Parser.readConcat(Parser.java:1995) [error] at org.h2.command.Parser.readCondition(Parser.java:1860) [error] at org.h2.command.Parser.readAnd(Parser.java:1841) [error] at org.h2.command.Parser.readExpression(Parser.java:1833) [error] at org.h2.command.Parser.parseSelectSimpleSelectPart(Parser.java:1746) [error] at org.h2.command.Parser.parseSelectSimple(Parser.java:1778) [error] at org.h2.command.Parser.parseSelectSub(Parser.java:1673) [error] at org.h2.command.Parser.parseSelectUnion(Parser.java:1518) [error] at org.h2.command.Parser.parseSelect(Parser.java:1506) [error] at org.h2.command.Parser.parsePrepared(Parser.java:405) [error] at org.h2.command.Parser.parse(Parser.java:279) [error] at org.h2.command.Parser.parse(Parser.java:251) [error] at org.h2.command.Parser.prepareCommand(Parser.java:217) [error] at org.h2.engine.Session.prepareLocal(Session.java:415) [error] at org.h2.engine.Session.prepareCommand(Session.java:364) [error] at org.h2.jdbc.JdbcConnection.prepareCommand(JdbcConnection.java:1119) [error] at org.h2.jdbc.JdbcPreparedStatement.<init>(JdbcPreparedStatement.java:71) [error] at org.h2.jdbc.JdbcConnection.prepareStatement(JdbcConnection.java:267) [error] at com.jolbox.bonecp.ConnectionHandle.prepareStatement(ConnectionHandle.java:820) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:193) [error] ... 80 more My model looks like this: @Entity @Table(name = "industry") public class Industry extends Model { @Id public Long id; public String name; public String shortname; // called in the view to trigger lazy-loading public String getName() { return name; } public static Finder<Long, Industry> find = new Finder<Long, Industry>(Long.class, Industry.class); } ... and finally the relevant part from my initial evolution: create table industry ( id bigint not null, name varchar(255), shortname varchar(255), constraint pk_industry primary key (id) } create sequence industry_seq start with 1000; Everything works fine running on my PostgreSQL DB, and from my point of view the code is not any different from the Play2.0 Computer Database Sample. I am happy for any help - thanks! Regards, Alex

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  • Why doesn't EnumerableRowCollection<DataRow>.Select() compile like this?

    - by David Fox
    This works: from x in table.AsEnumerable() where x.Field<string>("something") == "value" select x.Field<decimal>("decimalfield"); but, this does not: from x in table.AsEnumerable() .Where(y=>y.Field<string>("something") == "value") .Select(y=>y.Field<decimal>("decimalfield")); I also tried: from x in table.AsEnumerable() .Where(y=>y.Field<string>("something") == "value") .Select(y=>new { name = y.Field<decimal>("decimalfield") }); Looking at the two overloads of the .Select() method, I thought the latter two should both return EnumerableRowCollection, but apparently I am wrong. What am I missing?

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  • onfocus with select box in scriptaculous

    - by Stacia
    I have some code like so: $('product_name').onfocus=function() { this.focused=true; }; $('product_name').onblur=function() { this.focused=false; } function getEnter(evt){ if (evt.keyCode == Event.KEY_RETURN) { if ($('product_name').focused ) { ... However, if I try to add this to a select box and change the function to an ||, it breaks. Do select boxes work differently since they can be continuously selected? .focus seemed to make a difference (brighter color when in focus). I am trying to do a search on enter if either the product_name or the select box is focused and do something else otherwise. I have it set up now so everything works except the select box. Thanks.

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  • DataTable DataRow Select String with Quotation Marks

    - by RBrattas
    Hi, My string include quotation mark; the select statement crash. vm_TEXT_string = "Hello 'French' People"; vm_DataTable_SELECT_string = "[MyField] = '" + vm_TEXT_string + "'"; DataRow[] o_DataRow_ARRAY_Found = vco_DataTable.Select (vm_DataTable_SELECT_string); I cannot use this statement: string filter = "[MyColumn]" + " LIKE '%" + SearchWord + "%'"; I found string format: DataRow[] oDataRow = oDataSet.Tables["HasDiseas"].Select ( string.Format ( "DName='{0}'", DiseasListBox.SelectedItem.ToString () ) ); Any suggestion to selecta string with quotation mark? Thank you, Rune

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  • Solve the IE select overlap bug

    - by Vincent Robert
    When using IE, you cannot put an absolutely positioned div over a select input element. That's because the select element is considered an ActiveX object and is on top of every HTML element in the page. I already saw people hiding selects when opening a popup div, that leads to pretty bad user experience having controls disappearing. FogBugz actually had a pretty smart solution (before v6) of turning every select into text boxes when a popup was displayed. This solved the bug and tricked the user eye but the behavior was not perfect. Another solution is in FogBugz 6 where they no more use the select element and recoded it everywhere. Last solution I currently use is messing up the IE rendering engine and force it to render the absolutely positioned div as an ActiveX element too, ensuring it can live over a select element. This is achieved by placing an invisible iframe inside the div and styling it with: #MyDiv iframe { position: absolute; z-index: -1; filter: mask(); border: 0; margin: 0; padding: 0; top: 0; left: 0; width: 9999px; height: 9999px; overflow: hidden; } Anyone has a even better solution than this one ? EDIT: The purpose of this question is as much informative as it is a real question. I find the iframe trick to be a good solution but I am still looking for improvement like removing this ugly useless iframe tag that degrade accessibility.

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  • Excel VBA Select Case Loop Sub

    - by Zack
    In my excel file, I have a table setup with formulas. with Cells from Range("B2:B12"), Range ("D2:D12"), and etc every other row containing the answers to these formulas. for these cells (with the formula answers), I need to apply conditional formatting, but I have 7 conditions, so I've been using "select case" in VBA to change their interior background based on their number. I have the select case function currently set up within the sheet code, as opposed to it's own macro Private Sub Worksheet_Change(ByVal Target As Range) Dim iColor As Integer If Not Intersect(Target, Range("B2:L12")) Is Nothing Then Select Case Target Case 0 iColor = 2 Case 0.01 To 0.49 iColor = 36 Case 0.5 To 0.99 iColor = 6 Case 1 To 1.99 iColor = 44 Case 2 To 2.49 iColor = 45 Case 2.5 To 2.99 iColor = 46 Case 3 To 5 iColor = 3 End Select Target.Interior.ColorIndex = iColor End If End Sub but using this method, you must be actually entering the value into the cell for the formatting to work. which is why I want to write a subroutine to to do this as a macro. I can input my data, let the formulas work, and when everything is ready, I can run the macro and format those specific cells. I want an easy way to do this, obviously I could waste a load of time, typing out all the cases for every cell, but I figured it'd be easier with a loop. how would I go about writing a select case loop to change the formatting on a a specific range of cells every other row? thank you in advance.

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  • tsql replace value on select

    - by Zelter Ady
    I have a column (SERVICE_ID) in my table where I can have only 3 values: 0, 1 and 2. I'd like on select, on displayed result table, to change those value with some english words. select client, SERVICE_ID from customers displays now: -------------------------- | John | 1 | Mike | 0 | Jordan | 1 | Oren | 2 -------------------------- I'd like to change the query to get: -------------------------- | John | QA | Mike | development | Jordan | QA | Oren | management -------------------------- There is any way to do this using only the select?

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  • by jquery, set to option of html-select element selected atribude by text, not value

    - by loviji
    hello. I have a select element. <select class='cSelectType'> <option value="1">one</option> <option value="2">two</option> <option value="3">three</option> <option value="4">four</option> <option value="5">five</option> </select> i can by jquery set option value selected like this: $('.cSelectType option[value=4]').attr('selected', 'selected'); And select element will show "Four". By i wont something like this: $('.cSelectType option[xxx=Four]').attr('selected', 'selected'); i.e By text set selected attribute. some ideas please.

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