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  • What's -mutableSetValueForKey: returning, actually? Is that something special?

    - by dontWatchMyProfile
    From the docs: You usually access to-many relationships using mutableSetValueForKey:, which returns a proxy object that both mutates the relationship and sends appropriate key-value observing notifications for you. So this returns an "intelligent" NSMutableSet which automatically lets the context delete objects when they get deleted from the set, and reverse? Is that a proxy object?

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  • Scan HTML for values with a special character before them.

    - by DogPooOnYourShoe
    Say I have values on my page, like #100 #246, What I want to do is scan the page for values with a # before them and then alter them to put a hyperlink on it $MooringNumbers = '#!' . $MooringNumbers . ' | ' . '#!' . $row1["Number"]; } $viewedResult = '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; preg_replace('/#!(\d\d\d)/', '<a href="update.php?id=${1}">${1}</a>', $viewedResult); echo $viewedResult; This is the broken code which doesnt work.

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  • Set tier price on different products (special conditions) in Magento?

    - by user1547625
    Let’s say I sell mobile phones. I might sell phones with the following tiered pricing iPhone4 (1x$200ea. 3x$150ea. 10x$100ea.) iPhone4s (1x$300ea. 3x$250ea. 10x$200ea.) iPhone5 (1x$500ea. 3x$400ea. 10x$1300ea.) Plus maybe I sell Samsungs, Nokias, accessories, etc. So let’s say a customer wants to buy 3 iphones, but they want 1x iPhone 4, 1x iPhone 4s and 1x iPhone 5. Instead of getting the single unit price for each, we would want to group iphones, so that they would get the 3x price for each unit. So they would spend $150 on the iPhone 4, $250 on the iPhone 4s and $400 on the iPhone 5.... We’d have several categories and could create some type of spreadsheet for you, but would want to also have the ability to set up this categorization in the future. So please tell me how to get this done from magento admin or any other way?

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  • Code Golf: Code 39 Bar Code

    - by gwell
    The challenge The shortest code by character count to draw an ASCII representation of a Code 39 bar code. Wikipedia article about Code 39: http://en.wikipedia.org/wiki/Code_39 Input The input will be a string of legal characters for Code 39 bar codes. This means 43 characters are valid: 0-9 A-Z (space) and -.$/+%. The * character will not appear in the input as it is used as the start and stop characters. Output Each character encoded in Code 39 bar codes have nine elements, five bars and four spaces. Bars will be represented with # characters, and spaces will be represented with the space character. Three of the nine elements will be wide. The narrow elements will be one character wide, and the wide elements will be three characters wide. A inter-character space of a single space should be added between each character pattern. The pattern should be repeated so that the height of the bar code is eight characters high. The start/stop character * (bWbwBwBwb) would be represented like this: # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # ^ ^ ^^ ^ ^ ^ ^^^ | | || | | | ||| narrow bar -+ | || | | | ||| wide space ---+ || | | | ||| narrow bar -----+| | | | ||| narrow space ------+ | | | ||| wide bar --------+ | | ||| narrow space ----------+ | ||| wide bar ------------+ ||| narrow space --------------+|| narrow bar ---------------+| inter-character space ----------------+ The start and stop character * will need to be output at the start and end of the bar code. No quiet space will need to be included before or after the bar code. No check digit will need to be calculated. Full ASCII Code39 encoding is not required, just the standard 43 characters. No text needs to be printed below the ASCII bar code representation to identify the output contents. The character # can be replaced with another character of higher density if wanted. Using the full block character U+2588, would allow the bar code to actually scan when printed. Test cases Input: ABC Output: # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # Input: 1/3 Output: # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # Input: - $ (minus space dollar) Output: # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # Code count includes input/output (full program).

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  • Can get members, but not count of NSMutableArray

    - by Curyous
    I'm filling an NSMutableArray from a CoreData call. I can get the first object, but when I try to get the count, the app crashes with Program received signal: “EXC_BAD_ACCESS”. How can I get the count? Here's the relevant code - I've put a comment on the line where it crashes. - (void)viewDidLoad { [super viewDidLoad]; managedObjectContext = [[MySingleton sharedInstance] managedObjectContext]; if (managedObjectContext != nil) { charactersRequest = [[NSFetchRequest alloc] init]; charactersEntity = [NSEntityDescription entityForName:@"Character" inManagedObjectContext:managedObjectContext]; [charactersEntity retain]; [charactersRequest setEntity:charactersEntity]; [charactersRequest retain]; NSError *error; characters = [[managedObjectContext executeFetchRequest:charactersRequest error:&error] mutableCopy]; if (characters == nil) { NSLog(@"Did not get results for characters: %@", error.localizedDescription); } else { [characters retain]; NSLog(@"Found some character(s)."); Character* character = (Character *)[characters objectAtIndex:0]; NSLog(@"Name of first one: %@", character.name); NSLog(@"Found %@ character(s).", characters.count); // Crashes on this line with - Program received signal: “EXC_BAD_ACCESS”. } } } And previous declarations from the header file: @interface CrowdViewController : UITableViewController { NSManagedObjectContext *managedObjectContext; NSFetchRequest *charactersRequest; NSEntityDescription *charactersEntity; NSMutableArray *characters; } I'm a bit perplexed and would really appreciate finding out what is going on.

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  • HOWTO: Disable complex password policy on Hyper-V Server 2008?

    - by Ian Boyd
    How do you disable the password complexity requirements on a Microsoft Hyper-V Server 2008 R2? Keep in mind that when you log into the server, the only UI you have is: And you cannot run gpedit.msc: C:\Users\Administrator>gpedit.msc 'gpedit.msc' is not recognized as an internal or external command, operable program or batch file. because there are no .msc snap-ins installed with Microsoft Hyper-V Server 2008 R2. The problem comes when you're trying to add an account to the server, so you can manage it, but it doesn't like most passwords: And, predictably, typing NET HELPMSG 2245 gives you The password does not meet the password policy requirements. Check the minimum p assword length, password complexity and password history requirements. i hoped it would have been a friendly user experience, and either: offered to disable the password policy tell me how to disable the password policy tell me how to check the minimum password length, password complexity and password history requirements. Password Complexity Requirements The Microsoft's default password complexity for Server Core is: Passwords cannot contain the user’s account name or parts of the user’s full name that exceed two consecutive characters. Passwords must be at least six characters in length. Passwords must contain characters from three of the following four categories: 1.English uppercase characters (A through Z). 2.English lowercase characters (a through z). 3.Base 10 digits (0 through 9). 4.Non-alphabetic characters (for example, !, $, #, %). External links Technet Forums: Hyper-V Server disable complex passwords Technet: Passwords must meet complexity requirements of the installed password filter Update: 2k views? So many people keep coming coming to it: up-vote it!

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  • SEO issue red characters in source code? &gt; Why? Syntax highlighting? browser source code?

    - by judi
    SEO issue red characters Hi all I'm building webstes using dreamweaver, but when I look at the source code it is red for &quot; characters. I'm told anything appearing in red puts off Google's seo. Does anyone know why this appears in red? For example when I view code source on the site i get the gt; in red <a href="miss-sold-mortgages.html" class="darkblue">Find out more&gt;&gt;</a></span> </div> Thanks for your help Regards Judi

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  • How can I enable special Fn-Keys on my on lenovo s206 (e.g. touchpad on/off)?

    - by user2546783
    I can turn the touchpad off in the mouse settings, but two things won't work: The "disable while typing" option The standard on/off button for the touch pad won't work (it's the one with the little touchpad symbol crossed off, on the F6 key). I've tried any of the following combinations: Alt+F6 Fn+F6 Ctrl+F6 Super+F6 Shift+F6. Almost all the other keys of that kind work, like brightness control, volume control, Wifi toggle, but this one and the mic off and camera off won't work.

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  • Excel code question

    - by karatekid
    I have 2 different excel files(all people and special people) that i want to kick special people from all people. Cant find a way.. if you don't understand check my example: all people special people ---------- -------------- 1-john 1-john 2-jim 2-marry 3-mariah 4-russel 5-marry I want: all people special people ---------- -------------- 1-jim 1-john 2-mariah 2-marry 3-russel

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  • In SQL Server changing column varchar(255) nvarchar

    - by JD
    Hi, I am using SQL server 2008 express and some of our columns are defined as varchar(255). Should I convert these columns to NvarChar(255) or nvarchar(max)? The reason I ask is I read that nvarchar(255) for unicode characters would actually store 1/2 the number of characters (since unicode characters are 2 bytes) whereas 255 with varchar() would allow me to store 255 characters (or is it 255 - 2 for the offset). Would there be any performance hits using nvarchar(max)? JDs

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  • Decode base64 data as array in Python

    - by skerit
    I'm using this handy Javascript function to decode a base64 string and get an array in return. This is the string: base64_decode_array('6gAAAOsAAADsAAAACAEAAAkBAAAKAQAAJgEAACcBAAAoAQAA') This is what's returned: 234,0,0,0,235,0,0,0,236,0,0,0,8,1,0,0,9,1,0,0,10,1,0,0,38,1,0,0,39,1,0,0,40,1,0,0 The problem is I don't really understand the javascript function: var base64chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'.split(""); var base64inv = {}; for (var i = 0; i < base64chars.length; i++) { base64inv[base64chars[i]] = i; } function base64_decode_array (s) { // remove/ignore any characters not in the base64 characters list // or the pad character -- particularly newlines s = s.replace(new RegExp('[^'+base64chars.join("")+'=]', 'g'), ""); // replace any incoming padding with a zero pad (the 'A' character is zero) var p = (s.charAt(s.length-1) == '=' ? (s.charAt(s.length-2) == '=' ? 'AA' : 'A') : ""); var r = []; s = s.substr(0, s.length - p.length) + p; // increment over the length of this encrypted string, four characters at a time for (var c = 0; c < s.length; c += 4) { // each of these four characters represents a 6-bit index in the base64 characters list // which, when concatenated, will give the 24-bit number for the original 3 characters var n = (base64inv[s.charAt(c)] << 18) + (base64inv[s.charAt(c+1)] << 12) + (base64inv[s.charAt(c+2)] << 6) + base64inv[s.charAt(c+3)]; // split the 24-bit number into the original three 8-bit (ASCII) characters r.push((n >>> 16) & 255); r.push((n >>> 8) & 255); r.push(n & 255); } // remove any zero pad that was added to make this a multiple of 24 bits return r; } What's the function of those "<<<" and "" characters. Or is there a function like this for Python?

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  • Regular Expression for username

    - by neobie
    I need help on regular expression on the condition (4) below: Begin with a-z End with a-z0-9 allow 3 special characters like ._- The characters in (3) must be followed by alphanumeric characters, and it cannot be followed by any characters in (3) themselves. Not sure how to do this. Any help is appreciated, with the sample and some explanations.

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  • Mac 10.6 Universal Binary scipy: cephes/specfun "_aswfa_" symbol not found

    - by Markus
    Hi folks, I can't get scipy to function in 32 bit mode when compiled as a i386/x86_64 universal binary, and executed on my 64 bit 10.6.2 MacPro1,1. My python setup With the help of this answer, I built a 32/64 bit intel universal binary of python 2.6.4 with the intention of using the arch command to select between the architectures. (I managed to make some universal binaries of a few libraries I wanted using lipo.) That all works. I then installed scipy according to the instructions on hyperjeff's article, only with more up-to-date numpy (1.4.0) and skipping the bit about moving numpy aside briefly during the installation of scipy. Now, everything except scipy seems to be working as far as I can tell, and I can indeed select between 32 and 64 bit mode using arch -i386 python and arch -x86_64 python. The error Scipy complains in 32 bit mode: $ arch -x86_64 python -c "import scipy.interpolate; print 'success'" success $ arch -i386 python -c "import scipy.interpolate; print 'success'" Traceback (most recent call last): File "<string>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/interpolate/__init__.py", line 7, in <module> from interpolate import * File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/interpolate/interpolate.py", line 13, in <module> import scipy.special as spec File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/__init__.py", line 8, in <module> from basic import * File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/basic.py", line 8, in <module> from _cephes import * ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so, 2): Symbol not found: _aswfa_ Referenced from: /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so Expected in: flat namespace in /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so Attempt at tracking down the problem It looks like scipy.interpolate imports something called _cephes, which looks for a symbol called _aswfa_ but can't find it in 32 bit mode. Browsing through scipy's source, I find an ASWFA subroutine in specfun.f. The only scipy product file with a similar name is specfun.so, but both that and _cephes.so appear to be universal binaries: $ cd /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/ $ file _cephes.so specfun.so _cephes.so: Mach-O universal binary with 2 architectures _cephes.so (for architecture i386): Mach-O bundle i386 _cephes.so (for architecture x86_64): Mach-O 64-bit bundle x86_64 specfun.so: Mach-O universal binary with 2 architectures specfun.so (for architecture i386): Mach-O bundle i386 specfun.so (for architecture x86_64): Mach-O 64-bit bundle x86_64 Ho hum. I'm stuck. Things I may try but haven't figured out how yet include compiling specfun.so myself manually, somehow. I would imagine that scipy isn't broken for all 32 bit machines, so I guess something is wrong with the way I've installed it, but I can't figure out what. I don't really expect a full answer given my fairly unique (?) setup, but if anyone has any clues that might point me in the right direction, they'd be greatly appreciated. (edit) More details to address questions: I'm using gfortran (GNU Fortran from GCC 4.2.1 Apple Inc. build 5646). Python 2.6.4 was installed more-or-less like so: cd /tmp curl -O http://www.python.org/ftp/python/2.6.4/Python-2.6.4.tar.bz2 tar xf Python-2.6.4.tar.bz2 cd Python-2.6.4 # Now replace buggy pythonw.c file with one that supports the "arch" command: curl http://bugs.python.org/file14949/pythonw.c | sed s/2.7/2.6/ > Mac/Tools/pythonw.c ./configure --enable-framework=/Library/Frameworks --enable-universalsdk=/ --with-universal-archs=intel make -j4 sudo make frameworkinstall Scipy 0.7.1 was installed pretty much as described as here, but it boils down to a simple sudo python setup.py install. It would indeed appear that the symbol is undefined in the i386 architecture if you look at the _cephes library with nm, as suggested by David Cournapeau: $ nm -arch x86_64 /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so | grep _aswfa_ 00000000000d4950 T _aswfa_ 000000000011e4b0 d _oblate_aswfa_data 000000000011e510 d _oblate_aswfa_nocv_data (snip) $ nm -arch i386 /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so | grep _aswfa_ U _aswfa_ 0002e96c d _oblate_aswfa_data 0002e99c d _oblate_aswfa_nocv_data (snip) however, I can't yet explain its absence.

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  • C# Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    Hello guys, I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program: http://img43.imageshack.us/img43/2118/11618743.jpg

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  • Microsoft Chart control converts \n in file names to newline characters.

    - by xpda
    I am using a Microsoft Chart control (system.windows.forms.datavisualization.charting.chart) in a Windows forms application, vb.net 2008. I use folder paths for the x values in a pie chart. Chart control converts a name like c:\newfolder into c:[newline]ewfolder. I tried adding a slash, making it c:\\newfolder, but this only changes it to c:\[newline]ewfolder. Is there a workaround for this behavior?

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  • Why do I get "Illegal characters in path" while using XmlDiff to compare 2 xml files?

    - by Patryk
    I have a problem trying to compare 2 xml files with the XmlDiff library from Microsoft. I am using an overloaded function which passes 2 xmls as strings : xmldiff = new XmlDiff(XmlDiffOptions.IgnoreChildOrder | XmlDiffOptions.IgnorePrefixes | XmlDiffOptions.IgnoreNamespaces); bool identical = xmldiff.Compare(first, last, false); where first and last look more or less like this : <?xml version="1.0" encoding="ISO-8859-1"?> <breakfast_menu> <food> <name>Belgian Waffles</name> <price>$5.95</price> <description>two of our famous Belgian Waffles with plenty of real maple syrup</description> <calories>650</calories> </food> <food> <name>Strawberry Belgian Waffles</name> <price>$7.95</price> <description>light Belgian waffles covered with strawberries and whipped cream</description> <calories>900</calories> </food> </breakfast_menu> And I get this error

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  • How do I convert integers to characters in C#?

    - by Mike Webb
    I am trying to convert an index of 1 to 27 into the corresponding uppercase letter. I know that in C++ I could type this: char letter = 'A' + (char)(myIndex % 27); This same code does not work in C#. How can I accomplish this task in C#? EDIT: I'd rather not have to encode an enum or switch statement for this if there is a better mathematical solution like the one above.

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  • Objective-C - How To Remove Characters From a String?

    - by iAm
    I have a UILable that has a formatted String (formatted for currency), so there is a dollar sign, $21.34. In the core data entity the attribute is of a type double, I am using an NSDecimalNumber to save to the database. self.purchase.name = self.nameTextField.text; NSString *string = self.amountLabel.text NSDecimalNumber *newAmount = [[NSDecimalNumber alloc] initWithString:string]; NSLog(@"%@", string); // THIS RETURNS NaN, because of dollar sign i think NSManagedObjectContext *context = self.purchase.managedObjectContext; NSError *error = nil; if (![context save:&error]) { NSLog(@"Unresolved error %@, %@", error, [error userInfo]); abort(); } Anyway, I need this to not be NaN, so my thinking is to remove the dollar sign, but i do not know how to do that, or perhaps there is a better way to accomplish my goal.

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