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  • How to compare a string with an option value

    - by user225269
    I have this html form which has options: <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> <option value="ADDRESS">Address</option> </select></td></td> </tr> And I'm trying to have this as the form action: if ('{$_POST["ADDRESS"]}'="ADDRESS") Which will compare if the value in the option in the html form matches the word "Address". If it matches then it will execute this query: $saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); Please I need help in here, I thinks its wrong: if ('{$_POST["ADDRESS"]}'="ADDRESS")

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  • curl post picture multipart/form-data, php cURL need help!

    - by user331071
    I'm trying to upload a picture to a specific website using php cURL but I don't really understand what parameters do I need to send because the data looks a bit weird . Here is what i got with the http analyzer Type : multipart/form-data; boundary=---------------------------182983931283 -----------------------------182983931283 Content-Disposition: form-data; name="file"; filename="Blue hills.jpg" Content-Type: image/jpeg Here appears the souce of the image itself like "ÿØÿàÿØÿàÿØÿàÿØÿàÿØÿàÿØÿà" -----------------------------182983931283 Content-Disposition: form-data; name="action" images -----------------------------182983931283 Content-Disposition: form-data; name="anonymous_email" Y -----------------------------182983931283 Content-Disposition: form-data; name="site_id" 1 -----------------------------182983931283 and so on other parameters. The issue that I have is that I don't understand what is the boundary, where do I get it from (because it doesn't appear in the html document that generates the POST and how should I make the post . If you would give me a simple example to post the above parameters to http://example.com I will definitely get the trick . Currently I'm using the following function to make the post : function processPicturesPage($title, $price, $numbedrooms, $description) { //Set the login parameters and initiate the Login process $fields = array( "changedImages" = "", "site_id" = "1", "posting_id" = "", "current_live_date" = "", "images_loaded" = "", "image_actions" = "", "title" = $title, ); foreach($fields as $key=$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); $URL = "http://www.example.com/cgi-bin/add_posting.pl"; return $this-processCurlrequest($URL, count($fields), $fields_string); } and in the processCurlrequest I have the curl options (cookies etc) and url .

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  • Returning an integer from a select box - JavaScript

    - by Ross
    Very simply, I want to be able to access the year from the select box as an integer. In my test, my alertbox is telling me the value is undefined. <form name="form1" method="post" action=""> <label>birth year <select name="birth year" id="dueYear"> <OPTION VALUE='' SELECTED>--Year--</OPTION> <OPTION VALUE='2011'>2011</OPTION> <OPTION VALUE='2010'>2010</OPTION> <OPTION VALUE='2009'>2009</OPTION></SELECT> </select> </label> </form> <script type="text/javascript"> var dueDateYear = parseInt(document.getElementById("dueYear")); </script> <button onclick="alert(dueDateYear)">Click Me!</button> All I want it to do, is tell me the year I have selected -- any help would be appreciated, I am a newbie :(

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  • Jquery Returning values to original

    - by Cam
    So my script works perfectly, but here is the issue, I have buttons (Sprite action here) that are 40px height, but the top 20 only shows perfectly. When you click the button ie img the bottom 20px show perfecto! but... Issue, i included in my script a way to return all others to there default (only one should be selected) now, how can I fix this issue that I seem unable to correct as I can select multiple of them ** USERS can switch ** The last part of the script that is the issue. Thanks $(document).ready(function() { $('.form_sub').hide(); $('.theader').addClass('active'); $('.theader_t').click(function() { $('.form_header').show(); $('.form_sub').hide(); $('.theader').addClass('active'); $('.sub_theader').removeClass('active'); }); $('.sub_theader_t').click(function() { $('.form_header').hide(); $('.form_sub').show(); $('.theader').removeClass('active'); $('.sub_theader').addClass('active'); }); $('.top_head_img').click(function() { $(this).css({ position: 'relative', bottom: '20px' }).siblings().css( 'bottom', '0' ); }); }); <ul class="top_head"> <li> <a href="javascript:void(0)" onClick="selectPic5('top');"><img src="custom/images/top2.jpg" alt="Left" border="0" class="top_head_img"/></a> </li> <li> <a href="javascript:void(0)" onClick="selectPic5('center');"><img src="custom/images/mid2.jpg" alt="Center" border="0" class="top_head_img"/></a> </li> <li> <a href="javascript:void(0)" onClick="selectPic5('bottom');"><img src="custom/images/bot2.jpg" alt="Right" border="0" class="top_head_img"/></a> </li> </ul>

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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Xcode: Display Login View in applicationDidBecomeActive

    - by Patrick
    In my app I would like to show a login screen - which will be displayed when the app starts and when the app becomes active. For reference, I am using storyboards, ARC and it is a tabbed bar application. First off, I have this method which returns the topViewController. - (UIViewController *)topViewController:(UIViewController *)rootViewController { if (rootViewController.presentedViewController == nil) { return rootViewController; } if ([rootViewController.presentedViewController isMemberOfClass:[UINavigationController class]]) { UINavigationController *navigationController = (UINavigationController *)rootViewController.presentedViewController; UIViewController *lastViewController = [[navigationController viewControllers] lastObject]; return [self topViewController:lastViewController]; } UIViewController *presentedViewController = (UIViewController *)rootViewController.presentedViewController; return [self topViewController:presentedViewController]; } And I call this method here: - (void)applicationDidBecomeActive:(UIApplication *)application { if ( ... ) { // if the user needs to login PasswordViewController *passwordView = [[PasswordViewController alloc] init]; UIViewController *myView = [self topViewController:self.window.rootViewController]; [myView presentModalViewController:passwordView animated:NO]; } } To an extent this does work - I can call a method in viewDidAppear which shows an alert view to allow the user to log in. However, this is undesirable and I would like to have a login text box and other ui elements. If I do not call my login method, nothing happens and the screen stays black, even though I have put a label and other elements on the view. Does anyone know a way to resolve this? My passcode view is embedded in a Navigation Controller, but is detached from the main storyboard.

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  • ASP.NET MVC Viewmodel trouble...

    - by ile
    I've already started similar topic, but still didn't find final solution... So here I am with new one :) ... I'm developing NerdDinner from scratch and now I came to point where I define DinnerViewModel. Following these instructions (starting from Listing 5) I came to this: namespace Nerd.Controllers { // View Model Classes public class DinnerViewModel { public DinnerViewModel(List<Dinner> dinners) { this.Dinners = dinners; } public List<Dinner> Dinners { get; private set; } } public class DinnerController : Controller { private DinnerRepository dinnerRepository = new DinnerRepository(); .... public ActionResult NewDinners() { // Create list of products var dinners = new List<Dinner>(); dinners.Add(new Dinner(/*Something to add*/)); // Return view return View(new DinnerViewModel(dinners)); } } } Also, the Dinner table in this new version of NerdDinner is a bit shortened (it contains of DinnerID, Title, EventDate and Description fields). No matter what I try to add here dinners.Add(new Dinner(/*Something to add*/)); I always get following error Error 1 'Nerd.Model.Dinner' does not contain a constructor that takes '1' arguments C:\Documents and Settings\ilija\My Documents\Visual Studio 2008\Projects\Nerd\Nerd\Controllers\DinnerController.cs 150 25 Nerd Because I'm total beginner in C# and generally OOP, I have no idea what to do here... I suppose I need to declare a constructor, but how and where exactly? Thanks, Ile

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  • Problem executing trackPageview with Google Analytics.

    - by dmrnj
    I'm trying to capture the clicks of certain download links and track them in Google Analytics. Here's my code var links = document.getElementsByTagName("a"); for (var i = 0; i < links.length; i++) { linkpath = links[i].pathname; if( linkpath.match(/\.(pdf|xls|ppt|doc|zip|txt)$/) || links[i].href.indexOf("mode=pdf") >=0 ){ //this matches our search addClickTracker(links[i]); } } function addClickTracker(obj){ if (obj.addEventListener) { obj.addEventListener('click', track , true); } else if (obj.attachEvent) { obj.attachEvent("on" + 'click', track); } } function track(e){ linkhref = (e.srcElement) ? e.srcElement.pathname : this.pathname; pageTracker._trackPageview(linkhref); } Everything up until the pageTracker._trackPageview() call works. In my debugging linkhref is being passed fine as a string. No abnormal characters, nothing. The issue is that, watching my http requests, Google never makes a second call to the tracking gif (as it does if you call this function in an "onclick" property). Calling the tracker from my JS console also works as expected. It's only in my listener. Could it be that my listener is not deferring the default action (loading the new page) before it has a chance to contact Google's servers? I've seen other tracking scripts that do a similar thing without any deferral.

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  • How to fetch populated associated models in CakePHP when calling read()

    - by Code Commander
    I have the following Models: class Site extends AppModel { public $name = "Site"; public $useTable = "site"; public $primaryKey = "id"; public $displayField = 'name'; public $hasMany = array('Item' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { if($isAdmin) { return true; } return array_key_exists($this->id, $allowedSites); } } and class Item extends AppModel { public $name = "Item"; public $useTable = "item"; public $primaryKey = "id"; public $displayField = 'name'; public $belongsTo = array('Site' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { // My problem appears to be the next line: return $this->Site->canView($userId, $isAdmin); } } In my controller I am doing something like this: $result = $this->Item->read(null, $this->request->id); // Verify permissions if(!$this->Item->canView($this->Session->read('userId'), $this->Session->read('isAdmin'))) { $this->httpCodes(403); die('Permission denied.'); } I notice that in Item->canView() $this->data['Site'] is populated with the column data from the site table. But it merely an array and not an object. On the other hand $this->Site is a Site object, but it has not been populated with the column data from the site table like $this->data. What is the proper way to have CakePHP get the associated model as the object and containing the data? Or am I going about this all wrong? Thanks!

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  • Passing Values to Controllers

    - by Dru
    I'm trying to allow users to 'favorite' links (that is, create a new Favorite record with their user_id and the link_id) This is what I have so far.. When I click favorite (as a user), the new record is assigned to the user_id but the link_id field is nil. How can I pass the link_id into my FavoritesController? My View Code Added Link Model Code class FavoritesController < ApplicationController def create @user = User.find(session[:user_id]) @favorite = @user.favorites.create :link_id => params[:id] redirect_to :back end end The Favorite model belongs to :user and :link Note: I've also tried this but when I click 'favorite', there's an error "Couldn't find Link without an ID." Update <%= link_to "Favorite", :controller => :favorites, :action => :create, :link_id => link.id %> with class FavoritesController < ApplicationController def create @user = User.find(session[:user_id]) @favorite = @user.favorites.create :link_id => :params[:link_id] redirect_to :back end end Returns "can't convert Symbol into Integer" app/controllers/favorites_controller.rb:4:in [] app/controllers/favorites_controller.rb:4:in create I've tried forcing it into an Integer several ways with .to_i

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  • Desktop-like UI implementations for Java web applications?

    - by localshred
    At work we're discussing upgrading our view layer for our web application. We're currently running an old and "modified" version of FreeMarker Classic, which is a pain to work with. One of our developers suggested using a Component UI style architecture similar to desktop style environments. Essentially, this would mean that you would build custom HTML components as Java Classes that the controller would render into the Document view. This would completely take away the need to write HTML into a view layer. The Components would generate the view layer for you. For instance, the following rendered HTML: <h1>I am a title</h1> <p>I am a paragraph.</p> Would be generated by doing something like: String titleString = "I am a title"; html.elements.Heading heading = new html.elements.Heading(Heading.H1, titleString); String paraString = "I am a paragraph."; html.elements.Paragraph paragraph = new html.elements.Paragraph(paraString); PrintWriter somePrintWriter = new PrintWriter(); Document document = new Document(); document.addElement(heading); document.addElement(paragraph); document.compose(somePrintWriter); The above code is just an example, don't critique the names or style, I just wrote it for a quick demonstration of what we may be trying to accomplish. I'm trying to determine if this has been done before in Java, and if so if there are any links I can be pointed to. I've been researching it as much as I can, but haven't found any implementations that completely remove the template layer (such as JSP or JSF). Thanks!

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  • Why rails app is redirecting unexpectedly instead of matching the route?

    - by ruevaughn
    I asked this question earlier and thought it was fixed, but it's not. Previous question here My problem is I am trying to set my routes so that when I type in localhost:3000/sites/admin It should redirect to localhost:3000/en/sites/admin here is my routes.rb file scope ":locale", locale: /#{I18n.available_locales.join("|")}/ do get "log_out" => "sessions#destroy", as: "log_out" get "log_in" => "sessions#new", as: "log_in" resources :sites, except: [:new, :edit, :index, :show, :update, :destroy, :create] do collection do get :home get :about_us get :faq get :discounts get :services get :contact_us get :admin get :posts end end resources :users resources :abouts resources :sessions resources :coupons resources :monthly_posts resources :reviews resources :categories do collection { post :sort } resources :children, :controller => :categories, :only => [:index, :new, :create, :new_subcategory] end resources :products do member do put :move_up put :move_down end end resources :faqs do collection { post :sort } end root :to => 'sites#home' match "/savesort" => 'sites#savesort' end match '', to: redirect("/#{I18n.default_locale}") match '*path', to: redirect("/#{I18n.default_locale}/%{path}") But as of right now, it redirects to /en/en/en/en/en/en/en/en/en/en/sites/admin (adds en until browser complains). Any thoughts why it keeps adding /en?

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  • SQL Databases and table design/organization

    - by John McMullen
    (NOOB disclaimer) I'm working on a system (a type of map), that is accessed mostly via 3 fields: ID (auto incremented), X coordinate, and Y coordinate. As it is right now, i have all data on the map, stored in 1 table. Whenever the map display is loaded it simply queries the database for contents in x and y, and the DB gives the data (other fields in the same entry). If an item on the map is doing something, it has a flag saying its doing something, and then has an ID of the action in another table holding that type of 'actions'. Essentially, for all map data, its stored in 1 table. All actions of a certain type are stored in their own table. I'm a noob, and i'm wondering what the most effective/efficient structure for such a design? (a map that has items, and each item has stats/actions). I'm using PHP atm, using standard SQL queries to get my data. Should i split up the tables so that there are only x number of entries on a table? (coord range limits)? Should it just keep growing and growing? There's a lot of queries to the table... so just tryin to see what is best :/

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  • Have to click twice to submit the form

    - by phil
    Intended function: require user to select an option from the drop down menu. After user clicks submit button, validate if an option is selected. Display error message and not submit the form if user fails to select. Otherwise submit the form. Problem: After select an option, button has to be clicked twice to submit the form. I have no clue at all.. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style> p{display: none;} </style> </head> <script> $(function(){ // language as an array var language=['Arabic','Cantonese','Chinese','English','French','German','Greek','Hebrew','Hindi','Italian','Japanese','Korean','Malay','Polish','Portuguese','Russian','Spanish','Thai','Turkish','Urdu','Vietnamese']; $('#muyu').append('<option value=0>Select</option>'); //loop through array for (i in language) //js unique statement for iterate array { $('#muyu').append($('<option>',{id:'muyu'+i,val:language[i], html:language[i]})) } $('form').submit(function(){ alert('I am being called!'); // check if submit event is triggered if ( $('#muyu').val()==0 ) {$('#muyu_error').show(); } else {$('#muyu_error').hide(); return true;} return false; }) }) </script> <form method="post" action="match.php"> I am fluent in <select name='muyu' id='muyu'></select> <p id='muyu_error'>Tell us your native language</p> <input type="submit" value="Go"> </form>

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  • Objective C number keypad, custom comma button

    - by rom_j
    I'm trying to add a comma button on a number keypad that has previous, next and done buttons, so that it looks like this : Problem is, that the orange button does not respond to taps. Actually if I moved it above the "7" button and tapped it, the 7 would be tapped. So my orange button may be shown above the keyboard, but it's reacting to taps as if it were below. Here is an abstract of my code : -(void)textFieldDidBeginEditing:(UITextField *)textField{ UIView *inputAccessoryView = [[UIView alloc] initWithFrame:CGRectMake(0, 500, screenWidth, 40.0)]; // 3 buttons on top UIView *topToolbar = [[UIView alloc] initWithFrame:CGRectMake(0, 0.0, screenWidth, 40.0)]; [topToolbar addSubview:self.inputPrevButton]; [topToolbar addSubview:self.inputNextButton]; [topToolbar addSubview:self.inputDoneButton]; [inputAccessoryView addSubview:topToolbar]; // Comma button UIButton *commaButton = [UIButton buttonWithType:UIButtonTypeCustom]; [commaButton setFrame: CGRectMake(0, 204, 105, 52)]; [commaButton setTitle:@"." forState:UIControlStateNormal]; [commaButton addTarget:self action:@selector(addComma) forControlEvents:UIControlEventTouchUpInside]; [commaButton setBackgroundColor:[UIColor orangeColor]]; [inputAccessoryView addSubview:commaButton]; // Useless, but tried anyway [inputAccessoryView bringSubviewToFront:commaButton]; [textField setInputAccessoryView:self.inputAccessoryView]; } All I know is that I should not be doing this (which is actually not working), so what should I do ?

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  • Telerik MVC Grid won't load data into details table (subtable)

    - by henriksen
    I have a list of Plants and assosiated Projects. I want to output this in a table with all the Plants and use Telerik.Grid to expand a Plant, show a Telerik.Grid with associated Projects. I want the Projects to be dynamically loaded with Ajax. The code for the grid: @(Html.Telerik().Grid<PlantDto>() .Name("Plants") .Columns(columns => { columns.Bound(plant => plant.Title); }) .DetailView(details => details.ClientTemplate( Html.Telerik().Grid<ProjectDto>() .Name("Plant_<#= Id #>") .DataBinding(dataBinding => dataBinding.Ajax() .Select("ProjectsForPlant", "User", new { plantId = "<#= Id #>" })) .ToHtmlString() )) .DataBinding(dataBinding => dataBinding.Ajax().Select("PlantsForUser", "User")) ) The initial data is loaded into the grid just fine (the list of Plants) but when I expand a plant I just get an empty sub-table. Looking in FireBug there are no calls to the server. The controller that should serve the list of projects is never called. Anyone have an idea on what it could be?

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  • JAVASCRIPT - What am I doing incorrectly?

    - by DarkLightA
    LIVE CODE: http://jsfiddle.net/vy4nY/ I'm following this challenge, but I'm having some issues. I'm trying to make the Email Address box only appear when the checkbox is clicked on. What have I done incorrectly? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <title>JavaScript Challenges</title> <style type="text/css"> #emailpara {visibility:hidden;} </style> </head> <body> <form action=""> <fieldset> <legend>Email subscriptions</legend> <p id="subscribepara"> <label> <input type="checkbox" name="subscribe" id="subscribe"> Yes! I would like to receive the occasional newsletter via email. </label> </p> <p id="emailpara"> <label> Email Address: <input type="text" name="email" id="email"> </label> </p> </fieldset> </form> <script type="text/javascript"> document.getElementById('subscribe').onclick = (document.getElementById('subscribe').checked ? (document.getElementById('emailpara').style.visibility = 'visible') : (document.getElementById('emailpara').style.visibility = 'hidden')); </script> </body> </html>

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  • CanCan polymorphic resource access problem

    - by Call 'naive' True
    Hi everybody, i don't quite understand how to restrict access to links in this particular case with CanCan. I always get "Edit" link displayed. So i believe the problem is in my incorrect definition of cancan methods(load_ and authorize_). I have CommentsController like that: class CommentsController < ApplicationController before_filter :authenticate_user! load_resource :instance_name => :commentable authorize_resource :article def index @commentable = find_commentable #loading our generic object end ...... private def find_commentable params.each { |name, value| if name =~ /(.+)_id$/ return $1.classify.constantize.includes(:comments => :karma).find(value) end } end end and i have in comments/index.html.erb following code that render file from other controller: <%= render :file => "#{get_commentable_partial_name(@commentable)}/show.html.erb", :collection => @commentable %> you can think about "#{get_commentable_partial_name(@commentable)}" like just "articles" in this case. Content of "articles/show.html.erb": <% if can? :update, @commentable %> <%= link_to 'Edit', edit_article_path(@commentable) %> | <% end %> my ability.rb: class Ability include CanCan::Ability def initialize(user) user ||= User.new # guest user if user.role? :admin can :manage, :all elsif user.role? :author can :read, [Article, Comment, Profile] can :update, Article, :user_id => user.id end end end relations with models is: class Comment < ActiveRecord::Base belongs_to :commentable, :polymorphic => true, :dependent => :destroy ... end class Article < ActiveRecord::Base has_many :comments, :as => :commentable, :dependent => :destroy ... end i have tried debug this issue like that user = User.first article = Article.first ability = Ability.new(user) ability.can?(:update, article) and i always get "= true" in ability check Note: user.role == author and article.user_id != user.id if you need more information please write thank's for your time && sorry for my english

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  • How do I solve the .NET CF exception "Can't find PInvoke DLL"?

    - by Ignas Limanauskas
    This is to all the C# gurus. I have been banging my head on this for some time already, tried all kinds of advice on the net with no avail. The action is happening in Windows Mobile 5.0. I have a DLL named MyDll.dll. In the MyDll.h I have: extern "C" __declspec(dllexport) int MyDllFunction(int one, int two); The definition of MyDllFunction in MyDll.cpp is: int MyDllFunction(int one, int two) { return one + two; } The C# class contains the following declaration: [DllImport("MyDll.dll")] extern public static int MyDllFunction(int one, int two); In the same class I am calling MyDllFunction the following way: int res = MyDllFunction(10, 10); And this is where the bloody thing keeps giving me "Can't find PInvoke DLL 'MyDll.dll'". I have verified that I can actually do the PInvoke on system calls, such as "GetAsyncKeyState(1)", declared as: [DllImport("coredll.dll")] protected static extern short GetAsyncKeyState(int vKey); The MyDll.dll is in the same folder as the executable, and I have also tried putting it into the /Windows folder with no changes nor success. Any advice or solutions are greatly appreciated.

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  • Android How to get position of selected item from gridview without using onclicklistner, using ontouchlistner instead

    - by zonemikel
    I have a gridview, I need to do stuff on motioneven.action_down and do something for motioneven.action_up ... using onclicklistener is great but does not give me this needed functionality. Is there anyway to easily call the gridview and get its selected item in a ontouchlistener ? I've been having limited success with making my own implementation. Its hard to get the right x,y because if i call the child it gives me the x and y relative to the child so a button would be 0,0 to 48,48 but it does not tell you the actual location on the screen relative to the gridview or the screen itself. this is what i've been doing, its partially working so far. Grid.setOnTouchListener(new OnTouchListener() { public boolean onTouch(View v, MotionEvent event) { if (event.getAction() == MotionEvent.ACTION_DOWN) { int x = (int)event.getX(); int y = (int)event.getY(); int position = 0; int childCount = Grid.getChildCount(); Message msg = new Message(); Rect ButtonRect = new Rect(); Grid.getChildAt(0).getDrawingRect(ButtonRect); int InitialLeft = ButtonRect.left + 10; ButtonRect.offsetTo(InitialLeft, ButtonRect.top); // while(position < childCount){ if(ButtonRect.contains(x,y)){break;} if(ButtonRect.right + ButtonRect.width() > Grid.getWidth()) { ButtonRect.offsetTo(InitialLeft, ButtonRect.bottom);} position++; ButtonRect.offsetTo(ButtonRect.right, ButtonRect.top); } msg.what = position; msg.arg1 = ButtonRect.bottom; msg.arg2 = y; cHandler.sendMessage(msg); }// end if action up if (event.getAction() == MotionEvent.ACTION_UP) { } return false; } });

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  • Why isn't my submit button centered?

    - by William
    For some reason my submit button isn't centered. http://prime.programming-designs.com/test_forum/viewboard.php?board=0 #submitbutton{ margin: auto; border: 1px solid #DBFEF8; background-color: #DBFEF8; color: #000000; margin-top: 5px; width: 100px; height: 20px; } here's the html. <form method=post action=add_thread.php?board=<?php echo''.$board.''; ?>> <div id="formdiv"> <div class="fieldtext1">Name</div> <div class="fieldtext1">Trip</div> <input type="text" name=name size=25 /> <input type="text" name=trip size=25 /> <div class="fieldtext2">Comment</div> <textarea name=post rows="4" cols="70"></textarea> <div class="fieldtext2">Fortune</div> <input type="checkbox" name="fortune" value="fortune" /> </div> <input type=submit value="Submit" id="submitbutton"> </form>

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  • What could possibly be different between the table in a DataContext and an IQueryable<Table> when do

    - by Nate Bross
    I have a table, where I need to do a case insensitive search on a text field. If I run this query in LinqPad directly on my database, it works as expected Table.Where(tbl => tbl.Title.Contains("StringWithAnyCase") In my application, I've got a repository which exposes IQueryable objects which does some initial filtering and it looks like this var dc = new MyDataContext(); public IQueryable<Table> GetAllTables() { var ret = dc.Tables.Where(t => t.IsActive == true); return ret; } In the controller (its an MVC app) I use code like this in an attempt to mimic the LinqPad query: var rpo = new RepositoryOfTable(); var tables = rpo.GetAllTables(); // for some reason, this does a CASE SENSITIVE search which is NOT what I want. tables = tables.Where(tbl => tbl.Title.Contains("StringWithAnyCase"); return View(tables); The column is defiend as an nvarchar(50) in SQL Server 2008. Any help or guidance is greatly appreciated!

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  • jeditable table cell

    - by user666262
    Hi all, I am having an issue when using jeditable to edit a cell in a table. The project is the MVC 2 web application and the table has been put on the standard about page. How do i tell the script to call a specific method in the controller ? because it is currently just loading the entire page into the cell. This is the javascript: $(document).ready(function () { $('.editable').editable('http://localhost:2196/Home/About', { type: 'text', cancel: 'Cancel', event: 'dblclick', submit: 'OK', tooltip: 'double Click to edit...' }); }); This is the table : <% foreach (DataTableEditable.Models.Company item in (IEnumerable<DataTableEditable.Models.Company>)Model) {%> <tr id="<%= Html.Encode(item.ID) %>"> <td class="editable"><%= Html.Encode(item.Name) %> </td> <td><%= Html.Encode(item.Address) %> </td> <td><%= Html.Encode(item.Town) %> </td> </tr> <% }%> Thanks lots John

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  • Polymorphic urls with singular resources

    - by Brendon Muir
    I'm getting strange output when using the following routing setup: resources :warranty_types do resources :decisions end resource :warranty_review, :only => [] do resources :decisions end I have many warranty_types but only one warranty_review (thus the singular route declaration). The decisions are polymorphically associated with both. I have just a single decisions controller and a single _form.html.haml partial to render the form for a decision. This is the view code: = simple_form_for @decision, :url => [@decision_tree_owner, @decision.becomes(Decision)] do |form| The warranty_type url looks like this (for a new decision): /warranty_types/2/decisions whereas the warranty_review url looks like this: /admin/warranty_review/decisions.1 I think because the warranty_review id has no where to go, it's just getting appended to the end as an extension. Can someone explain what's going on here and how I might be able to fix it? I can work around it by trying to detect for a warranty_review class and substituting @decision_tree_owner with :warranty_review and this generates the correct url, but this is messy. I would have thought that the routing would be smart enough to realise that warranty_review is a singular resource and thus discard the id from the URL. This is Rails 3 by the way :)

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  • Need to reload current_cart to get the test passed

    - by leomayleomay
    I'm testing my online store app with RSpec, here's what I'm doing: # spec/controllers/line_items_controller_spec.rb require 'spec_helper' describe LineItemsController do describe "POST 'create'" do before do @current_cart = Factory(:cart) controller.stub!(:current_cart).and_return(@current_cart) end it 'should merge two same line_items into one' do @product = Factory(:product, :name => "Tee") post 'create', {:product_id => @product.id} post 'create', {:product_id => @product.id} assert LineItem.count.should == 1 assert LineItem.first.quantity.should == 2 end end end # app/controllers/line_items_controller.rb class LineItemsController < ApplicationController def create current_cart.line_items.each do |line_item| if line_item.product_id == params[:product_id] line_item.quantity += 1 if line_item.save render :text => "success" else render :text => "failed" end return end end @line_item = current_cart.line_items.new(:product_id => params[:product_id]) if @line_item.save render :text => "success" else render :text => "failed" end end end The problem right now is it never added up two line_items having the same product into one, because the second time I entered into the line_items_controller#create, the current_cart.line_items is [], I have run current_cart.reload to get the test passed, any idea what's going wrong?

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