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  • create dynamic navigation from xml file in flash cs3

    - by mjr
    action script newbie here :-) What I want to do is this, hand an xml file to a swf and have the swf generate a dynamic text box and button for each of the links in the xml file a rudimentary navigation here's the xml <?xml version="1.0" encoding="UTF-8"?> <page> <page name="Page Name 1" url="/page-1/" /> <page name="Page Name 2" url="/page-2/" /> <page name="Page Name 3" url="/page-3/" /> <page name="Page Name 4" url="/page-4/" /> </page> and in my fla I have a button in my library named 'nav_button' there's a layer named actions and in frame 1 I have this var xml:XML; var xmlList:XMLList; var xmlLoader:URLLoader = new URLLoader(); var button:Button = new Button(); xmlLoader.load(new URLRequest("links.xml")); xmlLoader.addEventListener(Event.COMPLETE, xmlLoaded); function xmlLoaded(event:Event):void { xml = XML(event.target.data); xmlList = xml.children(); trace(xml.length()); for(var i:int = 0; i < xmlList.length(); i++) { button = new Button(); button.x = 25; button.y = i * 50 +25; addChild(button); } } the xml imports fine, but when it comes to the for loop and adding the buttons and text boxes to the stage, I'm toast

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  • detect shutdown in window service

    - by deepu
    hi, i have a windows service that get user details and save the result into log text file. and, my problem is when i shut down or log off my system, i also would like to save the time that i down my system into that log file. but, i don't know how to do that. I checked the winproc method to detect shutdown operation but i was not able to use it on window service, on googling found it can be used with forms only. how can we detect user have clicked shutdown or log off and do some action. so,please give me some idea or suggestion on that. i have used it for logoff but on log entry is made when i logoff the system protected override void OnSessionChange(SessionChangeDescription changeDescription) { this.RequestAdditionalTime(250000); //gives a 25 second delay on Logoff if (changeDescription.Reason == SessionChangeReason.SessionLogoff) { // Add your save code here StreamWriter str = new StreamWriter("D:\\Log.txt", true); str.WriteLine("Service stoped due to " + changeDescription.Reason.ToString() + "on" + DateTime.Now.ToString()); str.Close(); } base.OnSessionChange(changeDescription); }

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  • curl post picture multipart/form-data, php cURL need help!

    - by user331071
    I'm trying to upload a picture to a specific website using php cURL but I don't really understand what parameters do I need to send because the data looks a bit weird . Here is what i got with the http analyzer Type : multipart/form-data; boundary=---------------------------182983931283 -----------------------------182983931283 Content-Disposition: form-data; name="file"; filename="Blue hills.jpg" Content-Type: image/jpeg Here appears the souce of the image itself like "ÿØÿàÿØÿàÿØÿàÿØÿàÿØÿàÿØÿà" -----------------------------182983931283 Content-Disposition: form-data; name="action" images -----------------------------182983931283 Content-Disposition: form-data; name="anonymous_email" Y -----------------------------182983931283 Content-Disposition: form-data; name="site_id" 1 -----------------------------182983931283 and so on other parameters. The issue that I have is that I don't understand what is the boundary, where do I get it from (because it doesn't appear in the html document that generates the POST and how should I make the post . If you would give me a simple example to post the above parameters to http://example.com I will definitely get the trick . Currently I'm using the following function to make the post : function processPicturesPage($title, $price, $numbedrooms, $description) { //Set the login parameters and initiate the Login process $fields = array( "changedImages" = "", "site_id" = "1", "posting_id" = "", "current_live_date" = "", "images_loaded" = "", "image_actions" = "", "title" = $title, ); foreach($fields as $key=$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); $URL = "http://www.example.com/cgi-bin/add_posting.pl"; return $this-processCurlrequest($URL, count($fields), $fields_string); } and in the processCurlrequest I have the curl options (cookies etc) and url .

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  • Hibernate saveorUpdate method problem

    - by umesh awasthi
    Hi all, i am trying to work on with Hibernate (Database side for first time) and some how struck in choosing best possible way to use saveOrUpdate or Save.Update i have a destination POJO class and its other attributes which needs to be updated along with the Destination entity. i am getting an XML file to be imported and i am using the following code to update/save the destination entity along with its attribute classes. try{ getSessionFactory().getCurrentSession().beginTransaction(); getSessionFactory().getCurrentSession().saveOrUpdate(entity); getSessionFactory().getCurrentSession().getTransaction().commit(); } catch(Exception e){ getSessionFactory().getCurrentSession().getTransaction().rollback(); } finally{ getSessionFactory().close(); } everything is working fine untill i am using the same session instance.but later on when i am using the same XML file to update the destination PO for certain attributes it giving me the following error. SEVERE: Duplicate entry 'MNLI' for key 'DESTINATIONID' 9 Jan, 2011 4:58:11 PM org.hibernate.event.def.AbstractFlushingEventListener performExecutions SEVERE: Could not synchronize database state with session org.hibernate.exception.ConstraintViolationException: Could not execute JDBC batch update at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:94) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:275) at org.hibernate.jdbc.AbstractBatcher.prepareStatement(AbstractBatcher.java:114) at org.hibernate.jdbc.AbstractBatcher.prepareStatement(AbstractBatcher.java:109) at org.hibernate.jdbc.AbstractBatcher.prepareBatchStatement(AbstractBatcher.java:244) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2242) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2678) at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:79) i am using UUID as primary key for the Destination table and in destination table i have a destination id which is unique.but i can understand that in the secodn case hibernate is not able to find if there is already an entry for the same destination in the DB and trying to execute insert statement rather than update. one possible solution is i can user destinationid to check if there is already a destination inplace with the given id and based on the results i can issue save or update command. my question is can this be achieve by any other good way..? Thanks in advance

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  • ASP.NET MVC Viewmodel trouble...

    - by ile
    I've already started similar topic, but still didn't find final solution... So here I am with new one :) ... I'm developing NerdDinner from scratch and now I came to point where I define DinnerViewModel. Following these instructions (starting from Listing 5) I came to this: namespace Nerd.Controllers { // View Model Classes public class DinnerViewModel { public DinnerViewModel(List<Dinner> dinners) { this.Dinners = dinners; } public List<Dinner> Dinners { get; private set; } } public class DinnerController : Controller { private DinnerRepository dinnerRepository = new DinnerRepository(); .... public ActionResult NewDinners() { // Create list of products var dinners = new List<Dinner>(); dinners.Add(new Dinner(/*Something to add*/)); // Return view return View(new DinnerViewModel(dinners)); } } } Also, the Dinner table in this new version of NerdDinner is a bit shortened (it contains of DinnerID, Title, EventDate and Description fields). No matter what I try to add here dinners.Add(new Dinner(/*Something to add*/)); I always get following error Error 1 'Nerd.Model.Dinner' does not contain a constructor that takes '1' arguments C:\Documents and Settings\ilija\My Documents\Visual Studio 2008\Projects\Nerd\Nerd\Controllers\DinnerController.cs 150 25 Nerd Because I'm total beginner in C# and generally OOP, I have no idea what to do here... I suppose I need to declare a constructor, but how and where exactly? Thanks, Ile

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  • How to fetch populated associated models in CakePHP when calling read()

    - by Code Commander
    I have the following Models: class Site extends AppModel { public $name = "Site"; public $useTable = "site"; public $primaryKey = "id"; public $displayField = 'name'; public $hasMany = array('Item' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { if($isAdmin) { return true; } return array_key_exists($this->id, $allowedSites); } } and class Item extends AppModel { public $name = "Item"; public $useTable = "item"; public $primaryKey = "id"; public $displayField = 'name'; public $belongsTo = array('Site' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { // My problem appears to be the next line: return $this->Site->canView($userId, $isAdmin); } } In my controller I am doing something like this: $result = $this->Item->read(null, $this->request->id); // Verify permissions if(!$this->Item->canView($this->Session->read('userId'), $this->Session->read('isAdmin'))) { $this->httpCodes(403); die('Permission denied.'); } I notice that in Item->canView() $this->data['Site'] is populated with the column data from the site table. But it merely an array and not an object. On the other hand $this->Site is a Site object, but it has not been populated with the column data from the site table like $this->data. What is the proper way to have CakePHP get the associated model as the object and containing the data? Or am I going about this all wrong? Thanks!

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  • Problem executing trackPageview with Google Analytics.

    - by dmrnj
    I'm trying to capture the clicks of certain download links and track them in Google Analytics. Here's my code var links = document.getElementsByTagName("a"); for (var i = 0; i < links.length; i++) { linkpath = links[i].pathname; if( linkpath.match(/\.(pdf|xls|ppt|doc|zip|txt)$/) || links[i].href.indexOf("mode=pdf") >=0 ){ //this matches our search addClickTracker(links[i]); } } function addClickTracker(obj){ if (obj.addEventListener) { obj.addEventListener('click', track , true); } else if (obj.attachEvent) { obj.attachEvent("on" + 'click', track); } } function track(e){ linkhref = (e.srcElement) ? e.srcElement.pathname : this.pathname; pageTracker._trackPageview(linkhref); } Everything up until the pageTracker._trackPageview() call works. In my debugging linkhref is being passed fine as a string. No abnormal characters, nothing. The issue is that, watching my http requests, Google never makes a second call to the tracking gif (as it does if you call this function in an "onclick" property). Calling the tracker from my JS console also works as expected. It's only in my listener. Could it be that my listener is not deferring the default action (loading the new page) before it has a chance to contact Google's servers? I've seen other tracking scripts that do a similar thing without any deferral.

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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Why isn't my submit button centered?

    - by William
    For some reason my submit button isn't centered. http://prime.programming-designs.com/test_forum/viewboard.php?board=0 #submitbutton{ margin: auto; border: 1px solid #DBFEF8; background-color: #DBFEF8; color: #000000; margin-top: 5px; width: 100px; height: 20px; } here's the html. <form method=post action=add_thread.php?board=<?php echo''.$board.''; ?>> <div id="formdiv"> <div class="fieldtext1">Name</div> <div class="fieldtext1">Trip</div> <input type="text" name=name size=25 /> <input type="text" name=trip size=25 /> <div class="fieldtext2">Comment</div> <textarea name=post rows="4" cols="70"></textarea> <div class="fieldtext2">Fortune</div> <input type="checkbox" name="fortune" value="fortune" /> </div> <input type=submit value="Submit" id="submitbutton"> </form>

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  • Passing Values to Controllers

    - by Dru
    I'm trying to allow users to 'favorite' links (that is, create a new Favorite record with their user_id and the link_id) This is what I have so far.. When I click favorite (as a user), the new record is assigned to the user_id but the link_id field is nil. How can I pass the link_id into my FavoritesController? My View Code Added Link Model Code class FavoritesController < ApplicationController def create @user = User.find(session[:user_id]) @favorite = @user.favorites.create :link_id => params[:id] redirect_to :back end end The Favorite model belongs to :user and :link Note: I've also tried this but when I click 'favorite', there's an error "Couldn't find Link without an ID." Update <%= link_to "Favorite", :controller => :favorites, :action => :create, :link_id => link.id %> with class FavoritesController < ApplicationController def create @user = User.find(session[:user_id]) @favorite = @user.favorites.create :link_id => :params[:link_id] redirect_to :back end end Returns "can't convert Symbol into Integer" app/controllers/favorites_controller.rb:4:in [] app/controllers/favorites_controller.rb:4:in create I've tried forcing it into an Integer several ways with .to_i

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  • Xcode: Display Login View in applicationDidBecomeActive

    - by Patrick
    In my app I would like to show a login screen - which will be displayed when the app starts and when the app becomes active. For reference, I am using storyboards, ARC and it is a tabbed bar application. First off, I have this method which returns the topViewController. - (UIViewController *)topViewController:(UIViewController *)rootViewController { if (rootViewController.presentedViewController == nil) { return rootViewController; } if ([rootViewController.presentedViewController isMemberOfClass:[UINavigationController class]]) { UINavigationController *navigationController = (UINavigationController *)rootViewController.presentedViewController; UIViewController *lastViewController = [[navigationController viewControllers] lastObject]; return [self topViewController:lastViewController]; } UIViewController *presentedViewController = (UIViewController *)rootViewController.presentedViewController; return [self topViewController:presentedViewController]; } And I call this method here: - (void)applicationDidBecomeActive:(UIApplication *)application { if ( ... ) { // if the user needs to login PasswordViewController *passwordView = [[PasswordViewController alloc] init]; UIViewController *myView = [self topViewController:self.window.rootViewController]; [myView presentModalViewController:passwordView animated:NO]; } } To an extent this does work - I can call a method in viewDidAppear which shows an alert view to allow the user to log in. However, this is undesirable and I would like to have a login text box and other ui elements. If I do not call my login method, nothing happens and the screen stays black, even though I have put a label and other elements on the view. Does anyone know a way to resolve this? My passcode view is embedded in a Navigation Controller, but is detached from the main storyboard.

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  • Objective C number keypad, custom comma button

    - by rom_j
    I'm trying to add a comma button on a number keypad that has previous, next and done buttons, so that it looks like this : Problem is, that the orange button does not respond to taps. Actually if I moved it above the "7" button and tapped it, the 7 would be tapped. So my orange button may be shown above the keyboard, but it's reacting to taps as if it were below. Here is an abstract of my code : -(void)textFieldDidBeginEditing:(UITextField *)textField{ UIView *inputAccessoryView = [[UIView alloc] initWithFrame:CGRectMake(0, 500, screenWidth, 40.0)]; // 3 buttons on top UIView *topToolbar = [[UIView alloc] initWithFrame:CGRectMake(0, 0.0, screenWidth, 40.0)]; [topToolbar addSubview:self.inputPrevButton]; [topToolbar addSubview:self.inputNextButton]; [topToolbar addSubview:self.inputDoneButton]; [inputAccessoryView addSubview:topToolbar]; // Comma button UIButton *commaButton = [UIButton buttonWithType:UIButtonTypeCustom]; [commaButton setFrame: CGRectMake(0, 204, 105, 52)]; [commaButton setTitle:@"." forState:UIControlStateNormal]; [commaButton addTarget:self action:@selector(addComma) forControlEvents:UIControlEventTouchUpInside]; [commaButton setBackgroundColor:[UIColor orangeColor]]; [inputAccessoryView addSubview:commaButton]; // Useless, but tried anyway [inputAccessoryView bringSubviewToFront:commaButton]; [textField setInputAccessoryView:self.inputAccessoryView]; } All I know is that I should not be doing this (which is actually not working), so what should I do ?

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  • SQL Databases and table design/organization

    - by John McMullen
    (NOOB disclaimer) I'm working on a system (a type of map), that is accessed mostly via 3 fields: ID (auto incremented), X coordinate, and Y coordinate. As it is right now, i have all data on the map, stored in 1 table. Whenever the map display is loaded it simply queries the database for contents in x and y, and the DB gives the data (other fields in the same entry). If an item on the map is doing something, it has a flag saying its doing something, and then has an ID of the action in another table holding that type of 'actions'. Essentially, for all map data, its stored in 1 table. All actions of a certain type are stored in their own table. I'm a noob, and i'm wondering what the most effective/efficient structure for such a design? (a map that has items, and each item has stats/actions). I'm using PHP atm, using standard SQL queries to get my data. Should i split up the tables so that there are only x number of entries on a table? (coord range limits)? Should it just keep growing and growing? There's a lot of queries to the table... so just tryin to see what is best :/

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  • JAVASCRIPT - What am I doing incorrectly?

    - by DarkLightA
    LIVE CODE: http://jsfiddle.net/vy4nY/ I'm following this challenge, but I'm having some issues. I'm trying to make the Email Address box only appear when the checkbox is clicked on. What have I done incorrectly? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <title>JavaScript Challenges</title> <style type="text/css"> #emailpara {visibility:hidden;} </style> </head> <body> <form action=""> <fieldset> <legend>Email subscriptions</legend> <p id="subscribepara"> <label> <input type="checkbox" name="subscribe" id="subscribe"> Yes! I would like to receive the occasional newsletter via email. </label> </p> <p id="emailpara"> <label> Email Address: <input type="text" name="email" id="email"> </label> </p> </fieldset> </form> <script type="text/javascript"> document.getElementById('subscribe').onclick = (document.getElementById('subscribe').checked ? (document.getElementById('emailpara').style.visibility = 'visible') : (document.getElementById('emailpara').style.visibility = 'hidden')); </script> </body> </html>

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  • Telerik MVC Grid won't load data into details table (subtable)

    - by henriksen
    I have a list of Plants and assosiated Projects. I want to output this in a table with all the Plants and use Telerik.Grid to expand a Plant, show a Telerik.Grid with associated Projects. I want the Projects to be dynamically loaded with Ajax. The code for the grid: @(Html.Telerik().Grid<PlantDto>() .Name("Plants") .Columns(columns => { columns.Bound(plant => plant.Title); }) .DetailView(details => details.ClientTemplate( Html.Telerik().Grid<ProjectDto>() .Name("Plant_<#= Id #>") .DataBinding(dataBinding => dataBinding.Ajax() .Select("ProjectsForPlant", "User", new { plantId = "<#= Id #>" })) .ToHtmlString() )) .DataBinding(dataBinding => dataBinding.Ajax().Select("PlantsForUser", "User")) ) The initial data is loaded into the grid just fine (the list of Plants) but when I expand a plant I just get an empty sub-table. Looking in FireBug there are no calls to the server. The controller that should serve the list of projects is never called. Anyone have an idea on what it could be?

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  • Have to click twice to submit the form

    - by phil
    Intended function: require user to select an option from the drop down menu. After user clicks submit button, validate if an option is selected. Display error message and not submit the form if user fails to select. Otherwise submit the form. Problem: After select an option, button has to be clicked twice to submit the form. I have no clue at all.. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style> p{display: none;} </style> </head> <script> $(function(){ // language as an array var language=['Arabic','Cantonese','Chinese','English','French','German','Greek','Hebrew','Hindi','Italian','Japanese','Korean','Malay','Polish','Portuguese','Russian','Spanish','Thai','Turkish','Urdu','Vietnamese']; $('#muyu').append('<option value=0>Select</option>'); //loop through array for (i in language) //js unique statement for iterate array { $('#muyu').append($('<option>',{id:'muyu'+i,val:language[i], html:language[i]})) } $('form').submit(function(){ alert('I am being called!'); // check if submit event is triggered if ( $('#muyu').val()==0 ) {$('#muyu_error').show(); } else {$('#muyu_error').hide(); return true;} return false; }) }) </script> <form method="post" action="match.php"> I am fluent in <select name='muyu' id='muyu'></select> <p id='muyu_error'>Tell us your native language</p> <input type="submit" value="Go"> </form>

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  • Why rails app is redirecting unexpectedly instead of matching the route?

    - by ruevaughn
    I asked this question earlier and thought it was fixed, but it's not. Previous question here My problem is I am trying to set my routes so that when I type in localhost:3000/sites/admin It should redirect to localhost:3000/en/sites/admin here is my routes.rb file scope ":locale", locale: /#{I18n.available_locales.join("|")}/ do get "log_out" => "sessions#destroy", as: "log_out" get "log_in" => "sessions#new", as: "log_in" resources :sites, except: [:new, :edit, :index, :show, :update, :destroy, :create] do collection do get :home get :about_us get :faq get :discounts get :services get :contact_us get :admin get :posts end end resources :users resources :abouts resources :sessions resources :coupons resources :monthly_posts resources :reviews resources :categories do collection { post :sort } resources :children, :controller => :categories, :only => [:index, :new, :create, :new_subcategory] end resources :products do member do put :move_up put :move_down end end resources :faqs do collection { post :sort } end root :to => 'sites#home' match "/savesort" => 'sites#savesort' end match '', to: redirect("/#{I18n.default_locale}") match '*path', to: redirect("/#{I18n.default_locale}/%{path}") But as of right now, it redirects to /en/en/en/en/en/en/en/en/en/en/sites/admin (adds en until browser complains). Any thoughts why it keeps adding /en?

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  • Desktop-like UI implementations for Java web applications?

    - by localshred
    At work we're discussing upgrading our view layer for our web application. We're currently running an old and "modified" version of FreeMarker Classic, which is a pain to work with. One of our developers suggested using a Component UI style architecture similar to desktop style environments. Essentially, this would mean that you would build custom HTML components as Java Classes that the controller would render into the Document view. This would completely take away the need to write HTML into a view layer. The Components would generate the view layer for you. For instance, the following rendered HTML: <h1>I am a title</h1> <p>I am a paragraph.</p> Would be generated by doing something like: String titleString = "I am a title"; html.elements.Heading heading = new html.elements.Heading(Heading.H1, titleString); String paraString = "I am a paragraph."; html.elements.Paragraph paragraph = new html.elements.Paragraph(paraString); PrintWriter somePrintWriter = new PrintWriter(); Document document = new Document(); document.addElement(heading); document.addElement(paragraph); document.compose(somePrintWriter); The above code is just an example, don't critique the names or style, I just wrote it for a quick demonstration of what we may be trying to accomplish. I'm trying to determine if this has been done before in Java, and if so if there are any links I can be pointed to. I've been researching it as much as I can, but haven't found any implementations that completely remove the template layer (such as JSP or JSF). Thanks!

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  • What could possibly be different between the table in a DataContext and an IQueryable<Table> when do

    - by Nate Bross
    I have a table, where I need to do a case insensitive search on a text field. If I run this query in LinqPad directly on my database, it works as expected Table.Where(tbl => tbl.Title.Contains("StringWithAnyCase") In my application, I've got a repository which exposes IQueryable objects which does some initial filtering and it looks like this var dc = new MyDataContext(); public IQueryable<Table> GetAllTables() { var ret = dc.Tables.Where(t => t.IsActive == true); return ret; } In the controller (its an MVC app) I use code like this in an attempt to mimic the LinqPad query: var rpo = new RepositoryOfTable(); var tables = rpo.GetAllTables(); // for some reason, this does a CASE SENSITIVE search which is NOT what I want. tables = tables.Where(tbl => tbl.Title.Contains("StringWithAnyCase"); return View(tables); The column is defiend as an nvarchar(50) in SQL Server 2008. Any help or guidance is greatly appreciated!

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  • jeditable table cell

    - by user666262
    Hi all, I am having an issue when using jeditable to edit a cell in a table. The project is the MVC 2 web application and the table has been put on the standard about page. How do i tell the script to call a specific method in the controller ? because it is currently just loading the entire page into the cell. This is the javascript: $(document).ready(function () { $('.editable').editable('http://localhost:2196/Home/About', { type: 'text', cancel: 'Cancel', event: 'dblclick', submit: 'OK', tooltip: 'double Click to edit...' }); }); This is the table : <% foreach (DataTableEditable.Models.Company item in (IEnumerable<DataTableEditable.Models.Company>)Model) {%> <tr id="<%= Html.Encode(item.ID) %>"> <td class="editable"><%= Html.Encode(item.Name) %> </td> <td><%= Html.Encode(item.Address) %> </td> <td><%= Html.Encode(item.Town) %> </td> </tr> <% }%> Thanks lots John

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  • CanCan polymorphic resource access problem

    - by Call 'naive' True
    Hi everybody, i don't quite understand how to restrict access to links in this particular case with CanCan. I always get "Edit" link displayed. So i believe the problem is in my incorrect definition of cancan methods(load_ and authorize_). I have CommentsController like that: class CommentsController < ApplicationController before_filter :authenticate_user! load_resource :instance_name => :commentable authorize_resource :article def index @commentable = find_commentable #loading our generic object end ...... private def find_commentable params.each { |name, value| if name =~ /(.+)_id$/ return $1.classify.constantize.includes(:comments => :karma).find(value) end } end end and i have in comments/index.html.erb following code that render file from other controller: <%= render :file => "#{get_commentable_partial_name(@commentable)}/show.html.erb", :collection => @commentable %> you can think about "#{get_commentable_partial_name(@commentable)}" like just "articles" in this case. Content of "articles/show.html.erb": <% if can? :update, @commentable %> <%= link_to 'Edit', edit_article_path(@commentable) %> | <% end %> my ability.rb: class Ability include CanCan::Ability def initialize(user) user ||= User.new # guest user if user.role? :admin can :manage, :all elsif user.role? :author can :read, [Article, Comment, Profile] can :update, Article, :user_id => user.id end end end relations with models is: class Comment < ActiveRecord::Base belongs_to :commentable, :polymorphic => true, :dependent => :destroy ... end class Article < ActiveRecord::Base has_many :comments, :as => :commentable, :dependent => :destroy ... end i have tried debug this issue like that user = User.first article = Article.first ability = Ability.new(user) ability.can?(:update, article) and i always get "= true" in ability check Note: user.role == author and article.user_id != user.id if you need more information please write thank's for your time && sorry for my english

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  • How do I solve the .NET CF exception "Can't find PInvoke DLL"?

    - by Ignas Limanauskas
    This is to all the C# gurus. I have been banging my head on this for some time already, tried all kinds of advice on the net with no avail. The action is happening in Windows Mobile 5.0. I have a DLL named MyDll.dll. In the MyDll.h I have: extern "C" __declspec(dllexport) int MyDllFunction(int one, int two); The definition of MyDllFunction in MyDll.cpp is: int MyDllFunction(int one, int two) { return one + two; } The C# class contains the following declaration: [DllImport("MyDll.dll")] extern public static int MyDllFunction(int one, int two); In the same class I am calling MyDllFunction the following way: int res = MyDllFunction(10, 10); And this is where the bloody thing keeps giving me "Can't find PInvoke DLL 'MyDll.dll'". I have verified that I can actually do the PInvoke on system calls, such as "GetAsyncKeyState(1)", declared as: [DllImport("coredll.dll")] protected static extern short GetAsyncKeyState(int vKey); The MyDll.dll is in the same folder as the executable, and I have also tried putting it into the /Windows folder with no changes nor success. Any advice or solutions are greatly appreciated.

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  • Android How to get position of selected item from gridview without using onclicklistner, using ontouchlistner instead

    - by zonemikel
    I have a gridview, I need to do stuff on motioneven.action_down and do something for motioneven.action_up ... using onclicklistener is great but does not give me this needed functionality. Is there anyway to easily call the gridview and get its selected item in a ontouchlistener ? I've been having limited success with making my own implementation. Its hard to get the right x,y because if i call the child it gives me the x and y relative to the child so a button would be 0,0 to 48,48 but it does not tell you the actual location on the screen relative to the gridview or the screen itself. this is what i've been doing, its partially working so far. Grid.setOnTouchListener(new OnTouchListener() { public boolean onTouch(View v, MotionEvent event) { if (event.getAction() == MotionEvent.ACTION_DOWN) { int x = (int)event.getX(); int y = (int)event.getY(); int position = 0; int childCount = Grid.getChildCount(); Message msg = new Message(); Rect ButtonRect = new Rect(); Grid.getChildAt(0).getDrawingRect(ButtonRect); int InitialLeft = ButtonRect.left + 10; ButtonRect.offsetTo(InitialLeft, ButtonRect.top); // while(position < childCount){ if(ButtonRect.contains(x,y)){break;} if(ButtonRect.right + ButtonRect.width() > Grid.getWidth()) { ButtonRect.offsetTo(InitialLeft, ButtonRect.bottom);} position++; ButtonRect.offsetTo(ButtonRect.right, ButtonRect.top); } msg.what = position; msg.arg1 = ButtonRect.bottom; msg.arg2 = y; cHandler.sendMessage(msg); }// end if action up if (event.getAction() == MotionEvent.ACTION_UP) { } return false; } });

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  • How to make ActionController::Base.asset_host and Base.relative_url_root independent?

    - by GSP
    In our Intranet environment we have a decree that common assets (stylesheets, images, etc) should be fed from Apache root while Rails apps runs from from a "sub directory" (a proxy to a Mongrel cluster). In other words: <%= stylesheet_tag '/common' %> # <link href="http://1.1.1.1/stylesheets/common.css" /> <%= link_to 'Home', :controller=>'home', :action=>'index' %> # <a href="http://1.1.1.1/myapp/" /> What I would like to do is define the assets and relative url in my configuration like this: ActionController::Base.asset_host=http://1.1.1.1 ActionController::Base.relative_url_root=/myapp But when I do this, the relative_url_root value gets appended to the asset_host value. (e.g. <link href="http://1.1.1.1/myapp/stylesheets/common.css"> ) Is there a way to stop this? And, more importantly, is there a best practice for how to deploy a rails app to an environment like this? (BTW, I don't want to simply hard code my asset paths since the development environment does not match the test and production environments.) Environment: Rails 2.3.4 Ruby 1.8.7 RedHat Linux 5.4?

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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