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  • directory resource does not create directory

    - by Dan Tenenbaum
    I have a Vagrantfile that provisions a VM by running a chef recipe. The first resource in the chef recipe is: directory "/downloads" do owner "root" group "root" mode "0755" action :create end # check that it worked: raise "/downloads doesn't exist!" unless File.exists? "/downloads" When I run this at work, it works fine. When I run it at home, it fails, the exception is raised when I check to see if /downloads exists. I'm not sure why this is happening. I would expect it to behave identically, since the underlying Vagrant box is the same both at work and at home. I am a chef newb so perhaps there is something I am not understanding about the order in which the resources are run within my recipe? I would expect them to run in sequential order... I also tried putting a notifies call inside the directory block, where I call another execute block :immediately. That works, but inside the second execute block I test to see whether /downloads has been created and it hasn't. Clearly I'm missing something very basic.

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  • Codeigniter - accessing variables from an array passed into a page.

    - by Matt
    Hello, I have a controller with an index function as follows: function index() { $this->load->model('products_model'); $data['product'] = $this->products_model->get(3); // 3 = product id $data['product_no'] = 3; $data['main_content'] = 'product_view'; //print_r($data['products']); $this->load->view('includes/template', $data); } This is the get function in the products_model file function get($id) { $results = $this->db->get_where('products', array('id' => $id))->result(); //get the first item $result = $results[0]; return $result; } The products table contains fields such as name, price etc. Please can you tell me how to output variables from $data['product'] after it is passed into the view? I have tried so many things but nothing is working, even though the print_r (commented out) shows the data - it is not being passed into the view. I thought it may have been because the view calls a template file which references the main_content variable: Template file contents: <?php $this->load->view('includes/header'); ?> <?php $this->load->view($main_content); ?> <?php $this->load->view('includes/footer'); ?> but i tried creating a flat view file and still couldn't access the variables. Many thanks,

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  • MVC3 View For Loop values initialization

    - by Ryan
    So I have a for loop in my View that is supposed to render out the input boxes. Now inside these input boxes I want to put lables that disappear when you click on them. This is all simple. Now it's probably because my brain was wired for php first, and it has been difficult to get it to think in lambdas and object orientation, but I can't figure out how to do this: @{ for (int i = 0; i < 3; i++) { <div class="editor-label grid_2">User</div> Model.Users[i].UserFirstName = "First Name"; Model.Users[i].UserLastName = "Last Name"; Model.Users[i].UserEmailAddress = "Email Address"; <div class="grid_10"> @Html.TextBoxFor(m => Model.Users[i].UserFirstName, new { @class = "user-input" }) @Html.TextBoxFor(m => Model.Users[i].UserLastName, new { @class = "user-input" }) @Html.TextBoxFor(m => Model.Users[i].UserEmailAddress, new { @class = "user-input-long" }) @Html.CheckBoxFor(m => Model.Users[i].IsUserAdmin) <span>&nbsp;admin?</span> </div> <div class="clear"> </div> } } And initialize the values for the users. And you're probably thinking "Of course that won't work. You're going to get a Null Reference Exception", and you would be correct. I might need to initialize them somewhere else and I don't realize it but I'm just not sure. I've tried the [DefaultValue("First Name")] route and that doesn't work. I'm probably thinking about this wrong, but my brain is already shot from trying to figure out how to wire up these events to the controller, so any help would be appreciated!

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  • How to implement a network protocol?

    - by gotch4
    Here is a generic question. I'm not in search of the best answer, I'd just like you to express your favourite practices. I want to implement a network protocol in Java (but this is a rather general question, I faced the same issues in C++), this is not the first time, as I have done this before. But I think I am missing a good way to implement it. In fact usually it's all about exchanging text messages and some byte buffers between hosts, storing the status and wait until the next message comes. The problem is that I usually end up with a bunch of switch and more or less complex if statements that react to different statuses / messages. The whole thing usually gets complicated and hard to mantain. Not to mention that sometimes what comes out has some "blind spot", I mean statuses of the protocol that have not been covered and that behave in a unpredictable way. I tried to write down some state machine classes, that take care of checking start and end statuses for each action in more or less smart ways. This makes programming the protocol very complicated as I have to write lines and lines of code to cover every possible situation. What I'd like is something like a good pattern, or a best practice that is used in programming complex protocols, easy to mantain and to extend and very readable. What are your suggestions?

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  • C# ...extract email address from inside 100's of text files

    - by Developer
    My SMTP server got 100's of errors when sending lots of emails. Now have lots of .BAD files each one containing an error message and somewhere in the middle, the actual email address it was supposed to be sent to. What is the easiest way to extract from each file "just" the "email address", so that I can have a list of the actual failed emails? I can code in C# and any suggestion will be truly welcomed. BAD SAMPLE TEXT: From: [email protected] To: [email protected] Date: Tue, 25 Sep 2012 12:12:09 -0700 MIME-Version: 1.0 Content-Type: multipart/report; report-type=delivery-status; boundary="9B095B5ADSN=_01CD9B35032DF58000000066my.server.co" X-DSNContext: 7ce717b1 - 1386 - 00000002 - C00402D1 Message-ID: Subject: Delivery Status Notification (Failure) This is a MIME-formatted message. Portions of this message may be unreadable without a MIME-capable mail program. --9B095B5ADSN=_01CD9B35032DF58000000066my.server.co Content-Type: text/plain; charset=unicode-1-1-utf-7 This is an automatically generated Delivery Status Notification. Unable to deliver message to the following recipients, due to being unable to connect successfully to the destination mail server. [email protected] --9B095B5ADSN=_01CD9B35032DF58000000066my.server.com Content-Type: message/delivery-status Reporting-MTA: dns;my.server.com Received-From-MTA: dns;Social Arrival-Date: Tue, 25 Sep 2012 11:45:15 -0700 Final-Recipient: rfc822;[email protected] Action: failed Status: 4.4.7 --9B095B5ADSN=_01CD9B35032DF58000000066my.server.com Content-Type: message/rfc822 Received: from Social ([127.0.0.1]) by my.server.com with Microsoft SMTPSVC(7.5.7601.17514); Tue, 25 Sep 2012 11:45:15 -0700 ====================================== ...and lots more text after ===================== Mainly I want to find the "[email protected]" email right in the middle...

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  • Object equality in context of hibernate / webapp

    - by bert
    How do you handle object equality for java objects managed by hibernate? In the 'hibernate in action' book they say that one should favor business keys over surrogate keys. Most of the time, i do not have a business key. Think of addresses mapped to a person. The addresses are keeped in a Set and displayed in a Wicket RefreshingView (with a ReuseIfEquals strategy). I could either use the surrogate id or use all fields in the equals() and hashCode() functions. The problem is that those fields change during the lifetime ob the object. Either because the user entered some data or the id changes due to JPA merge() being called inside the OSIV (Open Session in View) filter. My understanding of the equals() and hashCode() contract is that those should not change during the lifetime of an object. What i have tried so far: equals() based on hashCode() which uses the database id (or super.hashCode() if id is null). Problem: new addresses start with an null id but get an id when attached to a person and this person gets merged() (re-attached) in the osiv-filter. lazy compute the hashcode when hashCode() is first called and make that hashcode @Transitional. Does not work, as merge() returns a new object and the hashcode does not get copied over. What i would need is an ID that gets assigned during object creation I think. What would be my options here? I don't want to introduce some additional persistent property. Is there a way to explicitly tell JPA to assign an ID to an object? Regards

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  • writing a meta refresh method for rails

    - by aaronstacy
    I want a method in app/controllers/application.rb that can prepend/append text to whatever template gets rendered. Of course I can't call render twice w/o getting a double render error, so is this possible? I want to redirect after a delay using a meta refresh. Here's what I've got: app/controllers/application_controller.rb: def redirect_after_delay (url, delay) @redirect_delay = delay @redirect_url = url render end app/views/layouts/application.html.erb <!DOCTYPE html> <html lang="en"> <head> <%= yield :refresh_tag %> </head> <body> <%= yield %> </body> </html> So then if I want to add a redirect-after-delay, I add the following to 1) my controller and 2) the action's view: app/controllers/my_controller.rb def my_action redirect_after_delay 'http://www.google.com', 3 if some_condition end app/views/my_controller/my_action.html.erb <% content_for :refresh_tag do %> <meta http-equiv='refresh' content='<%=@redirect_delay%>;url=<%=@redirect_url%>'> <% end %> <h1>Please wait while you are redirected...</h1> Since the content_for block never changes, is it possible to do this in some generic way so that I don't have to put <%= yield :refresh_tag %> in each template? (e.g. could redirect_after_delay add it into whatever template is going to be rendered?)

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  • Using entity framework to connect to multiple similar tables in .net MVC.

    - by Dite
    A relative newcomer to .net MVC2 and the entity framework, I am working on a project which requires a single web application, (C# .net 4), to connect to multiple different databases depending on the route of access, (ie subdomain). No problem with this in principle and all the logic is written to transform the subdomain into an entity connection and pass this through to the Entity Model. The problem comes with the fact that the different database whilst being largely similar in structure contain 3 or 4 unique tables bespoke to that instance. To my mind there are two ways to solve this issue, neither of which i am sure will be possible. 1/ Use a separate entity model for each database. -Attempts down this route have through up conflicts where table/sp names are the same across differnt db's, or implicit conversion errors when I try and put the different models in different namespaces. or 2/ Overwrite the classes which refer to the changeable database objects based on the value of a base controller property. -I have found nothing to suggest i can even do this. My question is if either of theser routes can ever work in principle or if i should just give up on the EF and connect to the dtabases directlky using ADO. Perhaps there is another way to solve this problem i haven't thought of? Thanks for any help...

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  • PHP output results on to one page

    - by linda
    i have a system where a user searches for a film and reviews appear on a page with a button next to each review. The button can be selected to look at the individual review but i basically want a button that when selected it will look at all reviews on one page, the code i am using for the individual review is this <?php ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); $searchfilm=$_POST['searchfilm']; //Connect to database //Filter search $searchfilm = strtoupper($searchfilm); $searchfilm = strip_tags($searchfilm); $searchfilm = trim ($searchfilm); $query = mysql_fetch_assoc(mysql_query("SELECT filmreview FROM review WHERE id = '$id'")); $data = mysql_query("SELECT film.filmname, review.filmreview, review.reviewtitle, review.id FROM film, review WHERE film.filmid = review.filmid AND filmname = '$searchfilm'"); while($row = mysql_fetch_assoc($data)) { // echo $row['filmname']; // echo "<b>Film Name:</b> " .$searchfilm; echo "<table border=\"2\" align=\"left\">"; echo "<tr><td>"; echo "<b>Review Title:</b> " .$row['reviewtitle']; echo "<tr><td>"; echo $row['filmreview']; echo "<p>"; echo "<form method='post' action='analyse1.php'>"; echo "<input type='hidden' name='reviewid' value='".$row['id']."'>"; echo "<input type='submit' name='submit' value='Analyse'>"; echo "</form>"; echo "</table>"; } ?>

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  • Submit to open up a popup window and carry through input data

    - by zac
    Hi, I have a input box on one page that on submit opens a new page with a longer form and the first field is populated with what was entered from the previous pages input box. So on page 1 there is this code: <form action="sign-up.php"> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input value='Submit' /> </form> Then on the sign-up page the receiving form grabs the string out of the url //<!-- Begin function getParams() { var idx = document.URL.indexOf('?'); if (idx != -1) { var tempParams = new Object(); var pairs = document.URL.substring(idx+1,document.URL.length).split('&'); for (var i=0; i<pairs.length; i++) { nameVal = pairs[i].split('='); tempParams[nameVal[0]] = nameVal[1]; } return tempParams; } } var params = getParams(); // End --> I would like to keep all of this functionality but it have it occur in a popup. I added this function to the submit: function myPopup() { window.open( "sign-up.php", "myWindow", "status = 1, height = 300, width = 300, resizable = 0" ) and the form becomes <form> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input onClick="myPopup()" value='Submit' /> </form> But it no longer appends the input data to the url string. Anyone have any ideas on how I can accomplish this?

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  • PHP - upload.class image and $_FILES

    - by Ockonal
    Hello, I'm using class.upload.php to upload pictures onto the server. Here is my form: <form action="<?="http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];?>" method="post" enctype="multipart/form-data"> <table style="width: 100%; padding-top: 20px;"> <tr> <td>Image file:</td> <td><input type="file" name="image_file" /></td> </tr> <tr> <td>&nbsp;</td> <td align="right"><input type="submit" name="add_new" value="Add image" /><td></td> </tr> </table> </form> In php code I do: if( array_key_exists('add_new', $_POST) ) { echo 'add new is in array'; echo '<pre>'; print_r($_POST); print_r($_FILES); echo '</pre>'; $handle = new Upload($_FILES['image_file']); ... } Here is an output of print_r: Array ( [image_file] => somefile.png [add_new] => Add image ) Array ( ) As you can see second array is empty ($_FILES), so image doesn't upload. Why? operating system : Linux PHP version : 5.2.12 GD version : 2.0.34 supported image types : png jpg gif bmp open_basedir : /home/httpd/vhosts/kz-gbi.ru/httpdocs:/tmp

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  • Mysql Query is not working in edited jTable code, why?

    - by Furkan Kadioglu
    I'm using this example: www.jtable.org I've downloaded the jTable PHP version. I then edited the script. The jTable simple version is working, but my edited version isn't. I can create a list, but I can't add a row; this code is causing problems. However, PHP doesn't display any error messages. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } What is the problem?

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  • Why does this asp.net mvc unit test fail?

    - by Brian McCord
    I have this unit test: [TestMethod] public void Delete_Post_Passes_With_State_4() { //Arrange ViewResult result = stateController.Delete( 4 ) as ViewResult; var model = (State)result.ViewData.Model; //Act RedirectToRouteResult redirectResult = stateController.Delete( model ) as RedirectToRouteResult; var newresult = stateController.Delete( 4 ) as ViewResult; var newmodel = (State)newresult.ViewData.Model; //Assert Assert.AreEqual( redirectResult.RouteValues["action"], "Index" ); Assert.IsNull( newmodel ); } Here are the two controller actions that handle deleting: // // GET: /State/Delete/5 public ActionResult Delete(int id) { var x = _stateService.GetById( id ); return View(x); } // // POST: /State/Delete/5 [HttpPost] public ActionResult Delete(State model) { try { if( model == null ) { return View( model ); } _stateService.Delete( model ); return RedirectToAction("Index"); } catch { return View( model ); } } What I can't figure out is why this test fails. I have verified that the record actually gets deleted from the list. If I set a break point in the Delete method on the line: var x = _stateService.GetById( id ); The GetById does indeed return a null just as it should, but when it gets back to the newresult variable in the test, the ViewData.Model is the deleted model. What am I doing wrong?

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  • Negative number representation across multiple architechture

    - by Donotalo
    I'm working with OKI 431 micro controller. It can communicate with PC with appropriate software installed. An EEPROM is connected in the I2C bus of the micro which works as permanent memory. The PC software can read from and write to this EEPROM. Consider two numbers, B and C, each is two byte integer. B is known to both the PC software and the micro and is a constant. C will be a number so close to B such that B-C will fit in a signed 8 bit integer. After some testing, appropriate value for C will be determined by PC and will be stored into the EEPROM of the micro for later use. Now the micro can store C in two ways: The micro can store whole two byte representing C The micro can store B-C as one byte signed integer, and can later derive C from B and B-C I think that two's complement representation of negative number is now universally accepted by hardware manufacturers. Still I personally don't like negative numbers to be stored in a storage medium which will be accessed by two different architectures because negative number can be represented in different ways. For you information, 431 also uses two's complement. Should I get rid of the headache that negative number can be represented in different ways and accept the one byte solution as my other team member suggested? Or should I stick to the decision of the two byte solution because I don't need to deal with negative numbers? Which one would you prefer and why?

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  • ASP.NET MVC Viewmodel trouble...

    - by ile
    I've already started similar topic, but still didn't find final solution... So here I am with new one :) ... I'm developing NerdDinner from scratch and now I came to point where I define DinnerViewModel. Following these instructions (starting from Listing 5) I came to this: namespace Nerd.Controllers { // View Model Classes public class DinnerViewModel { public DinnerViewModel(List<Dinner> dinners) { this.Dinners = dinners; } public List<Dinner> Dinners { get; private set; } } public class DinnerController : Controller { private DinnerRepository dinnerRepository = new DinnerRepository(); .... public ActionResult NewDinners() { // Create list of products var dinners = new List<Dinner>(); dinners.Add(new Dinner(/*Something to add*/)); // Return view return View(new DinnerViewModel(dinners)); } } } Also, the Dinner table in this new version of NerdDinner is a bit shortened (it contains of DinnerID, Title, EventDate and Description fields). No matter what I try to add here dinners.Add(new Dinner(/*Something to add*/)); I always get following error Error 1 'Nerd.Model.Dinner' does not contain a constructor that takes '1' arguments C:\Documents and Settings\ilija\My Documents\Visual Studio 2008\Projects\Nerd\Nerd\Controllers\DinnerController.cs 150 25 Nerd Because I'm total beginner in C# and generally OOP, I have no idea what to do here... I suppose I need to declare a constructor, but how and where exactly? Thanks, Ile

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  • How can I remove the present view when I have added more than one subView ?

    - by srikanth rongali
    How can I remove the present view when I touched the close button. I did [self.view removeFromSuperView] when I added only one subView. It worked. But, I have now added another subView to the previous subView. I need to to get the parent view . How can I do it. My code of adding the subView is here. When I did the following only one view is removed. //FirstViewController: UIViewController -(void)libraryFunction:(id)sender { LibraryController *libraryController = [[LibraryController alloc]init]; [self.view addSubview:libraryController.view]; } //LibraryController: UIViewController -(void)viewDidLoad{ RootViewController *rootViewController = [[RootViewController alloc] initWithStyle:UITableViewStylePlain]; UINavigationController *aNavigationController = [[UINavigationController alloc] initWithRootViewController:rootViewController]; self.navController = aNavigationController; [aNavigationController release]; [rootViewController release]; [self.view addSubview:navController.view]; } //RootViewController: UITableViewController - (void)viewDidLoad { [super viewDidLoad]; self.navigationItem.rightBarButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"Close" style:UIBarButtonItemStyleBordered target:self action:@selector(close:)]; } -(void)close:(id)sender { [self.view removeFromSuperview]; } Thank You.

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  • Overriding Code Igniter 2.14's global_xss_filtering settting

    - by user2353007
    I have created the following file at: application/core/MY_Security.php <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); /* * Does not work with global xss */ class MY_Security extends CI_Security { function xss_clean($str, $is_image = FALSE) { $CI =& get_instance(); $CI->load->library('My_cleaner'); return $CI->my_cleaner->clean_html($str); } } this works great for $this-input-post('post_var', TRUE); and $this-security-xss_clean($input); It is working very well except when I go into application/config/config.php and change $config['global_xss_filtering] = FALSE; to $config['global_xss_filtering] = TRUE; in that case, I just get a white page on every controllers action/function. Does anybody know what else I have to change to get global_xss_filtering = TRUE; to work when overriding the xss_clean function in system/core/Security.php through application/core/MY_Security.php? I'm guessing it might be something with the loader but I'm not sure where to start. The next option is to just replace the function in the system/core/Security.php file which I am trying to avoid. Thanks.

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  • How can my controls size be NaN when it is actually shown?

    - by Stian Karlsen
    I have a Grid which contains an Image in one of its columns. The image itself does not have any Width or Height set, but its size is correctly controlled through the ColumnDefinition set. From this I would assume that the image controller actually has a Width and Height set, but when I try to bind another element to its Width and Height it doesn't work. When debugging it turns out that the value of Image.Height and Image.Width are NaN. Why? <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="350"></ColumnDefinition> <ColumnDefinition Width="*"></ColumnDefinition> <ColumnDefinition Width="10"></ColumnDefinition> <ColumnDefinition Width="*"></ColumnDefinition> </Grid.ColumnDefinitions> <Grid Grid.Column="0" Margin="5"> <Image x:Name="_image" Source="image.jpg"></Image> </Grid> </Grid>

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  • How do I pass an NSString through 3 ViewControllers?

    - by dBloc
    hey, I'm currently using the iPhone SDK and I'm having trouble passing an NSString through 3 views I am able to pass an NSString between 2 view controllers but I am unable to pass it through another one. My code is as follows... `- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)index`Path { NSString *string1 = nil; NSDictionary *dictionary = [listOfItems objectAtIndex:indexPath.section]; NSArray *array = [dictionary objectForKey:@"items"]; string1 = [array objectAtIndex:indexPath.row]; //Initialize the detail view controller and display it. ViewController2 *vc2 = [[ViewController2 alloc] initWithNibName:@"ViewController2" bundle:[NSBundle mainBundle]]; vc2.string1 = string1; [self.navigationController pushViewController:vc2 animated:YES]; [vc2 release]; vc2 = nil; } in the "ViewController 2" implementations I am able use "string1" in the title bar by doing the following.... - (void)viewDidLoad { [super viewDidLoad]; self.navigationItem.title = string1; UIBarButtonItem *addButton = [[[UIBarButtonItem alloc] initWithImage:[UIImage imageNamed:@"icon_time.png"] style:UIBarButtonItemStylePlain //style:UIBarButtonItemStyleBordered target:self action:@selector(goToThirdView)] autorelease]; self.navigationItem.rightBarButtonItem = addButton; } but I also have a NavBar Button on the right side that I would like to push a new view - (void)goToThirdView { ViewController3 *vc3 = [[ViewController3 alloc] initWithNibName:@"ViewController3" bundle:[NSBundle mainBundle]]; [self.navigationController pushViewController:NESW animated:YES]; vc3.string1 = string1 ; [vc3 release]; vc3 = nil; } How do I pass on that same string to the third view? (or fourth)

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  • in Rails, with check_box_tag, how do I keep the checkboxes checked after submitting query?

    - by Sebastien Paquet
    Ok, I know this is for the Saas course and people have been asking questions related to that as well but i've spent a lot of time trying and reading and I'm stuck. First of all, When you have a model called Movie, is it better to use Ratings as a model and associate them or just keep Ratings in an array floating in space(!). Second, here's what I have now in my controller: def index @movies = Movie.where(params[:ratings].present? ? {:rating => (params[:ratings].keys)} : {}).order(params[:sort]) @sort = params[:sort] @ratings = Ratings.all end Now, I decided to create a Ratings model since I thought It would be better. Here's my view: = form_tag movies_path, :method => :get do Include: - @ratings.each do |rating| = rating.rating = check_box_tag "ratings[#{rating.rating}]" = submit_tag "Refresh" I tried everything that is related to using a conditional ternary inside the checkbox tag ending with " .include?(rating) ? true : "" I tried everything that's supposed to work but it doesn't. I don't want the exact answer, I just need guidance.Thanks in advance!

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  • Pass a model object while using a upload

    - by Dejan.S
    I'm trying to pass my model object along with the file I'm uploading but I'm stuck on how I should that should be done. This is the code I use now [AcceptVerbs(HttpVerbs.Post)] public ActionResult Upload(PageBody pageBody) { foreach (string file in Request.Files) { var hpf = Request.Files[file] as HttpPostedFileBase; if (hpf.ContentLength == 0) continue; string savedFileName = Path.Combine(AppDomain.CurrentDomain.BaseDirectory + "Content/Uploads/", Path.GetFileName(hpf.FileName)); hpf.SaveAs(savedFileName); _pageBody.Pictures.Add(new PageBodyPicture() { Picture = file }); } return View(pageBody); } here is my view code, I got the model.Id but there but it wont pass even if I put just Id to the Upload method. <form action="/Admin/Upload" enctype="multipart/form-data" method="post"> <%= Html.HiddenFor(model => model.Id)%> <input type="file" name="file" id="file" /><br /> <input type="submit" name="submit" value="Upload" /> </form>

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  • Why isn't my submit button centered?

    - by William
    For some reason my submit button isn't centered. http://prime.programming-designs.com/test_forum/viewboard.php?board=0 #submitbutton{ margin: auto; border: 1px solid #DBFEF8; background-color: #DBFEF8; color: #000000; margin-top: 5px; width: 100px; height: 20px; } here's the html. <form method=post action=add_thread.php?board=<?php echo''.$board.''; ?>> <div id="formdiv"> <div class="fieldtext1">Name</div> <div class="fieldtext1">Trip</div> <input type="text" name=name size=25 /> <input type="text" name=trip size=25 /> <div class="fieldtext2">Comment</div> <textarea name=post rows="4" cols="70"></textarea> <div class="fieldtext2">Fortune</div> <input type="checkbox" name="fortune" value="fortune" /> </div> <input type=submit value="Submit" id="submitbutton"> </form>

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • Update Input Value With jQuery, Old Value Submitted to Form

    - by Tyler DeWitt
    I've got a form with an input with id/name league_id <form accept-charset="UTF-8" action="/user" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="?"><input name="authenticity_token" type="hidden" value="bb92urX83ivxOZZJzWLJMcr5ZSuamowO9O9Sxh5gqKo="></div> <input id="league_id" name="league_id" type="text" value="11"> <select class="sport_selector" id="sport_type_id" name="sport_type_id"><option value="5" selected="selected">Football</option> <option value="25">Women's Soccer</option> <option value="30">Volleyball</option> <option value="10">Men's Soccer</option></select> <input name="commit" type="submit" value="Save changes"> </form> In another part of my page, I have a drop down that, when changed, clears the value of league_id $("#sport_type_id").change -> $("#league_id").val(null) $(this).parents('form:first').submit() If I debug this page, I can see the value get wiped from the text box, but when the form is submitted, my controller always gets the old value. I tried changing the name of the input and got the same results.

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  • How to compare a string with an option value

    - by user225269
    I have this html form which has options: <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> <option value="ADDRESS">Address</option> </select></td></td> </tr> And I'm trying to have this as the form action: if ('{$_POST["ADDRESS"]}'="ADDRESS") Which will compare if the value in the option in the html form matches the word "Address". If it matches then it will execute this query: $saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); Please I need help in here, I thinks its wrong: if ('{$_POST["ADDRESS"]}'="ADDRESS")

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