Search Results

Search found 31994 results on 1280 pages for 'input output'.

Page 626/1280 | < Previous Page | 622 623 624 625 626 627 628 629 630 631 632 633  | Next Page >

  • Focus on textbox based on URL.

    - by Cameron
    I have two forms on one page and want to have the input boxes focused based on the URL. So for example: domain.com/Default.aspx#login and domain.com/Default.aspx#register and the javascript I have this: window.document.getElementById('<%=txtUserName.ClientID %>').focus(); window.document.getElementById('<%=txtEmail.ClientID %>').focus(); it might be better if the urls are Default.aspx?action=login actually (not sure if this effects the way in which it would work)

    Read the article

  • How to select all parent objects into DataContext using single LINQ query ?

    - by too
    I am looking for an answer to a specific problem of fetching whole LINQ object hierarchy using single SELECT. At first I was trying to fill as much LINQ objects as possible using LoadOptions, but AFAIK this method allows only single table to be linked in one query using LoadWith. So I have invented a solution to forcibly set all parent objects of entity which of list is to be fetched, although there is a problem of multiple SELECTS going to database - a single query results in two SELECTS with the same parameters in the same LINQ context. For this question I have simplified this query to popular invoice example: public static class Extensions { public static IEnumerable<T> ForEach<T>(this IEnumerable<T> collection, Action<T> func) { foreach(var c in collection) { func(c); } return collection; } } public IEnumerable<Entry> GetResults(AppDataContext context, int CustomerId) { return ( from entry in context.Entries join invoice in context.Invoices on entry.EntryInvoiceId equals invoice.InvoiceId join period in context.Periods on invoice.InvoicePeriodId equals period.PeriodId // LEFT OUTER JOIN, store is not mandatory join store in context.Stores on entry.EntryStoreId equals store.StoreId into condStore from store in condStore.DefaultIfEmpty() where (invoice.InvoiceCustomerId = CustomerId) orderby entry.EntryPrice descending select new { Entry = entry, Invoice = invoice, Period = period, Store = store } ).ForEach(x => { x.Entry.Invoice = Invoice; x.Invoice.Period = Period; x.Entry.Store = Store; } ).Select(x => x.Entry); } When calling this function and traversing through result set, for example: var entries = GetResults(this.Context); int withoutStore = 0; foreach(var k in entries) { if(k.EntryStoreId == null) withoutStore++; } the resulting query to database looks like (single result is fetched): SELECT [t0].[EntryId], [t0].[EntryInvoiceId], [t0].[EntryStoreId], [t0].[EntryProductId], [t0].[EntryQuantity], [t0].[EntryPrice], [t1].[InvoiceId], [t1].[InvoiceCustomerId], [t1].[InvoiceDate], [t1].[InvoicePeriodId], [t2].[PeriodId], [t2].[PeriodName], [t2].[PeriodDateFrom], [t4].[StoreId], [t4].[StoreName] FROM [Entry] AS [t0] INNER JOIN [Invoice] AS [t1] ON [t0].[EntryInvoiceId] = [t1].[InvoiceId] INNER JOIN [Period] AS [t2] ON [t2].[PeriodId] = [t1].[InvoicePeriodId] LEFT OUTER JOIN ( SELECT 1 AS [test], [t3].[StoreId], [t3].[StoreName] FROM [Store] AS [t3] ) AS [t4] ON [t4].[StoreId] = ([t0].[EntryStoreId]) WHERE (([t1].[InvoiceCustomerId]) = @p0) ORDER BY [t0].[InvoicePrice] DESC -- @p0: Input Int (Size = 0; Prec = 0; Scale = 0) [186] -- Context: SqlProvider(Sql2008) Model: AttributedMetaModel Build: 3.5.30729.1 SELECT [t0].[EntryId], [t0].[EntryInvoiceId], [t0].[EntryStoreId], [t0].[EntryProductId], [t0].[EntryQuantity], [t0].[EntryPrice], [t1].[InvoiceId], [t1].[InvoiceCustomerId], [t1].[InvoiceDate], [t1].[InvoicePeriodId], [t2].[PeriodId], [t2].[PeriodName], [t2].[PeriodDateFrom], [t4].[StoreId], [t4].[StoreName] FROM [Entry] AS [t0] INNER JOIN [Invoice] AS [t1] ON [t0].[EntryInvoiceId] = [t1].[InvoiceId] INNER JOIN [Period] AS [t2] ON [t2].[PeriodId] = [t1].[InvoicePeriodId] LEFT OUTER JOIN ( SELECT 1 AS [test], [t3].[StoreId], [t3].[StoreName] FROM [Store] AS [t3] ) AS [t4] ON [t4].[StoreId] = ([t0].[EntryStoreId]) WHERE (([t1].[InvoiceCustomerId]) = @p0) ORDER BY [t0].[InvoicePrice] DESC -- @p0: Input Int (Size = 0; Prec = 0; Scale = 0) [186] -- Context: SqlProvider(Sql2008) Model: AttributedMetaModel Build: 3.5.30729.1 The question is why there are two queries and how can I fetch LINQ objects without such hacks?

    Read the article

  • C program to display a jpeg or bmp or pcx file.

    - by Raj
    What is the code in 'c' to display a picture file like jpeg file or bmp file or pcx file. For example the picture may be available in desktop and the program during execution must be given the path of the file as input and should display the image.(If it is in command line,it'll be excellent). Platform:Windows xp Turbo c compiler(or turboc++)

    Read the article

  • UNIX sort: Sorting something from the clipboard

    - by Iker Jimenez
    The other day I saw a colleague of mine using sort to sort a number of lines he copied from a text file. I've been trying to reproduce it myself and I cannot seem to find how. The requirements are as follow: Use sort from command line, plus whatever else you need to add to configure input Paste the text to be sorted from the clipboard Get the sorted result in the console

    Read the article

  • jquery autocomplete IE 9 not working

    - by Al3mor
    I am trying to autocomplete in a input, It is working fine in Chrome,Safari&Firefox . It is not working on IE 9 alone. Please help. $("#name").autocomplete({ select: function(event, iu) { id = event.toElement.innerText.split('-') $("#id_estudiante").val(id[1]); $("#FinancieroGrid").load('php/Financiero/librerias/FindStudent.php?action='+id[1].replace(' ','')); }, source:'php/Financiero/function/getstuden.php', minLength:1 });

    Read the article

  • Empty white space between the 2 images

    - by Shivanand
    I have placed 2 images side by side in a div besides input box "Search by Contact". In the browser I find there is a gap between the 2nd image(Button T) and the one on its left. I am unable to remove the gap. Any help is highly appreciated. Here is the link to the html page: Space between button T and the one on its left.

    Read the article

  • Webrat select_date selector failure.

    - by sharas
    Code in steps file: select_date user.date_of_birth, :from => "Date of birth" Selector fail When I register with valid user credentials # features/step_definitions/authentication_steps.rb:2 Could not find field: "user_date_of_birth_1i_1i" (Webrat::NotFoundError) ./features/step_definitions/authentication_steps.rb:9:in `/^I register with valid user credentials$/' features/authentication.feature:6:in `When I register with valid user credentials' HTML output seems to be normal: <select name="user[date_of_birth(1i)]" id="user_date_of_birth_1i"> Is it bug, or I am doing something wrong

    Read the article

  • Makefile variable initialization and export

    - by Michael
    somevar := apple export somevar update := $(shell echo "v=$$somevar") all: @echo $(update) I was hoping to apple as output of command, however it's empty, which makes me think export and := variable expansion taking place on different phases. how to overcome this?

    Read the article

  • Large File Download - Connection With Server Reset

    - by daveywc
    I have an asp.net website that allows the user to download largish files - 30mb to about 60mb. Sometimes the download works fine but often it fails at some varying point before the download finishes with the message saying that the connection with the server was reset. Originally I was simply using Server.TransmitFile but after reading up a bit I am now using the code posted below. I am also setting the Server.ScriptTimeout value to 3600 in the Page_Init event. private void DownloadFile(string fname, bool forceDownload) { string path = MapPath(fname); string name = Path.GetFileName(path); string ext = Path.GetExtension(path); string type = ""; // set known types based on file extension if (ext != null) { switch (ext.ToLower()) { case ".mp3": type = "audio/mpeg"; break; case ".htm": case ".html": type = "text/HTML"; break; case ".txt": type = "text/plain"; break; case ".doc": case ".rtf": type = "Application/msword"; break; } } if (forceDownload) { Response.AppendHeader("content-disposition", "attachment; filename=" + name.Replace(" ", "_")); } if (type != "") { Response.ContentType = type; } else { Response.ContentType = "application/x-msdownload"; } System.IO.Stream iStream = null; // Buffer to read 10K bytes in chunk: byte[] buffer = new Byte[10000]; // Length of the file: int length; // Total bytes to read: long dataToRead; try { // Open the file. iStream = new System.IO.FileStream(path, System.IO.FileMode.Open, System.IO.FileAccess.Read, System.IO.FileShare.Read); // Total bytes to read: dataToRead = iStream.Length; //Response.ContentType = "application/octet-stream"; //Response.AddHeader("Content-Disposition", "attachment; filename=" + filename); // Read the bytes. while (dataToRead > 0) { // Verify that the client is connected. if (Response.IsClientConnected) { // Read the data in buffer. length = iStream.Read(buffer, 0, 10000); // Write the data to the current output stream. Response.OutputStream.Write(buffer, 0, length); // Flush the data to the HTML output. Response.Flush(); buffer = new Byte[10000]; dataToRead = dataToRead - length; } else { //prevent infinite loop if user disconnects dataToRead = -1; } } } catch (Exception ex) { // Trap the error, if any. Response.Write("Error : " + ex.Message); } finally { if (iStream != null) { //Close the file. iStream.Close(); } Response.Close(); } }

    Read the article

  • Javascript Global Variables Not Working as expected. Help?

    - by capri corn
    I am new to Javascript. I am facing a problem with global variables. I can't figure out that why the global variables are not working as the code looks ok. Please Help me solve this problem. I will breifly explain the code first.I have some text on a page which changes to text field when clicked. When I define the variables inside the functions body the code starts working fine. When these variables are defined globally as in the following code, the console displays this error: the variable is not defined. Here my code: <!DOCTYPE HTML> <html> <head> <title>Span to Text Box - Demo - DOM</title> <script type="text/javascript" language="javascript"> var textNode = document.getElementById('text'); var textValue = textNode.firstChild.nodeValue; var textboxNode = document.getElementById('textbox'); var doneButton = document.getElementById('done'); function change() { textboxNode.setAttribute('value', textValue); textNode.style.display = 'none'; textboxNode.setAttribute('type','text'); doneButton.setAttribute('type','button'); } function changeBack() { textNode.firstChild.nodeValue = textboxNode.value; textNode.style.display = 'block'; textboxNode.setAttribute('type', 'hidden'); doneButton.setAttribute('type','hidden'); } </script> </head> <body> <p id="text" onClick="change()">Click me!</p> <form onSubmit="return false;"> <input type="hidden" id="textbox" /> <input type="hidden" id="done" onClick="changeBack()" value="Done" /> </form> </body> </html> Please Help! Thanks in Advance.

    Read the article

  • How does extern work in c++?

    - by symfony
    This is from the <iostream>: namespace std { extern istream cin; ///< Linked to standard input extern ostream cout; ... It seems by using extern the data types defined in other namespaces will just be available?

    Read the article

  • Why is YAML installing to my home directory instead of its proper directory?

    - by Zack Shapiro
    I keep getting the following error when installing Ruby 1.9.3-p125: It seems your ruby installation is missing psych (for YAML output). To eliminate this warning, please install libyaml and reinstall your ruby. I've tried installing LibYAML and for some reason it's installing in my home directory on OS X Lion where the Documents, Music, Pictures, etc. folders are. Any idea how I can get rid of this error, properly install YAML and never have to deal with this again?

    Read the article

  • Looping through all attributes of a XML element in XSLT

    - by TheGNUGuy
    Hey everyone, I am trying to use <xsl:for-each select="@*"> to grab all the attributes of a given element but when i do that my <xsl:choose> statement doesn't execute. Here is the element that I'm working with: <textBox id="Airfare" value="" label="text 1"/> Here is the XSLT template I'm using: <xsl:template match="textBox"> <div> <xsl:choose> <xsl:when test="@label"> <xsl:value-of select="@label"/> </xsl:when> <xsl:otherwise> <xsl:text>No Label Defined</xsl:text> </xsl:otherwise> </xsl:choose> <xsl:element name="input"> <xsl:attribute name="type">text</xsl:attribute> <xsl:for-each select="@*"> <xsl:choose> <xsl:when test="@id"> <xsl:attribute name="name">form_<xsl:value-of select="@id"/></xsl:attribute> <xsl:attribute name="id">form_<xsl:value-of select="@id"/></xsl:attribute> </xsl:when> <xsl:when test="@label"> </xsl:when> <xsl:otherwise> <xsl:copy-of select="current()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:element> </div> And when I generate the HTML using PHP I get this: <div>text 1<input type="text" id="Airfare" value="" label="text 1"></div> As you can see it didn't add form_ to the id attribute it didn't generate a name attribute and it didn't skip over the label attribute. Thanks for your help!

    Read the article

  • How to minify jquery files?

    - by chobo2
    Hi I am using jquery and I got a couple plugins that don't offer a minified version. So I want to take the full version and minfiy it but all the sites I have found that you input your javascript and it minifies it breaks the plugin. Like it must strip something out because I get a syntax error. So anyone got a good one that I can use?

    Read the article

  • Where does _CrtDbgReportW ouput in Windows Mobile?

    - by Ignas Limanauskas
    I am using ASSERTE macro to check for pre-conditions. According to its definition it is using ASSERT_BASE, which in turn calls _CrtDbgReportW to print out the message. Where does _CrtDbgReportW output goes to? I would assume that if the application is started from debugger, it would go to debugger window. Where would the messages go if it is not under debugger?

    Read the article

  • print webpage in two columns

    - by machaa
    Hi, How to print a webpage in two columns or one column as per the user input/choice. And when a take a print out I'm getting the website url on the top left side, How can we stop printing this? Regards

    Read the article

  • Problems after the installation of ubuntu

    - by anwar
    hello members can anyone help me solve this issue. i have just installed ubuntu for the 1st time using vmware on windows 7 everything has been installed smoothly but after the installation in the login screen username is coming and when i try to enter password it is not taking any input, keyboard is not working at all and after moving away from ubuntu keyboard and everthing else is working fine. plz help thanks in advance.

    Read the article

  • retriving python objects ...python newbie

    - by gizgok
    I have a Club class and Player Class.The player class has an attribute Fav.clubs which will have unique club values.So the user is suppose to enter various club names.Based on the club names I have to retrieve those club objects and establish the relationship that this particular player has this Fav.clubs.The attribute Fav.clubs in Player class should store the names of Club .Now what I have to do is,take input from user about fav.clubs.This will be a list.After that traverse each element in the list and acc to string name find the corresponding club object and then store that object instance in Player class.

    Read the article

  • Java web services client

    - by Bill
    I want to build a web services client that takes wsdl link as the input and generates java classes. I know we can do this directly using Netbeans IDE where we provide the wsdl location during project setup. But I want the wsdl location to be provided when the client starts running. How do I do this?

    Read the article

  • SQL & Linq To SQL Help

    - by cre-johnny07
    I have a table which is some thing like below.. Date ID 2009-07-01 1 2009-07-01 2 2009-07-01 3 2009-08-01 4 2009-08-01 5 2009-08-01 6 2009-09-01 7 2009-09-01 8 2009-10-01 9 2009-10-01 10 2009-11-01 11 .... Now I need to write a query which will show a output like below. Date Start End 2009-07 1 3 2009-08 4 6 2009-09 7 8 ... How can I do this.. Any help would be highly appreciated Thanking In Advance Johnny

    Read the article

< Previous Page | 622 623 624 625 626 627 628 629 630 631 632 633  | Next Page >