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  • ASP.net debug hangs until I delete vbproj.user

    - by Mike Robertson
    Intermittently when I start debugging a web application VS hangs (not responding). It will start OK if I run the appllication without debugging. When it has happened once it will do it every time until I delete the vbporj.user file. This problem appeared when I moved to Win7 64bit. I am using VS2008 Pro and everything is patched up to date. I am using the internal IIS7.

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  • Perl: Compare and edit underlying structure in hash

    - by Mahfuzur Rahman Pallab
    I have a hash of complex structure and I want to perform a search and replace. The first hash is like the following: $VAR1 = { abc => { 123 => ["xx", "yy", "zy"], 456 => ["ab", "cd", "ef"] }, def => { 659 => ["wx", "yg", "kl"], 456 => ["as", "sd", "df"] }, mno => { 987 => ["lk", "dm", "sd"] }, } and I want to iteratively search for all '123'/'456' elements, and if a match is found, I need to do a comparison of the sublayer, i.e. of ['ab','cd','ef'] and ['as','sd','df'] and in this case, keep only the one with ['ab','cd','ef']. So the output will be as follows: $VAR1 = { abc => { 123 => ["xx", "yy", "zy"], 456 => ["ab", "cd", "ef"] }, def => { 659 => ["wx", "yg", "kl"] }, mno => { 987 => ["lk", "dm", "sd"] }, } So the deletion is based on the substructure, and not index. How can it be done? Thanks for the help!! Lets assume that I will declare the values to be kept, i.e. I will keep 456 = ["ab", "cd", "ef"] based on a predeclared value of ["ab", "cd", "ef"] and delete any other instance of 456 anywhere else. The search has to be for every key. so the code will go through the hash, first taking 123 = ["xx", "yy", "zy"] and compare it against itself throughout the rest of the hash, if no match is found, do nothing. If a match is found, like in the case of 456 = ["ab", "cd", "ef"], it will compare the two, and as I have said that in case of a match the one with ["ab", "cd", "ef"] would be kept, it will keep 456 = ["ab", "cd", "ef"] and discard any other instances of 456 anywhere else in the hash, i.e. it will delete 456 = ["as", "sd", "df"] in this case.

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  • Delete all characters in a multline string up to a given pattern

    - by biffabacon
    Using Python I need to delete all charaters in a multiline string up to the first occurrence of a given pattern. In Perl this can be done using regular expressions with something like: #remove all chars up to first occurrence of cat or dog or rat $pattern = 'cat|dog|rat' $pagetext =~ s/(.*?)($pattern)/$2/xms; What's the best way to do it in Python?

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  • Updating rows using "in" operator in "where" clause

    - by doublep
    Hi. I stumbled upon SQL behavior I don't understand. I needed to update several rows in a table at once; started with just finding them: SELECT * FROM some_table WHERE field1 IN (SELECT ...) This returned a selection of about 60 rows. Now I was pretty confident I got the subquery right, so I modified the first part only: UPDATE some_table SET field2 = some_value WHERE field1 IN (SELECT ...) In other words, this was exactly as the first query after the WHERE. However, it resulted in 0 rows updated, whereas I would expect those 60. Note that the statement above would change field2, i.e. I verified that some_value was not present in the selected rows. The subquery was a modestly complicated SQL piece with 2 (different) tables, 1 view, joins and its own WHERE clause. In case this matters, it happened with Oracle Database 10g. So, the question is, why UPDATE didn't touch the rows returned by SELECT?

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  • Parenthesis operator in C. What is the effect in the following code

    - by Andre
    Hi everyone, I was playing with a macro to enable/disable traces when I came out with the following code when the macro is disabled: int main { ("Hello world"); } This code is valid and I got the desired effect (nothing happens when the macro is disabled) but I couldn't figure out what exactly is happening. Is the compiler seeing the parenthesis as a "nameless" method declaration? To make it clearer the code is : #ifdef TRACE #define trace printf("%s %d -> ",__FILE__, __LINE__);printf else #define trace #endif int main { trace("Hello world"); } Thanks in advance.

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  • PG::Error: ERROR: operator does not exist: integer ~~ unknown

    - by rsvmrk
    I'm making a search-function in a Rails project with Postgres as db. Here's my code def self.search(search) if search find(:all, :conditions => ["LOWER(name) LIKE LOWER(?) OR LOWER(city) LIKE LOWER(?) OR LOWER(address) LIKE LOWER(?) OR (venue_type) LIKE (?)", "%#{search}%", "%#{search}%", "%#{search}%", "%#{search}%"]) else find(:all) end end But my problem is that "venue_type" is an integer. I've made a case switch for venue_type def venue_type_check case self.venue_type when 1 "Pub" when 2 "Nattklubb" end end Now to my question: How can I find something in my query when venue_type is an int?

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  • how to delete lowercase words from a string in python

    - by gaggina
    I'm new in python and I'm having some issues doing a simple thing. I've an array (or list as it's said in pyton) like this: list = [ 'NICE dog' , 'blue FLOWER' , 'GOOD cat' , 'YELLOW caw'] As you see each element of this array contains some words. These words is both lowercase and uppercase. How I can delete from this array each lowercase words? For example I'd like to have as result this list: list = [ 'NICE' , 'FLOWER' , 'GOOD' , 'YELLOW']

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  • How does the " is " operator work internally

    - by JDMX
    I want to compare the type of an object to a type to see if they are the same. I do not have the object, just the type of the object. I can do type1 == type2 and get general equality I can have a recursive loop where I repeat the above step for type1.BaseType until the BaseType is null. I can do type1.GetInterface( type2.FullName ) != null to check if type2 is an interface of type1 If I put it all together, I get if ( type2.IsInterface ) return type1.GetInterface( type2.FullName ) != null; while ( type1 != null ) { if ( type1 == type2 ) return true; type1 = type1.BaseType; } return false; Is that all the is keyword is. I cannot find the right keyword to plug into the Reflector search to find the function and a google search on "is" was not really helpful

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  • C: switch case with logical operator

    - by Er Avinash Singh
    While I am new to c and want help in this program my code is : #include<stdio.h> #include<conio.h> void main(){ int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in turbo c and it shows no error and the output is helloI thought somebody Please, let me know how is this working ??? note :- here break is not the case as I intentionally left them.

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  • SQL AND operator not working properly

    - by Chandana De Silva
    I have following two tables LandParcels Table Blockid ParcelNo storPri ======= ======== ======= 52000105 3 State 52000105 4 Private 52000105 5 State Actions Table Blockid ParcelNo ActionTaken ======= ======== =========== 52000105 3 Received 52000105 3 Send to Computer 52000105 4 Received 52000105 5 Received I want to find the records Received but not Send to Computer Here is my query select l.blockid, l.parcelno from landparcels l left join actions ac on l.blockid = ac.blockid and l.parcelno = ac.parcelno where ac.actiontaken = 'Received' and ac.actiontaken <> 'Send to Computer' and ac.blockid = 52000105 The result is Blockid ParcelNo ======= ======== 52000105 3 52000105 4 52000105 5 I want ParcelNo 4 and 5

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  • Writing a batch file to delete files with wildcards

    - by iamthejeff
    I have multiple websites set up in the same folder, and I want to create a batch file that will delete the cache in each of them without having to add a new line for each site. For example I am using this: del /S /Q D:\www\site-name\cache\* Which works, but I have to add a new line for every site in D:\www. The del command doesn't support: del /S /Q D:\www\*\cache\* So what is a better way to do this?

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  • Is the ruby operator ||= intelligent?

    - by brad
    I have a question regarding the ||= statement in ruby and this is of particular interest to me as I'm using it to write to memcache. What I'm wondering is, does ||= check the receiver first to see if it's set before calling that setter, or is it literally an alias to x = x || y This wouldn't really matter in the case of a normal variable but using something like: CACHE[:some_key] ||= "Some String" could possibly do a memcache write which is more expensive than a simple variable set. I couldn't find anything about ||= in the ruby api oddly enough so I haven't been able to answer this myself. Of course I know that: CACHE[:some_key] = "Some String" if CACHE[:some_key].nil? would achieve this, I'm just looking for the most terse syntax.

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  • Shift operator in Java bizarre program output

    - by Umesh Kacha
    I came across the following program and it behaving in unexpected manner. public class ShiftProgram { public static void main(String[] args) { int i = 0; while(-1 << i != 0) i++; System.out.println(i); } } If we think about this program output, when it reaches 32 while loop condition should return false and terminate and it should print 32. If you ran this program, it does not print anything but goes into an infinite loop. Any idea whats going on? Thank you in advance.

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  • using 'or' operator not working for menu

    - by John Wilkes
    In my code here, I have a CSS class called "active" which I use if the $_GET['page'] == tutorials, php, mysql, etc... The problem is, even if the 'page' variable is not equal to any of these values, the Tutorials button in this case is still active for some reason. Any ideas why this would be happening? Am I using the 'or' (||) operand incorrectly? <?php if($_GET['page'] == 'tutorials' || 'php' || 'mysql' || 'html' || 'css' || 'js') { ?> <li class="active"> <?php } else { ?> <li> <?php } ?> <a href="index.php?page=tutorials">Tutorials</a> <ul> <li><a href="index.php?page=php">PHP</a></li> <li><a href="index.php?page=mysql">MySQL</a></li> <li><a href="index.php?page=html">HTML</a></li> <li><a href="index.php?page=css">CSS</a></li> <li><a href="index.php?page=js">JS</a></li> </ul> </li>

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  • Using the AND and NOT Operator in Python

    - by NoahClark
    Here is my custom class that I have that represents a triangle. I'm trying to write code that checks to see if self.a, self.b, and self.c are greater than 0, which would mean that I have Angle, Angle, Angle. Below you will see the code that checks for A and B, however when I use just self.a != 0 then it works fine. I believe I'm not using & correctly. Any ideas? Here is how I am calling it: print myTri.detType() class Triangle: # Angle A To Angle C Connects Side F # Angle C to Angle B Connects Side D # Angle B to Angle A Connects Side E def __init__(self, a, b, c, d, e, f): self.a = a self.b = b self.c = c self.d = d self.e = e self.f = f def detType(self): #Triangle Type AAA if self.a != 0 & self.b != 0: return self.a #If self.a > 10: #return AAA #Triangle Type AAS #elif self.a = 0: #return AAS #Triangle Type ASA #Triangle Type SAS #Triangle Type SSS #else: #return unknown

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  • Cannot delete a remote branch created unintentionally

    - by Himel
    $ git branch -a * SocialAct master remotes/origin/HEAD -> origin/master remotes/origin/SocialAct remotes/origin/social I want to delete the remote branch "remotes/origin/social", and applied folloing command: $ git branch -d -r origin/social Deleted remote branch origin/social (was 26f6f61). But I have no idea how to bring these changes remotely so that the branches are deleted from origin and everyone can see the changes. I tried git push but that does not work Any help.

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