Search Results

Search found 34093 results on 1364 pages for 'identity access managem'.

Page 63/1364 | < Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >

  • VBA: How go I get the total width from all controls in an MS-Access form?

    - by Stefan Åstrand
    Hi, This is probably very basic stuff, but please bear in mind I am completely new to these things. I am working on a procedure for my Access datasheet forms that will: Adjust the width of each column to fit content Sum the total width of all columns and subtract it from the size of the window's width Adjust the width of one of the columns to fit the remaining space This is the code that adjusts the width of each column to fit content (which works fine): Dim Ctrl As Control Dim Path As String Dim ClmWidth As Integer 'Adjust column width to fit content For Each Ctrl In Me.Controls If TypeOf Ctrl Is TextBox Then Path = Ctrl.Name Me(Path).ColumnWidth = -2 End If Next Ctrl How should I write the code so I get the total width of all columns? Thanks a lot! Stefan Solution This is the code that makes an Access datasheet go from this: To this: Sub AdjustColumnWidth(frm As Form, clm As String) On Error GoTo HandleError Dim intWindowWidth As Integer ' Window width property Dim ctrl As Control ' Control Dim intCtrlWidth As Integer ' Control width property Dim intCtrlSum As Integer ' Control width property sum Dim intCtrlAdj As Integer ' Control width property remaining after substracted intCtrSum 'Adjust column width to standard width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name frm(Path).ColumnWidth = 1500 End If Next ctrl 'Get total column width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name intCtrlWidth = frm(Path).ColumnWidth If Path <> clm Then intCtrlSum = intCtrlSum + intCtrlWidth End If End If Next ctrl 'Adjust column to fit window intWindowWidth = frm.WindowWidth - 270 intCtrlAdj = intWindowWidth - intCtrlSum frm.Width = intWindowWidth frm(clm).ColumnWidth = intCtrlAdj Debug.Print "Totalt (Ctrl): " & intCtrlSum Debug.Print "Totalt (Window): " & intWindowWidth Debug.Print "Totalt (Remaining): " & intCtrlAdj Debug.Print "clm : " & clm HandleError: GeneralErrorHandler Err.Number, Err.Description Exit Sub End Sub Code to call procedure: Private Sub Form_Load() Call AdjustColumnWidth(Me, "txtDescription") End Sub

    Read the article

  • How to handle authenticated user access to resources in document oriented system?

    - by Jeremy Raymond
    I'm developing a document oriented application and need to manage user access to the documents. I have a module that handles user authentication, and another module that handles document CRUD operations on the data store. Once a user is authenticated I need to enforce what operations the user can and cannot perform to documents based upon the user's permissions. The best option I could think of to integrate these two pieces together would be to create another module that duplicates the data API but that also takes the authenticated user as a parameter. The module would delegate the authorization check to the auth module and delegate the document operation to the data access module. Something like: -module(auth_data_access). % User is authenticated (logged into the system) % save_doc validates if user is allowed to save the given document and if so % saves it returning ok, else returns {error, permission_denied} save_doc(Doc, User) -> case auth:save_allowed(Doc, User) of ok -> data_access:save_doc(Doc); denied -> {error, permission_denied} end end. Is there a better way I can handle this?

    Read the article

  • How can you connect to a password protected MS Access Database from a Spring JdbcTemplate?

    - by Tim Visher
    I need to connect to a password protected MS Access 2003 DB using the JDBC-ODBC bridge. I can't find out how to specify the password in the connect string, or even if that is the correct method of connecting. It would probably be relevant to mention that this is a Spring App which is accessing the database through a JdbcTemplate configured as a datasource bean in our application context file. Some relevant snippets: from application-context.xml <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate"> <property name="dataSource" ref="legacyDataSource" /> </bean> <bean id="jobsheetLocation" class="java.lang.String"> <constructor-arg value="${jobsheet.location}"/> </bean> <bean id="legacyDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.legacy.driverClassName}" /> <property name="url" value="${jdbc.legacy.url}"/> <property name="password" value="-------------" /> </bean> from our build properties jdbc.legacy.driverClassName=sun.jdbc.odbc.JdbcOdbcDriver jdbc.legacy.url=jdbc:odbc:Driver\={Microsoft Access Driver (*.mdb)};Dbq\=@LegacyDbPath@;DriverID\=22;READONLY\=true Any thoughts?

    Read the article

  • "Too many indexes on table" error when creating relationships in Microsoft Access 2010.

    - by avianattackarmada
    I have tblUsers which has a primary key of UserID. UserID is used as a foreign key in many tables. Within a table, it is used as a foreign key for multiple fields (e.g. ObserverID, RecorderID, CheckerID). I have successfully added relationships (with in the the MS Access 'Relationship' view), where I have table aliases to do the multiple relationships per table: *tblUser.UserID - 1 to many - tblResight.ObserverID *tblUser_1.UserID - 1 to many - tblResight.CheckerID After creating about 25 relationships with enforcement of referential integrity, when I try to add an additional one, I get the following error: "The operation failed. There are too many indexes on table 'tblUsers.' Delete some of the indexes on the table and try the operation again." I ran the code I found here and it returned that I have 6 indexes on tblUsers. I know there is a limit of 32 indexes per table. Am I using the relationship GUI wrong? Does access create an index for the enforcement of referential integrity any time I create a relationship (especially indexes that wouldn't turn up when I ran the script)? I'm kind of baffled, any help would be appreciated.

    Read the article

  • Data Type Not Consistent In MS Access? (Set new field as "TEXT" but system treats it as "Yes/No" field)

    - by user3522506
    I already have an SQL command that will insert any string in the field. But it doesn't accept any string, giving me "No value given for one or more required parameters". But if my string is "Yes" or "No", it will update successfully. And in MS Access, will appear as 0 or -1 even though I set the field as text even in the beginning. Could there be any configuration I have made in my MS Access 2007? con = New OleDbConnection(cs) con.Open() Dim cb As String = "Update FS_Expenses set FS_Date=#" & dtpDate2.Text & "#,SupplierID='" & txtSupplierID.Text & "', TestField=" & Label1.Text & " where ID=" & txtID2.Text & "" cmd = New OleDbCommand(cb) cmd.Connection = con cmd.ExecuteReader() MessageBox.Show("Successfully updated!", "Record", MessageBoxButtons.OK, MessageBoxIcon.Information) con.Close() TestField is already a TEXT data type, Label1.Text value is "StringTest", will give the error. However, set Label1.Text value as = "Yes", SQL will execute successfully. Therefore, field must have not been saved as TEXT.

    Read the article

  • Primary Key Identity Value Increments On Unique Key Constraint Violation

    - by Jed
    I have a SqlServer 2008 table which has a Primary Key (IsIdentity=Yes) and three other fields that make up a Unique Key constraint. In addition I have a store procedure that inserts a record into the table and I call the sproc via C# using a SqlConnection object. The C# sproc call works fine, however I have noticed interesting results when the C# sproc call violates the Unique Key constraint.... When the sproc call violates the Unique Key constraint, a SqlException is thrown - which is no surprise and cool. However, I notice that the next record that is successfully added to the table has a PK value that is not exactly one more than the previous record - For example: Say the table has five records where the PK values are 1,2,3,4, and 5. The sproc attempts to insert a sixth record, but the Unique Key constraint is violated and, so, the sixth record is not inserted. Then the sproc attempts to insert another record and this time it is successful. - This new record is given a PK value of 7 instead of 6. Is this normal behavior? If so, can you give me a reason why this is so? (If a record fails to insert, why is the PK index incremented?) If this is not normal behavior, can you give me any hints as to why I am seeing these symptoms?

    Read the article

  • My Access KeyChain certificate [Xcode]

    - by Momeks
    Hi , i create a provision and developer identity.certificate with apple provision assistant and i have huge problem , everything done , but when i add my certificate into KeyChain , the certificate add , but doesn't show on the Keys and my Certificate :( and xcode Organizer says a valid signing identity matching this profile could not be found in your keychain and compiler : Code Sign error: The identity 'iPhone Developer' doesn't match any valid certificate/private key pair in the default keychain i didn't have this problem on the leopard with sdk 3.1 my current os is 10.6.2 SDK 3.1.3 what's the problem ?

    Read the article

  • C#/Java: Proper Implementation of CompareTo when Equals tests reference identity

    - by Paul A Jungwirth
    I believe this question applies equally well to C# as to Java, because both require that {c,C}ompareTo be consistent with {e,E}quals: Suppose I want my equals() method to be the same as a reference check, i.e.: public bool equals(Object o) { return this == o; } In that case, how do I implement compareTo(Object o) (or its generic equivalent)? Part of it is easy, but I'm not sure about the other part: public int compareTo(Object o) { if (! (o instanceof MyClass)) return false; MyClass other = (MyClass)o; if (this == other) { return 0; } else { int c = foo.CompareTo(other.foo) if (c == 0) { // what here? } else { return c; } } } I can't just blindly return 1 or -1, because the solution should adhere to the normal requirements of compareTo. I can check all the instance fields, but if they are all equal, I'd still like compareTo to return a value other than 0. It should be true that a.compareTo(b) == -(b.compareTo(a)), and the ordering should stay consistent as long as the objects' state doesn't change. I don't care about ordering across invocations of the virtual machine, however. This makes me think that I could use something like memory address, if I could get at it. Then again, maybe that won't work, because the Garbage Collector could decide to move my objects around. hashCode is another idea, but I'd like something that will be always unique, not just mostly unique. Any ideas?

    Read the article

  • The name/identity of the invoker of a web service

    - by Swamy g
    I have a SOAP web service which I call from two clients using axis2. Can the web service know from which of these two clients the call originated from? If so, how do I know that during runtime? Is there any API provided to lookup the name of the invoker of a particular web service by that web service. Thanks.

    Read the article

  • Retrieve web user's Identity outside of request scope

    - by Kendrick
    I have an ASP.NET app that logs Audit reports using nHibernate's IPreUpdateListener. In order to set the current user in the Listener events, I was using System.Security.Principal.WindowsIdentity.GetCurrent(). This works fine when debugging on my machine, but when I move it to the staging server, I'm getting the ASP.NET process credentials, not the requesting user. In the ASP.NET page, I can use Request.LogonUserIdentity (which works fine since I'm using integrated authentication), but how do I reference this user directly without having to pass it directly to my event? I don't want to have to pass this info through the pipeline because it really doesn't belong in the intermediate events/calls.

    Read the article

  • Solve code issue - string identity testing

    - by kovibb
    Please for help with shell script. I really dont understand where is problem. Where I write to the Input variable for example /home/Kovi/Deskop/netlist.exe I still get true answer but the extension "exe" is not "scs". I also try "==" but it didnt working. Please some advice. Thank you very much. echo -n "Insert Entire Path (with file name and it's extension) of Input Netlist > " read Input if [ "${Input##*.}"="scs" ]; then echo "Patch verification is succesful.; else echo "Patch verification is failed, script was aborted. File dont exist or is empty or unreadable or is not spectre netlist." error_exit; fi

    Read the article

  • importing data using get or create - identity error 1062

    - by hamackey
    I am importing data from a mssql database into mysql. Works except when it encounters the id of a previous entry. id is unique. I need to get entries that already exist so that they can be placed in the work of the day. Error is IntegrityError: (1062, "Duplicate entry '001355338' for key 2") This entry is already in the database. I need it entered for that day, but can not have it added to the table. It is already there. def handle(self, *args, **options): 59 #patients_local = Patient.objects.all() 60 #attendings_local = Attending.objects.all() 61 connection = pyodbc.connect("XXXXXXXXXXX") 62 cursor = connection.cursor() 63 cursor.execute(COMMAND) 64 rows = cursor.fetchall() 65 for row in rows: 66 # get_or_create returns (object, boolean) 67 p, created = Patient.objects.get_or_create( 68 first_name = row.Firstname, 69 middle_name = '', 70 last_name = row.Lastname, 71 id = row.id, 72 )

    Read the article

  • Managing server instance identity on EC2

    - by kikibobo
    I recently brought up a cluster on EC2, and I felt like I had to invent a lot of things. I'm wondering what kinds of tools, patterns, ideas are out there for how to deal with this. Some context: I had 3 different kinds of servers, so first I created AMIs for each of them. The first AMI had zookeeper, so step one in deploying the system was to get the zookeeper server running. My script then made a note of the mapping between EC2's completely arbitrary and unpredictable hostnames, and the zookeeper server. Then as I brought up new instances of the other 2 kinds of servers, the first thing I would do is ssh to the new server, and add the zookeeper server to its /etc/hosts file. Then as the server software on each instance starts up, it can find zookeeper. Obviously this is a problem that lots of people have to solve, and it probably works a little bit differently in different clouds. Are there products that address this concept? I was pretty surprised that EC2 didn't provide some kind of way to tie your own name to its name. Thanks for any ideas.

    Read the article

  • Identity operators in Swift

    - by Tao
    If a is identical to c, b is identical to c, why a is not identical to b? var a = [1, 2, 3] var b = a var c = a[0...2] a === c // true b === c // true a === b // false If a, b, c are constants: let a = [1, 2, 3] let b = a let c = a[0...2] a === c // true b === c // true a === b // true

    Read the article

  • SQL SERVER – Change Database Access to Single User Mode Using SSMS

    - by pinaldave
    I have previously written about how using T-SQL Script we can convert the database access to single user mode before backup. I was recently asked if the same can be done using SQL Server Management Studio. Yes! You can do it from database property (Write click on database and select database property) and follow image. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Installed Ubuntu 12.04.01 with Windows XP but lost access to Windows XP

    - by Bob D
    The First time I tried to install Ubuntu the installer installed it on my D drive. This resulted in only booting to Windows XP with no access to Ubuntu. I had to download a disk partitioning program to undo all of this. A tip from the Internet said to create a partition on the C drive for Ubuntu, so I did along with a Swap Partition. I did this manually because the installer on the CD would not do so and would not let me do so from within the installer program. With the fresh partitions created for Ubuntu I let the installer do its thing. The computer rebooted and came up in Ubuntu. I then installed WINE and all was well. Then I shut the computer down for the night. The next day I turned on the computer and it booted directly into Ubuntu. I can see the Windows partition and all the files but it will not allow me to switch to the Windows XP OS. Does not even give me a choice to do so. I have reinstalled Ubuntu several times and each time is the same, I cannot access Windows XP anymore. Right now I am in a fresh install with only whatever the installer installed. How do I fix this?! I have tried the hold the shift key to see if something called GRUB shows up, but no. I tried shifting the order of boot in GRUB but that did not work either. I tried using EasyBCD but that will not run. One symptom I do not understand, my monitor will post a graphic when the computer reboots that the cable is disconnected, this is normal. Then when the computer gets to the actual boot process it will display the splash screens etc and it did this for Windows XP as well. But now something new has popped up, while booting Ubuntu after where it probably should be showing me a menu to pick what OS I want to boot, the monitor posts "Input Unsupported" until Ubuntu loads. I have never seen it post this before, maybe a clue to someone.

    Read the article

  • Extending the InputBox function for MS Access Forms

    While it's not possible to change the behavior of the InputBox function, this article illustrates how to create your own Access form that includes a text box with its InputMask property set to Password, and then use that form instead of the one generated by the VBA InputBox function.

    Read the article

  • Developing your Data Access Layer with ADO.NET Entity Framework 4

    Entity Framework has evolved in the light of feedback. ADO.NET Entity Framework 4 is now better able to accommodate different development methodologies. A welcome improvement is the way that, the application designer now has a range of options in the way that Entity Framework creates the Data Access layer. Prasanna returns to Simple-Talk to explain the significance of the changes.

    Read the article

  • Cannot access localhost without internet connection

    - by Pavel K.
    for some reason i cannot access localhost without internet connection in ubuntu, as soon as i disconnect from internet (with gui networkmanager), both "ping localhost" and "ping 127.0.0.1" return: ping: sendmsg: Operation not permitted i switched off iptables, "iptables -L" gives: Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination what could be the problem?

    Read the article

  • .NET Reflector 7.2 Early Access Build 2 Released: Performance Critical

    - by Bart Read
    I've just posted a write-up of some of the performance tuning I've done to improve .NET Reflector 7.2's start-up time here: http://www.reflector.net/2011/05/net-reflector-7-start-up-time-running-out-of-gas-or-pedal-to-the-metal/ You can get the new build from the .NET Reflector homepage at http://www.reflector.net/. Please remember to give us your feedback in the forum, at http://forums.reflector.net/, using the tags #7.2 and #eap. Technorati Tags: reflector,early access,7.2

    Read the article

  • Root Access: Don Dodge talks to 3 time founder Jennifer Reuting of DocRun

    Root Access: Don Dodge talks to 3 time founder Jennifer Reuting of DocRun Three time startup founder Jennifer Reuting, CEO of DocRun, and author of LLCs for Dummies, sits down with Don Dodge to talk startups. Jennifer started her first company at 17 from the ashes of a failed company. Jennifer is revolutionizing the legal docs business with DocRun. Inspiring interview. From: GoogleDevelopers Views: 258 12 ratings Time: 44:37 More in Science & Technology

    Read the article

< Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >