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  • MD5 password twice

    - by NoviceCoding
    I know MD5's safety is under question lately and this is the reason a lot of people are using salt (I dont understand this at all btw) but I was wondering if you wanted to easily implement a safe system in php can you just md5 something twice? like test 098f6bcd4621d373cade4e832627b4f6 fb469d7ef430b0baf0cab6c436e70375 So basically: $val = 'test'; $val = md5($val); $val = md5($val); Would that solve the whole rainbow security stuff? Is there an easy/noob proof way of making secure database passwords in php?

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  • Joining two tables (through a link), one which may yield multiple rows, together into one result.

    - by Eikern
    Lets say I've got a table listing car brands or models: Cars: Id | Brand ----------- 1 | BMW 2 | Audi 3 | Volvo And I've also got another table which links features. Link: Id | carid | featureid ----------------------- 1 | 1 | 1 2 | 1 | 2 3 | 2 | 2 4 | 3 | 1 5 | 3 | 2 6 | 3 | 3 And I've got the table listing the features. Features: Id | Feature ----------- 1 | A/C 2 | 4WD 3 | Heated seats I want to list these results on my front page like this: BMW A/C 4WD Audi 4WD Volvo A/C 4WD Heated seats What's the best/most efficient way of doing this (using PHP and MySQL)?

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  • SQL - get the article title with the last comment date

    - by stacker
    I have articles table, article_comments. I want to get the value: last_modified_all of article. I need this value to be the great date of this two: the last_modified field of articles table. the last comment of article_comments last_modified column. Can someone help me? the structure is very simple, and you can guess is without problem.

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  • How to join list of strings?

    - by satsurae
    Hi all, This is probably seriously easy to solve for most of you but I cannot solve this simply putting str() around it can I? I would like to convert this list: ['A','B','C'] into 'A B C'. Thanks in advance!!

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  • Combining Java hashcodes into a "master" hashcode

    - by Nick Wiggill
    I have a vector class with hashCode() implemented. It wasn't written by me, but uses 2 prime numbers by which to multiply the 2 vector components before XORing them. Here it is: /*class Vector2f*/ ... public int hashCode() { return 997 * ((int)x) ^ 991 * ((int)y); //large primes! } ...As this is from an established Java library, I know that it works just fine. Then I have a Boundary class, which holds 2 vectors, "start" and "end" (representing the endpoints of a line). The values of these 2 vectors are what characterize the boundary. /*class Boundary*/ ... public int hashCode() { return 1013 * (start.hashCode()) ^ 1009 * (end.hashCode()); } Here I have attempted to create a good hashCode() for the unique 2-tuple of vectors (start & end) constituting this boundary. My question: Is this hashCode() implementation going to work? (Note that I have used 2 different prime numbers in the latter hashCode() implementation; I don't know if this is necessary but better to be safe than sorry when trying to avoid common factors, I guess -- since I presume this is why primes are popular for hashing functions.)

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  • Can I store and join based on external attributes in Lucene/Solr

    - by Kibbee
    Is there a way to store information about documents that are stored in Lucene such that I don't have to update the entire document to update certain attributes about the documents? For instance, let's say I had a bunch of documents, and that I wanted to update a permissions list of who was allowed to see the documents on a daily, or more frequent, basis. Would it be possible to update all the permissions each day, without updating all the documents. I could do it by keeping a exactly which permissions were added and removed, but I would rather just be able to take the end list of permissions, and use that, rather than have to keep track of all the permission changes and post those entire documents to Lucene.

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  • SQL Join query, getting ManagerName

    - by user279521
    I have an tblEmployeeProfile & a tblPersonnel. tblPersonnel is an HR table, that consists of all employees in the company; tblEmployeeProfile contains details about an employee's position. tblPersonnel.PersonnelID tblPersonnel.FirstName tblPersonnel.MiddleName tblPersonnel.LastName tblPersonnel.PhoneNumber tblPersonnel.Email tblEmployeeProfile.EmployeeID tblEmployeeProfile.ManagerID tblEmployeeProfile.DepartmentID tblEmployeeProfile.JobCategoryID tblEmployeeProfile.SalaryID I want to return a record with the following fields: EmployeeID, FirstName, MiddleName, LastName, Email, ManagerFullName where EmployeeID = @EmployeeID *tblEmployeeProfile.ManagerID = tblPersonnel.PersonnelID* I can't seem to get the query correct for getting the ManagerFullName

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  • Native arrays and computing hashvalues (VB, C#)

    - by Jeffrey Kern
    I feel bad asking this question but I am currently not able to program and test this as I'm writing this on my cell-phone and not on my dev machine :P (Easy rep points if someone answers! XD ) Anyway, I've had experience with using hashvalues from String objects. E.g., if I have StringA and StringB both equal to "foo", they'll both compute out the same hashvalue, because they're set to equal values. Now what if I have a List, with T being a native data type. If I tried to compute the hashvalue of ListA and ListB, assuming that they'd both be the same size and contain the same information, wouldn't they have equal hashvalues as well?

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  • mysql joins - how to find all children that belongs to ALL parents

    - by kimsia
    I have three mysql tables items the columns are id, title items_in_categories the columns are id, item_id, category_id categories the columns are id, title I want to find all the items that belong to ALL the stated categories. Not any one category, but ALL categories Eg, if I want to search all the items that belongs to category id 3 and 5 I would like to use as simple a way as possible. I have tried AND and a nested NOT EXISTS as stated in the mysql manual. Nothing worked.

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  • x=["key" => "value"]. How does it work in Ruby?

    - by Earlz
    Ok, so I was comparing some stuff in my own DSL to Ruby. One construct they both support is this x=["key" => "value"] Knowing the difference between arrays and hashes, I would think this to be illegal, but the result in Ruby is [{"key" => "value"}] Why is this? And with this kinda syntax why can't you do x=("key" => "value") Why is an array a special case for implicitly created hashes?

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  • Problem in Union Join For MySQL Query

    - by Mac Taylor
    hey guys i managed to select from a table that saves my latest posts but i need to have double condition in selection here is my code : $sql_query = "SELECT b.*,u.username AS MY_Sender FROM TABLE_users u,TABLE_blogs b Where b.reciever = '0' AND u.user_id = b.sender UNION SELECT b.*,u.username AS MY_reciever FROM TABLE_users u,TABLE_blogs b Where b.reciever != '0' AND u.user_id = b.reciever ORDER BY bid DESC LIMIT 0,7 "; but MY_reciever is Null and empty Am i wrong in using UNION for this need ?!

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  • Hibernate inserting into join table

    - by Karl
    I got several entities. Two of them got a many-to-many relation. When I do a bigger operation on these entities it fails with this exception: org.hibernate.exception.ConstraintViolationException: could not insert collection rows: I execute the operation i a @Transactional context. I don't do any explicit flushing i my daos. The flush is triggered by a query. In the queue are 15 elements (all of the same structure). one of them always fails (but it's always a different one (I checked) and always at a different position). Does anybody have a hint for me for what I might do wrong? My Mapping: @ManyToMany(targetEntity = CategoryImpl.class) protected Set<Category> categories = new HashSet<Category>();

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  • SQL COUNT records in table 2 JOINS away

    - by Fred K
    Using MySQL, I have three tables: projects: ID name 1 "birthday party" 2 "soccer match" 3 "wine tasting evening" 4 "dig out garden" 5 "mountainbiking" 6 "making music" batches: ID projectID templateID when 1 1 1 7 days before 2 1 1 1 day before 3 4 2 21 days before 4 4 1 7 days before 5 5 1 7 days before 6 3 5 7 days before 7 3 3 14 days before 8 5 1 14 days before templates: ID message 1 "Hi, I'd like to invite ..." 2 "Dear Sir, Madam, ..." 3 "Can you please ..." 4 "Would you like to ..." 5 "To all dear friends ..." 6 "Does any of you guys ..." I would like to display a table of templates and the number of projects they're used in. So, the result should be: templateID projectCount 1 3 2 1 3 1 4 0 5 1 6 0 I've tried all kinds of SQL queries using various JOINs, but I guess this is too complicated for me. Is it possible to get this result using a single SQL statement?

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  • why doesn't perl sort the hash key in numeric order ?

    - by Haiyuan Zhang
    #!/usr/bin/perl use strict; use warnings; my %hash; foreach ( 1 .. 10 ) { $hash{$_} = $_; } foreach ( sort(keys %hash) ) { print $_ . ": " . "$hash{$_}" . "\n" ; } execute the above code, the result is as below : 1: 1 10: 10 2: 2 3: 3 4: 4 5: 5 6: 6 7: 7 8: 8 9: 9 Yes, I expect "10: 10" to be the last one taht is printed . So I just need someone to explain why perl give me surprise in this case.

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  • how can I display controller's variable (which is on a loop) on .html.erb page? ruby on rails

    - by rrz
    I have the following code listed below in my controller: struc = {'en' => 'english', 'es' => 'espaniol', 'de' => 'germany', 'fr' => 'french', 'it' => 'italy'} struc.each_pair do |key, value| @key=key @value=value end on my application.html.erb I have the following <select name="Language" onchange="location=this.options[this.selectedIndex].value;"> <option value="/<% @key %>/<%= @rem %>"><%= @value %></option> </select> Now how can i make the value of '@key' and '@value' appear recursively display on (application.html.erb)? Thanks in advance

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  • PHP: Doctrine: order joined records

    - by Sebastian Bechtel
    Hi, I'm new to doctrine: I have a problem with the sorting of joined records. A sample. I've got an Article model which is associated with a Source model in 1 <- n. The source model has a property called 'position' with an integer value. Now I want to fetch an article with it's sources orderes by the position. My DQL looks like this: $q = Doctrine_Query::create() ->select('a.title, s.content') ->from('Article a') ->leftJoin('a.Source s') ->where('a.id = ?') ->orderBy('s.position'); The result doesn't change if I edit the position. Best regards, Sebastian

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  • Why this code does not do what I mean?

    - by Mike
    $w = 'self-powering'; %h = (self => 'self', power => 'pau?', ); if ($w =~ /(\w+)-(\w+)ing$/ && $1~~%h && $2~~%h && $h{$2}=~/?$/) { $p = $h{$1}.$h{$2}.'ri?'; print "$w:"," [","$p","] "; } I expect the output to be self-powering: selfpau?ri? But what I get is: self-powering: [ri?] My guess is something's wrong with the code $h{$2}=~/?$/ It seems that when I use $h{$2}!~/?$/ Perl will do what I mean but why I can't get "self-powering: selfpau?ri?"? What am I doing wrong? Any ideas? Thanks as always for any comments/suggestions/pointers :)

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  • c# How to find if two objects are equal

    - by Simon G
    Hi, I'm needing to know the best way to compare two objects and to find out if there equal. I'm overriding both GethashCode and Equals. So a basic class looks like: public class Test { public int Value { get; set; } public string String1 { get; set; } public string String2 { get; set; } public override int GetHashCode() { return Value ^ String1.GetHashCode() ^ String2.GetHashCode(); } public override bool Equals( object obj ) { return GetHashCode() == obj.GetHashCode(); } } So for testing purposes I created two objects: Test t = new Test() { Value = 1, String1 ="One", String2 = "One" }; Test t2 = new Test() { Value = 1, String1 = "Two", String2 = "Two" }; bool areEqual = t.Equals( t2 ); In testing this areEqual returns true event though both objects are different. I realise this is because String1 and String2 are the same value in each object and thus cancels each other out when hashing. Is there a better way off hashing object that the method I have that will resolve my issue?

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  • How to get multiple counts with one SQL query?

    - by Crobzilla
    I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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  • Best way to do one-to-many "JOIN" in CouchDB

    - by mit
    There are CouchDB documents that are list elements: { "type" : "el", "id" : "1", "content" : "first" } { "type" : "el", "id" : "2", "content" : "second" } { "type" : "el", "id" : "3", "content" : "third" } There is one document that defines the list: { "type" : "list", "elements" : ["2","1"] , "id" : "abc123" } As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order. The result could be: { "content" : ["second", "first"] } In this case the order of the elements is already as it should be. Another possible result: { "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] } I started writing the map function: map = function (doc) { if (doc.type === 'el') { emit(doc.id, {"content" : doc.content}); //emit the id and the content exit; } if (doc.type === 'list') { for ( var i=0, l=doc.elements.length; i<l; ++i ){ emit(doc.elements[i], { "order" : i }); //emit the id and the order } } } This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result. Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.

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  • Marking up table joins in the Microstrategy project metadata with the architect tool?

    - by ConcernedOfTunbridgeWells
    Hi, I am evaluating Microstrategy 9.0.1 and attempting to build a prototype metadata layer using its Architect tool. The tool doesn't seem to have any specific means to mark up joins in the way that the editing tools for SSRS data source views or Business Objects universes do. How does this work in Microstrategy - I have never used this before and may be making invalid assumptions based on other systems I have seen. If one does do this with MicroStrategy, how is it done?

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  • Trying to create fields based on a case statement

    - by dido
    I'm having some trouble with the query below. I am trying to determine if the "category" field is A, B or C and then creating a field based on the category. That field would sum up payments field. But I'm running into error saying "incorrect syntax near keyword As". I am creating this in a SQL View. Using SQL Server 2008 SELECT r.id, r.category CASE WHEN r.category = 'A' then SUM(r.payment) As A_payments WHEN r.category = 'B' then SUM(r.payment) As B_payments WHEN r.category = 'C' then SUM(r.payment) As C_payments END FROM r_invoiceTable As r GROUP BY r.id, r.category I have data where all of the above cases should be executed because the data that I have has A,B and C Sample Data- r_invoiceTable Id --- Category ---- Payment 222 A ---- 50 444 A ---- 30 111 B ---- 90 777 C ---- 20 555 C ---- 40 Desired Output A_payments = 80, B_payments = 90, C_payments = 60

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  • Many to many self join through junction table

    - by Peter
    I have an EF model that can self-reference through an intermediary class to define a parent/child relationship. I know how to do a pure many-to-many relationship using the Map command, but for some reason going through this intermediary class is causing problems with my mappings. The intermediary class provides additional properties for the relationship. See the classes, modelBinder logic and error below: public class Equipment { [Key] public int EquipmentId { get; set; } public virtual List<ChildRecord> Parents { get; set; } public virtual List<ChildRecord> Children { get; set; } } public class ChildRecord { [Key] public int ChildId { get; set; } [Required] public int Quantity { get; set; } [Required] public Equipment Parent { get; set; } [Required] public Equipment Child { get; set; } } I've tried building the mappings in both directions, though I only keep one set in at a time: modelBuilder.Entity<ChildRecord>() .HasRequired(x => x.Parent) .WithMany(x => x.Children ) .WillCascadeOnDelete(false); modelBuilder.Entity<ChildRecord>() .HasRequired(x => x.Child) .WithMany(x => x.Parents) .WillCascadeOnDelete(false); OR modelBuilder.Entity<Equipment>() .HasMany(x => x.Parents) .WithRequired(x => x.Child) .WillCascadeOnDelete(false); modelBuilder.Entity<Equipment>() .HasMany(x => x.Children) .WithRequired(x => x.Parent) .WillCascadeOnDelete(false); Regardless of which set I use, I get the error: The foreign key component 'Child' is not a declared property on type 'ChildRecord'. Verify that it has not been explicitly excluded from the model and that it is a valid primitive property. when I try do deploy my ef model to the database. If I build it without the modelBinder logic in place then I get two ID columns for Child and two ID columns for Parent in my ChildRecord table. This makes sense since it tries to auto create the navigation properties from Equipment and doesn't know that there are already properties in ChildRecord to fulfill this need. I tried using Data Annotations on the class, and no modelBuilder code, this failed with the same error as above: [Required] [ForeignKey("EquipmentId")] public Equipment Parent { get; set; } [Required] [ForeignKey("EquipmentId")] public Equipment Child { get; set; } AND [InverseProperty("Child")] public virtual List<ChildRecord> Parents { get; set; } [InverseProperty("Parent")] public virtual List<ChildRecord> Children { get; set; } I've looked at various other answers around the internet/SO, and the common difference seems to be that I am self joining where as all the answers I can find are for two different types. Entity Framework Code First Many to Many Setup For Existing Tables Many to many relationship with junction table in Entity Framework? Creating many to many junction table in Entity Framework

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