Search Results

Search found 8547 results on 342 pages for 'hash join'.

Page 65/342 | < Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >

  • How to decrypt a password from SQL server?

    - by sef
    I have this query in sql server 2000: select pwdencrypt('AAAA') which outputs an encrypted string of 'AAAA': 0x0100CF465B7B12625EF019E157120D58DD46569AC7BF4118455D12625EF019E157120D58DD46569AC7BF4118455D How can I convert (decrypt) the output from its origin (which is 'AAAA')?

    Read the article

  • Inner join 2 tables one to many 2 where clauses

    - by user2892350
    I'm a relative rookie at this,so please bear with me... I have 2 tables: OrderDetail and OrderMaster...both have a column named SalesOrder. OrderDetail table has multiple rows per unique SalesOrder. OrderMaster table has one row per unique SalesOrder. OrderDetail has a column named LineType. OrderMaster has a column named OrderStatus. I want to select all records from OrderDetail that have a LineType of "1" AND whose matching SalesOrder line in the OrderMaster table has a OrderStatus column value of "4". In plain English, orders with a Status 4 are open and ready to ship, LineType value of 1 means the Detail Line is a product code. How should this query be structured? It's going into VS 2008 (VB). Many thanks in advance!!! Mike

    Read the article

  • Merging two arrays in PHP

    - by Industrial
    Hi everyone, I am trying to create a new array from two current arrays. Tried array_merge, but it will not give me what I want. $array1 is a list of keys that I pass to a function. $array2 holds the results from that function, but doesn't contain any non-available resuls for keys. So, I want to make sure that all requested keys comes out with 'null':ed values, as according to the shown $result array. It goes a little something like this: $array1 = array('item1', 'item2', 'item3', 'item4'); $array2 = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3' ); Here's the result I want: $result = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3', 'item4' => '' ); It can be done this way, but I don't think that it's a good solution - I really don't like to take the easy way out and suppress PHP errors by adding @:s in the code. This sample would obviously throw errors since 'item4' is not in $array2, based on the example. foreach ($keys as $k => $v){ @$array[$v] = $items[$v]; } So, what's the fastest (performance-wise) way to accomplish the same result?

    Read the article

  • initializing hashes

    - by Paul
    Seems like I am frequently writing something like this... a_hash['x'] ? a_hash['x'] += ' some more text' : a_hash['x'] = 'first text' seems like there ought to be a better way, but I can't find it.

    Read the article

  • select row from table and substitute a field with one from another column if it exists

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). My attempts: SELECT A.name, case when exists(select title from B where table_A_id = 5 and langcode= 'nl') then B.title else A.name END FROM A, B WHERE A.id = 5 and B.table_A_id = 5 and B.langcode = 'nl' -- second try: SELECT COALESCE(B.title, A.name) as name from A, B where A.id = 5 and B.table_A_id = 5 and exists(select title from B where table_A_id = 5 and langcode= 'nl') I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

    Read the article

  • Oracle join issue

    - by acadia
    Hello, I have 3 tables and I am joining these 2 tables as follows: SELECT EMP.FNAME,EMP.LNAME,EMP.AGE,EMPD.TQ,EMPD.TA,CTY.CITY_NAME FROM EMPLOYEE EMP,EMPLOYEE_DETAIL EMPD, CITY CTY WHERE EMP.EMP_ID=EMPD.EMP_ID AND EMPD_CITY_ID=CTY.CITY_ID I want to display records even if City record is not in CITY table. For eg. if City_ID record for say 10 is not in City table but there is an employee detail record with City_id 10 it should display City_name as null instead of not displaying the record at all. Appreciate your help

    Read the article

  • select row from table and substitute a field with one from another column if not null

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

    Read the article

  • How to coerce type of ActiveRecord attribute returned by :select phrase on joined table?

    - by tribalvibes
    Having trouble with AR 2.3.5, e.g.: users = User.all( :select => "u.id, c.user_id", :from => "users u, connections c", :conditions => ... ) Returns, e.g.: => [#<User id: 1000>] >> users.first.attributes => {"id"=>1000, "user_id"=>"1000"} Note that AR returns the id of the model searched as numeric but the selected user_id of the joined model as a String, although both are int(11) in the database schema. How could I better form this type of query to select columns of tables backing multiple models and retrieving their natural type rather than String ? Seems like AR is punting on this somewhere. How could I coerce the returned types at AR load time and not have to tack .to_i (etc.) onto every post-hoc access?

    Read the article

  • CakePHP 3-level-deep model associatons

    - by user357452
    Hi, I am relatively new to CakePHP, I am doing fine with the documentation, but I've been trying to find a way out to this problem for weeks and I don't seem to find the solution, I am sure it is easy and maybe even automagicaly doable, but I just don't know how to find it (maybe I don't know the jargon for these kind of things) My model structure is like this: <?php class Trip extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Start' => array( 'className' => 'Place', 'foreignKey' => 'start_id' ), 'End' => array( 'className' => 'Place', 'foreignKey' => 'end_id' ), 'Transport' => array( 'className' => 'Transport', 'foreignKey' => 'transport_id' ) ); } ?> <?php class Place extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id' ), 'State' => array( 'className' => 'State', 'foreignKey' => 'state_id' ), 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id' ) ); var $hasMany = array( 'PlaceStart' => array( 'className' => 'trip', 'foreignKey' => 'start_id', 'dependent' => false ), 'PlaceEnd' => array( 'className' => 'trip', 'foreignKey' => 'end_id', 'dependent' => false ) ); } ?> <?php class State extends AppModel { var $belongsTo = array( 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id', 'conditions' => '', 'fields' => '', 'order' => '' ) ); var $hasMany = array( 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id', 'dependent' => false ) ); } ?> ... and so forth with User, City, Country, and Transport Models. What I am trying to achieve is to get all the information of the whole tree when I search for a Trip. <?php class TripController extends AppController { function index() { debug($this->Trip->find('first')); } } Outputs Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [user_id] => 4 [start_id] => 2 [end_id] => 1 [title] => My trip [transport_id] => 1 ) [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 1 [direccion] => Lincoln Street ) [End] => Array ( [id] => 1 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 4 [address] => Fifth Avenue ) [Transport] => Array ( [id] => 1 [name] => car ) ) Here is the question: How do I get in one query all the information down the tree? I would like to have something like Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [Country] => Array ( [id] => 1 [name] = Spain ) [State] => Array ( [id] => 1 [name] = Barcelona ) [City] => Array ( [id] => 1 [name] = La Floresta ) [address] => Lincoln Street ) [End] => (same as Start) [title] => My trip [Transport] => Array ( [id] => 1 [name] => car ) ) ) Can CakePHP create this kind of data? Not only for $this->Model->find() but also for $this->paginate() as for example: // filter by start if(isset($this->passedArgs['start'])) { //debug('isset '.$this->passedArgs['start']); $start = $this->passedArgs['start']; $this->paginate['conditions'][] = array( 'OR' => array( 'Start.address LIKE' => "%$start%", 'Start.State.name LIKE' => "%$start%", 'Start.City.name LIKE' => "%$start%", 'Start.Country.name LIKE' => "%$start%" ) ); $this->data['Search']['start'] = $start; } It seems like a rough question but I am sure this is extensively done and documented, I'd really appreciate any help. Thanks Cheers Naoise

    Read the article

  • SQL OUTER JOIN with NEWID to generate random data for each row

    - by CL4NCY
    Hi, I want to generate some test data so for each row in a table I want to insert 10 random rows in another, see below: INSERT INTO CarFeatures (carID, featureID) SELECT C.ID, F.ID FROM dbo.Cars AS C OUTER APPLY ( SELECT TOP 10 ID FROM dbo.Features ORDER BY NEWID() ) AS F Only trouble is this returns the same values for each row. How do I order them randomly?

    Read the article

  • Grails many to many using a third 'join' class

    - by andy mccullough
    I read that a m:m relationship often means there is a third class that isn't yet required. So I have m:m on User and Project, and I created a third domain class, ProjectMembership The three domains are as follows (minimized for illustration purposes): User class User { String name static hasMany = [projectMemberships : ProjectMembership] } Project Membership class ProjectMembership { static constraints = { } static belongsTo = [user:User, project:Project] } Project: class Project { String name static hasMany = [projectMemberships : ProjectMembership] static constraints = { } } If I have the ID of the user, how can I get a list of Project objects that they are assigned to?

    Read the article

  • Python - Why ever use SHA1 when SHA512 is more secure?

    - by orokusaki
    I don't mean for this to be a debate, but I'm trying to understand the technical rationale behind why so many apps use SHA1, when SHA512 is more secure. Perhaps it's simply for backwards compatibility. Besides the obvious larger size (128 chars vs 40), or slight speed differences, is there any other reason why folks use the former? Also, SHA-1 I believe was first cracked by a VCR's processor years ago. Has anyone cracked 512 yet (perhaps with a leaf blower), or is it still safe to use without salting?

    Read the article

  • SQL: joining multiples tables into one.

    - by Graveen
    I have 4 tables. r1, r2, r3 and r4. The table columns are the following: rId | rName I want to have, in fine, an unique table - let's call it R. Obviously, R will have the following structure: rTableName | rId | rName I'm looking for a solution, and the more natural for me is to: add a single column to all rX insert this column the table name i'm processing generate SQLs and concatenate them all Although I see exactly how to perform 1 and 3 with batching, editing, etc... (I have only to perform it once and for all), I don't see how to do the point 2: self-getting the tablename to insert into SQL. Have you an idea / or a different way to do that could solve my problem? Note: In fact, there are 250+ rX tables. That's why i can't do this manually. Note2: Precisely, this is with MySQL.

    Read the article

  • Looking for an array (vs linked list) hashtable implementation in C

    - by kingusiu
    hi, I'm looking for a hashtable implementation in C that stores its objects in (twodimensional) arrays rather than linked lists. i.e. if a collision happens, the object that is causing the collision will be stored in the next free row index rather than pushed to the head and first element of a linked list. plus, the objects themselves must be copied to the hashtable, rather than referenced by pointers. (the objects do not live for the whole lifetime of the program but the table does). I know that such an implementation might have serious efficiency drawbacks and is not the "standard way of hashing" but as I work on a very special system-architecture i need those characteristics. thanks

    Read the article

  • T-SQL Self Join in combination with aggregate function

    - by Nick
    Hi, i have the following table. CREATE TABLE [dbo].[Tree]( [AutoID] [int] IDENTITY(1,1) NOT NULL, [Category] [varchar](10) NULL, [Condition] [varchar](10) NULL, [Description] [varchar](50) NULL, CONSTRAINT [PK_Tree] PRIMARY KEY CLUSTERED ( [AutoID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO the data looks like this: INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') go I try now to do the following: SELECT Category,COUNT(*) as CategoryCount FROM Tree where Condition = 'Alpha' group by Category but i wish also to get the Description for each Element. I tried several subqueries, self joins etc. i always come to the problem that the subquery cannot return more than one record. The problem is caused by a poor database design which i cannot change and i run out of ideas to get this done in a single query ;-(

    Read the article

  • MySQL Rating system (calculating average from two tables).

    - by MussuR
    I have two tables, videos and videos_ratings. The videos table has an int videoid field (and many others but those fields are not important I think) and many records. The videos_ratings table has 3 int fields: videoid, rating, rated_by which has many records (multiple records for each fields from the videos table) but not for all records from the videos table. Currently I have the following mysql query: SELECT `videos`.*, avg(`videos_ratings`.`vote`) FROM `videos`, `videos_ratings` WHERE `videos_ratings`.`videoid` = `videos`.`videoid` GROUP BY `videos_ratings`.`videoid` ORDER BY RAND() LIMIT 0, 12 It selects all the records from table videos that have a rating in table video_ratings and calculates the average correctly. But what I need is to select all records from the videos table, no matter if there is a rating for that record or not. And if there aren't any records in the videos_ratings table for that particular videos record, the average function should show 0. Hope someone could understand what I want... :) Thanks!

    Read the article

  • Filtering with joined tables

    - by viraptor
    I'm trying to get some query performance improved, but the generated query does not look the way I expect it to. The results are retrieved using: query = session.query(SomeModel). options(joinedload_all('foo.bar')). options(joinedload_all('foo.baz')). options(joinedload('quux.other')) What I want to do is filter on the table joined via 'first', but this way doesn't work: query = query.filter(FooModel.address == '1.2.3.4') It results in a clause like this attached to the query: WHERE foos.address = '1.2.3.4' Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to: WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4' It works fine. The question is of course - how can I achieve this with sqlalchemy itself?

    Read the article

  • Using intermediate array for hashCode and equals

    - by Basilevs
    As its a pain to handle structural changes of the class in two places I often do: class A { private B bChild; private C cChild; private Object[] structure() { return new Object[]{bChild, cChild}; } int hashCode() { Arrays.hashCode(structure); } boolean equals(Object that) { return Arrays.equals(this.structure(), ((A)that).structure()); } } What's bad about this approach besides boxing of primitives? Can it be improved?

    Read the article

  • How to map string keys to unique integer IDs?

    - by Marek
    I have some data that comes regularily as a dump from a data souce with a string natural key that is long (up to 60 characters) and not relevant to the end user. I am using this key in a url. This makes urls too long and user unfriendly. I would like to transform the string keys into integers with the following requirements: The source dataset will change over time. The ID should be: non negative integer unique and constant even if the set of input keys changes preferrably reversible back to key (not a strong requirement) The database is rebuilt from scratch every time so I can not remember the already assigned IDs and match the new data set to existing IDs and generate sequential IDs for the added keys. There are currently around 30000 distinct keys and the set is constantly growing. How to implement a function that will map string keys to integer IDs? What I have thought about: 1. Built-in string.GetHashCode: ID(key) = Math.Abs(key.GetHashCode()) is not guaranteed to be unique (not reversible) 1.1 "Re-hashing" the built-in GetHashCode until a unique ID is generated to prevent collisions. existing IDs may change if something colliding is added to the beginning of the input data set 2. a perfect hashing function I am not sure if this can generate constant IDs if the set of inputs changes (not reversible) 3. translate to base 36/64/?? does not shorten the long keys enough What are the other options?

    Read the article

  • When to use CTEs to encapsulate sub-results, and when to let the RDBMS worry about massive joins.

    - by IanC
    This is a SQL theory question. I can provide an example, but I don't think it's needed to make my point. Anyone experienced with SQL will immediately know what I'm talking about. Usually we use joins to minimize the number of records due to matching the left and right rows. However, under certain conditions, joining tables cause a multiplication of results where the result is all permutations of the left and right records. I have a database which has 3 or 4 such joins. This turns what would be a few records into a multitude. My concern is that the tables will be large in production, so the number of these joined rows will be immense. Further, heavy math is performed on each row, and the idea of performing math on duplicate rows is enough to make anyone shudder. I have two questions. The first is, is this something I should care about, or will SQL Server intelligently realize these rows are all duplicates and optimize all processing accordingly? The second is, is there any advantage to grouping each part of the query so as to get only the distinct values going into the next part of the query, using something like: WITH t1 AS ( SELECT DISTINCT... [or GROUP BY] ), t2 AS ( SELECT DISTINCT... ), t3 AS ( SELECT DISTINCT... ) SELECT... I have often seen the use of DISTINCT applied to subqueries. There is obviously a reason for doing this. However, I'm talking about something a little different and perhaps more subtle and tricky.

    Read the article

  • Ruby On Rails: Ask for Confirmation When Table Entry Associated With Another Is Destroyed

    - by Train Main
    Hi all, I would like some assistance with the following problem: I have a table of groups that is self-associated with itself, so each group is (optionally) linked to another in a hierarchical fashion. I want to write some code that will somehow check before the destruction of a group entry, if it has any children, and ask the user for confirmation, or whether they wish to delete the child groups as well. I've looked at callbacks, but I don't know how to get the confirmation request to the end user in the view, and then get the response back to the model's callback. Thanks

    Read the article

  • (PHP) 1)How to genrate Secreate key on User & Client Side ? 3) How to Compare Server side MD5 and Client side Md5 ?

    - by user557994
    /* In Below Code .. My problem is that 1) How to genrate Secreate key on User Side ? 2) How to genrate Secreate key on Client Side ? 3) How to Compare Server side MD5 and Client side Md5 ? Can you solve my problem ? */ $gid = $_GET['id']; if($gid=="") { $filename = "counter.txt"; $fp = fopen( $filename, "r" ) or die("Couldn't Generate Whiteboard"); while ( ! feof( $fp ) ) { $countfile = fgets( $fp); $countfile++; } fclose( $fp ); $fp = fopen( $filename, "w" ) or die("Couldn't generate whiteboard"); fwrite( $fp, $countfile ); fclose( $fp ); $doc = new DOMDocument('1.0', 'UTF-8'); $ele = $doc-createElement( 'root' ); $ele-nodeValue = $uvar; $doc-appendChild( $ele ); $test = $doc-save("$countfile.xml"); genkey($id); echo ""; $uvar=$_POST['msgval']; exit; } else { if($uvar == "") { $xdoc = new DOMDocument( '1.0', 'UTF-8' ); $xdoc-Load("$gid.xml"); $candidate = $xdoc-getElementsByTagName('root')-item(0); $newElement = $xdoc -createElement('root'); $txtNode = $xdoc -createTextNode ($root); $newElement - appendChild($txtNode); $candidate - appendChild($newElement); $msg = $candidate-nodeValue; } } function genkey($id) { $encrypt_key = "GJHsahakst1468464a"; $key = MD5("$id","$$encrypt_key"); return $key; } ? function sendRequest() { var uvar = document.getElementById('txtHint').value; var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if(xmlhttp.readyState == 4 && xmlhttp.status==200) { document.getElementById('txtHint').value = ""; } } xmlhttp.open("POST","post.php?id=",true); xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xmlhttp.send("umsg="+uvar); return; } Msg " /

    Read the article

< Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >