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  • jQuery find file extension (from string)

    - by SoulieBaby
    Hi all, I was wondering if it was possible for jQuery to find a file extension based on a returned string? A filename (string) will be passed to a function (openFile) and I wanted that function to do different things based on what file has been passed through, it could be image files or pdf files. function openFile(file) { //if .jpg/.gif/.png do something //if .zip/.rar do something else //if .pdf do something else }; I've been looking for something that will find the file's extension but I can't seem to find anything.

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  • Windows 2008 R2 File Sharing - 'Access denied' if groups are specified in ACL

    - by John Smith
    I am trying to move our old Windows 2003 File Server to Windows 2008 R2. What I have noticed, however, is that the entries for groups in the ACL are being ignored. For example, a user is part of a group in active directory. If I create a folder and enable full access for this group, then share this folder (and define sharing permissions for this group), users in that group do not get access to that folder. If I make an entry in the ACL for the user itself, it works perfectly. These even applies to my domain administrator account - If I create a folder and give full control to the local administrators group / domain administrators group, and I physically log on to the server, I still do not get access - I need to explicitly define my name to proceed. I am not sure what the problem is, tried looking it up in Google to no avail Any assistance will be greatly appreciated

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  • Creating a .bat file to execute mysql and other commands

    - by BCIT - JD
    I'm looking for a way to reduce the amount of typing I do to check mysql entries and other things. For example, I wanted to create a .bat file that will execute the following commands. mysql -u user -p *enter in the password* USE databasename SELCT * FROM table; The problem is after the initial mysql -u user -p the rest of the commands written down do not get executed. Is it possible to continue running commands after calling something like mysql or other programs, that seem to add its prefix(?) to the beginning of commands (mysql). I'm not very familiar with the terminology so forgive me if it sounds confusing. I'd like to use the same kind of concept for other things as well. Help is much appreciated, Thanks.

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  • Biztalk Flat File Schema - how to accept a LF or CRLF as the line delimiter

    - by FullOfQuestions
    Hi, Our client sends us a flat file as input, which we then take and convert to an XML file before sending to the destination system. The flat file consists of multiple lines, each line is delimited by LF or CRLF. How do I create a Flat File Schema so that Biztalk can interpret each line of data regardless of whether the line was delimited by LF (0x0A) or CRLF (0x0D 0x0A)? Thank you in advance, M

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  • Windows server 2008 R2 IIS7 file permissions

    - by StealthRT
    Hey all i am trying to figure out why i can not access a index.php file from within the wwwroot/mollify/backend directory. It keeps coming up with this: Server Error 403 - Forbidden: Access is denied. You do not have permission to view this directory or page using the credentials that you supplied. I've given all the permissions (Full control) to the wwwroot directory i could think of (IUSR, Guest, GUESTS, IIS_IUSRS, Users, Administrators, NETWORK, NETWORK SERVICE, SYSTEM, CREATOR OWNER & Everyone). I also added index.php to the "Default Document" under my website settings in IIS 7 manager. What else am i missing? Thanks! David

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  • PHP REGEX - text to array by preg_split at line break

    - by aSeptik
    Hi All! EDITED: need help on split Array array example: $text = array ( [0] => TEXT1:some normal text TEXT2:some long text here, and so on... sometimes i'm breaking down and... TEXT3:some normal text TEXT4:some normal text [1] => TEXT1:some normal text TEXT2:some long text here, and so on... sometimes i'm breaking down and... TEXT3:some normal text TEXT4:some normal text ) ok, now by using preg_split( '#\n(?!s)#' , $text ); i get [0] => Array ( [0] => some normal text [1] => some long text here, and so on... sometimes [2] => some normal text [3] => some normal text ) As you can see the [1] Element of the Array is cutted off! i want keep this line entirely: some long text here, and so on... sometimes i'm breaking down and... what Regex can get the entire line and also split at line break!?

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  • Windows 7 File Associations .mov

    - by Paul Mung
    I created a new windows 7 SP1 base image. Everything is all fine and dandy with that. So i am now installing standard applications I would like Quicktime to manage .mov files. The only problem is WMP (Windows Media Player) won't give up the association to .mov files. It's driving me crazy... i've been reading threads on how to fix file associations. I would like to do it via registry, powershell or cmdline. I cannot use GPO I've tried the following: assoc .mov=QuickTime.mov ftype QuickTime.mov="%ProgramFiles(x86)\QuickTime\QuickTimePlayer.exe" Reg add HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\UserChoice" /v Progid /d QuickTime.mov /f Reg add HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\OpenWithList" /v a /d QuickTimePlayer.exe /f Reg add "HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\OpenWithList" /v b /d wmplayer.exe /f Reg add HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\OpenWithList" /v MRUList /d ab /f Reg add HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\OpenWithProgids" /v Quicktime.mov /t REG_NONE /d 0000 /f Reg add HKCU\Software\Microsoft\windows\CurrentVersion\Explorere\FileExts\.mov\OpenWithProgids" /v WMP11.AssocFile.MOV /t REG_NONE /d 0000 /f

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  • What to use as a file server with a web interface and user management on MAMP

    - by Timo
    I want to set up file/photo sharing for a largish group of friends and family. Flickr, Picasa etc. are not optimal solutions because setting up accounts, sharing albums and navigating privacy settings is going to be overwhelming for some of the people. I just want to be able to give people a URL, a username, and password and have it be easy peasy. I want something very simple and easy to use (for the user) like MyTunesRSS. I've looked at a complete "social" solution like Elgg but that feels like using a cadillac to kill a fly. I only need: User management Simple upload / download of files Plug-into-MAMP ease of setup is a bonus Search / metadata / tags / commenting not necessary but also earns bonus points Free / cheap licence What would you recommend?

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  • synchronizing XML nodes between class and file using C#

    - by Sarah Vessels
    I'm trying to write an IXmlSerializable class that stays synced with an XML file. The XML file has the following format: <?xml version="1.0" encoding="utf-8" ?> <configuration> <logging> <logLevel>Error</logLevel> </logging> ...potentially other sections... </configuration> I have a DllConfig class for the whole XML file and a LoggingSection class for representing <logging> and its contents, i.e., <logLevel>. DllConfig has this property: [XmlElement(ElementName = LOGGING_TAG_NAME, DataType = "LoggingSection")] public LoggingSection Logging { get; protected set; } What I want is for the backing XML file to be updated (i.e., rewritten) when a property is set. I already have DllConfig do this when Logging is set. However, how should I go about doing this when Logging.LogLevel is set? Here's an example of what I mean: var config = new DllConfig("path_to_backing_file.xml"); config.Logging.LogLevel = LogLevel.Information; // not using Logging setter, but a // setter on LoggingSection, so how // does path_to_backing_file.xml // have its contents updated? My current solution is to have a SyncedLoggingSection class that inherits from LoggingSection and also takes a DllConfig instance in the constructor. It declares a new LogLevel that, when set, updates the LogLevel in the base class and also uses the given DllConfig to write the entire DllConfig out to the backing XML file. Is this a good technique? I don't think I can just serialize SyncedLoggingSection by itself to the backing XML file, because not all of the contents will be written, just the <logging> node. Then I'd end up with an XML file containing only the <logging> section with its updated <logLevel>, instead of the entire config file with <logLevel> updated. Hence, I need to pass an instance of DllConfig to SyncedLoggingSection. It seems almost like I want an event handler, one in DllConfig that would notice when particular properties (i.e., LogLevel) in its properties (i.e., Logging) were set. Is such a thing possible?

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  • .bat file overriding answer

    - by John Peters
    When I made this batch file, when typing y and n for the first time it works fine, but as soon as I choose n, every single time I try inputting something, it opens up the 7000 songs wpl list then closes it and replaces it with Rick Astley... HELP! @echo off :Ask echo Would you like to listen to the best songs out of the 7000 I have?(Y/N) set INPUT= set /P INPUT=Type input: %=% If /I "%INPUT%"=="y" goto yes If /I "%INPUT%"=="n" goto lolno echo Incorrect input & goto Ask :yes start c:/Users/MyName/Music/Playlists/"The Best of the 7000 songs that I have.wpl" :lolno start c:/Users/MyName/Music/Downloads/Music/"Various Artists"/"The Number One 80's Album Disc 2"/"06 Never Gonna Give You Up.mp3"

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  • Download file popup in IE not working it works well in Fire Fox

    - by Yogesh
    Hi window.location.href, using hidden Iframe and setting its source dynamically, setting return false; for onclick Nothing is working for IE. Basically, my dwr response generates a log file (foo.log) @business layer and it sends file name as response to dwr rpc request. Now I know the file name and its location I just want to download that file.(It works in FF not in IE).

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  • how do I paste text to a line by line text filter like awk, without having stdin echo to the screen?

    - by Barton Chittenden
    I have a text in an email on a windows box that looks something like this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same I want to extract the numbers, i.e. the first word on each line. I've got a terminal running bash open on my Linux box... If these were in a text file, I would do this: awk '{print $1}' mytextfile.txt I would like to paste these in, and get my numbers out, without creating a temp file. my naive first attempt looked like this: $ awk '{print $1}' 100 some random text 100 101 some more random text 101 102 lots of random text, all different 103 lots of random text, all the same 102 103 The buffering of stdin and stdout make a hash of this. I wouldn't mind if stdin all printed first, followed by all of stdout; this is what would happen if I were to paste into 'sort' for example, but awk and sed are a different story. a little more thought gave me this: open two terminals. Create a fifo file. Read from the fifo on one terminal, write to it on another. This does in fact work, but I'm lazy. I don't want to open a second terminal. Is there a way in the shell that I can hide the text echoed to the screen when I'm passing it in to a pipe, so that I paste this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same but see this? $ awk '{print $1}' 100 101 102 103

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  • How to get the file name for <input type="file" in jsp

    - by deepthinker121
    I want to read the file path from html input type="file" (the entry selected in the file dialog by the user) <script> function OpenFileDialog(form) { var a = document.getElementById("inputfile").click(); SampleForm.filePath.value = //set the path here document.SampleForm.submit(); } </script> <form name="SampleForm" action="TestServlet" method="get"> <input type="file" style="display:none;" id="inputfile"/> <a href="javascript:OpenFileDialog(this.form);">Open here</a> <input type="hidden" name="filePath" value=""/> </form> I want the path of the selected file to be read in my Servlet class How do I get the file path? Can I read it from var a? Or is there any way to directly access the file path from the input type="file" from my servlet?

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  • Windows redirect traffic to different DNS name not fixed IP address (hosts file equivalent)

    - by Arik Raffael Funke
    Using the Windows hosts file, one can redirect traffic for a domain to a specific IP address, e.g. domainA.com -- 127.0.0.1 I am looking for a SIMPLE way to do the same, but for a target domain name not for a target IP address (as this is dynamic), I.e. domainA.com -- domainB.com Addition: After the getting some initial answers I think I need to concretise my question. Situation: I have an application which looks up the IP of the target domain via DNS and then connects via HTTP to the IP address. I do not have control over any proxy settings. Option 1 Basically I am looking for a way to: intercept DNS requests for a domainA.com launch a DNS request for a domainB.com serve the IP of domainB.com in response to the request for domainA.com Without running an entire DNS server. Option 2 If a DNS server is the only way, in the alternative I would also be happy with an solution to how to define a non-standard DNS-server for a single application. Any ideas for wrapper applications, etc?

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  • Replacing text inside textarea without focus

    - by asker
    I want to replace selected text(or insert new text after cursor position if nothing is selected). The new text is entered from another textbox. I want to be able to insert new text without clicking first (focusing) in the textarea. meaning: first select text to replace inside textarea, then enter new text into the textbox and click the button. <textarea id='text' cols="40" rows="20"> </textarea> <div id="opt"> <input id="input" type="text" size="35"> <input type="button" onclick='pasteIntoInput(document.getElementById("input").value)' value="button"/> </div> function pasteIntoInput(text) { el=document.getElementById("text"); el.focus(); if (typeof el.selectionStart == "number"&& typeof el.selectionEnd == "number") { var val = el.value; var selStart = el.selectionStart; el.value = val.slice(0, selStart) + text + val.slice(el.selectionEnd); el.selectionEnd = el.selectionStart = selStart + text.length; } else if (typeof document.selection != "undefined") { var textRange = document.selection.createRange(); textRange.text = text; textRange.collapse(false); textRange.select(); } } Online example: link text

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  • Who owns a php exec tar extracted file?

    - by Ken
    As far as file permissions are concerned, when you use a php script to unzip a tar file, who is the "owner" user of the files created? I'm wondering if its my ftp user because I uploaded the script file? Or does apache own the file? I know their are flags to be set to preserve the original permissions which I don't want (files where created and archived by someone else). I want my user to be the creater/owner of the files.

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  • File and Printer Sharing Port issue in Windows 7 64 bit

    - by Mohit
    So, This is totally weird and I could not find any way to fix it. In simple words after the diagnosis this what is happening. On a windows 7 64 bit box, Whenever I am trying to access a server using file share. It is trying to connect to port 80 http on the place of 445. I observed that using WireShark. Telnet to 445 works. Any clue how to fix this. Scanned the machine using Malware bytes, Symantec and MS live essentials . I dont want to recreate the whole machine again. Please help me here. Regards Mohit Thakral

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  • How to repair a broken .EXE file association

    - by Pointy
    After (hopefully) scrubbing viruses out of a Windows 7 installation (after deciding not to simply run over the laptop repeatedly with my car), I've got everything almost back to normal. The only lingering issue I have is that for my non-admin users, the ".exe" file extension doesn't work. That is, clicking on the various desktop application links results in a "How do you want to open this?" dialog. I've been through the alleged registry fixing from "winhelponline" and that had absolutely no effect. I've tried running "assoc" for the affected users, but it reports the .exe association to be "exefile" even though it persistently does not work. Right-clicking on a desktop icon and then choosing "start" does successfully open an application, but that's clearly a terrible situation. For my admin user, things seem to work fine. What do I need to do to get things working?

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  • How to display certain lines from a text file in Linux?

    - by Boaz
    Hi, I guess everyone knows the useful Linux cmd line utilities head and tail. Head allows you to print the first X lines of a file, tail does the same but prints the end of the file. What is a good command to print the middle of a file? something like middle --start 10000000 --count 20 (print the 10,000,000th till th 10,000,010th lines). I'm looking for something that will deal with large files efficiently. I tried tail -n 10000000 | head 10 and it's horrifically slow. Thanks, Boaz

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  • downloaded zip file returns zero has 0 bytes as size

    - by Yaw Reuben
    I have written a Java web application that allows a user to download files from a server. These files are quite large and so are zipped together before download. It works like this: 1. The user gets a list of files that match his/her criteria 2. If the user likes a file and wants to download he/she selects it by checking a checkbox 3. The user then clicks "download" 4. The files are then zipped and stored on a server 5. The user this then presented with a page which contains a link to the downloadable zip file 6. However on downloading the zip file the file that is downloaded is 0 bytes in size I have checked the remote server and the zip file is being created properly, all that is left is to serve the file the user somehow, can you see where I might be going wrong, or suggest a better way to serve the zip file. The code that creates the link is: <% String zipFileURL = (String) request.getAttribute("zipFileURL"); %> <p><a href="<% out.print(zipFileURL); %> ">Zip File Link</a></p> The code that creates the zipFileURL variable is: public static String zipFiles(ArrayList<String> fileList, String contextRootPath) { //time-stamping Date date = new Date(); Timestamp timeStamp = new Timestamp(date.getTime()); Iterator fileListIterator = fileList.iterator(); String zipFileURL = ""; try { String ZIP_LOC = contextRootPath + "WEB-INF" + SEP + "TempZipFiles" + SEP; BufferedInputStream origin = null; zipFileURL = ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"; FileOutputStream dest = new FileOutputStream(ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"); ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream( dest)); // out.setMethod(ZipOutputStream.DEFLATED); byte data[] = new byte[BUFFER]; while(fileListIterator.hasNext()) { String fileName = (String) fileListIterator.next(); System.out.println("Adding: " + fileName); FileInputStream fi = new FileInputStream(fileName); origin = new BufferedInputStream(fi, BUFFER); ZipEntry entry = new ZipEntry(fileName); out.putNextEntry(entry); int count; while ((count = origin.read(data, 0, BUFFER)) != -1) { out.write(data, 0, count); } origin.close(); } out.close(); } catch (Exception e) { e.printStackTrace(); } return zipFileURL; }

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  • linux/shell: change a file's modify timestamp relatively?

    - by index
    My Canon camera produces files like IMG_1234.JPG and MVI_1234.AVI. It also timestamps those files. Unfortunately during a trip to another timezone several cameras were used, one of which did not have the correct time zone set - meta data mess.. Now I would like to correct this. Proposed algorithm: 1 read file's modify date 2 add delta, i.e. hhmmss (preferred: change timezone) 3 write new timestamp Unless someone knows a tool or a combination of tools that do the trick directly, maybe one could simplify the calculation using epoch time (seconds since ..) and whip up a shell script. Any help appreciated!

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  • OS X Snow Leopard, change file permissions on copy

    - by Francesco K
    I work with OS X, Snow Leopard and need to allow users to make copies of files (templates) located in a read-only repository for subsequent editing. The repository is located on a separate physical drive mounted to the OS X boot volume. As this is a shared computer in a school environment, all users access the machine via a single login ("user_local"). Whether using POSIX permissions or ACLs, the use case requires the file permissions to change from "read" to "read write" as they get copied to the "user_local" home directory. Googling around has not yielded anything that would indicate that this is possible via the Snow Leopard permission system. Question 1: Is this in fact possible via the permission system? If so, how? Question 2: If not possible, how would one go about solving this problem? I imagine this to be a fairly common use case so there must be a workable solution for it out there. Thanks.

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  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

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  • Using Terminal Services 'query' in batch file

    - by dboarman-FissureStudios
    I have a batch file that checks several of our servers for a user. From the command: query user %userID% /server:ServerName I want to capture the output before it goes to the screen. Is there a way to redirect the output to a variable? The basic gist of what I want to accomplish is this - we iterate through our servers: query user %userID% /server:Server1 query user %userID% /server:Server2 query user %userID% /server:Server3 query user %userID% /server:Server4 Instead of outputting a message that the user could not be found on a specific server, I would like for it to only notify me if it finds the user on a server.

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  • VSFTPD uploaded file permissions

    - by Katafalkas
    Let me first say that there are loads of topics regarding this, and I am sure i have seen them all by now. Still non of the solutions seem to help. I installed vsftpd. created a user ftp-data. Now I need that files uploaded by user ftp-data would have 755 permissions. Solving this should be as easy as adding: local_umask=002 file_open_mode=0755 but that did not help, then I have tried a number of variations of this, still did not help. The I added: chmod_enable=YES still did not help. At the moment I think that I am missing something very simple and obvious, just cant find it. Maybe someone could help me to find what I am missing. This is my config file: anonymous_enable=NO local_enable=YES write_enable=YES local_umask=002 anon_upload_enable=NO anon_mkdir_write_enable=NO dirmessage_enable=NO xferlog_enable=YES connect_from_port_20=YES xferlog_file=/var/log/xferlog listen=YES local_root=/var/www/ftp-gallery pam_service_name=vsftpd userlist_enable=YES tcp_wrappers=YES

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