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  • Django sitemap intermittent www

    - by Jen Z
    The automatic sitemap for my Django site fluctuates between including the www on urls and leaving it out (I'm aiming to have it in all the time). This has ramifications in google not indexing my pages properly so I'm trying to narrow down what would be causing this issue. I have set PREPEND_WWW = True and my site record in the sites framework is set to include the www e.g. it's set to www.example.com as opposed to example.com. I'm using memcached but pages should expire from the cache after 48 hours so I wouldn't have thought that would be causing the issue? You can see the problem in effect at http://www.livingspaceltd.co.uk/sitemap.xml (refresh the page a few times). My sitemaps setup is fairly prosaic so I'm doubtful that that is the issue, but in case it's something obvious I'm missing here's the code: ***urls.py*** sitemaps = { 'subpages': Subpages_Sitemap, 'standalone_pages': Standalone_Sitemap, 'categories': Categories_Sitemap, } urlpatterns = patterns('', (r'^sitemap\.xml$', 'django.contrib.sitemaps.views.sitemap', {'sitemaps': sitemaps}), ... ***sitemaps.py*** # -*- coding: utf-8 -*- from django_ls.livingspace.models import Page, Category, Standalone_Page, Subpage from django.contrib.sitemaps import Sitemap class Subpages_Sitemap(Sitemap): changefreq = "monthly" priority = 0.4 def items(self): return Subpage.objects.filter(restricted_to__isnull=True) class Standalone_Sitemap(Sitemap): changefreq = "weekly" priority = 1 def items(self): return Standalone_Page.objects.all() class Categories_Sitemap(Sitemap): changefreq = "weekly" priority = 0.7 def items(self): return Category.objects.all()

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  • Django does not load internal .css files

    - by Rubén Jiménez
    I have created a Django project in local which runs without any kind of problem. But, after an annoying and difficult Cherokee + uWSGI installation on Amazon AWS, my project does not show Django .css internal files. http://f.cl.ly/items/2Q2W3I3R0X1n2X3v0q2P/django_error.jpg <-- /Admin/ looks like The image is a screen of my /admin/, which should have a different style, but .css files are not loaded. [pid: 23206|app: 0|req: 19/19] 83.49.10.217 () {56 vars in 1121 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/base.css = generated 2896 bytes in 6 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) [pid: 23206|app: 0|req: 20/20] 83.49.10.217 () {56 vars in 1125 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/login.css = generated 2899 bytes in 5 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) This is a log from Cherokee. I don't understand why it is looking for the .css files in that path. Cherokee should be searching the files in Django original directory so i didn't change .css files in my project. Any advice? Thanks a lot.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • How to create instances of related models in Django

    - by sevennineteen
    I'm working on a CMSy app for which I've implemented a set of models which allow for creation of custom Template instances, made up of a number of Fields and tied to a specific Customer. The end-goal is that one or more templates with a set of custom fields can be defined through the Admin interface and associated to a customer, so that customer can then create content objects in the format prescribed by the template. I seem to have gotten this hooked up such that I can create any number of Template objects, but I'm struggling with how to create instances - actual content objects - in those templates. For example, I can define a template "Basic Page" for customer "Acme" which has the fields "Title" and "Body", but I haven't figured out how to create Basic Page instances where these fields can be filled in. Here are my (somewhat elided) models... class Customer(models.Model): ... class Field(models.Model): ... class Template(models.Model): label = models.CharField(max_length=255) clients = models.ManyToManyField(Customer, blank=True) fields = models.ManyToManyField(Field, blank=True) class ContentObject(models.Model): label = models.CharField(max_length=255) template = models.ForeignKey(Template) author = models.ForeignKey(User) customer = models.ForeignKey(Customer) mod_date = models.DateTimeField('Modified Date', editable=False) def __unicode__(self): return '%s (%s)' % (self.label, self.template) def save(self): self.mod_date = datetime.datetime.now() super(ContentObject, self).save() Thanks in advance for any advice!

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  • Django website on Apache with wsgi failing

    - by notagain
    I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

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  • Django Development Environment Setup Questions

    - by Ross Peoples
    Hello, I'm trying to set up a good development environment for a Django project that I will be working on from two different physical locations. I have two Mac machines, one at home and one at work that I do most of my development on. I currently host a Ubuntu virtual machine on one of the machines to host the Django environemnt, install DropBox on it, and edit source code from my Mac. When I save the code file, the changes get synced over DropBox to the Ubuntu VM and the Django development server automatically restarts because of the change. This method has worked well in the past, but I am starting to use DropBox for a lot of other things now and don't want all of that to be downloaded on every virtual machine I use. Plus, I want to start using Eclipse + PyDev to be able to debug code and have code completion. Currently, I use TextEdit which is great, but doesn't support debugging or completion. So what are my options? I thought about setting up a Parallels VM on a thumb drive that has my entire environment on it (Eclipse included), but that has its own problems. Any other thoughts?

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  • django simple approach to multi-field search

    - by Scott Willman
    I have a simple address book app that I want to make searchable. The model would look something like: class Address(models.Model): address1 = models.CharField("Address Line 1", max_length=128) address2 = models.CharField("Address Line 2", max_length=128) city = models.CharField("City", max_length=128) state = models.CharField("State", max_length=24) zipCode = models.CharField("Zip Code", max_length=24) def __unicode__(self): return "%s %s, %s, %s, %s" % (self.address1, self.address2, self.city, self.state, self.zipCode) class Entry(models.Model): name = models.CharField("Official School Name", max_length=128) createdBy = models.ForeignKey(User) address = models.ForeignKey(Address, unique=True) def __unicode__(self): return "%s - %s, %s" % (self.name, self.address.city, self.address.state) I want the searching to be fairly loose, like: Bank of America Los Angeles 91345. It seems like I want a field that contains all of those elements into one that I can search, but that also seems redundant. I was hoping I could add a method to the Entry model like this: def _getSearchText(self): return "%s %s %s" % (self.name, self.address, self.mascot) searchText = property(_getSearchText) ...and search that as a field, but I suppose that's wishful thinking... How should I approach this using basic Django and SqLite (this is a learning exercise). Thank you!!

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  • How to save to Django Model that Have Mulitple Foreign Keys Fields

    - by Spikie
    I have Models for business Apps class staff_name(models.Model): TITLE_CHOICES = ( ('Mr', 'Mr'), ('Miss', 'Miss'), ( 'Mrs', 'Mrs'), ( 'chief', 'chief'), ) titlename = models.CharField(max_length=10,choices=TITLE_CHOICES) firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) date = models.DateTimeField(auto_now=True) class meta: ordering = ["date"] get_latest_by = "date" class inventory_transaction(models.Model): stock_in = models.DecimalField(blank=True, null=True,max_digits=8, decimal_places=2) stock_out = models.DecimalField(blank=True,null=True,max_digits=8, decimal_places=2) Number_container = models.ForeignKey(container_identity) staffs = models.ForeignKey(staff_name) goods_details = models.ForeignKey(departments) balance = models.DecimalField(max_digits=8, decimal_places=2) date = models.DateTimeField(auto_now=True) What i want to accomplish is check if the staff have made entry to the table before if yes add the value for the stock in plus (last) balance field and assign to balance if no just assign stock in value to balance field and save these are my codes These are my codes: try: s = staffname.staffs_set.all().order_by("-date").latest() # staffname is the instant of the class model staff_name e = s.staffs_set.create(stockin=vdataz,balance=s.balance + vdataz ) # e is the instant of the class model inventory_transaction e.save e.staffs.add(s) e.from_container.add(containersno) e.goods_details.add(department) except ObjectDoesNotExist: e = staff_name.objects.create(stockin=vdataz,balance=vdataz ) e.save e.staffs.add(staffname) e.from_container.add(containersno) e.goods_details.add(department) I will really appreciate a solution Thanks I hope it make more sense now. iam on online if you need more explanation just ask in the comment.Thank you for your help

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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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  • Django - foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = type_g.type_id, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT n.*, l.* FROM objtree_nodes n JOIN objtree_labels l ON (n.node_id = l.node_id) WHERE n.type_id = 15 AND n.parent_id = 50 AND l.type_id = 1 Any help is GREATLY appreciated. Regards

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • Need a workaround to filter on related model and aggregated fields in Django

    - by parxier
    I opened a ticket for this problem. In a nutshell here is my model: class Plan(models.Model): cap = models.IntegerField() class Phone(models.Model): plan = models.ForeignKey(Plan, related_name='phones') class Call(models.Model): phone = models.ForeignKey(Phone, related_name='calls') cost = models.IntegerField() I want to run a query like this one: Phone.objects.annotate(total_cost=Sum('calls__cost')).filter(total_cost__gte=0.5*F('plan__cap')) Unfortunately Django generates bad SQL: SELECT "app_phone"."id", "app_phone"."plan_id", SUM("app_call"."cost") AS "total_cost" FROM "app_phone" INNER JOIN "app_plan" ON ("app_phone"."plan_id" = "app_plan"."id") LEFT OUTER JOIN "app_call" ON ("app_phone"."id" = "app_call"."phone_id") GROUP BY "app_phone"."id", "app_phone"."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan"."cap" and errors with: ProgrammingError: column "app_plan.cap" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan".... Is there any workaround apart from running raw SQL?

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  • Ajax request not receiving xml from Django

    - by amougeot
    I have a Django server which handles requests to a URL which will return some HTML for use in an image gallery. I can navigate to the URL and the browser will display the HTML that is returned, but I can't get that same HTML by doing an AJAX call (using jQuery) to the same URL. This is the view that generates the response: def gallery_images(request, gallery_name): return render_to_response('galleryimages.html', {'images': get_images_of_gallery(gallery_name)}, mimetype='text/xml') This is the 'galleryimages.html' template: {% for image in images %} <div id="{{image.name}}big"> <div class="actualImage" style="background-image:url({{image.image.name}});"> <h1>{{image.caption|safe}}</h1> </div> </div> {% endfor %} This is the jQuery call I am making: $("#allImages").load("http://localhost:8000/galleryimages/Web"); However, this loads nothing into my #allImages div. I've used firebug and ran jQuery's Ajax method .get("http://localhost:8000/galleryimages/Web") and firebug says that the response text is completely empty. When I check my Django server log, this is the entry I see for when I navigate to the URL manually, through my browser: [16/Jan/2010 17:34:10] "GET /galleryimages/Web HTTP/1.1" 200 215 This is the entry in the server log for when I make the AJAX call: [16/Jan/2010 17:36:19] "OPTIONS /galleryimages/Web HTTP/1.1" 200 215 Why does the AJAX request not get the xml that my Django page is serving?

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  • Django | passing form values

    - by MMRUser
    I want to create a user sign up process that requires two different forms with the same data one (1st form) is for filling out the data and other one (2nd form) is for displaying the filled data as a summery (before actually saving the data) so then user can view what he/she has filled up... my problem is that how do I pass 1st form's data in to the 2nd one .. I have used the basic Django form manipulation mechanism and passed the form field values to the next form using Django template tags.. if request.method == 'POST': form = Users(request.POST) if form.is_valid(): cd = form.cleaned_data try: name = cd['fullName'] email = cd['emailAdd'] password1 = cd['password'] password2 = cd['password2'] phoneNumber = cd['phoneNumber'] return render_to_response('signup2.html', {'name': name, 'email': email, 'password1': password1, 'password2': password2, 'phone': phone, 'pt': phoneType}) except Exception, ex: return HttpResponse("Error %s" % str(ex)) and from the second from I just displayed those field values using tags and also used hidden fields in order to submit the form with values, like this: <label for="">Email:</label> {{ email }} <input type="hidden" id="" name="email" class="width250" value="{{ email }}" readonly /> It works nicely from the out look, but the real problem is that if someone view the source of the html he can simply get the password even hackers can get through this easily. So how do I avoid this issue.. and I don't want to use Django session since this is just a simple sign up process and no other interactions involved. Thanks.

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  • Sort queryset by a generic foreign key (django)?

    - by thornomad
    I am using Django's comment framework which utilizes generic foreign keys. Question: How do I sort a given model's queryset by their comment count using the generic foreign key lookup? Reading the django docs on the subject it says one needs to calculate them not using the aggregation API: Django's database aggregation API doesn't work with a GenericRelation. [...] For now, if you need aggregates on generic relations, you'll need to calculate them without using the aggregation API. The only way I can think of, though, would be to iterate through my queryset, generate a list with content_type and object_id's for each item, then run a second queryset on the Comment model filtering by this list of content_type and object_id ... sort the objects by the count, then re-create a new queryset in this order by pulling the content_object for each comment ... This just seems wrong and I'm not even sure how to pull it off. Ideas? Someone must have done this before. I found this post online but it requires me handwriting SQL -- is that really necessary ?

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  • List display names from django models

    - by Ed
    I have an object: POP_CULTURE_TYPES = ( ('SG','Song'), ('MV', 'Movie'), ('GM', 'Game'), ('TV', 'TV'), ) class Pop_Culture(models.Model): name = models.CharField(max_length=30, unique=True) type = models.CharField(max_length=2, choices = POP_CULTURE_TYPES, blank=True, null=True) Then I have a function: def choice_list(request, modelname, field_name): mdlnm = get.model('mdb', modelname.lower()) mdlnm = mdlnm.objects.values_list(field_name, flat=True).distinct().order_by(field_name) return render_to_response("choice_list.html", { 'model' : modelname, 'field' : field_name, 'field_list' : mdlnm }) This gives me a distinct list of all the "type" entries in the database in the "field_list" variable passed in render_to_response. But I don't want a list that shows: SG MV I want a list that shows: Song Movie I can do this on an individual object basis if I was in the template object.get_type_display But how do I get a list of all of the unique "type" entries in the database as their full names for output into a template? I hope this question was clearly described. . .

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  • MVC null model problem

    - by femi
    hello, i have created two create actions..one to call the create view and the other to process the create view using httppost. when i call the create view, it gets published correctly , dropdowns and all. the problem is that when i fill out the create form and click on the submit button, i get an error; Object reference not set to an instance of an object. My first thoughts are that i am passing a null model to the httppost create action.. How can i check to see if i am passing in a null model to the httppost create action? thanks

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  • Metalanguage like BNF or XML-Schema to validate a tree-instance against a tree-model

    - by Stefan
    Hi! I'm implementing a new machine learning algorithm in Java that extracts a prototype datastructure from a set of structured datasets (tree-structure). As im developing a generic library for that purpose, i kept my design independent from concrete data-representations like XML. My problem now is that I need a way to define a data model, which is basically a ruleset describing valid trees, against which a set of trees is being matched. I thought of using BNF or a similar dialect. Basically I need a way to iterate through the space of all valid TreeNodes defined by the ModelTree (Like a search through the search space for algorithms like A*) so that i can compare my set of concrete trees with the model. I know that I'll have to deal with infinite spaces there but first things first. I know, it's rather tricky (and my sentences are pretty bumpy) but I would appreciate any clues. Thanks in advance, Stefan

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  • iPad: Show view as Model View

    - by a111
    hi all, i want to show my view as a model view. In iPad there are four method to show the view as modal which is listed 1. Full Screen 2. Page Sheet 3. Form sheet 4. Current Context i use following code to display the view as model -(void)OpenContactPicker { ABPeoplePickerNavigationController *ContactPicker = [[ABPeoplePickerNavigationController alloc] init]; ContactPicker.peoplePickerDelegate = self; [self presentModalViewController:ContactPicker animated:YES]; //[self.modalViewController presentModalViewController:ContactPicker animated:YES]; [ContactPicker release]; } above code open the view in full screen mode but i want to some different. Please suggest how can i show this view as Page Sheet or Form sheet or Current Context

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  • Unicode issue in Django

    - by Kave
    I seem to have a unicode problem with the deal_instance_name in the Deal model. It says: coercing to Unicode: need string or buffer, __proxy__ found The exception happens on this line: return smart_unicode(self.deal_type.deal_name) + _(u' - Set No.') + str(self.set) The line works if I remove smart_unicode(self.deal_type.deal_name) but why? Back then in Django 1.1 someone had the same problem on Stackoverflow I have tried both the unicode() as well as the new smart_unicode() without any joy. What could I be missing please? class Deal(models.Model): def __init__(self, *args, **kwargs): super(Deal, self).__init__(*args, **kwargs) self.deal_instance_name = self.__unicode__() deal_type = models.ForeignKey(DealType) deal_instance_name = models.CharField(_(u'Deal Name'), max_length=100) set = models.IntegerField(_(u'Set Number')) def __unicode__(self): return smart_unicode(self.deal_type.deal_name) + _(u' - Set No.') + str(self.set) class Meta: verbose_name = _(u'Deal') verbose_name_plural = _(u'Deals') Dealtype: class DealType(models.Model): deal_name = models.CharField(_(u'Deal Name'), max_length=40) deal_description = models.TextField(_(u'Deal Description'), blank=True) def __unicode__(self): return smart_unicode(self.deal_name) class Meta: verbose_name = _(u'Deal Type') verbose_name_plural = _(u'Deal Types')

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  • Kohana 3: Example of model with validation

    - by Svish
    I find examples and tutorials about models and about validation. And I places that say the validation (or most of it at least) should be in the model, which I agree with. But I can't any examples or tutorials that show how that should be done. Could anyone help me with a simple example on how that could be done? Where would you have the rules in the model? Where would the validation happen? How would the controller know if the validation passed or fail? How would the controller get error messages and things like that? Hope someone can help, cause feel a bit lost here :p

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  • Rails 2.3.5 model name translation problem in error messages

    - by Jason Nerer
    Hi Rails'ers, I encountered some problem while trying to translate my model's names and attributes in a Rails 2.3.5 app. I have the following model: class BillingPlan < ActiveRecord::Base validates_presence_of :billing_option_id belongs_to :order belongs_to :user belongs_to :billing_option end When validation fails, my models attributes are translated correctly, but the modelname itself is not. I use the following translation skeleton in de.yml de: activerecord: models: shipping_plan: "Versandart" billing_plan: "Rechnungsart" attributes: shipping_plan: shipping_option_id: "Versandoption" billing_plan: billing_option_id: "Rechnungsoption" Basis for my translation file is: http://github.com/svenfuchs/rails-i18n/blob/master/rails/locale/de.yml Can anyone help? Thx in advance J.

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  • Generate Entity Data Model from Data Contract

    - by CSmooth.net
    I would like to find a fast way to convert a Data Contract to a Entity Data Model. Consider the following Data Contract: [DataContract] class PigeonHouse { [DataMember] public string housename; [DataMember] public List<Pigeon> pigeons; } [DataContract] class Pigeon { [DataMember] public string name; [DataMember] public int numberOfWings; [DataMember] public int age; } Is there an easy way to create an ADO.NET Entity Data Model from this code?

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  • Django queries: Count number of objects with FK to model instance

    - by Chris Lawlor
    This should be easy but for some reason I'm having trouble finding it. I have the following: App(models.Model): ... Release(models.Model): date = models.DateTimeField() App = models.ForeignKey(App) ... How can I query for all App objects that have at least one Release? I started typing: App.objects.all().annotate(release_count=Count('??????')).filter(release_count__gt=0) Which won't work because Count doesn't span relationships, at least as far as I can tell. BONUS: Ultimately, I'd also like to be able to sort Apps by latest release date. I'm thinking of caching the latest release date in the app to make this a little easier (and cheaper), and updating it in the Release model's save method, unless of course there is a better way. Edit: I'm using Django 1.1 - not averse to migrating to dev in anticipation of 1.2 if there is a compelling reason though.

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  • Why is Django reverse() failing with unicode?

    - by JeffS
    Here is a django models file that is not working as I would expect. I would expect the to_url method to do the reverse lookup in the urls.py file, and get a url that would correspond to calling that view with arguments supplied by the Arguments model. from django.db import models class Element(models.Model): viewname = models.CharField(max_length = 200) arguments = models.ManyToManyField('Argument', null = True, blank = True ) @models.permalink def to_url(self): d = dict( self.arguments.values_list('key', 'value') ) return (self.viewname, (), d) class Argument(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) The value d ends up as a dictionary from a unicode string to another unicode string, which I believe, should work fine with the reverse() method that would be called by the permalink decorator, however, it results in: TypeError: reverse() keywords must be strings

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