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  • xargs command works on ubuntu, but not mac

    - by Corey Hart
    I have the following line of code that I use to update my personal date variable in my projects to todays current date. This line works in Ubuntu's terminal, but the Mac terminal seems to be far behind. Unfortunately, I copied this snippet from some site, so I'm not sure how it exactly works. Suggestions? grep -ilr --exclude=revar.sh --exclude=README.md "[DATE]" * | grep -v .git | xargs -i@ sed -i "s/\[DATE\]/${today}/g" @

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  • How to handle date difference between client and server?

    - by daydreamer
    I have an API which looks like /summary/yyyy/mm Which returns the summary of their data for the year and month requested. One of the things it returns the number of days left if this is current year and month. For example: days_left: 9 for 2013 and 10 and current date on server is 21 Oct 2013 How I calculate remaining days? This is implemented in python as def current_financial_month_details(self): time_from, time_to = self \ .get_start_end_time_current_financial_month() today = datetime.today() from_time = datetime(year=today.year, month=today.month, day=today.day) return { 'time_from': time_from, 'time_to': time_to, 'remaining_days': (time_to - from_time).days } The problem? The server is in east coast and the client(me with browser) is on pacific time zone When its 9PM PST the time changes in east coast, so if I run hit /summary/2013/10 and if it is Oct 21 2013 for me on PST, the date has already changed on EST, so days_left: 8 which is incorrect on client end. right? How do I handle this situation?

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  • Externally disabling signals for a Linux program.

    - by Harry
    Hello, On Linux, is it possible to somehow disable signaling for programs externally... that is, without modifying their source code? Context: I'm calling a C (and also a Java) program from within a bash script on Linux. I don't want any interruptions for my bash script, and for the other programs that the script launches (as foreground processes). While I can use a... trap '' INT ... in my bash script to disable the Ctrl C signal, this works only when the program control happens to be in the bash code. That is, if I press Ctrl C while the C program is running, the C program gets interrupted and it exits! This C program is doing some critical operation because of which I don't want it be interrupted. I don't have access to the source code of this C program, so signal handling inside the C program is out of question. #!/bin/bash trap 'echo You pressed Ctrl C' INT # A C program to emulate a real-world, long-running program, # which I don't want to be interrupted, and for which I # don't have the source code! # # File: y.c # To build: gcc -o y y.c # # #include <stdio.h> # int main(int argc, char *argv[]) { # printf("Performing a critical operation...\n"); # for(;;); // Do nothing forever. # printf("Performing a critical operation... done.\n"); # } ./y Regards, /HS

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  • How to run bash script from windows using plink on linux

    - by user128877
    I'm trying to run a simple bat file from windows that will run a bash script on linux machine. The bash script is located on the linux machine. For example: I'm trying to run this bat file from windows plink.exe -pw <password> root@<ip> bash -c "/root/script.sh" Result: When running from windows the cmd is stuck forever when running the specific script (/root/script.sh) from the linux machine it's working just fine. The script contain ruby code and I'm using RVM

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  • have a bash script remotely shutdown another computer on the lan

    - by gletscher
    Hi I want to write a bash script that when called shuts down another computer on the lan. Maybe using ssh? The other computer is an ubuntu machine. Now I'm not sure how to send e.g. a sudo shutdown -h now command from withing a bash script to the ssh after logging in. Also I'm not sure how to obtain the rights for the sudo command, hence how to handle the communication between the server and client from within a bash script. Any suggestions are greatly appreciated.

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  • Windows CMD, show the current folder name at prompt dynamically like Bash

    - by guneysus
    I am trying to modify my CMD, to show only current dir name dynamically like: Desktop $ When i switched the folder, it must be updated. It is not required to be code in purely batch file, it may depend any external commands, cygwin bash, etc. @echo off set a=bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'" %a% cmd outputs _test-et Microsoft Windows [Version 6.3.9600] (c) 2013 Microsoft Corporation. Tüm haklari saklidir. >> But >> prompt %a% gives bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'"

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  • Display date/time in Ubuntu lock screen (cinnamon-like)

    - by 3l4ng
    I was using Ubuntu 13.04 till a few days ago. I had installed Nemo and I guess cinnamon got installed too (I was still using Unity nonetheless). One of the good things about that was the lock screen somehow changed to mimick cinnamon's (with the background as a darkened version of desktop background and date/time displayed), something like this: I have no idea how this happened, but it looked great. It does not seem to work on Ubuntu 13.10. Anyone has any ideas to get a similar lock screen? I just need to display the date/time on one side with the bg as a darkened version of my desktop wallpaper

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  • Calculate Age using Date Field

    - by BRADINO
    So if you have a database table that has DOB borthdays as date fields, this is an easy way to query that table based on age parameters. The following examples assume that the date of birth date field is dob and the table name is people. Find people who are 30 years old SELECT DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0 AS `age` FROM `people` HAVING `age` = 30 Find people who are 31-42 years old SELECT DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0 AS `age` FROM `people` HAVING `age`>= 31 AND `age` <= 42 Find oldest person SELECT MAX(DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0) AS `age` FROM `people` Find youngest person SELECT MIN(DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0) AS `age` FROM `people`

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  • How to replace the SharePoint date calendar control with more user friendly jQuery calendar control

    - by ybbest
    When you use the SharePoint date and time type for date of birth field, you will notice that the calendar control is extremely non-user-friendly. You can only navigate month by month as shown below. To resolve the issue, you can customize the list form page using SharePoint designer and replace the OOB calendar control with popular jQuery control. The solution works for both SharePoint 2010,2013 and office365. Here are the steps for how to achieve this. 1. Open SharePoint designer and create a New List Form called customNew and set as default form for the selected type. 2. Open style library in file explorer and copy jQuery and jQuery UI files into the style library in SharePoint site. You can download the jQuery and jQuery UI from the web and the content of the contactPersonCustomNewForm.js is as below. I use the dd/mm/yy format as my locale in Regional Settings is English(New Zealand). You need to change this if you live in another country with different date format $(document).ready(function() { $("img#ctl00_m_g_540b9a50_52dc_4400_a58d_1db99555fddf_ff41_ctl00_ctl00_DateTimeField_DateTimeFieldDateDatePickerImage").parent().hide(); $("img#ctl00_m_g_540b9a50_52dc_4400_a58d_1db99555fddf_ff41_ctl00_ctl00_DateTimeField_DateTimeFieldDateDatePickerImage").hide(); $("input#ctl00_m_g_540b9a50_52dc_4400_a58d_1db99555fddf_ff41_ctl00_ctl00_DateTimeField_DateTimeFieldDate").datepicker({ changeMonth:true, changeYear:true, showOn: "button", buttonImage: "/_layouts/images/calendar.gif", buttonImageOnly: true, defaultDate:"01/01/1970", yearRange: "c-20:c+20", dateFormat: "dd/mm/yy" }); }); In order to get the image and textbox selector above , you can open IE developer toolbar(click F12) and find the control ID as below: 3. Open SharePoint designer and edit the newly created New List Form customNew.aspx in advance mode. Then copy and paste the following links in the PlaceHolderAdditionalPageHead. <SharePoint:CssRegistration name="<%$SPUrl:~SiteCollection/Style Library/themes/ui-lightness/jquery-ui.css%>" runat="server"/> <SharePoint:ScriptLink language="javascript" name="~sitecollection/Style Library/jquery-1.10.2.js" Defer="false" runat="server"/> <SharePoint:ScriptLink language="javascript" name="~sitecollection/Style Library/jquery-ui-1.10.4.custom.min.js" Defer="false" runat="server"/> <SharePoint:ScriptLink language="javascript" name="~sitecollection/Style Library/contactPersonCustomNewForm.js" Defer="false" runat="server"/>   4. Now go to the list and click add, you will see the new calendar control as shown below

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  • Date Time Format in RUBY

    - by Madhan ayyasamy
    The following snippets is very useful when we render views dates in various format in ruby on rails."Format meaning:  %a - The abbreviated weekday name (``Sun'')  %A - The  full  weekday  name (``Sunday'')  %b - The abbreviated month name (``Jan'')  %B - The  full  month  name (``January'')  %c - The preferred local date and time representation  %d - Day of the month (01..31)  %H - Hour of the day, 24-hour clock (00..23)  %I - Hour of the day, 12-hour clock (01..12)  %j - Day of the year (001..366)  %m - Month of the year (01..12)  %M - Minute of the hour (00..59)  %p - Meridian indicator (``AM''  or  ``PM'')  %S - Second of the minute (00..60)  %U - Week  number  of the current year,          starting with the first Sunday as the first          day of the first week (00..53)  %W - Week  number  of the current year,          starting with the first Monday as the first          day of the first week (00..53)  %w - Day of the week (Sunday is 0, 0..6)  %x - Preferred representation for the date alone, no time  %X - Preferred representation for the time alone, no date  %y - Year without a century (00..99)  %Y - Year with century  %Z - Time zone name  %% - Literal ``%'' character   t = Time.now   t.strftime("Printed on %m/%d/%Y")   #=> "Printed on 04/09/2003"   t.strftime("at %I:%M%p")            #=> "at 08:56AM""Have a great day!

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  • Package information was last updated 59 days ago even though Ubuntu is up to date

    - by Luuz
    I'm using ubuntu 11.10 and in the update manager I have a message that says package information last updated 59 days ago press the check button to check for software updates I do that, but i'm up to date. I checked other threads with this same problem, and saw i should do sudo apt-get update in a terminal to see which repository is not up to date and when I did, I got this message: Failed to fetch http://extras.ubuntu.com/ubuntu/dists/oneiric/Release Then I checked for this repository in software sources but couldn't find this specific one. In my /etc/apt/sources.list.d I have only one line: deb http://archive.canonical.com/ubuntu oneiric partner #Added by software-center So now I don't know what to do more. Should I upgrade to 12.04 and will it solve my problem? I wouldn't want to upgrade if there is a problem in the last version but I don't know much about Ubuntu so, can anyone help me please? Thank you!!

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  • The Case of the Missing Date/Time Stamp: Reporting Services 2008 R2 Snapshots

    - by smisner
    This week I stumbled upon an undocumented “feature” in SQL Server 2008 R2 Reporting Services as I was preparing a demonstration on how to set up and use report snapshots. If you’re familiar with the main changes in this latest release of Reporting Services, you probably already know that Report Manager got a facelift this time around. Although this facelift was generally a good thing, one of the casualties – in my opinion – is the loss of the snapshot label that served two purposes… First, it flagged the report as a snapshot. Second, it let you know when that snapshot was created. As part of my standard operating procedure when demonstrating report snapshots, I point out this label, so I was rather taken aback when I didn’t see it in the demonstration I was preparing. It sort of upset my routine, and I’m rather partial to my routines. I thought perhaps I wasn’t looking in the right place and changed Report Manager from Tile View to Detail View, but no – that label was still missing. In the grand scheme of life, it’s not an earth-shattering change, but you’ll have to look at the Modified Date in Details View to know when the snapshot was run. Or hope that the report developer included a textbox to show the execution time in the report. (Hint: this is a good time to add this to your list of report development best practices, whether a report gets set up as a report snapshot or not!) A snapshot from the past In case you don’t remember how a snapshot appeared in Report Manager back in the old days (of SQL Server 2008 and earlier), here’s an image I snagged from my Reporting Services 2008 Step by Step manuscript: A snapshot in the present A report server running in SharePoint integrated mode had no such label. There you had to rely on the Report Modified date-time stamp to know the snapshot execution time. So I guess all platforms are now consistent. Here’s a screenshot of Report Manager in the 2008 R2 version. One of these is a snapshot and the rest execute on demand. Can you tell which is the snapshot? Consider descriptions as an alternative So my report snapshot demonstration has one less step, and I’ll need to edit the Denali version of the Step by Step book. Things are simpler this way, but I sure wish we had an easier way to identify the execution methods of the reports. Consider using the description field to alert users that the report is a snapshot. It might save you a few questions about why the data isn’t up-to-date if the users know that something changed in the source of the report. Notice that the full description doesn’t display in Tile View, so keep it short and sweet or instruct users to open Details View to see the entire description.

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  • Calendar icon in unity shows wrong date

    - by felix
    There is a column of icons in unity on the far left and one of them has the number "31" in big numerals. If you mouse over it it says "Google Calendar" and if you click on it you get google calendar which of course shows the correct date. Today is November 3. Shouldn't it say "3" instead? If I type "date" from the command line I get Sun Nov 3 21:19:37 GMT 2013 I see this was fixed for Chrome at least in 2011 http://gmailblog.blogspot.co.uk/2011/04/5-years-of-google-calendar-and-new.html .

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  • Organising dates in PHP

    - by richzilla
    Hi All, Im wanting to organize a series of dates in the following format. As a bit of context, the dates are the dates of upcoming events that can be added by my users. The format: January 2011 date - event date - event date - event February 2011 date - event date - event date - event with all events in a given month, arranged by the date on which they occur. All of my event dates are stored in my database as unix timestamps. Problem is, i dotn know where id start to develop a function that would order all of my events in this way. Can anyone help me out? Cheers

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  • Problem with Zend_Date and ISO_8601 format

    - by Noah Goodrich
    Frankly, I'm flummoxed. Can anyone tell me why I would get a failure message with this code? $date = Zend_Date::now(); $date = $date->getIso(); if(Zend_Date::isDate($date, Zend_Date::ISO_8601)) { print('success'); } else { print('failure'); } exit; It also fails if I just pass in a Zend_Date object. UPDATE: a var_dump of the initial $date object looks like this: object(Zend_Date)#107 (8) { ["_locale:private"]= string(5) "en_US" ["_fractional:private"]= int(0) ["_precision:private"]= int(3) ["_unixTimestamp:private"]= int(1257508100) ["_timezone:private"]= string(14) "America/Denver" ["_offset:private"]= int(25200) ["_syncronised:private"]= int(0) ["_dst:protected"]= bool(true) } And a var_dump of the $date string after calling $date-getIso() looks like this: string(25) "2009-11-06T04:48:20-07:00" I am using ZF 1.9.5 on PHP 5.2.8. I am using XAMPP for Windows too if that makes a difference.

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  • missing value true / false: error in loop not in one-off

    - by vincent hay
    I am new on R and I have a problem with a test in a loop that I want to code. With a data frame (tabetest) like the one here after: Date 25179M103 1 14977 77.7309 2 14978 77.2567 3 14979 77.7507 I have: if(tabetest[3,"Date"]-tabetest[1,"Date"]1){print("ok")} [1] "ok" But: j=1 > position = 1 > price=tabetest for (i in 1:nrow(tabetest)-position){if(tabetest[i+position,"Date"]-tabetest[position,"Date"]>20){price[i+position,j]=price[i+position,j]/price[position,j]-1};position=position+1} Returns an error. R says that there is a missing value where true/false is required in: if (tabetest[i + position, "Date"] - tabetest[position, "Date"] > I have spent quite some time on that error but still don't understand where it comes from. Thanks for your help, Vincent

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  • How to get strptime to raise ArgumentError with garbage trailing characters

    - by Matt Briggs
    We have to handle user specified date formats in our application. We decided to go with Date.strptime for parsing and validation, which works great, except for how it just ignores any garbage data entered. Here is an irb session demonstrating the issue ree-1.8.7-2010.01 > require 'date' => true ree-1.8.7-2010.01 > d = Date.strptime '2001-01-01failfailfail', '%Y-%m-%d' => #<Date: 4903821/2,0,2299161> ree-1.8.7-2010.01 > d.to_s => "2001-01-01" what we would like, is behavior more like this ree-1.8.7-2010.01 > d = Date.strptime '2001failfailfail-01-01', '%Y-%m-%d' ArgumentError: invalid date Any suggestions would be appreciated

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  • Why is Ubuntu's clock getting slower or faster?

    - by ændrük
    Ubuntu's clock is off by about a half hour: Where do I even start troubleshooting this? It's allegedly being set "automatically from the Internet". How can I verify that "the Internet" knows what time it is? Details Ubuntu has had plenty of time to communicate with the Internet: $ date; uptime Fri May 18 05:56:00 PDT 2012 05:56:00 up 12 days, 10:48, 2 users, load average: 0.61, 0.96, 1.15 This time server I found via a web search does appear to know the correct time: $ date; ntpdate -q north-america.pool.ntp.org Fri May 18 05:56:09 PDT 2012 server 208.38.65.37, stratum 2, offset 1752.625337, delay 0.10558 server 46.166.138.172, stratum 2, offset 1752.648597, delay 0.10629 server 205.189.158.228, stratum 3, offset 1752.672466, delay 0.11829 18 May 05:56:18 ntpdate[29752]: step time server 208.38.65.37 offset 1752.625337 sec There aren't any reported errors related to NTP: $ grep -ic ntp /var/log/syslog 0 After rebooting, the time was automatically corrected and the following appeared in /var/log/syslog: May 18 17:58:12 aux ntpdate[1891]: step time server 91.189.94.4 offset 1838.497277 sec A log of the offset reported by ntpdate reveals that the clock is drifting by about 9 seconds every hour: $ while true; do ntpdate-debian -q | tail -n 1 >> 'drift.log'; sleep 16m; done ^C $ r -e ' attach(read.table("drift.log", header=FALSE)) clock <- as.POSIXct(paste(V1, V2, V3), format="%d %b %H:%M:%S") fit <- lm(V10~clock) png("drift.png") plot(clock, V10, xlab="Clock time", ylab="Time server offset (s)") abline(fit) mtext(sprintf("Drift rate: %.2f s/hr", fit$coefficients[[2]]*3600)) '

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  • grep is inconsistently defaulting to grep -P?

    - by Sammitch
    I have a script that does some housekeeping that works perfectly well when invoked from an interactive shell, but did nothing when invoked by cron. To troubleshoot this I started a shell with a 'blank' environment with the command: env -i /bin/bash --noprofile --norc Using this blank env I've dug into my script and found that the following grep will not match any files: grep -il "^ws_status\s*=\s*[\"']remove[\"']$" However, when run from an interactive shell the command will return the filenames of the matching files. As a note, the expression is matching lines like: WS_STATUS = "remove" Through trial-and-error I discovered that adding -P to the options [Perl regex] the command started working normally in the 'blank' shell. However, I have no idea why my login shell appears to be defaulted to grep -P. There is only one grep binary, /bin/grep There are no aliases defined for grep=pgrep or grep="grep -P" There is no env variable GREP_OPTIONS defined. What's the deal here? Note: OS is RHEL v5.10, Bash is v3.2.25, grep is v2.5.1

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  • MySQL equivalent to .pgpass, or automatic authentication in a cron job for mySQL

    - by Ibrahim
    I'm writing a bash script to back up my databases. Most are postgresql, and in postgres there's a way to avoid having to authenticate by creating a ~/.pgpass file which contains the postgres password. I put this in root's home directory and made it chmod 0600, so that root could dump the postgres databases without having to authenticate. Now I want to do something similar for mysql, although I only have one mysql database. How can I do this? I don't want to specify the password on the command line for mysqldump because this is part of a script that might be somewhat visible to other users. Is there a better way (i.e. built in to mysql) to do this than make a file that only root can read and then read that to get the mysql password, and then use that in the bash script as a variable?

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  • MySQL equivalent to .pgpass, or automatic authentication in a cron job for mySQL

    - by Ibrahim
    I'm writing a bash script to back up my databases. Most are postgresql, and in postgres there's a way to avoid having to authenticate by creating a ~/.pgpass file which contains the postgres password. I put this in root's home directory and made it chmod 0600, so that root could dump the postgres databases without having to authenticate. Now I want to do something similar for mysql, although I only have one mysql database. How can I do this? I don't want to specify the password on the command line for mysqldump because this is part of a script that might be somewhat visible to other users. Is there a better way (i.e. built in to mysql) to do this than make a file that only root can read and then read that to get the mysql password, and then use that in the bash script as a variable?

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