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  • How do I control the background color during the iPhone flip view animation transition?

    - by Rob S.
    I have some pretty standing flipping action going on: [UIView beginAnimations:@"swapScreens" context:nil]; [UIView setAnimationTransition:UIViewAnimationTransitionFlipFromLeft forView:self.view cache:YES]; [UIView setAnimationDuration:1.0]; [self.view exchangeSubviewAtIndex:0 withSubviewAtIndex:1]; [UIView commitAnimations]; To Apple's credit, this style of animation is amazingly easy to work with. Very cool, and I've been able to animate transitions, flips, fades etc. throughout the app very easily. Question: During the flip transition, the background visible 'behind' the two views during the flip is white and I'd like it to be black. I've: Set the background of the containing view (self.view above) - no dice. I really thought that would work. Set the background of each view to black - no dice. I didn't think this would work although you give different things a shot to understand better :) Google'd like crazy; keep landing on Safari-related listings. Thanks in advance!

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  • XSLT Transforming sequential XML to hierarchical XML

    - by Jean-Paul Smit
    I have a requirement to transform a sequential XML node list into a hierarchical, but I run into some XSLT specific knowledge gap. The input XML contains articles, colors and sizes. In the sample below 'Record1' is an article, 'Record2' represents a color and 'Record3' are the sizes. The number of colors and sizes (record2 and record3) elements can vary. <root> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> </root> All fields are on the same hierarchical level, but still I have to create this structure as output: <root> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> </root> I've tried to iterate the nodes sequentially but for example the 'article' (=record1) node tag needs to remain unclosed while 'color' (=record2) nodes are processed. The same counts for processing 'size' (=record3) having 'color' unclosed, but that is not allowed by XSLT. My next idea was to call a template for every article, color and size level, but I don't know how to select for example all 'record3' nodes between the current 'record2' and the next article represented by 'record1'. I've also got a limitation on the XSLT version because I need this transformation in BizTalk Server which only supports XSLT 1.0 Can someone push me in the right direction?

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  • Using colon syntax and variables in Sass

    - by corroded
    I am still using the old colon syntax (I prefer it more than the bracket syntax) and this particular code: a.button-link +box($main-color) +border-radius(5px) :background :color $main-color :color #fff :padding 5px generates a warning like so: DEPRECATION WARNING: On line 12, character 3 of '/Users/eumir/rails_apps/dxconnect/app/ stylesheets/partials/utilities/_link-styles.sass' Setting properties with = has been deprecated and will be removed in version 3.2. Use "background: $main-color" instead. I tried that but my background color still doesn't show up. Any help on this please? Thanks!

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  • What is the benefit of using int instead of bigint in this case?

    - by Yeti
    (MYSQL n00b) I have 3 tables: id = int(10), photo_id = bigint(20) PHOTO records limited to 3 million PHOTO: +-------+-----------------+ | id | photo_num | +-------+-----------------+ | 1 | 123456789123 | | 2 | 987654321987 | | 3 | 5432167894321 | +-------+-----------------+ COLOR: +-------+-----------------+---------+ | id | photo_num | color | +-------+-----------------+---------+ | 1 | 123456789123 | red | | 2 | 987654321987 | blue | | 3 | 5432167894321 | green | +-------+-----------------+---------+ SIZE: +-------+-----------------+---------+ | id | photo_num | size | +-------+-----------------+---------+ | 1 | 123456789123 | large | | 2 | 987654321987 | small | | 3 | 5432167894321 | medium | +-------+-----------------+---------+ Both COLOR and SIZE tables will have several million records. Q1: Is it better to change photo_num on COLOR and SIZE to int(10) and point it to PHOTO's id? Right now I use these: (PHOTO is no where in the picture) SELECT * from COLOR WHERE photo_num='xxx'; SELECT * from SIZE WHERE photo_num='xxx'; Q2: How will the SELECT query look if PHOTO id was used in COLOR, SIZE?

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  • Blending pixels from Two Bitmaps

    - by MarkPowell
    I'm beating my head against a wall here, and I'm fairly certain I'm doing something stupid, so time to make my stupidity public. I'm trying to take two images, blend them together into a third image using standard blending algorithms (Hardlight, softlight, overlay, multiply, etc). Because Android does not have such blend properties build in, I've gone down the path of taking each pixel and combine them using an algorithm. However, the results are garbage. Any help would be appreciated. Below is the code, which I've tried to strip out all the "junk", but some may have made it through. I'll clean it up if something isn't clear. Bitmap src = BitmapFactory.decodeResource(getResources(), R.drawable.base, options); Bitmap mutableBitmap = src.copy(Bitmap.Config.RGB_565, true); int imageId = getResources().getIdentifier("drawable/" + filter, null, getPackageName()); Bitmap filterBitmap = BitmapFactory.decodeResource(getResources(), imageId, options); float scaleWidth = ((float) mutableBitmap.getWidth()) / filterBitmap.getWidth(); float scaleHeight = ((float) mutableBitmap.getHeight()) / filterBitmap.getHeight(); IntBuffer buffSrc = IntBuffer.allocate(src.getWidth() * src.getHeight()); mutableBitmap.copyPixelsToBuffer(buffSrc); buffSrc.rewind(); IntBuffer buffFilter = IntBuffer.allocate(resizedFilterBitmap.getWidth() * resizedFilterBitmap.getHeight()); resizedFilterBitmap.copyPixelsToBuffer(buffFilter); buffFilter.rewind(); IntBuffer buffOut = IntBuffer.allocate(src.getWidth() * src.getHeight()); buffOut.rewind(); while (buffOut.position() < buffOut.limit()) { int filterInt = buffFilter.get(); int srcInt = buffSrc.get(); int alphaValueFilter = Color.alpha(filterInt); int redValueFilter = Color.red(filterInt); int greenValueFilter = Color.green(filterInt); int blueValueFilter = Color.blue(filterInt); int alphaValueSrc = Color.alpha(srcInt); int redValueSrc = Color.red(srcInt); int greenValueSrc = Color.green(srcInt); int blueValueSrc = Color.blue(srcInt); int alphaValueFinal = convert(alphaValueFilter, alphaValueSrc); int redValueFinal = convert(redValueFilter, redValueSrc); int greenValueFinal = convert(greenValueFilter, greenValueSrc); int blueValueFinal = convert(blueValueFilter, blueValueSrc); int pixel = Color.argb(alphaValueFinal, redValueFinal, greenValueFinal, blueValueFinal); buffOut.put(pixel); } buffOut.rewind(); mutableBitmap.copyPixelsFromBuffer(buffOut); BitmapDrawable drawable = new BitmapDrawable(getResources(), mutableBitmap); imageView.setImageDrawable(drawable); } int convert (int in1, int in2) { //simple multiply for example return in1 * in2 / 255; }

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  • Easiest way to convert json data into objects with methods attached?

    - by John Mee
    What's the quickest and easiest way to convert my json, containing the data of the objects, into actual objects with methods attached? By way of example, I get data for a fruitbowl with an array of fruit objects which in turn contain an array of seeds thus: {"fruitbowl": [{ "name": "apple", "color": "red", "seeds": [] },{ "name": "orange", "color": "orange", "seeds": [ {"size":"small","density":"hard"}, {"size":"small","density":"soft"} ]} } That's all nice and good but down on the client we do stuff with this fruit, like eat it and plant trees... var fruitbowl = [] function Fruit(name, color, seeds){ this.name = name this.color = color this.seeds = seeds this.eat = function(){ // munch munch } } function Seed(size, density){ this.size = size this.density = density this.plant = function(){ // grow grow } } My ajax's success routine currently is currently looping over the thing and constructing each object in turn and it doesn't handle the seeds yet, because before I go looping over seed constructors I'm thinking Is there not a better way? success: function(data){ fruitbowl.length = 0 $.each(data.fruitbowl, function(i, f){ fruitbowl.push(new Fruit(f.name, f.color, f.seeds)) }) I haven't explored looping over the objects as they are and attaching all the methods. Would that work?

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  • How to change CSS color values in real-time off a javascript slider?

    - by bflora
    I'm making a page where the user gets a javascript slider that goes from 0 to 100 and can use it to set the opacity of a div on the page. I want the opacity of that div to change in real-time as they work the slider. I've not done this before. What's the best approach? There cursor in the slider displays the slider's current value as you move it. It seems to be that I just need to find a way to display that value in any arbitrary other place on the page so I can display it in the style settings for the div. The .js file that generates the slider has a line that (I think) is setting the current value in the cursor: $(this).children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); TO get this changing number to display somewhere else at the same time, do I just need to add a div somewhere and then add a line like this? $("#newDivId").children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); That seems like it would give me the number showing up in a div. How then would I get it into a form I could put into the style settings for a div? If this was a php variable, I would do something like this, style="opacity:<?php print $value ?>;" What would be the .js equivalent?

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  • How do I Convert ARGB value from string to color?

    - by James
    I am trying to use the MakeColor method in the GDIAPI unit but the conversion from int to byte is not returning me the correct value. Example var argbStr: string; A, R, G, B: Byte; begin argbStr := 'ffffcc88'; A := StrToInt('$' + Copy(AValue, 0, 2)); R := StrToInt('$' + Copy(AValue, 3, 2)); G := StrToInt('$' + Copy(AValue, 5, 2)); B := StrToInt('$' + Copy(AValue, 7, 2)); Result := MakeColor(A, R, G, B); end; What am I doing wrong?

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  • how to view different file extension in different color ib terminal of mac leopard.

    - by Suren
    Hi, I am trying to get colored listing of directories and files as per their extension after ls command. Recently I switched over to mac leopard from Linux. There is no .bashrc file in my home directory, so I created one with the following contents.This is doing only a bit what I want (only directories as colored). I also want to view files with different extension in different colors. What and where to add? thanx in advance :) # Define how Bash prompt looks like: # # User @ Host - working dir #export PS1='\u@\h\w$ ' export PS1='\u@\h\w: ' # Cli Colors export CLICOLOR=1 # use blue for dir’s export LSCOLORS=exfxcxdxbxegedabagacad # Alias # # alias ls='ls -al'

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  • How to set result of function as global variable.

    - by George
    I'm sure this is really simple and I'm drawing a giant blank, but how do you set the result of a function as a global variable? Example, I want to set the first "color" in array "colors" as global variable "color" (I know the example doesn't make much practical sense, but it's just to illustrate my question): var color = ""; function selectColor () { var colors = ["blue","red","green","yellow"]; var color = colors[0]; return color; } window.onload = function () { selectColor (); alert(color); }

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  • Indexing a method return (depending on Internationalization)

    - by Hedde
    Consider a django model with an IntegerField with some choices, e.g. COLORS = ( (0, _(u"Blue"), (1, _(u"Red"), (2, _(u"Yellow"), ) class Foo(models.Model): # ...other fields... color = models.PositiveIntegerField(choices=COLOR, verbose_name=_(u"color")) My current (haystack) index: class FooIndex(SearchIndex): text = CharField(document=True, use_template=True) color = CharField(model_attr='color') def prepare_color(self, obj): return obj.get_color_display() site.register(Product, ProductIndex) This obviously only works for keyword "yellow", but not for any (available) translations. Question: What's would be a good way to solve this problem? (indexing method returns based on the active language) What I have tried: I created a function that runs a loop over every available language (from settings) appending any translation to a list, evaluating this against the query, pre search. If any colors are matched it converts them backwards into their numeric representation to evaluate against obj.color, but this feels wrong.

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  • How can I serve up color-coded Java code using PHP?

    - by Eric
    I'd like to embed code from my SVN repository into my website, using PHP. The SVN has public anonymous access, so the PHP code should be fine reading it. The code on said SVN is java, and so far I've had no luck finding a syntax-highlighter to make the code more readable. Ideally I'd like one that uses CSS classes so that I can change the colors to match the look of the website. Could someone point me to a PHP library that highlights Java code?

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  • DataGridView avoiding adding new columns

    - by phenevo
    Why, this code create 2 the same columns in grid (Color and Color). How to inputs data color from collection in column which existing before set datasource ?? public Form1() { InitializeComponent(); DataGridViewTextBoxColumn ds = new DataGridViewTextBoxColumn(); ds.Name = "Color"; dataGridView1.Columns.Add(ds); List<Car> cars=new List<Car>(); for (int i = 0; i < 5; i++) { Car car=new Car {Type = "type" + i.ToString(),Color=Color.Silver}; cars.Add(car); } dataGridView1.DataSource = cars; }

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  • Nested <a> and <span> challenge

    - by PaddyO
    Hi all, Trying in vain to get a nested link working within a nested span. This is a working test page for the code below to explain what I'm trying to do. Any ideas on how to get this working in valid html? I guess it's either a nesting order or style syntax thing but I am at a loss. Any thoughts much appreciated. <div id="greyback"> <ul id="scrollbox"> <li class="listcat">List header</li> <li><a class="menu" href="#freeze">List item 1<span><b>This text has popped up because you have clicked the list item, which has an "a" tag and now has :focus. That "a" tag is the first of two.</b><br><br>What I am trying to do is to set the second "a" tag as a DIFFERENT "embedded" link in this box<span style="color: blue; background-color: yellow;">eg, here<a href="http://www.conservationenterprises.com" target="blank">This is the second (nested) "a" tag in this html nest. It is a link to an external site. Instead of this being an always-visible link, I want it to sit within the yellow box in the first span (click the List item 1 to display).</a></span> </a></span> </li> </a></span> </li> </ul> </div> and the CSS: #scrollbox {margin: 0 auto; margin-top: 1em; margin-bottom: 1em; width:19em; height:auto; max-height: 21em; overflow:auto; border-bottom: 0.1em solid #FFA500; border-top: 0.1em solid #FFA500;} #scrollbox a {float: left; color:#000000; text-decoration:none; width:18em; height: auto; margin-bottom: 0.5em; font-family: Arial, sans-serif; font-size: 0.9em; text-align:left;} #scrollbox a.menu {} #scrollbox a span {display:none; position:absolute; left:0em; top:0;} #scrollbox a span img {float: right; border:0; max-width:7.5em;} #scrollbox a:hover {border: 0; color: #7ebb11; font-size:0.9em;} #scrollbox a:hover span {border: 0; color: #535353;} #scrollbox a span:focus {color: blue;} #scrollbox a:active {border:none; color: #535353; text-decoration: none;} #scrollbox a:focus {border:0em solid #000; outline:0;} #scrollbox a:active span, #scrollbox li a:active span, #scrollbox a:focus span, #scrollbox li a:focus span {display: block; width: 52.5em; min-height: 20em; height: auto; left: 1.5em; top:18em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: #c3FFe3; color: #535353; border: solid #FFA500 0.25em;} #scrollbox li a:active span span, #scrollbox li a:focus span span{display: block; width: auto; height: auto; min-height: 2em; left: 25em; top:10em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: transparent; color: #535353; border: dashed red 1px;} .ul#scrollbox {padding-left: 0.1em;} #scrollbox li {float:left; list-style: none; background: url(blank.png) no-repeat left center; margin-left: 0em; font-family:Arial, sans-serif; font-size: 0.9em;} #scrollbox li.listcat {float: left; text-align:left; width: 18em; margin-left: 0em; margin-top: 0.1em; margin-bottom: 0.3em; padding-top:0.5em; color: green; font-size: 0.9em; font-weight:bold;} Cheers Patrick.

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  • How to color or highlight line when user click the checkbox in jQuery?

    - by Rohit
    I am implementing the highlight procedure of line . If the user click the checkbox it will highlight whole line by yellow. User can make as this any number of line. So it is possible to highlight the whole line when user click the checkbox? Please check my picture I select all text when I click the checkbox (because you will understand my problem) I am trying here in this fiddle <div> <button id="next">next </button> <button id ="previous">previous </button> </div> Checked rows: <span id="checkedRows"></span> <div id="content"> <div id="left"> <div class='cb'> <input type="checkbox" /> </div> </div> <div id="realTimeContents" class="left realtimeContend_h"></div> </div>

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  • How to set only the first cell of a UITableView to a different color?

    - by Ted
    I use cellForRowAtIndexPath like here: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if(cell == nil) cell = [self getCellContentView:CellIdentifier]; UILabel *lbl = (UILabel*)[cell.contentView viewWithTag:1]; for (UITableViewCell *c in [tbl visibleCells]) { // UITableViewCell *cell2 = [tbl cellForRowAtIndexPath:[NSIndexPath indexPathForRow:i inSection:0]]; UILabel *lbl = (UILabel*)[c.contentView viewWithTag:1]; lbl.textColor = [UIColor redColor]; } if([tbl indexPathForCell:cell].section==0) lbl.textColor = [UIColor whiteColor]; UILabel *lblTemp1 = (UILabel *)[cell viewWithTag:1]; UILabel *lblTemp2 = (UILabel *)[cell viewWithTag:2]; //First get the dictionary object lblTemp1.text = @"test!"; lblTemp2.text = @"testing more"; NSLog(@"%@",[tbl indexPathForCell:cell]); return cell; } But is still makes some of my cells white instead of gray. How can I change only the first item in the row to white?

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