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  • How to show unread subforums?

    - by bilygates
    I have written a simple forum in PHP using PostgreSQL. The forum consists of a number of subforums (or categories, if you like) that contain topics. I have a table that stores when was the last time a user visited a topic. It's something like this: user_id, topic_id, timestamp. I can easily determine what topics should be marked as unread by comparing the timestamp of the last topic reply with the timestamp of the last user visit. My question is: how do I efficiently determine what subforums (categories) should be marked as unread? All I've come up with is this: every time a user visits a topic, update the visit timestamp and check if all the topics from the current subforum are read or unread. If they are all read, mark the subforum as read for the user. Else, mark it as unread. But I think there must be another way. Thank you in advance.

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  • How to return focus from GridView or DataGrid to other control on the page

    - by Senthilkumar
    I Want to know how to focus to control after completing tab navigation for the grid view. I have certain controls in my page and GridView/DataGrid as last control, when I navigate (Tab key navigation) on my page. I can navigate from first control to GridView but when I finish all editable items in grid the tab control goes to browser address bar. I need this should focus to again first control on the page. My question is how can I do this? If it is an ordinary controls then I can use (on key down) attribute of the same.. here how can I get access to the last row's last column on the grid view.

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  • Find subset with K elements that are closest to eachother

    - by Nima
    Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

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  • time difference on heroku server

    - by railsnew
    There seems to be a time difference on heroku server. >> Customer.last.id => 584 >> Customer.last.created_at => Thu, 06 May 2010 01:43:20 UTC +00:00 >> Time.zone => #<ActiveSupport::TimeZone:0x2b1dec47e5c0 @utc_offset=0, @tzinfo=#<TZInfo::DataTimezone: Etc/UTC>, @name="UTC"> >> Time.now => Wed May 05 19:05:15 -0700 2010 >> Time.now.zone => "PDT" Notice that current time is May 05 19...however, created_at date for last record is May 06 01:43. This does not make any sense. What can be causing this and how would I go about fixing this?

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  • Drupal and Login Toboggan -- infinite redirect loop

    - by Ian Silber
    I'm getting a redirect loop when using Login Toboggan. It doesn't happen all of the time and I think I've narrowed it down to something with the session, specifically the active-tabs[last-active-href] value. Since it's intermittent, I was able to print out a session of a working copy and a non-working copy. Here are both: WORKS -- Array ( [active-tabs] = Array ( [last-active-href] = index ) ) toboggan/denied DOESN'T WORK -- Array ( [active-tabs] = Array ( [last-active-href] = user/register [user] = user/register ) [wantsEvents] = [wantsResources] = [wantsSupport] = ) toboggan/denied I've also noticed that if I comment out the following line the redirection loop stops (although no page loads): $return = menu_execute_active_handler('user/register'); Any ideas? I'm at my wits end.

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  • Communicating from website to desktop application (not vice-versa)

    - by chakrit
    I am designing an application such that it will have to react to certain actions required by the website, mostly the same way Last.FM client does (if you have used one) The way Last.FM client works is that, it will register a custom protocol in Windows (lastfm://) and on their website, they use that protocol to trigger certain action on the player, e.g.: lastfm://artist//similarartists will actually direct any Last.FM client running to load up similar artists. I would like to do the same thing for my application. Is this a good idea? Is there any good alternatives to send a message from a website to a desktop client in this manner?

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  • How to compare if string has a enter key in the end using jquery/javascript?

    - by user144842
    I have a string value from a user input box. I have to figure out if last char is a enter key (line feed). Thats the code. Here I am checking if last char has a whitespace. Now I also have to check if last char is enter key (carriage return or line feed). How can i do this? var txt = $get("<%= txtUserText.ClientID %>"); if (txt.value.substring(txt.value.length -1) !== ' ' || <checkifLastCharIsEnterKey>) //my code to take action **I don't think i need a keypress or keyup event because this above piece of code is not invoked at the time of user input.

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  • DOM class injection in PHP

    - by Adam Kiss
    idea Via jQuery, I was able to mark all :first-child and :last-child elements in document (well, almost all :)) with class first which could I later style (i.e. first li in ul#navigation would be easily adressable as ul#navigation .first). I used following code: var $f = $('*:first-child') $f.addClass('first'); var $l = $('body *:last-child') $l.addClass('last'); question Now, my question is if it's possible to do the same via php, so non-JS users/gadgets could have the same effects and additional styling and also it would be less overkill on browser. So, is it possible to capture output, parse it as html and inject this class easily in php?

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  • How and when to log account access login with PHP?

    - by Nazgulled
    I want to implement a basic login system in some PHP app where no cookies will be involved. I mean, the user closes the browser and the login expires, it will remain active during the browser session (or if the user explicitly logs out) otherwise. I want to log all this activity and I'm thinking that every time the user refreshes the page, opens a different link or logs out, I record that time as the last access made by that user, overwriting the previous access log. But my problem is when and how should I insert another record into the database instead of overwriting the last one? Should I just define a timeout and if the last access was made above that timeout, another log should be inserted into the database? Should the session expire too after that timeout? Or is there a better way? Ideally, I would like to log the "log out action" when the browser was closed, but I don't think there's a way to detect that is there? Suggestions?

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • mysql LAST_INSERT_ID() used with multiple records INSERT statement

    - by bogdan
    Hello, If i insert multiple records with a loop that executes a single record insert, the last insert id returned is, as expected, the last one... but if i do a multiple records insert statement: INSERT INTO people (name,age) VALUES('William',25),('Bart',15),('Mary',12); let's say the three above are the first records inserted in the table...after the insert statement i expected last insert id to return 3, but it returned 1...the first insert id for the statement in question... So can someone please confirm if this is the normal behavior of LAST_INSERT_ID() in the context of multiple records INSERT statements...so i can base my code on it thanks :)

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  • Taking out a subpart from Enumerable

    - by sawa
    I often want to take out a subpart from an Enumerable. The subpart is sometimes at the beginning and sometimes the end of the original Enumerable instance, and the length used to specify the subpart is sometimes that of the subpart and sometimes its complement. That gives four possibilities, but I only know how to do three of them. Is there a way to do the fourth one? Getting the first n elements: [1, 2, 3, 4, 5].first(3) #= [1, 2, 3] or [1, 2, 3, 4, 5].take(3) #= [1, 2, 3] Dropping the first n elements: [1, 2, 3, 4, 5].drop(3) #= [4, 5] Getting the last n elements: [1, 2, 3, 4, 5].last(3) #= [3, 4, 5] Dropping the last n elements: [1, 2, 3, 4, 5].some_method(3) #= [1, 2]

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  • How do I *really* justify a horizontal menu in HTML+CSS?

    - by flight
    You find plenty of tutorials on menu bars in HTML, but for this specific (though IMHO generic) case, I haven't found any decent solution: # THE MENU ITEMS SHOULD BE JUSTIFIED JUST AS PLAIN TEXT WOULD BE # # ^ ^ # # There's an varying number of text-only menu items and the page layout is fluid. # # The first menu item should be left-aligned, the last menu item should be right- # # aligned. The remaining items should be spread optimal on the menu bar. # # # # The number is varying,so there's no chance to pre-calculate the optimal widths. # # # # Note that a TABLE won't work here as well: # # - If you center all TDs, the first and the last item aren't aligned correctly. # # - If you left-align and right-align the first resp. the last items, the spacing # # will be sub-optimal. # Isn't it strange that there is no obvious way to implement this in a clean way by using HTML+CSS?

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  • MySQL, return only rows where there are duplicates among two columns.

    - by Richard Waite
    I have a table in MySQL of contact information ; first name, last name, address, etc. I would like to run a query on this table that will return only rows with first and last name combinations which appear in the table more than once. I do not want to group the "duplicates" (which may only be duplicates of the first and last name, but not other information like address or birthdate) - I want to return all the "duplicate" rows so I can look over the results and determine if they are dupes or not. This seemed like it would be a simple thing to do, but it has not been. Every solution I can find either groups the dupes and gives me a count only (which is not useful for what I need to do with the results) or doesn't work at all. Is this kind of logic even possible in a query ? Should I try and do this in Python or something?

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  • Navigation Bar color doesn't change back? iOS7

    - by TKP
    I have several tableviews with navigation controller. The navigation bar is white for all the views except the last one, which is red. I have [[[self navigationController] navigationBar] setTintColor:[UIColor redColor]; in the viewDidLoad of the last tableview and [[[self navigationController] navigationBar] setTintColor:[UIColor whiteColor]; in the viewDidLoad of other table views. It works fine until I get to the last view and the color of the navigation bar changes to red. When I go back to the previous views, all the previous views' navigation bar has changed to red. Where should I put those codes so the color will remain unchanged? Thanks,

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  • How to check whether iterators form a contiguous memory zone?

    - by Vincent
    I currently have the following function to read an array or a vector of raw data (_readStream is a std::ifstream) : template<typename IteratorType> inline bool MyClass::readRawData( const IteratorType& first, const IteratorType& last, typename std::iterator_traits<IteratorType>::iterator_category* = nullptr ) { _readStream.read(reinterpret_cast<char*>(&*first), (last-first)*sizeof(*first)); return _readStream.good(); } First question : does this function seem ok for you ? As we read directly a block of memory, it will only work if the memory block from first to last is contiguous in memory. How to check that ?

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  • pagination using php with mysql data

    - by pradeep
    i am trying to create a pagination in which there are 5 items at a time depending on the number of items in DB. i wrote this code . but i dono how to go further .its buggy..any better pagination or alteration for this <?php $myresult .= "<div class='pagination' >"; if ($pagenum == 1) { } else { $pagenum = 1; $myresult .= "<a href='javascript:newPage(\"".$pagenum."\")'>&nbsp;first&nbsp;</a>"; $myresult .= " "; $previous = $pagenum-1; $myresult .= "<a href='javascript:newPage(\"".$previous."\")'> &nbsp;Prev&nbsp;</a>"; if ($pagenum == $last) { $previous3 = $pagenum-4; $myresult .= "<a href='javascript:newPage(\"".$previous3."\")'> &nbsp; $previous3 &nbsp;</a>"; $previous2 = $pagenum-3; $myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>"; } if ($pagenum > 2) { $previous1 = $pagenum-2; $myresult .= "<a href='javascript:newPage(\"".$previous1."\")'> &nbsp; $previous1 &nbsp;</a>"; } if ($pagenum > 1) { $previous2 = $pagenum-1; $myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>"; $myresult .= " "; } } $myresult .= "<span class=\"disabled\"> $pagenum </span>"; if ($pagenum == $last) { } else { if($pagenum < $last - 1) { $next = $pagenum+1; $myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp; $next &nbsp;</a>"; } if($pagenum < $last - 2) { $next1 = $pagenum+2; $myresult .= "<a href='javascript:newPage(\"".$next1."\")'> &nbsp; $next1 &nbsp;</a>"; } if($pagenum == 1 ) { $next2 = $pagenum+3; $myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>"; $next3 = $pagenum+4; $myresult .= "<a href='javascript:newPage(\"".$next3."\")'> &nbsp; $next3 &nbsp;</a>"; } if($pagenum == 2 ) { $next2 = $pagenum+3; $myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>"; } $next = $pagenum+1; $myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp;Next&nbsp;</a>"; $myresult .= "<a href='javascript:newPage(\"".$last."\")'>&nbsp;Last</a>"; } $myresult .= "</div>"; $myresult .= "</br>"; ?>

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  • Importing data from a text file using python

    - by Will
    I have a text file containing data in rows and columns (~17000 rows in total). Each column is a uniform number of characters long, with the 'unused' characters filled in by spaces. For example, the first column is 11 characters long, but the last four characters in that column are always spaces (so that it appears to be a nice column when viewed with a text editor). Sometimes it's more than four if the entry is less than 7 characters. The columns are not otherwise separated by commas, tabs, or spaces. They are also not all the same number of characters (the first two are 11, the next two are 8 and the last one is 5 - but again, some are spaces). What I want to do is import the entires (which are numbers) in the last two columns if the second column contains the string 'OW' somewhere in it. Any help would be greatly appreciated.

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  • deleting unaccessed files using python

    - by damon
    My django app parses some files uploaded by the user.It is possible that the file uploaded by the user may remain in the server for a long time ,without it being parsed by the app.This can increase in size if a lot of users upload a lot of files. I need to delete those files not recently parsed by the app -say not accessed for last 24 hours.I tried like this import os import time dirname = MEDIA_ROOT+my_folder filenames = os.listdir(dirname) filenames = [os.path.join(dirname,filename) for filename in filenames] for filename in filenames: last_access = os.stat(filename).st_atime #secs since epoch rtime = time.asctime(time.localtime(last_access)) print filename+'----'+rtime This shows the last accessed times for each file..But I am not sure how I can test if the file access time was within the last 24 hours..Can somebody help me out?

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  • HABTM checking for match of latest 3

    - by user333614
    Here's an interesting one for you folks... I have a HABTM (has_and_belongs_to_many) relationship between "Dogs" and "Trips". My goal is to find two result sets: 1) Dogs that have been on at least 1 of the last 3 trips and call that @dogs_current 2) Dogs that have NOT been on any of the last 3 trips and call that @dogs_old I found that I can find what the last 3 trips are by doing this in the Trip model: named_scope :last3, :order => 'date DESC', :limit => 3 But not sure how to use that list get 1 and 2. This hack works, but it seems ugly. There must be a better way! :) @dogs_current = [] @dogs_old = [] @dogs.each do |dog| if (Trip.last3 - dog.trips).size < 3 then @dogs_current << dog else @dogs_old << dog end end Any ideas? Thanks! -Cam

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  • regex no character

    - by iamnotmad
    In this text: warning here there are several types of warnings in this string warning.gif at the end warning end of line warning I want to match every warning except warning.gif. I cannot seem to get it to include the last one that has no character (control or otherwise) after it. using warnings?[^\.] gets what I want except for the last warning (on the last line). I think because there is no character at all after. How can I get it to include that one?

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  • taking and holding input

    - by gcc
    i tried to take input from user input like that input:: first line:>>name(white space)last name second line:>>identification number(white space)birtdate(,,:,,:) third line:>>lesson which he take (ce140 ce213 ce383...) last line:>>note he take(80 60 ......) this input type for each student i tried to hold this input in struct like struct name is first line { second line third line last line } my testing scanf("%[^\n]\n); take input hold in string scanf("%s",...secondline_name); storing in secondline_name . . . but this doesnot work are there any other way to hold input

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  • programming help

    - by user208639
    class Person holds personal data Its constructor receives 3 parameters, two Strings representing first and last names and an int representing age public Person(String firstName, String lastName, int age) { its method getName has no parameters and returns a String with format "Lastname, Firstname" its method getAge takes no parameters and returns an int representing the current age its method birthday increases age value by 1 and returns the new age value Create the class Person and paste the whole class into the textbox below public class Person { public Person(String first, String last, int age) { getName = "Lastname, Firstname"; System.out.print(last + first); getAge = age + 1; return getAge; System.out.print(getAge); birthday = age + 1; newAge = birthday; return newAge; } } im getting errors such as "cannot find symbol - variable getName" but when i declare a variable it still not working, i also wanted to ask if i am heading in the right direction or is it all totally wrong? im using a program called BlueJ to work on.

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  • How to know whether to create a general system or to hack a solution

    - by Andy K
    I'm new to coding , learning it since last year actually. One of my worst habits is the following: Often I'm trying to create a solution that is too big , too complex and doesn't achieve what needs to be achieved, when a hacky kludge can make the fit. One last example was the following (see paste bin link below) http://pastebin.com/WzR3zsLn After explaining my issue, one nice person at stackoverflow came with this solution instead http://stackoverflow.com/questions/25304170/update-a-field-by-removing-quarter-or-removing-month When should I keep my code simple and when should I create a 'big', general solution? I feel stupid sometimes for building something so big, so awkward, just to solve a simple problem. It did not occur to me that there would be an easier solution. Any tips are welcomed. Best

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  • Forbes Announcing The World’s Top 20 Billionaires

    - by Suganya
    Forbes company recently conducted a survey to figure out the world’s Billionaires list and has released it listing the top 20 names of the Billionaires. The company says that for the third time in the last three years the world has a new richest man for this year. So it means that Bill Gates was beaten up by someone else in world. Who is the new richest man in the world?   Forbes.Com announced the richest man in world and this time it is not Bill Gates. But it is Carlos Slim Helu who is into Telecom industry. Carlos lives in Mexico and he had the third richest man’s place last year. Having shown a Net worth of $ 53.5 Billion, Carlos has increased $18.5 Billion in a year. Carlos swooped on the privatization of Mexico’s national telephone service during the last decade and now has achieved the world’s first richest man. Following Carlos, in the second position is Bill Gates with the Nett worth of $53 Billion. As Bill Gates requires no great introduction, lets move on to the next place. The third place is occupied by Warren Buffett followed by Mukesh Ambani and Lakshmi Mittal in fourth and fifth places respectively. The top 20 names of world’s richest people, their occupation and the Nett worth that they hold are S.No Name Nett Worth (in $ Billion) Source of Income 1 Carlos Slim Helu 53.5 Telecom 2 Bill Gates 53 Microsoft 3 Warren Buffett 47 Investments 4 Mukesh Ambani 29 Petrochemical, Oil and Gas 5 Lakshmi Mittal 28.7 Steel 6 Lawrence Ellison 28 Oracle 7 Bernard Arnault 27.5 Luxury Goods 8 Eike Batista 27 Mining, Oil 9 Amancio Ortega 25 Fashion, Retail 10 Karl Albrecht 23.5 Supermarkets 11 Ingvar Kamprad and Family 23 IKEA 12 Christy Walton and Family 22.5 Wal-Mart 13 Stefan Persson 22.4 H & M 14 Li Ka-shing 21 Diversified 15 Jim C. Walton 20.7 Wal-Mart 16 Alice Walton 20.6 Wal-Mart 17 Liliane Bettencourt 20 L’Oreal 18 S. Robson Walton 19.8 Wal-Mart 19 Prince Alwaleed bin Talal Alsaud 19.4 Diversified 20 David Thomson and Family 19 Thomson Reuters   Source: Forbes and Image Credit : kevindooley Join us on Facebook to read all our stories right inside your Facebook news feed.

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