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  • ruby number to human-readable string conversion

    - by yaya3
    I need to have a list with id's for each list item being #one, #two etc. Is this the most efficient way or am I missing an in built ruby function here? -num_array = ["one", "two", "three", "four", "five", "six", "seven"] -navigation[:primary_level].each_with_index do |primary_item, idx| %li{ :id => "#{num_array[idx]}"}

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  • Having a number in

    - by Wiika
    Can someone give me a query that will return as a result rows ID 1 & 3? ID Name Hidden 1 Mika 1,4,2 2 Loca 0 3 Nosta 4 4 Like 2 Something like this SELECT * FROM table WHERE Hidden HAVING(4)

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  • how to number t-rows ,when table generated using nested forloop in django templates

    - by stackover
    Hi, This part is from views.py results=[(A,[stuObj1,stuObj2,stuObj3]),(B,[stuObj4,stuObj5,stuObj6]),(C,[stuObj7,stuObj8])] for tup in results: total = tot+len(tup[1]) render_to_response(url,{'results':res , 'total':str(tot),}) this is template code: <th class="name">Name</th> <th class="id">Student ID</th> <th class="grade">Grade</th> {% for tup in results %} {% for student in tup|last %} {% with forloop.parentloop.counter as parentid%} {% with forloop.counter as centerid%} <tbody class="results-body"> <tr> <td>{{student.fname|lower|capfirst}} {{student.lname|lower|capfirst}}</td> <td>{{student.id}}</td> <td>{{tup|first}}</td> </tr> {% endfor %} {% endfor %} Now the problems am having are 1. numbering the rows. Here my problem is am not sure if i can do things like total=total-1 in the templates to get the numbered rows like <td>{{total}}</td> 2.applying css to tr:ever or odd. Whats happening in this case is everytime the loop is running the odd/even ordering is lost. these seems related problems. Any ideas would be great :)

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  • Take the intersection of an arbitrary number of lists in python

    - by thepandaatemyface
    Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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  • java.sql.SQLException: Parameter index out of range (3 > number of parameters, which is 2)

    - by sam
    @WebMethod(operationName = "SearchOR") public SearchOR getSearchOR (@WebParam(name = "comp") String comp, @WebParam(name = "name") String name) { //TODO write your implementation code here: SearchOR ack = null; try{ String simpleProc = "{ call getuser_info_or(?,?)}"; CallableStatement cs = con.prepareCall(simpleProc); cs.setString(1, comp); cs.setString(2, name); ResultSet rs = cs.executeQuery(); System.out.print("2"); /* int i = 0, j = 0; if (rs.last()) { i = rs.getRow(); ack = new SearchOR[i]; rs.beforeFirst(); }*/ while (rs.next()) { // ack[j] = new SearchOR(rs.getString(1), rs.getString(2)); // j++; ve.add(rs.getString(1)); ve.add(rs.getString(2)); }}catch ( Exception e) { e.printStackTrace(); System.out.print(e); } return ack; } I am getting error at portion i have made bold.It is pointing to that location.My Query is here: DELIMITER $$ DROP PROCEDURE IF EXISTS discoverdb.getuser_info_or$$ MySQL returned an empty result set (i.e. zero rows). CREATE PROCEDURE discoverdb.getuser_info_or ( IN comp VARCHAR(100), IN name VARCHAR(100), OUT Login VARCHAR(100), OUT email VARCHAR(100) ) BEGIN SELECT sLogin, sEmail INTO Login, email FROM ad_user WHERE company = comp OR sName=name; END $$ MySQL returned an empty result set (i.e. zero rows). DELIMITER ;

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  • Auto generate varchar Ticket number via DB...

    - by Rusty
    Hello, I'm looking for suggestion on how to get the DB to auto generate Ticket numbers (preferably via the SQL DB) for a varchar column. I have the following tables in the DB: Activities & Cases and would prefer the format to be "Act000001" or "Cse000001". This would be something similar to the identity column property. Any suggestion would be highly appreciated. Thanks. Rusty

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  • How to catch specific exception without error number?

    - by CJ7
    I need to catch the following specific exception: System.Data.OleDb.OleDbException was caught ErrorCode=-2147467259 Message="The changes you requested to the table were not successful because they would create duplicate values in the index, primary key, or relationship. Change the data in the field or fields that contain duplicate data, remove the index, or redefine the index to permit duplicate entries and try again." Source="Microsoft JET Database Engine" I'm not sure what ErrorCode is but it looks unreliable. Can I rely on Message being identical across platforms? Is the only solution to do a text search of Message for words like duplicate and primary key? Note: see my question here for why I need to catch this exception.

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  • Limit Annotation number in Mapkit

    - by teddafan
    Hi all, I want to stop my app from loading more annotations after they are all added ( they are added by the user one by one). How would you do that? the following code is what i think is important (void) loadAndSortPOIs { [poiArray release]; nextPoiIndex = 0; NSString *poiPath = [[NSBundle mainBundle] pathForResource:@"pois" ofType:@"plist"]; poiArray = [[NSMutableArray alloc] initWithContentsOfFile:poiPath]; CLLocation *homeLocation = [[CLLocation alloc] initWithLatitude:homeCoordinate.latitude longitude:homeCoordinate.longitude]; for (int i = 0; i < [poiArray count]; i++) { NSDictionary *dict = (NSDictionary*) [poiArray objectAtIndex: i]; CLLocationDegrees storeLatitude = [[dict objectForKey:@"workingCoordinate.latitude"] doubleValue]; CLLocationDegrees storeLongitude = [[dict objectForKey:@"workingCoordinate.longitude"] doubleValue]; CLLocation *storeLocation = [[CLLocation alloc] initWithLatitude:storeLatitude longitude:storeLongitude]; CLLocationDistance distanceFromHome = [storeLocation getDistanceFrom: homeLocation]; NSMutableDictionary *mutableDict = [[NSMutableDictionary alloc] initWithDictionary:dict]; [mutableDict setValue:[NSNumber numberWithDouble:distanceFromHome] forKey:@"distanceFromHome"]; [poiArray replaceObjectAtIndex:i withObject:mutableDict]; [mutableDict release]; } [homeLocation release]; // now sort by distanceFromHome NSArray *sortDescriptors = [NSArray arrayWithObject: [[NSSortDescriptor alloc] initWithKey: @"distanceFromHome" ascending: YES]]; [poiArray sortUsingDescriptors:sortDescriptors]; NSLog (@"poiArray: %@", poiArray); } Thank you for your help. Best regards,

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  • Internet Explorer not incrementing number for non-sibling <li> elements

    - by biagidp
    I've got some html that looks like this: <ol> <div> <li>one</li> </div> <div> <li>two</li> </div> <div> <li>three</li> </div> </ol> Which looks like this in Chrome/Firefox: 1. one 2. two 3. three But looks like this in IE: 1. one 1. two 1. three If I change the code so that the li element is the parent of the div element instead of the other way around (so that all the li elements are siblings) IE renders it correctly. Anyone know what causes this or if this is the intended working behavior of IE? Furthermore is one way technically more correct than the other? <div><li></li></div> VS. <li><div></div></li> Thanks, David

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  • PHP and MS Access: Number of Records returned by SELECT query

    - by VarunGupta
    I am running following PHP code to interact with a MS Access database. $odbc_con = new COM("ADODB.Connection"); $constr = "DRIVER={Microsoft Access Driver (*.mdb)}; DBQ=" . $db_path . ";"; $odbc_con -> open($constr); $rs_select = $odbc_con -> execute ("SELECT * FROM Main"); Using ($rs_select - RecordCount) gives -1 though the query is returning non-zero records. (a) What can be the reason? (b) Is there any way out? I have also tried using count($rs_select -> GetRows()). This satisfies the need but looks inefficient as it will involve copying of all the records into an array first.

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  • C# : Number Conversion Problem

    - by Sayem Ahmed
    Today I faced a strange problem in C#. I have an ASP.NET page where user can enter certain price, quantity etc. I get the price value, convert it to double, then multiply it with 100 and then typecast it to an integer. When the price is "33.30", after converting it to double it remains 33.3 (obviously...), but after multiplying it with 100, it becomes 3329.9999999999995, and when I cast it to integer by applying simple cast operator "(int) (price * 100) ", it becomes 3329. Right now I have no idea why this is happening. So I thought may be you guys can help :) .

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  • How to use R-Tree for plotting large number of map markers on google maps

    - by Eeyore
    After searching SO and multiple articles I haven't found a solution to my problem. What I am trying to achieve is to load 20,000 markers on Google Maps. R-Tree seems like a good approach but it's only helpful when searching for points within the visible part of the map. When the map is zoomed out it will return all of the points and...crash the browser. There is also the problem with dragging the map and at the end of dragging re-running the query. I would like to know how I can use R-Tree and be able to achieve the all of the above.

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  • inserting large number of dates

    - by Radhe
    How can I insert all dates in an year(or more) in a table using sql My dates table has following structure dates(date1 date); Suppose I want to insert dates between "2009-01-01" to "2010-12-31" inclusive. Is there any sql query for the above?

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  • Objective-c Method to get a number then countdown in 1 every second

    - by Sami
    Hi, i need a little help i have a method which gets value such as 50, it then assigns that value to trackDuration, so NSNumber *trackDuration = 50, i want the method to every second minus 1 from the value of trackDuration and update a label, the label being called duration. Here's what i have so far; - (void) countDown { iTunesApplication *iTunes = [SBApplication applicationWithBundleIdentifier:@"com.apple.iTunes"]; NSNumber *trackDuration = [NSNumber numberWithDouble:[[iTunes currentTrack] duration]]; while (trackDuration > 0) { trackDuration - 1; int inputSeconds = [trackDuration intValue]; int hours = inputSeconds / 3600; int minutes = ( inputSeconds - hours * 3600 ) / 60; int seconds = inputSeconds - hours * 3600 - minutes * 60; NSString *trackDurationString = [NSString stringWithFormat:@"%.2d:%.2d:%.2d", hours, minutes, seconds]; [duration setStringValue:trackDurationString]; sleep(1); }} Any help would be much appreciated, thanks in advanced, Sami.

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  • Why is my number being rounded incorrectly?

    - by izb
    This feels like the kind of code that only fails in-situ, but I will attempt to adapt it into a code snippet that represents what I'm seeing. float f = myFloat * myConstInt; /* Where myFloat==13.45, and myConstInt==20 */ int i = (int)f; int i2 = (int)(myFloat * myConstInt); After stepping through the code, i==269, and i2==268. What's going on here to account for the difference?

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  • Rails - Format number as currency format in the Getter

    - by daemonsy
    I am making a simple retail commerce solution, where there are prices in a few different models. These prices contribute to a total price. Imagine paying $0.30 more for selecting a topping for your yogurt. When I set the price field to t.decimal :price, precision:8, scale:2 The database stores 6.50 as 6.5. I know in the standard rails way, you call number_to_currency(price) to get the formatted value in the Views. I need to programmatically call the price field as well formatted string, i.e. $6.50 a few places that are not directly part of the View. Also, my needs are simple (no currency conversion etc), I prefer to have the price formatted universally in the model without repeated calling number_to_currency in views. Is there a good way I can modify my getter for price such that it always returns two decimal place with a dollar sign, i.e. $6.50 when it's called? Thanks in advance.

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  • jQuery - After number of elements add html!

    - by Florescu Adrian
    Hello. I need to know if I can count the elements inside a div and after 3 elements to add an html object. <div id="wrapper"> <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here </div>

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