Search Results

Search found 8942 results on 358 pages for 'print r'.

Page 67/358 | < Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >

  • How to use traceit to report function input variables in stack trace

    - by reckoner
    Hi, I've been using the following code to trace the execution of my programs: import sys import linecache import random def traceit(frame, event, arg): if event == "line": lineno = frame.f_lineno filename = frame.f_globals["__file__"] if filename == "<stdin>": filename = "traceit.py" if (filename.endswith(".pyc") or filename.endswith(".pyo")): filename = filename[:-1] name = frame.f_globals["__name__"] line = linecache.getline(filename, lineno) print "%s:%s:%s: %s" % (name, lineno,frame.f_code.co_name , line.rstrip()) return traceit def main(): print "In main" for i in range(5): print i, random.randrange(0, 10) print "Done." sys.settrace(traceit) main() Using this code, or something like it, is it possible to report the values of certain function arguments? In other words, the above code tells me "which" functions were called and I would like to know "what" the corresponding values of the input variables for those function calls. Thanks in advance.

    Read the article

  • Crystal Reports, alignment when printing

    - by andySF
    Hello, i have a report with 2 objects. a text object from left to right and a database field on top of this object. When I load the report in viewer(or print from viewer) it looks OK but when I print the report programmatically with ReportDocument.PrintToPrinter() the database field moves to to the left and as a result it print on the text object. Concatenate the text and database field is not an option. The margins are the same in viewer and before to print programmatically. in viewer: http://promagic.hopto.org/screens/screen_2010-5-13_10_24_7-531.png programmatically: http://promagic.hopto.org/screens/screen_2010-5-13_10_25_55-187.png (the bold text is from db) Can anyone help me? Thanks!

    Read the article

  • combine lines from 2 prints to single line and insert into mysql database

    - by bleomycin
    Hello everyone i currently have this: import feedparser d = feedparser.parse('http://store.steampowered.com/feeds/news.xml') for i in range(10): print d.entries[i].title print d.entries[i].date How would i go about making it so that the title and date are on the same line? Also it doesn't need to print i just have that in there for testing, i would like to dump this output into a mysql db with the title and date, any help is greatly appreciated!

    Read the article

  • PHP - Nested Looping Trouble

    - by Jeremy A
    I have an HTML table that I need to populate with the values grabbed from a select statement. The table cols are populated by an array (0,1,2,3). Each of the results from the query will contain a row 'GATE' with a value of (0-3), but there will not be any predictability to those results. One query could pull 4 rows with 'GATE' values of 0,1,2,3, the next query could pull two rows with values of 1 & 2, or 1 & 3. I need to be able to populate this HTML table with values that correspond. So HTML COL 0 would have the TTL_NET_SALES of the db row which also has the GATE value of 0. <?php $gate = array(0,1,2,3); $gate_n = count($gate); /* Database = my_table.ID my_table.TT_NET_SALES my_table.GATE my_table.LOCKED */ $locked = "SELECT * FROM my_table WHERE locked = true"; $locked_n = count($locked); /* EXAMPLE RETURN Row 1: my_table['ID'] = 1 my_table['TTL_NET_SALES'] = 1000 my_table['GATE'] = 1; Row 2: my_table['ID'] = 2 my_table['TTL_NET_SALES'] = 1500 my_table['GATE'] = 3; */ print "<table border='1'>"; print "<tr><td>0</td><td>1</td><td>2</td><td>3</td>"; print "<tr>"; for ($i=0; $i<$locked_n; $i++) { for ($g=0; $g<$gate_n; $g++) { if (!is_null($locked['TTL_NET_SALES'][$i]) && $locked['GATE'][$i] == $gate[$g]) { print "<td>$".$locked['TTL_NET_SALES'][$i]."</td>"; } else { print "<td>-</td>"; } } } print "</tr>"; print "</table>"; /* What I want to see: <table border='1'> <tr> <td>0</td> <td>1</td> <td>2</td> <td>3</td> </tr> <tr> <td>-</td> <td>1000</td> <td>-</td> <td>1500</td> </tr> </table> */ ?>

    Read the article

  • Question about multiple 'catch'

    - by chun
    Can anyone tell me why the output of this class is 'xa'? why the other exception won't be caught? public class Tree { public static void main(String... args){ try { throw new NullPointerException(new Exception().toString()); } catch (NullPointerException e) { System.out.print("x"); } catch (RuntimeException e) { System.out.print("y"); } catch (Exception e) { System.out.print("z"); } finally{System.out.println("a");} } }

    Read the article

  • How to define and use a friend function to a temlate class with the same template?

    - by Narek
    I have written the following code: #include <iostream> using namespace std; template <class T> class AA { T a; public: AA() { a = 7; } friend void print(const AA<T> & z); }; template <class T> void print(const AA<T> & z) { cout<<"Print: "<<z.a<<endl; } void main() { AA<int> a; print<int>(a); } And getting the following error: error C2248: 'AA<T>::a' : cannot access private member declared in class 'AA<T>' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(7) : see declaration of 'AA<T>::a' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(30) : see reference to function template instantiation 'void print<int>(const AA<T> &)' being compiled 1> with 1> [ 1> T=int 1> ] What's wrong?

    Read the article

  • Why jquery have problem with onbeforeprint event?

    - by Cesar Lopez
    Hi all, I have the following function. $(function() { $(".sectionHeader:gt(0)").click(function() { $(this).next(".fieldset").slideToggle("fast"); }); $("img[alt='minimize']").click(function(e) { $(this).closest("table").next(".fieldset").slideUp("fast"); e.stopPropagation(); return false; }); $("img[alt='maximize']").click(function(e) { $(this).closest("table").next(".fieldset").slideDown("fast"); e.stopPropagation(); return false; }); }); <script type="text/javascript"> window.onbeforeprint = expandAll; function expandAll(){ $(".fieldset:gt(0)").slideDown("fast"); } </script> For this html <table class="sectionHeader" ><tr ><td>Heading 1</td></tr></table> <div style="display:none;" class="fieldset">Content 1</div> <table class="sectionHeader" ><tr ><td>Heading 2</td></tr></table> <div style="display:none;" class="fieldset">Content 2</div> I have several div class="fieldset" over the page, but when I do print preview or print, I can see all divs sliding down before opening the print preview or printing but on the actual print preview or print out they are all collapse. I would appreciate if anyone comes with a solution for this. Anyone have any idea why is this or how to fix it? Thanks. PS:Using a does not work either ( I assume because jquery using toggle) and its not the kind of question I am looking for.

    Read the article

  • Problem overridding virtual function

    - by William
    Okay, I'm writing a game that has a vector of a pairent class (enemy) that s going to be filled with children classes (goomba, koopa, boss1) and I need to make it so when I call update it calls the childclasses respective update. I have managed to create a example of my problem. #include <stdio.h> class A{ public: virtual void print(){printf("Hello from A");} }; class B : public A{ public: void print(){printf("Hello from B");} }; int main(){ A ab = B(); ab.print(); while(true){} } Output wanted: "Hello from B" Output got: "Hello from A" How do I get it to call B's print function?

    Read the article

  • list comprehension example

    - by self
    can we use elif in list comprehension? example : l = [1, 2, 3, 4, 5] for values in l: if values==1: print 'yes' elif values==2: print 'no' else: print 'idle' can we use list comprehension for such 2 if conditions and one else condition? foe example answer like : ['yes', 'no', 'idle', 'idle', 'idle'] I have done till now only if else in list comprehension.

    Read the article

  • Getting unhandled error and connection get lost when a client tries to communicate with chat server in twisted

    - by user2433888
    from twisted.internet.protocol import Protocol,Factory from twisted.internet import reactor class ChatServer(Protocol): def connectionMade(self): print "A Client Has Connected" self.factory.clients.append(self) print"clients are ",self.factory.clients self.transport.write('Hello,Welcome to the telnet chat to sign in type aim:YOUR NAME HERE to send a messsage type msg:YOURMESSAGE '+'\n') def connectionLost(self,reason): self.factory.clients.remove(self) self.transport.write('Somebody was disconnected from the server') def dataReceived(self,data): #print "data is",data a = data.split(':') if len(a) > 1: command = a[0] content = a[1] msg="" if command =="iam": self.name + "has joined" elif command == "msg": ma=sg = self.name + ":" +content print msg for c in self.factory.clients: c.message(msg) def message(self,message): self.transport.write(message + '\n') factory = Factory() factory.protocol = ChatServer factory.clients = [] reactor.listenTCP(80,factory) print "Iphone Chat server started" reactor.run() The above code is running succesfully...but when i connect the client (by typing telnet localhost 80) to this chatserver and try to write message ,connection gets lost and following errors occurs : Iphone Chat server started A Client Has Connected clients are [<__main__.ChatServer instance at 0x024AC0A8>] Unhandled Error Traceback (most recent call last): File "C:\Python27\lib\site-packages\twisted\python\log.py", line 84, in callWithLogger return callWithContext({"system": lp}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\log.py", line 69, in callWithContext return context.call({ILogContext: newCtx}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 118, in callWithContext return self.currentContext().callWithContext(ctx, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 81, in callWithContext return func(*args,**kw) --- --- File "C:\Python27\lib\site-packages\twisted\internet\selectreactor.py", line 150, in _doReadOrWrite why = getattr(selectable, method)() File "C:\Python27\lib\site-packages\twisted\internet\tcp.py", line 199, in doRead rval = self.protocol.dataReceived(data) File "D:\chatserverultimate.py", line 21, in dataReceived content = a[1] exceptions.IndexError: list index out of range Where am I going wrong?

    Read the article

  • perl : Passing hash , array through socket program betwen client and server

    - by pavun_cool
    Hi All . In sockets I have written the client server program . First I tried to send the normal string among them it sends fine . After that I am trying to send the hash and array values from client to server and server to client . When I printing the values using Dumper . It is giving me only reference . What Should I do for getting accessing the actual values in client server . Server Program: use IO::Socket; use strict; use warnings; my %hash = ( "name" => "pavunkumar " , "age" => 20 ) ; my $new = \%hash ; #Turn on System variable for Buffering output $| = 1; # Creating a a new socket my $socket= IO::Socket::INET->new(LocalPort=>5000,Proto=>'tcp',Localhost => 'localhost','Listen' => 5 , 'Reuse' => 1 ); die "could not create $! \n" unless ( $socket ); print "\nUDPServer Waiting port 5000\n"; my $new_sock = $socket->accept(); my $host = $new_sock->peerhost(); while(<$new_sock>) { #my $line = <$new_sock>; print Dumper "$host $_"; print $new_sock $new . "\n"; } print "$host is closed \n" ; Client Program use IO::Socket; use Data::Dumper ; use warnings ; use strict ; my %hash = ( "file" =>"log.txt" , size => "1000kb") ; my $ref = \%hash ; # This client for connecting the specified below address and port # INET function will create the socket file and establish the connection with # server my $port = shift || 5000 ; my $host = shift || 'localhost'; my $recv_data ; my $send_data; my $socket = new IO::Socket::INET ( PeerAddr => $host , PeerPort => $port , Proto => 'tcp', ) or die "Couldn't connect to Server\n"; while (1) { my $line = <stdin> ; print $socket $ref."\n"; if ( $line = <$socket> ) { print Dumper $line ; } else { print "Server is closed \n"; last ; } } I have given my sample program about what I am doing , Can any one tell me what I am doing wrong in this code. And what I need to do for accessing the hash values . Thanks in Advance

    Read the article

  • What's wrong with this statement in perl?

    - by benjamin button
    print "$_", join(',',sort keys %$h),"\n"; It's giving me an error below: Use of uninitialized value in string at missing_months.pl line 36. 1,10,11,12 this print statement is present in a for loop as below: foreach my $num ( sort keys %hash ) { my $h = $hash{$num}; print "$_", join(',',sort keys %$h),"\n"; }

    Read the article

  • Why can't I handle a KeyboardInterrupt in python?

    - by Josh
    I'm writing python 2.6.6 code on windows that looks like this: try: dostuff() except KeyboardInterrupt: print "Interrupted!" except: print "Some other exception?" finally: print "cleaning up...." print "done." dostuff() is a function that loops forever, reading a line at a time from an input stream and acting on it. I want to be able to stop it and clean up when I hit ctrl-c. What's happening instead is that the code under except KeyboardInterrupt: isn't running at all. The only thing that gets printed is "cleaning up...", and then a traceback is printed that looks like this: Traceback (most recent call last): File "filename.py", line 119, in <module> print 'cleaning up...' KeyboardInterrupt So, exception handling code is NOT running, and the traceback claims that a KeyboardInterrupt occurred during the finally clause, which doesn't make sense because hitting ctrl-c is what caused that part to run in the first place! Even the generic except: clause isn't running. EDIT: Based on the comments, I replaced the contents of the try: block with sys.stdin.read(). The problem still occurs exactly as described, with the first line of the finally: block running and then printing the same traceback.

    Read the article

  • Sending email in asp .net

    - by program-java
    hii every one, I m creating an project in which Admin is one user I want code or any idea how can Admin send a quotation of any type of products to his customer though email on their email ID and this quotation has to be a print option button bec. after clicking on print button quotation should be print How can i do it?

    Read the article

  • variable being weirdly deleted

    - by calccrypto
    im having a weird problem with one variable: its not being recognized but its still printing. i would post my code, but it is massive. the basic idea is: # pseudocode def function(stuff): <do stuff> # These are the only 2 conditions if tag == 3: pka = <a string> if tag == 4: pka = <a string> print pka # (1) print pka # (2) <do stuff not modifying pka> print pka # (3) if pka == 'RSA': <do stuff> elif pka == 'DSA': <do stuff> my code will error at (2). however, it will print out (1), (2), and (3), all of which are the same. is there any general explanation of why this is happening? if my code is really needed, i will post it, but otherwise, i would rather not due to its size update: now the code will error at the if statement after (3), saying UnboundLocalError: local variable 'pka' referenced before assignment even though (1),(2),(3) just printed

    Read the article

  • how to insert page view of a node in another page in drupal

    - by sprugman
    I have a list of node ids and I want to display the 'page' view of each one. For various reasons, I don't want to do this with views, and don't think I should need a module. Just an API call to theme('node'). Something like: $nids = array(3,4,5); foreach ($nids as $nid) { $node = node_load($nid); $result .= theme('node', $node); } but I'm not getting back the full page view of the node. I added this to my node-[type].tpl.php file: if ($page) print "PAGE MODE "; else print "NOT PAGE "; if ($teaser) print "TEASER MODE "; else print "NOT TEASER "; and got: NOT PAGE NOT TEASER I seem to be in some kind of limbo. I suspect there's an argument that I add to the theme function, but the terms are all so general (theme, teaser, page, node), I'm having trouble with my google-fu.

    Read the article

  • How can I find out the original username a process was started with?

    - by szabgab
    There is a perl script that needs to run as root but the we must make sure the user who runs the script did not log-in originally as user foo as it will be removed during the script. So how can I find out if the user, who might have su-ed several times since she logged in has not impersonated 'foo' at any time in that chain? I found an interesting perl script that was calling the following two shell scripts, but I think that would only work on Solaris. my $shell_paren = `ps -ef | grep -v grep | awk \'{print \$2\" \"\$3}\' | egrep \"^@_\" | awk \'{print \$2}'`; my $parent_owner = `ps -ef | grep -v grep | awk \'{print \$1\" \"\$2}\' | grep @_ | awk \'{print \$1}\'`; This needs to work on both Linux and Solaris and I'd rather eliminate the repeated calls to he the shell and keep the whole thing in Perl.

    Read the article

  • Unable to plot graph using matplotlib

    - by Aman Deep Gautam
    I have the following code which searches all the directory in the current directory and then takes data from those files to plot the graph. The data is read correctly as verified by printing but there are no points plotted on graph. import argparse import os import matplotlib.pyplot as plt #find the present working directory pwd=os.path.dirname(os.path.abspath(__file__)) #find all the folders in the present working directory. dirs = [f for f in os.listdir('.') if os.path.isdir(f)] plt.figure() plt.xlim(0, 20000) plt.ylim(0, 1) for directory in dirs: os.chdir(os.path.join(pwd, directory)); chd_dir = os.path.dirname(os.path.abspath(__file__)) files = [ fl for fl in os.listdir('.') if os.path.isfile(fl) ] print files for f in files: f_obj = open(os.path.join(chd_dir, f), 'r') list_x = [] list_y = [] for i in xrange(0,4): f_obj.next() for line in f_obj: temp_list = line.split() print temp_list list_y.append(temp_list[0]) list_x.append(temp_list[1]) print 'final_lsit' print list_x print list_y plt.plot(list_x, list_y, 'r.') f_obj.close() os.chdir(pwd) plt.savefig("test.jpg") The input files look like the following: 5 865 14709 15573 14709 1.32667e-06 664 0.815601 14719 1.55333e-06 674 0.813277 14729 1.82667e-06 684 0.810185 14739 1.4e-06 694 0.808459 Can anybody help me with why this is happening? Being new I would like to know some tutorial where I can get help with kind of plotting as the tutorial I was following made me end up here. Any help appreciated.

    Read the article

  • create a class attribute without going through __setattr__

    - by eric.frederich
    Hello, What I have below is a class I made to easily store a bunch of data as attributes. They wind up getting stored in a dictionary. I override __getattr__ and __setattr__ to store and retrieve the values back in different types of units. When I started overriding __setattr__ I was having trouble creating that initial dicionary in the 2nd line of __init__ like so... super(MyDataFile, self).__setattr__('_data', {}) My question... Is there an easier way to create a class level attribute with going through __setattr__? Also, should I be concerned about keeping a separate dictionary or should I just store everything in self.__dict__? #!/usr/bin/env python from unitconverter import convert import re special_attribute_re = re.compile(r'(.+)__(.+)') class MyDataFile(object): def __init__(self, *args, **kwargs): super(MyDataFile, self).__init__(*args, **kwargs) super(MyDataFile, self).__setattr__('_data', {}) # # For attribute type access # def __setattr__(self, name, value): self._data[name] = value def __getattr__(self, name): if name in self._data: return self._data[name] match = special_attribute_re.match(name) if match: varname, units = match.groups() if varname in self._data: return self.getvaras(varname, units) raise AttributeError # # other methods # def getvaras(self, name, units): from_val, from_units = self._data[name] if from_units == units: return from_val return convert(from_val, from_units, units), units def __str__(self): return str(self._data) d = MyDataFile() print d # set like a dictionary or an attribute d.XYZ = 12.34, 'in' d.ABC = 76.54, 'ft' # get it back like a dictionary or an attribute print d.XYZ print d.ABC # get conversions using getvaras or using a specially formed attribute print d.getvaras('ABC', 'cm') print d.XYZ__mm

    Read the article

  • R matrix handling expressions aren't evaluated in a function or a "for" loop - Column extract doesn't seem to work

    - by Sal Leggio
    I have an R matrix named ddd. When I enter this, everything works fine: i <- 1 shapiro.test(ddd[,y]) ad.test(ddd[,y]) stem(ddd[,y]) print(y) The calls to Shapiro Wilk, Anderson Darling, and stem all work, and extract the same column. If I put this code in a "for" loop, the calls to Shapiro Wilk, and Anderson Darling stop working, while the the stem & leaf call and the print call continue to work. for (y in 7:10) { shapiro.test(ddd[,y]) ad.test(ddd[,y]) stem(ddd[,y]) print(y) } The decimal point is 1 digit(s) to the right of the | 0 | 0 0 | 899999 1 | 0 [1] 7 The same thing happens if I try and write a function. SW & AD do not work. The other calls do. D <- function (y) { + shapiro.test(ddd[,y]) + ad.test(ddd[,y]) + stem(ddd[,y]) + print(y) } D(9) The decimal point is at the | 9 | 000 9 | 10 | 00000 [1] 9 Why don't all the calls behave the same way?

    Read the article

  • Explanation of output

    - by Anon
    My program class Building { Building() { System.out.print("b "); } Building(String name) { this(); System.out.print("bn " + name); } }; public class House extends Building { House() { System.out.print("h "); // this is line# 1 } House(String name) { this(); // This is line#2 System.out.print("hn " + name); } public static void main(String[] args) { new House("x "); } } We know that compiler will write a call to super() as the first line in the child class's constructor. Therefore should not the output be: b (call from compiler written call to super(), before line#2 b (again from compiler written call to super(),before line#1 ) h hn x But the output is b h hn x Why is that?

    Read the article

  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

    Read the article

  • issue running a batch script to kill a process

    - by user657064
    I am using the following script on a command line to kill a hypothetical notepad process (using a Korn shell in Windows XP, if that matters): kill $(tasklist | grep -i notepad.exe | awk '{print 2}') Now I take this line, and put it into a batch file c:\temp\testkill.bat, thinking that I should just as well be able to kill the process by running the batch file. However, when I run the batch file, I get the following awk error about unbalanced parentheses: C:/Temp ./testkill.bat C:\Tempkill $(tasklist | grep -i notepad.exe | awk '{print $2}') awk: unbalanced () Context is: {print $2}) <<< C:/Temp So I'm baffled as to why I am getting this error about unbalanced parentheses when I run this script via a batch file, but have no issues when I run the command directly from the command line? (Btw, I'm not necessarily tied to this way of killing a process - as a total noob to shell scripting, I am additionally wondering why if I write the following on the command line: tasklist | grep -i notepad.exe | awk '{print $2}' | kill the process ID that comes out of the tasklist/grep/awk calls doesn't seem to properly get piped to kill...)

    Read the article

  • It says i have an indented block when i dont?

    - by user3728373
    def cave(): global key global response print(''' You find yourself standing infront of a cave. You venture into the cave to find a large door blocking your path. (insert key, turn around''') response = input("Enter a command: ") while response != 'insert key' or response != 'turn around': if response =='insert key' or response == 'turn around': break print('Choose one of the options: ") response = input() if response == 'insert key': if key == 1: win() else: print('''You don't have a key. Get One!!''') elif response == 'turn around' : home()

    Read the article

  • python - returns incorrect positive #

    - by tekknolagi
    what i'm trying to do is write a quadratic equation solver but when the solution should be -1, as in quadratic(2, 4, 2) it returns 1 what am i doing wrong? #!/usr/bin/python import math def quadratic(a, b, c): #a = raw_input("What\'s your `a` value?\t") #b = raw_input("What\'s your `b` value?\t") #c = raw_input("What\'s your `c` value?\t") a, b, c = float(a), float(b), float(c) disc = (b*b)-(4*a*c) print "Discriminant is:\n" + str(disc) if disc = 0: root = math.sqrt(disc) top1 = b + root top2 = b - root sol1 = top1/(2*a) sol2 = top2/(2*a) if sol1 != sol2: print "Solution 1:\n" + str(sol1) + "\nSolution 2:\n" + str(sol2) if sol1 == sol2: print "One solution:\n" + str(sol1) else: print "No solution!" EDIT: it returns the following... import mathmodules mathmodules.quadratic(2, 4, 2) Discriminant is: 0.0 One solution: 1.0

    Read the article

< Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >