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• how find teh objects between two labels in clearcase

  - by cheia

  Hi , I would like to get all sources/objects between two releases that happened within a month from clear case.I wrote the below command and it displays only less number of sources compared to the actual one. Please advive where I am wrong Cleartool find < -element "lbtype (Label b) && ! lbtype(label a) && ! -element (.../Branch1/latest)" -print where label a is the label of last month release lable b is the current label and brach1 is the branch from where all release happened Thanks in advance

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• the callback sequence of viewDidAppear and viewDidDisappear between two view controllers

  - by olinYY

  As I know, there are at least two ways to present a UIViewController on another UIViewController, first is using presentModalViewController:animated: on UIViewController, another is using pushViewController:animated: on UINavigationController, it seems when 2 view controller changing their appearance, the invoke sequence of appear/disappear callbacks are different. Following is an example, A is a UINavigationController, and B is a normal view controller, the actual callback sequence are: (1) A using presentModalViewController:animated: to show B: [B viewWillAppear]; [A viewWillDisappear]; [B viewDidAppear]; [A viewDidDisappear]; (2) A using pushViewController:animated: to show B: [A viewWillDisappear]; [B viewWillAppear]; [A viewDidDisappear]; [B viewDidAppear]; So my question is that, are these different callback sequence stable, or there are no definite sequence we can rely on? If they are stable, is there any document mentions this behavior? Can anyone help? Thanks in advanced!

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• Popuplating an NSPopupButton with the contents of two NSArrayControllers

  - by ndg

  I'm looking to populate an NSPopupButton with the contents of two NSArrayControllers. The NSArrayControllers are both bound to my Core Data Managed Object Context and represent separate entities (in this example: Person and Department). Within my NSPopupButton, I would like a list of departments, and the people that work under them. Like so: Department 1 Person 1 Person 2 Department 2 Person 3 Person 4 All departments would need to be disabled by default, meaning that users should only be able to select people listed within the dropdown. I'm lost as to how I would go about doing something like this. The concept of manually populating an NSPopupButton seems fairly trivial, but I'm a bit shaky as to best to populate the element with Core Data objects. Essentially, I'm just looking for someone to point me in the right direction. I imagine there's a right way to do this, and a number of very wrong ways.

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• SELECT subset from two tables and LEFT JOIN results

  - by Doctor Trout

  Hi all, I'm trying to write a bit of SQL for SQLITE that will take a subset from two tables (TableA and TableB) and then perform a LEFT JOIN. This is what I've tried, but this produces the wrong result: Select * from TableA Left Join TableB using(key) where TableA.key2 = "xxxx" AND TableB.key3 = "yyyy" This ignore cases where key2="xxxx" but key3 != "yyyy". I want all the rows from TableA that match my criteria whether or not their corresponding value in TableB matches, but only those rows from TableB that match both conditions. I did manage to solve this by using a VIEW, but I'm sure there must be a better way of doing this. It's just beginning to drive me insane tryng to solve it now. (Thanks for any help, hope I've explained this well enough).

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• Writing in two sessions from the same file (PHP)

  - by bellesebastien

  Hi, I want to make it possible for the administrator to log in as a fontend user from the backend. Right now I'm using two sessions (sessions with different names), one for the admin and one for the frontend. Is it possible to write in the first session, close it and then open a new session? This is a simplified version of what I attempted but failed: session_name('admin_session'); session_start(); // use first session without generatring any output session_close(); session_name('frontend_session'); session_start(); // use the second session Thanks.

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• Problem creating calculations 'engine' in two class java calculator

  - by tokee

  i have hit a brick wall whilst attempting to create a two class java calculator but have been unsuccessful so far in getting it working. i have the code for an interface which works and displays ok but creating a seperate class 'CalcEngine' to do the actual calculations has proven to be beyond me. I'd appreciate it if someone could kick start things for me and create a class calcEngine which works with the interface class and allows input when from single button i.e. if one is pressed on the calc then 1 displays onscreen. please note i'm not asking someone to do the whole thing for me as i want to learn and i'm confident i can do the rest including addition subtraction etc. once i get over the obstacle of getting the two classes to communicate. any and all assistance would be very much appreciated. Please see the calcInterface class code below - import java.awt.*; import javax.swing.*; import javax.swing.border.*; import java.awt.event.*; /** *A Class that operates as the framework for a calculator. *No calculations are performed in this section */ public class CalcFrame implements ActionListener { private CalcEngine calc; private JFrame frame; private JTextField display; private JLabel status; /** * Constructor for objects of class GridLayoutExample */ public CalcFrame() { makeFrame(); //calc = engine; } /** * This allows you to quit the calculator. */ // Alows the class to quit. private void quit() { System.exit(0); } // Calls the dialog frame with the information about the project. private void showAbout() { JOptionPane.showMessageDialog(frame, "Group Project", "About Calculator Group Project", JOptionPane.INFORMATION_MESSAGE); } private void makeFrame() { frame = new JFrame("Group Project Calculator"); makeMenuBar(frame); JPanel contentPane = (JPanel)frame.getContentPane(); contentPane.setLayout(new BorderLayout(8, 8)); contentPane.setBorder(new EmptyBorder( 10, 10, 10, 10)); /** * Insert a text field */ display = new JTextField(); contentPane.add(display, BorderLayout.NORTH); //Container contentPane = frame.getContentPane(); contentPane.setLayout(new GridLayout(4, 4)); JPanel buttonPanel = new JPanel(new GridLayout(4, 4)); contentPane.add(new JButton("1")); contentPane.add(new JButton("2")); contentPane.add(new JButton("3")); contentPane.add(new JButton("4")); contentPane.add(new JButton("5")); contentPane.add(new JButton("6")); contentPane.add(new JButton("7")); contentPane.add(new JButton("8")); contentPane.add(new JButton("9")); contentPane.add(new JButton("0")); contentPane.add(new JButton("+")); contentPane.add(new JButton("-")); contentPane.add(new JButton("/")); contentPane.add(new JButton("*")); contentPane.add(new JButton("=")); contentPane.add(new JButton("C")); contentPane.add(buttonPanel, BorderLayout.CENTER); //status = new JLabel(calc.getAuthor()); //contentPane.add(status, BorderLayout.SOUTH); frame.pack(); frame.setVisible(true); } /** * Create the main frame's menu bar. * The frame that the menu bar should be added to. */ private void makeMenuBar(JFrame frame) { final int SHORTCUT_MASK = Toolkit.getDefaultToolkit().getMenuShortcutKeyMask(); JMenuBar menubar = new JMenuBar(); frame.setJMenuBar(menubar); JMenu menu; JMenuItem item; // create the File menu menu = new JMenu("File"); menubar.add(menu); // create the Quit menu with a shortcut "Q" key. item = new JMenuItem("Quit"); item.setAccelerator(KeyStroke.getKeyStroke(KeyEvent.VK_Q, SHORTCUT_MASK)); item.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { quit(); } }); menu.add(item); // Adds an about menu. menu = new JMenu("About"); menubar.add(menu); // Displays item = new JMenuItem("Calculator Project"); item.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { showAbout(); } }); menu.add(item); } /** * An interface action has been performed. * Find out what it was and handle it. * @param event The event that has occured. */ public void actionPerformed(ActionEvent event) { String command = event.getActionCommand(); if(command.equals("0") || command.equals("1") || command.equals("2") || command.equals("3") || command.equals("4") || command.equals("5") || command.equals("6") || command.equals("7") || command.equals("8") || command.equals("9")) { int number = Integer.parseInt(command); calc.numberPressed(number); } else if(command.equals("+")) { calc.plus(); } else if(command.equals("-")) { calc.minus(); } else if(command.equals("=")) { calc.equals(); } else if(command.equals("C")) { calc.clear(); } else if(command.equals("?")) { } // else unknown command. redisplay(); } /** * Update the interface display to show the current value of the * calculator. */ private void redisplay() { display.setText("" + calc.getDisplayValue()); } /** * Toggle the info display in the calculator's status area between the * author and version information. */ }

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• How to diff two regions of the same file in Eclipse

  - by Thomas Nilsson

  I'm a TDDer and often have a need to refactor out common or similar code. If it is exactly the same there is no big problem, Eclipse can almost always do that by itself. But to get there I'm finding myself often looking at similar, but not identical, code fragments in the same, or even different, files. It would be very handy if there was a possibility to mark two regions and get Eclipse (or some other tool) to mark the differences. With this information it would be much simpler to iteratively move the regions closer until they are the same and then activate the Extract Method refactoring. It can be done in Emacs of course, but I'd like to have this readily available from Eclipse. Any pointers?

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• django + xmppy: send a message to two recipients

  - by Agrajag

  I'm trying to use xmpppy for sending jabber-messages from a django-website. This works entirely fine. However, the message only gets sent to the -first- of the recipients in the list. This happens when I run the following function from django, and also if I run it from an interactive python-shell. The weird part though, is that if I extract the -body- of the function and run that interactively, then all the recipients (there's just 2 at the moment) get the message. Also, I do know that the inner for-loop gets run the correct count times (2), because the print-statement does run twice, and return two different message-ids. The function looks like this: def hello_jabber(request, text): jid=xmpp.protocol.JID(settings.JABBER_ID) cl=xmpp.Client(jid.getDomain(),debug=[]) con=cl.connect() auth=cl.auth(jid.getNode(),settings.JABBER_PW,resource=jid.getResource()) for friend in settings.JABBER_FRIENDS: id=cl.send(xmpp.protocol.Message(friend,friend + ' is awesome:' + text)) print 'sent message with id ' + str(id) cl.disconnect() return render_to_response('jabber/sent.htm', locals())

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• Transform Two Lists into One Different List

  - by Ngu Soon Hui

  I have two lists of double List<double> X List<double> Y And I have a destination object: public class PointD { public double X {get;set;} public double Y {get;set;} } How to transform them into a single list? public static List<PointD> Transform(List<double> X, List<double> Y) { } All the errors checking must be there.

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• Inverse relationship of two variables

  - by Jam

  this one is maybe pretty stupid.. Or I am just exhausted or something, but I just cant seem to solve it.. Problem : two variables X and Y, value of Y is dependent on value of X. X can have values ranging from some value to some value (lets say from 0 to 250) and y can have different values (lets say from 0.1 to 1.0 or something..) - but it is inverse relatonship (what I mean is: if value of X is e.g. 250, then value of Y would be 0.1 and when X decreases up to 0, value of Y raises up to 1.0.. So how should I do it? lets say I have function: -- double computeValue (double X) { /computation/ return Y; } Also, is there some easy way to somehow make the scaling of the function not so linear? - For example when X raises, Y decreases slower at first but then more rapidly in the end.. (rly dont know how to say it but I hope you guys got it) Thanks in advance for this stupid question :/

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• How to create relationship between two tables with revisions using Entity Framework

  - by Chris Ridenour

  So I am in the process of redesigning a small database (and potentially a much larger one) but want to show the value of using revisions / history of the business objects. I am switching the data from Access to MSSQL 2008. I am having a lot of internal debate on what version of "revision history" to use in the design itself - and thought I had decided to add a "RevisionId" to all tables. With this design - adding a RevisionId to all tables we would like tracked - what would be the best way to create Navigational Properties and Relationships between two tables such as | Vendor | VendorContact | where a Vendor can have multiple contacts. The Contacts themselves will be under revision. Will it require custom extensions or am I over thinking this? Thanks in advance.

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• Float over two elements

  - by eWolf

  My problem is rather complex to explain, so I'll show you an example: http://ewolf.bplaced.de/misc/float.htm I want to have a floated element (the blue box) to be be placed over two other elements (red and green) and I want the whole thing to be fixed-width and centered (done by the box with the black border) while the background of the red and green box should fill the whole width. I'm actually not quite sure if the way I've done it now is XHTML/CSS valid, but it works - at least in Firefox. In IE6, the green box expands to fit the whole blue box - how can I fix this in IE6 or find another solution to show it correctly in all browsers?

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• Combine two views into one view

  - by Kevin

  I have two views that I would like to combine into one. The first view shows all items of X where company ID = Y. This is to give preferential sort to the client first, and then everyone else. So I created a second view, all items of X, where company ID != Y. I created it as an Attachment to attach to the first view, but I don't think I got the intended result. How can I combine these views so the first view results are listed first, and then the second view is too, using the same pager, filters, and arguments? Is there any way of achieving this without programming it?

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• problem in counting two fields in one query

  - by Mac Taylor

  hey guys i need to count new private messages and old one from a table so first thing come to mind is using mysql_num_rows and easy thing to do // check new pms $user_id = $userinfo['user_id']; $sql = "SELECT author_id FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='1' OR pm_unread='1')"; $result = $db->sql_query($sql) ; $new_pms = $db->sql_numrows($result); $db->sql_freeresult($result); // check old pms $sql = "SELECT author_id FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='0' OR pm_unread='0')"; $result = $db->sql_query($sql) ; $old_pms = $db->sql_numrows($result); $db->sql_freeresult($result); but how can i count these two fields just in one statement and shorter lines ?~

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• Adding Street View controls (the two icons just above the +) to a Google Map (v3)

  - by AlexV

  It's probably something really simple, but I can't find it in the docs and I can't find a map with it to check it's source... I use version 3 of the API. I guess it's an something to add in myOptions? var latlng = new google.maps.LatLng(-34.397, 150.644); var myOptions = { zoom: 8, center: latlng, mapTypeId: google.maps.MapTypeId.ROADMAP } map = new google.maps.Map(document.getElementById('map_canvas'), myOptions); Currently I only have dragging controls and the zoom pane controls. I would like to have the two Street View controls icons too. If you want full source, I'm using this example as a base (how would you add Street View controls to this example?).

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• lambda expression for a query on two tables that returns records from one table

  - by peetee

  I have two tables TableA (articles) int id int Type string name and TableB (compatibles) int linked_ID int tableA_ID TableA records: id=1, Type=0, name="ArticleA" id=2, Type=1, name="ArticleB" id=3, Type=2, name="ArticleC" id=4, Type=1, name="ArticleD" TableB records: linked_ID= 1, tableA_ID=2 linked_ID= 1, tableA_ID=3 linked_ID= 1, tableA_ID=4 TableB has a list of arcicels that are compatible to a certain article. I am quite new to queries (didn't need them in my projects yet). But as C# and WPF allow some pretty cool automation with Binding I would like to add a binding that returns the following: Give me all articles that are of Type 1 and compatible to my selected article (id=1). The simple part of it works well (articles has a list of all articles): private ObservableCollection<Article> _articles = new ObservableCollection<Article>(); [fill it with the available articles] and then: comboBoxArticles.ItemsSource = _articles.AsBindable().Where( c => c.Typ == 0 ); How can I extend the Where clause to query another table? Thanks a lot in advance.

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• How to make a NON-LINE based diff between two strings in Java

  - by Mycol

  I have to compare the text content of two xml elements, eg. <p>During lunch he hears strangers whispering, catching the name "Potter" and "Harry", and someone saying You-Know-Who has gone at last. </p> and <p>During dinner he hears strangers whispering, catching the name "Rossi" and "Mario", and someone saying You-Know-Who has gone at first. </p> What I'm looking for is some java libraries to make a diff between the content of paragraphs. All the tools I found makes a line diff. But they're not what I want, simply because i have no lines, but "strings" to compare. What I need is to have a char-based diff: eg. a diff that tells me something like " from the first file, remove char from 8 to 12, add the string "dinner" from char 8."

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• Use LINQ to count the number of combinations existing in two lists

  - by Ben McCormack

  I'm trying to create a LINQ query (or queries) that count the total number of occurences of a combinations of items in one list that exist in a different list. For example, take the following lists: CartItems DiscountItems ========= ============= AAA AAA AAA BBB AAA BBB BBB CCC CCC DDD The result of the query operation should be 2 since I can find two combinations of AAA and BBB (from DiscountItems) within the contents of CartItems. My thinking in approaching the query is to join the lists together to shorten CartItems to only include items from DiscountItems. The solution would be to find the CartItem in the resulting query that occurs the least amount of times, thus indicating how many combinations of items exist in CartItems. How can this be done? Here's the query I already have, but it's not working. query results in an enumeration with 100 items, far more than I expected. Dim query = From cartItem In Cart.CartItems Group Join discountItem In DiscountGroup.DiscountItems On cartItem.SKU Equals discountItem.SKU Into Group Select SKU = cartItem.SKU, CartItems = Group Return query.Min(Function(x) x.CartItems.Sum(Function(y) y.Quantity))

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• Mysql two table query

  - by Sergio

  I'm using two tables. First (friendlist), which contains users who are on the list of friends and the other table (members) that contains the basic data of the users. Friendlist looks like: id | myid | date | user ----------------------------------------- 001 | 50624 | 2010-01-01 | 32009 002 | 41009 | 2010-05-05 | 50624 003 | 50624 | 2010-03-02 | 23007 The column "myid" contains members who added other users (those from column "user") to their frindlist. I want to get the list of all users that I have added to list and those who add me to their friendlist. In this example, if my id is 50624, the list would look like: | allfriends | --------------- 32009 41009 23007 Then I need to check all users from "allfriend" list with data from the table "members". I want to get only the users with status 1. The members table looks like: id | status | photo -------------------------------- 32009 | 0 | 1.jpg 41009 | 1 | 2.jpg 23007 | 1 | 3.jpg How this mysql query should look like? Thanks for any help.

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• Updating the getDistanceFrom between two annotations in MapKit

  - by Krismutt

  Hey everybody! I wanna have a UILabel that shows the distance between two annotations... but how do I get it to update the distance each time the current location is updated (location)?? CLLocationCoordinate2 savedPlace = savedPosition; CLLocationCoordinate2D currentPlace = location; CLLocation *locCurrent = [[CLLocation alloc] initWithLatitude:currentPlace.latitude longitude:currentPlace.longitude]; CLLocation *locSaved = [[CLLocation alloc] initWithLatitude:savedPlace.latitude longitude:savedPlace.longitude]; CLLocationDistance distance = [locSaved distanceFromLocation:locCurrent]; [showDistance setText:[NSString stringWithFormat:@"%g", distance]]; Thanks in advance!

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• str_replace() with two-dimensional array

  - by Qiao

  You can use arrays with str_replace(): $array_from = array ('from1', 'from2'); $array_to = array ('to1', 'to2'); $text = str_replace ($array_from, $array_to, $text); But what if you have two-dimensional array? $array_from_to = array ( 'from1' => 'to1'; 'from2' => 'to2'; ); How can you use it with str_replace()? Speed matters - array is big enough.

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• Associating logging from two or more processes

  - by Fadeproof

  I have two processes that I have up and running and I am doing logging from. One is a client the other is a webservice. I want to setup a central log system where I can track logs and interactions between processes -- for instance I want to be able to associate calls made from the client to the webservice when I look at the logs. I guess this means that somehow the processid of the client process needs to flow over to the webservice in some way for it to be trackable? Is this possible with current logging frameworks such as Enterprise Library or Log4Net? Is there anyone that has looked into something like this? Any help would be appreciated. If you have a more defining term for this please feel free to change the title of the question or tags.

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• two where conditions in a mysql query

  - by Kaartz

  I have a table like below |date|dom|guid|pid|errors|QA|comm| |2010-03-22|xxxx.com|jsd3j234j|ab|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|ab|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|if|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|if|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|he|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|he|No|xxxxxx|| I want to retrieve the total count of "dom" referred to each "QA" and also I need the count of "errors" detected by the "QA" SELECT date, count(dom), QA FROM reports WHERE date="2010-03-22" GROUP BY QA |2010-03-22|2|ab| |2010-03-22|2|if| |2010-03-22|2|he| SELECT date, count(dom), count(errors), QA FROM reports WHERE errors="Yes" GROUP BY QA |2010-03-22|1|ab| |2010-03-22|1|if| |2010-03-22|1|he| I want to combine the above two queries, is it possible. If I use the below query, I am not getting the desired result. SELECT date, count(dom), QA, count(errors) FROM reports WHERE date="2010-03-22" AND errors="Yes" GROUP BY QA I want the below output |2010-03-22|2|ab|1| |2010-03-22|2|if|1| |2010-03-22|2|he|1| Please help me.

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• GXT - link two components height

  - by jjczopek

  Hi! I want to have a panel, with two columns. The first column will contain a list of beans, and the right one a form panel for editing those beans. What I want to do, is that list height is the same as height of the form panel on the right. My list of beans will be larger and larger over time, so it's height will probably exceed form height. When that happens, there should be a scrollbar showed for the list. I also don't want to set explicit size for list and my form panel (it should be flexible because some time I will add or remove some form fields). I'm basically new to GXT. I'm looking forward for some proposals. Cheers, jjczopek

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• Find common nodes from two linked lists using recursion

  - by Dan

  I have to write a method that returns a linked list with all the nodes that are common to two linked lists using recursion, without loops. For example, first list is 2 - 5 - 7 - 10 second list is 2 - 4 - 8 - 10 the list that would be returned is 2 - 10 I am getting nowhere with this.. What I have been think of was to check each value of the first list with each value of the second list recursively but the second list would then be cut by one node everytime and I cannot compare the next value in the first list with the the second list. I hope this makes sense... Can anyone help?

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