Search Results

Search found 27519 results on 1101 pages for 'sql learner'.

Page 673/1101 | < Previous Page | 669 670 671 672 673 674 675 676 677 678 679 680  | Next Page >

  • Performance optimization for mssql: decrease stored procedures execution time or unload the server?

    - by tim
    Hello everybody! We have a web service which provides search over hotels. There is a problem with performance: a single request to the service takes around 5000 ms. Almost all of the time is spent in database by executing storing procedures. During the request our server (mssql2008) consumes ~90% of the processor time. When 2 requests are made in parallel the average time grows and is around 7000 ms. When number of request is increasing, the average time of response is increasing as well. We have 20-30 requests per minute. Which kind of optimization is the best in this case having in mind that the goal is to provide stable response time for the service: 1) Try to decrease the stored procedures execution time 2) Try to find the way how to unload the server It is interesting to hear from people who deal with booking sites. Thanks!

    Read the article

  • how to pull and display range (min-max) data for each page in pagination?

    - by Ty W
    I have a table of data that is searchable and sortable, but likely to produce hundreds or thousands of results for broad searches. Assuming the user searches for "foo" and sorts the foos in descending price order I'd like to show a quick-jump select menu like so: <option value="1">Page 1 ($25,000,000 - $1,625,000)</option> <option value="2">Page 2 ($1,600,000 - $1,095,000)</option> <option value="3">Page 3 ($1,095,000 - $815,000)</option> <option value="4">Page 4 ($799,900 - $699,000)</option> ... Is there an efficient way of querying for this information directly from the DB? I've been grabbing all of the matching records and using PHP to calculate the min and max value for each page which seems inefficient and likely to cause scaling problems. The only possible technique I've been able to come up with is some way of having a calculated variable that increments every X records (X records to a page), grouping by that, and selecting MIN/MAX for each page grouping... unfortunately I haven't been able to come up with a way to generate that variable.

    Read the article

  • Is there a way to force Report Builder to use "WITH (NOLOCK)" in the queries it generates?

    - by Joe Pineda
    Hi. At work, users are very happy to generate their own reports using Reporting Services' Report Builder. But, alas, the queries it generates are very inefficient, and they don't use "WITH (NOLOCK)" - slowing down things for everyone. These are reports that really do need to be run using latest data - can't be offloaded to the reporting server. And since they query very specific, detailed data, hypercubes are of no use here. So the question is: Is there a way to configure Report Builder's Data Models so the queries it generates always use "WITH (NOLOCK)" when querying a table?

    Read the article

  • Same Salt, Different Encrypted Password is not working? Using Linq to update password.

    - by Xaisoft
    Hello, I am running into a wall regarding changing the password and was wondering if anyone had any ideas. Here are the database values prior to changing the password: Clear Text password = abc1980 Encrypted Password = Yn1N5l+4AUqkOM3WYO7ww/sCN+o= Salt = 82qVIhUIoblBRIRvFSZ1fw== After I change my password to abc1973, salt remains the same, but the Encrypted Password changes which is supposed to happen: Encrypted Password = rHtjLq3qxAl/7T1GfkxrsHzPsNk= However, when I try to login with abc1973 as the password, it does not login. If I try abc1980, it logs me in. It is updating the database, is it caching the values somewhere? Any ideas?

    Read the article

  • Select Query Joined on Two Fields?

    - by btollett
    I've got a few tables in an access database: ID | LocationName 1 | Location1 2 | Location2 ID | LocationID | Date | NumProductsDelivered 1 | 1 | 12/10 | 3 2 | 1 | 01/11 | 2 3 | 1 | 02/11 | 2 4 | 2 | 11/10 | 1 5 | 2 | 12/10 | 1 ID | LocationID | Date | NumEmployees | EmployeeType 1 | 1 | 12/10 | 10 | 1 (=Permanent) 2 | 1 | 12/10 | 3 | 2 (=Temporary) 3 | 1 | 12/10 | 1 | 3 (=Support) 4 | 2 | 10/10 | 1 | 1 5 | 2 | 11/10 | 2 | 1 6 | 2 | 11/10 | 1 | 2 7 | 2 | 11/10 | 1 | 3 8 | 2 | 12/10 | 2 | 1 9 | 2 | 12/10 | 1 | 3 What I want to do is pass in the LocationID as a parameter and get back something like the following table. So, if I pass in 2 as my LocationID, I should get: Date | NumProductsDelivered | NumPermanentEmployees | NumSupportEmployees 10/10 | | 1 | 11/10 | 1 | 2 | 1 12/10 | 1 | 2 | 1 It seems like this should be a pretty simple query. I really don't even need the first table except as a way to fill in the combo box on the form from which the user chooses which location they want a report for. Unfortunately, everything I've done has resulted in me getting a lot more data than I should be getting. My confusion is in how to set up the join (presumably that's what I'm looking for here) given that I want both the date and locationID to be the same for each row in the result set. Any help would be much appreciated. Thanks.

    Read the article

  • Transfer Data between databases with postgres

    - by user227932
    I need to transfer some data from another Database. The old database is called paw1.moviesDB and the new database is paw1. The schema of each table are the following Awards (name of the table)(new DB) Id [PK] Serial Award Nominations (name of the table) (old DB) Id [PK] Serial nominations I want to copy the data from old DB to the new DB.

    Read the article

  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

    Read the article

  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

    Read the article

  • SQL query construction - separate data in a column into two columns

    - by Tommy
    I have a column that contains links. The problem is that the titles of the links are in the same column, so it looks like this: linktitle|-|linkurl I want link title and linkurl in separate columns. I've created a new column for the urls, so I'm looking for a way to extract them and update the linkurl column with them. Is there any clever way to construct a query that does this?

    Read the article

  • MS Access PIVOT with User Defined Field

    - by user2535359
    Any of you good souls please help!! I need to query the source table shown in the below. (NULL are blank fields) UNUM, Ticket, Overflow 1 , 135 , NULL 1 , 136 ,NULL 1, 137, NULL 1, 138, NULL 1, NULL, 2b 2, 135, NULL 2, 136, NULL 2, 137, NULL 3, 135, NULL 3, 136, NULL 3, 137,NULL 3, 138, NULL 3, 139, NULL 3, 140, NULL 3, NULL, 66a 4, NULL, 12a 5, NULL, 14a I need to generate the output as shown below. UserNum, Ticket1, Ticket2, Ticket3, Ticket4, Ticket5, Ticket6, Ticket7, Ticket8, Ticket9, Overflow 1, 135, 136, 137, 138, Null, Null, Null, Null, Null, 2b 2, 135, 136, 137, Null, Null, Null, Null, Null, Null, Null 3, 135, 136, 137, 138, 139, 140, Null, Null, Null, 66a 4, Null, Null, Null, Null, Null, Null, Null, Null, Null, 12a 5, Null, Null, Null, Null, Null, Null, Null, Null, Null, 14a The source table has multiple tickets assigned to user. There are always maximum of 9 tickets. The user either has a ticket or an overflow but here can be only overflow per user. I am having issue pivoting the data in Ticket column to pre-defined field names like Ticket1, Ticket2...

    Read the article

  • Combine First, Middle Initial, Last name and Suffix in T-SQL (No extra spaces)

    - by Paul
    I'm trying not to reinvent the wheel here...I have these four fields [tbl_Contacts].[FirstName], [tbl_Contacts].[MiddleInitial], [tbl_Contacts].[LastName], [tbl_Contacts].[Suffix] And I want to create a FullName field in a view, but I can't have extra spaces if fields are blank...So I can't do FirstName + ' ' + MiddleInitial + ' ' + LastName + ' ' + Suffix...Because if there is no middle initial or suffix I'd have 2 extra spaces in the field. I think I need a Case statement, but I thought someone would have a handy method for this...Also, the middleinitial and suffix may be null.

    Read the article

  • Multiple/Sub quries with codeigniter

    - by user1011713
    I just started with Codeigniter and this is driving me nuts. I have a query that determines whether a user has bought any programs. I then have to use that program's type category to run and determine how many times he or she has recorded a query in another table. Sorry for the confusion but the code hopefully makes sense. I'm having problem returning the two arrays from my Model to my Controller to onto the view obviously. function specificPrograms() { $specific_sql = $this->db->query("SELECT program,created FROM `assessment` WHERE uid = $this->uid"); if($specific_sql->num_rows() > 0) { foreach ($specific_sql->result() as $specific) { $data[] = $specific; $this->type = $specific->program; } return $data; } $sub_sql = $this->db->query("SELECT id FROM othertable WHERE user_id_fk = $this->uid and type = '$this->type'"); if($sub_sql->num_rows() > 0) { foreach ($sub_sql->result() as $otherp) { $data[] = $otherp; } return $data; } } Then in my Controller I have, $data['specific'] = $this->user_model->specificPrograms(); $data['otherp'] = $this->user_model->specificPrograms(); Thanks for any help.

    Read the article

  • How to make NOT IN statement via Restrictions

    - by slavig
    I used this trick: List statuses = new ArrayList(); Criteria criteria = session.createCriteria(MessageQueue.class); criteria.add(Restrictions.not(Restrictions.in("message_status", statuses))); and this code creates: ...from MESSAGE_QUEUE mq where not (mq.message_status in (?, ?, ?, ?))... but I need: ...from MESSAGE_QUEUE mq where mq.message_status NOT IN (?, ?, ?, ?) Du you think they are equal statements?

    Read the article

  • left join without duplicate values using MIN()

    - by Clipper87
    I have a table_1: id custno 1 1 2 2 3 3 and a table_2: id custno qty descr 1 1 10 a 2 1 7 b 3 2 4 c 4 3 7 d 5 1 5 e 6 1 5 f When I run this query to show the minimum order quantities from every customer: SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr FROM table_1 LEFT OUTER JOIN table_2 ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2 WHERE table_2.custno = table_1.custno ) Then I get this result: custno qty descr 1 5 e 1 5 f 2 4 c 3 7 d Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description. How could I do this ? Thx!

    Read the article

  • One on One table relation - is it harmful to keep relation in both tables?

    - by EBAGHAKI
    I have 2 tables that their rows have one on one relation.. For you to understand the situation, suppose there is one table with user informations and there is another table that contains a very specific informations and each user can only link to one these specific kind of informations ( suppose second table as characters ) And that character can only assign to the user who grabs it, Is it against the rules of designing clean databases to hold the relation key in both tables? User Table: user_id, name, age, character_id Character Table: character_id, shape, user_id I have to do it for performance, how do you think about it?

    Read the article

  • MySQL -- How to do this better?

    - by Andrew
    $activeQuery = mysql_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0"); $active = mysql_fetch_assoc($activeQuery); $failedQuery = mysql_query("SELECT count(`status`) AS `failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1"); $failed = mysql_fetch_assoc($failedQuery); $completedQuery = mysql_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2"); $completed = mysql_fetch_assoc($completedQuery); There has to be a better way to do that, right? I don't know how much I need to elaborate as you can see what I'm trying to do, but is there any way to do all of that in one query? I need to be able to output the active, failed, and completed assignments, preferably in one query.

    Read the article

< Previous Page | 669 670 671 672 673 674 675 676 677 678 679 680  | Next Page >