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  • One on One table relation - is it harmful to keep relation in both tables?

    - by EBAGHAKI
    I have 2 tables that their rows have one on one relation.. For you to understand the situation, suppose there is one table with user informations and there is another table that contains a very specific informations and each user can only link to one these specific kind of informations ( suppose second table as characters ) And that character can only assign to the user who grabs it, Is it against the rules of designing clean databases to hold the relation key in both tables? User Table: user_id, name, age, character_id Character Table: character_id, shape, user_id I have to do it for performance, how do you think about it?

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  • Membership provider to use or not to use?????

    - by Shekhar_Pro
    Hi every one , Wish u all a Happy New Year. I am developing a website that uses facebook. Now for managing user i thought Using membrship provider. and choose'd to develop a Custom membership provider. Now my problem is that My data base schema dosn't match the Standred membership schema and the functions provided to Override take different argument than i expect. Like membership uses username as a username to log in. But i haev to use User email ID as the user name, also its searching functions is based on using Username as way to serach but i want it to search by UserID. Same Goes for User insertion, deletion, Updation.. please help me .... Edit Its just an idea, Would it be feasible to forcefully pass my values in the arguments and then handle them in my code.

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  • Combine First, Middle Initial, Last name and Suffix in T-SQL (No extra spaces)

    - by Paul
    I'm trying not to reinvent the wheel here...I have these four fields [tbl_Contacts].[FirstName], [tbl_Contacts].[MiddleInitial], [tbl_Contacts].[LastName], [tbl_Contacts].[Suffix] And I want to create a FullName field in a view, but I can't have extra spaces if fields are blank...So I can't do FirstName + ' ' + MiddleInitial + ' ' + LastName + ' ' + Suffix...Because if there is no middle initial or suffix I'd have 2 extra spaces in the field. I think I need a Case statement, but I thought someone would have a handy method for this...Also, the middleinitial and suffix may be null.

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  • is Payment table needed when you have an invoice table like this?

    - by EBAGHAKI
    this is my invoice table: Invoice Table: invoice_id creation_date due_date payment_date status enum('not paid','paid','expired') user_id total_price I wonder if it's Useful to have a payment table in order to record user payments for invoices. payment table can be like this: payment_id payment_date invoice_id price_paid status enum('successful', 'not successful')

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  • Transfer Data between databases with postgres

    - by user227932
    I need to transfer some data from another Database. The old database is called paw1.moviesDB and the new database is paw1. The schema of each table are the following Awards (name of the table)(new DB) Id [PK] Serial Award Nominations (name of the table) (old DB) Id [PK] Serial nominations I want to copy the data from old DB to the new DB.

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  • MS Access PIVOT with User Defined Field

    - by user2535359
    Any of you good souls please help!! I need to query the source table shown in the below. (NULL are blank fields) UNUM, Ticket, Overflow 1 , 135 , NULL 1 , 136 ,NULL 1, 137, NULL 1, 138, NULL 1, NULL, 2b 2, 135, NULL 2, 136, NULL 2, 137, NULL 3, 135, NULL 3, 136, NULL 3, 137,NULL 3, 138, NULL 3, 139, NULL 3, 140, NULL 3, NULL, 66a 4, NULL, 12a 5, NULL, 14a I need to generate the output as shown below. UserNum, Ticket1, Ticket2, Ticket3, Ticket4, Ticket5, Ticket6, Ticket7, Ticket8, Ticket9, Overflow 1, 135, 136, 137, 138, Null, Null, Null, Null, Null, 2b 2, 135, 136, 137, Null, Null, Null, Null, Null, Null, Null 3, 135, 136, 137, 138, 139, 140, Null, Null, Null, 66a 4, Null, Null, Null, Null, Null, Null, Null, Null, Null, 12a 5, Null, Null, Null, Null, Null, Null, Null, Null, Null, 14a The source table has multiple tickets assigned to user. There are always maximum of 9 tickets. The user either has a ticket or an overflow but here can be only overflow per user. I am having issue pivoting the data in Ticket column to pre-defined field names like Ticket1, Ticket2...

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • In the context of an asp.net website, what's the most efficient way to check whether a User has acce

    - by scaramouch
    I have a webpage that you pass in an id parameter (via a querystring), which it then uses to fetch data from a database. Typically, a user would navigate to this page from another page that lists only those records that the user has access to. However, if they go directly to the page by typing in the URL in the Address Bar, they can effectively view any record they like. Eg. If they were to type something like http://localhost/TestSite/ClientAdmin/ManageLocation.aspx?LocationID=5 into their Address Bar, they can access the database record with the LocationID equal to five - even though they shouldn't have access to it. Now, I could solve this by doing a database check every time the page is loaded to see whether the current user has access to the record they're trying to view. However this doesn't seem very efficient given that in most cases a user won't be trying to access a record that isn't theirs. Does anyone have a better suggestion? Thanks.

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  • How to group by having the same id?

    - by simpatico
    Hello, I want the customerid who bought product X and Y and Z, from the following schema: Sales(customerid, productName, rid); I could do the intersection: select customerid from sales where productName='X' INTERSECT select customerid from sales where productName='X' INTERSTECT select customerid from sales where productName='Z' Is this the best I could do?

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  • mysql: managing memory usage

    - by every_answer_gets_a_point
    i am doing a delete with a LIKE statement my keybuffer is 25m, the sort buffer size is 256k the delete has been taking over 2 hours should i increase memory usage? there are about 50 megs of data in the table from which i am deleting, thats about 500,000 rows is there anything else i can do on the adminsitration size to speed up this delete?

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  • excel:mysql: rs.Update not working

    - by every_answer_gets_a_point
    i am updating a table using an ODBC connection from excel to mysql unfortunately the only column that gets updated is this one: .Fields("instrument") = "NA" where i am assigning variables to .Fields, it is putting NULL values!! what is going on here? here's the code Option Explicit Dim oConn As ADODB.Connection Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=pas;" & _ "Option=3" End Sub Function esc(txt As String) esc = Trim(Replace(txt, "'", "\'")) End Function Private Sub InsertData() Dim dpath, atime, rtime, lcalib, aname, rname, bstate, instrument As String Dim rs As ADODB.Recordset Set rs = New ADODB.Recordset ConnectDB With wsBooks rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable Worksheets.Item("Report 1").Select dpath = Trim(Range("B2").Text) atime = Trim(Range("B3").Text) rtime = Trim(Range("B4").Text) lcalib = Trim(Range("B5").Text) aname = Trim(Range("B6").Text) rname = Trim(Range("B7").Text) bstate = Trim(Range("B8").Text) ' instrument = GetInstrFromXML(wbBook.FullName) With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = bstate .Fields("instrument") = "NA" .Update ' stores the new record End With ' get the last id Set rs = oConn.Execute("SELECT @@identity", , adCmdText) 'MsgBox capture_id rs.Close Set rs = Nothing End With End Sub

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  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • wp+sql+image not goin in the folder

    - by happy
    this is my code for uploading image in database but image are going to the desird forlder...but when i m tryin to retrieve the images to diaplay,,they are not displayed..anyone help me...... $category=$_POST['category']; $uploadDir = 'D:/xampp/htdocs/js/wordpress/wp-content/plugins/img/imagess/ '; $fileName = $_FILES['Photo']['name']; $tmpName = $_FILES['Photo']['tmp_name']; $fileSize = $_FILES['Photo']['size']; $fileType = $_FILES['Photo']['type']; $filePath = $uploadDir . $fileName; $result = move_uploaded_file($tmpName,$filePath); if (!$result) { echo "Error uploading file"; exit; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } global $wpdb; //$insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category),array('%b','%s')); $insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category)); $wpdb->insert('categories',array('cat_name'=>$category)); echo "Successfully Submitted";

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  • Error 49 bad bind variable oracle forms

    - by mysticfalls
    I would like to ask regarding this error... Error 49 at line 5, column 6 bad bind variable 'S_ORD.payment_type' Here is the code: DECLARE N NUMBER; v_credit S_CUSTOMER.credit_rating%type; BEGIN IF :S_ORD.payment_type = 'CREDIT' THEN SELECT credit_rating INTO v_credit FROM S_CUSTOMER WHERE :S_ORD.customer_id = id; IF v_credit NOT IN ('GOOD', 'EXCELLENT') THEN :S_ORD.payment_type:= 'CASH'; n:=SHOW_ALERT('Payment_Type_Alert'); END IF; END IF; END; I'm new to oracle forms so I'm not sure if I have a missing setup or anything. S_ORD table exist and has a column payment_type, which consists of 'CREDIT' and 'CASH' value. Thank you.

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