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  • Drupal db_query_range sql query

    - by hfidgen
    Hiya, I'm trying to get this working and the query executes but nothing comes back.. I've tried everything I can think of, can you spot what I'm doing wrong? Thanks in advance! $nido = $node->nid; $result = db_query_range(' SELECT i.nid, i.iid, a.fid, p.filename, p.filepath FROM {drup_image_attach} i LEFT JOIN {drup_image} a ON i.iid = a.nid LEFT JOIN {drup_files} p ON a.fid = p.fid WHERE i.nid = %d AND p.filename = "recipe_thumb"', $nido, 0, 10); echo "Filepath = " . $result ->filepath. "<br>"; echo "Filepath = " . $result ->filename . "<br>"; echo "IID = " . $result ->iid. "<br>"; echo "NID = " . $result ->nid . "<br>"; } EDIT - sorted out a couple of bits, but the output is still empty!

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  • PHP Error - Login Script

    - by gamerzfuse
    I am creating a new login script/members directory. I am creating it from scratch without any frameworks (advice on this matter would also be appreciated). The situation: // Look up the username and password in the database $query = "SELECT admin_id, username FROM admin WHERE adminname = '$admin_user' AND password = SHA1('$admin_pass')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { This bit of code keeps giving me an error (the last line in particular): Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in /home8/craighoo/public_html/employees/security/dir_admin.php on line 20 When echoing the query I get: SELECT admin_id, username FROM admin WHERE adminname = 'admin' AND password = SHA1('tera#byte') Thanks in advance!

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  • Sharepoint SSRS: Unexpected Error Encountered

    - by Nicholas
    We are running an intranet website hosted on Sharepoint 2007, serving reports to users via SSRS. Recently, our users are experiencing error when trying to access certain reports with the error message "An unexpected error has occurred". After trying many things, to cut a long story short we manage to temporarily solve the problem by manually running UPDATE STATISTICS on the tables in the database. However, this error will periodically crop up again and again, running UPDATE STATISTICS immediately solved it. I had suggested to run a daily job in the server to auto run UPDATE STATISTICS every few hours or so but was rejected by my team lead. Is there any other workaround for this error? Why does UPDATE STATISTICS solve the problem, I still not very understand?

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  • how to compare dates in php and sql?

    - by sebastian
    Hi, I want to make a notification system. Shortly.. to compare two dates, the only problem is that i want to compare the months. to see if a month or two have passed from last notification. i want to use one or two months from an entry in a mysql database. the client must select when the notification must come, one or two months. thank you, Sebastian

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  • How to get max row from table

    - by Odette
    HI I have the following code and a massive problem: WITH CALC1 AS ( SELECT OTQUOT, OTIT01 AS ITEMS, ROUND(OQCQ01 * OVRC01,2) AS COST FROM @[email protected] WHERE OTIT01 <> '' UNION ALL SELECT OTQUOT, OTIT02 AS ITEMS, ROUND(OQCQ02 * OVRC02,2) AS COST FROM @[email protected] WHERE OTIT02 <> '' UNION ALL SELECT OTQUOT, OTIT03 AS ITEMS, ROUND(OQCQ03 * OVRC03,2) AS COST FROM @[email protected] WHERE OTIT03 <> '' UNION ALL SELECT OTQUOT, OTIT04 AS ITEMS, ROUND(OQCQ04 * OVRC04,2) AS COST FROM @[email protected] WHERE OTIT04 <> '' UNION ALL SELECT OTQUOT, OTIT05 AS ITEMS, ROUND(OQCQ05 * OVRC05,2) AS COST FROM @[email protected] WHERE OTIT05 <> '' ORDER BY OTQUOT ASC ) SELECT OTQUOT, ITEMS, MAX(COST) FROM CALC1 WHERE OTQUOT = '04886471' GROUP BY OTQUOT, ITEMS result: 04886471 FEPO5050WCGA24 13.21 04886471 GFRK1650SGL 36.21 04886471 FRA7500GA 12.6 04886471 CGIFESHAZ 11.02 04886471 CGIFESHPDPR 11.79 04886471 GFRK1350DBL 68.23 04886471 RET1.63825GP 32.55 04886471 FRSA 0.12 04886471 GFRK1350SGL 55.94 04886471 GFRK1650DBL 71.89 04886471 FEPO6565WCGA24 16.6 04886471 PCAP5050GA 0.28 04886471 FEPO6565NCPAG24 0.000000 How can I get the result of the row with the Itemcode that has the highest value? In this case I need the result: 04886471 GFRK1650DBL 71.89 but i dont know how to change my code to get that - can anybody please help me?

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  • PostgreSQL JOIN with array type with array elements order, how to implement?

    - by Adiasz
    Hello I have two tables in database: CREATE TABLE items( id SERIAL PRIMARy KEY, ... some other fields ); This table contains come data row with unique ID. CREATE TABLE some_choosen_data_in_order( id SERIAL PRIMARy KEY, id_items INTEGER[], ); This table contains array type field. Each row contains values of IDs from table "items" in specyfic order. For example: {2,4,233,5}. Now, I want to get data from table "items" for choosen row from table "some_choosen_data_in_order" with order for elements in array type. The my attempt is JOIN: SELECT I.* FROM items AS I JOIN some_choosen_data_in_order AS S ON I.id = ANY(S.id_items) WHERE S.id = ? Second attempt was subquery like: SELECT I.* FROM items AS I WHERE I.id = ANY (ARRAY[SELECT S.id_items FROM some_choosen_data_in_order WHERE id = ?]) But none of them keep IDs order in array field. Could You help me, how to get data from "items" table with correspond with array IDs order from "some_choosen_data_in_order" table for specyfic row?

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  • Require help in Writing Query

    - by harigm
    The following image have been uploaded to show what I am trying to do and what I wanted out of it Can any one help me write the Query to get the results what I want Please check the following SELECT * FROM KPT WHERE PROPERTY_ID IN (SELECT PROPERTY_ID FROM khata_header WHERE DIV_ID = 3 and RECORD_STATUS = 0) and CHALLAN_NO > 42646 The above is the query I have written and I have got the following result set ID CHALLAN_NO PROPERTY_ID SITE_NO TOTAL_AMOUNT ----- ------------- -------------- ------------------- --------------- 1242 42757 3103010141 296 595 1243 63743 3204190257 483 594 1244 63743 3204190257 483 594 1334 43395 3217010223 1088 576 1421 524210 3320050416 (null) (null) 1422 524210 3320050416 (null) (null) 1560 564355 3320021408 (null) (null) 1870 516292 3320040420 (null) (null) 1940 68357 3217100104 139 1153 1941 68357 3217100104 139 1153 2002 56256 3320100733 511 4430 2003 56256 3320100733 511 4430 2004 66488 3217040869 293 3094 2005 66488 3217040869 293 3094 2016 64571 3217040374 (null) (null) 2036 523122 3320020352 (null) (null) 2039 65682 3217040021 273 919 In my resultset, I am getting the PropertyId repeated, since there are multilple entries, How Can I know How many have been repeated What are those Property Id which have repeated more than 2 times. Little Back ground about the tables are PROPERTY_ID is the FK in the KPT PROPERTY_ID is the PK in KH I am writing a subquery to get the Result, so I am stuck I dont know how to get my results Please help

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  • How to call a scalar function in a stored procedure

    - by Luke101
    I am wacking y head over the problem with this code. DECLARE @root hierarchyid declare @lastchild hierarchyid SELECT @root = NodeHierarchyID from NodeHierarchy where ID = 1 set @lastchild = getlastchild(@root) it says it does not recognize getlastchild function. What am I doing wrong here

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  • Explanation of converting exporting an XML document as a relational database using XSLT

    - by Yaaqov
    I would like to better understand the basic steps needed to a take an XML document like this Breakfast Menu... <?xml version="1.0" encoding="ISO-8859-1"?> <breakfast_menu> <food> <name>Belgian Waffles</name> <price>$5.95</price> <description>two of our famous Belgian Waffles with plenty of real maple syrup</description> <calories>650</calories> </food> <food> <name>Strawberry Belgian Waffles</name> <price>$7.95</price> <description>light Belgian waffles covered with strawberries and whipped cream</description> <calories>900</calories> </food> <food> <name>Berry-Berry Belgian Waffles</name> <price>$8.95</price> <description>light Belgian waffles covered with an assortment of fresh berries and whipped cream</description> <calories>900</calories> </food> <food> <name>French Toast</name> <price>$4.50</price> <description>thick slices made from our homemade sourdough bread</description> <calories>600</calories> </food> <food> <name>Homestyle Breakfast</name> <price>$6.95</price> <description>two eggs, bacon or sausage, toast, and our ever-popular hash browns</description> <calories>950</calories> </food> </breakfast_menu> And "export" it to say, an Access or MySQL database using XSLT, creating two joined tables: Table: breakfast_menu Field: menu_item_id Field: food_id Table: food Field: food_id Field: name Field: price Field: description Field: calories If there are online tutorials on this that you know of, I'd be interesting in learning more, as well. Thanks.

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  • MySQL MyISAM table performance... painfully, painfully slow

    - by Salman A
    I've got a table structure that can be summarized as follows: pagegroup * pagegroupid * name has 3600 rows page * pageid * pagegroupid * data references pagegroup; has 10000 rows; can have anything between 1-700 rows per pagegroup; the data column is of type mediumtext and the column contains 100k - 200kbytes data per row userdata * userdataid * pageid * column1 * column2 * column9 references page; has about 300,000 rows; can have about 1-50 rows per page The above structure is pretty straight forwad, the problem is that that a join from userdata to page group is terribly, terribly slow even though I have indexed all columns that should be indexed. The time needed to run a query for such a join (userdata inner_join page inner_join pagegroup) exceeds 3 minutes. This is terribly slow considering the fact that I am not selecting the data column at all. Example of the query that takes too long: SELECT userdata.column1, pagegroup.name FROM userdata INNER JOIN page USING( pageid ) INNER JOIN pagegroup USING( pagegroupid ) Please help by explaining why does it take so long and what can i do to make it faster. Edit #1 Explain returns following gibberish: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE userdata ALL pageid 372420 1 SIMPLE page eq_ref PRIMARY,pagegroupid PRIMARY 4 topsecret.userdata.pageid 1 1 SIMPLE pagegroup eq_ref PRIMARY PRIMARY 4 topsecret.page.pagegroupid 1 Edit #2 SELECT u.field2, p.pageid FROM userdata u INNER JOIN page p ON u.pageid = p.pageid; /* 0.07 sec execution, 6.05 sec fecth */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE u ALL pageid 372420 1 SIMPLE p eq_ref PRIMARY PRIMARY 4 topsecret.u.pageid 1 Using index SELECT p.pageid, g.pagegroupid FROM page p INNER JOIN pagegroup g ON p.pagegroupid = g.pagegroupid; /* 9.37 sec execution, 60.0 sec fetch */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE g index PRIMARY PRIMARY 4 3646 Using index 1 SIMPLE p ref pagegroupid pagegroupid 5 topsecret.g.pagegroupid 3 Using where Moral of the story Keep medium/long text columns in a separate table if you run into performance problems such as this one.

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  • Representing Sparse Data in PostgreSQL

    - by Chris S
    What's the best way to represent a sparse data matrix in PostgreSQL? The two obvious methods I see are: Store data in a single a table with a separate column for every conceivable feature (potentially millions), but with a default value of NULL for unused features. This is conceptually very simple, but I know that with most RDMS implementations, that this is typically very inefficient, since the NULL values ususually takes up some space. However, I read an article (can't find its link unfortunately) that claimed PG doesn't take up data for NULL values, making it better suited for storing sparse data. Create separate "row" and "column" tables, as well as an intermediate table to link them and store the value for the column at that row. I believe this is the more traditional RDMS solution, but there's more complexity and overhead associated with it. I also found PostgreDynamic, which claims to better support sparse data, but I don't want to switch my entire database server to a PG fork just for this feature. Are there any other solutions? Which one should I use?

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  • T-SQL Table Joins - Unique Situation

    - by Dimitri
    Hello Everyone. This is my first time encountering the case like this and don't quite know how to handle. Situation: I have one table tblSettingsDefinition, with fields: ID, GroupID, Name, typeID, DefaultValue. Then I have tblSettingtypes with fields TypeID, Name. And I have final table, tblUserSettings with fields SettingID, SettingDefinitionID, UserID, Value. The whole point of this is to have customizable settings. Setting can be defined for a Group or as global setting (if GroupID is NULL). It will have a default value, but if user modifies the setting, an entry is added to tblUserSettings that stores new value. I want to have a query that grabs user settings by first looking at the tblUserSettings, and if it has records for the given user, grabs them, if not retrieves default settings. But the trick is that no matter if user has settings or not, I need to have fields from other two table retrieved to know the setting's Type, Name etc... (which are stored in those other tables). I'm writing query something like this: SELECT * FROM tblSettingDefinition SD LEFT JOIN tblUserSettings US ON SD.SettingID = US.SettingDefinitionID JOIN tblSettingTypes ST ON SD.TypeID=ST.ID WHERE US.UserID=@UserID OR ((SD.GroupID IS NULL) OR (SD.GroupID=(SELECT GroupID FROM tblUser WHERE ID=@UserID))) but it retrieves settings for all users from tblUserSettings instead of just ones that match current @UserID. And if @UserID has no records in tblUserSettings, still, all user settings are retrieved instead of the defaults from tblSettingDefinition. Hope I made myself clear. Any help would be highly appreciated. Thank you.

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  • Why would I get a duplicate key error when updating a row?

    - by hdx
    I'm using postgres and I'm getting the duplicate key error when updating a row: cursor.execute("UPDATE jiveuser SET userenabled = 0 WHERE userid = %s" % str(userId)) psycopg2.IntegrityError: duplicate key value violates unique constraint "jiveuser_pk" I don't understand how updating a row can cause this error... any help will be much appreciated.

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  • Connecting to Teradata via PHP

    - by AFHood
    We need to access a Teradata database via php application We don't have odbc (unixodbc etc) on the server. How might one go about connecting to a teradata database quickly. Keep in mind - this app needs to be as portable as possible.

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  • Help with this query in Access

    - by DiegoMaK
    ID- DATE- NAME 10100- 2010/04/17- Name1 10100- 2010/04/14- Name2 10200- 2010/04/17- Name3 10200- 2010/04/16- Name4 10200- 2010/04/15- Name5 10400- 2010/04/01- Name6 I have this fields(and others too) in one table. I need to do a query which return the ID with your respective name where more recently date for example the results for desired query in that data example will be. 10100- 2010/04/17- Name1 10200- 2010/04/17- Name3 10400- 2010/04/01- Name6 Ommiting ID with older dates. Then I need one query for that. thanks.

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  • Query not returning rows in a table that don't have corresponding values in another [associative] ta

    - by Obay
    I have Table: ARTICLES ID | CONTENT --------------- 1 | the quick 2 | brown fox 3 | jumps over 4 | the lazy Table: WRITERS ID | NAME ---------- 1 | paul 2 | mike 3 | andy Table: ARTICLES_TO_WRITERS ARTICLE_ID | WRITER_ID ----------------------- 1 | 1 2 | 2 3 | 3 To summarize, article 4 has no writer. So when I do a "search" for articles with the word "the": SELECT a.id, a.content, w.name FROM articles a, writers w, articles_to_writers atw WHERE a.id=atw.article_id AND w.id=atw.writer_id AND content LIKE '%the%' article 4 does not show up in the result: ID | CONTENT | NAME ----------------------- 1 | the quick | paul How do I make article 4 still appear in the results even though it has no writers?

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  • How to Set Customer Table with Multiple Phone Numbers? - Relational Database Design

    - by user311509
    CREATE TABLE Phone ( phoneID - PK . . . ); CREATE TABLE PhoneDetail ( phoneDetailID - PK phoneID - FK points to Phone phoneTypeID ... phoneNumber ... . . . ); CREATE TABLE Customer ( customerID - PK firstName phoneID - Unique FK points to Phone . . . ); A customer can have multiple phone numbers e.g. Cell, Work, etc. phoneID in Customer table is unique and points to PhoneID in Phone table. If customer record is deleted, phoneID in Phone table should also be deleted. Do you have any concerns on my design? Is this designed properly? My problem is phoneID in Customer table is a child and if child record is deleted then i can not delete the parent (Phone) record automatically.

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  • "SELECT TOP", "LEFT OUTER JOIN", "ORDER BY" gives extra rows

    - by Codesleuth
    I have the following Access query I'm running through OLE DB in .NET: SELECT TOP 25 tblClient.ClientCode, tblRegion.Region FROM (tblClient LEFT OUTER JOIN tblRegion ON tblClient.RegionCode = tblRegion.RegionCode) ORDER BY tblRegion.Region There are 431 records within tblClient that have RegionCode set to NULL. For some reason, the query above returns all these 431 records instead of the first 25. If I change the query to ORDER BY tblClient.Client (the name of the client) like so: SELECT TOP 25 tblClient.ClientCode, tblRegion.Region FROM (tblClient LEFT OUTER JOIN tblRegion ON tblClient.RegionCode = tblRegion.RegionCode) ORDER BY tblClient.Client I get the expected result set of 25 records, showing a mixture of region names and NULL values. Why is it that ordering by a field retrieved through a LEFT OUTER JOIN will the TOP clause not work?

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  • How can I choose different hints for different joins for a single table in a query hint?

    - by RenderIn
    Suppose I have the following query: select * from A, B, C, D where A.x = B.x and B.y = C.y and A.z = D.z I have indexes on A.x and B.x and B.y and C.y and D.z There is no index on A.z. How can I give a hint to this query to use an INDEX hint on A.x but a USE_HASH hint on A.z? It seems like hints only take the table name, not the specific join, so when using a single table with multiple joins I can only specify a single strategy for all of them. Alternative, suppose I'm using a LEADING or ORDERED hint on the above query. Both of these hints only take a table name as well, so how can I ensure that the A.x = B.x join takes place before the A.z = D.z one? I realize in this case I could list D first, but imagine D subsequently joins to E and that the D-E join is the last one I want in the entire query. A third configuration -- Suppose I want the A.x join to be the first of the entire query, and I want the A.z join to be the last one. How can I use a hint to have a single join from A to take place, followed by the B-C join, and the A-D join last?

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  • Why Banks or Financial Companies prefer Oracle than other RDBMS for their "Core" systems?

    - by edwin.nathaniel
    I'd like to know why most Banks or Financial companies prefer Oracle than other RDBMS for their core systems (the absolutely minimum features that a Bank must support). I found a few answers that didn't satisfy me. For example: Oracle has more features. But features for what? Can't you implement that in application level if you were not using Oracle? Could someone please describe a bit more technical but still on high-level overview of what the bank needs and how Oracle would solve it and the others can't or don't have the features yet? I came from the web-app (web 2.0) crowd who normally hear news about MySQL, PostgreSQL or even key-value/column-oriented storage solution. I have almost zero knowledge on how Banks or Financial companies operates from technical perspective. Thank you, Ed

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