Search Results

Search found 96223 results on 3849 pages for 'user group meetings'.

Page 68/3849 | < Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >

  • Centos Xen resizing DomU partition and volume group

    - by thepearson
    I have a setup like so: Dom0 LV | DomU Physical Disk | | XVDA1 XVDA2 (/boot) (DomU PV) | VolGroup00 (DomU VG) | | LogVol00 LogVol01 (swap) (/) I am trying to resize the DomU root Filesystem. (VolGroup00-LogVol01) I realize that I now need to resize the partition XVDA2, however when I try doing this with parted on Dom0 it just tells me "Error: Could not detect file system." So to resize the root part VolGroup-LogVol00 shouldn't the process be: # Shut down DomU xm shutdown domU #Resize Dom0 Logical volume lvextend -L+2G /dev/volumes/domU-vol # Parted parted /dev/volumes/domU-vol # Resize root partition resize 2 START END (This is where I get an error) "Error: Could not detect file system." # add the vm volume group to Dom0 lvm kpartx -a /dev/volumes/domU-vol # resize the domU PV pvresize /dev/mapper/domU-pl (as listed in pvdisplay) # The domU volume group should automatically adjust # resize the DomU lv lvextend -L+2G /dev/VolGroup/LogVol00 And then obviously increase the fs, remove the device from kpartx etc The problem is I dont know how to resize the partition? How do I resize this partition so I can run pvresize on the DomU? Thanks

    Read the article

  • VSFTP Users and Directories

    - by Mathew
    I'm stuck. I've been working all day on trying to figure out what I'm doing wrong and I've hit wall after wall. What I'm trying to do: Setup FTP in such a way that certain users have access only to their directory, but higher level users have access to all directories. What I've Googled so far: I started with this, but that didn't do what I needed it to. I then used this, but once I created one user, it wouldn't let me create another one. Finally, I decided to follow this, but it wouldn't let me even create one user. I'm using Ubuntu 10. I can login to ftp as a root user and it takes me to the home directory. If I try to login using the user I created in the tutorial it says: Status: Connection established, waiting for welcome message... Response: 220 (vsFTPd 2.2.2) Command: USER mathew Response: 331 Please specify the password. Command: PASS **** Response: 530 Login incorrect. Error: Critical error Error: Could not connect to server

    Read the article

  • Why is user asked to choose their workgroup?

    - by Clinton Blackmore
    We running Mac OS X Server 10.5.8 with Mac OS X 10.5.8 clients. Students use network logins to, well, log in. I've been asked to deny internet access to a specific user. I was told that a good way to do it is to create a user workgroup called "No Internet Access" and manage settings there. (Specifically, I told parental controls to allow access to no sites, and blacklisted all the installed web browsers). Now, when the user authenticates to log in, they are greeted with this dialog: Workgroups for <username> Grade 7 Students No Internet Access It is unlikely that the student would willing choose "No Internet Access" to be their base group. Looking in Workgroup Manager at the student's record, it shows their primary group ID is the grade 7 group, and "No Internet Access" is listed as another group they belong to. I looked at the managed preferences for all the computers pertaining to logins. They are set to their defaults. Specifically, the computer groups' preference for Logins - Access has the defaults: [unchecked] Ignore workgroup nesting [checked] Combine available workgroup settings Based on my reading of Tips and Tricks for Mac Administrators, this should be correct, the user should not be asked which group they belong to, and settings from all applicable groups should be applied. How can I achieve that result? Edit: I've decided to add some additional information from the Tips and Tricks for Mac Management White Paper (via Apple in Education, via the author's site). On page 21, it says: With Leopard MCX, workgroup preference settings are combined by default into a single set of values. This means that instead of having to choose between the Math, Science, or Language Arts workgroups when logging in, a user can just authenticate and be taken directly to the desktop. All the settings for each of those workgroups are composited together, providing you with all the Dock items and a composite of all the other settings. On page 40, an example is given in which settings are combined from different 'domains', one computer group, two (user) workgroups, and one individual user's settings. [When johnd logs into a leopard client,] the items staged in the Dock from left to right are: computer group, first workgroup alphabetically, second workgroup, user. Items within the workgroup are staged alphabetically. Nowhere is there an indication that groups are nested; indeed, I can see no sensible (non-flat) heirarchy for groups like Math, Science, and Language Arts. I strongly believe that there is a way to apply settings from two unrelated user workgroups such that a user of OS X 10.5.x or newer does not need to choose their workgroup. This is what I seek to achieve.

    Read the article

  • sql group by with left join

    - by cometta
    fail statement:Error: ORA-00979: not a GROUP BY expression select org_division.name , org_department.name , org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code but below is ok select org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code how to use group by with left join when i need to show value of org_division.name , org_department.name ?

    Read the article

  • "Fast link detected" warning in GP management console

    - by ???????? ??????
    There is a message that is shown in every report i make in Group Policy Results section of Group Policy Management Console, saying that "A fast link is detected". I followed the link in the waring, but after I read the page several times, I concluded, that I can ignore the warning. However, I noticed that the group policies are not applied when security filtering is used untl "gpupdate /sync" is executed... Is this related to the fast sync? In general, can somebody explain me the consequences of fast links briefly?

    Read the article

  • Configure Nagios To Alert Depending On Host Group That Service Alert Originates From

    - by StrangeWill
    So my setup: Services are shared between all hosts (CPU/RAM/Disk/Services). Hosts are split into two main groups: "Production" and "Development". We have two contact groups: "Production" and "Development". Lets say my development SQL server runs low on RAM, I want it to only alert those in "Development" contact group (this service is of course assigned to a host in the "Development" host group, using the shared RAM monitoring service). I'm pretty much stumped on this... I can't configure it at the service level (they're shared there), and I can't seem to get escalations to do it for me either... Do I need to use service groups along with escalations and bite the bullet on building that list? Or am I missing something stupidly simple? I'm using Centreon for configuration if that helps.

    Read the article

  • I can't make this query work with SUM function

    - by Mehper C. Palavuzlar
    This query gives an error: select ep, case when ob is null and b2b_ob is null then 'a' when ob is not null or b2b_ob is not null then 'b' else null end as type, sum(b2b_d + b2b_t - b2b_i) as sales from table where ... group by ep, type Error: ORA-00904: "TYPE": invalid identifier When I run it with group by ep, the error message becomes: ORA-00979: not a GROUP BY expression The whole query works OK if I remove the lines sum(b2b_d+b2b_t-b2b_i) as sales and group by ..., so the problem should be related to SUM and GROUP BY functions. How can I make this work? Thanks in advance for your help.

    Read the article

  • How to make multiple segmented inputs in a single input group in Bootstrap

    - by metaculus
    This is how it is supposed to look like on Airbnb home page http://airbnb.com I have tried .input-group-addon and nest in it another <input> like so: <div class="col-lg-6"> <div class="input-group"> <input type="text" class="form-control"> <span class="input-group-addon"> <input type="text" id="nested-input" class="form-control"> </span> <span class="input-group-btn"> <button class="btn btn-default" type="button">Go!</button> </span> </div> </div> </div> And it didn't work. Does Bootstrap support this styling?

    Read the article

  • best way to store 1:1 user relationships in relational database

    - by aharon
    What is the best way to store user relationships, e.g. friendships, that must be bidirectional (you're my friend, thus I'm your friend) in a rel. database, e.g. MYSql? I can think of two ways: Everytime a user friends another user, I'd add two rows to a database, row A consisting of the user id of the innitiating user followed by the UID of the accepting user in the next column. Row B would be the reverse. You'd only add one row, UID(initiating user) followed by UID(accepting user); and then just search through both columns when trying to figure out whether user 1 is a friend of user 2. Surely there is something better?

    Read the article

  • Group testNG tests without annotations

    - by diy
    Hi gents and ladies, I'm responsible for allowing unit tests for one of ETL components.I want to acomplish this using testNG with generic java test class and number of test definitions in testng.xmlpassing various parameters to the class.Oracle and ETL guys should be able to add new tests without changing the java code, so we need to use xml suite file instead of annotations. Question Is there a way to group tests in testng.xml?(similarly to how it is done with annotations) I mean something like <group name="first_group"> <test> <class ...> <parameter ...> </test> </group> <group name="second_group"> <test> <class ...> <parameter ...> </test> </group> I've checked the testng.dtd as figured out that similar syntax is not allowed.But is therea workaround to allow grouping? Thanks in advance

    Read the article

  • Sql Server Service Broker Conversation Groups

    - by Brian Hasden
    Can someone explain conversation groups in service broker? Currently, I'm using service broker to send messages from one SQL server to another. On the sending server, I'm trying to correlate the messages so they are processed in serial on the receiving side. Based on the documentation, conversation groups seem to be a perfect fit for this, but on the receiving server, the messages get assigned to a different conversation group from the one I specified when sending the message. I've search around the web and saw that this behavior seems to be intended (http://social.msdn.microsoft.com/forums/en-US/sqlservicebroker/thread/baf48074-6804-43ab-844a-cb28a6dce02b/), but then I'm confused about the usefulness of the syntax from (http://msdn.microsoft.com/en-us/library/ms178624.aspx) WAITFOR( GET CONVERSATION GROUP @conversation_group_id FROM [dbo].[ReceiveQueue] ) If the conversation group doesn't come across with the message from the sender and messages sent with the same conversation group id don't have the same conversation group id on the receive side, what's the point of the code above?

    Read the article

  • Group by and order by

    - by Simon Thompson
    using LINQ to NHibernate does anybody know how to use group by and order by in the same expression. I am having to execute the group by into a list and then order this, seem that I am missing soemthing here ??? Example:- Private function LoadStats(...) ... Dim StatRepos As DataAccess.StatsExtraction_vwRepository = New DataAccess.StatsExtraction_vwRepository return (From x In StatRepos.GetAnswers(Question, Questionnaire) _ Group x By xData = x.Data Into Count() _ Select New ChartData With {.TheData = xData, .TheValue = xData.Count} ).ToList.OrderBy(Function(x) x.TheData) End Sub

    Read the article

  • Can't assign software to non-admin account

    - by labyrinth
    I'm trying to deploy software on our domain using group policy, but I am only able to do so if the user is a member of a group with administrative privileges. We do not want to allow users to install programs generally, but do want to be able to assign/publish. The test program I'm using is originally a .msi file, and it installs fine for users in the administrators group. How can we assign/publish to normal users without opening up the ability to install whatever? Also, from what I've read, I believe I have correct permissions on the folder/share where the .msi files are stored. This is on Win2008R2 with Win7Pro clients.

    Read the article

  • Get twitter bootstrap btn-group to operate like grouped navigation bar with drop down menus

    - by Jeremy Child
    I have been trying to get Twitter Bootstrap btn-group with dropdown to work for multiple buttons that have a drop down menu. Example: <div class="btn-group"> <a href="#" class="btn">1</a> <a href="#" class="btn">2</a> <a href="#" class="btn">3</a> <a href="#" class="btn">4</a> <a href="#" class="btn">5</a> </div> And also my attempt: http://jsfiddle.net/x2BGB/ This displays a button group. I would like some of the buttons in that group to have drop down menus. An example of what I am trying to achieve is: Note: the grouped button "bar" should not have rounded cornes when a button is next to another button. (right side).

    Read the article

  • Error when pushing to Heroku - ...appear in group - Ruby on Rails

    - by bgadoci
    I am trying to deploy my first rails app to Heroku and seem to be having a problem. After git push heroku master, and heroku rake db:migrate I get an error saying: SELECT posts.*, count(*) as vote_total FROM "posts" INNER JOIN "votes" ON votes.post_id = posts.id GROUP BY votes.post_id ORDER BY created_at DESC LIMIT 5 OFFSET 0): I have included the full error below and also included the PostControll#index as it seems that is where I am doing the grouping. Lastly I included my routes.rb file. I am new to ruby, rails, and heroku so sorry for simple/obvious questions. Processing PostsController#index (for 99.7.50.140 at 2010-04-21 12:50:47) [GET] ActiveRecord::StatementInvalid (PGError: ERROR: column "posts.id" must appear in the GROUP BY clause or be used in an aggregate function : SELECT posts.*, count(*) as vote_total FROM "posts" INNER JOIN "votes" ON votes.post_id = posts.id GROUP BY votes.post_id ORDER BY created_at DESC LIMIT 5 OFFSET 0): vendor/gems/will_paginate-2.3.12/lib/will_paginate/finder.rb:82:in `send' vendor/gems/will_paginate-2.3.12/lib/will_paginate/finder.rb:82:in `paginate' vendor/gems/will_paginate-2.3.12/lib/will_paginate/collection.rb:87:in `create' vendor/gems/will_paginate-2.3.12/lib/will_paginate/finder.rb:76:in `paginate' app/controllers/posts_controller.rb:28:in `index' /home/heroku_rack/lib/static_assets.rb:9:in `call' /home/heroku_rack/lib/last_access.rb:25:in `call' /home/heroku_rack/lib/date_header.rb:14:in `call' thin (1.0.1) lib/thin/connection.rb:80:in `pre_process' thin (1.0.1) lib/thin/connection.rb:78:in `catch' thin (1.0.1) lib/thin/connection.rb:78:in `pre_process' thin (1.0.1) lib/thin/connection.rb:57:in `process' thin (1.0.1) lib/thin/connection.rb:42:in `receive_data' eventmachine (0.12.6) lib/eventmachine.rb:240:in `run_machine' eventmachine (0.12.6) lib/eventmachine.rb:240:in `run' thin (1.0.1) lib/thin/backends/base.rb:57:in `start' thin (1.0.1) lib/thin/server.rb:150:in `start' thin (1.0.1) lib/thin/controllers/controller.rb:80:in `start' thin (1.0.1) lib/thin/runner.rb:173:in `send' thin (1.0.1) lib/thin/runner.rb:173:in `run_command' thin (1.0.1) lib/thin/runner.rb:139:in `run!' thin (1.0.1) bin/thin:6 /usr/local/bin/thin:20:in `load' /usr/local/bin/thin:20 PostsController def index @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @ugtag_counts = Ugtag.count(:group => :ugctag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @vote_counts = Vote.count(:group => :post_title, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = [:tags, :votes] end @posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id", :order => "created_at DESC", :page => params[:page], :per_page => 5) @popular_posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id", :order => "vote_total DESC", :page => params[:page], :per_page => 3) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end routes.rb ActionController::Routing::Routes.draw do |map| map.resources :ugtags map.resources :wysihat_files map.resources :users map.resources :votes map.resources :votes, :belongs_to => :user map.resources :tags, :belongs_to => :user map.resources :ugtags, :belongs_to => :user map.resources :posts, :collection => {:auto_complete_for_tag_tag_name => :get } map.resources :posts, :sessions map.resources :posts, :has_many => :comments map.resources :posts, :has_many => :tags map.resources :posts, :has_many => :ugtags map.resources :posts, :has_many => :votes map.resources :posts, :belongs_to => :user map.resources :tags, :collection => {:auto_complete_for_tag_tag_name => :get } map.resources :ugtags, :collection => {:auto_complete_for_ugtag_ugctag_name => :get } map.login 'login', :controller => 'sessions', :action => 'new' map.logout 'logout', :controller => 'sessions', :action => 'destroy' map.root :controller => "posts" map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format' end UPDATE TO SHOW MODEL AND MIGRATION FOR POST class Post < ActiveRecord::Base has_attached_file :photo validates_presence_of :body, :title has_many :comments, :dependent => :destroy has_many :tags, :dependent => :destroy has_many :ugtags, :dependent => :destroy has_many :votes, :dependent => :destroy belongs_to :user after_create :self_vote def self_vote # I am assuming you have a user_id field in `posts` and `votes` table. self.votes.create(:user => self.user) end cattr_reader :per_page @@per_page = 10 end migrations for post class CreatePosts < ActiveRecord::Migration def self.up create_table :posts do |t| t.string :title t.text :body t.timestamps end end def self.down drop_table :posts end end _ class AddUserIdToPost < ActiveRecord::Migration def self.up add_column :posts, :user_id, :string end def self.down remove_column :posts, :user_id end end

    Read the article

  • Active Directory - Query Group for all machines

    - by Ben Cawley
    Hi, I'm trying to obtain a list of all Machines that are members of a known group. I have the group GUID and am constructing a query using the "memberof=" format and filtering by ObjectClass. This works fine but doesn't return machines if the PrimaryGroup attribute of a machine is set to be the known group. In this case, that machine won't be returned. I've found the explanation of why this is in the following link (See Joe Kaplan's response) http://www.eggheadcafe.com/software/aspnet/29773581/active-directory-query-c.aspx Unfortunately the outlined answer is how to obtain the list of groups from a given user. I'd like to do the reverse and from a given group obtain the list of machines. It seems that the PrimaryGroup information is stored on the Machine/User side so I'm not sure if what I want to do is even possible. I had thought I would be able to query the TokenGroup attribute of the known group and then construct a query to return all machines that have the TokenGroup attribute set but it seems that not all groups have this attribute. Does anyone have any ideas or suggestions? If any clarification is needed let me know! Cheers, Ben

    Read the article

  • How to add a user to a SharePoint group programatically - Access is Denied

    - by Josh
    I have tried and tried to add a user to a SharePoint group using C# programatically (using a non-site admin). If I am logged in as a site admin, it works fine... but, if I am logged in as a non-site admin then I get an access is denied error. After doing some investigation I found that I needed to either "impersonate" the user (which didn't seem to work) or "ensure the user", so I have ended up at this code (which has worked for some people). Can some help explain to me why the following does not work and still gives me an Access is Denied error? SPSecurity.RunWithElevatedPrivileges(delegate() { using (SPSite site = new SPSite(SPControl.GetContextSite(HttpContext.Current).Url)) //have also tried passing in the ID - doesn't make a difference { using (SPWeb web = site.OpenWeb()) { web.AllowUnsafeUpdates = true; // add user to group SPGroup group = this.Web.Groups[groupList.Items[i].Value]; SPUser spUser = web.EnsureUser(provider + ":" + user.UserName); //provider is previously defined spUser.Email = user.Email; spUser.Name = txtFullName.Text; group.AddUser(spUser); // update group.Update(); } } }

    Read the article

  • sort the "rollup" in group by

    - by shantanuo
    I found that the "with rollup" option used with group by is very useful. But it does not behave with "order by" clause. Is there any way to order by the way I want as well as calculate the sub-totals? CREATE TABLE `mygroup` ( `id` int(11) default NULL, `country` varchar(100) default NULL ) ENGINE=MyISAM ; INSERT INTO `mygroup` VALUES (1,'India'),(5,'India'),(8,'India'),(18,'China'),(28,'China'),(28,'China'); mysql>select country, sum(id) from mygroup group by country with rollup; +---------+---------+ | country | sum(id) | +---------+---------+ | China | 74 | | India | 14 | | NULL | 88 | +---------+---------+ 3 rows in set (0.00 sec) mysql>select country, sum(id) as cnt from mygroup group by country order by cnt ; +---------+------+ | country | cnt | +---------+------+ | India | 14 | | China | 74 | +---------+------+ 2 rows in set (0.00 sec) mysql>select country, sum(id) as cnt from mygroup group by country with rollup order by cnt; ERROR 1221 (HY000): Incorrect usage of CUBE/ROLLUP and ORDER BY Expected Result: +---------+------+ | country | cnt | +---------+------+ | India | 14 | | China | 74 | | NULL | 88 | +---------+---------+ 3 rows in set (0.00 sec)

    Read the article

  • Windows 7 Printing to a network printer

    - by JohnyV
    We have a 2008 server as our print server. Clients that use windows xp with a logon script to map have no problems printing. When I test printing to a network printer on a windows 7 machine it works fine up to a few machines as soon As i get 12-15 workstations trying to print, when they log in they get the yellow exclamation mark and needs troubleshooting against the printer name. It is being deploy by group policy. I have tried to deploy it by group policy also by group policy preferences and by using a script and i get the same error whatever i try. Does anyone have any suggestions to try and troubleshoot? Once again Windows xp clients have no issues printing at all. It is only windows 7 clients. Thanks

    Read the article

  • How to stop a Linux LVM volume group?

    - by thkala
    I am currently dealing with a multiple disk failure on a Linux LVM Volume Group that is backed up by a RAID-5 md device. One disk has been taken out completely and another one is showing a limited number of corrupt sectors, due to what seems to have been a misbehaving power supply. The problem is that once an I/O error hits, md takes the array down, since it does not have enough devices for it to be operational. Where md the only one involved, I could mdadm --stop the array and then recreate it to get all devices active again. Unfortunately, the array is a PV in an LVM volume group and I cannot seem to get the kernel to release it. vgchange -an does not seem to do anything, bar spew out a couple of I/O errors. I am obviously missing something, but how in the name of -insert-favorite-deity- do I get LVM to release the underlying PV without rebooting the server?

    Read the article

  • Two people using the same computer at the same time remotely!

    - by Mani
    We have two computer in office and two people. My computer is much more faster than another computer. Is it possible my colleague connect to my computer remotely and work by my computer? Using "Remote Desktop" in Windows only one user can log into computer. So when he connect remotely, my user logged off. Is there a tool which can help in this case? I already knew VNC (RealVNC) But it's not helping because when a user connect to my computer, he see exactly my desktop, not his own user desktop.

    Read the article

  • Cannont add service account to domain group during sql cluster install

    - by Sam
    I'm installing a 2008 instance on a 2003 machine which is already running 2005. I need to set up domain groups for the security setup step: http://msdn.microsoft.com/en-us/library/ms179530.aspx On Windows Server 2003, specify domain groups for SQL Server services. All resource permissions are controlled by domain-level groups that include SQL Server service accounts as group members. Much more info on this here: http://support.microsoft.com/kb/910708 I've had problems with being able to add the windows service accounts to the groups at install time. The security admins had to make my account a domain admin - which they were hesitant to do. The account under which SQL Server Setup is running must have permissions to add accounts to the domain groups. Is there a specific security setting which would allow my account to add accounts to a group?

    Read the article

< Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >