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  • Is it possible to combine these 3 mySQL queries?

    - by Greenie
    I know the $downloadfile - and I want the $user_id. By trial and error I found that this does what I want. But it's 3 separate queries and 3 while loops. I have a feeling there is a better way. And yes, I only have a very little idea about what I'm doing :) $result = pod_query("SELECT ID FROM wp_posts WHERE guid LIKE '%/$downloadfile'"); while ($row = mysql_fetch_assoc($result)) { $attachment = $row['ID']; } $result = pod_query("SELECT pod_id FROM wp_pods_rel WHERE tbl_row_id = '$attachment'"); while ($row = mysql_fetch_assoc($result)) { $pod_id = $row['pod_id']; } $result = pod_query("SELECT tbl_row_id FROM wp_pods_rel WHERE tbl_row_id = '$pod_id' AND field_id = '28'"); while ($row = mysql_fetch_assoc($result)) { $user_id = $row['pod_id']; }

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  • How to make #include <mysql.h> work?

    - by symfony
    I'm building an open source project from source, and it need to include <mysql.h>: #if USE_MYSQL #include <mysql.h> #endif and the compilor reports: mysql.h no such file or directory MySQL is yet another greater open source project,what do I need to do to make it work?

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  • mysql query help, take total sum from a table, and based on discount value on another table calcula

    - by vegatron
    hi I have a table called invoices: CREATE TABLE IF NOT EXISTS `si_invoices` ( `id` int(10) NOT NULL AUTO_INCREMENT, `biller_id` int(10) NOT NULL DEFAULT '0', `customer_id` int(10) NOT NULL DEFAULT '0', `type_id` int(10) NOT NULL DEFAULT '0', `inv_tax_id` int(10) NOT NULL, `date` date NOT NULL DEFAULT '0000-00-00', `unreg_customer` tinyint(1) NOT NULL DEFAULT '0', `discount` decimal(10,2) NOT NULL DEFAULT '0.00', `discount_type` tinyint(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=20 ; each invoice has items that are stored in invoice_items table : CREATE TABLE IF NOT EXISTS `si_invoice_items` ( `id` int(10) NOT NULL AUTO_INCREMENT, `invoice_id` int(10) NOT NULL DEFAULT '0', `quantity` int(10) unsigned NOT NULL DEFAULT '0', `product_id` int(10) DEFAULT '0', `warehouse_id` int(10) NOT NULL, `unit_price` decimal(25,2) DEFAULT '0.00', `total` decimal(25,2) DEFAULT '0.00', `description` text, PRIMARY KEY (`id`), KEY `invoice_id` (`invoice_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=56 ; and tax table CREATE TABLE IF NOT EXISTS `si_tax` ( `tax_id` int(11) NOT NULL AUTO_INCREMENT, `tax_description` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL, `tax_percentage` decimal(25,6) DEFAULT '0.000000', `type` varchar(1) COLLATE utf8_unicode_ci DEFAULT NULL, `tax_enabled` varchar(1) COLLATE utf8_unicode_ci NOT NULL DEFAULT '1', PRIMARY KEY (`tax_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=5 ; here is what I want to do step 1: get the sum_total of the invoice Items for a speciefic invoice step 2: calculate the discount, in the invoice table I have a discount_type field : if its equal to 0 , then there will be no discount if its equal to 1 , the discount value will be stored in the discount field if its equal to 2 , the discount is a percentage of sum_total step 3: calculate the taxes based on inv_tax_id based on the tax id , I will look in the tax table , get the tax_percentage and multiply it by the (sum_total - discount) in short here is the equation $gross_total = $sum_total - $disount + taxes

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • MySQL: Is it faster to use inserts and updates instead of insert on duplicate key update?

    - by Nir
    I have a cron job that updates a large number of rows in a database. Some of the rows are new and therefore inserted and some are updates of existing ones and therefore update. I use insert on duplicate key update for the whole data and get it done in one call. But- I actually know which rows are new and which are updated so I can also do inserts and updates seperately. Will seperating the inserts and updates have advantage in terms of performance? What are the mechanics behind this ? Thanks!

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  • question about MySQL transaction and trigger

    - by WilliamLou
    I quickly browsed MySQL manual but didn't find the exact information about my question. Here is my question: if I have a InnoDB table A with two triggers triggered by 'AFTER INSERT ON A' and 'AFTER UPDATE ON A'. More specifically, For example: one trigger is defined as: CREATE TRIGGER test_trigger AFTER INSERT ON A FOR EACH ROW BEGIN INSERT INTO B SELECT * FROM A WHERE A.col1 = NEW.col1 END; You can ignore the query between BEGIN AND END, basically I mean this trigger will insert several rows into table B which is also a InnoDB table. Now, if I started a transaction and then insert many rows, say: 10K rows, into table A. If there is no trigger associated with table A, all these inserts are atomic, that's for sure. Now, if table A is associated with several insert/update triggers which insert/update many rows to table B and/or table C etc.. will all these inserts and/or updates are still all atomic? I think it's still atomic, but it's kind of difficult to test and I can't find any explanations in the Manual. Anyone can confirm this? Thanks a lot!

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  • Error No 150 mySQL

    - by buddhamagnet
    Hi all. This is making me sweat - I am getting error 150 when I try and create a table in mySQL. I've scoured the forums to no avail. The statement uses foreign key constraints - both tables are InnoDB, all relevant columns have the same data type and both tables have the same charset and collation. Here's the CREATE TABLE and the original CREATE TABLE statement for the table that's being referenced. Any ideas? New table: CREATE TABLE `approval` ( `rev_id` int(10) UNSIGNED NOT NULL, `rev_page` int(10) UNSIGNED NOT NULL, `user_id` int(10) UNSIGNED NOT NULL, `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`rev_id`,`rev_page`,`user_id`), KEY `FK_approval_user` (`user_id`), CONSTRAINT `FK_approval_revision` FOREIGN KEY (`rev_id`, `rev_page`) REFERENCES `revision` (`rev_id`, `rev_page`), CONSTRAINT `FK_approval_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Referenced table: CREATE TABLE `revision` ( `rev_id` int(10) unsigned NOT NULL auto_increment, `rev_page` int(10) unsigned NOT NULL, `rev_text_id` int(10) unsigned NOT NULL, `rev_comment` tinyblob NOT NULL, `rev_user` int(10) unsigned NOT NULL default '0', `rev_user_text` varbinary(255) NOT NULL default '', `rev_timestamp` binary(14) NOT NULL default '\0\0\0\0\0\0\0\0\0\0\0\0\0\0', `rev_minor_edit` tinyint(3) unsigned NOT NULL default '0', `rev_deleted` tinyint(3) unsigned NOT NULL default '0', `rev_len` int(10) unsigned default NULL, `rev_parent_id` int(10) unsigned default NULL, PRIMARY KEY (`rev_id`), UNIQUE KEY `rev_page_id` (`rev_page`,`rev_id`), KEY `rev_timestamp` (`rev_timestamp`), KEY `page_timestamp` (`rev_page`,`rev_timestamp`), KEY `user_timestamp` (`rev_user`,`rev_timestamp`), KEY `usertext_timestamp` (`rev_user_text`,`rev_timestamp`) ) ENGINE=InnoDB AUTO_INCREMENT=4904 DEFAULT CHARSET=binary MAX_ROWS=10000000 AVG_ROW_LENGTH=1024;

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  • Can you reuse a mysql result set in PHP?

    - by MarathonStudios
    I have a result set I pull from a large database: $result = mysql_query($sql); I loop through this recordset once to pull specific bits of data and get averages using while($row = mysql_fetch_array($result)). Later in the page, I want to loop through this same recordset again and output everything - but because I used the recordset earlier, my second loop returns nothing. I finally hacked around this by looping through a second identical recordset ($result2 = mysql_query($sql);), but I hate to make the same SQL call twice. Any way I can loop through the same dataset multiple times?

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  • Can not set password for mysql server in cent os 6.2

    - by HarshanaD
    I have installed mysql and then mysql-server. Then i start the mysql demon and follow below steps, # chkconfig --level 2345 mysqld on # mysqladmin -u root password testpassword But i can not set the password because it gives me the below error, Access denied for user root@localhost (using password: no) I logged in as root user and perform those steps. I even uninstalled mysql server and reinstalled but same problem occurred.

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  • MySql selecting default value if there are no result?

    - by Kenan
    i'm having 2 tables: members and comments. I select all members, and then join comments. But in comments I'm selecting some SUM of points, and if user never commented, I can't get that user in listing?! So how to select default value for SUM, or some other solution: SELECT c.comment_id AS item_id, m.member_id AS member_id, m.avatar, SUM(c.vote_value) AS vote_value, SUM(c.best) AS best, SUM(c.vote_value) + SUM(c.najbolji)*10 AS total FROM members m LEFT JOIN comments c ON m.member_id = c.author_id GROUP BY c.author_id ORDER BY m.member_id DESC LIMIT {$sql_start}, {$sql_pokazi}

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  • Ordering by number of rows?

    - by Rob
    Alright, so I have a table outputting data from a MySQL table in a while loop. Well one of the columns it outputs isn't stored statically in the table, instead it's the sum of how many times it appears in a different MySQL table. Sorry I'm not sure this is easy to understand. Here's my code: $query="SELECT * FROM list WHERE added='$addedby' ORDER BY time DESC"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $loghwid = $row['hwid']; $sql="SELECT * FROM logs WHERE hwid='$loghwid' AND time < now() + interval 1 hour"; $query = mysql_query($sql) OR DIE(mysql_error()); $boots = mysql_num_rows($query); //Display the table } The above is the code displaying the table. As you can see it's grabbing data from two different MySQL tables. However I want to be able to ORDER BY $boots DESC. But as its a counting of a completely different table, I have no idea of how to go about doing that. I would appreciate any help, thank you.

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  • mysql join with conditional

    - by Conor H
    Hi There, I am currently working on a MySQL query that contains a table: TBL:lesson_fee -fee_type_id (PRI) -lesson_type_id (PRI) -lesson_fee_amount this table contains the fees for a particular 'lesson type' and there are different 'fee names' (fee_type). Which means that there can be many entries in this table for one 'lesson type' In my query I am joining this table onto the rest of the query via the 'lesson_type' table using: lesson_fee INNER JOIN (other joins here) ON lesson_fee.lesson_type_id = lesson_type.lesson_type_id The problem with this is that it is currently returning duplicate data in the result. 1 row for every duplicate entry in the 'lesson fee' table. I am also joining the 'fee type' table using this 'fee_type_id' Is there a way of telling MySQL to say "Join the lesson_fee table rows that have lesson_fee.lesson_type_id and fee_type_id = client.fee_type_id". UPDATE: Query: SELECT lesson_booking.lesson_booking_id,lesson_fee.lesson_fee_amount FROM fee_type INNER JOIN (lesson_fee INNER JOIN (color_code INNER JOIN (employee INNER JOIN (horse_owned INNER JOIN (lesson_type INNER JOIN (timetable INNER JOIN (lesson_booking INNER JOIN CLIENT ON client.client_id = lesson_booking.client_id) ON lesson_booking.timetable_id = timetable.timetable_id) ON lesson_type.lesson_type_id = timetable.lesson_type_id) ON horse_owned.horse_owned_id = lesson_booking.horse_owned_id) ON employee.employee_id = timetable.employee_id) ON employee.color_code_id = color_code.color_code_id) ON lesson_fee.lesson_type_id = lesson_type.lesson_type_id) ON lesson_fee.fee_type_id = client.fee_type_id WHERE booking_date = '2010-04-06' ORDER BY lesson_booking_id ASC How do I keep the format(indentation) of my query?

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  • BackUp MySql Database from CommandLine

    - by srk
    I am able to backup mysql database via command line by executing the below : C:\MySQL\MySQL Server 5.0\bin\mysqldump\" -uroot -ppassword sample \"D:/admindb/AAR12.sql\" But there is no DROP and CREATE database queries in my .mysql file What should i add in the syntax to get the create info to my generated .sql file ?

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  • Rotate a table in word

    - by Jake Pearson
    I have a word 2007 document in portrait mode. I have a table that is too wide to fit in 8.5" but would fit in 11". Is there a way to make just one page landscape? Or alternately is there a way to rotate a table 90 degrees?

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  • MySQL Table does not support optimize

    - by Dscoduc
    My Wordpress tables appear to be in need of optimization so I looked into the commmand OPTIMIZE TABLE . When I run the command I get the following results: Table does not support optimize, doing recreate + analyze instead The tables are built using the Wordpress 2.91 installer and haven't been modified at all. Is this normal? How can I optimize my database to keep things working correctly?

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  • Phpmyadmin mysql foreign key problem

    - by alan
    Hey guys i'm using phpmyadmin (php & mysql) and i'm having alot of trouble linking the tables using foreign keys. I'm getting negative values for the field countyId (which is the foriegn key). However it is linking to my other table fine and it's cascading fine. So when I go to add data there will be a drop box for the CountyId and the values will look something like this, " -1 1- " Here is my alter statement, ALTER TABLE Baronies ADD FOREIGN KEY (CountyId) REFERENCES Counties (CountyId) ON DELETE CASCADE

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  • Excel, Pivot table, Relocate Filters on the worksheet

    - by Maria
    Hej, In my worksheet where i have my pivot table i have many different filters to chose between. For the view of the eye it doesnt really look nice and i want to be able to maybe split tha t long list of filters into a few shorter once. But i cant figure out how to do this. Ive seen where i can move the whole pivot table, but then its all included and as one unsplitable piece.... anyone knows if this is possible??

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  • MySQL: Creating table with FK error (errno 150)

    - by Peter Bailey
    I've tried searching on this error and nothing I've found helps me, so I apologize in advance if this is a duplicate and I'm just too dumb to find it. I've created a model with MySQL Workbench and am now attempting to install it to a mysql server. Using File Export Forward Engineer SQL CREATE Script... it outputs a nice big file for me, with all the settings I ask for. I switch over to MySQL GUI Tools (the Query Browser specifically) and load up this script (note that I'm going form one official MySQL tool to another). However, when I try to actually execute this file, I get the same error over and over SQLSTATE[HY000]: General error: 1005 Can't create table './srs_dev/location.frm' (errno: 150) "OK", I say to myself, something is wrong with the location table. So I check out the definition in the output file. SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; -- ----------------------------------------------------- -- Table `state` -- ----------------------------------------------------- DROP TABLE IF EXISTS `state` ; CREATE TABLE IF NOT EXISTS `state` ( `state_id` INT NOT NULL AUTO_INCREMENT , `iso_3166_2_code` VARCHAR(2) NOT NULL , `name` VARCHAR(60) NOT NULL , PRIMARY KEY (`state_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `brand` -- ----------------------------------------------------- DROP TABLE IF EXISTS `brand` ; CREATE TABLE IF NOT EXISTS `brand` ( `brand_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(45) NOT NULL , `domain` VARCHAR(45) NOT NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , PRIMARY KEY (`brand_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `location` -- ----------------------------------------------------- DROP TABLE IF EXISTS `location` ; CREATE TABLE IF NOT EXISTS `location` ( `location_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(255) NOT NULL , `address_line_1` VARCHAR(255) NULL , `address_line_2` VARCHAR(255) NULL , `city` VARCHAR(100) NULL , `state_id` TINYINT UNSIGNED NULL DEFAULT NULL , `postal_code` VARCHAR(10) NULL , `phone_number` VARCHAR(20) NULL , `fax_number` VARCHAR(20) NULL , `lat` DECIMAL(9,6) NOT NULL , `lng` DECIMAL(9,6) NOT NULL , `contact_url` VARCHAR(255) NULL , `brand_id` TINYINT UNSIGNED NOT NULL , `summer_hours` VARCHAR(255) NULL , `winter_hours` VARCHAR(255) NULL , `after_hours_emergency` VARCHAR(255) NULL , `image_file_name` VARCHAR(100) NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , `created_date` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`location_id`) , CONSTRAINT `fk_location_state` FOREIGN KEY (`state_id` ) REFERENCES `state` (`state_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `fk_location_brand` FOREIGN KEY (`brand_id` ) REFERENCES `brand` (`brand_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; CREATE INDEX `fk_location_state` ON `location` (`state_id` ASC) ; CREATE INDEX `fk_location_brand` ON `location` (`brand_id` ASC) ; CREATE INDEX `idx_lat` ON `location` (`lat` ASC) ; CREATE INDEX `idx_lng` ON `location` (`lng` ASC) ; Looks ok to me. I surmise that maybe something is wrong with the Query Browser, so I put this file on the server and try to load it this way ] mysql -u admin -p -D dbname < path/to/create_file.sql And I get the same error. So I start to Google this issue and find all kinds of accounts that talk about an error with InnoDB style tables that fail with foreign keys, and the fix is to add "SET FOREIGN_KEY_CHECKS=0;" to the SQL script. Well, as you can see, that's already part of the file that MySQL Workbench spat out. So, my question is then, why is this not working when I'm doing what I think I'm supposed to be doing? Version Info: # MySQL: 5.0.45 GUI Tools: 1.2.17 Workbench: 5.0.30

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  • Late feedback

    - by Sveta Smirnova
    MySQL Community team asked me to write about Devconf 2013 few months ago. Conference was in June, 2013, but I remembered about this my promise only now: month later after my participating in MySQL Connect and Expert Troubleshooting seminar (change country to United Kingdom if you see blank page). I think it is too late for the feedback, but I still have few thoughts which I want to record.DevConf (former PHPConf) always was a place where I tried new topics. At first, because I know audience there very well and they will be bored if I repeat a story which I was telling last year, but also because it is much easier to get feedback in your own native language. But last years my habit seems started to change and I presented improved version of my 2012 MySQL Connect talk about MySQL backups. Of course, I also had a seminar with unique topic, made for this conference first time: Troubleshooting MySQL Performance with EXPLAIN and Using Performance Schema to Troubleshoot MySQL. And these topics, improved, were presented at the expert seminar. It is interesting how my habit changes and one public speaking activity interferes next one.What is good about DevConf is it forces you to create new ideas and do it really well, because audience is not forgiving at all, so they catch everything you miss or prepared not good enough. This can be bad if you want to make a marketing-style topic for free, but allows to present technical features in really good details: all these sudden discussions really help.In year 2013 Oracle had a booth at the conference and was presented by a bunch of people. Dmitry Lenev presented topic "New features of replication in MySQL 5.6" and Victoria Reznichenko worked on the booth. What was new at the conference this year is greater interest in NoSQL, scale and fast development solutions. This, unfortunately, means not so huge interest in MySQL as it was earlier. However, at the same time, "Common" track was really MySQL track: not only Oracle, but people from other companies presented about it.

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  • Only first table in create table statement being created

    - by Craig
    The table "credentials" does show up in the adb shell. I've checked logcat and it doesn't seem to report a problem... private static final String DATABASE_CREATE = "create table credentials (_id integer primary key autoincrement, " + "username text not null, password text not null, " + "lastupdate text);" + "create table user (_id integer primary key autoincrement, " + "firstname text not null, " + "lastname text not null);" + "create table phone (_phoneid integer primary key autoincrement, " + "userid integer not null, phonetype text not null, " + "phonenumber text not null);" + "create table email (_emailid integer primary key autoincrement, " + "userid integer not null, emailtype text not null, " + "emailaddress text not null);" + "create table address (_addressid integer primary key autoincrement," + "userid integer not null, addresstype text not null, " + "address text not null);" + "create table instantmessaging (_imid integer primary key autoincrement, " + "userid integer not null, imtype text not null, " + "imaccount text not null);"; I've been pouring over this and I bet its some silly syntax typo! Or, at least I hope it is something trivial ;-) Craig

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  • How to display SUM fields from a detailed table in a master table

    - by max
    What is the best approach to display the summery of DETAILED.Fields in its master table? E.g. I have a master table called 'BILL' with all the bill related data and a detailed table ('BILL_DETAIL') with the bill detailed related data, like NAME, PRICE, TAX, ... Now I want to list all BILLS, without the details, but with the sum of the PRICE and TAX stored in the detail table. Here is a simplified schema of that tables: TABLE BILL ---------- - ID - NAME - ADDRESS - ... TABLE BILL_DETAIL ----------------- - ID - BILLID - PORDUCT_NAME - PRICE - TAX - ... The retrieved table row should look like this: BILL.CUSTOMER_NAME, BILL.CUSTOMER_ADDRESS, sum(BILL_DETAIL.PRICE), sum(BILL.DETAIL.TAX), ... Any sugguestions?

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