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  • Getting shortest path between 2 nodes in quickgraph

    - by Xtapodi
    Hello, i want to ask if there is any way to generate the shortest path from node A to node B without generating the shortest paths to all the other nodes (stop when node B is in the examined set) with A-star in QuickGraph. I want to plug QuickGraph into a game and thus generating all the paths is not allowed from the time limitations the environment imposes. Any other suggestions to solve my problem in C# are welcome Thanks in advance, Xtapodi

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  • How to display the data of DOM parsed attributes in the listView display ?

    - by Praween k
    Hi, I am building a test output for DOM parser with node "Rider" and within that 7 attributes are there.URL://http://ps700.pranasystems.com/tours/8/xml/results/stage1results.xml. I want to display only the "name" and the "team" attributes output in the listview mode of the device.I am not getting clear where to store the output to display. Please help me someone for how to store and display that data to the output of the device in List view. Thanks in advance //-------------------------------// Here is my code------------// public String getSearch(String strURL) { URL url; URLConnection urlConn = null; NamedNodeMap nnm = null; int len; try { url = new URL(strURL); urlConn = url.openConnection(); } catch (IOException ioe) { Log.e("Could not Connect: "+ioe.getMessage(), "."); } DocumentBuilder builder = null ; Document doc = null ; try { DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); doc = db.parse(urlConn.getInputStream()); Node thisNode, currentNode, node,theAttribute ; NodeList nchild, nodeList; String name; ArrayList<Node> result = new ArrayList<Node>(); nodeList = doc.getElementsByTagName("rider"); int length = nodeList.getLength(); for (int i = 0; i < length; i++) { currentNode = nodeList.item(i); NamedNodeMap attributes = currentNode.getAttributes(); Log.i("TAG", attributes.toString()); for (int a = 0; a < attributes.getLength(); a++) { theAttribute = attributes.item(a); } // s1.setAdapter(new ArrayAdapter<Node>(this, // android.R.layout.simple_list_item_1,result)); }catch(ParserConfigurationException pce ){ Log.e("Could not Parse XML:" +pce.getMessage() ,"."); } catch (SAXException se) {Log.e("Could not Parse XML: "+se.getMessage(), ".");} catch (IOException ioe) {Log.e("Invalid XML: "+ioe.getMessage(), ".");} return strURL; }

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  • how to avoid 'out of memory' errors when programmatically generating a lot of nodes in drupal?

    - by sprugman
    I'm creating about 150 nodes programmatically and running into 'out of memory' errors when doing it all in a single request. (I have a menu callback that generates the nodes and calls node_save() on them.) Example: for($i=0; $i<150; $i++) { $node = new stdClass(); $node->title="Foo $i"; $node->field_myfield[0]['value'] = "Bar $i"; ... node_save($node); } I've heard of BatchAPI, but never used it. Is that the right tool to get around this? The docs talk about timeouts, but not memory issues. Is there something simpler that I might be missing?

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  • Does this data structure have a name? Sort of a "linked matrix"?

    - by Bob
    Let's say I wanted similar functionality to a doubly linked list but needed a matrix instead so that each node was structured like this: public class Node { Node Up, Down, Left, Right; object Value; } Is there a name for such a structure? I've looked through this Wikipedia listing of data structures but didn't see anything similar. Unless I just missed it.

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  • Remove Empty Attributes from XML

    - by er4z0r
    Hi, I have a buggy xml that contains empty attributes and I have a parser that coughs on empty attributes. I have no control over the generation of the xml nor over the parser that coughs on empty attrs. So what I want to do is a pre-processing step that simply removes all empty attributes. I have managed to find the empty attribus, but now I don't know how to remove them: XPathFactory xpf = XPathFactory.newInstance(); XPath xpath = xpf.newXPath(); XPathExpression expr = xpath.compile("//@*"); Object result = expr.evaluate(d, XPathConstants.NODESET); if (result != null) { NodeList nodes = (NodeList) result; for(int node=0;node<nodes.getLength();node++) { Node n = nodes.item(node); if(isEmpty(n.getTextContent())) { this.log.warn("Found empty attribute declaration "+n.toString()); NamedNodeMap parentAttrs = n.getParentNode().getAttributes(); parentAttrs.removeNamedItem(n.getNodeName()); } } } This code gives me a NPE when accessing n.getParentNode().getAttributes(). But how can I remove the empty attribute from an element, when I cannot access the element?

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  • ViewModel Views relation/link/syncroniztion

    - by mehran
    Third try to describing problem: Try 1: Sunchronizing view model and view Try2: WPF ViewModel not active presenter Try3: I have some class for view models: public class Node : INotifyPropertyChanged { Guid NodeId { get; set; } public string Name { get; set; } } public class Connection: INotifyPropertyChanged { public Node StartNode { get; set; } public Node EndNode { get; set; } } public class SettingsPackModel { public List<Node> Nodes { get; private set; } public List<Connection> Connections { get; private set; } } I also have some templates to displays these models: <DataTemplate DataType="{x:Type vm:Node}">…</DataTemplate> <DataTemplate DataType="{x:Type vm:Connection}"> <my:ConnectionElment StartNodeElment="???" EndNodeElment="???"> </my:ConnectionElment> <DataTemplate> But the problem is that DataTemplate for Connection need reference ot two element of type UIElement , how can I pass these two, how can I fill ??? in above expression?

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  • Drupal: assign block to a specific content type

    - by bert
    I made a customized template called node-mynode.tpl.php Whenever a node of type mynode is requested, then node-mynode.tpl.php is automatically used. However, now user wants to see a specific menu block in this case. Question: How can I assign a block to a specific content type? Hint: I have started to look at URL aliases with Pathauto. I suspect one solution may lie in this direction.

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  • Scaling Java applications - existing cluster-aware IoC frameworks?

    - by Zoltan
    Most people use some kind of an IoC framework - Guice, Spring, you name it. Many of us need to scale their applications too, so they complicate their lifes with Terracotta, Glassfish/JBoss/insertyourfavouritehere clusters. But is it really the way to go? Are you using any of the above? Here's some ideas we currently have implemented in a yet-to-be-opensourced framework, and I'd like to see what you think of it, or maybe "it's a complete ripoff of XY!". cluster-wide object replication - give it a name, and whenever you do something (in any node) on such an object, it will get replicated - with different guarantees do transparent soft-loadbalancing - simplest scenario: restful webservice method call proxied to an other node view-only node injection: inject a proxy to a "named" object, and get your calls automatically proxied to a node Would you use something like that? Is there a current, stable, enterprise-ready implementation out there?

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  • How change Castor mapping to remove "xmlns:xsi" and "xsi:type" attributes from element in XML output

    - by Derek Mahar
    How do I change the Castor mapping <?xml version="1.0"?> <!DOCTYPE mapping PUBLIC "-//EXOLAB/Castor Mapping DTD Version 1.0//EN" "http://castor.org/mapping.dtd"> <mapping> <class name="java.util.ArrayList" auto-complete="true"> <map-to xml="ArrayList" /> </class> <class name="com.db.spgit.abstrack.ws.response.UserResponse"> <map-to xml="UserResponse" /> <field name="id" type="java.lang.String"> <bind-xml name="id" node="element" /> </field> <field name="deleted" type="boolean"> <bind-xml name="deleted" node="element" /> </field> <field name="name" type="java.lang.String"> <bind-xml name="name" node="element" /> </field> <field name="typeId" type="java.lang.Integer"> <bind-xml name="typeId" node="element" /> </field> <field name="regionId" type="java.lang.Integer"> <bind-xml name="regionId" node="element" /> </field> <field name="regionName" type="java.lang.String"> <bind-xml name="regionName" node="element" /> </field> </class> </mapping> to suppress the xmlns:xsi and xsi:type attributes in the element of the XML output? For example, instead of the output XML <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="UserResponse"> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> I'd prefer <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> such that the element name implies the xsi:type.

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  • How to remove all comment tags from XmlDocument

    - by Filburt
    How would i go about to remove all comment tags from a XmlDocument instance? Is there a better way than retrieving a XmlNodeList and iterate over those? XmlNodeList list = xmlDoc.SelectNodes("//comment()"); foreach(XmlNode node in list) { node.ParentNode.RemoveChild(node); }

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  • How to integrate an dynamically generated JSON Object into an other object?

    - by Marco Ciarfaglia
    How can I put this JSON Object in the function or object below? // this function generates an JSON Object dynamically $(".n_ListTitle").each(function(i, v) { var node = $(this); var nodeParent = node.parent(); var nodeText = node.text(); var nodePrice = node.siblings('.n_ListPrice'); var prodPrice = $(nodePrice).text(); var prodId = nodeParent.attr('id').replace('ric', ''); var prodTitle = nodeText; var json = { id : prodId, price : prodPrice, currency : "CHF", name : prodTitle }; return json; }); TDConf.Config = { products : [ // here should be inserted the JSON Object {id: "[product-id1]", price:"[price1]", currency:"[currency1]", name:"[product-name1]"}, {id: "[product-id2]", price:"[price2]", currency:"[currency2]", name:"[product-name2]"}, ... })], containerTagId :"..." }; If it is not understandable please ask :) Thanks in advance for helping me to figure out!

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  • [C#] Problems with implementing generic IEnumerator and IComparable

    - by r0h
    Hi all! I'm working on an AVL Tree. The tree itself seems to be working but I need a iterator to walk through the values of the tree. Therefore I tried to implement the IEnumerator interace. Unfortunately I get a compile time error implementing IEnumerator and IComparable. First the code and below that the error. class AvlTreePreOrderEnumerator<T> : IEnumerator<T> where T :IComparable<T> { private AvlTreeNode<T> current = default(T); private AvlTreeNode<T> tree = null; private Queue<AvlTreeNode<T>> traverseQueue = null; public AvlTreePreOrderEnumerator(AvlTreeNode<T> tree) { this.tree = tree; //Build queue traverseQueue = new Queue<AvlTreeNode<T>>(); visitNode(this.tree.Root); } private void visitNode(AvlTreeNode<T> node) { if (node == null) return; else { traverseQueue.Enqueue(node); visitNode(node.LeftChild); visitNode(node.RightChild); } } public T Current { get { return current.Value; } } object IEnumerator.Current { get { return Current; } } public void Dispose() { current = null; tree = null; } public void Reset() { current = null; } public bool MoveNext() { if (traverseQueue.Count > 0) current = traverseQueue.Dequeue(); else current = null; return (current != null); } } The error given by VS2008: Error 1 The type 'T' cannot be used as type parameter 'T' in the generic type or method 'Opdr2_AvlTreeTest_Final.AvlTreeNode'. There is no boxing conversion or type parameter conversion from 'T' to 'System.IComparable'. For now I've not included the tree and node logic. I anybody thinks is necessary to resolve this probleem, just say so! Thx!

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  • More localized, efficient Lowest Common Ancestor algorithm given multiple binary trees?

    - by mstksg
    I have multiple binary trees stored as an array. In each slot is either nil (or null; pick your language) or a fixed tuple storing two numbers: the indices of the two "children". No node will have only one child -- it's either none or two. Think of each slot as a binary node that only stores pointers to its children, and no inherent value. Take this system of binary trees: 0 1 / \ / \ 2 3 4 5 / \ / \ 6 7 8 9 / \ 10 11 The associated array would be: 0 1 2 3 4 5 6 7 8 9 10 11 [ [2,3] , [4,5] , [6,7] , nil , nil , [8,9] , nil , [10,11] , nil , nil , nil , nil ] I've already written simple functions to find direct parents of nodes (simply by searching from the front until there is a node that contains the child) Furthermore, let us say that at relevant times, both all trees are anywhere between a few to a few thousand levels deep. I'd like to find a function P(m,n) to find the lowest common ancestor of m and n -- to put more formally, the LCA is defined as the "lowest", or deepest node in which have m and n as descendants (children, or children of children, etc.). If there is none, a nil would be a valid return. Some examples, given our given tree: P( 6,11) # => 2 P( 3,10) # => 0 P( 8, 6) # => nil P( 2,11) # => 2 The main method I've been able to find is one that uses an Euler trace, which turns the given tree, with a node A to be the invisible parent of 0 and 1 with a depth of -1, into: A-0-2-6-2-7-10-7-11-7-2-0-3-0-A-1-4-1-5-8-5-9-5-1-A And from that, simply find the node between your given m and n that has the lowest number; For example, to find P(6,11), look for a 6 and an 11 on the trace. The number between them that is the lowest is 2, and that's your answer. If A is in between them, return nil. -- Calculating P(6,11) -- A-0-2-6-2-7-10-7-11-7-2-0-3-0-A-1-4-1-5-8-5-9-5-1-A ^ ^ ^ | | | m lowest n Unfortunately, I do believe that finding the Euler trace of a tree that can be several thousands of levels deep is a bit machine-taxing...and because my tree is constantly being changed throughout the course of the programming, every time I wanted to find the LCA, I'd have to re-calculate the Euler trace and hold it in memory every time. Is there a more memory efficient way, given the framework I'm using? One that maybe iterates upwards? One way I could think of would be the "count" the generation/depth of both nodes, and climb the lowest node until it matched the depth of the highest, and increment both until they find someone similar. But that'd involve climbing up from level, say, 3025, back to 0, twice, to count the generation, and using a terribly inefficient climbing-up algorithm in the first place, and then re-climbing back up. Are there any other better ways?

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  • why it throws index out of bounds exception??

    - by Johanna
    Hi I want to use merge sort for sorting my doubly linked list.I have created 3 classes(Node,DoublyLinkedList,MergeSort) but it will throw this exception for these lines: 1.in the getNodes method of DoublyLinkedList---> throw new IndexOutOfBoundsException(); 2.in the add method of DoublyLinkedList-----> Node cursor = getNodes(index); 3.in the sort method of MergeSort class------> listTwo.add(x,localDoublyLinkedList.getValue(x)); 4.in the main method of DoublyLinkedList----->merge.sort(); this is my Merge class:(I put the whole code for this class for beter understanding) public class MergeSort { private DoublyLinkedList localDoublyLinkedList; public MergeSort(DoublyLinkedList list) { localDoublyLinkedList = list; } public void sort() { if (localDoublyLinkedList.size() <= 1) { return; } DoublyLinkedList listOne = new DoublyLinkedList(); DoublyLinkedList listTwo = new DoublyLinkedList(); for (int x = 0; x < (localDoublyLinkedList.size() / 2); x++) { listOne.add(x, localDoublyLinkedList.getValue(x)); } for (int x = (localDoublyLinkedList.size() / 2) + 1; x < localDoublyLinkedList.size(); x++) { listTwo.add(x, localDoublyLinkedList.getValue(x)); } //Split the DoublyLinkedList again MergeSort sort1 = new MergeSort(listOne); MergeSort sort2 = new MergeSort(listTwo); sort1.sort(); sort2.sort(); merge(listOne, listTwo); } public void merge(DoublyLinkedList a, DoublyLinkedList b) { int x = 0; int y = 0; int z = 0; while (x < a.size() && y < b.size()) { if (a.getValue(x) < b.getValue(y)) { localDoublyLinkedList.add(z, a.getValue(x)); x++; } else { localDoublyLinkedList.add(z, b.getValue(y)); y++; } z++; } //copy remaining elements to the tail of a[]; for (int i = x; i < a.size(); i++) { localDoublyLinkedList.add(z, a.getValue(i)); z++; } for (int i = y; i < b.size(); i++) { localDoublyLinkedList.add(z, b.getValue(i)); z++; } } } and just a part of my DoublyLinkedList: private Node getNodes(int index) throws IndexOutOfBoundsException { if (index < 0 || index > length) { throw new IndexOutOfBoundsException(); } else { Node cursor = head; for (int i = 0; i < index; i++) { cursor = cursor.getNext(); } return cursor; } } public void add(int index, int value) throws IndexOutOfBoundsException { Node cursor = getNodes(index); Node temp = new Node(value); temp.setPrev(cursor); temp.setNext(cursor.getNext()); cursor.getNext().setPrev(temp); cursor.setNext(temp); length++; } public static void main(String[] args) { int i = 0; i = getRandomNumber(10, 10000); DoublyLinkedList list = new DoublyLinkedList(); for (int j = 0; j < i; j++) { list.add(j, getRandomNumber(10, 10000)); MergeSort merge = new MergeSort(list); merge.sort(); System.out.println(list.getValue(j)); } } PLEASE help me thanks alot.

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  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

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  • How to return array of C++ objects from a PHP extension

    - by John Factorial
    I need to have my PHP extension return an array of objects, but I can't seem to figure out how to do this. I have a Graph object written in C++. Graph.getNodes() returns a std::map<int, Node*>. Here's the code I have currently: struct node_object { zend_object std; Node *node; }; zend_class_entry *node_ce; then PHP_METHOD(Graph, getNodes) { Graph *graph; GET_GRAPH(graph, obj) // a macro I wrote to populate graph node_object* n; zval* node_zval; if (obj == NULL) { RETURN_NULL(); } if (object_init_ex(node_zval, node_ce) != SUCCESS) { RETURN_NULL(); } std::map nodes = graph-getNodes(); array_init(return_value); for (std::map::iterator i = nodes.begin(); i != nodes.end(); ++i) { php_printf("X"); n = (node_object*) zend_object_store_get_object(node_zval TSRMLS_CC); n-node = i-second; add_index_zval(return_value, i-first, node_zval); } php_printf("]"); } When i run php -r '$g = new Graph(); $g->getNodes();' I get the output XX]Segmentation fault meaning the getNodes() function loops successfully through my 2-node list, returns, then segfaults. What am I doing wrong?

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  • C++ Linked List - Reading data from a file with a sentinel

    - by Nick
    So I've done quite a bit of research on this and can't get my output to work correctly. I need to read in data from a file and have it stored into a Linked List. The while loop used should stop once it hits the $$$$$ sentinel. Then I am to display the data (by searching by ID Number[user input]) I am not that far yet I just want to properly display the data and get it read in for right now. My problem is when it displays the data is isn't stopping at the $$$$$ (even if I do "inFile.peek() != EOF and omit the $$$$$) I am still getting an extra garbage record. I know it has something to do with my while loop and how I am creating a new Node but I can't get it to work any other way. Any help would be appreciated. students.txt Nick J Cooley 324123 60 70 80 90 Jay M Hill 412254 70 80 90 100 $$$$$ assign6.h file #pragma once #include <iostream> #include <string> using namespace std; class assign6 { public: assign6(); // constructor void displayStudents(); private: struct Node { string firstName; string midIni; string lastName; int idNum; int sco1; //Test score 1 int sco2; //Test score 2 int sco3; //Test score 3 int sco4; //Test score 4 Node *next; }; Node *head; Node *headPtr; }; assign6Imp.cpp // Implementation File #include "assign6.h" #include <fstream> #include <iostream> #include <string> using namespace std; assign6::assign6() //constructor { ifstream inFile; inFile.open("students.txt"); head = NULL; head = new Node; headPtr = head; while (inFile.peek() != EOF) //reading in from file and storing in linked list { inFile >> head->firstName >> head->midIni >> head->lastName; inFile >> head->idNum; inFile >> head->sco1; inFile >> head->sco2; inFile >> head->sco3; inFile >> head->sco4; if (inFile != "$$$$$") { head->next = NULL; head->next = new Node; head = head->next; } } head->next = NULL; inFile.close(); } void assign6::displayStudents() { int average = 0; for (Node *cur = headPtr; cur != NULL; cur = cur->next) { cout << cur->firstName << " " << cur->midIni << " " << cur->lastName << endl; cout << cur->idNum << endl; average = (cur->sco1 + cur->sco2 + cur->sco3 + cur->sco4)/4; cout << cur->sco1 << " " << cur->sco2 << " " << cur->sco3 << " " << cur->sco4 << " " << "average: " << average << endl; } }

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  • How to stop Zend Framework from appending '/scripts/' to the View Base Path

    - by Hannes
    Thats basically my code (simplified): class IndexController extends Zend_Controller_Action { public function indexAction(){ $this->view->setBasePath(APPLICATION_PATH . '/views/partner/xyz/'); $this->view->render('node.phtml'); } } Now what I (obvoiusly) want is to use the view script APPLICATION_PATH . '/views/partner/xyz/node.phtml' but ZF always tries to load APPLICATION_PATH . '/views/partner/xyz/scripts/node.phtml' is there any Way around that Behviour?

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  • Removing HTML entities while preserving line breaks with JSoup

    - by shrodes
    I have been using JSoup to parse lyrics and it has been great until now, but have run into a problem. I can use Node.html() to return the full HTML of the desired node, which retains line breaks as such: Gl&oacute;andi augu, silfurn&aacute;tt <br />Bl&oacute;&eth; alv&ouml;ru, starir &aacute; <br />&Oacute;&eth;ur hundur er &iacute; v&iacute;gam&oacute;&eth;, &iacute; maga... m&eacute;r <br /> <br />Kolni&eth;ur gref, kvik sem dreg h&eacute;r <br />Kolni&eth;ur svart, hvergi bjart n&eacute; But has the unfortunate side-effect, as you can see, of retaining HTML entities and tags. However, if I use Node.text(), I can get a better looking result, free of tags and entities: Glóandi augu, silfurnátt Blóð alvöru, starir á Óður hundur er í vígamóð, í maga... mér Kolniður gref, kvik sem dreg hér Kolniður svart, Which has another unfortunate side-effect of removing the line breaks and compressing into a single line. Simply replacing <br /> from the node before calling Node.text() yields the same result, and it seems that that method is compressing the text onto a single line in the method itself, ignoring newlines. Is it possible to have the best of both worlds, and have tags and entities replaced correctly which preserving the line breaks, or is there another method or way of decoding entities and removing tags without having to replace them manually?

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  • How to print element values when iterating through XML document in PHP

    - by pharma_joe
    I am iterating through the results of a service call to yahoo news thus: //Send service request if (!$yahooResults = file_get_contents($yahooRequest)) { echo 'Error processing service request'; } //Read result into xml document $yahooResultXml = new DOMDocument('1.0', 'UTF-8'); $yahooResultXml-loadXML($yahooResults); //Build page include_once('components/pageHeader.php'); echo 'Search Results'; //echo $yahooResultXml-saveHTML(); //Iterate over each Result node $stories = $yahooResultXml-getElementsByTagName('Result'); foreach ($stories as $story) { //Title //Summary //Url //Source //Language //Publish Date //Modification Date } include_once('components/pageFooter.php'); Each Title is in a Title node within a Result Node. I cannot figure out how to simply echo the content of the Title node!

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  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

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  • Product Kit does not save the selected products!

    - by doublejosh
    Arg! When I save my product kit, with several product selected, I land on a blank product kit node (as in no sub products). The message confirms the update, however when I return to the node edit page the products are no longer selected, hence the blank kit node page. Thoughts on debugging this, or what might lead to it?

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  • I'm new to C++. Please Help me with the Linked List (What functions to add)?

    - by Igal
    DEAR All; Hi, I'm just beginner to C++; Please help me to understand: What functions should be in the Linked list class ? I think there should be overloaded operators << and ; Please help me to improve the code (style, errors, etc,) Thanks for advance. Igal. Please review the small code for the integer List (enclosed MyNODE.h and ListDriver1.cpp); MyNODE.h // This is my first attempt to write linked list. Igal Spector, June 2010. #include <iostream.h> #include <assert.h> //Forward Declaration of the classes: class ListNode; class TheLinkedlist; // Definition of the node (WITH IMPLEMENTATION !!!, without test drive): class ListNode{ friend class TheLinkedlist; public: // constructor: ListNode(const int& value, ListNode *next= 0); // note: no destructor, as this handled by TheLinkedList class. // accessor: return data in the node. // int Show() const {return theData;} private: int theData; //the Data ListNode* theNext; //points to the next node in the list. }; //Implementations: //constructor: inline ListNode::ListNode(const int &value,ListNode *next) :theData(value),theNext(next){} //end of ListNode class, now for the LL class: class TheLinkedlist { public: //constructors: TheLinkedlist(); virtual ~TheLinkedlist(); // Accessors: void InsertAtFront(const &); void AppendAtBack(const &); // void InOrderInsert(const &); bool IsEmpty()const;//predicate function void Print() const; private: ListNode * Head; //pointer to first node ListNode * Tail; //pointer to last node. }; //Implementation: //Default constructor inline TheLinkedlist::TheLinkedlist():Head(0),Tail(0) {} //Destructor inline TheLinkedlist::~TheLinkedlist(){ if(!IsEmpty()){ //list is not empty cout<<"\n\tDestroying Nodes"<<endl; ListNode *currentPointer=Head, *tempPtr; while(currentPointer != 0){ //Delete remaining Nodes. tempPtr=currentPointer; cout<<"The node: "<<tempPtr->theData <<" is Destroyed."<<endl<<endl; currentPointer=currentPointer->theNext; delete tempPtr; } Head=Tail = 0; //don't forget this, as it may be checked one day. } } //Insert the Node to the beginning of the list: void TheLinkedlist::InsertAtFront(const int& value){ ListNode *newPtr = new ListNode(value,Head); assert(newPtr!=0); if(IsEmpty()) //list is empty Head = Tail = newPtr; else { //list is NOT empty newPtr->theNext = Head; Head = newPtr; } } //Insert the Node to the beginning of the list: void TheLinkedlist::AppendAtBack(const int& value){ ListNode *newPtr = new ListNode(value, NULL); assert(newPtr!=0); if(IsEmpty()) //list is empty Head = Tail = newPtr; else { //list is NOT empty Tail->theNext = newPtr; Tail = newPtr; } } //is the list empty? inline bool TheLinkedlist::IsEmpty() const { return (Head == 0); } // Display the contents of the list void TheLinkedlist::Print()const{ if ( IsEmpty() ){ cout << "\n\t The list is empty!!"<<endl; return; } ListNode *tempPTR = Head; cout<<"\n\t The List is: "; while ( tempPTR != 0 ){ cout<< tempPTR->theData <<" "; tempPTR = tempPTR->theNext; } cout<<endl<<endl; } ////////////////////////////////////// The test Driver: //Driver test for integer Linked List. #include <iostream.h> #include "MyNODE.h" // main Driver int main(){ cout<< "\n\t This is the test for integer LinkedList."<<endl; const int arraySize=11, ARRAY[arraySize]={44,77,88,99,11,2,22,204,50,58,12}; cout << "\n\tThe array is: "; //print the numbers. for (int i=0;i<arraySize; i++) cout<<ARRAY[i]<<", "; TheLinkedlist list; //declare the list for(int index=0;index<arraySize;index++) list.AppendAtBack( ARRAY[index] );//create the list cout<<endl<<endl; list.Print(); //print the list return 0; //end of the program. }

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  • How can I store this kind of graph in neo4j for fast traversal?

    - by James
    This is a graph whose nodes exist in many connected components at once because a node's relationships are a collection of edge groups such that only one edge per edge group can be present at once. I need to be able to find all of the connected components that a node exists in. What would be the best way to store this graph in neo4j to quickly find all of the connected components that a node exists in? Is there a way to use the built in traversals to do this? Also: is there a name for this kind of graph? I'd appreciate any help/ideas. Update: Sorry for not being clear. All nodes are of the same type. Nodes have a variable number of edge groups. Exactly one edge from each edge group needs to be chosen for a particular connected component. I'm going to try to explain through example: Node x1 is related to: (x2 or x3 or x4) AND (x5 or x6) AND (x7) Node x2 is related to: (x8) AND (x9 or x10) So x1's first edge group is (x2, x3, x4), its second edge group is (x5, x6), and its third edge group is (x7). So here are a few connected components that x1 exists in: CC1: x1 is related to: x2, x5, x7 x2 is related to: x8 x9 CC2: x1 is related to: x2, x6, x7 x2 is related to: x8, x9 CC3: x1 is related to: x3, x5, x7 CC4: x1 is related to: x3, x6, x7 etc. I'm grateful for your help in this.

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  • infix operation to postfix using stacks

    - by Chris De La O
    We are writing a program that needs to convert an infix operation (4 5/3) to postfix (4 5 3 / ) using stacks. however my convert to postfix does not work as it doesnt not output the postFix array that is supposed to store the conversion from infix notation to postfix notation. here is the code for the convertToPostix fuction. //converts infix expression to postfix expression void ArithmeticExpression::convertToPostfix(char *const inFix, char *const postFix) { //create a stack2 object named cow Stack2<char> cow; cout<<postFix; char thing = '('; //push a left parenthesis onto the stack cow.push(thing); //append a right parenthesis to the end of inFix array strcat(inFix, ")"); int i = 0;//declare an int that will control posFix position //if the stack is not empty if (!cow.isEmpty()) { //loop to run until the last character in inFix array for (int x = 0; inFix[x]!= '\0'; x++ ) { //if the inFix element is a digit if (isdigit(inFix[x])) { postFix[i]=inFix[x];//it is assigned to the next element in postFix array i++;//move on to next element in postFix } //if the inFix element is a left parenthesis else if (inFix[x]=='(') { cow.push(inFix[x]);//push it unto the stack } //if the inFix element is an operator else if (isOperator(inFix[x])) { char oper2 = inFix[x];//char variable holds inFix operator if (isOperator(cow.stackTop()))//if the top node in the stack is an operator { while (isOperator(cow.stackTop()))//and while the top node in the stack is an operator { char oper1 = cow.stackTop();//char variable holds node operator if(precedence( oper1, oper2))//if the node operator has higher presedence than node operator { postFix[i] = cow.pop();//we pop such operator and insert it in postFix array's next element cow.push(inFix[x]);//and push inFix operator unto the stack i++;//move to the next element in posFix } } } //if the top node is not an operator //we push the current inFix operator unto the top of the stack else cow.push(inFix[x]); } //if the inFix element is a right parenthesis else if (inFix[x]==')') { //we pop everything in the stack and insert it in postFix //until we arrive at a left paranthesis while (cow.stackTop()!='(') { postFix[i] = cow.pop(); i++; } //we then pop and discard left parenthesis cow.pop(); } } postFix[i]='\0'; //print !!postFix array!! (not stack) print();//code for this is just cout<<postFix; }

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