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  • Hash Digest / Array Comparison in C#

    - by Erik Karulf
    Hi All, I'm writing an application that needs to verify HMAC-SHA256 checksums. The code I currently have looks something like this: static bool VerifyIntegrity(string secret, string checksum, string data) { // Verify HMAC-SHA256 Checksum byte[] key = System.Text.Encoding.UTF8.GetBytes(secret); byte[] value = System.Text.Encoding.UTF8.GetBytes(data); byte[] checksum_bytes = System.Text.Encoding.UTF8.GetBytes(checksum); using (var hmac = new HMACSHA256(key)) { byte[] expected_bytes = hmac.ComputeHash(value); return checksum_bytes.SequenceEqual(expected_bytes); } } I know that this is susceptible to timing attacks. Is there a message digest comparison function in the standard library? I realize I could write my own time hardened comparison method, but I have to believe that this is already implemented elsewhere.

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  • Password protected .NET ClickOnce deployment?

    - by splattne
    How can I protect a ClickOnce deployed application with a password? Do I have to change the IIS settings of the web or is there a way to do it programmatically? I'm using Visual Studio 2005 (.NET 2.0). If I have to use web credentials, are auto-updates of the application still possible? Would be great if you could provide some sample code or detailed instructions for administering IIS. Thank you!

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  • Forgot SQL Server Password

    - by buyutec
    I installed SQL Server 2005 sometime ago and forgot the administrator password I set during setup. How can I connect to SQL server now? EDIT: I think I only allowed Sql Server Authentication. Login with integrated security also does not work.

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  • Creating a unique key based on file content in python

    - by Cawas
    I got many, many files to be uploaded to the server, and I just want a way to avoid duplicates. Thus, generating a unique and small key value from a big string seemed something that a checksum was intended to do, and hashing seemed like the evolution of that. So I was going to use hash md5 to do this. But then I read somewhere that "MD5 are not meant to be unique keys" and I thought that's really weird. What's the right way of doing this? edit: by the way, I took two sources to get to the following, which is how I'm currently doing it and it's working just fine, with Python 2.5: import hashlib def md5_from_file (fileName, block_size=2**14): md5 = hashlib.md5() f = open(fileName) while True: data = f.read(block_size) if not data: break md5.update(data) f.close() return md5.hexdigest()

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  • django-registration password reset custom template not loading

    - by ip.
    I'm using django-registration for registering users, however when I want to use my own template for password reset I get the admin template and not the template I created. My template is in myapp/templates/registration/password_reset_form.html and my template loaders are properly set: TEMPLATE_LOADERS = ( 'django.template.loaders.filesystem.Loader', 'django.template.loaders.app_directories.Loader', ) What could I be missing? I'm using Django 1.4

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  • ASP.NET Password textbox, has text as characters entered

    - by SimonNet
    When I look at gmail on my mobile web browser the password textbox hashes the characters as I type so I can see the actual input as I type before is hashed with an asterisk. So as I enter it becomes, P -- *a -- **s etc.. How is this done? I presume its javascript? If somone can point me in the right direction that would be great.

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  • svn for emacs: how do you set author name and save password

    - by Jack
    I can't seem to find this on google anywhere. I am trying to move to emacs from eclipse but I can't for the life of me figure out how to set my svn author name so it doesn't default the author name OR save the password so I don't have to type it in any each time. I am Ubuntu 8.10 if that matters. Any insight would be great. Thanks.

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  • Password protect web service

    - by Henrik
    Hi! Is it possible to require user name and password for a web service without changing the code for existing web service? Adding a DLL and configuration would be OK, but I rather not change the web service.

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  • Question about the mathematical properties of hashes

    - by levand
    Take a commonly used binary hash function - for example, SHA-256. As the name implies, it outputs a 256 bit value. Let A be the set of all possible 256 bit binary values. A is extremely large, but finite. Let B be the set of all possible binary values. B is infinite. Let C be the set of values obtained by running SHA-256 on every member of B. Obviously this can't be done in practice, but I'm guessing we can still do mathematical analysis of it. My Question: By necessity, C ? A. But does C = A?

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  • Secure password transmission over unencrypted tcp/ip

    - by academicRobot
    I'm in the designing stages of a custom tcp/ip protocol for mobile client-server communication. When not required (data is not sensitive), I'd like to avoid using SSL for overhead reasons (both in handshake latency and conserving cycles). My question is, what is the best practices way of transmitting authentication information over an unencrypted connection? Currently, I'm liking SRP or J-PAKE (they generate secure session tokens, are hash/salt friendly, and allow kicking into TLS when necessary), which I believe are both implemented in OpenSSL. However, I am a bit wary since I don't see many people using these algorithms for this purpose. Would also appreciate pointers to any materials discussing this topic in general, since I had trouble finding any.

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  • Ruby: rules for implicit hashes

    - by flyer
    Why second output shows me only one element of Array? Is it still Array or Hash already? def printArray(arr) arr.each { | j | k, v = j.first printf("%s %s %s \n", k, v, j) } end print "Array 1\n" printArray( [ {kk: { 'k1' => 'v1' }}, {kk: { 'k2' => 'v2' }}, {kk: { 'k3' => 'v3' }}, ]) print "Array 2\n" printArray( [ kk: { 'k1' => 'v1' }, kk: { 'k2' => 'v2' }, kk: { 'k3' => 'v3' }, ]) exit # Output: # # Array 1 # kk {"k1"=>"v1"} {:kk=>{"k1"=>"v1"}} # kk {"k2"=>"v2"} {:kk=>{"k2"=>"v2"}} # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}} # Array 2 # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}}

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  • ADO.NET connection string and password with "=" in it

    - by Philippe Leybaert
    How do I build a connection string which includes a passsword having a "=" in it? (I'm connecting to MySql 5.1) For example, let's say the password is "Ge5f8z=6", what would the connection string look like? I tried: Server=DBSERV;Database=mydb;UID=myuser;PWD="Ge5f8z=6"; and Server=DBSERV;Database=mydb;UID=myuser;PWD=Ge5f8z=6;" Both don't work.

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  • validation of password with ()-=_+

    - by jpallavi
    I am not able to validate passord with ()-=_+ , i.e it should accept these special characters but its not working when i use the regular expression as `validates_format_of :password, :with => /^[A-Za-z0-9. ! @ # $ % ^ & * ( ) _ - + = ]*\z/` its only excepting till * but not accepting ()-=_+ in ruby on rails.

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  • Accessing a nested hash in a controller

    - by Magicked
    I have the following (snipped) parameters passed into my controller. Parameters: {"commit"=>"OK", "action"=>"set_incident_incident_status_id", "id"=>"1", "controller"=>"incidents", "incident"=>{"incident_status_id"=>"1"}} I know that if I want to select the incident, I can do: @incident = Incident.find(params[:id]) How do I access the "incident"={"incident_status_id"="1"}? I thought to try something like: @incident_status = IncidentStatus.find(params[:incident => :incident_status_id]) But that didn't work. I'm assuming it's just a syntax problem at this point, and I haven't found a solution yet. Any help would be much appreciated!

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  • openldap and root password

    - by nav.jdwdw
    I recently changed my root password, but when I restart Ldap (openldap-2.2.13) I couldn't log in with Ldap users to any application that is on this server. in /var/log/httpd/ssl_error_log I can find a lot of error like: [Tue Jun 01 02:27:24 2010] [warn] [client 89.138.98.214] [26762] auth_ldap authenticate: user foo authentication failed; URI /svn-clients/clients/myclient/ [LDAP: ldap_simple_bind_s() failed][Can't contact LDAP server] I guess there is a linkage between user root and the Ldap configuration, I also changed the rootpw entry in slapd.conf, but this doesn't seem to make things better.

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