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  • .NET Regular Expression to split multiple words or phrases

    - by Cj Anderson
    I'm using the code below to take a string and split it up into an array. It will take: Disney Land and make it two separate elements. If the string contains "Disney Land" then it is one element in the array. Works great, however it adds some empty elements to the array each time. So I just iterate over the elements and remove them if they are empty. Is there a tweak to the code below that will prevent those empty elements from occurring? Private m_Reg As Regex m_Reg = New Regex("([^""^\s]+)\s*|""([^""]+)""\s*") Dim rezsplit = m_Reg.Split(criteria)

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  • Regular Expression Help - Brackets within brackets

    - by adbox
    Hello I'm trying to develop a function that can sort through a string that looks like this: Donny went to the {park|store|{beach with friends|beach alone}} so he could get a breath of freash air. What I intend to do is search the text recursively for {} patterns where there is no { or } inside the {}, so only the innermost sandwiched text is selected, where I will then run a php to array the contents and select one at random, repeating process until the whole string has been parsed, showing a complete sentence. I just cannot wrap my head around regular expressions though. Appreciate any help!

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  • Identifying that a variable is a new-style class in Python?

    - by Dave Johansen
    I'm using Python 2.x and I'm wondering if there's a way to tell if a variable is a new-style class? I know that if it's an old-style class that I can do the following to find out. import types class oldclass: pass def test(): o = oldclass() if type(o) is types.InstanceType: print 'Is old-style' else: print 'Is NOT old-style' But I haven't been able to find anything that works for new-style classes. I found this question, but the proposed solutions don't seem to work as expected, because simple values as are identified as classes. import inspect def newclass(object): pass def test(): n = newclass() if inspect.isclass(n): print 'Is class' else: print 'Is NOT class' if inspect.isclass(type(n)): print 'Is class' else: print 'Is NOT class' if inspect.isclass(type(1)): print 'Is class' else: print 'Is NOT class' if isinstance(n, object): print 'Is class' else: print 'Is NOT class' if isinstance(1, object): print 'Is class' else: print 'Is NOT class' So is there anyway to do something like this? Or is everything in Python just a class and there's no way to get around that?

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  • Excel Matching problem with logic expression

    - by abelenky
    (I understand Excel is only borderline programming) I have a block of data that represents the steps in a process and the possible errors: ProcessStep Status FeesPaid OK FormRecvd OK RoleAssigned OK CheckedIn Not Checked In. ReadyToStart Not Ready for Start I want to find the first Status that is not "OK". I have attempted this: =Match("<>""OK""", StatusRange, 0) which is supposed to return the index of the first element in the range that is NOT-EQUAL (<) to "OK" But this doesn't work, instead returning #N/A. I expect it to return 4 (index #4, in a 1-based index, representing that CheckedIn is the first non-OK element) Any ideas how to do this?

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  • JSP: EL expression is not evaluated

    - by James
    I have a JSP page running on Tomcat 5.5. I have the following code: <c:forEach var="i" begin="1" end="10" step="1"> <c:out value="${i}" /> <br /> </c:forEach> The output I am getting is: ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} I cant work out why the forEach loop is working but the output is not working. Any help any one could give would be great.

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  • Regular expression of unicode characters on string

    - by Marcus King
    I'm working in c# doing some OCR work and have extracted the text I need to work with. Now I need to parse a line using Regular Expressions. string checkNum; string routingNum; string accountNum; Regex regEx = new Regex(@"\u9288\d+\u9288"); Match match = regEx.Match(numbers); if (match.Success) checkNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\u9286\d{9}\u9286"); match = regEx.Match(numbers); if(match.Success) routingNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\d{10}\u9288"); match = regEx.Match(numbers); if (match.Success) accountNum = match.Value.Remove(match.Value.Length - 1, 1); The problem is that the string contains the necessary unicode characters when I do a .ToCharArray() and inspect the contents of the string, but it never seems to recognize the unicode characters when I parse the string looking for them. I thought strings in C# were unicode by default.

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  • How to evaluate a custom math expression in Python

    - by taynaron
    I'm writing a custom dice rolling parser (snicker if you must) in python. Basically, I want to use standard math evaluation but add the 'd' operator: #xdy sum = 0 for each in range(x): sum += randInt(1, y) return sum So that, for example, 1d6+2d6+2d6-72+4d100 = (5)+(1+1)+(6+2)-72+(5+39+38+59) = 84 I was using regex to replace all 'd's with the sum and then using eval, but my regex fell apart when dealing with parentheses on either side. Is there a faster way to go about this than implementing my own recursive parsing? Perhaps adding an operator to eval?

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  • Can you reverse order a string in one line with LINQ or a LAMBDA expression

    - by Student for Life
    Not that I would want to use this practically (for many reasons) but out of strict curiousity I would like to know if there is a way to reverse order a string using LINQ and/or LAMBDA expressions in one line of code, without utilising any framework "Reverse" methods. e.g. string value = "reverse me"; string reversedValue = (....); and reversedValue will result in "em esrever" EDIT Clearly an impractical problem/solution I know this, so don't worry it's strictly a curiosity question around the LINQ/LAMBDA construct.

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  • Regular expression for parsing CSV in PHP

    - by Discodancer
    I already managed to split the CSV file using this regex: "/,(?=(?:[^\"]\"[^\"]\")(?![^\"]\"))/" But I ended up with an array of strings that contain the opening and ending double quotes. Now I need a regex that would strip those strings of the delimiter double quotes. As far as I know the CSV format can encapsulate strings in double quotes, and all the double quotes that are already a part of the string are doubled. For example: My "other" cat becomes "My ""other"" cat" What I basically need is a regex that will replace all sequences of N doublequotes with a sequence of (N/2 - rounded down) double quotes. Or is there a better way ? Thanks in advance.

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  • Regular expression literal

    - by Marcus
    As I'm RegEx dyslexic.. what RegEx can you use to find each of the following strings - with the exception of "LoginException"? NullPointerException LoginException BooException Abc123Exception

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  • How to print unicode string in PHP

    - by Pentium10
    I have this small script: <? header('Content-Type: text/javascript; charset=utf8'); $s="L\u00e1szl\u00f3 M\u00e1rton"; echo $s; ?> The browser displays "L\u00e1szl\u00f3 M\u00e1rton" and it should display László Márton. What I am doing wrong?

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  • Javascript + Pretty Print JSON

    - by FlySwat
    I'm looking for a jQuery plugin or a standalone script that will take a javascript object and create a navigatable tree like the FireBug plug in does. Does this exist, or will I need to write one? Googling hasn't found much yet.

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  • Regular Expression to break row with comma separated values into distinct rows

    - by Nick
    I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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  • how do you print a bag datatype?

    - by shiva
    Bag<String> wordFrequencies = getWordFrequencies(text); how do i see what this wordfrequencies bag contains.. i ve used org.apache.commons.collections15.Bag org.apache.commons.collections15.bag.HashBag packages

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  • What does the following Regex expression do?

    - by Jim
    Hi, I would like to understand what the following code is doing. This logic is part of a routine to strip out html from the body of an email message. mBBSREgEx.IgnoreCase = True mBBSREgEx.Global = True mBBSREgEx.Pattern = "<[^>]*>" sResult = mBBSREgEx.Replace(sResult, "") Thank you, Jim

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  • Getting error in MVC Proj while writing Lambda Expression

    - by Shrewd Demon
    hi, i am creating a sample movie (MVC) application. I was getting fine with Viewing and Creating a new record, but when i wrote the code to get the details of a particular record i met with the following error: Unable to cast objec`t of type 'System.Data.Objects.ObjectQuery`1[MovieApp.Models.Movie]' to type 'MovieApp.Model`s.Movie'. here is the code i wrote for getting the details public ActionResult Details(int id) { var moviedetail = (Movie)_entities.MovieSet.Where(mvid => mvid.Id == id); return View(moviedetail); } can any body tell me whats going wrong and where ?? thank you.

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  • Print a JavaScript array to HTML, square brackets and quotation marks intact

    - by Mark Gia Bao Nguyen
    I'd like to set the attribute of an input form with an array of values (to use for autocomplete search). I have a JS array that looks a little something like this: var suggestions = ["value1", "value2", "value3"]; Using jQuery, I did this: $("#search-input").attr("data-source", suggestions); Desired output: <input type='search' data-source='["value1", "value2", "value3"]' /> Actual output: <input type='search' data-source='value1, value2, value3' /> This breaks the autocomplete as it requires an array (or at least something that looks like a JavaScript array).

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  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

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