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  • Plotting points so that they do not overlap if they have the same co-ordinates

    - by betamax
    Hi everyone, I have a function that takes longitude and latitude and converts it to x and y to be plotted. The conversion to X and Y is working fine and that is not what I have the problem with. I want to ensure that two points are not plotted in the same place. In one set of results there are about 30 on top of each other (because they have the same latitude and longitude), this number could be a lot larger. At the moment I am trying to achieve this by moving points to the left, right, top or bottom of the point to make a square. Once a square made up of points has been drawn, then moving to the next row on and drawing another square of points around the previous square. The code is Javascript but it is very generic so I guess it's slightly irrelevant. My code is as follows: var prevLong, prevLat, rand = 1, line = 1, spread = 8, i = 0; function plot_points(long, lat){ // CODE HERE TO CONVERT long and lat into x and y // System to not overlap the points if((prevLat == lat) && (prevLong == long)) { if(rand==1) { x += spread*line; } else if(rand==2) { x -= spread*line; } else if(rand==3) { y += spread*line; } else if(rand==4) { y -= spread*line; } else if(rand==5) { x += spread*line; y += spread*line; } else if(rand==6) { x -= spread*line; y -= spread*line; } else if(rand==7) { x += spread*line; y -= spread*line; } else if(rand==8) { x -= spread*line; y += spread*line; // x = double } else if(rand==9) { x += spread*line; y += spread; } else if(rand==10) { x += spread; y += spread*line; } else if(rand==11) { x -= spread*line; y -= spread; } else if(rand==12) { x -= spread; y -= spread*line; } else if(rand==13) { x += spread*line; y -= spread; } else if(rand==14) { x += spread; y -= spread*line; } else if(rand==15) { x += spread*line; y -= spread; } else if(rand==16) { x += spread; y -= spread*line; } else if(rand==17) { x -= spread*line; y += spread; } else if(rand==18) { x -= spread; y += spread*line; } else if(rand==19) { x -= spread*line; y += spread; } else if(rand==20) { x -= spread; y += spread*line; } if(rand == 20) {rand = 1; line++; } else { rand++; } i++ } else { line = 1; i = 0; } prevLat = latitude; prevLong = longitude; return [x,y]; } This is the output: It isn't working correctly and I don't even know if I am approaching the problem in a correct way at all. Has anyone had to do this before? What method would you suggest?

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  • Simply if Statement for checking co-ordinate square.

    - by JonB
    I have an UIImageView and taking the raw touch input. I need to check if a touch is within a certain set of squares. At the moment... I have this if statement.... if(46 < touchedAt.x && touchedAt.x < 124 && 18 < touchedAt.y && touchedAt.y < 75) but I have tried to simplify it to this one... if(46 < touchedAt.x < 124 && 18 < touchedAt.y < 75) It didn't work. Is it possible to simplify like this or am I stuck with the slightly lengthier version at the top? Is there a reason why the types of comparisons in the bottom if don't work? Many Thanks.

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  • How do you keep yourself and your co-workers from creating huge classes

    - by PieterG
    Stackoverflow users, How do you keep yourself from creating large classes with large bodied methods. When deadlines are tight, you end up trying to hack things together and it ends up being a mess which would need to be refactored. For me, the one way was to start with test driven development and that lends itself to good class design as well as the SRP (Single Responsibility Principle). I also see developers just double clicking on controls and typing out line after line in the event method that gets fired. What are your suggestions?

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  • Getting keypress cursor co-ordinates

    - by nijikunai
    I'm writing a simple browser based ide with intellisense (code completion) support. So whenever the user inserts a dot (.) character, I need to display a div element (as context menu) near the cursor. Can this can be done and if yes how? Thanks in advance!

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  • Python/Biomolecular Physics- Trying to code a simple stochastic simulation of a system exhibiting co

    - by user359597
    *edited 6/17/10 I'm trying to understand how to improve my code (make it more pythonic). Also, I'm interested in writing more intuitive 'conditionals' that would describe scenarios that are commonplace in biochemistry. The conditional criteria in the below program is explained in Answer #2, but I am not satisfied with it- it is correct, but isn't obvious and isn't easy to implement for more complicated conditional scenarios. Ideas welcome. Comments/criticisms welcome. First posting experience @ stackoverflow- please comment on etiquette if needed. The code generates a list of values that are the solution to the following exercise: "In a programming language of your choice, implement Gillespie’s First Reaction Algorithm to study the temporal behaviour of the reaction A---B in which the transition from A to B can only take place if another compound, C, is present, and where C dynamically interconverts with D, as modelled in the Petri-net below. Assume that there are 100 molecules of A, 1 of C, and no B or D present at the start of the reaction. Set kAB to 0.1 s-1 and both kCD and kDC to 1.0 s-1. Simulate the behaviour of the system over 100 s." def sim(): # Set the rate constants for all transitions kAB = 0.1 kCD = 1.0 kDC = 1.0 # Set up the initial state A = 100 B = 0 C = 1 D = 0 # Set the start and end times t = 0.0 tEnd = 100.0 print "Time\t", "Transition\t", "A\t", "B\t", "C\t", "D" # Compute the first interval transition, interval = transitionData(A, B, C, D, kAB, kCD, kDC) # Loop until the end time is exceded or no transition can fire any more while t <= tEnd and transition >= 0: print t, '\t', transition, '\t', A, '\t', B, '\t', C, '\t', D t += interval if transition == 0: A -= 1 B += 1 if transition == 1: C -= 1 D += 1 if transition == 2: C += 1 D -= 1 transition, interval = transitionData(A, B, C, D, kAB, kCD, kDC) def transitionData(A, B, C, D, kAB, kCD, kDC): """ Returns nTransition, the number of the firing transition (0: A->B, 1: C->D, 2: D->C), and interval, the interval between the time of the previous transition and that of the current one. """ RAB = kAB * A * C RCD = kCD * C RDC = kDC * D dt = [-1.0, -1.0, -1.0] if RAB > 0.0: dt[0] = -math.log(1.0 - random.random())/RAB if RCD > 0.0: dt[1] = -math.log(1.0 - random.random())/RCD if RDC > 0.0: dt[2] = -math.log(1.0 - random.random())/RDC interval = 1e36 transition = -1 for n in range(len(dt)): if dt[n] > 0.0 and dt[n] < interval: interval = dt[n] transition = n return transition, interval if __name__ == '__main__': sim()

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  • Convert Lat/Longs to X/Y Co-ordinates

    - by michael
    I have the Lat/Long value of New York City, NY; 40.7560540,-73.9869510 and a flat image of the earth, 1000px × 446px. I would like to be able to convert, using Javascript, the Lat/Long to an X,Y coordinate where the point would reflect the location. So the X,Y coordinate form the Top-Left corner of the image would be; 289, 111 Things to note: don't worry about issues of what projection to use, make your own assumption or go with what you know might work X,Y can be form any corner of the image Bonus points for the same solution in PHP (but I really need the JS)

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  • In ADL_Display_ConnectedDisplays_Get() from ATI's ADL Library, the out parameter lpConnections is co

    - by animesh
    The API defined in the ADL SDK manual reads: int ADL_Display_ConnectedDisplays_Get(int iAdapterIndex, int* lpConnections) They say that lpConnections is the pointer to the bit field indicating whether the output connectors on the specified adapter have devices physically attached to them. This information is exactly what I want but nowhere in the documentation I could find any data on what the various bits in the lpConnections obtained might mean. I also tried going through the header files but found nothing relevant on this. I know this is very specific to but can anyone here answer?

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  • Optimizing list comprehension to find pairs of co-prime numbers

    - by user3685422
    Given A,B print the number of pairs (a,b) such that GCD(a,b)=1 and 1<=a<=A and 1<=b<=B. Here is my answer: return len([(x,y) for x in range(1,A+1) for y in range(1,B+1) if gcd(x,y) == 1]) My answer works fine for small ranges but takes enough time if the range is increased. such as 1 <= A <= 10^5 1 <= B <= 10^5 is there a better way to write this or can this be optimized?

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  • Co-opt popular abandonware opensource project?

    - by Mike Bouck
    Here's the scenario: A popular open source project is used/loved by many but has become stale due to the fact that the last drop came out nearly a year ago. Many bugs/feature requests/fixes have been logged in the interim and everyone is getting by via downloading the trunk and building custom/private builds with the changes incorporated. The copyright is simple -- there is none and the code is in the public domain. The project owner spins the project as community open source and has set up a sourceforge site, but to date (5 years running now) has yet to accept one contributor. In other words the "community" is a community of one. The project owner takes great pride in the project and has obviously contributed a lot of time/effort but for whatever reason has has seemingly abandoned the project and is unresponsive when offers of help are made. So, the question, should the community fork the codebase, set up a new community site, and take matters in their own hands?

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  • C# cross thread dialogue co-operation

    - by John Attridge
    K I am looking at a primarily single thread windows forms application in 3.0. Recently my boss had a progress dialogue added on a separate thread so the user would see some activity when the main thread went away and did some heavy duty work and locked out the GUI. The above works fine unless the user switches applications or minimizes as the progress form sits top most and will not disappear with the main application. This is not so bad if there are lots of little operations as the event structure of the main form catches up with its events when it gets time so minimized and active flags can be checked and thus the dialog thread can hide or show itself accordingly. But if a long running sql operation kicks off then no events fire. I have tried intercepting the WndProc command but this also appears queued when a long running sql operation is executing. I have also tried picking up the processes, finding the current app and checking various memory values isiconic and the like inside the progress thread but until the sql operation finishes none of these get updated. Removing the topmost causes the dialog to disappear when another app activates but if the main app is then brought back it does not appear again. So I need a way to find out if the other thread is minimized or no longer active that does not involve querying the actual thread as that locks until the sql operation finishes. Now I know that this is not the best way to write this and it would be better to have all the heavy processing on separate threads leaving the GUI free but as this is a huge ancient legacy app the time to re-write in that fashion will not be provided so I have to work with what I have got. Any help is appreciated

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  • Converting between square and rectangular pixel co-ordinates

    - by FlyboyUtah
    I'm new at using transforms and this type of math, and would appreciate some direction solving my coding problem. I'm writing in XCode for the iphone, and am working with CGraphics. Problem: In Xcode, I want to draw curves, lines and so on it's screen of of square pixels. Then convert those points, as close as possible, into non-square pixel sysem. For example if the original coordinate system is 500 x 500 pixels that are displayed on square screen of 10 by 10 inchs I draw a round circle with the circle formula. It looks round, and all is well. Now, I draw the same circle on a second 10 x 10 inch screen that is 850 pixels by 500 pixels. Without changing the coordinates, the same circle formual displays something that looks like an egg. How can I draw the circle on the second screen in a different coordinate system? And in addition, I need to access the set of points x,y system individually. s

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  • Windows 8 : Microsoft dépose un nouveau brevet, qui rends encore plus plausible l'existence d'un mode "Direct Experience"

    Windows 8 : Microsoft dépose un nouveau brevet, qui rends encore plus plausible l'existence d'un mode "Direct Experience" Mise à jour du 06.02.2011 par Katleen En août 2010, nous vous parlions de l'hypothétique mode "Direct Experience", qui pourrait être disponible dans la prochaine version de Windows (voir news précédentes) et dont la but serait d'accélérer l'exécution de contenus multimédias. En gros, il permettrait à l'OS de démarrer sous différents modes suivant les besoins spécifiques détectés (par exemple, si un DVD est inséré dans...

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  • SAP : "Il faut faire simple, rapide, et sur mesure", le co-CEO Bill McDermott revient sur les mutations en cours de l'éditeur allemand

    SAP : « Il faut faire simple, rapide, et sur mesure » Bill McDermott, co-CEO, revient sur les grandes mutations en cours de l'éditeur allemand De passage à Paris, Bill McDermott ? un des deux co-PDG de SAP - a fait le tour des sujets qui conditionnent l'avenir de l'éditeur allemand. La conférence de presse s'est tenue au SAP Forum qui s'est déroulé le 31 mai au CNIT de La Défense. Parmi la myriade de sujets, Bill McDermott a confirmé son ambition dans les bases de données. Avec le rachat de Sybase, SAP a un objectif clair : devenir le leader de ce secteur dominé actuellement (en valeur) par son grand concurrent Oracle et en unité par Microsoft. « Dans le mo...

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  • Long-term Freelance contract: should it have a salary-day or not?

    - by otto
    I don't like to speak about money. I just like to work. I still believe in a relationship between good work and good compensation. Hence I don't want ask my employer about my compensations, actually they are asking me. So I created a liberal contract with unspecified salary-day -- I did not want to lose my rights to my own projects and I did not pay any attention to the salary-day. Now the firm said that they would have paid me 1 month earlier if I had provided a tax -paper. I provided it before the next payment -day (unspecified). During the next month, the co-employer pretty much blocks my working -- does not allow me to access working repository and the co-employer goes to cruise when we should finalize a project so I cannot do anything. Now the project is not finalized, the co-employer has apparently provided some false statements to the boss about my doings (not getting anything for one month's work and 1 month when the co-employer pretty much wasted just my time) -- I was only allowed to debug the code of my co-employer and not to do anything. I feel that co-employer did not allow me to work by purpose so that they have an excuse not to pay any salary. The co-employer says that I cannot speak to the boss. The boss say that I need to speak directly to co-employer, not to him. I haven't said anything about the situation. I did not get things done because I was not allowed and now I am not even allowed to speak. Boss is the person who pays salaries. But both boss and co-employer have stages in the firm -- I think co-employer and boss are the same person pretty much, they created a theatre so that they get almost 2 month's work for free. Now I have multiple ideas how to avoid this kind of situations in the future: specify the salary day make sure you can speak directly to the manager and the boss, not through middle-hand other?

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  • Google : "ne plus être soumis à la loi des États-Unis serait génial", son co-fondateur critique les plateformes fermées de Facebook et Apple

    Google : « ne plus être soumis à la loi des États-Unis, ce serait génial » Son co-fondateur critique Facebook et Apple et se dit « plus inquiet que jamais » pour l'ouverture d'Internet « La liberté sur Internet est en danger ». Cette déclaration alarmiste ne vient pas du Parti Pirate ou de l'Electronic Frontier Foundation mais d'un acteur beaucoup plus étonnant : Sergey Brin, un des deux co-fondateurs de Google. Dans un entretien au quotidien britannique The Guardian, le jeune dirigeant (38 ans) s'en prend pêle-mêle aux gouvernements qui essayent de contrôler l'expression des citoyens, aux associations d'auteurs/compositeurs qui sous prétexte, d'après lui, de lutter c...

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  • Firefox sur le déclin ? Presque, répond un de ses co-créateurs : un avis qui ne fait pas l'unanimité

    Mise à jour du 19/05/10 Firefox est-il sur le déclin ? Presque, répond son co-créateur mais son avis ne fait pas l'unanimité Black Ross, un des créateurs de Firefox, employé aujourd'hui de Facebook, pense que son navigateur n'est plus ce qu'il était. C'est en ces termes qu'il a répondu avant-hier à une question sur l'avenir du Panda Roux : « Je pense que la Fondation Mozilla est progressivement retombées dans ses anciens travers, elle est être trop timide, trop passive et trop focalisée sur le consensus pour délivrer rapidement des produits innovants ». Son avis n'est pas isolé. Un autre co-fondateur du navigateur, John ...

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  • Le co-fondateur d'Hotmail veut rendre les SMS gratuits pour tous, un nouveau service voit le jour : JaxtrSMS

    Le co-fondateur d'Hotmail prévoit de rendre les SMS gratuits pour tous les utilisateurs de mobile Un nouveau service voit le jour : JaxtrSMS Sabeer Bhatia, que l'on qualifie de "serial entrepreneur", assure d'avoir trouvé la meilleure idée du siècle depuis la création d'Hotmail. Pour rappel, il était le co-fondateur de ce service, qui fut vendu à Microsoft pour 400 millions de dollars en 1998. Sa dernière idée en date, une application baptisée JaxtrSMS, se vanterait de fournir un service de sms gratuit, illimité et international. Cette application viendrait compléter les solutions VoIP de la société Jaxtr, connue pour fournir des prix attractifs. L...

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  • Opera s'associe à un distributeur chinois dans une co-entreprise, pour créer un navigateur mobile spécifique à ce pays

    Opera s'associe à un distributeur chinois dans une co-entreprise, pour créer un navigateur mobile spécifique à ce pays Opera Software vient de signer un accord avec l'opérateur chinois Telling Telecom, pour la création d'un co-autreprise à laquelle sera alloué un capital d'environ 20 millions d'euros et dont 40 % appartiendront à l'éditeur norvégien (au bout de trois ans). Le but de ce rapprochement est de mettre sur pieds un navigateur mobile spécial, pour le marché chinois, en combinant les technologies d'Opera avec du contenu local. Le logiciel bénéficiera ensuite du réseau de distribution de Telling dans le pays (l'entreprise possède 9000 employés et 18% de la part de marché de la distribution mobile en Chine). ...

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  • Google pourrait lancer son réseau social Google Circles en Mai, mais la firme dément la rumeur et réfute l'existence d'un tel service

    Google pourrait lancer son réseau social Google Circles en Mai, mais la firme dément la rumeur et réfute l'existence d'un tel service Le Web est en effervescence depuis ce matin, depuis qu'un site a lancé une rumeur : Google lancerait ce jour un nouveau réseau social : Google Circles. Ce dernier consisterait en un service d'échange de photos et de vidéos, mais aussi de partage de "statuts". Les contenus ainsi partagés ne le seraient qu'avec les "contacts les plus appropriés de votre cercle" d'amis virtuels, soit du tri sélectif pour chaque donnée échangée. Le produit serait développé sous la direction de Chris Messina (créateur de succès numériques comme BarCamp ou Hashtags), avec entre autres dan...

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  • Google confirme l'existence d'une tablette Nexus 10 pour concurrencer l'iPad, alors que sa Nexus 7 séduit de plus en plus les bidouilleurs

    Google confirme l'existence d'une Nexus 10 Alors que sa tablette Nexus 7 séduit de plus en plus les bidouilleurs Une Nexus 10. C'est ce qu'a utilisé Vic Gundotra, vice-président de Google en charge de l'ingénierie, pour prendre des photos de vacances qu'il a ensuite publiées sur sa page Google+. Le haut-dirigeant a donc confirmé de facto que l'entreprise allait bien sortir une nouvelle tablette grand format pour concurrencer l'iPad. Une confirmation qui n'a pas pris la forme habituelle d'une déclaration mais que l'on retrouve retrouve dans les méta-données, relevées par le site The Verge, des photos de Vic Gundotra. [IMG]http://ftp-developpez.co...

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  • Why does cron.hourly not care about the existence of anacron?

    - by Oliver Salzburg
    This question came up over in Root Access. Why does the default /etc/crontab not check for existence (and executable flag) of /usr/sbin/anacron for the hourly entry? My /etc/crontab: # m h dom mon dow user command 17 * * * * root cd / && run-parts --report /etc/cron.hourly 25 6 * * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.daily ) 47 6 * * 7 root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.weekly ) 52 6 1 * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.monthly ) What makes hourly different from the others?

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