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  • Ways to ensure unique instances of a class?

    - by Peanut
    I'm looking for different ways to ensure that each instance of a given class is a uniquely identifiable instance. For example, I have a Name class with the field name. Once I have a Name object with name initialised to John Smith I don't want to be able to instantiate a different Name object also with the name as John Smith, or if instantiation does take place I want a reference to the orginal object to be passed back rather than a new object. I'm aware that one way of doing this is to have a static factory that holds a Map of all the current Name objects and the factory checks that an object with John Smith as the name doesn't already exist before passing back a reference to a Name object. Another way I could think of off the top of my head is having a static Map in the Name class and when the constructor is called throwing an exception if the value passed in for name is already in use in another object, however I'm aware throwing exceptions in a constructor is generally a bad idea. Are there other ways of achieving this?

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  • Upgrade Ubuntu 11.10 to 12.10

    - by Daniel Minassian
    To whoever can help, I want to update the ubuntu on my laptop to 12.10 from the current version 11.10, when i click on the update manager i get a partial update gui, if i click cancel on that i get the gui for update which has three buttons check, install updates and upgrade. The upgrade button upgrades only to 12.04.1.LTS, when i press check it checks and gives me this error "W:Failed to fetch h t t p://lb.archive.ubuntu.com/ubuntu/dists/precise/main/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/lb.archive.ubuntu.com_ubuntu_dists_precise_main_i18n_Index , W:Failed to fetch h t t p://lb.archive.ubuntu.com/ubuntu/dists/precise/multiverse/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/lb.archive.ubuntu.com_ubuntu_dists_precise_multiverse_i18n_Index , W:Failed to fetch http://lb.archive.ubuntu.com/ubuntu/dists/precise/restricted/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/lb.archive.ubuntu.com_ubuntu_dists_precise_restricted_i18n_Index , W:Failed to fetch http://lb.archive.ubuntu.com/ubuntu/dists/precise/universe/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/lb.archive.ubuntu.com_ubuntu_dists_precise_universe_i18n_Index , E:Some index files failed to download. They have been ignored, or old ones used instead." Thank you for your time and help, Daniel Minassian

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  • Network does not connect at boot

    - by Daniel Svozil
    I am on Ubuntu 12.04, fresh install. When I boot a machine, the boot screen says Connecting to network, later it is changed to something like Did not connect, trying for another 60s. However, the network does not connect at the boot. But I can then log in without a network connection, and if I start a network manager service manually from the terminal (sudo service network-manager start), the network is connected without any problems. Please, does anybody know where the problem could be? I don't want to wait more than two minutes every computer restart :-). I am new to Ubuntu (and also to upstart) so I am a bit lost. There is no /var/log/messages, in dmesg I found this record, though it may not be related: init: network-interface (eth1) pre-start process (492) terminated with status 1 init: network-interface (eth1) post-stop process (548) terminated with status 1 Thanks Daniel

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  • Adjust Terminal - (Arch-like Info-Screen)

    - by Daniel
    I use Ubuntu for many years but recently I discovered a nice feature in Arch. It is common to display system-information on headless servers on ssh-login, on Ubuntu its the landscape- package. I wounded if it's possible to create the same for the normal terminal in Ubuntu . Like the terminal in Arch I think it might be useful to have this information displayed, at the time one starts the terminal. Is it possible to create something like this for the terminal, and if so what would you suggest? I tried motd but these messages were not displayed. Daniel

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • Tricky SQL query involving consecutive values

    - by Gabriel
    I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • Creating an excel macro to sum lines with duplicate values

    - by john
    I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • Are there any well known algorithms to detect the presence of names?

    - by Rhubarb
    For example, given a string: "Bob went fishing with his friend Jim Smith." Bob and Jim Smith are both names, but bob and smith are both words. Weren't for them being uppercase, there would be less indication of this outside of our knowledge of the sentence. Without doing grammar analysis, are there any well known algorithms for detecting the presence of names, at least Western names?

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  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

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  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

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  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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  • Allow Incoming Responses from Curl On Ubuntu 11.10 - Curl

    - by Daniel Adarve
    I'm trying to get a Curl Response from an outside server, however I noticed I cant neither PING the server in question nor connect to it. I tried disabling the iptables firewall but I had no success. My server is running behind a Cisco Linksys WRTN310N Router with the DD-wrt firmware Installed. In which I already disabled the firewall. Here are my network settings: Ifconfig eth0 Link encap:Ethernet HWaddr 00:26:b9:76:73:6b inet addr:192.168.1.120 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::226:b9ff:fe76:736b/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:49713 errors:0 dropped:0 overruns:0 frame:0 TX packets:30987 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:52829022 (52.8 MB) TX bytes:5438223 (5.4 MB) Interrupt:16 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:341 errors:0 dropped:0 overruns:0 frame:0 TX packets:341 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:27604 (27.6 KB) TX bytes:27604 (27.6 KB) /etc/resolv.conf nameserver 192.168.1.1 /etc/nsswitch.com passwd: compat group: compat shadow: compat hosts: files dns networks: files protocols: db files services: db files ethers: db files rpc: db files netgroup: nis /etc/host.conf order hosts,bind multi on /etc/hosts 127.0.0.1 localhost 127.0.0.1 callcenter # The following lines are desirable for IPv6 capable hosts ::1 ip6-localhost ip6-loopback fe00::0 ip6-localnet ff00::0 ip6-mcastprefix ff02::1 ip6-allnodes ff02::2 ip6-allrouters /etc/network/interfaces # The loopback network interface auto lo iface lo inet loopback # The primary network interface auto eth0 iface eth0 inet static address 192.168.1.120 netmask 255.255.255.0 network 192.168.1.1 broadcast 192.168.1.255 gateway 192.168.1.1 The Url to which im trying to get a connection to is https://www.veripayment.com/integration/index.php When I ping it on terminal heres what I get daniel@callcenter:~$ ping www.veripayment.com PING www.veripayment.com (69.172.200.5) 56(84) bytes of data. --- www.veripayment.com ping statistics --- 2 packets transmitted, 0 received, 100% packet loss, time 1007ms Thanks in Advance

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  • Game editor integration with the engine?

    - by Daniel
    What I am trying to figure out is what is the best way to integrate the editor(level, effects, model, etc...) in the most effective way? Now the first thing I thought would be to create the game engine(*) extremely modular. For example I took the example of game states. You could have multiple game states that all have their own update() and draw() methods among others. Each game state class would inherit from a base GameState class. This allows for a more modular approach and a useful one at that. Now would the most efficient approach be to implement the editor along with the modular engine, or create two different designs for both the game, and editor? I thought to take the game state example and extend it to window states, and well could be used for a lot more systems. Is there a better implementation of this design(game state) for use in other systems used in the engine? *: Now I know the term game engine is sorta irrelevant, and misused in many situations. What I am referring to as the "game engine" is the combination of the systems that the game must interact with for short. Also this is more of a theory / design question than an implementation. Even though both mix, i'd rather like to have a more general idea on how the editor is built in an efficient way and still using the same engine code as what the game uses. Thanks, Daniel P.S If you need more clarification or extra bits just leave a comment.

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  • How To Scale Canvas In Android

    - by Daniel Braithwaite
    I am writing a android game using Canvas as the way to draw everything, the problem is that when i run it on different android phones the canvas dosn't change size i tried using canvas.scale() but that didn't make a i difference. The code i use for drawing is ... public void draw( Canvas c, int score ) { Obstical2[] obstmp = Queue.toArray(this.o); Coin[] cointmp = QueueC.toArray(this.c); for( int i = 0; i < obstmp.length; i++ ) { obstmp[i].draw(c); } for( int i = 0; i < cointmp.length; i++ ) { cointmp[i].draw(c); } c.drawText(String.format("%d", score ), 20, 50, textPaint); if( isWon && isStarted ) c.drawText("YOU WON", 20, 400, resPaint); else if( isLost && isStarted ) c.drawText("YOU LOST", 20, 400, resPaint); } The function above calls the draw functions for the entity's on the screen, theses function are as follows Draw Function For Obstical : public void draw( Canvas c ) { Log.i("D", "COIN"); coin.draw(c); } Draw Function For Coin : public void draw( Canvas c ) { obstical.draw(c); } How could i make the canvas re-size to it would look the same on any screen ? Cheers Daniel

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  • Set default owner/user

    - by Daniel Hollands
    I'm a web developer, and so have set-up an old machine in the office as an Ubuntu Server, for the purposes of testing websites. I've set-up LAMP and have created a /var/www folder, from which all my local sites are served. The issue is that of user permissions, i.e. any files that I copy into that folder (from my Windows machine via the network) automatically take on me (daniel) as their owner. The problem is that I want www-data to become the owner. I did some research and saw that it should be possible to use setuid (and setgid) to automatically set www-data as the owner of all files put into /var/www automatically, so far I've not had any luck making it work. Can someone help please? Thank you UPDATE: Would this do what I want it to do? Default file permissions for php user www-data UPDATE 2: I've kinda fixed my issue by changing my samba settings. Using Webmin, I was able to go in and change the default settings (as seen here: http://imageshack.us/photo/my-images/521/captureon.png/)

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  • Run script after switching user account "to the same account"

    - by Peter Sivák
    In Ubuntu, when I click on Switch User Account... and then choose the same account to log in (for example if my name is John Smith, I click on switch user account and then log into the John Smith account again), how can I run a script after that? (I know, that I can run a script after "first" login by putting it in /etc/profile file, but this script is not executed again when I choose switch user account and then immediately log in back to the same account.)

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  • GDL Presents: Women Techmakers with JESS3

    GDL Presents: Women Techmakers with JESS3 Join Leslie, COO and Co-founder of JESS3, in conversation with Megan Smith and Betsy Masiello, as they discuss Leslie's experience growing a design business from two employees to a transnational operation. Hosts: Megan Smith - Vice President, Google [x] | Betsy Masiello - Policy Manager Guest: Leslie Bradshaw - President, COO and Co-founder, JESS3 From: GoogleDevelopers Views: 0 3 ratings Time: 01:00:00 More in Science & Technology

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  • Show Notes: Getting Past the Cloud Hype

    - by Bob Rhubart
    This week’s ArchBeat podcast features an unvarnished bit of conversation culled from a recent virtual meet-up. These meet-ups are informal conversations among architects, many of who have participated in previous ArchBeat programs. There’s no prearranged topic, so the participants talk about whatever is on their minds. The most recent meet-up included Oracle ACE Director Ran Batra, director of cloud computing product development with AT&T, and Daniel Templeton, principal product manager for Oracle Grid Engine, and the man behind Dan T’s GridBlog. The conversation took place at the end of the year – and the end of the decade – a time when most tech publications feature their predictions for the coming year.  I wanted a different spin on that theme, so I asked Ron and Dan to talk about the technologies about which they weren’t all that optimistic.   I found that ten-minute chunk of conversation particularly interesting, so that’s what you’re going to hear this week. Listen Get Social If you have questions or comment for Ron and/or Daniel you can connect via the following: Ron Batra Blog | Twitter | LinkedIn | Oracle Mix | Oracle ACE Profile Daniel Templeton Blog | Twitter | LinkedIn Coming Up Oracle ACE Director Debra Lilley talks about her role in the UKOUG’s development group and that group’s collaboration with Oracle on Oracle Fusion Applications. Dr Frank Munz, author of Middleware and Cloud Computing: Oracle Fusion Middleware on Amazon Web Services and Rackspace Cloud. Stay tuned: http://feeds2.feedburner.com/OtnArch2ArchRSS   del.icio.us Tags: oracle,oracle technology network,archbeat,cloud computing,software architect,podcast Technorati Tags: oracle,oracle technology network,archbeat,cloud computing,software architect,podcast

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  • IE9 GPO Setting "Configure Tracking Protection Lists"

    - by Daniel B
    I've just installed IE9 on my workstations and Server in our network. According to technet article http://technet.microsoft.com/en-us/library/gg699401.aspx There is a GPO setting for IE9 called "Configure Tracking Protection Lists" located at Windows Components\Internet Explorer\Privacy in the admistrative templates. I can find all the other IE9 settings in the GPO, but I cannot find this one. Does anyone know if there is an updated template, or if this setting was removed from the RC version of IE9? Thanks, Daniel

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  • how to set php SERVER_PORT var to 80, behind varnish?

    - by Daniel
    how to force php to read SERVER_PORT as 80, when apache listens on 8080 and varnish listens on 80 ?? if my apache vhost is set to 8080, SERVER_PORT will always be 8080, this is troubling me a little since in many parts of the application some links are calculated with SERVER_NAME and SERVER_PORT together, .. so what I need is that php "believes" that SERVER_PORT is 80, so all links will pass trough varnish regards Daniel

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  • How to count the most recent value based on multiple criteria?

    - by Andrew
    I keep a log of phone calls like the following where the F column is LVM = Left Voice Mail, U = Unsuccessful, S = Successful. A1 1 B1 Smith C1 John D1 11/21/2012 E1 8:00 AM F1 LVM A2 2 B2 Smith C2 John D2 11/22/2012 E1 8:15 AM F2 U A3 3 B3 Harvey C3 Luke D3 11/22/2012 E1 8:30 AM F3 S A4 4 B4 Smith C4 John D4 11/22/2012 E1 9:00 AM F4 S A5 5 B5 Smith C5 John D5 11/23/2012 E5 8:00 AM F5 LVM This is a small sample. I actually have over 700 entries. In my line of work, it is important to know how many unsuccessful (LVM or U) calls I have made since the last Successful one (S). Since values in the F column can repeat, I need to take into consideration both the B and C column. Also, since I can make a successful call with a client and then be trying to contact them again, I need to be able to count from the last successful call. My G column is completely open which is where I would like to put a running total for each client (G5 would = 1 ideally while G4 = 0, G3 = 0, G2 = 2, G1 = 1 but I want these values calculated automatically so that I do not have scroll through 700 names).

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