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  • html5 vs flash - full comparison chart anywhere?

    - by iddqd
    So since Steve Jobs said Flash sucks and implied that HTML5 can do everything Flash can without the need for a Plugin, I keep hearing those exact words from a lot of People. I would really like to have a Chart somewhere (similar to http://en.wikipedia.org/wiki/Comparison_of_layout_engines_%28HTML5%29#Form_elements_and_attributes ) that I can just show to those people. Showing all the little things that Flash can do right now, that HTML5/Ajax/CSS is not yet even thinking about. But of course also the things that HTML5 does better. I would like to see details compared like audio playback, realtime audio processing, byte level access, bitmap data manipulation, webcam access, binary sockets, stuff in the works such as P2P technology (adobe stratus) and all the stuff I don't know about myself. Ideally with examples of what can be accomplished with, lets say Binary Sockets (such as a POP3 client) because otherwise it won't mean a lot to non-programmers since they will just say "well we can do without Binary Sockets". And ideally with some current benchmarks and some examples of websites that use this technology. I've searched the web and am surprised not to find anything. So is there such a comparison somewhere? Or does anybody want to create this and post it to Wikipedia? ;-)

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  • Log 2 N generic comparison tree

    - by Morano88
    Hey! I'm working on an algorithm for Redundant Binary Representation (RBR) where every two bits represent a digit. I designed the comparator that takes 4 bits and gives out 2 bits. I want to make the comparison in log 2 n so If I have X and Y .. I compare every 2 bits of X with every 2 bits of Y. This is smooth if the number of bits of X or Y equals n where (n = 2^X) i.e n = 2,4,8,16,32,... etc. Like this : However, If my input let us say is 6 or 10 .. then it becomes not smooth and I have to take into account some odd situations like this : I have a shallow experience in algorithms .. is there a generic way to do it .. so at the end I get only 2 bits no matter what the input is ? I just need hints or pseudo-code. If my question is not appropriate here .. so feel free to flag it or tell me to remove it. I'm using VHDL by the way!

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  • Windows 7 System Tray Date Display Not Appearing

    - by Anton
    I'm using Windows 7 RC and for some reason, the date won't show at all on my system tray. It used to for a while, but one day it just stopped (I didn't even notice it until someone pointed it out). So I've been trying to fix it, by customizing the format of the date, resetting to defaults, etc... But nothing works, it still doesn't show. The time appears fine.

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  • Python to see if a file falls into a date range

    - by tod
    I have a script that I want to have an if statement check if a file falls between several specified date periods as it searches directories. I have been able to get the time in %Y-%m-%d format for the file, but I can't seem to be able to specify a date range for python to go through. Any ideas/help? Here's what I have so far for name in files: f = os.path.join(root, name) dt = os.path.getmtime(f) nwdt = time.gmtime(dt) ndt = time.strftime('%Y-%m-%d', nwdt)

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  • How to get the Date in a batch file in a predictable format?

    - by AngryHacker
    In a batch file I need to extract a month, day, year from the date command. So I used the following, which essentially parses the Date command to extract its sub strings into a variable: set Day=%Date:~3,2% set Mth=%Date:~0,2% set Yr=%Date:~6,4% This is all great, but if I deploy this batch file to a machine with a different regional/country settings, it fails because month, day and year are in different locations. How can I extract month, day and year regardless of the date format?

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  • DATE function does not support all the dates in DAX by design #powerpivot #tabular #dax

    - by Marco Russo (SQLBI)
    The DATE function in DAX has this simple syntax: DATE( <year>, <month>, <day> ) If you are like me, you never read the BOL notes that says in a clear way that it supports dates beginning with March 1, 1900. In fact, I was wrongly assuming that it would have supported any date that can be represented in a Date data type in Data Models, so all the dates beginning with January 1, 1900. The funny thing is that in some of the BOL documentation you will find that Date data type supports dates after March 1, 1900 (which seems not including that date, but this is a detail…). But we should not digress. The real issue is that if you try to call the DATE function passing values between January 1 and February 28, 1900, you will see a different day as a result. evaluate row ( "x", DATE( 1900, 1, 1 ) ) -- return WRONG result -- [x] 12/31/1899 12:00:00 AM   evaluate row ( "x", DATE( 1901, 2, 29 ) ) -- return WRONG result -- [x] 2/28/1900 12:00:00 AM   evaluate row ( "x", DATE( 1900, 3, 1 ) ) -- return CORRECT result -- [x] 3/1/1900 12:00:00 AM As usual, this is not a bug. It is “by design”. The DATE function works in this way in Excel. And also in Excel it was “by design”. In this case the design is having the same bug of Lotus 1-2-3 that handled 1900 a leap year, even though it isn’t. The first release of Lotus 1-2-3 is dated 1983. I hope many of my readers are younger than that. I tried to open a bug in Connect. Please vote it. I would like if Microsoft changed this type of items from “by design” (as we can expect) to “by genetic disease”. Or by “historical respect”, in order to be more politically correct.

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  • count how many days within a date range are within another date range

    - by joko13
    From October 1st to March 31 the fee is $1 (season 1). From April 1st to September 30 the fee is $2 (season 2). How can I calculate the total fee of a given date range (user input) depending on how many days of this date range fall into season 1 and season 2? The following gives me the number of days of the user´s date range, but I have no idea how to test against season 1 or season 2: $user_input_start_date = getdate( $a ); $user_input_end_date = getdate( $b ); $start_date_new = mktime( 12, 0, 0, $user_input_start_date['mon'], $user_input_start_date['mday'], $user_input_start_date['year'] ); $end_date_new = mktime( 12, 0, 0, $user_input_end_date['mon'], $user_input_end_date['mday'], $user_input_end_date['year'] ); return round( abs( $start_date_new - $end_date_new ) / 86400 ); Thanks for your help! EDIT: Given that a date range starts and ends in 2012 or starts in 2012 and ends in 2013 alone gives me 10 different possibilities of in which season a date range can start and where it can end. There must be a better solution than iterating if/else and comparing dates over and over again for the following conditions: Date range is completely within season 1 Date range starts in season 1 and ends in season 2 Date range starts in season 1, spans across season 2 and ends in the second part of season 1 ... and so forth with "Starts in season 2", etc

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  • Mac OS date command - getting higher temporal resolution

    - by Mark
    Hey all, I am trying to use the date command in Terminal on multiple Mac OS X machines that are synced via NTP to synchronize some code in a program. Essentially I am running a program... MyProgram with arguments[date] I can get date to give me the seconds since the Unix epoch with the %M specifier. When I try to use %N to get nanosecond resolution, date just returns N. Is there anyway to get date to give me finer then second resolution? I wouldn't even mind passing two arguments such as (date +%M):arg2 And then converting units in the program. Many thanks in advance! %N specifier listed here: http://en.wikipedia.org/wiki/Date_(Unix)

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  • Java - Parsing a Date from a String

    - by Yatendra Goel
    I want to parse a java.util.Date from a String. I tried the following code but got unexpected output: Date getDate() { Date date = null; SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd"); try { date = sdf.parse("Sat May 11"); } catch (ParseException ex) { Logger.getLogger(URLExtractor.class.getName()).log(Level.SEVERE, null, ex); return null; } return date; } When I run the above code, I got the following output: Mon May 11 00:00:00 IST 1970

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  • Mac OS date command - getting higher resolution time

    - by Mark
    Hey all, I am trying to use the date command in Terminal on multiple Mac OS X machines that are synced via NTP to synchronize some code in a program. Essentially I am running a program... MyProgram with arguments[date] I can get date to give me the seconds since the Unix epoch with the %M specifier. When I try to use %N to get nanosecond resolution, date just returns N. Is there anyway to get date to give me finer then second resolution? I wouldn't even mind passing two arguments such as (date +%M):arg2 And then converting units in the program. Many thanks in advance! %N specifier listed here: http://en.wikipedia.org/wiki/Date_(Unix)

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  • Twitter date unparseable?

    - by Andreas
    Hi, I want to convert the date string in a Twitter response to a Date object, but I always get a ParseException and I cannot see the error!?! Input string: Thu Dec 23 18:26:07 +0000 2010 SimpleDateFormat Pattern: EEE MMM dd HH:mm:ss ZZZZZ yyyy Method: public static Date getTwitterDate(String date) { SimpleDateFormat sf = new SimpleDateFormat(TWITTER); sf.setLenient(true); Date twitterDate = null; try { twitterDate = sf.parse(date); } catch (Exception e) {} return twitterDate; } I also tried this: http://friendpaste.com/2IaKdlT3Zat4ANwdAhxAmZ but that gives the same result. I use Java 1.6 on Mac OS X. Cheers, Andi

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  • Subtracting Delphi Time Ranges from a Date Range, Calculate Remaining Time

    - by Anagoge
    I'm looking for an algorithm that will help calculate a workday working time length. It would have an input date range and then allow subtracting partially or completely intersecting time range slices from that date range and the result would be the number of minutes (or the fraction/multiple of a day) left in the original date range, after subtracting out the various non-working time slices. For Example: Input date range: 1/4/2010 11:21 am - 1/5/2010 3:00 pm Subtract out any partially or completely intersecting slices like this: Remove all day Sunday Non-Sundays remove 11:00 - 12:00 Non-Sundays remove time after 5:00 pm Non-Sundays remove time before 8:00 am Non-Sundays remove time 9:15 - 9:30 am Output: # of minutes left in the input date range I don't need anything overly-general. I could hardcode the rules to simplify the code. If anyone knows of sample code or a library/function somewhere, or has some pseudo-code ideas, I'd love something to start with. I didn't see anything in DateUtils, for example. Even a basic function that calculates the number of minutes of overlap in two date ranges to subtract out would be a good start.

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  • Wordpress Events List Date Problem

    - by Roger
    Hi, I'm having a problem displaying events in the correct order in wordpress. I think the problem is because wordpress is treating the date as a string and ordering it by the day because it's in british date format. The goal is to display a list of future events with the most current event at the top of the list. But I must use the british date format of dd/mm/yyyy. Do I need to go back to the drawing board or is there a way of converting the date to achieve the result I need? Thanks in advance :) <ul> <?php // Get today's date in the right format $todaysDate = date('d/m/Y');?> <?php query_posts('showposts=50&category_name=Training&meta_key=date&meta_compare=>=&meta_value=' . $todaysDate . '&orderby=meta_value&order=ASC'); ?> <?php if (have_posts()) : while (have_posts()) : the_post(); ?> <li> <h3><a href="<?php the_permalink(); ?>"> <?php the_title(); ?> </a></h3> <?php $getDate = get_post_meta($post->ID, 'date', TRUE); $dateArray = explode('/', $getDate); ?> <?php if($getDate != '') { ?> <div class="coursedate rounded"><?php echo date('d F Y', mktime(0, 0, 0, $dateArray[1], $dateArray[0], $dateArray[2])); ?></div> <?php } ?> <p><?php get_clean_excerpt(140, get_the_content()); ?>...</p> <p><strong><a class="link" href="<?php the_permalink(); ?>">For further details and booking click here</a></strong></p> </li> <?php endwhile; ?> <?php else : ?> <li>Sorry, no upcoming events!</li> <?php endif; ?>

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  • Create lags with a for-loop in R

    - by cptn
    I've got a data.frame with stock data of several companies (here it's only two). I want 10 additional columns in my stock data.frame df with lagged dates (from -5 days to +5 days) for both companies in my event data.frame. I'm using a for loop which is probably not the best solution, but it works partially. DATE <- c("01.01.2000","02.01.2000","03.01.2000","06.01.2000","07.01.2000","09.01.2000","10.01.2000","01.01.2000","02.01.2000","04.01.2000","06.01.2000","07.01.2000","09.01.2000","10.01.2000") RET <- c(-2.0,1.1,3,1.4,-0.2, 0.6, 0.1, -0.21, -1.2, 0.9, 0.3, -0.1,0.3,-0.12) COMP <- c("A","A","A","A","A","A","A","B","B","B","B","B","B","B") df <- data.frame(DATE, RET, COMP, stringsAsFactors=F) df # DATE RET COMP # 1 01.01.2000 -2.00 A # 2 02.01.2000 1.10 A # 3 03.01.2000 3.00 A # 4 06.01.2000 1.40 A # 5 07.01.2000 -0.20 A # 6 09.01.2000 0.60 A # 7 10.01.2000 0.10 A # 8 01.01.2000 -0.21 B # 9 02.01.2000 -1.20 B # 10 04.01.2000 0.90 B # 11 06.01.2000 0.30 B # 12 07.01.2000 -0.10 B # 13 09.01.2000 0.30 B # 14 10.01.2000 -0.12 B this loop works fine comp <- as.vector(unique(df$COMP)) mylist <- vector('list', length(comp)) # create lags in DATE for(i in 1:length(comp)) { print(i) comp_i <- comp[i] df_k <- df[df$COMP %in% comp_i, ] # all trading days of one firm df_k <- transform(df_k, DATEm1 = c(NA, head(DATE, -1)), DATEm2 = c(NA, NA, head(DATE, -2)), DATEm3 = c(NA, NA, NA, head(DATE, -3)), DATEm4 = c(NA, NA, NA, NA,head(DATE, -4)), DATEm5 = c(NA, NA, NA, NA, NA, head(DATE, -5)), DATEp1 = c(DATE[-1], NA)) #DATEp2 = c(DATE[-2], NA, NA), #DATEp3 = c(DATE[-3], NA, NA, NA), #DATEp4 = c(DATE[-4], NA, NA, NA, NA), #DATEp5 = c(DATE[-5], NA, NA, NA, NA, NA)) mylist[[i]] = df_k } df1 <- do.call(rbind, mylist) But if I add the lines with DATEp2, DATEp3, DATEp4, DATEp5. the code doesn't work. Can anybody tell me what I'm doing wrong here? Here the code with all the lagged dates. # create lags in DATE for(i in 1:length(comp)) { print(i) comp_i <- comp[i] df_k <- df[df$COMP %in% comp_i, ] # all trading days of one firm df_k <- transform(df_k, DATEm1 = c(NA, head(DATE, -1)), DATEm2 = c(NA, NA, head(DATE, -2)), DATEm3 = c(NA, NA, NA, head(DATE, -3)), DATEm4 = c(NA, NA, NA, NA,head(DATE, -4)), DATEm5 = c(NA, NA, NA, NA, NA, head(DATE, -5)), DATEp1 = c(DATE[-1], NA), DATEp2 = c(DATE[-2], NA, NA), DATEp3 = c(DATE[-3], NA, NA, NA), DATEp4 = c(DATE[-4], NA, NA, NA, NA), DATEp5 = c(DATE[-5], NA, NA, NA, NA, NA)) mylist[[i]] = df_k } df1 <- do.call(rbind, mylist)

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  • Store date object in sqlite database

    - by bnabilos
    Hello, I'm using a database in my Java project and I want to store date in it, the 5th and the 6th parameter are Date Object. I used the solution below but I have errors in these 2 lines : creerFilm.setDate(5, new Date (getDateDebut().getDate())); creerFilm.setDate(6, new Date (getDateFin().getDate())); PreparedStatement creerFilm = connecteur.getConnexion().prepareStatement("INSERT INTO FILM (ID, REF, NOM, DISTRIBUTEUR, DATEDEBUT, DATEFIN) VALUES (?, ?, ?, ?, ?, ?)"); creerFilm.setInt(1, getId()); creerFilm.setString(2, getReference()); creerFilm.setString(3, getNomFilm()); creerFilm.setString(4, getDistributeur()); creerFilm.setDate(5, new Date (getDateDebut().getDate())); creerFilm.setDate(6, new Date (getDateFin().getDate())); creerFilm.executeUpdate(); creerFilm.close(); Can you help me to fix that please ? Thank you

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  • How to distinguish date at midnight from date w/o time in Oracle?

    - by Swiety
    I would like to distinguish date at midnight (i.e. '12/05/2010 00:00:00') from date without time specified (i.e. '12/05/2010'). This value is provided by user, sometimes it is only date which is important, sometimes it is date and time and later the application is expected to show the time only when it was explicitly provided. So for the following inputs I would expect the following outputs: for '12/05/2010' I would expect '12/05/2010' for '12/05/2010 09:23' I would expect '12/05/2010 09:23' for '12/05/2010 00:00' I would expect '12/05/2010 00:00' I know I can model it in two separate columns, date and time, but I was wondering was there any way of handling this in single date column?

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  • Ambiguous Comparison Hint

    - by Ondrej Brejla
    Hi everybody! Today we would like to show you some new hint which will be available in NetBeans 7.3. It's called Ambiguous Comparison hint. Its name seems to be quite fuzzy, but it describes exactly what the hint does. It tries to check all comparisons whether they are intended. Because sometimes you want to make a simple assignment, but you make a typo and comparison appears. It's really dangerous mistake because then your code doesn't work as expected. Your application can produce buggy results. So here is how it looks like: But sometimes a comparison is really intended. E.g. in return statements when you want to return a boolean, so then the hint works as expected and no warning appears. That's all for today and as usual, please test it and if you find something strange, don't hesitate to file a new issue (component php, subcomponent Editor). Thanks.

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  • In PHP, how do I add 3 months to the purchase date retrieved from the iPhone InApp receipt?

    - by Cocoanut
    After I have validated the receipt against the App Store from my PHP server, the App Store sends me back a JSON response with "status" : 0 "receipt" : ( .... ) One of the receipt items is "purchase_date" which contains the following string (example) "2010-02-09 19:17:04 Etc/GMT" I'm trying to establish a subscription service and would like to add 3 months to this date and then write that expiry date into a MySQL table. Is there a string-to-date type function in PHP that can allow me to achieve the adding of 3 months? I have found this example which looks like it adds 1 month to a date: $date = date("Y-m-d");// current date $date = strtotime(date("Y-m-d", strtotime($date)) . " +1 month"); But I'm not sure how I can turn the string passed by the App Store into a PHP recognised date.

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  • In registration form adding date dialogbox how can apply validation in system date in dialog ends

    - by narasimha
    hi i am implementing registration form adding date field then click icon to display date dialog window then limit date validation in system date below date only how can implement the validation protected Dialog onCreateDialog(int id) { Calendar c = Calendar.getInstance(); int cyear = c.get(Calendar.YEAR); int cmonth = c.get(Calendar.MONTH); int cday = c.get(Calendar.DAY_OF_MONTH); switch (id) { case DATE_DIALOG_ID: return new DatePickerDialog(this, mDateSetListener, cyear, cmonth, cday); } return null; } private DatePickerDialog.OnDateSetListener mDateSetListener = new DatePickerDialog.OnDateSetListener() { public void onDateSet(DatePicker view, int year, int monthOfYear, int dayOfMonth) { String date_selected = String.valueOf(monthOfYear+1)+" /"+String.valueOf(dayOfMonth)+" /"+String.valueOf(year); EditText birthday=(EditText) findViewById(R.id.EditTextBirthday); birthday.setText(date_selected); } }; public void onClick(View v) { if(v == b1) showDialog(DATE_DIALOG_ID); } } ** showing in system date in below dates only how can implemented some solution in running year to below years are display not incrementing above years this condition are appliying validations how can implemented ?

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  • Using an objects date (without time) for a table header instead of an objects date and time (iphone)

    - by billywilliamton
    I've been working on an iphone project and have run into an issue. Currently In the table view where it displays all the objects, I use headers based on the objects datePerformed field. The only problem is that my code apparently creates a header that contains both the date and time resulting in objects not being grouped solely by their date as I intended, but rather based on their date and time. I'm not sure if it matters, but when an object is created I use a date picker to pick the date, but not the time. I was wondering if anyone could give me any suggestions or advice. Here is the code where i set up the fetchedResultsController - (NSFetchedResultsController *)fetchedResultsController { if (fetchedResultsController != nil) { return fetchedResultsController; } // Create and configure a fetch request with the Exercise entity. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Exercise" inManagedObjectContext:managedObjectContext]; [fetchRequest setEntity:entity]; // Create the sort descriptors array using date and name NSSortDescriptor *dateDescriptor = [[NSSortDescriptor alloc] initWithKey:@"datePerformed" ascending:NO]; NSSortDescriptor *nameDescriptor = [[NSSortDescriptor alloc] initWithKey:@"name" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:dateDescriptor, nameDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; // Create and initialize the fetch results controller NSFetchedResultsController *aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:managedObjectContext sectionNameKeyPath:@"datePerformed" cacheName:@"Root"]; self.fetchedResultsController = aFetchedResultsController; fetchedResultsController.delegate = self; // Memory management calls [aFetchedResultsController release]; [fetchRequest release]; [dateDescriptor release]; [nameDescriptor release]; [sortDescriptors release]; return fetchedResultsController; } Here's where I set up the table header properties - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { // Display the exercise' date as section headings. return [[[fetchedResultsController sections] objectAtIndex:section] name]; } Any suggestions welcome. Thanks for your time. -Billy Williamton

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  • How do I change the date format in Gnome 3 shell?

    - by James Haigh
    I want to change the date/time format on the top panel to a format close to RFC 3339 / ISO 8601, like one of these: %F %T ? 2013-06-24 16:13:00 %F %a %T ? 2013-06-24 Mon 16:13:00 %A %F %T ? Monday 2013-06-24 16:13:00 I know Unity has a preference somewhere hidden away in dconf, this is how I did it in Unity, but I can't find such a preference for Gnome 3 shell. Preferably, I'd also like to set one of these as my system-wide date/time locale preference.

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  • Log "date -s" command

    - by LinuxPenseur
    Hi, I know that the date -s <STRING> command sets the time described by the string STRING. What i want is to log the above command whenever it is used to set the time into the file /tmp/log/user.log. In my Linux distribution the logging is done by syslog-ng. I already have some logs going into /tmp/log/user.log. This is the content of /etc/syslog-ng/syslog-ng.conf in my system for logging into /tmp/log/user.log destination d_notice { file("/tmp/log/user.log");}; filter f_filter10 { level(notice) and not facility(mail,authpriv,cron); }; log { source(s_sys); filter(f_filter10); destination(d_notice); }; What should i do so that date -s command is also logged into /tmp/log/user.log

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  • Vista: "Change date and time" causes permissions error

    - by alexsome
    I double-click on the time in the bottom right to open the date and time panel. Then I click on the "Change date and time..." button (which has a shield) and I get the UAC dialog. I click "Continue", then am presented with an error that reads: Unable to continue You do not have permission to perform this task. Please contact your computer administrator for help. I will mention I have Comodo installed, but I have turned it off to test this out and I get the same results. All that I've found while googling were suggestions to turn UAC off, but I am interested in learning what the actual problem is. Thanks in advance.

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  • javascript Date.parse

    - by user121196
    Case One: new Date(Date.parse("Jul 8, 2005")); Output: Fri Jul 08 2005 00:00:00 GMT-0700 (PST) Case Two: new Date(Date.parse("2005-07-08")); Output: Thu Jul 07 2005 17:00:00 GMT-0700 (PST) Why is the second parse incorrect?

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  • SQL Query to check ALL days exist between a date range

    - by CL4NCY
    Hi, I have a table of Prices with a start date, end date and price. I want a search to pass in a date range and return whether a price exists for all days in that range. The date range can span multiple prices, just not have any gaps in between. Is this possible? Prices startDate datetime endDate datetime price DECLARE @startDate datetime = '2010-04-01', @endDate datetime = '2010-04-30' SELECT * FROM Prices WHERE @startDate BETWEEN startDate AND endDate...

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