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  • How to Configure OpenLDAP on Ubuntu 10.04 Server

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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  • How to configure ldap on ubuntu 10.04 server

    - by user3215
    I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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  • Select From MySQL PHP

    - by Liju
    Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • change owner/uid of mount point upon mount

    - by Shiplu
    The scenario is like this. Bob has a computer. It crashed. Now he only has the hdd. The hdd is in ext3 format. He go to his office and told the sys admin John to mount this hdd and put the mount point in his home directory. John used the following fstab entries. # Bobs harddisk /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/windows ntfs ro,loop,offset=32256 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/linux ext3 ro,loop,offset=14048810496 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/extra ntfs ro,loop,offset=28015335936 0 0 Bob was happy. He could access his old extra and windows. Specially the Documents and Settings in windows was helpful for him. But he found a problem. He is a web developer and all his websites are in linux/home/bob/public_html directory. When he tried to access that public_html directory he got permission_denied. He executed ls -lh he saw this. drwxr-xr-x 2 john john 4.0K Nov 9 2011 Desktop drwxr-xr-x 3 john john 4.0K Aug 12 2011 Documents drwxr-xr-x 3 john john 4.0K Aug 21 2011 public_html He contacted John thinking he might be mistakenly did this. But John couldn't find a way why this happend? Then one thing came into his mind file system hardly store username. They store uids. So he executed ls -ln drwxr-xr-x 2 1000 1000 4096 Nov 9 2011 Desktop drwxr-xr-x 3 1000 1000 4096 Aug 12 2011 Documents drwxr-xr-x 3 1000 1000 4096 Aug 21 2011 public_html John thinks 1000 is the first uid on a linux system. As he is the admin of the current system. He created his account first. so Johns uid was 1000. Bob also setup his private system and crated his account first. So Bobs uid was 1000 too. So thats an expected behavior. But problem remains. How can Bob access those websites in public_html?

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  • Looking for equivalent of ProxyPassReverseMatch in Apache to fix missing trailing forward slash issue

    - by Alex Man
    I have two web servers, www.example.com and www.userdir.com. I'm trying to make www.example.com as the front end proxy server to serve requests like in the format of http://www.example.com/~username such as http://www.example.com/~john/ so that it sends an internal request of http://www.userdir.com/~john/ to www.userdir.com. I can achieve this in Apache with ProxyPass /~john http://www.userdir.com/~john ProxyPassReverse /~john http://www.userdir.com/~john The ProxyPassReverse is necessary as without it a request like http://www.example.com/~john without the trailing forward slash will be redirected as http://www.userdir.com/~john/ and I want my users to stay in the example.com space. Now, my problem is that I have a lot of users and I cannot list all those user names in httpd.conf. So, I use ProxyPassMatch ^(/~.*)$ http://www.userdir.com$1 but there is no such thing as ProxyPassReverseMatch in Apache. Without it, whenever the trailing forward slash is missing in the URL, one will be directed to www.userdir.com, and that's not what I want. I also tried the following to add the trailing forward slash RewriteCond %{REQUEST_URI} ^/~[^./]*$ RewriteRule ^/(.*)$ http://www.userdir.com/$1/ [P] but then it will render a page with broken image and CSS because they are linked to http://www.example.com/images/image.gif while it should be http://www.example.com/~john/images/image.gif. I have been googling for a long time and still can't figure out a good solution for this. Would really appreciate it if any one can shed some light on this issue. Thank you!

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  • Using git through cygwin on windows 8

    - by 9point6
    I've got a windows 8 dev preview (not sure if it's relevant, but I never had this hassle on w7) machine and I'm trying to clone a git repo from github. The problem is that my ~/.ssh/id_rsa has 440 permissions and it needs to be 400. I've tried chmodding it but the any changes on the user permissions gets reflected in the group permissions (i.e. chmod 600 results in 660, etc). This appears to be constant throughout any file in the whole filesystem. I've tried messing with the ACLs but to no avail (full control on my user and deny everyone resulted in 000) here's a few outputs to help: $ git clone [removed] Cloning into [removed]... @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ WARNING: UNPROTECTED PRIVATE KEY FILE! @ @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ Permissions 0660 for '/home/john/.ssh/id_rsa' are too open. It is required that your private key files are NOT accessible by others. This private key will be ignored. bad permissions: ignore key: /home/john/.ssh/id_rsa Permission denied (publickey). fatal: The remote end hung up unexpectedly $ ll ~/.ssh total 6 -r--r----- 1 john None 1675 Nov 30 19:15 id_rsa -rw-rw---- 1 john None 411 Nov 30 19:15 id_rsa.pub -rw-rw-r-- 1 john None 407 Nov 30 18:43 known_hosts $ chmod -v 400 ~/.ssh/id_rsa mode of `/home/john/.ssh/id_rsa' changed from 0440 (r--r-----) to 0400 (r--------) $ ll ~/.ssh total 6 -r--r----- 1 john None 1675 Nov 30 19:15 id_rsa -rw-rw---- 1 john None 411 Nov 30 19:15 id_rsa.pub -rw-rw-r-- 1 john None 407 Nov 30 18:43 known_hosts $ set | grep CYGWIN CYGWIN='sbmntsec ntsec server ntea' I realize I could use msysgit or something, but I'd prefer to be able to do everything from a single terminal Edit: Msysgit doesn't work either for the same reasons

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  • Building a project in VS that depends on a static and dynamic library

    - by fg nu
    Noob noobin'. I would appreciate some very careful handholding in setting up an example in Visual Studio 2010 Professional where I am trying to build a project which links: a previously built static library, for which the VS project folder is "C:\libjohnpaul\" a previously built dynamic library, for which the VS project folder is "C:\libgeorgeringo\" These are listed as Recipes 1.11, 1.12 and 1.13 in the C++ Cookbook. The project fails to compile for me with unresolved dependencies (see details below), and I can't figure out why. Project 1: Static Library The following are the header and source files that were compiled in this project. I was able to compile this project fine in VS2010, to the named standard library "libjohnpaul.lib" which lives in the folder ("C:/libjohnpaul/Release/"). // libjohnpaul/john.hpp #ifndef JOHN_HPP_INCLUDED #define JOHN_HPP_INCLUDED void john( ); // Prints "John, " #endif // JOHN_HPP_INCLUDED // libjohnpaul/john.cpp #include <iostream> #include "john.hpp" void john( ) { std::cout << "John, "; } // libjohnpaul/paul.hpp #ifndef PAUL_HPP_INCLUDED #define PAUL_HPP_INCLUDED void paul( ); // Prints " Paul, " #endif // PAUL_HPP_INCLUDED // libjohnpaul/paul.cpp #include <iostream> #include "paul.hpp" void paul( ) { std::cout << "Paul, "; } // libjohnpaul/johnpaul.hpp #ifndef JOHNPAUL_HPP_INCLUDED #define JOHNPAUL_HPP_INCLUDED void johnpaul( ); // Prints "John, Paul, " #endif // JOHNPAUL_HPP_INCLUDED // libjohnpaul/johnpaul.cpp #include "john.hpp" #include "paul.hpp" #include "johnpaul.hpp" void johnpaul( ) { john( ); paul( ); Project 2: Dynamic Library Here are the header and source files for the second project, which also compiled fine with VS2010, and the "libgeorgeringo.dll" file lives in the directory "C:\libgeorgeringo\Debug". // libgeorgeringo/george.hpp #ifndef GEORGE_HPP_INCLUDED #define GEORGE_HPP_INCLUDED void george( ); // Prints "George, " #endif // GEORGE_HPP_INCLUDED // libgeorgeringo/george.cpp #include <iostream> #include "george.hpp" void george( ) { std::cout << "George, "; } // libgeorgeringo/ringo.hpp #ifndef RINGO_HPP_INCLUDED #define RINGO_HPP_INCLUDED void ringo( ); // Prints "and Ringo\n" #endif // RINGO_HPP_INCLUDED // libgeorgeringo/ringo.cpp #include <iostream> #include "ringo.hpp" void ringo( ) { std::cout << "and Ringo\n"; } // libgeorgeringo/georgeringo.hpp #ifndef GEORGERINGO_HPP_INCLUDED #define GEORGERINGO_HPP_INCLUDED // define GEORGERINGO_DLL when building libgerogreringo.dll # if defined(_WIN32) && !defined(__GNUC__) # ifdef GEORGERINGO_DLL # define GEORGERINGO_DECL _ _declspec(dllexport) # else # define GEORGERINGO_DECL _ _declspec(dllimport) # endif # endif // WIN32 #ifndef GEORGERINGO_DECL # define GEORGERINGO_DECL #endif // Prints "George, and Ringo\n" #ifdef __MWERKS__ # pragma export on #endif GEORGERINGO_DECL void georgeringo( ); #ifdef __MWERKS__ # pragma export off #endif #endif // GEORGERINGO_HPP_INCLUDED // libgeorgeringo/ georgeringo.cpp #include "george.hpp" #include "ringo.hpp" #include "georgeringo.hpp" void georgeringo( ) { george( ); ringo( ); } Project 3: Executable that depends on the previous libraries Lastly, I try to link the aforecompiled static and dynamic libraries into one project called "helloBeatlesII" which has the project directory "C:\helloBeatlesII" (note that this directory does not nest the other project directories). The linking process that I did is described below: To the "helloBeatlesII" solution, I added the solutions "libjohnpaul" and "libgeorgeringo"; then I changed the properties of the "helloBeatlesII" project to additionally point to the include directories of the other two projects on which it depends ("C:\libgeorgeringo\libgeorgeringo" & "C:\libjohnpaul\libjohnpaul"); added "libgeorgeringo" and "libjohnpaul" to the project dependencies of the "helloBeatlesII" project and made sure that the "helloBeatlesII" project was built last. Trying to compile this project gives me the following unsuccessful build: 1------ Build started: Project: helloBeatlesII, Configuration: Debug Win32 ------ 1Build started 10/13/2012 5:48:32 PM. 1InitializeBuildStatus: 1 Touching "Debug\helloBeatlesII.unsuccessfulbuild". 1ClCompile: 1 helloBeatles.cpp 1ManifestResourceCompile: 1 All outputs are up-to-date. 1helloBeatles.obj : error LNK2019: unresolved external symbol "void __cdecl georgeringo(void)" (?georgeringo@@YAXXZ) referenced in function _main 1helloBeatles.obj : error LNK2019: unresolved external symbol "void __cdecl johnpaul(void)" (?johnpaul@@YAXXZ) referenced in function _main 1E:\programming\cpp\vs-projects\cpp-cookbook\helloBeatlesII\Debug\helloBeatlesII.exe : fatal error LNK1120: 2 unresolved externals 1 1Build FAILED. 1 1Time Elapsed 00:00:01.34 ========== Build: 0 succeeded, 1 failed, 2 up-to-date, 0 skipped ========== At this point I decided to call in the cavalry. I am new to VS2010, so in all likelihood I am missing something straightforward.

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  • Love and Hate Outlook autocomplete, Outlook 2010/Exchange 2010

    - by Kay Sellenrode
    I think that almost every Exchange admin can concur with me that the Outlook autocomplete cache is one of those things you love but at the same time also hate. Users mostly love this function, except when it fails.Luckily since Outlook 2010 things got a little better and we got rid of the dreaded nk2 files.Outlook 2010 now includes a folder named "Suggested Contacts", all users you send an email to and that don't already have an contact object are saved in this suggested contacts folder.A lot of people thought this folder is also the source for the autocomplete cache, which would make it somewhat easy to manage, I wish the solution was that easy.Badly enough separate from the suggested contacts, outlook still maintains a cache for the autocomplete function. Let us say you run in to the following situation: John works for company A and is a popular contact for almost everyone in your organization.Now John quit his job at Company A and moved to Company B.Luckily John maintains your company as customer, but his email address is now changed from companyA.com to companyB.comSince you don't want to do any business with Company A anymore, you want to make sure none of your users accidentally mail to his old address.Now this is where the real fun starts, cause almost all of your 1000 users have mailed at least once with John.Resulting in the fact that every user has John most probably listed in their autocomplete cache.  I have run into sort like situations multiple times with several customers, which is always a pain.And of course this blog post is the result of one of those issues once again.I knew that with the Suggested contacts we could do more than previously, but still never spent time on it before.But today I thought lets nail this now and forever!!  Ok let's start of that things are different for every combination of outlook and exchange.I explain the procedure for Exchange 2010 SP1+ in combination with Outlook 2010.At first we want to get rid of all contact objects that contain [email protected] do this we need to be assigned to the RBAC role "Mailbox Import Export", which can be done through the Exchange Control panel.In my test environment I assigned this role to the Organization admins, but in real life you might want to add it to a custom role. Open the Exchange control panel by logging in to the ecp url, in my case https://ITFEX.itf.local/ECP, and make sure you selected your organization as management scope.Browse to Roles & Auditing, and open the properties for the organization management role group.click on the Add button to add a new role to the Organization Management role group, select the Mailbox Import Export role and click on add and OK to add it to the role.  Once you have assigned that role to your account you can open the Exchange Management Shell and execute the following command: Get-mailbox –resultsize unlimited | search-mailbox –targetmailbox "your.account" –targetfolder searchanddelete –loglevel full –logonly –searchquery "kind:contact AND [email protected]" This command will create a list with all mailboxes and any contacts that were found with an email address that contains [email protected], this list is then posted in the mailbox you specified at your.account in the folder searchanddelete.Now examine the report that was created and posted in the mailbox to see if it matches what you think it should match.My results looked like this:  When you're confident that the search includes all references and no false positives you can execute almost the same command, but this time with an delete action instead of the logonly. Get-mailbox –resultsize unlimited | search-mailbox –targetmailbox "your.account" –targetfolder searchanddelete –loglevel full –DeleteContent –searchquery "kind:contact AND [email protected]" Now most people would think this would remove the contact object from the suggested contacts, resulting in a removal from the autocomplete list.Sad but not true, to clean up the autocomplete list start Outlook with the command: "outlook /cleanautocompletecache" This will result in an empty cache, but luckily this is rebuild based on the suggested contacts, which now doesn't include the [email protected] contact anymore.

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  • SQL: Add counters in select

    - by etarvt
    Hi, I have a table which contains names: Name ---- John Smith John Smith Sam Wood George Wright John Smith Sam Wood I want to create a select statement which shows this: Name 'John Smith 1' 'John Smith 2' 'Sam Wood 1' 'George Wright 1' 'John Smith 3' 'Sam Wood 2' In other words, I want to add separate counters to each name. Is there a way to do it without using cursors?

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • Case insensitive duplicates SQL

    - by hdx
    So I have a users table where the user.username has many duplicates like: username and Username and useRnAme john and John and jOhn That was a bug and these three records should have been only one. I'm trying to come up with a SQL query that lists all of these cases ordered by their creation date, so ideally the result should be something like this: username jan01 useRnAme jan02 Username jan03 john feb01 John feb02 jOhn feb03 Any suggestions will be much appreciated

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  • Permission problem - users can't access main index.php anymore

    - by JMan
    From /var/www, I executed "chmod -R 774 ." and now none of my .php scripts are accessible. From my browser, when I type in mydomain.com or mydomain.com/test2.php or mydomain.com/test.php, I get the 403 Forbidden error msg. So, I changed the permissions of 3 of the .php scripts to 775, but this didn't help either. Here is the output from "ls -la /var/www": drwxrwxr-- 6 john wheel 4096 2010-09-29 17:38 . drwxr-xr-x 14 root root 4096 2010-09-27 21:15 .. -rwxrwxr-x 1 john wheel 3353 2010-09-29 05:29 index.php -rwxrwxr-x 1 john wheel 124 2010-09-27 23:12 .htaccess -rwxrwxr-x 1 john john 34 2010-09-29 17:39 test2.php -rwxrwxr-x 1 john john 26 2010-09-28 22:08 test.php The .htaccess file does a URL mod_rewrite so typing in index.php is not needed. Thanks for your help.

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  • insert multiple elements in string in python

    - by Anurag Sharma
    I have to build a string like this { name: "john", url: "www.dkd.com", email: "[email protected]" } where john, www.dkd.com and [email protected] are to be supplied by variables I tried to do the following s1 = "{'name:' {0},'url:' {1},'emailid:' {2}}" s1.format("john","www.dkd.com","[email protected]") I am getting the following error Traceback (most recent call last): File "<stdin>", line 1, in <module> KeyError: "'name" Dont able to understand what I am doing wrong

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  • JavaScript Class Patterns

    - by Liam McLennan
    To write object-oriented programs we need objects, and likely lots of them. JavaScript makes it easy to create objects: var liam = { name: "Liam", age: Number.MAX_VALUE }; But JavaScript does not provide an easy way to create similar objects. Most object-oriented languages include the idea of a class, which is a template for creating objects of the same type. From one class many similar objects can be instantiated. Many patterns have been proposed to address the absence of a class concept in JavaScript. This post will compare and contrast the most significant of them. Simple Constructor Functions Classes may be missing but JavaScript does support special constructor functions. By prefixing a call to a constructor function with the ‘new’ keyword we can tell the JavaScript runtime that we want the function to behave like a constructor and instantiate a new object containing the members defined by that function. Within a constructor function the ‘this’ keyword references the new object being created -  so a basic constructor function might be: function Person(name, age) { this.name = name; this.age = age; this.toString = function() { return this.name + " is " + age + " years old."; }; } var john = new Person("John Galt", 50); console.log(john.toString()); Note that by convention the name of a constructor function is always written in Pascal Case (the first letter of each word is capital). This is to distinguish between constructor functions and other functions. It is important that constructor functions be called with the ‘new’ keyword and that not constructor functions are not. There are two problems with the pattern constructor function pattern shown above: It makes inheritance difficult The toString() function is redefined for each new object created by the Person constructor. This is sub-optimal because the function should be shared between all of the instances of the Person type. Constructor Functions with a Prototype JavaScript functions have a special property called prototype. When an object is created by calling a JavaScript constructor all of the properties of the constructor’s prototype become available to the new object. In this way many Person objects can be created that can access the same prototype. An improved version of the above example can be written: function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { toString: function() { return this.name + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); In this version a single instance of the toString() function will now be shared between all Person objects. Private Members The short version is: there aren’t any. If a variable is defined, with the var keyword, within the constructor function then its scope is that function. Other functions defined within the constructor function will be able to access the private variable, but anything defined outside the constructor (such as functions on the prototype property) won’t have access to the private variable. Any variables defined on the constructor are automatically public. Some people solve this problem by prefixing properties with an underscore and then not calling those properties by convention. function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { _getName: function() { return this.name; }, toString: function() { return this._getName() + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); Note that the _getName() function is only private by convention – it is in fact a public function. Functional Object Construction Because of the weirdness involved in using constructor functions some JavaScript developers prefer to eschew them completely. They theorize that it is better to work with JavaScript’s functional nature than to try and force it to behave like a traditional class-oriented language. When using the functional approach objects are created by returning them from a factory function. An excellent side effect of this pattern is that variables defined with the factory function are accessible to the new object (due to closure) but are inaccessible from anywhere else. The Person example implemented using the functional object construction pattern is: var personFactory = function(name, age) { var privateVar = 7; return { toString: function() { return name + " is " + age * privateVar / privateVar + " years old."; } }; }; var john2 = personFactory("John Lennon", 40); console.log(john2.toString()); Note that the ‘new’ keyword is not used for this pattern, and that the toString() function has access to the name, age and privateVar variables because of closure. This pattern can be extended to provide inheritance and, unlike the constructor function pattern, it supports private variables. However, when working with JavaScript code bases you will find that the constructor function is more common – probably because it is a better approximation of mainstream class oriented languages like C# and Java. Inheritance Both of the above patterns can support inheritance but for now, favour composition over inheritance. Summary When JavaScript code exceeds simple browser automation object orientation can provide a powerful paradigm for controlling complexity. Both of the patterns presented in this article work – the choice is a matter of style. Only one question still remains; who is John Galt?

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  • How to have a consistent mail receiver name displayed in Outlook 2007 in the inbox folder

    - by usr
    Currently the same sender address appears differently in my inbox for different mails. The variations are: john[email protected] Doe, John That is because I received some mails before I changed the name to "John Doe" and some after. It is now very annoying to find mails from John because I have to look at two places in my inbox after I sort them by sender. How can I make Outlook always sho "Doe, John"?

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  • Free Online Performance Tuning Event

    - by Andrew Kelly
      On June 9th 2010 I will be showing several sessions related to performance tuning for SQL Server and they are the best kind because they are free :).  So mark your calendars. Here is the event info and URL: June 29, 2010 - 10:00 am - 3:00 pm Eastern SQL Server is the platform for business. In this day-long free virtual event, well-known SQL Server performance expert Andrew Kelly will provide you with the tools and knowledge you need to stay on top of three key areas related to peak performance...(read more)

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  • Oracle Social Network Developer Challenge: Fishbowl Solutions

    - by Kellsey Ruppel
    Originally posted by Jake Kuramoto on The Apps Lab blog. Today, I give you the final entry in the Oracle Social Network Developer Challenge, held last week during OpenWorld. This one comes from Friend of the ‘Lab and Fishbowl Solutions (@fishbowle20) hacker, John Sim (@jrsim_uix), whom you might remember from his XBox Kinect demo at COLLABORATE 12 (presentation slides and abstract) hacks and other exploits with WebCenter. We put this challenge together specifically for developers like John, who like to experiment with new tools and push the envelope of what’s possible and build cool things, and as you can see from his entry John did just that, mashing together Google Maps and Oracle Social Network into a mobile app built with PhoneGap that uses the device’s camera and GPS to keep teams on the move in touch. He calls it a Mobile GeoTagging Solution, but I think Avengers Assemble! would have equally descriptive, given that was obviously his inspiration. Here’s his description of the mobile app: My proposed solution was to design and simplify GeoLocation mapping, and automate updates for users and teams on the move; who don’t have access to a laptop or want to take their ipads out – but allow them to make quick updates to OSN and upload photos taken from their mobile device – there and then. As part of this; the plan was to include a rules engine that could be configured by the user to allow the device to automatically update and post messages when they arrived at a set location(s). Inspiration for this came from on{x} – automate your life. Unfortunately, John didn’t make it to the conference to show off his hard work in person, but luckily, he had a colleague from Fishbowl and a video to showcase his work.    Here are some shots of John’s mobile app for your viewing pleasure: John’s thinking is sound. Geolocation is usually relegated to consumer use cases, thanks to services like foursquare, but distributed teams working on projects out in the world definitely need a way to stay in contact. Consider a construction job. Different contractors all converge on a single location, and time is money. Rather than calling or texting each other and risking a distracted driving accident, an app like John’s allows everyone on the job to see exactly where the other contractors are. Using his GPS rules, they could easily be notified about how close each is to the site, definitely useful when you have a flooring contractor sitting idle, waiting for an electrician to finish the wiring. The best part is that the project manager or general contractor could stay updated on all the action (or inaction) using Oracle Social Network, either sitting at a desk using the browser app or desktop client or on the go, using one of the native mobile apps built for Oracle Social Network. I can see this being used by insurance adjusters too, and really any team that, erm, assembles at a given spot. Of course, it’s also useful for meeting at the pub after the day’s work is done. Beyond people, this solution could also be implemented for physical objects that are in route to a destination. Say you’re a customer waiting on rail shipment or a package delivery. You could track your valuable’s whereabouts easily as they report their progress via checkins. If they deviated from the GPS rules, you’d be notified. You might even be able to get a picture into Oracle Social Network with some light hacking. Thanks to John and his colleagues at Fishbowl for participating in our challenge. We hope everyone had a good experience. Make sure to check out John’s blog post on his work and the experience using Oracle Social Network. Although this is the final, official entry we had, tomorrow, I’ll show you the work of someone who finished code, but wasn’t able to make the judging event. Stay tuned.

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  • Error building C program

    - by John
    Here are my 2 source files: main.c: #include <stdio.h> #include "part2.c" extern int var1; extern int array1[]; int main() { var1 = 4; array1[0] = 2; array1[1] = 4; array1[2] = 5; array1[3] = 7; display(); printf("---------------"); printf("Var1: %d", var1); printf("array elements:"); int x; for(x = 0;x < 4;++x) printf("%d: %d", x, array1[x]); return 0; } part2.c #include <stdio.h> int var1; int array1[4]; void display(void); void display(void) { printf("Var1: %d", var1); printf("array elements:"); int x; for(x = 0;x < 4;++x) printf("%d: %d", x, array1[x]); } When i try to compile the program this is what i get: Ld /Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Products/Debug/Test normal x86_64 cd /Users/John/Xcode/Test setenv MACOSX_DEPLOYMENT_TARGET 10.7 /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang -arch x86_64 -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk -L/Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Products/Debug -F/Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Products/Debug -filelist /Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Intermediates/Test.build/Debug/Test.build/Objects-normal/x86_64/Test.LinkFileList -mmacosx-version-min=10.7 -o /Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Products/Debug/Test ld: duplicate symbol _display in /Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Intermediates/Test.build/Debug/Test.build/Objects-normal/x86_64/part2.o and /Users/John/Library/Developer/Xcode/DerivedData/Test-blxrdmnozbbrbwhcekmouessaprf/Build/Intermediates/Test.build/Debug/Test.build/Objects-normal/x86_64/main.o for architecture x86_64 clang: error: linker command failed with exit code 1 (use -v to see invocation) I am using Xcode and both files are inside of a C project called Test What is causing the error and how do i fix it?

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  • Trying to reconcile global ip address and Vhosts

    - by puk
    I have been using my local machine as a web server for a while, and I have several websites set up locally on my machine, all with similar Vhost files like the one seen here /etc/apache2/sites-available/john.smith.com: <VirtualHost *:80> RewriteEngine on RewriteOptions Inherit ServerAdmin [email protected] ServerName john.smith.com ServerAlias www.john.smith.com DocumentRoot /home/john/smith # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn LogFormat "%v %l %u %t \"%r\" %>s %b" comonvhost CustomLog /var/log/apache2/access.log comonvhost </VirtualHost> then I set up the /etc/hosts file like so for every Vhost: 192.168.1.100 www.john.smith.com john.smith.com 192.168.1.100 www.jane.smith.com jane.smith.com 192.168.1.100 www.joe.smith.com joe.smith.com 192.168.1.100 www.jimbob.smith.com jimbob.smith.com Now I am hosting my friend's website until he gets a permanent domain. I have port forwarding set up to redirect port 80 to my machine, but I don't understand how the global ip fits into all of this. Do I for example use the following web site addresses (assume global ip is 12.34.56.789): 12.34.56.789.john.smith 12.34.56.789.jane.smith 12.34.56.789.joe.smith 12.34.56.789.jimbob.smith

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  • SQL Joing on a one-to-many relationship

    - by Harley
    Ok, here was my original question; Table one contains ID|Name 1 Mary 2 John Table two contains ID|Color 1 Red 2 Blue 2 Green 2 Black I want to end up with is ID|Name|Red|Blue|Green|Black 1 Mary Y Y 2 John Y Y Y It seems that because there are 11 unique values for color and 1000's upon 1000's of records in table one that there is no 'good' way to do this. So, two other questions. Is there an efficient way to get this result? I can then create a crosstab in my application to get the desired result. ID|Name|Color 1 Mary Red 1 Mary Blue 2 John Blue 2 John Green 2 John Black If I wanted to limit the number of records returned how could I do something like this? Where ((color='blue') AND (color<>'red' OR color<>'green')) So using the above example I would then get back ID|Name|Color 1 Mary Blue 2 John Blue 2 John Black I connect to Visual FoxPro tables via ADODB. Thanks!

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  • How to detect if certain characters are at the end of an NSString?

    - by Sheehan Alam
    Let's assume I can have the following strings: "hey @john..." "@john, hello" "@john(hello)" I am tokenizing the string to get every word separated by a space: [myString componentsSeparatedByString:@" "]; My array of tokens now contain: @john... @john, @john(hello) For these cases. How can I make sure only @john is tokenized, while retaining the trailing characters: ... , (hello) Note: I would like to be able to handle all cases of characters at the end of a string. The above are just 3 examples.

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  • JavaScript function binding (this keyword) is lost after assignment

    - by Ding
    this is one of most mystery feature in JavaScript, after assigning the object method to other variable, the binding (this keyword) is lost var john = { name: 'John', greet: function(person) { alert("Hi " + person + ", my name is " + this.name); } }; john.greet("Mark"); // Hi Mark, my name is John var fx = john.greet; fx("Mark"); // Hi Mark, my name is my question is: 1) what is happening behind the assignment? var fx = john.greet; is this copy by value or copy by reference? fx and john.greet point to two diferent function, right? 2) since fx is a global method, the scope chain contains only global object. what is the value of this property in Variable object?

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  • SSH and Active Directory authentication

    - by disserman
    Is it possible to set up Linux (and Solaris) SSH server to authenticate users in this way: i.e. user john is a member of the group Project1_Developers in the Active Directory. we have something on the server A (running Linux, the server has an access to the AD via i.e. LDAP) in the SSH server LDAP (or other module) authentication config like root=Project1_Developers,Company_NIX_Admins. when john connects to the server A using his username "john" and domain password, the server checks the john's group in the domain and if the group is "Project1_Developers" or "Company_NIX_Admins", makes him locally as a root with a root privileges. The idea is also to have only a "root" and a system users on the server, without adding user "john" to all servers where John can log in. Any help or the idea how to make the above or something similar to the above? Preferred using AD but any other similar solution is also possible. p.s. please don't open a discussions is it secure to login via ssh as root or not, thanks :)

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