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  • Chalk Talk with John: What Does User Experience Mean to You?

    - by Tanu Sood
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Author: John Brunswick The "Chalk Talk with John" series will explore the practical value of Middleware in the context of two fictional communities, shared through analogies aligned to enterprise technology.  This format offers business stakeholders and IT a common language for understanding the benefits of technology in support of their business initiatives, regardless of their current level of technical knowledge. I will endeavor to showcase an episode highlighting business use cases and how technology plays a role in business on a bi-weekly basis. The debut episode highlights the benefits of user experience capabilities supplied by Portal technologies, by juxtaposing the communities of Middleware Fields and Codeaway Valley with regard to the time and effort their residents spend performing everyday tasks.  This comparison provides insight into the benefits of leveraging a common user experience foundation to support the tasks that our employees, customers and partners engage in on a daily basis with our organizations. Take a look and let me know your thoughts! Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} About me: Hi, I am John Brunswick, an Oracle Enterprise Architect. As an Oracle Enterprise Architect, I focus on the alignment of technical capabilities in support of business vision and objectives, as well as the overall business value of technology.  Before coming to Oracle, I was a Practice Manager within BEA System's Business Interaction Division consulting organization, orchestrating enterprise systems in support of line of business goals. Connect with me on Twitter and visit my site for Oracle Fusion Middleware related tips.

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  • Should be simple: existing laptop with local user and outlook 2007 migrate on same computer to domain user with outlook 2007 emails intact

    - by bifpowell
    I have Dell Laptop with windows 7 64 bit and for the last year it's been just a machine with an account like: machine\john there are files in folders and stuff in c:\users\john and john uses outlook 2007 as a pop3 client and has identifiable local appdata pst files. Now I installed a server and want to have everything be domain-centric so I added this laptop to the domain with admin credentials and then logged in as a domain user as: domain\john.smith Now I want to duplicate machine\john (outlook emails mostly) to domain\john.smith. In the past I used the Files and Settings Xfer Wizard and done. I tried that here and it crunched away for a while, made the file, but the restore had no effect - it ran for a while, had a progress bar, but it's like nothing happened at all afterwards. I've rebooted the machine, logged in as domain administrator as the first user to log on after the restart and tried: c:\users\john xcopy c:\users\john c:\users\john.smith /V /C /F /H /K /Y /E ...and it copies some of it, but when it gets to c:\users\john.smith\appdata\local\application data it chokes "Access denied, unable to create directory" I also tried logging in as domain\john.smith and copying the entire directory that the PSTs are in from machine\john and a lot of the mail was there when I launched outlook after replacing the PSTs, but not all of them??? I got errors about files in use when doing this method, which I figure must be why not all the old emails are in the inbox?... There must be some extremely simple way to do what must be a very common requirement. Any guidance appreciated.

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  • VBA/SQL recordsets

    - by intruesiive
    The project I'm asking about is for sending an email to teachers asking what books they're using for the classes they're teaching next semester, so that the books can be ordered. I have a query that compares the course number of this upcoming semester's classes to the course numbers of historical textbook orders, pulling out only those classes that are being taught this semester. That's where I get lost. I have a table that contains the following: -Professor -Course Number -Year -Book -Title The data looks like this: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 12 1111 Pride and Prejudice smith 11 1222 Infinite Jest smith 10 1333 The Bible smith 13 1333 The Bible smith 12 1222 The Alchemist smith 10 1111 Moby Dick johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 10 1333 Everything is Illuminated johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time johnson 10 1333 Great Expectations johnson 9 1222 Proust on the Shore Here's what I need the code to do "on paper": Group the records by professor. Determine every unique course number in that group, and group records by course number. For each unique course number, determine the highest year associated. Then spit out every record with that professor+course number+year combination. With the sample data, the results would be: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 13 1333 The Bible johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time I'm thinking I should make a record set for each teacher, and within that, another record set for each course number. Within the course number record set, I need the system to determine what the highest year number is - maybe store that in a variable? Then pull out every associated record so that if the teacher ordered 3 books the last time they taught that class (whether it was in 2013 or 2012 and so on) all three books display. I'm not sure I'm thinking of record sets in the right way, though. My SQL so far is basic and clearly doesn't work: SELECT [All].Professor, [All].Course, Max([All].Year) FROM [All] GROUP BY [All].Professor, [All].Course; Thanks for your help.

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  • Webcast: John Fowler Reveals The Next Step In Data Center Consolidation – June 27 At 10 AM PT

    - by Roxana Babiciu
    Completely integrated solutions are just better. But don't take our word for it - encourage your customers and prospects to join this live webcast featuring Oracle EVP John Fowler to find out why. Participants will learn how consolidating their existing data center to this new generation of solutions will simplify architectures, jump start application deployment and improve system performance - with easy self-service and private cloud capabilities.

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  • SQL: Add counters in select

    - by etarvt
    Hi, I have a table which contains names: Name ---- John Smith John Smith Sam Wood George Wright John Smith Sam Wood I want to create a select statement which shows this: Name 'John Smith 1' 'John Smith 2' 'Sam Wood 1' 'George Wright 1' 'John Smith 3' 'Sam Wood 2' In other words, I want to add separate counters to each name. Is there a way to do it without using cursors?

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  • JavaScript Class Patterns

    - by Liam McLennan
    To write object-oriented programs we need objects, and likely lots of them. JavaScript makes it easy to create objects: var liam = { name: "Liam", age: Number.MAX_VALUE }; But JavaScript does not provide an easy way to create similar objects. Most object-oriented languages include the idea of a class, which is a template for creating objects of the same type. From one class many similar objects can be instantiated. Many patterns have been proposed to address the absence of a class concept in JavaScript. This post will compare and contrast the most significant of them. Simple Constructor Functions Classes may be missing but JavaScript does support special constructor functions. By prefixing a call to a constructor function with the ‘new’ keyword we can tell the JavaScript runtime that we want the function to behave like a constructor and instantiate a new object containing the members defined by that function. Within a constructor function the ‘this’ keyword references the new object being created -  so a basic constructor function might be: function Person(name, age) { this.name = name; this.age = age; this.toString = function() { return this.name + " is " + age + " years old."; }; } var john = new Person("John Galt", 50); console.log(john.toString()); Note that by convention the name of a constructor function is always written in Pascal Case (the first letter of each word is capital). This is to distinguish between constructor functions and other functions. It is important that constructor functions be called with the ‘new’ keyword and that not constructor functions are not. There are two problems with the pattern constructor function pattern shown above: It makes inheritance difficult The toString() function is redefined for each new object created by the Person constructor. This is sub-optimal because the function should be shared between all of the instances of the Person type. Constructor Functions with a Prototype JavaScript functions have a special property called prototype. When an object is created by calling a JavaScript constructor all of the properties of the constructor’s prototype become available to the new object. In this way many Person objects can be created that can access the same prototype. An improved version of the above example can be written: function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { toString: function() { return this.name + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); In this version a single instance of the toString() function will now be shared between all Person objects. Private Members The short version is: there aren’t any. If a variable is defined, with the var keyword, within the constructor function then its scope is that function. Other functions defined within the constructor function will be able to access the private variable, but anything defined outside the constructor (such as functions on the prototype property) won’t have access to the private variable. Any variables defined on the constructor are automatically public. Some people solve this problem by prefixing properties with an underscore and then not calling those properties by convention. function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { _getName: function() { return this.name; }, toString: function() { return this._getName() + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); Note that the _getName() function is only private by convention – it is in fact a public function. Functional Object Construction Because of the weirdness involved in using constructor functions some JavaScript developers prefer to eschew them completely. They theorize that it is better to work with JavaScript’s functional nature than to try and force it to behave like a traditional class-oriented language. When using the functional approach objects are created by returning them from a factory function. An excellent side effect of this pattern is that variables defined with the factory function are accessible to the new object (due to closure) but are inaccessible from anywhere else. The Person example implemented using the functional object construction pattern is: var john = new Person("John Galt", 50); console.log(john.toString()); var personFactory = function(name, age) { var privateVar = 7; return { toString: function() { return name + " is " + age * privateVar / privateVar + " years old."; } }; }; var john2 = personFactory("John Lennon", 40); console.log(john2.toString()); Note that the ‘new’ keyword is not used for this pattern, and that the toString() function has access to the name, age and privateVar variables because of closure. This pattern can be extended to provide inheritance and, unlike the constructor function pattern, it supports private variables. However, when working with JavaScript code bases you will find that the constructor function is more common – probably because it is a better approximation of mainstream class oriented languages like C# and Java. Inheritance Both of the above patterns can support inheritance but for now, favour composition over inheritance. Summary When JavaScript code exceeds simple browser automation object orientation can provide a powerful paradigm for controlling complexity. Both of the patterns presented in this article work – the choice is a matter of style. Only one question still remains; who is John Galt?

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  • Convince developer to use IDE

    - by artjom
    There is a developer, lets call him John (currently on probationary period) in company(pretty small company approx. 10 persons, 3 developers, one of them works long in this company know business process around and can be consider as Team leader) who didn't want to use any IDE at all(he is using some text editor). Application this team working on is medium size Java application with Spring Hibernate technology stack and refactoring/adding new features to launch new version of that application in near future. John performance working without IDE on this application is lower then desirable, team leader's (lets call him Bill) assumption is this happens because John is not using IDE. Bill try to persuade John to use IDE, but this idea meets a lot of resistance and main reason is "I want to be in total control of what I am doing, so I need to write all code by myself". How can Bill convince John to try to use IDE? (considering the fact what Bill already protected John from company owner several complaints about John performance)

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  • Search 2 Columns with 1 Input Field

    - by Norbert
    I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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  • How are views constructed in Josh Smith's MVVM sample?

    - by Wim Coenen
    Being new to both WPF and MVVM, I'm studying Josh Smith's article on the MVVM pattern and the accompanying sample code. I can see that the application is started in app.xaml.cs by constructing a MainWindow object, wiring it to a MainWindowViewModel object and then showing the main window. So far so good. However, I can't find any code which instantiates the AllCustomersView or CustomerView classes. Using "find all references" on the constructors of those views comes up with nothing. What am I missing here?

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  • "ldap_add: Naming violation (64)" error when configuring OpenLDAP

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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  • How to Configure OpenLDAP on Ubuntu 10.04 Server

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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  • How to configure ldap on ubuntu 10.04 server

    - by user3215
    I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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  • Select From MySQL PHP

    - by Liju
    Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • 9 New BizTalk Wencasts in the Light & Easy Series

    - by Alan Smith
    During the MVP summit in February I managed to catch up with a few of the BizTalk MVPs who had recorded new webcasts for the “BizTalk Light & Easy” series. The 9 new webcasts are online now at CloudCasts. ·         BizTalk 2010 and Windows Azure – Paul Somers ·         BizTalk and AppFabric Cache Part 1 – Mike Stephenson ·         BizTalk and AppFabric Cache Part 2 – Mike Stephenson ·         Integration to SharePoint 2010 Part 1 – Mick Badran ·         Integration to SharePoint 2010 Part 2 – Mick Badran ·         Better BizTalk Testing by Taking Advantage of the CAT Logging Framework – Mike Stephenson ·         Calling Business Rules from a .NET Application – Alan Smith ·         Tracking Rules Execution in a .NET Application – Alan Smith ·         Publishing a Business Rules Policy as a Service – Alan Smith The link is here. Big thanks to Paul, Mike and Mick for putting the time in. “BizTalk Light & Easy” is an ongoing project, if you are feeling creative and would like to contribute feel free to contact me via this blog. I can email you some tips on webcasting and the best formats to use.

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  • SEO impact on subdomain for full name and obscure ccTLD

    - by Dan Christian
    There have been a few questions on subdomains and their impact on SEO, mostly in comparison to subfolders. The closest question I've found is this question but it still doesn't completely answer my query. I'm setting up a blog for 'Sam Smith'. It's imperative the SEO is based around his full name as he is a prominent blogger and his name is his value. All ccTLD variations of 'samsmith' (samsmith.com, samsmith.cc etc) are taken. However there has been the opportunity to register an obscure ccTLD for 'smith'. In regards to SEO value purely from the URL... 1) Will there be any negative SEO implications on searches for 'Sam Smith' when setting up the subdomain as 'sam.smith.' compared to a more regular 'samsmith.' domain? Will a search engine recognise the subdomain as the full name as oppose to just 'smith'? 2) Are there any negative SEO implications with an obscure ccTLD. For instance if Sam Smith was a prominent blogger in Canada with most of his audience based there, would there be any negative SEO if he had, for example, a .co ccTLD.

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  • change owner/uid of mount point upon mount

    - by Shiplu
    The scenario is like this. Bob has a computer. It crashed. Now he only has the hdd. The hdd is in ext3 format. He go to his office and told the sys admin John to mount this hdd and put the mount point in his home directory. John used the following fstab entries. # Bobs harddisk /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/windows ntfs ro,loop,offset=32256 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/linux ext3 ro,loop,offset=14048810496 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/extra ntfs ro,loop,offset=28015335936 0 0 Bob was happy. He could access his old extra and windows. Specially the Documents and Settings in windows was helpful for him. But he found a problem. He is a web developer and all his websites are in linux/home/bob/public_html directory. When he tried to access that public_html directory he got permission_denied. He executed ls -lh he saw this. drwxr-xr-x 2 john john 4.0K Nov 9 2011 Desktop drwxr-xr-x 3 john john 4.0K Aug 12 2011 Documents drwxr-xr-x 3 john john 4.0K Aug 21 2011 public_html He contacted John thinking he might be mistakenly did this. But John couldn't find a way why this happend? Then one thing came into his mind file system hardly store username. They store uids. So he executed ls -ln drwxr-xr-x 2 1000 1000 4096 Nov 9 2011 Desktop drwxr-xr-x 3 1000 1000 4096 Aug 12 2011 Documents drwxr-xr-x 3 1000 1000 4096 Aug 21 2011 public_html John thinks 1000 is the first uid on a linux system. As he is the admin of the current system. He created his account first. so Johns uid was 1000. Bob also setup his private system and crated his account first. So Bobs uid was 1000 too. So thats an expected behavior. But problem remains. How can Bob access those websites in public_html?

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  • Looking for equivalent of ProxyPassReverseMatch in Apache to fix missing trailing forward slash issue

    - by Alex Man
    I have two web servers, www.example.com and www.userdir.com. I'm trying to make www.example.com as the front end proxy server to serve requests like in the format of http://www.example.com/~username such as http://www.example.com/~john/ so that it sends an internal request of http://www.userdir.com/~john/ to www.userdir.com. I can achieve this in Apache with ProxyPass /~john http://www.userdir.com/~john ProxyPassReverse /~john http://www.userdir.com/~john The ProxyPassReverse is necessary as without it a request like http://www.example.com/~john without the trailing forward slash will be redirected as http://www.userdir.com/~john/ and I want my users to stay in the example.com space. Now, my problem is that I have a lot of users and I cannot list all those user names in httpd.conf. So, I use ProxyPassMatch ^(/~.*)$ http://www.userdir.com$1 but there is no such thing as ProxyPassReverseMatch in Apache. Without it, whenever the trailing forward slash is missing in the URL, one will be directed to www.userdir.com, and that's not what I want. I also tried the following to add the trailing forward slash RewriteCond %{REQUEST_URI} ^/~[^./]*$ RewriteRule ^/(.*)$ http://www.userdir.com/$1/ [P] but then it will render a page with broken image and CSS because they are linked to http://www.example.com/images/image.gif while it should be http://www.example.com/~john/images/image.gif. I have been googling for a long time and still can't figure out a good solution for this. Would really appreciate it if any one can shed some light on this issue. Thank you!

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  • Using git through cygwin on windows 8

    - by 9point6
    I've got a windows 8 dev preview (not sure if it's relevant, but I never had this hassle on w7) machine and I'm trying to clone a git repo from github. The problem is that my ~/.ssh/id_rsa has 440 permissions and it needs to be 400. I've tried chmodding it but the any changes on the user permissions gets reflected in the group permissions (i.e. chmod 600 results in 660, etc). This appears to be constant throughout any file in the whole filesystem. I've tried messing with the ACLs but to no avail (full control on my user and deny everyone resulted in 000) here's a few outputs to help: $ git clone [removed] Cloning into [removed]... @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ WARNING: UNPROTECTED PRIVATE KEY FILE! @ @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ Permissions 0660 for '/home/john/.ssh/id_rsa' are too open. It is required that your private key files are NOT accessible by others. This private key will be ignored. bad permissions: ignore key: /home/john/.ssh/id_rsa Permission denied (publickey). fatal: The remote end hung up unexpectedly $ ll ~/.ssh total 6 -r--r----- 1 john None 1675 Nov 30 19:15 id_rsa -rw-rw---- 1 john None 411 Nov 30 19:15 id_rsa.pub -rw-rw-r-- 1 john None 407 Nov 30 18:43 known_hosts $ chmod -v 400 ~/.ssh/id_rsa mode of `/home/john/.ssh/id_rsa' changed from 0440 (r--r-----) to 0400 (r--------) $ ll ~/.ssh total 6 -r--r----- 1 john None 1675 Nov 30 19:15 id_rsa -rw-rw---- 1 john None 411 Nov 30 19:15 id_rsa.pub -rw-rw-r-- 1 john None 407 Nov 30 18:43 known_hosts $ set | grep CYGWIN CYGWIN='sbmntsec ntsec server ntea' I realize I could use msysgit or something, but I'd prefer to be able to do everything from a single terminal Edit: Msysgit doesn't work either for the same reasons

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  • Building a project in VS that depends on a static and dynamic library

    - by fg nu
    Noob noobin'. I would appreciate some very careful handholding in setting up an example in Visual Studio 2010 Professional where I am trying to build a project which links: a previously built static library, for which the VS project folder is "C:\libjohnpaul\" a previously built dynamic library, for which the VS project folder is "C:\libgeorgeringo\" These are listed as Recipes 1.11, 1.12 and 1.13 in the C++ Cookbook. The project fails to compile for me with unresolved dependencies (see details below), and I can't figure out why. Project 1: Static Library The following are the header and source files that were compiled in this project. I was able to compile this project fine in VS2010, to the named standard library "libjohnpaul.lib" which lives in the folder ("C:/libjohnpaul/Release/"). // libjohnpaul/john.hpp #ifndef JOHN_HPP_INCLUDED #define JOHN_HPP_INCLUDED void john( ); // Prints "John, " #endif // JOHN_HPP_INCLUDED // libjohnpaul/john.cpp #include <iostream> #include "john.hpp" void john( ) { std::cout << "John, "; } // libjohnpaul/paul.hpp #ifndef PAUL_HPP_INCLUDED #define PAUL_HPP_INCLUDED void paul( ); // Prints " Paul, " #endif // PAUL_HPP_INCLUDED // libjohnpaul/paul.cpp #include <iostream> #include "paul.hpp" void paul( ) { std::cout << "Paul, "; } // libjohnpaul/johnpaul.hpp #ifndef JOHNPAUL_HPP_INCLUDED #define JOHNPAUL_HPP_INCLUDED void johnpaul( ); // Prints "John, Paul, " #endif // JOHNPAUL_HPP_INCLUDED // libjohnpaul/johnpaul.cpp #include "john.hpp" #include "paul.hpp" #include "johnpaul.hpp" void johnpaul( ) { john( ); paul( ); Project 2: Dynamic Library Here are the header and source files for the second project, which also compiled fine with VS2010, and the "libgeorgeringo.dll" file lives in the directory "C:\libgeorgeringo\Debug". // libgeorgeringo/george.hpp #ifndef GEORGE_HPP_INCLUDED #define GEORGE_HPP_INCLUDED void george( ); // Prints "George, " #endif // GEORGE_HPP_INCLUDED // libgeorgeringo/george.cpp #include <iostream> #include "george.hpp" void george( ) { std::cout << "George, "; } // libgeorgeringo/ringo.hpp #ifndef RINGO_HPP_INCLUDED #define RINGO_HPP_INCLUDED void ringo( ); // Prints "and Ringo\n" #endif // RINGO_HPP_INCLUDED // libgeorgeringo/ringo.cpp #include <iostream> #include "ringo.hpp" void ringo( ) { std::cout << "and Ringo\n"; } // libgeorgeringo/georgeringo.hpp #ifndef GEORGERINGO_HPP_INCLUDED #define GEORGERINGO_HPP_INCLUDED // define GEORGERINGO_DLL when building libgerogreringo.dll # if defined(_WIN32) && !defined(__GNUC__) # ifdef GEORGERINGO_DLL # define GEORGERINGO_DECL _ _declspec(dllexport) # else # define GEORGERINGO_DECL _ _declspec(dllimport) # endif # endif // WIN32 #ifndef GEORGERINGO_DECL # define GEORGERINGO_DECL #endif // Prints "George, and Ringo\n" #ifdef __MWERKS__ # pragma export on #endif GEORGERINGO_DECL void georgeringo( ); #ifdef __MWERKS__ # pragma export off #endif #endif // GEORGERINGO_HPP_INCLUDED // libgeorgeringo/ georgeringo.cpp #include "george.hpp" #include "ringo.hpp" #include "georgeringo.hpp" void georgeringo( ) { george( ); ringo( ); } Project 3: Executable that depends on the previous libraries Lastly, I try to link the aforecompiled static and dynamic libraries into one project called "helloBeatlesII" which has the project directory "C:\helloBeatlesII" (note that this directory does not nest the other project directories). The linking process that I did is described below: To the "helloBeatlesII" solution, I added the solutions "libjohnpaul" and "libgeorgeringo"; then I changed the properties of the "helloBeatlesII" project to additionally point to the include directories of the other two projects on which it depends ("C:\libgeorgeringo\libgeorgeringo" & "C:\libjohnpaul\libjohnpaul"); added "libgeorgeringo" and "libjohnpaul" to the project dependencies of the "helloBeatlesII" project and made sure that the "helloBeatlesII" project was built last. Trying to compile this project gives me the following unsuccessful build: 1------ Build started: Project: helloBeatlesII, Configuration: Debug Win32 ------ 1Build started 10/13/2012 5:48:32 PM. 1InitializeBuildStatus: 1 Touching "Debug\helloBeatlesII.unsuccessfulbuild". 1ClCompile: 1 helloBeatles.cpp 1ManifestResourceCompile: 1 All outputs are up-to-date. 1helloBeatles.obj : error LNK2019: unresolved external symbol "void __cdecl georgeringo(void)" (?georgeringo@@YAXXZ) referenced in function _main 1helloBeatles.obj : error LNK2019: unresolved external symbol "void __cdecl johnpaul(void)" (?johnpaul@@YAXXZ) referenced in function _main 1E:\programming\cpp\vs-projects\cpp-cookbook\helloBeatlesII\Debug\helloBeatlesII.exe : fatal error LNK1120: 2 unresolved externals 1 1Build FAILED. 1 1Time Elapsed 00:00:01.34 ========== Build: 0 succeeded, 1 failed, 2 up-to-date, 0 skipped ========== At this point I decided to call in the cavalry. I am new to VS2010, so in all likelihood I am missing something straightforward.

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  • Love and Hate Outlook autocomplete, Outlook 2010/Exchange 2010

    - by Kay Sellenrode
    I think that almost every Exchange admin can concur with me that the Outlook autocomplete cache is one of those things you love but at the same time also hate. Users mostly love this function, except when it fails.Luckily since Outlook 2010 things got a little better and we got rid of the dreaded nk2 files.Outlook 2010 now includes a folder named "Suggested Contacts", all users you send an email to and that don't already have an contact object are saved in this suggested contacts folder.A lot of people thought this folder is also the source for the autocomplete cache, which would make it somewhat easy to manage, I wish the solution was that easy.Badly enough separate from the suggested contacts, outlook still maintains a cache for the autocomplete function. Let us say you run in to the following situation: John works for company A and is a popular contact for almost everyone in your organization.Now John quit his job at Company A and moved to Company B.Luckily John maintains your company as customer, but his email address is now changed from companyA.com to companyB.comSince you don't want to do any business with Company A anymore, you want to make sure none of your users accidentally mail to his old address.Now this is where the real fun starts, cause almost all of your 1000 users have mailed at least once with John.Resulting in the fact that every user has John most probably listed in their autocomplete cache.  I have run into sort like situations multiple times with several customers, which is always a pain.And of course this blog post is the result of one of those issues once again.I knew that with the Suggested contacts we could do more than previously, but still never spent time on it before.But today I thought lets nail this now and forever!!  Ok let's start of that things are different for every combination of outlook and exchange.I explain the procedure for Exchange 2010 SP1+ in combination with Outlook 2010.At first we want to get rid of all contact objects that contain [email protected] do this we need to be assigned to the RBAC role "Mailbox Import Export", which can be done through the Exchange Control panel.In my test environment I assigned this role to the Organization admins, but in real life you might want to add it to a custom role. Open the Exchange control panel by logging in to the ecp url, in my case https://ITFEX.itf.local/ECP, and make sure you selected your organization as management scope.Browse to Roles & Auditing, and open the properties for the organization management role group.click on the Add button to add a new role to the Organization Management role group, select the Mailbox Import Export role and click on add and OK to add it to the role.  Once you have assigned that role to your account you can open the Exchange Management Shell and execute the following command: Get-mailbox –resultsize unlimited | search-mailbox –targetmailbox "your.account" –targetfolder searchanddelete –loglevel full –logonly –searchquery "kind:contact AND [email protected]" This command will create a list with all mailboxes and any contacts that were found with an email address that contains [email protected], this list is then posted in the mailbox you specified at your.account in the folder searchanddelete.Now examine the report that was created and posted in the mailbox to see if it matches what you think it should match.My results looked like this:  When you're confident that the search includes all references and no false positives you can execute almost the same command, but this time with an delete action instead of the logonly. Get-mailbox –resultsize unlimited | search-mailbox –targetmailbox "your.account" –targetfolder searchanddelete –loglevel full –DeleteContent –searchquery "kind:contact AND [email protected]" Now most people would think this would remove the contact object from the suggested contacts, resulting in a removal from the autocomplete list.Sad but not true, to clean up the autocomplete list start Outlook with the command: "outlook /cleanautocompletecache" This will result in an empty cache, but luckily this is rebuild based on the suggested contacts, which now doesn't include the [email protected] contact anymore.

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • Filter rows on the basis of "First Name" + "Last Name" in SQL

    - by Raghav Khunger
    Hi, I have a user table in my database which contains two columns FirstName and LastName. Now in my front end there is a textbox to filter out the users from this table. Let's suppose I am taking that input from the front end in the form of a input parameter "@SEARCHKEYWORD". I have created a sample below: DECLARE @Test TABLE ([ID] INT IDENTITY, [FNAME] NVARCHAR(100), [LNAME] NVARCHAR(100) ) INSERT INTO @Test( FNAME, LNAME ) SELECT 'John','Resig' UNION ALL SELECT 'Dave','Ward' UNION ALL SELECT 'Peter','Smith' UNION ALL SELECT 'Dave','Smith' UNION ALL SELECT 'Girija','Acharya' UNION ALL SELECT 'Devendra', 'Gujel' UNION ALL SELECT 'Arjit', 'Gupta' DECLARE @SEARCHKEYWORD NVARCHAR(100) SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD i.e. so far I have thought of this query to filter out the rows but it is not giving the desired results: SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD Here are the desired outputs which I needed for the inputs mentioned below: --WHEN @SEARCHKEYWORD='John Resig' --Desired OUTPUT: the row which contains 'John','Resig' --WHEN @SEARCHKEYWORD='Ac' --Desired OUTPUT: the row which contains 'Girija','Acharya' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith' --WHEN @SEARCHKEYWORD='g' --Desired OUTPUT: the row which contains 'Devendra', 'Gujel' and 'Arjit', 'Gupta' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith'

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